x + y = 16 y = 3x
x + (3x) = 16 4x = 16
x = 4
y = 3x y = 3(4) y = 12
Trouvons y
(4, 12)
y = 3x
x + y = 186 x = 2y
(2y) + y = 186 3y = 186
y = 62
x = 2y
x = 2(62) x = 124
Trouvons x
(124, 62)
x = 2y
2x + 2y = 48 x = 2y
2(2y) + 2y = 48 6y = 48
y = 8
x = 2y x = 2(8) x = 16
Trouvons x
(16, 8)
x = 2y
x = 2y + 5 x + y = 17
(2y + 5) + y = 17 3y + 5 = 17
3y = 12
x = 2y + 5 x = 2(4) + 5 x = 13
Trouvons y
y = 4
(13, 4)
Âge d’Élizabeth Âge d’André
X = 2y + 5
2x + 3y = 181 3x + 4y = 252
-y = -39 y = 39
2x + 3y = 181 Trouvons x
6x + 9y = 543 -6x - 8y = -504
Éliminons le x
2x + 3(39) = 181 2x + 117 = 181 2x = 64
x = 32
Le prix d’un
chandail est 32$
(32, 39)
4x + 3y = 214 5x + 2y = 208
7x = 196 x = 28
4x + 3y = 214 Trouvons y
-8x – 6y = -428 15x + 6y = 624 Éliminons le y
4(28) + 3y = 214 112 + 3y = 214 3y = 102
2y = ???
Réponse
2(34) = 68$
y = 34