3/1
N
14
14C ﺔﻴﺒﻌﺸﻟﺍ ﺔﻴﻁﺍﺭﻘﻤﻴﺩﻟﺍ ﺔﻴﺭﺌﺍﺯﺠﻟﺍ ﺔﻴﺭﻭﻬﻤﺠﻟﺍ
ﺩﻌﺒ ﻥﻋ ﻥﻴﻭﻜﺘﻟﺍﻭ ﻡﻴﻠﻌﺘﻠﻟ ﻲﻨﻁﻭﻟﺍ ﻥﺍﻭﻴﺩﻟﺍ ﺔﻴﻨﻁﻭﻟﺍ ﺔﻴﺒﺭﺘﻟﺍ ﺓﺭﺍﺯﻭ ﻯﻭﺘﺴﻤﻟﺍ ﻥﺎﺤﺘﻤﺍ ﺏﺍﻭﺠ ﻡﻴﻤﺼﺘ
– ﻱﺎﻤ ﺓﺭﻭﺩ 2011
ﺔﺒﻌﺸﻟﺍﻭ ﻯﻭﺘﺴﻤﻟﺍ :
ﺔﻴﺒﻴﺭﺠﺘ ﻡﻭﻠﻋ ﻱﻭﻨﺎﺜ 3 ﺓﺩﺎﻤﻟﺍ
: ﺔﻴﺌﺎﻴﺯﻴﻓ ﻡﻭﻠﻋ
لﻭﻷﺍ ﻥﻴﺭﻤﺘﻟﺍ :
ﻥ 6
- 1 : , A=12
ﻪﻟ ﻥﺫﺇ Z=6 ﻭ ﺕﺎﻨﻭﺘﻭﺭﺒ 6
ﺕﺎﻨﻭﺭﺘﻨ 6 ...
ﻥ 0,25
: Z=6 ,A=14 ﻪﻟ ﻥﺫﺇ
ﻭ ﺕﺎﻨﻭﺘﻭﺭﺒ 6 ﺕﺎﻨﻭﺭﺘﻨ 8
...
ﻥ 0,25
– 2 ﺭﺒﻟﺍ ﺩﺩﻋ ﺱﻔﻨ ﻥﺎﻜﻠﺘﻤﺘ ﺎﻤﻬﻨﻷ ﻥﻴﺭﻴﻅﻨ ﻥﻴﺘﺍﻭﻨﻟﺍ ﻥﻴﺘﺎﻫ لﻜﺸﺘ ﻡﻌﻨ ﺩﺩﻋ ﻲﻓ ﻥﺎﻔﻠﺘﺨﺘﻭ ﺕﺎﻨﻭﺘﻭ
ﺕﺎﻨﻭﺭﺘﻴﻨﻟﺍ ...
ﻥ 0,5
/ 3 ﺃ -
ﺏ – = ∆mC 2 E ℓ
E ℓ = [ Zmp+(A-Z)mn –m( ) ]C2 ...
...
ﻥ 0,5
E ℓ= [6.1,672621.10-27 + 8 .1,674927.10-27 -2,32584 .10-26 ](3.108 )2 ....
ﻥ 0,75
= 1,59.10-11J E ℓ
...
...
..
ﻥ 0,75
- ـﺟ ﻥﻭﻴﻠﻜﻴﻨ E ℓ/ A = 1,59.10-11/14 = 1,135 .10-12 J / ...
ﻥ 0,5 + ﻥ 0,5
ﺩ - E = ∆mC2 ...
ﻥ 0,5
E= [ me- + m ( ) - m ( ) ] C 2 ...
....
...
ﻥ 0,5
E= [ 9,109381.10-31 + 2,32527.10-26 - 2,32584 .10-26 ]×(3.108)2 4,31.10-13 J = -
... E ﻥ 0,5
ﻲﻨﺎﺜﻟﺍ ﻥﻴﺭﻤﺘﻟﺍ :
ﻥ 6
– 1
→a = m F→
∑
→a = m P→
ﺭﻭﺤﻤﻟﺍ ﻰﻠﻋ : (OX)
... a=0 ﻥ 0,25
ﺔﻜﺭﺤﻟﺍ ﻤ
ﺙﻴﺤ ﺔﻤﻅﺘﻨﻤ ﺔﻤﻴﻘﺘﺴ :
x=V0x.t = V0cosα .t ﺔﻗﻼﻌﻟﺍ
) (1 ...
...
ﻥ 0,5
ﺭﻭﺤﻤﻟﺍ ﻰﻠﻋ : (OY)
... a=g ﻥ 0,25
ﺙﻴﺤ ﻡﺎﻅﺘﻨﺈﺒ ﺓﺭﻴﻐﺘﻤ ﺔﻤﻴﻘﺘﺴﻤ ﺔﻜﺭﺤﻟﺍ :
.. t α Y= ½ gt2-V0sin ﺔﻗﻼﻌﻟﺍ
) (2 ...
ﻥ 0,5
ﺔﻗﻼﻌﻟﺍ ﻥﻤ : 1
t= x/ V0cosα .
ﺔﻗﻼﻌﻟﺍ ﻲﻓ ﺽﻴﻭﻌﺘﻟﺎﺒ ﺩﺠﻨ 2
:
Y= g. x2/2(V0cosα)2 -xtangα ...
ﻥ 0,5
ﺩﺠﻨ ﺽﻴﻭﻌﺘﻟﺎﺒ :
Y= 0,261 x2 - 0,577x ...
ﻥ 0,5
ﺭﺎﺘﺨﻤﻟﺍ ﻡﻠﻌﻤﻟﺍ ﻲﻓ ﺡﺎﺒﺴﻟﺍ ﺔﻜﺭﺤ ﺭﺎﺴﻤ ﺔﻟﺩﺎﻌﻤ ﻲﻫﻭ .
3/2
– 2 Y=8m
ﺔﻟﺩﺎﻌﻤﻟﺍ ﻲﻓ ﺽﻴﻭﻌﺘﻟﺎﺒ : 2
- 2,5t 8= 4,9t2
ﻪﻨﻤﻭ : 4,9t2 -2,5t -8 =0 .
...
ﻥ 0,5
ﺩﺠﻨ ﺔﻟﺩﺎﻌﻤﻟﺍ ﻩﺫﻫ لﺤﺒ :
t=1,56s ....
...
...
ﻥ 0,5
- 3
= 5 cos30.1,56 = 6,75m x = V0cosα t
...
ﻥ 0,5
Y= ½ gt2-V0sinα .t = 4,9(1,56)2-5sin 30.1,56= 8m ...
ﻥ 0,5
- 4
= V0cos30 =5cos30 = 4,33m/s Vx
...
ﻥ 0,5
= 9,8.1,56 – 5.0,5 = 12,8m/s
= gt –V0sin30 Vy
...
ﻥ 0,5
V2= Vx2 + Vy2 = (4,33)2+ (12,8)2 V = 13 ,5m/s ...
ﻥ 0,5
ﺙﻟﺎﺜﻟﺍ ﻥﻴﺭﻤﺘﻟﺍ :
ﻥ 4
– 1
) + H2O (ℓ) C6H7O6- (aq) + H3O+(aq) C6H8O6 (aq
...
ﻥ 1
– 2 ﺓﺩﺭﺎﺸﻟﺍ C6H7O6-
ﺍ ﺽﻤﺤﻟ ﻕﻓﺍﺭﻤﻟﺍ ﺱﺎﺴﻷﺍ ﻲﻫ ﻙﻴﺒﺭﻭﻜﺴﻷ
C6H8O6 ...
ﻥ 1
- 3 /xmax
= x f
τ ...
...
ﻥ 0.5
xmax = C1V
x f = [ H3O+ ]. V
= [ H3O+ ]. V / C1V = [ H3O+ ]/C1 τ
= 10-PH / 10-2 = 10-3,01 / 10-2 = 10-1, 01 ...τ
...
ﻥ 0,5
= 0,0977 ...τ
...
ﻥ 0,5
1
<
ﻡﺎﺘ ﺭﻴﻏ لﻭﺤﺘﻟﺍ τ ...
ﻥ 0,5
ﻊﺒﺍﺭﻟﺍ ﻥﻴﺭﻤﺘﻟﺍ :
ﻥ 4
/dt - 1 = d [Cr+3]
ν
ﺔﻋﺭﺴﻟﺍ ﺏﺎﺴﺤﻟ ﺩﻨﻋ
t=40s ﻲﻔﻜﻴ ﺤ ﺎﺴ ﺏ
ﺱﺎﻤﻤﻟﺍ لﻴﻤ ﺩﻨﻋ ﻰﻨﺤﻨﻤﻠﻟ
s t=40
(40s)
=
BC/ACν
=8/50=0,16.10-3 mol/l.s ...
ﻥ 1
3/3
– 2 ﺱﺎﻤﻤﻟﺍ ﻪﻴﺠﻭﺘ لﻤﺎﻌﻤ ﻥﻷ ﻥﻤﺯﻟﺍ ﺭﻭﺭﻤ ﻊﻤ ﺹﻗﺎﻨﺘﺘ ﻲﺌﺎﻴﻤﻴﻜﻟﺍ لﻋﺎﻔﺘﻟﺍ ﺔﻋﺭﺴ ﻥﺃ ﺞﺘﻨﺘﺴﻨ ﻥﺎﻴﺒﻟﺍ لﻼﺨ ﻥﻤ
ﻯﺭﺨﻷ ﺔﻅﺤﻟ ﻥﻤ ﺹﻗﺎﻨﺘﻴ ﻰﻨﺤﻨﻤﻠﻟ ..
...
ﻥ 1
– 3 لﻋﺎﻔﺘﻟﺍ ﻑﺼﻨ ﻥﻤﺯ
/2
τ 1
ﻡﺯﻼﻟﺍ ﻥﻤﺯﻟﺍ ﻭﻫ ﻲﻤﺠﺤﻟﺍ ﻡﺩﻘﺘﻟﺍ ﻭﺃ لﻋﺎﻔﺘﻟﺍ ﻡﺩﻘﺘ لﺼﻴ ﻲﻜﻟ
ﺔﻴﺌﺎﻬﻨﻟﺍ ﻪﺘﻤﻴﻗ ﻑﺼﻨ ﻰﻟﺇ ...
ﻥ 1
ﺩﺠﻨ ﻥﺎﻴﺒﻟﺍ ﻥﻤ
½ =12s τ
...
ﻥ 1