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a 1,a 2,a 3,...berealnumbersgeneratedbythefollowingrule.Therstnumber,a 1,equals 1,andthereaftereahnumberequalsthepreviousnumberplusitssquareroot.Thissimplystated

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Épreuve de setion européenne

A simple sequene not given by a simple formula

Let

a 1

,

a 2

,

a 3

,...berealnumbersgeneratedbythefollowingrule.Therstnumber,

a 1

,equals 1,andthereaftereahnumberequalsthepreviousnumberplusitssquareroot.Thissimplystated

rule raisesan obvious question :what is thenumber

a n

?

To get a feel for the question, let us work out

a n

for a few small values of

n

. We have

a 2 = 1 + √

1 = 2

.Then

a 3 = 2 + √ 2 a 4 = 2 + √

2 + q

2 + √ 2

andsoon.Notiethattheexpressionsontheright-handsidedonotseemtosimplify,andthat

eah new one is twie as longas theprevious one. From this observation it follows quiteeasily

that theexpressionfor

a 12

wouldinvolve 1024 ourenes ofthenumber 2,most ofthem inside ajungleofsquareroots.Suhanexpressionwouldnot giveus muhinsightintothenumber

a 12

.

Adaptedfrom Mathematis, AVery ShortIntrodutionbyTimothyGowers

Questions

1. Translatethe denition ofthesequene

a n

asa relationbetween

a n+1

and

a n

.

2. Givetherawformulafor

a 5

.

3. Explain the sentene Notie that the expressions on the right-hand side do not seem to

simplify,and thateahnew one istwieaslongastheprevious one.

4. Prove thatthe expression of

a 12

wouldinvolve 1024 ourenesofthe number 2.

5. Theaim ofthe following questionsistoount thenumberof squareroot signsin

a n

.Let's denote thisnumber by

u n

,for any naturalnumber

n

.

a. Find out the valuesof

u n

for

n

from 1to 5.

b. Prove byindutionthat

u n = 2 n 1 − 1

.

. Use theformulato ompute thenumberof squareroot signsin

a 12

.

Références

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