R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
A. B ALLESTER -B OLINCHES
M. C. P EDRAZA -A GUILERA
M. D. P ÉREZ -R AMOS
On Π-normally embedded subgroups of finite soluble groups
Rendiconti del Seminario Matematico della Università di Padova, tome 96 (1996), p. 115-120
<http://www.numdam.org/item?id=RSMUP_1996__96__115_0>
© Rendiconti del Seminario Matematico della Università di Padova, 1996, tous droits réservés.
L’accès aux archives de la revue « Rendiconti del Seminario Matematico della Università di Padova » (http://rendiconti.math.unipd.it/) implique l’accord avec les conditions générales d’utilisation (http://www.numdam.org/conditions).
Toute utilisation commerciale ou impression systématique est constitutive d’une infraction pénale. Toute copie ou impression de ce fichier doit conte- nir la présente mention de copyright.
Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
http://www.numdam.org/
of Finite Soluble Groups.
A. BALLESTER-BOLINCHES
(*) -
M. C.PEDRAZA-AGUILERA (*)
M. D.
PÉREZ-RAMOS (*)
1. - Introduction and statement of results.
All groups considered in this paper are finite and soluble.
Let 1l be a set of
primes.
Asubgroup H
of a group G is said to ben-normary
embedded in G if a Hall1l-subgroup
of H is also a Hall Jr-subgroup
of some normalsubgroup
of G. A HallR-subgroup
of a normalsubgroup
of G is an obviousexample
of a;r-normally
embedded sub-group of G. This
embedding property
was studiedin [I]
and[2].
Thepresent
paperrepresents
anattempt
to carry thisstudy
further. In factwe
analyze
whatproperties
related top-normal embedding property ( ~
aprime number)
can be extended to a set ofprimes
,~.Our first Theorem concerns Snormalizers associated to a saturated formation ! Chambers
[3] proved
that in a group G with abelianSylow p-subgroups,
the ff-normalizers of G arep-normally
embedded inG,
where T is saturated formation. We prove:THEOREM 1. Let T be a saturated
formation. If
G is a group withabelian
Hall R-subgroups,
then the tf-normalizersof
G are1l-normally
embedded in G.
Let 1l be a set of
primes.
Asubgroup
U of a group G is said to be;r-pronormal
in G if U and U9 areconjugate
inU9))
for
all g
E G. Note that the1l-pronormality
isjust
the1Kpronormality
introduced in
[6]
when T is the saturated formation of all soluble(*) Indirizzo
degli
AA.:Departament d’Algebra,
Universitat de Val6neia,C/Doctor
Moliner 50, 46100 Burjassot (Val6neia),Spain.
116
a-groups. This
embedding property
isclosely
related to jap-normalembedding
one as it is shown in thefollowing
Theorem.THEOREM 2. For a
a-subgroup
Uof
a groupG,
thefollowing
state-ments are
equivalent:
(i)
U is7r-normally
embedded in G.(ii)
U is7r-pronormal
in G and a CAPsubgroup of
G.(iii)
Upermutes
with every Hall.7r’-subgroup of
G and is normal- izedby
each Hall.7l-subgroup of
Gcontaining
it.Wood [5]
proves thefollowing
result:THEOREM
(Wood).
Let p be aprime
and let G be a group. The fol-lowing
statements arepairwise equivalent:
(a)
All the maximalsubgroups
of G arep-normally
embedded in G.(b) Every Sylow p-subgroup
of every maximalsubgroup
of G ispronormal
in G.(c)
G hasp-length
at most one.The obvious extension of Wood’s Theorem to a set of
primes
Jr doesnot hold. Let H be the
symmetric
group ofdegree
3. It is known that H has an irreducible and faithful module overGF(5),
the finite field of 5elements,
V say. Let Jr ={ 2, 5 }
and G =[V] H.
Then the Hall a-sub- groups of the maximalsubgroups
of G arepronormal
in G. However then-length
of G isbigger
than 1.THEOREM 3. be a set
of primes.
Let G be a group. Thefollow- ing
statements areequivaLent:
(i)
All maximalsubgroups of
G are7r-normally
embedded in G.(ii) Every
Hall;r-subgroup of
a maximalsubgroup of
G is .7l-pronormal
in G.If either
(i)
or(ii) hold,
then G hasJr-le%gth
at most one.The
symmetric
group ofdegree
3 hasJr-length
one for ;r ={ 2, 3 }.
However the maximal
subgroup ((12))
of G is not.7l-normally
embeddedin G. So the assertion in Theorem 3: G has
Jr-length
at most one, doesnot
imply (i)
and(ii)
ingeneral.
2. - Preliminaries.
In this section we collect some results which are needed in
proving
our Theorems. All the known results
concerning
finite soluble groups which we will need appear in[4].
This book is the main reference for the notation andterminology.
From now on jr will be a set of
primes.
LEMMA 1
[2].
Let U be an-normally
embeddedsubgroup of
agroup
G, K
a norn2alsubgroup of G,
and L asubgroup of
G.Then:
(i) If
U is asubgroup of L,
then U isor-normally
embedded in L.(ii)
UK isn-normally
embedded in G andUK/K
isn-normally
embedded in
G/K.
(iii) If K is a subgroup of L and L/K is a-normally
embedded inG/K,
then L isn-normally
embedded in G.LEMMA 2. Assume that T is a set
of primes
fl r = 0. Let P bea
n-subgroup of a
group G and letQ
be ar-subgroup of G. Suppose
thatP is
n-normally
embedded in G andQ is i-normally
embedded in G.If (P, Q) is
a(z
Ui)-group,
thenPQ
=QP.
PROOF.
By
virtue of Lemma1,
we have that P is an-normally
em-bedded
subgroup
in T =(P, Q)
=P[P, Q] Q.
So P is a Hall7r-subgroup
of its normal closure =
P[P, Q].
SinceQ
is ar-group and r n.7r =0,
it follows that P is a Hall
7r-subgroup
of T.Analogously
we have thatQ
is a Hall
r-subgroup
of T. Thisimplies
that T =PQ
=QP
because T is a(i
Ur)-group.
LEMMA 3.
If
a group G has an abelian Hall then G hasn-length at
most one.PROOF. Consider the upper n’ n-series of G:
where
No
=0,,, (G), P,
=0,,, (G)
andNl /P1
= Let H be aHall
,r-subgroup
of G.By ([4] [1; (3.2)]),
we know thatHNO /No
is a Hall.1l-subgroup
ofG/No .
Since =0,, (GINO)
is a normalsubgroup
ofG/No ,
it follows thatHNo /No .
NowHNo /No
is abelian. Thisimplies
thatPI/No by
virtueof [7].
In par-ticular H 5
PI
andGIP,
is then a.1l’-group.
This means thatA7i
= G andG has
.7r-length
at most one.118
3. - Proofs of the Theorems.
PROOF OF THEOREM 1. We argue
by
induction onG ~ .
Let D be an~normalizer of G associated to the Hall
system E
of G. It is clear thatwe can assume that D G. Let N be a minimal normal
subgroup
of G.Then
DN/N
is an Snormalizer of G associated to the Hallsystem
ENIN
ofG/N ([4] [V; (3.2)]).
SinceG/N
has abelian Halla-subgroups,
it follows that
DN/N
isn-normally
embedded inG/N
and so DN is Jr-normally
embedded in G. Assume thatN1
andN2
are two distinct mini-mal normal
subgroups
of G. ThenDNi
isa-normally
embedded in G for~~{1,2}.
Since Z reduces inDNI
andDN2 ,
we have that is.7r-normally
embedded in Gby ([2] [Th.1]). Now, by ([4] [V; (3.2)]),
D ei-ther covers or avoids
Ni .
IfNi
D forsome i,
it follows that D ismally
embedded in G and we are done. So D avoidsN,
andN2 .
This im-plies
that D =DN, n DN2
isa-normally
embedded in G and we aredone.
Consequently
G has aunique
minimal normalsubgroup,
N say.Then
F( G )
is a p-group for someprime
p. Since DN isa-normally
em-bedded in
G,
we havethat p
e a. Inparticular, ( G )
= 1 and G has anormal Hall
n-subgroup H
because G hasjr-length
at most oneby
Lem-ma 3. Since H is abelian and
F(G) ~ H,
it follows that H ~CG (F( G )) ~
~
F(G).
This meansthat F(G)
is an abelian Halla-subgroup
of G.By ([4]
[V; (3.6)
and(3.7)]),
there exists a maximalsubgroup
M of G such thatG =
F(G)M
and D is an Snorrnalizer of M.By induction,
D is Jr-normal-ly
embedded in M. Let A be a Halla-subgroup
of D. Then A is a HallJr-subgroup
of(Am).
Since D ~F(G)
andF(G)
isabelian,
we havethat
(A~) = ~A G ~
and so(Am)
is a normalsubgroup
of G. Therefore D isa-normally
embedded in G and the Theorem isproved.
PROOF OF THEOREM 2.
(i) implies (ii).
Since U is a Hallsubgroup
of a normal
subgroup
ofG,
it follows that U ispronormal
in G.Then,
there exists x e J =
(U, ug)
with Ug = Ux .By
Lemma1,
U is .7r-nor-mally
embedded in J andUOR(J)/OR(J)
is.7r-normally
embedded inwhich is a n-group. This
implies
that J =UOR(J).
In par- ticular x = uz, with u E U and z EOR(J).
So U9 = Ux = Uz and U isa-pronormal
in G.Let
H/K
be a chief factor of G. IfH/K
isan’ -group,
then U avoidsH/K.
Assume thatH/K
is a n-group. Let T be a Hallsystem
of G reduc-ing
into U. Then E reduces into UK.By
Lemma1,
UK isJl-normally
em-bedded in G. Since T also reduces into
H,
we have that isn-normally
embedded in Gby ([2] [Th.1]).
Inparticular,
UK n H is also subnormal inG,
we have that and U either covers oravoids
H/K.
Therefore U is a CAPsubgroup
of G.(ii) implies (i).
Assume that U isR-pronormal
in G and a CAPsubgroup
of G. We prove that U isR-normally
embedded in Gby
induc-tion on
G 1.
Let N be a minimal normalsubgroup
of G. SinceUN/N
isn-pronormal
inG/N
andUN/N
is a CAPsubgroup
ofG,
we have thatUN is a
R-normally
embeddedsubgroup
of Gby
induction. If N is a;r’-group,
then U isn-normally
embedded in G and we are done. Hencewe may assume
(G)
= 1. Now U isR-pronormal
in UN and UN is n-group. This means that U is a normalsubgroup
of UN.Moreover,
Ueither covers or avoids N. If N
U,
then U isR-normally
embedded inG and we are done. Thus and U ~
CG (N).
Therefore we may assume that U centralizes every minimal normal
subgroup
of G. With the samearguments
to those used in([4] [I;
(7.12)]),
we conclude that U is normal in G and so U isR-normally
em-bedded in G.
(i) implies (iii).
Assume that U isR-normally
embedded in G and letGR’
be a HallR’-subgroup
of G.By
Lemma2,
Upermutes
withGR’,
because
G¡r’
is;r’-normally
embedded in G.Let
GR
be a HallR-subgroup
of G such that UGR.
Since U isn-normally
embedded inG,
we have that U isa-normally
embeddedin
G~ .
This means that U is normal inG,~ .
HenceG,~
normalizes U..
(iii) implies (i). Suppose
thatG ¡r’
is a Hallir’-subgroup
of G suchthat
GR’ permutes
with U and letGR
be a HallR-subgroup
of G suchthat U ~
G,,.
Then U is normalizedby G~ .
Moreover G =G¡rG¡r’
andhence Since U is a Hall
R-subgroup
ofUGR’
andU 5
( UG ) ,
it follows that U is a Hall.7r’subgroup of ~ UG ~
and U isR-normally
embedded in G.PROOF OF THEOREM 3. Since the maximal
subgroups
of G are CAPsubgroups
ofG,
it follows that every Hallx-subgroup
of every maximalsubgroup
is a CAPsubgroup
of G. So theequivalence
between(i)
and(ii)
in Theorem 3 follows from theequivalence
between(i)
and(ii)
inTheorem 2. Assume that there exists a group G such that G has the
property (i)
but G does not haveR-length
at most one. Let us considerG of minimal order. Since the
property (i)
is invariant underepimorphic images,
we have thatG/N
hasR-length
at most one for every minimalnormal
subgroup
N of G. Since the class of all groups withR-length
atmost one is a saturated
formation,
it follows that G has aunique
mini-mal normal
subgroup,
N say, such that G = MN and M n N = 1 forsome maximal
subgroup
M of G.By hypothesis
M isR-normally
embed-ded in G. If N is a n-group, then M should be
an’ -group
and then G hasR-length
at most one, a contradiction. So N must be But then G also has7r-length
at most one, a contradiction.120
REFERENCES
[1] A. BALLESTER-BOLINCHES - M. D.
PEREZ-RAMOS, Permutability in finite
sol-uble groups, Math. Proc. Camb. Phil.
Soc.,
115 (1993), pp. 393-396.[2] A. BALLESTER-BOLINCHES - M. D. PÉREZ-RAMOS,
03C0-normally
embedded sub- groupsof finite
soluble groups, Rend. Sem. Mat. Univ. Padova, 94 (1995), pp.113-119.
[3] G. A. CHAMBERS,
p-normally
embeddedsubgroups of finite
soluble groups, J.Algebra,
16 (1970), pp. 442-455.[4] K. DOERK - T.HAWKES, Finite Soluble
Groups,
Walter DeGruyter,
Berlin, New York (1992).[5] G. J. WOOD, On
pronormal subgroups of finite
soluble groups, Arch. Math.,25 (1974), pp. 578-588.
[6] N.
MÜLLER,
F-PronormaleUntergruppen
endlichauflösbarer Gruppen, Diplomarbeit,
JohannesGutenberg-Universität,
Mainz (1985).[7] D. J. S. ROBINSON, A Course in the
Theory of Groups, Springer-Verlag,
New York,Heidelberg,
Berlin.Manoscritto pervenuto in redazione il 9 febbraio 1995
e, in forma revisionata, 1’8