R ENDICONTI
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M ARTA M ORIGI
A note on factorized (finite) p-groups
Rendiconti del Seminario Matematico della Università di Padova, tome 98 (1997), p. 101-105
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MARTA MORIGI
(*)
Dedicated to
Prof.
Zacher, on his 70-thbirthday
A group G is factorized if it has the form G =
AB,
where A and B aretwo proper
subgroups
of G. A lot of work has been done toinvestigate
how the structure of A and B influences the structure of
G,
and in this direction there is a famous theoremby
Ito which states that if A and Bare abelian then G is
metabelian [6,
p.384]. Moreover, Kegel
andWielandt
proved that,
in the case of finite groups, if A and B arenilpo-
tent then G is soluble
[6,
pp.379-382].
From these results
originates
thefollowing:
CONJECTURE.
If
A and B arefinite nilpotent
groupsof
classes aand
{3 respectively,
the derivedlength of G
is boundedby a function of
aperhaps
a +{3.
Elisabeth
Pennington proved
theconjecture
when A and B have co-prime orders,
with the functiongiven by
a +fl,
and showed that theproblem
ofbounding
the derivedlength
of G can be reduced to the caseof p-groups
[5].
But in this critical case nogeneral
result is known.A very
special
situation is examinedby
MeCann,
whoproved
that ifG = AB is a finite p-group, with A abelian and B
extraspecial,
then thederived
length
of G is at most 3[2].
In this note we are able to be a little more
general,
with thefollowing:
(*) Indirizzo
degll’A.:
Universitadegli
Studi di Padova,Dipartimento
di Ma-tematica Pura ed
Applicata,
via Belzoni n.7, 35131 Padova,Italy.
102
THEOREM 2. Let G = AB be a
finite
p-group, where A is abelian and B’ has order p. Then oneof
thefollowing
must occur:i) A G B ’
is theproduct of
two abelian groups.ii) B ~ G
is abelian.In both cases, the derived
length of
G is at most 3.Examples
of groupssatisfying
theassumptions
andhaving
derivedlength
3 areeasily constructed;
for instance it isenough
to considerthe wreath
product
of a group of order p with a non-abelian group of or-der
p 3 .
Theorem 2 can be obtained
by specializing
a moregeneral proposi- tion,
which bounds the derivedlength
of a factorized finite p-group G =AB,
where A isabelian,
in terms of the order ofB’,
the derivedsubgroup
of B. Moreprecisely,
we have:THEOREM 1. Let G = AB be a
finite
p-group, where A is abelian and then the derivedlength of
G is at most n + 2.A theorem of the same flavour was obtained
by
Kazarin[4],
whoproved
that if G = AB is a finite p-group, such thatlA’ I = pm
andI B’ = pn ,
then the derivedlength
of G is at most 2m + 2n + 2. Com-bining
this with Theorem 1 it is alsopossible
to prove:THEOREM 3. Let G = AB be a
finite
p-group, such thatand
B’ ~ = p n ,
with m ~ n, then the derivedlength of
G is at mostm+2n+2.
In the
proof
of these thorems thehypothesis
that the groups consid- ered are finiteplays
an essential role.Nevertheless,
afterhaving proved
Theorem 1 in the finite case, it ispossible
to prove it for infinite groups as well. Moreprecisely
we have:THEOREM 2’. Let G = AB be a group, where
A,
B are p-groups, such that A is abetian then G is soluble and has derivedlength
at most n + 2.Here the notation used is standard and in
particular
thesymbol HG
denotes the normal closure of a
subgroup
H in a groupG,
i.e. the small-est normal
subgroup
of Gcontaining
H.Moreover, Z( G )
denotes thecenter of the group
G,
G ’ is the derivedsubgroup
ofG, (g)
is the sub-group
generated by
g E G and[x, y]
is the usual commuta-tor,
for X, y E G.To prove the
theorem,
two results are needed which areprobably
known but the author could not find them in the literature stated in the
following
form.LEMMA 1. Let G = AB be a group, with A abelian and
Z(G) ~ 1;
then there exists a non-trivial normal
subgroup
Nof
G such that N ; Aor N~B.
PROOF. Consider 1 ~ ab E
Z(G),
with a E A and b E B. We may as-sume a ~ 1 ~ b. Then for each x E A we have 1 =
[ab, x]
= is a normalsubgroup
of G contained inB,
as we wanted.
Note that Lemma 1 is no
longer
true if wedrop
thehypothesis
thatA is
abelian,
even for finite p-groups, as anexample
of Gillamshows
[3].
LEMMA. 2. Let G = AB be a group, V 5
Z(A),
W 5Z(B)
such that AW = WA and VB = BV aresubgroups;
then[V, W] ~ Z([A, B]).
PROOF The
proof
is the same as Ito’s(see [5]).
Let a
E A,
b EB,
al EV, 61
EW,
andput
=a2 b2, a bl
whereal E V and
b3
E W. Then:The statement now follows
immediately.
Another Lemma is
needed,
whoseproof
is trivial:LEMMA 3. Let K be a p-group such that K’ has then the derived
length of
K is at rrzost k + 1.PROOF OF THEOREM 1. The
proof
isby
induction on n, where.
For n = 0 the theorem is true
by
Ito’s result.We now assume that it is true for each natural number less or
equal
than n - 1.
104
If
AnB~Z(B)
then is anormal
subgroup
of G contained in B and such that N n B’ ~ 1.If N is abelian then
d(G) 5
n + 2 becauseI (BIN)’ I ~
and soby
induction + 1.
If N is not abelian then N’ a G has 1. Moreover
=
soby
induction t + 2. Asd(N’ ) ~ t
the result follows. So w.m.a. A n B ~
Z(B).
We now prove the
following
statement:There exists W ~
Z(B)
such that AW = WA and 1 ~ T = AW n B’ . Choose a maximalsubgroup
W ~Z(B)
such that AW is asubgroup
and assume
by
contradiction that AW n B’ = 1. Put K =(AW)G ,
thecore of AW in G. Then
G/K
= andAKIK
is core-free.By
Lemma 1 there exists a minimal normal
subgroup N/K
ofGIK
such thatN ~ BK and so
N = ZK,
where Z = B n N is not contained in K. Ofcourse, as the groups considered are finite and
nilpo-
tent. so
Z Z(B).
It follows thatAWZ = AWN is a
subgroup,
as N N G. MoreoverZ ~ W,
otherwise wewould have ZK ~ = K. As WZ ~
Z(B),
this contradicts the max-imality
ofW,
and we haveproved
the statement.~Ve have T ~ AW n B =
(A n B)W ~ Z(B ),
and moreoverTA,
;
[A, AW] _ [A, W] ~ Z([A, B]) by
Lemma 2.Consider
A G
=A(A G
nB).
If T ~(A G
nB)’,
then T ~[A, B]
be-cause
A[A, B]/[A, B] = A/(A
n[A, B])
is abelian. It follows thatT G
=T[A, T]
is abelian.By
induction +1,
sod(G) ~ n
+ 2Now assume
T ~ (A G n B )’
and considerA G T,
which is normal in Gas T ~
Z(B).
We have
AG T = A(AG T n B) = A(AG n B)T,
-so= (A n B)’,
as T ~Z(B).
Let We haveI A G Tn
n B ’ ~
= p m + t ,
where t > 1 because andT ~ ( (A G n
n B ) T )’ . By
induction derivedsubgroup
of))
has orderp n - cm + t~,
, so-
( m
+t )
+ 1by
Lemma 3. It follows thatd(G) 5 n + 2 - t + 1 5 n + 2
and theproof
iscomplete.
PROOF OF THEOREM 2. It is
enough
to gothrough
theproof
of The-orem 1 once more,
considering n
= 1 andkeeping
in mind that the sub-group T considered is
actually
B ’ .PROOF OF THEOREM 3. The
proof
isby
induction on n .+ m and fol-lows
exactly
the samesteps
as Kazarin’sproof [4].
PROOF OF THEOREM 2’. Note that
by Corollary
7.3.10of [1]
G thereis a soluble normal
subgroup
M of G such that G/M is finite. As AM/M andBM/M
are finite p-groups,G/M
=(AM/M)(BM/M)
isnilpotent,
thus G is soluble. From this follows that G is
locally
finite. Let g E EG(n + 2~,
the( n
+2)-th
term of the derived series of G. There exists a fi- nite set X= I ai, bi aci
eA, b~
EB, i
=1,
... ,r; j
=1,
... ,s}
such thatLet Ao = ~ ac2 ~ i
=1, ... , r), Bo
=(B’,
=1,
... ,s ~. Then Ao
andBo
are finite and
(X) % ~Ao , Bo ~. By
Lemma 1.2.3 of[1]
there exists a finitesubgroup H
of G such that~Ao ,
=Ap-
plying
Theorem 2 to H we obtain thatH (n
+ 2) = l and thusG ~n + 2~
=1,
as g was an
arbitrary
element ofG ~n + 2~.
The
proof
is nowcomplete.
REFERENCES
[1] B. AMBERG - S. FRANCIOSI - F. DE GIOVANNI, Products
of Groups,
OxfordMathematical
Monographs,
Clarendon Press, Oxford (1992).[2] B. MC CANN, A note on the derived
length of products of
certain p-groups, Proc. R. Ir. Acad., 93A, No 2 (1993), pp. 185-187.[3] J. D. GILLAM,
A finite
p-group P = AB with core(A) =core(B) ={1}, Rocky
Mountain J. Math., 3, No 1 (1973), pp. 15-17.
[4] L. S. KAZARIN, The
product of two nilpotent
groups (in Russian), Problems ingroup
theory
andhomological algebra,
Yaroslavl Gos. Univ., Yaroslavl (1982), pp. 47-49.[5] E. A. PENNINGTON, On
products of finite nilpotent
groups, Math. Z., 134 (1973), pp. 81-83.[6] W. R. SCOTT,
Group Theory,
Prentice-Hall, Inc.,Englewood Cliffs,
New Jer-sey (1964).
Manoscritto pervenuto in redazione il 5 febbraio 1996.