R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
G IOVANNI B ASSANELLI
On horospheres and holomorphic endomorfisms of the Siegel disc
Rendiconti del Seminario Matematico della Università di Padova, tome 70 (1983), p. 147-165
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Horospheres Holomorphic
of the Siegel Disc.
GIOVANNI BASSANELLI
(*)
RIASSUNTO - Introdotte le nozioni di orosfera e di orocielo nel cerchio d
Siegel 8
si estende and 8 il classico lemma di Julia. Si prova, inoltre, chese F 6 un endomorfismo olomorfo di 8 con comportamento «
regolare
» suun orociclo e vicino ad un
punto
del bordo, allora F 6 un automorfismo.Introduction.
The
concept
ofhorocycle
andhorosphere
in the unit disc of C have been introducedby
Poinear6 with an immediate andsuggestive interpretation:
«the[h]orocycles
may beregarded [...]
as the loci ofpoints having
the same distance from a non euclidean line that lies atinfinity)> ([3], § 82).
Similar notions ofhorospheres
can be definedin the unit ball
Bn (for
the euclideannorm)
of Cn. Thehorospheres
of
Bn
are characterised in terms of theKobayashi distance,
y whichplays,
in this case, the role of the Poinear6 distance(see [12]).
Oneof the most
important
results abouthorospheres
is the classical Julia’s lemma.P. C.
Yang (see [12]
and[8])
has extended theseconcepts
andJulia’s lemma to
strictly pseudo-convex
domains of~n,
with smoothboundary.
In this paper, we shall introduce the notions of
horosphere
andhorocycle
in theSiegel
disc 8. We characterise the0160ilov boundary
of
horospheres
in terms of theKobayashi
distance(Theorem 1.6)
(*)
Indirizzo dell’A.: Scuola NormaleSuperiore,
Pisa.and we establish an extension of Julia’s lemma
(Theorem 2.5).
Inthe last
part
of the article it isproved
that if .I’ is aholomorphic endomorphism
of8,
which behaves« regularly»
on ahorocycle
andnear a
boundary point
of8y
thenF e Aut(6) (Theorem 5.3).
Com-parison
with ananalogous
theoremconcerning
theendomorphisms
of
Bn suggests
that similar resultsmight
hold for other classical domains.§
1. - This section is devoted to theproof
of Theorem 1.6(which
establishes a connection between the
Kobayashi
distance andSilov horocycles)
and of Theorem 1.7 about the behaviour ofautomorphisms
on
horocycles
andhorospheres.
For the
points
of Cm we use thenotation $ = (~1’ ~2’
... ,~m)
andwe set As usual
will denote the canonical base of C’n. For any m X m,
complex matrix Z, 11 Z 11
will be theoperator-norm
Let be a natural
number;
we denoteby ,S(N; C) (respectively S(N; R))
the set ofN X N, complex (resp. real) symmetric matrices;
by U(N; C)
the set of N XN, complex unitary
matrices.The
Siegel
dise is the setwhere I is the
identity
matrix of orderN,
andI - ZZ
> 0 meansthat I - ZZ is
positive
definite. TheSilov boundary
of 8 isThe group
Aut(8)
has been determinedby
C. L.Siegel
in[11].
For any the map
Øzo
definedby
belongs
toAut(6).
The set of allØzo
whenZo
varies on 8 is a sub- groupacting transitively
on 8. For any there exists U EE
U(N; C) and
E 6 such thatW(Z)
=(Z E 6).
This for-mula and
(1.1)
show that everyautomorphism P
is defined in aneigh-
bourhood
of 9
andIf (as 6)
=1.1. DEFINITION.
is called
horosphere; W)
is calledhorocycle,
and theSiZov
horo-cycle is, by definition
1.2. REMARK.
The
Carath6odory
andKobayashi
metrics and distances on 6 coincide(see [4],
Theorem IV.1.8 and LemmaV.1.5)
and we can statethe
following
1.3. DEFINITION.
Z, WE 6;
the distance between Z and1.4. LEMMA. Let and
are
defined
thenPROOF. See
[9],
p.145,
formula(2)
.For s1, s2 , ... , sN E
R+, [si,
82’ ... , will stand for thediagonal
matrix
PROOF. See
[11],
Lemma1,
p. 12 o1.6. THEOREM. Let Z E
B,
W Ea, B,
k ERt.
Then Z Ea, H (k, W) if
andonly if
PROOF. Let then
(1.3)
isequivalent
toi.e.
(by (1.2))
toAssume that
(1.4)
holds. Let iThen,
for eacht,
and,
in view of(1.4),
as iby
Lemma 1.5 there exists Y E such thattherefore
Let Bj
=[0,
... ,0, 1, 0,
... ,0].
Condition(1.4) yields
with Tn view of
(1.5)
Hence Moreover
putting
since This proves that
(1.4) W ).
To prove the converse, let
Hence
as
We
investigate
now howautomorphism
transformshorospheres.
PROOF. There exist U E
U(N; C)
andZo
e 6 such that SinceHence, using (1.2)
we have§
2. we show that eachhorosphere is,
in some wTay, the limit of a sequence of ball for the distance d(Lemma
2.2 and2.3).
Thisresult and the fact that
holomorphic endomorphisms
contract d enableus to prove an
analogous
of Julia’s lemma(Theorem 2.5).
We
begin by establishing
thesepreliminary
lemmas.2.1. LEMMA. Let every r E
(0, 1 ),
thefollowing
con-ditions are
PROOF.
in view of
(1.1). Multiplying
on the leftby
the matrixr(I
-ZZo)’
.
(I
-Zo Zo)-2
and on theright by
itsadjoint
weget
and,
if it issufficiently large,
ure must haveThe conclusion follows from Lemma 2.1 m
2.3. LEMMA. Let be a sequence con-
PROOF. In view of Lemma
I for
infinitely
many n E N.Then,
2.4. REMARK. Let W E and let
(Zn)neN
be a sequence con-verging
to W. ThenPROOF. Let M > 0. Since
0,
there is suchmorphism. Suppose
there is a sequence such thatand there exists a E
Rt
such thatT hen ~ -A
PROOF. Let
W ).
We can assume, without any restric- tion thatBy previous
Remark we candefine,
y for nsufficiently large,
therefore
It
follows,
from Lemma2.2,
that there exists no E N such thatSince F is a contraction
for d,
but
Lemma 2.3
yields F(Z)
EH(k, W )
§
3. H. Alexander hasproved
in[1]
that if S2 is a domain of Crt(n
>1)
with S~ r’1 and if F: Q - Cn is aholomorphic
map such thatF(Q
r1 c then .~ is constant or .I’ extends to anautomorphism
ofReplacing
Cnby S(N; C) (N > 1)
andBn by 9
some of the
machinary
involved in theproof
of H. Alexander cannot beadapted
because 38 is not a smoothhypersurface.
Then we canestablish
only
some first consequences ofprevious hypothesies (see
Theorem
3.6).
The
Siegel
upperhalf-plane
is the set Je ={X
+i Y; X,
Y ES(N; R)
and Y >
0}.
It is well known(see [7],
p.5)
that theCayley
trans-formation Z -
(j(Z)
=i(I
-E-Z)(I - Z)-l maps E bi-holomorphically
onto H. Moreover the
0160ilov boundary 8sH
of H is definedby
thetwo
equivalent
conditions3.1. LEMMA. Let S be a smooth real
submanifold of S(N; C)
suchand S n
as B -=1=
0. Then1)/2.
PROOF.
Replacing 8 by H
we can assume 0 Let n ==
dim s,
then there is a C°° mapX +
iY:~S(N; R) + i,S(N; R)
such that =
Y(O)
= 0 andY(s) > 0
for all s ERn. Moreover thejacobian
matrix[aXIas, a Y/as]
has rank n.Let Y = It is
enough
to prove that = 0 for1 ~ i c j ~ N, a = 1, 2, ... , n.
Sinceyii(O) = 0
and forall s,
then = 0. For all
and therefore
and
It follows that
then
3.2. LEMMA. Let U E There exists a smooth real
manifold
Sof S(N; C)
such that U 86 andN(N
+1)/2
PROOF.
Replacing E by JC
we can ass-Limewith
XoES(N;R),
where A is anorthogonal
matrix of orderN, d2 , ... ,
and0, d2 =
0. Then(X, t )
-X +
... ,with X E
S(N; R)
and t E R+ is therequired parametrization e
3.3. LEMMA. Let Q be a domain in
S(N; C)
such that Q r1 -=I=- 0.Let F be a
diffeomorphism of
Q onto an open subsetF(S2) of S(N; C).
If F(Q
r138)
c38,
then n8s 8)
ca,
8.PROOF. We
begin by showing
thatF(S2
r138)
is open in 38. Since is the unit ball for a norm inS(N; ~) _
RN(N+I)equivalent
to theeuclidean norm, then 86 is
homeomorphic
to SN(N+1)-i .Then, by
Theo-rem 6.6 in
[6]
Ch.III,
it isenough
to notice that38)
is ahomeomorphism
and r1 86 is open in 38.and suppose
F(Z)
Eo E"’" Os 8. By
Lemma 3.2 thereis smooth real submanifold S such that
F(Z)
E S cF(Q
n anddimRS> N(N +1)/2. Thus, by
Lemma3.1,
This is a contradiction
For and
C),
let3.4. LEMMA. Let 0 r 1. There exist an open
neighbourhood
Eof
theidentity
matrixI,
a- continousfunction f
on and F, > 0 such that(ii) f
isplurisubharrnonic
onLet . therefore
hence I
Forany ~
with~~~~~ ))
=1,
we haveIf O is such that
(I - r 214N)~’ 1,
then(i)
is satisfied.The function Lemma
11.6.2).
is
plurisubharmonic (see [4~,
If follows that
It follows
3.5. REMARK. Let f2 be a domain in
S(N; C)
such that S2 r1 ~ 0.If f : ,S2 -~ ~
is aholomorphic function
such thatf(Z)
=0, for
every Z EQ
r1a, 8,
thenf
= 0 inQ.
PROOF. In view of
(3.1) Q
r’1 isbi-holomorphically equivalent
to an open subset of
3.6. THEOREM. Let Q be a domain in
C)
such that Q r1 0 0.If
F:~ -~ S(N; C)
is aholomorphic
map such thatF(Q
r186,
then one
of
thefollowing
statements holds:(i)
There such that the map .~ H.F’(Z) ~
isconstant;
(ii)
There isZ
e such thatdF(2)
is invertible and there is an openneighbourhood S~1 of 2
such that cPROOF. If there is
Z
E Q r1 such thatdF(2)
isinvertible,
then the theorem follows from Lemma 3.3. Therefore it is
enough
assume
det dF(Z)
= 0on 42
r1 and prove(i).
Henceby previous Remark, det dF(Z)
= 0 onQ.
If N =1,
then .F is a constant map.Let N > 1. Since max rank
dF(Z)
= nN(N
-E--1)/2,
there existsZeQ
a minor M =
M(Z)
ofdF(Z)
of order n such that det 0 fora suitable A. Still
by
Remark 3.5 there is B E Q r1 a6s
such thatdet 0.
Replacing
.Fby
for a suitable 0 E there is no re-striction in
assuming
B = I. LetSince
(Z
EQ), by
theimplicit
function theo-rem there
exists r,
such that all the arefunctionally dependent
on onFjlhl’
... ,Fj nhn -
With the same notations as in Lemma 3.4 let
and let T be the set defined
by
Then T n n
8)
~ 0.(In
fact in aneighbourhood
of I .T’ is bi-holomorphically equivalent
to an affinesubspace).
The functionf
attains its maximum on T r1 17 m 6 in a suitable matrix
Zie
r18)
(see [5],
p.272).
In view of Lemma3.4,
Then=
F(Z1)
E 38. It follows that there exists with11
=1,
such that
II
- 1.Let Z2
be a matrix nearZo .
ThenZo
+k(Z2 - Zo)
E 17 m 6 rlBe(I)
for
every A
e C with121
1.Therefore, by
theprevious argument
It follows
11 Hence,
by
thestrong
maximumprinciple
for each Â. Thus
F(Z) ~o
is constant 1§
4. In this section we shall show that if .F is aholomorphic endomorphism
of 8 which maps apiece
of theSilov horocycle 8sH(1 , 1)
into the same
0160ilov horocycle
and behaves«regularly
» near apoint
of
a, 8~
then Fmaps 8
r1 intoH(k, I )
forevery k
ERt (Theo-
rem
4.4).
The group A c
S(N; R)l
is a group of automor-phism
of je which actstransitively
on For A ES(N; R),
letVA(Z) -
+A) (Z E 8).
SincePAE
we can extendPA
in a
neighbourhood
of6.
4.1. PROPOSITION. The set
subgroup of
Aut(6)
which actstransitively
ona,
8*.Moreover, for
all A ES(N; R), (i) PA(I) + Ii
(ii)
EI).
PROOF. To prove
(i)
it isenough
toverify
that4.2. LEMMA. Let
U,
V E and 7~ ERt. I f det( U - V)
=Aø
thenthere exists
PEÂut(E)
such thatPROOF. In view of Lemma
1.5,
there exists suchthat U = T tT. Let W =
tT TlT.
Sincedet(I - W )
=det( U - V) # 0, by Proposition 4.1y
there exists A eS(N; R)
such that!f~(W) = 20137.
Let
~(Z) =
Since~((1_~)/(1+k))I(~)
EI)
and =
I,
the lemma follows from Theorem 1.7 andProposition
4.1 .4.3. Then
PROOF. It
follows,
from Definition1.1,
that12(3Z-I) E
and
ZZ = ZZ.
Therefore there exists such that Z = Hence4.4. THEOREM. Let F: & -~ ~ be a
holomorphic endomorphism for
which the
following
conditions hold:(i)
There is a domain Q c 8 such that(ii)
There is a sequence(Zn)nEN
such that(C)
limZn
= -I,
(D)
limF(Zn)
= Wfor
a suitable TV Ec~s
~.Then, for
every k ER+.
IPROOF.
Setting
= 2Z -1, p
is anisomorphism
ofS(N; C)
It follows from
(B)
thatThe map L defined
by L(Z)
= isholomorphic
onIf Z E r’1
a, 8, then Z, G(Z)
E8s 6
and.L(Z) G(Z)
= I. We denoteby I~1
the union of these connectedcomponents
of IWwhich intersectIn view of
(3.1),
which is
connected;
therefore Henceby
Remark3.5,
wehave
and a fortiori for every
For every
tI E R ;
moreover, sincet1 E
RI .
Then - 31 E From(C)
it follows thatlim,8(Zn)
= -31;
thus,
for every nsufficiently
and(4.2) yields
for every n
sufficiently large.
and
If
det (I - W ) = 0, then ,
for a suitablecontradicting G(- i1) e~(8).
Thusdet(1 - W) #
0. We canapply
Lemma 4.2 to I and
W,
andreplace
.F’by
so there is not restric-tion
assuming
W = - I. Therefore(4.5)
becomes Ii.e.
Let It
follows,
from Theorem1.7, (4.3)
and
(4.6)
thatT(0)
= 0 and Since Tis a contraction for
d,
thenBy
remark4.3, T(- 3I) _ - 3I.
Thus .F’ is aholomorphic
map with.F’(o)
= 0. Therefore we canapply
the Schwarz lemma(see [4],
Theorem
III.2.3) : by (4.6), ))
=||
and I is acomplex
ex-tremal
point
of6,
then =yF(l 1)
for every p EC,
3.It follows that = 21 for every A E
~, ~ IÂI
1. Since the sequence satisfies(2.1),
then the theorem follows from Julia’s lemma.§
5. We come now to theproof
of our main theorem(Theorem 5.3).
5.1. LEMMA. Let - E be a
holomorphic endomorp hism
with= 0. Then the sequence
(Kn)neN of
the iterates Kn = .g’o...o.gof
.Kcontains a
subsequence convergent
on allcompact
subsets to a holo-morphic endomorphism
Lof
f or
everyA, BEE.
PROOF. For
all i, j
such that the sequence(K£)v
is
equibounded,
because Thus there exists asubsequence (Knk)kEN uniformely convergent
on allcompact
subsets of E to aholomorphic
map .L.Moreover, by
the Schwarzlemma,
The
holomorphic endomorphisms
contract the distanced,
henceand
for every
A, B e
8. Therefore5.2. LEMMA. Let K: 8 ~ 8 be a
holomorphic endomorphism. Suppose
there is a domain A c 8 such that
for all
Then .I~ EPROOF. Let C
Replacing K by
we may assume C =0,
andg(o)
= 0.Let s E
(0, 1)
be such that c 11. thereforeZ)
=K(Z)),
i.e. by
Definition11
=11 K(Z) II,
for every Z EBs(O).
Let Z E6,
and
by
the Schwarz lemmaMoreover with lim
w (Z)
= 0.Let
then,
for 1therefore The lemma fol-
L, 4-
lows from Theorem III.2.4 in
[4]
.5.3. THEOREM..Let F: 8 -~ ~ be a
holomorphic endomorphism.
LetV1, V2 , W1, a, 8, k1, R.
be such that thefollowing
conditionshold :
(ii)
There exists a domain Q c ~ such that(iii)
There is a sequence(Zn)neN
such that limZn
=W1
andlim
.I’(Zn )
==W2 .
Then
FeAut(8).
PROOF.
Replacing
Fby
PoFoPby
a suitable choice ofeAut(8) (see
Lemma4.2)
we can assumeVI
=V2
=I, Wl 17 k1=k2=1.
As in the
proof
of Theorem4.4, replace
Fby
G = Sincen
98)
c38,
then we canappply
Theorem 3.6. But lim =-
fJ(W2)
with +1~
2+1)
eC),
there-fore there is such that is constant. Hence all
hypothesies
of Theorem 4.4 aresatisfied.
Let
as g(1, I)
and let E be such thatWi(0) = Z,
=I,
=0, Pl(I)
= I.Setting K = Pl0Fo(/)l,
it
follows,
from Theorem 1.7 and from(4.1 ),
thatfor all Moreover
Let t > 0 be such that then
by (ii, B)
andby
theSchwarz lemma
In view of
(5.4),
Lemma 5.1 can beapplied.
Thus(by (5.5))
satisfied the
hypothesies
of Theorem3.6,
and(by (5.3), (5.4))
for every k E and
L(O)
= 0. Therefore there isno ~
E such that is a constant map. Itfollows,
from Theo-rem
3.6,
that there isZ
e 6 such that is invertible.Hence,
fora suitable open
neighbourhood 91
of2,
~l = is an openneigh-
bourhood of
W
=E(2)
Itfollows,
from(5.1),
for all Since
then
Therefore, by
Lemma5.2,
5.4. REMARK.
Hypothesis (iii)
in Theorem 5.3 can not bedropped
(see
Remark 1 in[2]).
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