R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
J OHN D. O’N EILL
Measurable products of modules
Rendiconti del Seminario Matematico della Università di Padova, tome 73 (1985), p. 261-269
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JOHN D. O’NEILL
SUMMARY - In this paper all groups are abelian,
rings
are associative withidentity,
and modules are leftunitary.
We are interested in modules of the form a directproduct
of submodulesGi
over an index set I.1
Many
theorems about such modulesrequire
thatIII
be non-measurable.Here we let 1 be
arbitrary,
put mild restrictions on theGi’s,
and obtainnew results. In Section I we
eqtablish
somedecomposition
theorems.We then
apply
them tohomomorphisms
of the formf : n Gi
2013~ A where :in Section 2 .d is a slender module and in Section 3 A is an infinite direct
sum of submodules.
0. Prellminaries.
Let I be a set and
P(I)
its power set. Here(as
in[3]) III
is measurableif there is a
0,1 countably
additivefunction 03BC
onP(I)
such that = 1and = 0 for each If no such function
exists, ~I~
is non-measurable. If
f3
is the least measurablecardinal,
it is aregular
limitcardinal such that a
f3 implies
2e~8.
If all sets are constructible( Tr = Z),
measurable cardinals do not exist. Agood
discussion of these matters may be found in[5].
If
(~ +, .)
is a Booleanring,
an ideal .~ is here called ay-ideal if,
whenever s2 ,...}
is a countable set oforthogonal
elements inS, 1
sn E .K for some k inN,
the naturalnumbers,
n>k
Let .Z~ be a
ring
and A a R-module. Afilter
F is a set ofprincipal
(*)
Indirizzo dell’A.:University
of Detroit, Detroit,Michigan
48221262
right
ideals in .R suchthat,
for eacha.R,
bR inF,
there is a cR in Fcontained in aR and is
torsion-free if,
for r E .R and x E.A,
rx = 0implies r
= 0 or x = 0. A is divisible if rA = A for all non-zero rin .R.
D(A)
is the maximal divisible submodule of A and A is reduced ifD(A)
= 0.In
general
ourterminology
agrees with that in Fuchs[3].
1.
Decomposition
theorems.We
begin
with a set-theoretic lemma. We omit itsproof
sinceits statements are well-known or
easily proved (e.g.
see page 161 inII of
[3]
or pages 342-356 in[5]).
LEMMA 1.1. Let I be a
set, S
=P(I ),
and g a propery-ideal
in the Boolean
ring (S, +, .).
(a) S¡K
is finite and there areorthogonal elements,
say ul,... , Ue, in S which map onto the atoms of
SIK.
(b)
IfJ,
is a set oforthogonal
elementsin S,
almostall
s~’s
are in .g. IfJJI
isnon-measurable, then sj
E K for somecofinite subset J’ of J. ~
(c)
IfIII
isnon-measurable,
then K =P(I’)
for some cofinitesubset I’ of I.
REMARK. If g is an ideal of finite index in a
complete
Booleanring,
it need not be ay-ideal (consider S
= 2N and let K be a maximalideal
containing 2(N». However,
if I is aset, then |I|
is measurableif and
only
if S =P(I)
has a propery-ideal
Kcontaining
the atomsof S.
We now use Lemma 1.1 to obtain
decompositions
ofspecific
modules. In the next two theorems the
ring
.Z~ isarbitrary.
THEOREM 1.2. Let X be a R-module where the
G,ls
are1
pairwise isomorphic
of non-measurablecardinality.
If .g is a propery-ideal
in S =P(I )
andH = IIGi:s
eK),
then X = H wheres
0 Gi
for some finite subset E of I. If I isinfinite,
H.E
P;&OOF. Let
Gi
- G be anisomorphism
for some group G and each i. Let Ut, u, be as in Lemma 1.1. Foreach un
letAn
=e
==
~~ ~i ~(g) :
un g EG). Clearly
eachAn ~
G and we set L =0
1An.
We claim X = Let x
= ~ xi ,
xi EGi ,
be an element in X .1
If s
E S,
wedefine xs == .2
Xi. Hence x== .2 XSg
where i E sgexactly
iEs G
if
ni(xi)
= g E G. Since thesg’s partition land IGI
isnon-measurable,
~
Sg E K for some cofinite subset G’ of Gby
Lemma 1.1 andG’ G’ "
is in .H. Now X will be in .L
+
H if we canshow xsg
is in it for anyfixed g.
But sg == ~ -+- v
where each an = 0 or 1 and v E K.SO xsg === .2 anxun +
xv-2~
which is in .L+
H(unv
is inK).
Suppose
now 2/1+
...+ ye + z
= 0 with yn inAn
and z in ~H. Forany fixed n and some i in un the ith
component
of z is 0 since un is not in K. Hence the ithcomponent
of yn is 0 and yn = 0. Thereforez = 0 and X =
H,
as desired. If E consists of one element from each un, then Since X =Gi,
weE i%E
0:!. 0
infinite.IBE
THEOREM 1.3. Let X
== 0 Gi
be a .R-module where eachGi
andi
the set of their
isomorphism
classes have non-measurablecardinality.
If K is a
y-ideal
inS = P(I )
and then X =s
==
where,
for some finite subset.E, Gi
andGi .
E
PROOF. Write I =
U S; where i, i’
are in the same s;exactly
ifJ
Then
partitions I, IJI
isnon-measurable, and 0 Gi
=i
- ~ G8~
whereGS~ _ ~ Gi . By
Lemma 1.1 there is a J’ cofiniteJ
in J such
that E sj
E Kand 0
Forfixed j Gs
is aproduct
J’ J’
of
isomorphic
groupsand,
ifS;
=P(s;),
thenK;
_8;
r1 .K is ay-ideal
in
By
the last theorem6~
= whereHj == 0
EK;)
s
and,
for a finitesubset t;
of S;,Gi
andGi.
Sot..f 1,
Let Z be the left sum and let H’ be the module in the bracket. If E = we have and
E
Gi .
Since Hf ç H and H r1 L =0,
H = H’ and theproof
IBE is
complete.
Our next
proposition
will prove useful later.264
PROPOSITION 1.4. Let E
I,
be a set of R-modules and let V be the set of theirisomorphism
classes.(c~)
If and each is c «, a fixed non-measurablecardinal,
then
1 VI
is non-measurable.(b)
If each andIVI
arenon-measurable,
then forsome non-measurable x and all i.
PROOF.
(a)
Let Y be a free R-module of rank a. ThenY/.Hi
for some
.H~i
and each i. The number of distinct submodules of Yis 2~~ 2~
which is non-measurable since a is. So1 VI
is non-measur-able sincex is. So is non-mesaurable.
(b) Let P
be the least non-measurable cardinal
(it’s
anordinal).
Let J be a subset of I such that the ordinals are distinct with least upper boundSince B
is aregular
cardinal if a =B,
wehave B
=fl,
acontradiction. So « C
fl.
2. Slender modules.
In this section we
apply
the theorems of the last section to map-pings
of the formf :
- A where .A. is a slender R-module. Ini
the literature there appear various definitions of a « slender » module
(or group). Actually
these definitions areessentially
the same aswe shall show.
Therefore,
we define : aR-module
A is slender if it satisfies any(hence all)
of the four conditions ofProposition
2.1.PROPOSITION 2.1. Let A be a R-module. The
following
areequi-
valent.
(1)
If is ahomomorphism,
almost allcomponents
in map to 0.
(2)
Iff: RN - A
is ahomomorphism,
there is a cofinite sub- set C in N such that = 0.,
(3)
If~Gn~, nEN,
is a countable set ofR-modnles and f :
Ais a
homomorphism,
thenGnj
= 0 for some k inN. N
n>k
(4)
If{Gn}, nEN,
is a countable set ofR-modnles
andf : fI Gn-A
is a
homomorphism,
thenf(G,)
= 0 for almost all n inN.
PROOF.
(1) =>(2).
We writewhere en
is aN-tuple
N
with 1 in the nth
position
and 0 elsewhere. It suffices to assume= 0 for all n but
f (x)
~ 0 for some x e RN and to derive a con-tradiction. Write, x
and,
for each n inN,
set an === ...
+ rien).
For each k the kthcomponent
in RN ofan is 0 for almost all n.
Hence,
if B= Il Ra,,,,
there is a naturalimbedding
withg(an)
== an for each n. Consider the mapf :
B - A. Since =f (x)
~ 0 for each n, we have a contradic- tion of(1)
withrespect
tofg.
Therefore(1) =>(2).
(2)
~(3). Suppose (3)
is false. For each k in Nchoose xk E FI Gn
n>k so that ~ 0. There is a natural map g: RN -
FI Gn carrying
ento xn . RN - A is a
homomorphism
andby (2)
= 0k>m
for some m. So 0 = for a contradiction. Thus
(2) ~ (3). Clearly (3) ~ (4) ~ (1)
and theproposition
is true.REMARK.
(1)
is the definition of slender usedby
Fuchs[3,
vol.11,
pg.
159]
in the case .1~ = Z and A is torsion-free(a
slender R-module is torsion-free if .I~ = Z but not ingeneral.
SeeExample
3 on p. 399 of[4]). (2)
and(3)
are the definitions of slender used in[2]
and[4].
We now
apply
Theorem 1.3 to a map from a directproduct
ofmodules to a slender module.
THEOREM 2.2. Let X be a module where each and
i
the set of their
isomorphism
classes are non-measurable. Iff:
X -~ Ais a
homomorphism
and A isslender,
then .X = L(f) H
where = 0and,
for some finite subsetE, .L ~ ~ 6~
andH FI Gi .
E IBE
PROOF. For S =
P(I )
let .Kis
E S :f(fl Gi)
8 =01. Clearly
Kis an ideal and it is a
y-ideal by (3)
ofProposition
2.1. Theorem 1.3completes
theproof.
COROLLARY 2.3. Let .R be a commutative
integral
domain nota field and let A be a countable torsion-free reduced
R-module.
If R-module Xequals II Gi
where for some non-measurable a1
and all i and if
f :
X - A is ahomomorphism,
then X = where= 0
and,
for some finite subsetE, L = + Gi
andGi .
E
266
PROOF. We assume A is non-zero and hence is countable.
Thus the set of
isomorphism
classes of theGi’s
is non-measurableby Proposition
1.4. The result now follows from Theorem 2.2.COROLLARY 2.4. Let A be a torsion-free abelian group which does not contain a copy of
Q, ZN,
or thep-adic integers
for aprime
p.Let X be an abelian group where a for some non-measur- 1
able oc abd all i. If
f :
X - A is ahomomorphism,
then XL (B H
where
f (.H~)
= 0and,
for some finiteE,
L iand H Il Gà .
E IBE
PROOF. A is a slender Z-module
by
Theorem 95.3 in[3]. Proposi-
tion 1.4 and Theorem 2.2
complete
theproof.
NOTE. If is a set of
indecomposable
groups of non-measurablecardinality,
the least upper bound of may not be non-measurable.There exists
arbitrarily large indecomposable
groups(Theorem
2.1in
[7]),
3. Direct
products
and sums.Suppose
are modules andf : X -~ .A
is ai J
homomorphism.
Most known theoremsdealing
with this situationrequire that |I|
be non-measurable(see [6]
forreferences).
In thissection we let I be
arbitrary, put
some restrictions on theGi’s
andobtain new results. Other results with I
arbitrary
may be found inpart
2 of[6]. By fi
we will mean the mapf
followedby
theprojec-
tion to
A~ .
THEOBEM 3.1. Let be two
R-modules
i J
and let
f :
X - A be ahomomorphism. Suppose
eachGi
and the setof their
isomorphism
classes have non-measurablecardinality.
If(a)
.F’ is a filter of non-zeroprincipal right
ideals in .R or(b)
R is a commuta-tive
integral domain,
then ~’ _ whereL "’-.1 E8 Gi
E
for some finite E such
that,
for some non-zero b in=R,
isIBE
contained in
(a) n
rA or(b) D(A)
for almostall j
in J.PROOF. Let 8 =
P(I). (a)
Let K =is
E S: for somersR
in Fwe have
s Gi) z
rReF for almostall j
inJI.
It is easy to see that K is an ideal in ~S and it is
a y-ideal by
Chase’sTheorem
(Theorem
2.1 in[1]
or Theorem 1.1 in[6]).
Conclusion(a)
follows
immediately
from Theorem 1.3 above and from Theorem 1.3 in[6]. (b)
Let .g =is
E S: for some rs # 0 we have 8Gi) ç
c
D(A)
for almost allji.
Then K is ay-ideal
in Sby
Theorem 1.5 in[6] and,
from that theorem and Theorem 1.3above,
we have conclu- sion(b).
We next
apply
Theorem 3.1 to the case wheref
is theidentity
map. For best results we let A be torsion free.
THEOREM 3.2. Let A be a torsion-free .R-module with
decomposi-
tions A where c a for some non-measurable a
i J
and all i. If .h is a filter of non-zero
principal right
ideals in R suchthat n rA
= 0 or if .R is a commutativeintegral
domain andD(A)
=0,
rREF
then there are finite subsets
h
in I andJ1
in such that B0153
PROOF. Since .A is
torsion-free,
we may assume c a.By Proposi-
tion 1.4 the set of
isomorphism
classes of theGi’s
has non-measurablecardinality.
Letf
be theidentity
map in Theorem 3.1.By
that theorem and the fact that A is torsion-free wehave,
for some finite subsetsIl
in I andJl
inJ,
A =Z 0 .H
with and H C Theconclusion of the theorem now follows. Il Jl
If R = Z and A in the last theorem is
just
an abelian group, tor- sion-freeness is notrequired
to obtain ameaningful decomposition
theorem.
THEOREM 3.3. Let A be a reduced abelian group
i J
where for some non-measurable oc and all i. There are decom-
positions Gi
=Bi(f) Ci, A~
and finite subsetsIl
inI, Ji
in J such that
and is bounded
268
PROOF.
By Proposition
1.4 the set ofisomorphism
classes to whichthe
Gils belong
has non-measurablecardinality. By
Theorem 3.1(with f
theidentity
map andD(A)
=0)
there is adecomposition
A =
L + H
and finite subsetsh
andJi
such thatL Gi, H gz
Il
= II Gi, and %H C
+ Aj
for some n in N. Since ourgoals
are iso-il .
morphisms
notidentities,
we may assumen( n
J, for n in N.The rest of the
proof
isexactly
like that ofCorollary
1.9 in[6].
COROLLARY 3.4.
Suppose
A is a reduced abelian group,1
IGil
ce for some non-measurable a and alli,
and letfi
be an infinitecardinal. Then A is a direct sum
of P
non-zerosubgroups
if andonly
if some finite sum of
Gi’s
is or(b),
for some n inN,
eachG~
hasa n-bounded direct summand
Bi
such that1
PROOF.
Sufhciency
is clear. To shownecessity
setA
J
A~ ~
0 andJJI
=~8,
andapply
Theorem 3.3. Assume thedecomposi-
tions there have been made and
ln Bij ~8. By (c)
thenCi
is adirect sum
of P
non-zerosubgroups.
~’REFERENCES
[1] S. U.
CHASE,
On direct sums andproducts of
modules, Pacific Journal of Mathematics, 12(1962),
pp. 847-854.[2]
M. DUGAS - R. GOBEL,Quotients of reflexive
modules, Fundamenta Mathe-maticae, 114 (1981),
pp. 17-28.[3] L. FUCHS,
Infinite
AbelianGroups,
Academic Press, Vol. I(1970),
Vol. II(1973).
[4] E. L.
LADY,
Slenderrings
and modules, Pacific Journal of Mathematics, 49(1973),
pp. 397-406.[5]
A. LEVY, Basic SetTheory, Springer-Verlag,
1979.[6]
J. D. O’NEILL, On directproducts of
modules, Comm. inAlg.,
to appear.[7]
S. SHELAH,Infinite
abelian groups, Whitehead Problem and some construc-tions, Israel Journal of Mathematics, 21
(1975),
pp. 243-256.Manoscritto