Restricted set addition in Abelian groups:
results and conjectures
par VSEVOLOD F. LEV
RÉSUMÉ. Nous
présentons
un ensemble de conjecturesimbriquées
qui peuvent être considérées comme desanalogues
pour l’addition restreinte des théorèmesclassiques
dûs à Kneser,Kemperman
etScherk. Les connections avec le théorème de
Cauchy-Davenport,
la conjecture d’Erdos-Heilbronn et la méthode
polynomiale
d’Alon-Nathanson-Ruzsa sont étudiées.
Cet article ne suppose pas
d’expertise
de la part du lecteur etpeut servir d’introduction au sujet.
ABSTRACT. We present a system of interrelated conjectures which
can be considered as restricted addition counterparts of classi- cal theorems due to Kneser, Kemperman, and Scherk. Connec- tions with the theorem of
Cauchy-Davenport,
conjecture of Erdos- Heilbronn, andpolynomial
method of Alon-Nathanson-Ruzsa arediscussed.
The paper assumes no expertise from the reader and can serve
as an introduction to the
subject.
0.
Quick
start.Is it true that for any sets A and B of residues modulo a
positive
inte-ger, such that A f1
( - B ) _ {0},
there are at leastA
3 residuesrepresentable
as a + b with a EA, b
EB, and a #
b? We believe that theanswer is
"yes" ,
and there is not muchexaggeration
insaying
that thegoal
of this paper is to
explain why
thisconjecture
is soexciting,
where it camefrom,
and what it is related to.In the next section we review three remarkable theorems on set addi- tion due to
Cauchy, Davenport, Kneser, Kemperman,
andScherk;
thesetheorems are of utmost
importance
in what follows. In Section 2 webriefly
discuss theconjecture
of Erd6s-Heilbronn(presently
the theorem of Dias daSilva-Hamidoune)
which is the restricted additionanalog
ofthe theorem of
Cauchy-Davenport.
In Sections 3 and 4 we consider con-jectural
restricted additioncounterparts
of the theorems of Kneser andKemperman-Scherk, respectively.
1. Historical
background,
I. Unrestricted set addition.Additive combinatorial number
theory
is a branch of mathematics whichcan be traced down to its very roots. It is
generally
believed that the first result in this area is a well-known theorem due toCauchy
andDavenport.
Let A and B be
non-empty
sets of residues modulo aprime
p, and denoteby
A + B the set of all residuesrepresentable
as a sum a + b witha E A and b E B. Given the number of elements in A and B
(and
noother information on the two
sets),
how small can A + B be? If A and B are arithmeticprogressions
with the same commondifference,
then it isimmediately
seen that either A + B contains all presidues,
or otherwiseI A + B~ _
The theorem ofCauchy-Davenport
shows that thisis the extremal case.
Theorem 1.1
(Cauchy-Davenport).
For anynon-empty
sets A and Bof
residues modulo a
prime
p we haveThis theorem was first established in 1813
by Cauchy (see [C13])
whoused it to
give
an alternativeproof
of the result ofLagrange
that the con-gruence
by2
+ c - 0(mod p)
is solvable for any non-zero residues a,b,
and c.(Lagrange’s
result isactually
a lemma in hisproof
of thefamous
four-squares theorem.)
In 1935 Theorem 1.1 wasindependently
re-discovered
by Davenport (see [D35, D47])
as a "modulo panalog"
of aconjecture
of Landau and Schnirelmannconcerning
thedensity
of the sumof
integer
sequences.Among
numerousgeneralizations
of the theorem ofCauchy-Davenport
the
deepest
and mostpowerful is, undoubtedly,
an extension ontoarbitrary
abelian groups due to Kneser.
Loosely speaking,
it says that if A and Bare
finite, non-empty
subsets of an abelian group, then"normally"
thereare at least
I A
1 group elementsrepresentable
as a + b with a E Aand b E B. In other
words, letting
we
have IA
+B~
>IAI
+1,
unless there are some"special
reasons"for this to fail. To state Kneser’s theorem
precisely
we have to introducesome notation.
Throughout
the paper, for subsets A and B of an abelian group G wedefine the sum set A + B
by (1.1). (For
an element b E G we write A + b instead ofNotice,
that if H is asubgroup
of G and if for C C G wedenote
by
C theimage
of C under the canonicalhomomorphism
G 2013~G/H,
then
A + B = A + B for
anyA,
B C G. Theperiod (or stabilizer)
of a setC C G is defined
by H(C)
:={g
E G: C + g =C},
and C is said to beperiodic
oraperiodic according
to whetherH(C) ~ {0}
orH(C) _ {0}.
The
following properties
of theperiod
are almost immediate andyet
worthto be recorded
explicitly:
(i) H(C)
is asubgroup
ofG;
(ii) H(C)
= G if andonly
if C 0 or C =G;
(iii)
C is a union of cosets ofH(C). Indeed,
for asubgroup H
G theset C is a union of H-cosets if and
only
if HH(C);
(iv) C/H(C) (the image
of C under the canonicalhomomorphism
G -G/H(C))
is anaperiodic
subset of thequotient
groupG/H(C);
(v)
if C isfinite,
then so isH(C)
andICIH(C)L IH(C)I;
(vi)
for any B C G we haveH(C) H(B
+C).
Theorem 1.2
(Kneser, [Kn53, Kn55];
see also[Ma65]). Suppose
that Aand B are
finite non-empty
subsetsof
an abelian groupsatisfying
Then
letting
H :=H(A
+B)
we haveCorollary
1.1. Let A and B befinite non-empty
subsetsof
an abelian] IAI
+1,
then A + B isperiodic.
Notice that Kneser’s theorem
implies readily
the theorem ofCauchy- Davenport :
for theonly non-empty periodic
subset of a group of residues modulo aprime
is the group itself.Theorem 1.2 shows that any
pair
of subsetsA, B
of an abelian groupG, satisfying (1.2),
can be obtainedby "lifting"
subsetsA, B
of aquotient
group such that
Indeed,
let H :=H(A
+B)
and denoteby
A and B theimages
of A andB, respectively,
under the canonicalhomomorphism
G 2013~G/H.
Then(1.3)
holds
by
Theorem1.2,
andfurthermore,
Thus A and B are obtained from A + H and B + H
(which
are the fullinverse
images
of A and B inG) by removing
less than~H~
elementstotally.
It is not difficult to see that Theorem 1.2 is
equivalent
toCorollary
1.1 inthe sense that the former can be
easily
deduced from the latter. We leave the deduction as an exercise to the interested reader.The third result we discuss in this section will be referred to as the theorem of
Kemperman-Scherk.
It relates the size of the sum set A + B to the number ofrepresentations
of group elements as a + b with a C A and b E B.Assuming
that finite subsets A and B of an abelian group G are fixed andimplicit
from thecontext,
for every c E G we writethe number of
representations
of c as a sum of an element of A and anelement of B.
(A
moreprecise
but heavier notation would bev,q,B(c).) Evidently, v(c)
> 0 if andonly
if c E A + B. The theorem ofKemperman-
Scherk shows that if A + B is
small,
then any c E A + B has many repre- sentations in the above indicated form.Theorem 1.3
(Kemperman-Scherk).
Let A and B befinite non-empty,
subsetsof
an abelian group. Thenv(c) > IAI
-~IBI - JA
+BI for
anyc E A + B. In other
words,
The
history
of Theorem 1.3 dates back to 1951 when Moserproposed
in the American Mathematical
Monthly
aproblem
which can beformulated as follows:
For
finite
subsets A and Bof
the torus groupII8/7G
such thatIn 1955
(see [S55])
Scherkpublished
a solution whichactually
assumedA and B to be subsets of an
arbitrary
abelian group(not necessarily
thetorus
group).
Theargument
of Scherkrequires
very minor modifications toyield
theproof
of Theorem1.3,
but it was not untilKemperman’s
papers[Ke56, Ke60]
that the full version of the theorem has been stated.Indeed,
in the second of the two papers
Kemperman
ascribes the theorem toScherk;
on the other
hand,
in his solution of Moser’sproblem
Scherk indicates that theargument
follows the ideas of his earlierjoint
paper withKemperman.
With this in
mind,
we believe that the theorem should bear both names.Here is a short
proof
of the theorem ofKemperman-Scherk
based onKneser’s theorem.
Proof of
Theorem 1.3. IfJA
+BI
2IAI
+IBI - 1,
the assertion istrivial;
suppose that
A
+BI
k with some k > 2 and show thatv(c)
> k for any c E A + B. Let H :=H(A
+B)
and fix arepresentation
c = ao +
bo
with ao E A andbo E
B.By
Kneser’s theorem we haveand
by
theboxing principle, (A - ao) n
H and(bo - B)
fl H share at leastl~ common elements.
However,
eachpair (a, b)
such that a EA,
b EB,
and a - ao =
bo - b yields
a solution to a + b = c, whencev(c) > k
asclaimed. D
2. Historical
background,
II. Restricted set addition.Return for a moment to the theorem of
Cauchy-Davenport,
but insteadof
counting
all sums a + b consideronly
thosewith a #
b. How many are there? Thisquestion
was askedby
Erd6s and Heilbronn in the mid sixties(of
the twentiethcentury).
For subsets A and B of an abelian group G write
In contrast with the
regular
sum setA+B,
the sum setA-f-B
is often called"restricted".
Suppose
that G is the group of residues modulo aprime
p.If A and B coincide and form an arithmetic
progression
modulo p with at least two terms, then either contains all residues(this
holds if(p + 3)/2),
orIAI
+IBI -
3. Erd6s and Heilbronnconjectured
that infact,
for anynon-empty
sets A and B of residues moduloa
prime
p one hasThis
conjecture
wasfrequently
mentionedby
Erd6s in histalks,
but it seemsthat it was first
published
in[EG80] only.
It took about 30 years untilDias da Silva and
Hamidoune, using
advanced linearalgebra tools, proved
the
conjecture;
see[DH94]. Analyzing
theirproof, Alon, Nathanson,
andRuzsa
proposed
in[ANR95, ANR96]
anelegant
andpowerful "polynomial
method" which has
simplified
theoriginal argument drastically. Moreover,
their
method,
furtherdeveloped by
Alon in[A99],
allows one to handle avariety
of unrelated combinatorialproblems.
The basic idea of themethod,
as
applied
to theproblem
ofEd6s-Heilbronn,
is to consider thepolynomial P(x, y)
:=(~2013~/)
over the fieldGF(p).
We haveP(a, b)
=0 for any
pair (a, b)
such that a E A and b EB,
and since thepolynomial
has
"many
roots" itsdegree (which
is +1)
is to belarge.
Another
approach
ispursued
in[FLP99, LOOa]
where combinatorial con-siderations are combined with the character sum
technique.
Forinstance,
in
[LOOa,
Theorem2]
we were able to establish the structure of sets Aof residues modulo a
prime
p such that 200p/50
and2.18IAI-
6.- _ _
3. Restricted set addition and Kneser’s theorem
Once we have a restricted set addition
analog
of theCauchy-Davenport
theorem,
it is most natural to ask for such ananalog
for Kneser’s theorem.Let G be an abelian group. For two finite
non-empty
subsetsA,
B CG,
how
large
can the restricted sum setA+B
begiven
that it isaperiodic?
Set
Go
:=fg
E G:2g
=01,
thesubgroup
of Gconsisting
of zero and allelements of order two. For
brevity
we writeLG
:= In connection with restricted additionproblems
this invariant of the group G was introduced in[LOOa, LOOb, L01];
itsimportance
stems from the fact that for any c EA+B
such thatv(c)
>LG
we have c EA+B.
Fix aninteger n >
2 and an elementd E G of order at least 2n - 1 and let A = B :=
{0, d, . (n - 1)d}
+Go.
so that
IA+BI == (2n-1)IGol-2 ==
on the otherhand,
it is
easily
verified thatA~-B
isaperiodic.
Based on numerical evidence and severalparticular
cases which we cansettle,
weconjectured
in[LOOa]
that if
IAI
+IBI - (LG
+2)
holds for finitenon-empty
subsetsA,
B CG,
thenA+B
isperiodic
andindeed,
we haveA+B
= A + B.Conjecture
3.1. Let G be an abelian group, and let A and B befinite non-empty
subsetsof
Gsatisfying
Then
A+B
= A + B.For some
partial
results towards theproof
ofConjecture
3.1 the reader isreferred to
[LOOa, LOOb, L01] .
Inparticular, [LOOb,
Theorem4] implies
thatfor any finite
non-empty
subsetsA,
B C G such thatA4B #
A-~ B one has>
(1-S)(~A~+~B~)-(LG+2),
where 6 =IAIIBI/(IAI+IBI)2 ::;
0.25.Also,
we have verifiedcomputationally Conjecture
3.1 for allcyclic
groups G with 125,
and in the case A = B 36. The reader will checkeasily
that theconjecture
is valid for allcyclic
groups ofprime
order
(when
it isequivalent
to the Erd6s-Heilbronnconjecture);
for theinfinite
cyclic
group(then ]
>IAI
-~ 3 for anyfinite,
non-emptyA,
B CG)
and as one can deduce fromit,
for all torsion-free abelian groups;and for
elementary 2-groups (in
which case the assertion istrivial).
In
fact, Conjecture
3.1 is not ananalog,
but rather acounterpart
of Kneser’s theorem. It shows that either the restricted sum setA-f-B
is"large",
or it coincides with theregular
sum set A + B and then the well- establishedmachinery
of Kneser’s theorem can be used tostudy
it.Remark. The conditions
are not to be confused with each other. It is not difficult to see that if A =
B,
then(i) implies (ii);
on the otherhand,
if G has no elementsof even
order,
then(ii) implies (i). However,
ingeneral
none of the twoconditions follows from another one:
consider,
forinstance,
the subsetsA =
{0,1, 2},
B ={10, 11, 12}
of the additive group ofintegers (where (i)
holds but
(ii)
doesnot),
and the subsets A = B ={I, 2, 4, 5}
of the groupof residues modulo 6
(here (ii)
holds but(i) fails).
In
conjunction
with the theorems of Kneser andKemperman-Scherk, Conjecture
3.1readily implies
Corollary
3.1. Let G be an abelian group, and let A and B befinite
non-empty
subsetsof
Gsatisfying (3.1).
ThenProof. (i)
If there were c E A + B such thatv(c)
2 +LG,
thenby
the theorem ofKemperman-Scherk
we hadI
However, ) by Conjecture
3.1.(ii)
Follows from(iii)
and the trivial estimatesI
(iii)
Immediate from Kneser’s theorem and sinceIA + B~ _
IAI
+IBI -
1. DEach one of conditions
(i)-(iii)
of the lastcorollary, along
with assump- tion(3.1), implies
thatA+B
isperiodic.
For(ii)
and(iii)
this isobvious;
as to
(i),
itgives A+B
= A +B,
andperiodicity
of this sum follows from Kneser’s theorem. This allows us to stateyet
anothercorollary
ofConjec-
ture
3.1,
which isparallel
toCorollary
1.1.Corollary
3.2. Let G be an abelian groups, and let A and B befinite
non-empty
subsetsof
Gsatisfying (3.1).
ThenA+B
isperiodic.
Just as
Corollary
1.1 isequivalent
to Kneser’stheorem, Corollary
3.2 isequivalent
toConjecture
3.1.Proposition
3.1.Corollary
3.2implies Conjecture
~.1.Proof. Suppose
thatCorollary
3.2 holds true and let A and B be finite non-empty
subsets of an abelian groupG, satisfying (3.1).
We use inductionby
to prove that
A+B
= A + B. The case = 1 is easy in viewof
1,
and we assume that 2.Write D :=
{d
E A fl B:2d ~
so that A + B =(A+B)
U{2d:
dE D},
the two sets at theright-hand
sidebeing disjoint.
Ourgoal
is to show that D = 0.
Assuming
theopposite,
we set n :==~~2d:
d ED}~ ]
and k :=
mindED v(2d),
so that 1 kLG
and kn.Notice,
thatby
the theorem ofKemperman-Scherk
wehave IA + BI 2: IAI
+(B~ - k,
whence n
JA
+LG
+ 3 - k.Let H :=
H(A+B),
so thatIHI
> 1by Corollary
3.2. We claim that(d
+H)
n A =(d
+H)
={d}
for any d E D.Indeed, assuming,
say,(in
view of a + d EA-~B),
a contradiction. This shows that for all d E D the sets(d + H) B {d~
aredisjoint
with A.Moreover, they
aredisjoint
witheach other: for if
(d’
+H)
f1(d"
+H) #
0, then d" E(d’
+H)
nA,
henced" = d’. Thus
and
similarly B
+Therefore,
ifA, B,
andA-~-B
denote the
images
ofA, B,
andrespectively,
under the canonicalhomomorphism
G ~G/H,
thenthe last
inequality following
fromAs
LG > LGIH,
it follows thatIAI (LG/ H + 3),
hence
A+B =
A + Bby
the inductionhypothesis. However,
for any d E D itsimage d
EG/H
satisfies 2d E(A
+B) B (A-+-B),
a contradiction. 0 Infact,
it suffices to proveConjecture
3.1(or Corollary
3.2 to which itis
equivalent)
in theparticular
case B C Aonly.
Conjecture
3.1’. Let G be an abelian groups, let A and B befinite
non-emPty
subsetsof G, satisfying (3.1),
and suppose that B C A. ThenA+B=A+B.
Corollary
3.2’. Let G be an abelian group, let A and B befinite
non-errapty
subsetsof G, satisfying (3.1),
and suppose that B C A. ThenA+B
is
periodic.
Proposition
3.2.Corollary
3.2’implies Conjecture 3.1’,
whichimplies Conjecture 3.1,
whichimplies Corollary
3.2.Thus,
allfour
results areequivalent in
the sense that eachof
themimplies
the other three.Proof. Exactly
as in theproof
ofProposition 3.1,
one can see thatConjec-
ture 3.1’ follows from
Corollary
3.2’. We show thatConjecture
3.1 followsfrom
Conjecture
3.1’.To this
end,
suppose thatConjecture
3.1’ istrue,
and let A and B be finitenon-empty
subsets of an abelian groupG, satisfying (3.1).
We wantto show that
A-f-B
= A + B. Set A* := A U B and B* := A nB;
we canassume that
B* ~
0, for otherwise the assertion is immediate.Plainly,
we have
IA*I
+IB*I
=IAI
+IBI
andA*48*
CA+B,
whenceIA*I
+IB*I- (LG
+2).
FromConjecture
3.1’ we deriveA*+B*
= A* +B*,
and this shows that for any d E B* there exist a* E
A*,
b* E B* such thatb* and 2d = a* + b*. Since a* + b* E
A*+B*
CA-f-B,
it follows thatA-f-B
= A +B,
asrequired.
DRemark. It is
easily
seenthat,
without loss ofgenerality,
one can assume0 E A r1
B, 0 ~ A-~B
inConjectures
3.1 and 3.1’ and Corollaries 3.2 and 3.2’. Infact,
it is the lastcorollary
with this extraassumption
that hasbeen verified
computationally
forcyclic
groups of small order. Some further reformulations arepossible.
Forinstance, Conjecture
3.1 isequivalent
tothe assertion that if
A,
B C Gsatisfy
0 E A n B and0 ~ A+B,
then4. Restricted set addition and the theorem of
Kemperman-Scherk
What is the restricted addition
analog
of the theorem ofKemperman-
Scherk ? That
is,
how small canmincEA+B v(c)
be forJAI,
andIA+BI
given?
Consider anexample
similar to that constructed in Section 3. Fixa
subgroup H
G such that 2h = 0 forany h
EH,
aninteger n
>2,
and an element d E G of order at least 2n -1,
and let A = B :={0, d, ... , (n - 1)dl
+ H. ThenIAI (IHI
+2)
whenceConjecture
4.1. Let A and B befinite non-empty
subsetsof
an abeliangroup. Then
v(c) > IAI
~-IBI -
2 -for
any c E A+ B. In otherwords,
As it is the case with
Conjecture 3.1,
we have verifiedConjecture
4.1computationally
for allcyclic
groups7Gl
with 125,
and in the case A = Bwith 1 36.
Also, Conjecture
4.1 is true for torsion-free abelian groups(then IAI
3 for any finitenon-empty
A andB),
for groups of residues modulo aprime (when
it isequivalent
to theconjecture
of Erdos-Heilbronn),
and forelementary
abelian2-groups (follows
from the theoremof
Kemperman-Scherk
and the observation thatA+B
=(A
+B) B {0}
forthese
groups).
Corollary
4.1. Let A and B befinite non-empty
subsetsof
an abeliangroup.
If
there exists an element c E A + B with aunique representation
as c = a + b(a E A,
b EB),
thenProposition
4.1.Corollary l~.1 irraplies Conjecture .~.1.
Proof. Suppose
thatCorollary
4.1 holds true, and let A and B be finitenon-empty
subsets of an abelian group. We fixarbitrarily
c E A + B andshow that +
] B ] -
2 -v(c).
Write k :=
v(c)
and let c = al +bl
= ... = ak +bk, where ai
EA, bi
E B(i
=l, ... , k),
be the krepresentations
of c. Define B’ : =B B {bl, ... ,
Then c has aunique representation
as c = a+ b’
witha E A and b’ E B’
(namely,
c = ak +bk) ,
whenceby Corollary
4.1as
required.
DThe
following
immediatecorollary
ofConjecture 4.1,
as we will seeshortly,
isequivalent
toConjecture
3.1. The formerconjecture, therefore,
is a
strengthening
of the latter.Corollary
4.2. Let A and B be,finite non-empty
subsetsof
an abeliangroup G.
If
there exists an element c E A + B such thatv(c) LG,
thenProposition
4.2.Corollary 4.2
isequivalent
toConjecture
3.1.Proof.
It is clear thatCorollary
3.1(i),
and thereforeConjecture 3.1, implies Corollary
4.2. On the otherhand,
ifCorollary
4.2 holds true and if A and Bare finite
non-empty
subsets of an abelian group G such thatI
IB/-(La+2),
thenv(c)
>LG
for any c EA-I-B,
whenceA+B
= A+B. 0 Remark. It is not clear whetherCorollary
4.2implies Conjecture 4.1;
inother
words,
whetherConjectures
3.1 and 4.1 areequivalent.
Corollary
4.2 can be reduced to the case B C A.Corollary
4.2’. Let A and B befinite non-errapty
subsetsof
an abeliangroup
G, satisfying
B C A.If
there exists an element c E A + B such thatv(c) LG,
then- .. a.. - . - . ,
Proposition
4.3.CoroLlary lf.2’
isequivalent
toCorollary 4.2.
First
proof.
Consider theimplications
(Corollary 4.2’)
~(Conjecture 3.1’)
#
(Conjecture 3.1)
~(Corollary 4.2).
0
Second
proof.
We follow theproof
ofProposition
3.2.Suppose
that Corol-lary
4.2’ is true and let A and B be finitenon-empty
subsets of an abeliangroup G.
Assuming
thatLG
andIAI
(LG
+2)
we will obtain a contradiction.We observe that the theorem of
Kemperman- Scherk,
whenceA4B #
A + B. Set A* := A U B and B* := A n B. We haveB* #
0, for otherwiseA+B
= A + B. In view ofA*+B*
CA+B
weobtain
hence
by Corollary
4.2’ every c E A* + B* has at leastrepresentations
as c = a* + b* with a* E
A*, b*
E B*. ThusA*48*
= A* + B* and(as
inthe
proof
ofProposition 3.2)
we conclude thatA-f-B
= A +B,
thesought
contradiction. D
The reader is
urged
to compare our nextcorollary
with thequestion
westarted our paper with.
Corollary
4.3.Suppose
that A and B arefinite
subsetsof
an abelian groupsatisfying An (-B) = {0}.
ThenProof.
From A n(-B) _ {0}
it follows thatv(0)
= 1(the only representa-
tion of 0
being 0 = 0 + 0).
DRemark. It is not difficult to see that if
LG
=1,
thenConjectures
3.1 and4.1 are
equivalent
to each other and toCorollary
4.3.Indeed,
in this caseCorollaries 4.1 and 4.2
coincide; however,
we saw that the former of them isequivalent
toConjecture
4.1 and the latter isequivalent
toConjecture
3.1.To
verify
thatCorollary
4.3implies Conjecture
3.1 for groups Gsatisfying LG
=1,
observe that if A-~ B then there exists such that2c V A+B; letting
A’ := A - c and B’ := B - c weget
A’ rl(-B’) = {0}
whence
IA’+B’I ]
>IA’I
+ 3 =IAI
+ 3by Corollary
4.3.In
conclusion,
we note that for restricted set addition it may be natural toreplace v(c) by
the "restrictedrepresentation
function"From
Conjecture
4.1 it is not difficult to deriveCorollary
4.4. Let A and B befinite non-empty
subsetsof
an abeliangroup G. Then
Proof.
IfmincEA+B v(c) LG then, assuming Conjecture 4.1,
weget
Otherwise we have
A+B
= A -~- B whenceby
the theorem ofKemperman-
Scherk
The result now follows from
u
5. A
unifying conjecture
When this paper was
essentially completed
we were able to state a rathergeneral conjecture
which is somewhatsimpler, yet stronger
thanConjec-
tures 3.1 and 4.1.
Conjecture
5.1. For anyfinite non-empty
subsets A and Bof
an abeliangroup we have
In other
words, if I (A + B) B (A+B)~ > 3,
thenIAI
+ 3.We make several remarks:
(i)
It iseasily
seen thatConjecture
5.1implies Conjectures
3.1 and 4.1.Moreover,
ifLG
= 1 then all threeconjectures
areequivalent
to eachother.
(ii)
Thegeneral
case reduceseasily
to the case 0 E B CA, 0 ~ A+B.
(iii)
We have verifiedConjecture
5.1(in
fact itsspecial
case described in(ii))
for allcyclic
groupsZi
of25,
andassuming equal
setsummands
(A
=B)
of order 1 36.(iv) Conjecture
5.1 is valid for torsion-free abelian groups(in
this case3 holds for any finite
non-empty
subsets A andB).
(v)
It is valid also for groups of residues modulo aprime (when
it isequivalent
toErdos-Heilbronn) .
(vi)
It is valid also forelementary
abelian2-groups (in
these groups we haveA+B
=(A+ B) B {0}
forany A
andB).
(vii) Perhaps, using Kemperman’s
results it is feasible to proveConjec-
ture 5.1 in the case
1
-I--I B I - 1.
This would show that theconjecture
isequivalent
to the assertion that ifI + B 3,
then
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Vsevolod F. LEV
Department of Mathematics The University of Haifa at Oranim
Tivon 36006, ISRAEL
E-mail : seva(Qmath.haifa.ac.il URL: http : //math. haifa. ac . il/"’seva/