C OMPOSITIO M ATHEMATICA
S IDDHARTHA S AHI
The Capelli identity and unitary representations
Compositio Mathematica, tome 81, n
o3 (1992), p. 247-260
<http://www.numdam.org/item?id=CM_1992__81_3_247_0>
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The Capelli identity and unitary representations
SIDDHARTHA SAHI (C
Department of Mathematics, Princeton University, Princeton, NJ 08544 Received 13 August 1990; accepted 24 April 1991
Introduction
Let 03A9 =
G/K
be an irreducible Hermitiansymmetric
space of tubetype
and of rank n. Its Shilovboundary
is of the formG/P
where P = LN is a maximalparabolic subgroup
of G. It is known that n =Lie(N)
is an abelian Liealgebra
with a natural Jordan
algebra
structure. There is adistinguished polynomial (the
Jordan
norm)
cp on n. Thepolynomial
ç hasdegree n
and transformsby
apositive
characterv-2
of L.Let
P
be theopposite parabolic
and consider for each t E R the inducedrepresentation I(t)
=Ind P (vt Q 1) (normalized induction). Using
theGelfand-Naimark
decomposition
G :NLN
and theexponential
map, we may realizeI(t)
as asubspace E(t)
ofCOO(n).
The
Killing
form and Cartan involutionyield
anisomorphism
from n to n*.Thus we
get
a differentialoperator
D =è(cp) corresponding
to 9 in the usualmanner. It is known that for each m E
Z,
Dm intertwines1(m)
with its Hermitiandual 1( - m).
Soif ~,~
is the Hermitianpairing
betweenI(m)
and1( - m),
then(fl, f2)m
=~Dmf1,f2~
is an invariant Hermitian form onI(m).
Our main result is an
explicit
formula for thesignature
of this form on each K-type !
To state this result we introduce some notation.
Let b and 1)s
becompact
andmaximally split
Cartansubalgebras, respectively,
of g= Lie(G).
TheK-types
inI(t)
occur withmultiplicity
one, and havehighest 1)-weights
of the formb 1 Y 1
+ " +bn03B3n,
where yi are the Harish-Chandrastrongly orthogonal
rootsand
b1 ··· bn
areintegers. Also,
if as is thesplit part
of1)s,
then the restrictedroot
system
E(a’, g)
is oftype Cn,
and all the short root spaces have a common dimension d. Our main result isTHEOREM 1.
For 03B2
=bly,
+... +bnYn,
letI(m)p
be thecorresponding
K-isotypic subspace of I(m).
Thenfor
anyf
EI(m),,
we haveThis work was supported in part by an NSF grant at Princeton University.
where
Let us write
R(m)
for the kernel of Dm andQ(m)
for thequotient I(m)/R(m).
Weconsider next the
question
of theunitarizability
ofQ(m).
Variousparity
considerations arise-there is an
important
difference between the cases of even and odd d.THEOREM 2.
Suppose
that either(a)
d0(mod 4)
and m isodd;
or that(b)
d ~
2(mod 4)
and m ~n(mod 2).
ThenQ(m)
is a direct sumof
n + 1unitary representations Qo,..., Qn.
This is
proved
in3.1,
and in 3.2 we extend this result todegenerate
seriesrepresentations
of the universalcovering
groupG
of G.It may be shown
(although
we do not do so in thispaper)
that theQi
areirreducible, Qo
andQn
areholomorphic
andanti-holomorphic
discrete seriesrepresentations
and that the otherQi
arecohomologically
induced represen- tations(indeed they
areA(q, 03BB)’s
for suitable 0-stableparabolics q).
For odd d the situation is
completely
different. Therepresentation Q(m)
iseither
irreducible,
or it breaks up intoapproximately n/2 pieces
of which at most2 are
unitary.
These areholomorphic
andanti-holomorphic
discrete series for G.The other
"interesting" unitary representations
occur forhalf-integral
values ofm, whose
analysis requires
an extension of thepresent techniques.
This we leaveto a future paper.
In the
appendix
westudy
thedegenerate
series ofG. Using
results of[G]
wegive
acomplete
determination of thepoints
ofreducibility
of this series. Thispart
isindependent
of the rest of the paper and we include itonly
for the sake ofcompleteness.
Here are the main ideas and
techniques
of this paper.The first
ingredient
is thegeneralized Capelli identity
of[KosS].
This is aformula for the radial
part
of L-invariant differentialoperator qJm Dm
onL/L n
K.The second
ingredient
is theCayley transform,
as discussed in[KorW],
forexample.
This is an element cof Ad(gc)
whichinterchanges Ïc
withIc, and 4’ c
withI)c.
Now, conjugation by
c transformsç"’ D"’
to ac-invariant
differentialoperator 0394m
onI(m).
We show that0394m
actsby
the scalarqm(03B2)
onI(m)03B2.
Theexplicit
formula for
qm(03B2)
then follows from thegeneralized Capelli identity!
We now describe some of the relevant literature. Since the work of
[W]
and[RV],
two papers have obtainedexplicit
formulas for the innerproduct
onholomorphic
discrete series with one-dimensional lowestK-types.
Ofthese, [FK]
which considersholomorphic
functions onQ,
is closest to ourapproach.
Since
holomorphic
functions are determinedby
their values on the Shilovboundary,
theboundary
value map imbeds these spaces inside the1(m).
It ispossible
to rederive some of the results of[FK]
from our main result.The paper
[G]
considers Hermitianrepresentations
with one-dimensional K-types (semi-spherical)
which are annihilatedby
a certain ideal inu(g), deriving
an
explicit
formula for the innerproduct.
It is easy to seethat,
while any suchrepresentation
must be a constituentof 1(t),
mostunitary
constituentsof 1(t)
arenot
semi-spherical.
If m islarge enough,
then among theunitary representations
in Theorem 2
only
the discrete seriesQo
andQn
have one dimensionalK-types.
The
representations 1(0)
have been studied forSU(n, n)
andSp(n, R)
in[KaV]
and the
general I(t)
is considered forS U(2, 2)
in[JV]
and[S].
It is a
pleasure
to thank Bert Kostant for invaluable advice and encourage- ment. While various ideas in this paper were worked out inFall 1987,
the wholepicture
became much clearer to me after the results of[KosS]
were obtained.The final version of this paper has also benefited from
helpful
discussions with DavidVogan
andGregg
Zuckerman.Finally,
it would be a shame topermit
the’Cayley
coincidence’ to go unremarked. Indeed aprovisional
title for this paper was "TheCayley
Transform of the
Cayley Operator
andUnitary Representations",
which wasabandoned as
being
too cumbersome.1. Preliminaries
The material of this section is well-known. All the basic facts may be found in
[KorW], [KosS]
and[B].
In whatfollows,
all Liealgebras
will be real unlesscomplexified
with asubscript
"c".1.1. The
Cayley transform
Let
(g, f)
be an irreducible Hermitiansymmetric pair
of tubetype.
Fix a Cartandecomposition
g = 1 + p and let a’ be a Cartansubspace
of p. Choose ts ~ f sothat b’
= as~ ts
is amaximally split
Cartansubalgebra
of g.It is known
([M])
that the restricted rootsystem
is oftype Cn
wheren =
dim(as).
Thus we may choose a basis 03B51,...,03B5n for(as)*
such thatThe root spaces for
+ ei ± ej
have a common dimension which we will denoteby
d. The root spaces for ±2ej
are one-dimensional. Thus +2Bj
may beregarded
as a root
of 4’
in g,vanishing
on ts.To each
2Bj
we attach in a standard manner(see [KosR])
anS-triple
{hj,
ej,fil,
contained in g. TheseS-triples
commute, and ifthen
{h, e, f 1
is also anS-triple.
The
eigenvalues
ofad(h)
on g are -2, 0
and 2. Let us writen,
1 and n for thecorresponding eigenspaces.
ThenClearly
q = 1 + n is a maximalparabolic subalgebra
whose one-dimensionalcenter is a = Rh. Let m (9 a be the
Langlands decomposition
of I.We fix
positive
restricted rootsystems
of g and1, lexicographically
withrespect
toh 1, ... hn .
ThusThe
Cayley
transform is the element(of
order4)
inAd(gc)
definedby
c = exp
nil4(e
+f ).
It is known thatc(Ic)
=fc
andc(c)
=le,
and thatC2
is theCartan involution for the
symmetric pairs (f,
1 nf)
and(I, I ~ f).
Let us write
b
= f nc(hsc). Then b
is acompact
Cartansubalgebra
for g(and f),
and we have the
decomposition b
= t +ts,
where t =ic(aS).
The Harish-Chandra
strongly orthogonal
roots in03A3(hc, 9c)
are 03B31, ..., Ynwhere yi
= c o(203B5i).
1.2. The
Capelli identity
Let P be the
polynomial algebra
on n. Then 1 actsnaturally
on 9by
It is known
(see [KosS]
for details andreferences)
that thealgebra
of lowestweight
vectorsof (n, Y)
is apolynomial algebra
in ngenerators
~1,...,~n withdeg(cpj) = j
andweight(cpj) = -2vj, where vj
= E + ... + 03B5j.Furthermore,
n has the structure of aformally
real Jordanalgebra
with e(see 1.1)
as theidentity.
We normalize the gjby requiring
that~j(e)
= 1 and write vfor vn and 9 for 9,. Then ç is the Jordan norm
polynomial
for n.Let 0 be the Cartan involution on g, then
(x, y)
=B(x, Oy)/B(e, f )
is apositive
definite inner
product
on n(where B
is theKilling form).
Thus we have anisomorphism
ô from Y to thealgebra
of constant coefficient differentialoperators
on n. We write D for~(~).
It is easy to see that
cpm Dm
commutes with03C0(I)
on Y. It follows from Schur’s Lemma that it actsby
a scalar on each irreducible constituent of p.PROPOSITION
([KosS]). If
V is an irreduciblesubrepresentation of (03C0, P)
withhighest weight
03BB =03BB103B51
+ ... +03BBn03B5n,
thenfor
allf
inV,
Moreover,
there is anad(I
nf)-invariant
elementXm
in theenveloping algebra u(I)
such that03C0(Xm) = cpmDm.
Proof.
This is a reformulation of the main result of[KosS].
The function denotedby f;’
in(3.16)
of that paper is ahighest weight
vector ofweight
-
Zi (Âi - d/2(n -
2i +1»e,,
and(4.4)
in that paper shows thatThus
if f is
ahighest weight
vector ofweight Â,
thenwhich,
aftersimplification,
proves the firstpart
of theProposition.
Also,
as shown in Section 4 of[KosS] (although
withslightly
differentnotation), ~mDm
is an invariant differentialoperator
onL/L n K.
Now theexistence of
X m
follows from the fact that the natural map fromÕ//(I)LnK
toD(L/L n K)
issurjective.
D1.3. The induced
representation
Let 03A9 =
G/K
be the Hermitiansymmetric
spacecorresponding
to thepair (g, f)
and let P be the normalizer of q in G. Then
G/P
is the Shilovboundary
of Q inthe bounded
(Harish-Chandra)
realization. LetP
be theopposite parabolic
subgroup
and letP
=LN
=MAN
be its Levi andLanglands decompositions.
Let à be half the sum of restricted roots in n. Then an easy calculation shows that tJ = rv where 03BD = 03B51 + ...
+ En
as in 1.2 andr = (nd - d + 2)/2.
For eacht E R,
we define thecharacter xt
of Lby Xt(m exp(H))
=exp(tv(H))
for all m E Mand H E a. We define
and we write n, for the
representation
of G onI(t) by right
translations.Since G =
PK,
restriction to K is aK-isomorphism
betweenI(t)
andC’«L
nK)BK). Now,
as remarked in1.1, (K,
L nK)
is asymmetric pair.
Itfollows that each
K-type
inI(t)
hasmultiplicity
one.Furthermore,
theK-types
which do occur are
exactly
those that have an L n K-fixed vector.By
theCartan-Helgason theorem,
thishappens exactly
when thehighest weight fl
ofthe
K-type
satisfiesPlt
= 0 andwhere
the yj
are as in 1.1.We will write
I(t)03B2
for theK-type
ofI(t)
ofhighest weight p.
Since
PN
is open and dense inG,
restriction to Ngives
aninjection
fromI(t)
to
C°°(N). Using
theexponential
map toidentify
n andN,
weget
anembedding f H f from I(t)
intoC~(n).
Theimage E(t)
will be referred to as thenon-compact picture.
In this
picture,
g actsby polynomial
coefficient vector fields and so n,gives
ahomomorphism
from theenveloping algebra *(g)
to theWeyl algebra
11/ ofpolynomial
coefficient differentialoperators
on n.The action of q is
particularly simple,
and we havewhere
03C0(u)
is as in 1.2 and v isregarded
as a character of 1vanishing
on m.If D =
è(cp)
is as in1.2,
then D:E(t)
~C~(n).
The crucialproperty
of Dm is thefollowing:
PROPOSITION
([B]).
For eachinteger m 0,
Dm intertwines nmand n_m.
DFor a different
proof
seeProposition
V.6.1 in[JV].
For fi
EI(t)
andf2 E I ( - t)
we definewhere
dg
is theright-invariant
measure onPBG.
It is
easily
checked that the aboveexpression
iswell-defined,
and that itgives
a
non-degenerate, Hermitian,
G-invariantpairing
betweenI(t)
andI(-t).
The
pairing
has a verysimple expression
in thenon-compact picture.
Itbecomes
2. The
signature
of the hermitian form In this section we prove Theorem 1.2.1. Finite dimensional
subrepresentations
Let v = 03B51 + ...
+ 03B5n
be as in 1.2.Regard
v as a characterof b’ by extending
ittrivially
on ts. Thenby
theCartan-Helgason theorem,
for eachnonnegative integer
m, there is a finite-dimensionalspherical representation
of G withhighest weight
2mv. An easy calculation of central characters shows that these finite dimensionalrepresentations
occur as constituents of certain of theE(t)’s.
Thenext lemma makes this
precise.
Let r =
(nd -
d +2)/2
be as in1.3,
and let m 0 be aninteger.
LEMMA 1.
E(r
+2m)
has afinite-dimensional subrepresentation F2.
withhighest weight
2mv.Furthermore, if f
EF2.,
thenf
is apolynomial
on n.Proof.
As remarked in1.3,
n,gives
ahomomorphism of Gll(g)
into W. Thus 03C0t may be extended to an action on all ofC~(n).
For t = r +
2m,
the constant function is03C0t(n)-invariant
and transformsby
thecharacter 2mv of I. Thus it
generates
a finite-dimensionalsubrepresentation F2m,
say,
of C~(n).
Thisexponentiates
to aspherical representation
of the group G. It follows thatF2m
consists of K-finite vectors and so is contained inE(t).
Finally,
iff
is inF2m
thenf
=03C0t(u) ·
1 for some u inu(g).
Since03C0t(u)
EW,f
must be a
polynomial.
DLet ~ be the Jordan norm as in 1.2. Define the
polynomial t/J (of degree 2n) by
where e is as in l.l and
x’
is the square in the Jordanalgebra.
LEMMA 2.
The functions
1 andcplm
are thehighest
and lowestweight
vectors inF2m. The functions cpm
andt/lm
span the one-dimensional spacesof L-fixed
and K-fixed
vectorsrespectively.
Proof.
The formula for03C0r+2m(I)
shows that theonly polynomials
transform-ing by
a character of 1er +2m (1)
are the powerscpk
for k =0, 1, ....
The firstpart
of the Lemma follows after we note that1, lpm, ,2m
transformby
theappropriate weights
of a.It remains to show that
03C8m
is K-fixed.Complexifying
the action of g onF2m
we
get
aholomorphic representation
of Qc. Let c be theCayley
transform as in1.2. Then c acts on
F2m
and it suffices to show that c takes~m to 03C8m.
Let e1 ··· en be as in 1.1. Then the
set {ad(L~K)(03B11e1 + ···
+03B1nen)|03B1j~R}
isopen in n.
(Indeed
as remarked inProposition
1 of[KosS],
this is an opencone.)
On the other
hand,
sincecpm
and03C8m
are both L nK-invariant,
it suffices to show thatHowever,
this follows from the definition of c and an easysl2-calculation.
0 Each of the
representations
n, isspherical. Let f
be the K-fixed vector in1(t);
then we have
ft(mank) = (avy-r.
The next Lemmagives
anexplicit
formula forf.
LEMMA 3. The
spherical
vector inE(t)
isqit - r/2.
Proof.
The formulafor f
shows thatft+r(g) = (f2+r (g))t/2.
On the otherhand,
Lemma 2 shows that the
spherical
vector inE(2
+r)
ist/f.
Thus thespherical
vector in
E(t
+r)
is03C8t/2
and the result follows. 0 LEMMA 4. For each w and t inR,
the mapf ~ 03C8tf
is aK-isomorphism
betweenE(w)
andE(w
+2t).
Proof.
The definitionof I(t)
in 1.3 shows thatif f ~ I(w) and f’ E 1(2t
+r),
thenf1 belongs
toI(w
+2t).
Inparticular, f2t+rJ belongs
toI(w
+2t)
for allf
in1(w). Going
over to thecompact picture,
we see that the mapf ~ f2t+rf is
a K-isomorphism -
indeed it isjust
theidentity
map in thecompact picture.
On theother
hand, by
Lemma3,
this map becomesf ~ 03C8tf
in thenoncompact picture.
D As remarked in
1.3,
for each m, 03C0mgives
ahomomorphism
ofe(g)
into theWeyl algebra
3Y’. Let us write"fi/ m
for theimage.
Then"fi/ m
contains all constant coefficient differentialoperators
and is stable under theadjoint
action of03C0m(G).
The next Lemma is due to Kostant.
LEMMA 5. For each
p E F2m, the
operatorpDm belongs
to"fi/m. Moreover,
themap p H
pDm
intertwinesF2.
with asubrepresentation of
theadjoint
actionof
Gon
Wm.
Proof. (Kostant)
Fixf
EE(m), g
E G and letf ’
=Dm03C0m(g)-1f.
Thenby
Lemma2.3, f’ ~ E(-m) and n-m(g)f’
=Dmf.
Now,
if p EF2m ~ E(r
+2m),
then as remarked in theproof
of Lemma4, pf’ ~ E(m). Further,
it is easy to check that03C0m(g)(pf’)
=(03C0r+2(g)p)(03C0-m(g)f’).
Rewriting
this in termsof f,
weget
Now set p = 1 in
(1).
This shows thatBy
the remarkspreceding
thisLemma,
theright
sideof (2)
is in1f/’ m.
On theother
hand,
sinceF,.
isirreducible,
the set{03C0r+2m(g) · 1|g ~ G}
spansF2m.
Thisproves the first
part
of the Lemma. The secondpart
is nowjust
theidentity (1).
D Let us write
Om
for the differentialoperator 03C8mDm.
In Lemma 2 we showedthat in the
representation
of gc onF2m,
theCayley
transform c mapsgm
to.pm.
Combining
this with Lemma 5gives
us thefollowing key
result.PROPOSITION.
Om
=03C0m(c)~mDm03C0m(c)-1.
~2.2.
Proof of
Theorem 1For each
integer
m0,
we define a Hermitian form(,)m
onE(m) by
where f and f ’ belong
toE(m) and ~,~
is as in 1.2.Proposition
1.3 shows that(,)m
is03C0m(g)-invariant. Consequently,
foreach p
asin 1.3 there is a constant
qm(03B2)
such that for allf
EI(m),,
The
right
side of(2)
can beexpressed
in thenon-compact picture
as follows:LEMMA 1.
Let If¡
be as in2.1,
thenfor
allf
EI(m),
Proof.
This is easy to check for m = 0. Thegeneral
case followsby
Lemma2.1.4. D
COROLLARY. For each
f
EE(m)p, 03C8mDmf
=qm(03B2)f.
Proof.
This followsby combining (1), (2)
and the Lemma.~
Now consider the restriction of
(nm, C~(n))
to 1. The formula in 1.3 shows that iff ~ P
has03C0m(as)-weight 03A303BBi03B5i,
then it has7r(a’)-weight 03A3(03BBi
+ m -r)03B5i.
Combining
this withProposition
1.2gives
LEMMA 2. Let V be
a finite dimensional,
irreducible03C0m(I)-subrepresentation of CI(n)
withhighest weight 03A3i 03BBi03B5i,
thenfor
allf
E VFurther,
there is anad(I~)-invariant
elementYm
inU(I)
such that7r.(Y.) = cpm Dm.
0We are now in a
position
to prove Theorem 1.Proof of
Theorem 1. LetZm
=ad(c) Ym,
thenZm
Eand Proposition
2.1shows that
03C0m(Zm) = A..
Now
if f is
ahighest weight
vector for03C0m(I)
withweight
2Si bi03B5i
then 1.3implies
that03C0m(c)f
is ahighest weight
vector for7r.(t,,)
withweight fi
=Si biyi.
Thus
by
Lemma2,
3. Certain
unitary representations
In this section we prove Theorem 2 and extend our results to the universal
covering
group.3.1.
Proof of
Theorem 2Let
E(m)
and(, )m
be as in2.2,
and writeV(m)
for the Harish-Chandra module of K-finite vectors inE(m). If R(m)
is the radicalof (, )m,
thenR(m)
is a submodule ofV(m) ;
and thequotient Q(m)
=V(m)/R(m)
is a Harish-Chandra module with anon-degenerate
Hermitian form.Theorem 1
completely
determines the K-structure and the form onQ(m).
Wewill show that the form is definite on certain submodules of
Q(m).
For this weneed an
elementary
Lemma. Fix apositive integer m
and let 9 and -4 be the sets ofhighest weights
ofK-types
of inQ(m)
andR(m) respectively.
LEMMA.
Suppose
S is a subsetof 2
with the property thatfor
each03B2~S, 03B2 ± 03B3j~S~R for
eachj.
Then03A3{Q(m)03B2 |03B2 ~ S}
is ag-submodule of Q(m).
Proof.
From 1.1 we see that thet-weights
of theadjoint representation
are+ yi and 1 2(±03B3i ± 03B3j).
So ifV03B2
is aK-type
ofV(m),
then03C0m(g)V03B2 ~ 03A3{V03B1|03B1 = 03B2, 03B2 ± 03B3j}.
Now let W =
LpeS V(m)03B2.
Then theassumption
of the Lemma shows that03C0m(g)W ~ W
+R(m),
whichclearly implies
the result. DProof of
Theorem 2. First suppose that(a)
d = 4k and m =2p -
1 withk, p E N.
Thenqm(03B2)
becomesLet us write 9 for the
K-types
ofQ(m) and ai
fork(n -
2i +1).
The formulashows that 2 consists
of fl
=Li biyi
such that(a) b, bn
E Z and(b)
foreach
i, either bi + ai -p or bi + ai a
p.Let
Sl = {03B2~2|b1 ··· bl p - al and - p - al+1 bl+1 ··· bn}.
Then 9 is the
disjoint
union ofSo,..., Sn
and eachSI
satisfies thehypothesis
ofthe Lemma above. Thus if we write
QI
for03A3{Q(m)03B2|03B2~Sl},
then eachQI
is asubmodule,
andQ(m)
=Qo
+ ··· +6n
It iseasily
checked thatfor fi
in a fixedSl,
allqm(03B2)
have the samesign. Consequently QI
is unitarizable.The
argument
for case(b),
when d ==2(mod 4)
and m ---n(mod 2),
is similar.D It can be shown that the
representations QI
areirreducible,
but theproof
is abit involved. Once this is
proved, Proposition
6.1 of[VZ]
can beapplied
toshow that
QI
is anA(ql, 03BB),
where q, is a 0-stableparabolic
whose Levicomponent
is a real form of f. Wepostpone
this to a future paper.The
representations Qo
andQn
are theholomorphic (and anti-holomorphic)
discrete series considered
by
Wallach in[W]. They
have 1-dimensional lowestK-types. Renormalizing
our form to be 1 on the lowestK-type gives
anexplicit
formula for the form considered
by [W]!
Thisyields
Wallach’s results on theanalytic
continuation of these series. Since these results arealready
known(see [FK]),
we omit the details.Finally,
let uspoint
out that Theorem 2applies
to the groupsSO* (4n) (with
d =
4), O(4p
+1, 2) (with d
=4p), E7(-25) (with d
=8), U(n, n) (with d
=2)
andO(4p
+3, 2) (with d
=4p
+2).
3.2.
Degenerate
seriesfor
the universalcovering
groupLet
G
be the universalcovering
group of G and letL
be the inverseimage
of L inG. Then it may be shown that
~
L x Z. The characters of Z may be identified with the set[0, 1) through
thecorrespondence 03B1 ~ 03BE03B1
where03BE03B1(~)
=exp(203C0i03B1~).
We define 03C003B1,t to be the
representation
ofG by right
translations onObserve that
1(0, t)
isjust I(t).
An easy calculation shows that the
K-types
occur withmultiplicity
one andhave
highest weights
such thatPlt
= 0 andAs
before, restricting
to N andusing
the exp map, weget
aninjection
from1(a, t)
toC~(n).
Let us writeE(a, t)
for theimage.
The spaceE(a, t) depends
onboth a
and t,
however the action ofna,t(g) depends only
on t.We observe also that the Hermitian dual of
E(a, t)
isE(a, - t).
Asbefore,
Dmintertwines
E(a, m)
with its Hermitiandual,
so that weget
a Hermitian form onE(a, m)
for each m. Thesignature
of this form isgiven by
Theorem 1(the only
difference is that
the b j
are in Z +a).
Let us write
V(a, m)
for the Harish-Chandra module ofE(a, m)
andQ(a, m)
forthe
quotient
ofY(a, m) by
the radical of the form.Arguing
as in theproof
of Theorem 2 we find that if(a) d
= 4k and m is even,or if
(b) d
= 4k + 2and m ~ n (mod 2),
thenQ(1 2, m)
is a direct sum of n + 1unitary representations
whoset-types
may beexplicitly computed
as before.Appendix
In this
appendix
westudy
thereducibility
of1(a, t) using
a result of Guillemonat.For the group
Sp(n, R),
Kudla and Rallis[KuR]
describe how this may be done.However their result
depends crucially
onProposition
1.2 of[KuR]
which doesnot
obviously
hold for other tube domains.Guillemonat in
[G],
considers aproblem
very similar to the one discussed inour paper. He studies
representations
of g which have a one-dimensionalf-type
annihilated
by
a certain ideal J in theenveloping algebra.
Theserepresentations
are constructed as follows:
Let a be as in 1.1 and
let 3
be the center of . Fix 03BB E a*and x E 3*
and let ~~,03BB bethe
ix-semi-spherical
function on G with infinitesimal charactercorresponding
to 03BB. The
representation V’,Â
of[G]
is obtainedby
theright
translations of CPx,;’.This
representation
has a natural Hermitian form(normalized
to be 1 on~~,03BB).
The
quotient
ofV’~,03BB, by
this form is an irreduciblerepresentation denoted V,,,
inSection 5 of
[G].
The connection with our paper is
that V~,03BB
is a constituent ofI(a, t)
fora =
ix(H)/2n (mod Z)
and t =03BB(E)/n
where H and E are in Section 2.2 and Section 3.1 of
[G]. (This
followsby elementary
infinitesimal character andf-type considerations.) Furthermore,
forthese values of the
parameters, V’~,03BB
andI(a, t)
have the samet-types. Therefore, I(a, t)
is irreducible if andonly
if thecorresponding V~,03BB
is irreducible. We claim that thishappens
if andonly
if the formon V’,,
isnon-degenerate.
Thisdepends
on the
following simple
observation:If the form is
degenerate
then therepresentation
isclearly
reducible.Suppose
the form is non
degenerate.
Since ~~,03BB is acyclic
vector, it suffices to show that therepresentation
iscompletely
reducible. This is a consequence of the next Lemma.LEMMA.
Suppose
V is a Harish-Chandra module with anon-degenerate
invariant Hermitian
form. If
eachK-type
in V hasmultiplicity
one, then V iscompletely
reducible.Proof
If W be a submoduleof v
thenW 1 ~ {03BD
EV|(v, w)
= 0 for all w EW}
isalso a submodule. On the other
hand,
since eachK-type
in Vhasmultiplicity
one, the form is definite on each
K-type.
Since differentK-types
areorthogonal,
it follows that
W 1
containsexactly
theK-types
not in WConsequently
V = W ~ W~.
aIn Section 6 of
[G]
it is shown that the formon V’~,03BB
isnon-degenerate
if andonly
if theexpressions
in formulas(1’)
and(2’)
of[G
Section6.9]
are non-zero.Rewriting
these formulas in our notation therequirement
becomesThis is
equivalent
to the condition that for each i =l, ... , n,
Thus for d ~
0 (mod 4), 1(0, t)
is reducible for oddintegral
valuesof t,
and1(1, t)
is reducible for evenintegral
values of t. While for d ---2(mod 4), 1(0, t)
isreducible when t - n is an even
integer
and1(1, t)
is reducible when t - n is anodd
integer.
For odd values
of d,
therepresentations 1(0, t)
andI(t, t)
are reducible forintegral
values of t and also forhalf-integral
values. There areunitary representations
at these otherpoints
which are not amenable to thepresent
analysis.
We intend to discuss these and otherunitary
constituents of1(t)
in afuture paper.
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