Multiplicative Dedekind ~-function and representations of finite groups
par GALINA VALENTINOVNA VOSKRESENSKAYA
RÉSUMÉ. Dans cet article, nous étudions le
problème
de trou-ver des groupes finis tels que les formes modulaires associées aux
éléments de ces groupes au moyen de certaines representations
fidèles appartiennent à des classes particulières de formes modu- laires
(appelées produits ~ multiplicatifs).
Ceproblème
est ouvert.Nous trouvons des groupes
métacycliques
ayant cettepropriete
et décrivons les p-sous-groupes de
Sylow, p ~
2, de tels groupes.Nous donnons
également
un aperçu des résulats reliant les pro-duits ~ multiplicatifs
et les éléments d’ordre fini deSL(5, (C).
ABSTRACT. In this article we
study
theproblem
offinding
suchfinite groups that the modular forms associated with all elements of these groups
by
means of a certain faithful representation be-long
to aspecial
class of modular forms(so-called multiplicative
~-products).
Thisproblem
is open.We find
metacyclic
groups with such property and describe theSylow p-subgroups, p ~
2, for such groups. We also give areview of the results about the connection between
multiplicative
~-products
and elements of finite orders inSL(5, C).
1. Introduction.
The
investigation
of connections between modular forms and represen- tations of finite groups is aninteresting
modern aspect of thetheory
ofmodular forms.
In this article we
study
theproblem
offinding
such finite groups that the modular forms associated with all elements of these groupsby
meansof a certain faithful
representation belong
to aspecial
class of modular forms(so-called multiplicative q-products) .
Thisproblem
is open: all such groups have not been found. It will beinteresting
to find thecomplete
classification. G.Mason gave an
example
of such a group: the groupM24.
This group is unsolvable and
large
but it ispossible
to find groups associated withmultiplicative 17-products
which are notsubgroups in.A/124-
So we havea non-trivial
problem
of classification. Also sometimes for the same groupwe can find several faithful
representations
with ourproperty.
And it is thesecond
aspect
of classification. The author has shown that all groups of order 24 have thisproperty.
Therepresentation
in this case is theregular
one
[17].
The
present
paper continues the author’sinvestigations
ofmetacyclic
groups which has been started in the articles
[19], [22].
Inparticular
wehave studied
completely
the case of dihedral groups. We find allmetacyclic
groups with such
property
withgenetic
code a, b : a~ = = e,b-lab
=ar > in the case when the
cyclic
groups a > and b > have no nontrivial intersection.We consider the groups and their
representations
in detail and we writeexplicitly
suchrepresentations
that the associated modular forms are mul-tiplicative q-products.
Sometimes for the same group we find distinct such faithfulrepresentations.
We use our theorem about such abelian groups which is also formulated.
It was
proved
in[21].
Also we describe theSylow p-subgroups, p # 2,
for such groups. In conclusion we
give
a review of the results about the connection betweenmultiplicative q-products
and elements of finite orders inSL(5, ~).
2.
Multiplicative q-products.
The Dedekind
q-function
is definedby
the formulaz
belongs
to the uppercomplex half-plane.
In this article we consider the modular forms which can be
completely
described
by
thefollowing
conditions:1.
They
are cusp forms ofintegral weight (with characters);
2.
they
areeigenforms
withrespect
to all Heckeoperators;
3.
they
have zeroesonly
in the cusps and every zero hasmultiplicity
1.A
priori
we don’t suppose that these functions are modifiedproducts
ofDedekind
17-function.
But in fact it is so, there are 28 such functions. Itwas
proved
in[18].
Let us
give
thecomplete
list.Forms of the
weight
1:Forms of the
weight
2:Forms of the
weight
3:Forms of the
weight
4:Form of the
weight
5:~4(4z)r~2(2z)r~4(z).
Forms of the
weight
6:1]12(2z).
Form of the
weight
8:Form of the
weight
12:Ti 24 (z) -
We add to this list two cusp forms of
half-integral weight, q (24z), 7/~(8~).
These functions we shall call
multiplicative 1]-products
becausethey
havemultiplicative
Fourier coefficients.D.Dummit,
H.Kisilevskii and J.McKay
obtained the same list of cusp forms from anotherpoint
of view:they
showed that among functions of the kindwhere ak
and tk
EN, only
these 30 functions hadmultiplicative
coeffi-cients.
They
checked itby computer
calculations[3].
Yves Martin found allq-quotients.
But thequotients
cannot be used in our case. From var-ious
points
of view these functions have been studied in recent works of American andJapanese
mathematicians~1~, [3], [4], [6]
to[14].
3.
Representations
of finite groups and modular forms.We
assign
modular forms to elements of finite groupsby
thefollowing
rule. Let $ be such a
representation
of a finite group Gby
unimodularmatrices in a space V whose dimension is divisible
by
24 that for anyelement g
E G the characteristicpolynomial
of the operator~(g)
is of theform:
With
each g
E G we can associate the functionThe function is a cusp form of a certain level
N(g)
and of theweight
k(g) - z ~~=1 ~
with the characterequal
to the character of thequadratic
field
We shall consider an
interesting problem:
the
problem of finding
suchfinite
groups that all modularforms assigned
to all elements
of
the groupby
meansof
afaithful representations
are mul-tiplicative q-products.
Now this
problem
is open: all such groups have not been found.G.Mason has shown that all functions associated with elements of the Mathieu group
M24 by
means of therepresentation
on the Leech lattice aremultiplicative q-products.
There are 21 functions of this kind.It is
possible
to find groups associated withmultiplicative q-products
which are not
subgroups
inM24.
Theorem 3.1.
Let g
be such an element in G that thefunction
associated with g
by
arepresentation (as
describedabove)
is amultiplica-
tive
1]-product
then thefunctions qh(z), h
=gk,
are alsomultiplicative q-products.
In Table 1 we list all the
possible assignments
ofmultiplicative
ducts to elements of
cyclic
groups. It is very useful in ourproofs.
Theorem 3.2. For any
cyclic
groupZn,
1 G n23,
there are such repre- sentationsTl
andT2,
dimTl
= nl, dimT2
= n2, nj n2 =24,
that the cuspforms i7g(z)
associated with all elements EZn by
meansof representations n2Tl, nlT2,
are alsomultiplicative
These theorems are
proved
in[19], [20].
A
representation
of a group will be called desired orof permissible type if, by
means of thisrepresentation,
themultiplicative q-products
are asso-ciated with all elements of this group. We shall not call these groups and
representations "admissible"
because the word "admissible" has anothersense in the
theory
ofautomorphic representations.
In this paper we shall list the
metacyclic
groups with faithful represen- tations of this kind. Permissible groups are listed up toisomorphism.
The desired groups can contain
only
elements whose orders do not exceed 24 and are notequal
to13, 17,
19. Due to Theorem 3.1. it is sufficient to consider therepresentations only
for elements that do notbelong
to thesame
cyclic
group. Theidentity
element of the groupcorresponds
to thecusp form
Tj 24 (z) -
If a
permissible
group is asubgroup
of anotherpermissible
group then it is sufficient tostudy
in detail thelarger
grouponly.
The result for thesubgroup immediately
follows.We shall use the
following
theorem which isproved
in[21].
Theorem 3.3. Let G be an abelian group and T a
faithful representation
such that
for
every g E G the characteristicpolynomial of
theoperator
T(g)
isof
theform
thecorresponding
cuspform
being a multiplicative
Then G is a sub-group
of
one(or several) of
thefollowing
groups:We include
only
the maximal abelian groups.Table 1.
- -
4.
Metacyclic
groups and modular forms.Metacyclic
groupis, by definition,
a finite group with acyclic
normalsubgroup
such that thecorresponding factor-group
is alsocyclic.
The
genetic
code of ametacyclic
group is a, b : e, bs - e,b_lab
= a’’ > .In this paper we
completely analyze
the cases when m =6, 8, 9, 12, 16, 18,
24 and thecyclic
groups a > and b > have no nontrivial intersection. The cases m =3, 4, 5, 7, 11,
23 were considered in the article[19],
the cases m =10, 14, 15, 20, 21,
22 can be found in thearticle
[22].
The result can be stated in the form of thefollowing
theorem.Theorem 4.1. Let G be a
metacyclic
group with thefollowing genetic
codea, b : = e, e,
b-lab
= ar >, m =6, 8, 9,12,16,18, 24,
such that the modular
form
associated with each elementof
this groupby
means
of
afaithful representation is
amultiplicative 1J-product
and thecyclic
groups a > and b > have the trivial intersection. Then thepossible
valuesof
m, s, r(up
toisomorphism)
are listed in the Table 2.Table 2.
The dihedral groups of
permissible types
were studied in detailby
theauthor in the
previous
paper[15].
4.1.
Metacyclic
groups of the kinda, b : as -
= e,b-lab = a5
> .4.1.1. = e,
b-lab
=a5
>.The desired
representation
is the direct sum of all the irreducible repre- sentations with themultiplicity
one.The cusp
corresponds
to the elementsa,a5,
the cusp formq 4(6z) corresponds
to the other elements of order 6. The cusp formcorresponds
to the elementsa2,a4,
the cusp formq8 (3z)
cor-responds
to all the other elements of order 3. The cusp formq 12 (2z)
cor-responds
to the elements of order 2.This group contains
D6
as asubgroup.
Therefore the groupD6
is alsopermissible.
4.1.2. The group a, b :
a 6
=e, b4 =
e,b-lab = a5
>.This group is
permissible.
The desiredrepresentation
is theregular
representation.
The cusp formsq’(6z), 7~(4~), 178(3z) , r~12(2z)" 1724(Z)
correspond
to elements of the group.Let us consider the groups whose elements have admissible orders but the groups have no
representations
of the desiredtype.
Thegenetic
codeof such a group is = e, bs = e,
b-lab = a5
>, s =8,12,16, 24.
Ifs =
12,
then the group contains7G6
x26 .
If s =16,
then the group containsZ16 x 7L2.
If s =18,
then the group containsZ18
x22.
If s =24,
then thegroup contains
7G24
x7G2.
But these abeliansubgroups
are notpermissible.
The case s = 8 is more difficult.
Let T be a desired
representation, Tl
be a trivialrepresentation (Tl (g) _ 1, Vg
EG~.
Let denote as xT and Xl their characters. It has beenproved
in
[21]
that if the groupZ12
x7G2
is of a desiredtype,
then all elementsof the order 12
correspond
to the cusp formq~ (12z) ,
all elements of order6
correspond
toq 4(6z),
all elements of order 4correspond
toq6 (4z),
allelements of order 3
correspond
to178(3z),
all elements of order 2correspond
to
7~(2~).
ThereforexT(g)
=0,9 =I
e,xT(e)
= 24.Using
this fact it is easy to show that in ourmetacyclic
group the cusp forms7~(12~), ql(8Z), q~(6z), q6 (4z), q8 (3 z), 7~(2~), T,24 (Z) correspond
toelements of the group.
Consider the scalar
product
xT, Xl>= 48 ~
24= 2.
Since this number must be aninteger,
we obtain a contradiction and the desiredrepresentation
T cannot be constructed.
4.2.
Metacyclic
groups of the kinda, b : a 8
=e, b’
= e,b-lab
= ar > .4.2.1. The group a, b :
a 8
= e,b2 =
e,b-lab = a3
>.This group has the
following
irreduciblerepresentations:
..
The desired
representation
is the direct sumAll elements of order 8
correspond
to the cusp formr~2(8z)r~2(4z),
allelements of order 4
correspond
to the cusp the elementa4 corresponds
to~8(2z)r~g(z),
all the other elements of order 2correspond
to the cusp form
q 12 (2z).
4.2.2. The
a, b :a 8
= e,b2 =
e,b-1 ab = a5
>.The desired
representation
is the direct sum of all irreduciblerepresenta-
tions with the
multiplicity
2. Thecorrespondence
between modular forms and elements of the group is as in 4.2.1.4.2.3. The b :
ag
=e, b2 =
e,b-l ab
=a7
>.This group has the
following
irreduciblerepresentations:
The desired
representation
is the direct sumThe
correspondence
between modular forms and elements of the group isasin4.2.1.We can consider another desired
representation:
All elements of order 8
correspond
to the cusp formr~2(8z)r~(4z)
xr~(2z)r~2(z),
the elements of order 4correspond
to the cusp formr~4(4z)
xq~ (2z)q~(z),
the elementa4 corresponds
tor~$(2z)r~g(z),
all other elements of order 2correspond
to the cusp formTj 12 (2z).
4.2.4. The group a, b :
a8
=e, b4
= e,b-lab = a3
>.This group has the
following
irreduciblerepresentations:
The desired
representation
is the direct sum that containsT13, T14
with themultiplicity 2,
all otherrepresentations
with themultiplicity
1.All elements of order 8
correspond
to the cusp formr~2(8z)~2(4z),
theelements
a2, as, a2b2, asb2 correspond
to the cusp form~4(4z)r~4(2z),
allother elements of order 4
correspond
to the cusp formr~6(4z),
the elementa4 corresponds
to7~ (2~)7~ (~), elements b2
anda4b2 correspond
to the cusp form7]12 (2z).
4.2.5. The group a, b :
a8
= e,b4 =
e,b-lab = a5
>.The desired
representation
is the direct sum of all the irreducible repre- sentations with themultiplicity
one. Thecorrespondence
between modularforms and elements of the group is as in 4.2.4.
4.3.
Metacyclic
groups of the kind a, b : am =e, bs
= e,b-lab == aT
>,m=9,18.
The group
Z18
xZk
is notpermissible
if k > 1. The groupZg
xZk
is notpermissible
if k > 2.So we must consider for m = 9 the variants:
andform=18
The groups
D9
andD18
arepermissible [15].
4.3.1. The group a, b :
a9
= e,b3 =
e,b-lab = a4
>.This group is of the order 27 and has 8 elements of order 3.
Let T be a desired
representation, u
elementscorrespond
toThe number u can be
equal
to2,4,6,8.
The scalarproduct
where Xl is the character of the trivial
representation.
This number must be an
integer,
but it is not aninteger
if u =2, 4, 6, 8.
We obtain a contradiction and the desired
representation
T cannot be con-structed.
This group is
isomorphic
to the groupGI
~a, b : a9 == e, b3
=e,
b-1ab = a7
> . So the groupGi
is notpermissible. G1
is asubgroup
inthe group
So the groups
G2
andG3
are notpermissible.
4.3.2. The group a, b :
a9
= e,b6
= e,b-lab = a2
>.This group contains a
subgroup
a, c :a9
=e, c3
= e,b-1 ab
=a4
>(c
=b2)
which is notpermissible.
Our group is
isomorphic
to the groupGl
~ a, b :a9
= e,b6 =
e,b-1 ab
=a 5> -
So the groupGl
is notpermissible. Cl
is asubgroup
in the groupSo the groups
G2
andG3
are notpermissible.
4.3.3. The group a, b :
a9
= e,b4
= e,b-lab
>.This group is of order 36 and has 12
conjugacy
classes. This group is per- missible. The desiredrepresentation
contains two irreducible 2-dimensionalrepresentations
which send the element a to the matrix of order 3 withmultiplicity 2,
other irreduciblerepresentations
are included with multi-plicity
2. The cusp formsq(18z)q(6z), r~2(9z)r~2(3z), r~3(6z)r~3(2z),
1]12(2z), r~24 (z) correspond
to elements of the group.4.4.
Metacyclic
groups of the kinda, b : a 12
= = e,= ar > .
This group contains a
subgroup
which isgenerated by
the elementsa2
and b. This
subgroup
has agenetic
code: c, d :c6
= e, d’ = e, = cT > .Taking
into account the results of4.1.,
we see that our group is notpermissible if s # 2, 4, 6.
The group a, b :a12
= e,b6
= e, = a’’ >is not
permissible
because it contains thesubgroup Z12
x7~3
which is notpermissible.
4.4.1. The groups a, b :
a12
= e,b2
= e, = a~’ >.The number r can be
equal
to5, 7,
11. In all these cases theregular representation
is the desired one. It has beenproved
in[17]
that theregular representation
for any group of order 24 ispermissible.
The cusp forms~(12~), q4 (6z), r~6 (4z), r~g (3z), 7~(2~), r~24 (z) correspond
to elements of the group.4.4.2. The groups
a, b : a12
= e,b4
= e,b-1 ab
= a’’ >.In this case the number r is
equal
to one of the values5,7
or 11. Thesubgroup
H ^--J a > x b > isisomorphic to Z12
xZ2 .
It has beenproved
in
[21]
that if the groupZ12
xZ2
ispermissible
then there is thesingle possibility
for thecorrespondence
between elements of the group and cusp forms:~(12~), q4 (6z), r~6 (4z), r~g (3z), 7~(2~), ~24 (z) correspond
to theelements of the group
Z12
xZ2.
In our group of order 48 each elementconjugate
to an element in H. So if T is apermissible representation
of ourgroup then
xT(g)
=0, if g #
e. Consider the scalarproduct
xT, xtr >=48 - 2.
But this number must be aninteger.
We obtain a contradiction.4.5.
Metacyclic
groups of the kinda, b : a16
= = e,= ar > .
Because the group
Z16
XZn
is notpermissible
if m > 1 we must consideronly
the cases s =2,
r =7, 9, 15; s
=4,
r =3, 5,11,13.
The dihedral group
D16
ispermissible.
It was considered in[15].
4. 5.1. The group a, b :
a 16
= e,b2 =
e,b-1 a b
=a7
>.This group has the
following
irreduciblerepresentations:
The desired
representation
is the direct sumAll elements of order 16
correspond
to the cusp form all elements of order 8correspond
to the cusp formr~2(8z)r~2(4z),
the ele-ments
a4, a12 correspond
to the cusp formr~4(4z)r~4(2z),
the elementa8
cor-responds
to7~ (2~)7~ (~),
all other elements of order 2correspond
to the cusp formTj 12 (2z).
4.5.2. The group a, b : = e,
b2
= e,b-lab = a9
>.The desired
representation
is the direct sum of all the irreducible repre- sentations withmultiplicity
1. Thecorrespondence
between modular forms and elements of the group is as in 4.5.1.4.5.3. The groups
a, b : a 16
=e, b4
=e, b-lab
=aT,r
=3, 5, 11, 13
>.The
subgroup
H ~a2
> xb2
>~7Gg
xZ2.
It has beenproved
in[21]
that therepresentation
of the group x h > ispermissible only
in thefollowing
three cases:(1)
all elements of order 8correspond
to the cusp formr~2(8z)r~2(4z),
allelements
of order 4correspond
to the cusp form7~(4~)7~(2~),
theelement
f4 corresponds
tor~8(2z)r~8(z),
two other elements of order 2correspond
to the cusp formq 12 (2z).
(2)
all elements of order 8correspond
to the cusp formr~2(8z)r~2(4z),
allelements of the order 4
correspond
to the cusp formr~4(4z)r~4(2z),
allelements of order 2
correspond
to(3)
all elements of order 8correspond
to the cusp formq 3(8z),
all ele-ments of order 4
correspond
to the cusp formr~6(4z),
the element hcorresponds
tor~g(2z)~8(z),
two other elements of order 2correspond
to the cusp form
Tj 12 (2z).
Let us consider the case r = 3.
Let T be a desired
representation, lF
be such one-dimensional represen- tation that = = i. Let denote as XT and X.1, their charac- ters. Because the element acorresponds
toq(16z),q(8z)
theelement a2 corresponds
to the cusp theelement a4 corresponds
tothe cusp form
r4(4z)4(2z),
theelement a8 corresponds
to the cusp formr~$(2z)~$(z).
So for the group H the third variant is excluded. If an elementg #
e,b2, a8, a8 b2
then we haveXT(9)
= 0 or +Xq,(g3)
= 0. Theelements
b2, a8 b2are conjugate
andcorrespond
to the same cusp form. Sowe see that the scalar
product
If the elements
b 2, a8b 2 correspond
to1]12(2z)
thenXT (b2)
= 0 and thescalar
product
isequal
to xT,x~ > = 64 ’ (24
+8) = 2 .
But this number must be aninteger.
We obtain a contradiction and the desired representa- tion T cannot be constructed.If the elements
b2, a 8b 2 correspond
to thenxT(b2)
= 8 andthe scalar
product
isequal
to xT,64 ’ (24
+ 8 - 2 ’8)
=Since
this number must be an
integer,
we obtain a contradiction.The group
a, b : a16
=e, b4
= e,b-lab
=a3
> isisomorphic
toa,b : a16
=e,b4
=e,b-lab= all > .
The group a, b :
a 16
= e,b4
= e,b-lab
=a5
is notpermissible.
It canbe
proved similarly.
This group isisomorphic
to a, b :a16
= e,b4
= e,b-lab
= > .4.6.
Metacyclic
groups of the kinda, b : a 24 =
= e,’
The group
Z24
xZ
is notpermissible
if m > 1. So we have thesingle possibility:s
= 2.The group C a, b :
a24
= e,b2
= e,b-1 ab
=a17
> ispermissible.
The desired
representation
contains all irreduciblerepresentations
withmultiplicity
1except
such one-dimensionalrepresentations (D
=-1. The cusp form
q (24z) corresponds
to all elements of order24,
the cusp formq 2 (12z) corresponds
to all elements of order12,
the cuspcorresponds
to all elements of order8,
the cusp form1]4 (6z) corresponds
toall elements of order
6,
the cuspcorresponds
to all elements of order4,
the cusp formTj 8(3z) corresponds
to all elements of order3,
the cusp formTj 12 (2z) corresponds
toa12,
the cusp formcorresponds
tob, al2b.
.All other groups a, b :
a24
= e,b2
= e,b-1 ab
= ar > are not per- missible. Let us prove it. If T is apermissible representation
of suchmetacyclic
group thenxT(g) - 0,
e. Then the scalarproduct
XT, Xtr >== -
2-4 - ’1
48 - * But this number must be aninteger.
We obtaina contradiction. The theorem is
proved.
4.7.
Metacyclic
groups andmultiplicative q-products.
Maintheorem.
Now we can formulate the
following
result.Theorem 4.2. Let G be such a
metacyclic
group with thefollowing genetic
codesuch that a modular
form
associated with each elementof
this groupby
means
of
afaithful representation
is amultiplicative q-product
and thecyclic
groups a > and b > have no nontrivial intersection. Thenfor
rra, s, r(up
to anisomoqphism )
there areonly
thefollowing possibilities:
It has been
proved
in this article and in the works[19], [22].
5.
Sylow subgroups
ofpermissible
groupsTheorem 5.l. Let G be a
finite
group such that there is afaithful
repre- sentation T with thefollowing property.
For every g E G the characteristicpolynomial of
theoperator T(g)
isof
theform Py(x) _ J)lk,
and the
corresponding
cuspform qg (z)
== is amultiplicative
Then
for
theSylow p-subgroups, 2,
there areonly
thefollowing possibilities:
Proof.
The
Sylow 3-subgroups.
We shall describe all the cases in detail.
A
permissible 3-group
can containonly
elements of order1,
3 and 9.Let T be a desired
representation, Tl
be the trivialrepresentation (Tl (9) == 1, d9
EG.)
The group
23
xZ3-
We must consider three cases.
(1)
All elements of order 3correspond
to the cusp formq 8(3z).
ThenXT(e) = 24, XT(9)
=0, ord(g) ~
3. The scalarproduct
But this number must be an
integer.
We obtain a contradiction and the desiredrepresentation
T cannot be constructed.(2)
All elements of order 3correspond
to the cusp formIn this case the group is
permissible.
The desiredrepresentation
contains
Tl
withmultiplicity 8,
all other irreduciblerepresentations
with
multiplicity
2.(3)
In this case u elementscorrespond
to the cusp form andv elements
correspond
to the cusp formr~$(3z),
where u and v arepositive integers.
The group ispermissible. Since 9 and g2 correspond
to the same modular
form,
then u and v are even. The scalarproduct
Since this number must be an
integer
we have u = 2. This vari-ant is suitable. Let
f
andf2
be the elements whichcorrespond
to?~ (3~)~ (2~).
LetTk
be an one-dimensionalrepresentation
of our group and Mk be itsmultiplicity
in T. IfTk(f)
= 1 then m~ = 4. For otherone-dimensional
representation
mk = 2. Therepresentation
T is per-missible.
The group
Z3
xZ3
XZ3-
Let us prove that this group is not
permissible.
We must consider twocases.
(1)
All elements of order 3correspond
to the cusp form The scalarproduct
But this number must be an
integer.
We obtain a contradiction.(2)
In this case u elementscorrespond
to the cusp formq6 (3z) T,6 (Z) ,
andv elements
correspond
to the cusp form71 8(3z),
where u and v arepositive integers.
The numbers u and v are even. The scalarproduct
Since this number must be an
integer
we have u =14,
ml = 4. LetTk
be an one-dimensionalrepresentation
of our group and mk be itsmultiplicity
in T.Let ul be the number of
elements g
whichcorrespond
to the cusp form1J6(3z)1J6(z)
andTk(g)
=1;
let U2 be the number of elements g whichcorrespond
to the cusp form176(3z)176(z)
andTk(g) = (3;
letu3 be the number of
elements g
whichcorrespond
to the cusp form1J6(3z)1J6(z)
andTk(9) _ ~3 ~
Then U2 = U3, Ul +2~c2
= 14.If
Tk
is not trivial thenui # 14,
and v,l - u2 = 5. We obtain ul =8,
u2 =3,
and does not contain elementscorresponding
tothe cusp form
r~8(3z).
It contains 8 elements whichcorrespond
to thecusp form and the element e. Its order is
equal
to 9. Ifan element h
corresponds
to the cuspform T/8(3z)
thenTk(h) ~
1 for1. Then among
eigenvalues
of the operatorT(h)
there areonly
4eigenvalues equal
to 1 and the characteristicpolynomial
of theoperator
T(h)
cannot be(x3 - 1)$.
We obtain a contradiction.The groups
Z9
xZ3-
Let us prove that this group is not
permissible.
In this group there are 8 elements of the order
3,
18 elements of the order 9 and the element e.The number XT, Xl >=
i.
But this number must be aninteger.
Weobtain a contradiction.
The group
~9(3)
~a. II b. c : a3
= = =e; ab
=bac, ac
= ca. Ibc=cb> .
This group is of order 27 and it has 11
conjugacy
classes.They
are:The commutant is
generated by
the element c.This group has the
following
irreduciblerepresentations:
The desired
representation
is the direct sumThe elements a,
b, a2, b2,
ac,bc, a2c, b2c, ac2, bc2, a2c2, b2c2 correspond
tothe cusp form
Tj8(3z),
all other elements of the order 3correspond
to thecusp form
The group a, b :
a9
= e,b3
= e,b-lab = a4
> is notpermissible.
Thishas been
proved
in 4.3.1.The
Sylow p-subgroups,
p =5, 7,11.
Let us prove that the group
Z5
xZ5
is notpermissible.
In this group there are 24 elements of the order 5.The number XT, X 1
>= 25 - 5
But this number must be aninteger.
We obtain a contradiction. The elements of order 25 do not
correspond
tothe
multiplicative 17-products.
So we have theonly possibility: S(5) 7G5.
We consider the cases p =
7, 11 by
ananalogous
way. Now we can prove thefollowing
result.Theorem 5.2. There is no
finite
solvable group G such that afaithful representations assigns
to every elerrtentof
G amultiplicative 17-product,
every
product being assigned
to some element.Proo f.
The order of this group will be
equal
to2~ ’ 3~’ 5’ 7’
11.According
to thetheorem of Ph.Hall
[5]
there is asubgroup
of order 35 in this group. It is known that there isonly
one group of order 35. It isZ35.
But elements of order 35 do notcorrespond
to themultiplicative 17-product.
The theoremis
proved.
In conclusion we shall formulate an open
problem.
It will be very inter-esting
to
find
analgebraic
structure such that allmultiplicative 17-products,
andonly thern,
are associated with its elements in a natural way.6.
Multiplicative 17-products
and theadjoint representations SL(5,C).
In this section we
give
some results about the connection between mul-tiplicative 17-products
and elements of finite order inSL(5, C) by
means ofthe
adjoint representation. They
wereproved
in[16]
and[22].
Theorem 6.1. All
multiplicative 17-products of weight greater
than 1 canbe
associated, by
theadjoint representation,
with elementsof finite
orderin the group
SL(5, cC).
Theeigenvalues of
the element g ESL(5, C)
thatcorresponds
to agiven
cuspform
can befound uniquely,
up to apermutation of
thevaluers, up to raising eigenvalues
to a powercoprime
with the orderof
the element g, andup to
themultiplying
eacheigenvalues by
the samefifth
rootof unity.
Theorem 6.2. The maximal
finite subgroups of SL(5, ~C),
whose elements g have such characteristicpolynomials
that the cor-responding
cuspforms
aremultiplicative 17-products,
are the direct
products of
the group7G5 (which
isgenerated by
the scalar and oneof
thefollowing
groups:S4, A4
xZ2, Q8
X23, D4
XZ3, D6,
the
binary
tetrahedral group, themetacyclic
groupof
order21,
the groupof
order 1~ :
a, b . a3 - b2 - (ab)2
>, all groupsof
order16,
23
X23,29, ZIO, ZI 11 ~14, i Z15 -
Theorem 6.3. Let Ad be the
adjoint representation of the
groupSL(5, C) and g
ESL(5, C), ord(g) =1= 3, 6, 9, 21,
is such that the characteristicpoly-
nomials
of
theoperator Ad(g) is of
theform
Then the
corresponding
cuspform
is amultiplicative
",-product of
theweight k(g)
>1,
and allmultiplicative q-products of
theweight k(g)
> 1 can be obtainedby
this way.If ord(g)
=3, 6, 9,
21 thenby
this way we can obtain allmultiplicative
",-products of
theweight k(g)
> 1. Moreover in thiscorrespondence
thereare
five
modularforms
which are notmultiplicative r¡-products:
Sketch
of
theproof.
We shall express in this sketch all main ideas of the
proof.
Let T :
SL(5, (C) -> GL(V)
be a naturalrepresentation
ofSL(5, C)
in afive-dimensional vector space
V;
T* :SL(5, (C) -> GL(V*)
is theconjugate representation.
Let us consider the
representation
T ~ T* :SL(5, ~) ~ GL(V 0 V*).
This
representation
can bedecomposed
into the direct sumTi 0 T2,
whereTl
is theadjoint representation
Ad of the groupSL(5, C)
in 24-dimensional space,T2
is one-dimensionalidentity representation. Let Al, A2, A3, A4, A5
be theeigenvalues
of the operatorT(g).The
elementsÀk/Àm,
1l,
rrt G5,
are the
eigenvalues
of theoperator
T ~T*(g). Excluding
oneeigenvalue equal
to1,
we obtain the set ofeigenvalues
of theoperator Ad(g).
Since there are four or more values
equal
to 1 among theeigenvalues
ofthe
operator Ad(g),
theweight
of the modular form?7g(z)
associated with g isgreater
than 1.The number
equal
to 1eigenvalues
of theoperator Ad(g)
is determinedby
the number of
equal eigenvalues
of theoperator T(g).
Thiscorrespondence
is described in the table next page. We denote identical values
by
identicalsymbols
and different valuesby
differentsymbols.
Let us consider the
problem
for each order from 1 to 24. Theidentity
element
corresponds to r¡24(z).
Let us denote the characteristicpolynomial
of the operator