R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
C. D AVID
T
3-systems of finite simple groups
Rendiconti del Seminario Matematico della Università di Padova, tome 89 (1993), p. 19-27
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C.
DAVID (*)
1. Introduction.
We
present
here some further evidence insupport
of thefollowing conjecture,
first formulatedby Wiegold
in the seventies.CONJECTURE.
Every
finite non-abeliansimple
group hasexactly
one
T3-system.
Gilman [5]
has shown that theconjecture
holds for thesimple
groups
PSL(2, p)
with pprime, (indeed
it was this result thatprompt-
ed the
conjecture),
while Evans[4]
has done it for certain Suzuki groups. In both cases the action of theautomorphism
group on theG-defining subgroups
isalternating
orsymmetric,
and this too seemslikely
to reflect ageneral
truth.The Suzuki groups and the
P,SL(2, p)
are easier to cope with than thealternating
groups, no doubt because of the muchgreater diversity
of
subgroups
inalternating
groups. SinceA5
=PSL(2, 5),
Gilman’s re-sult
provides
the answer, whileA6
is so small that asimple
calculation is sufficient. The aim of this note is to sketch aproof
of thefollowing
result.
THEOREM. The
alternating
groupA7
hasjust
oneT3-system,
andthe action of
Aut F3
on theA7 defining subgroups
isalternating
orsymmetric.
The methods are
elementary throughout.
I see no way of establish-ing
theconjecture
for thegeneral alternating
groupAn .
(*) Indirizzo dell’A.: School of Mathematics,
University
of Wales,College
of Cardiff,Senghennydd
Road, Cardiff CF2 4AG.20
2.
T3-systems
and a result of Evans.Let
Fn
be a free group of finiterank n,
and let G be any group. We say that N is aG-defining subgroup
ofFn
if N andFn /N
= G. De-note the set of all
G-defining subgroups
ofFn by 2(G, n)
and notice that2(G, n)
is notempty
if andonly
if G can begenerated by
nelements.
For each 7 E
Aut Fn
and NE.E(G, n)
weclearly
have = G sothat Na
E 2(G, n).
In this way we obtain an action ofAut Fn
onE(G, n),
the orbits of which are called theTn-systems
of G.([5]
and[3]).
-When we
investigate T-systems
of aspecific
groupG,
it is found to be rather difficult to workdirectly
with the action ofAut Fn
onn).
B. H. Neumann and H. Neumann
[7]
introduced the notion of gene-rating
G-vectors which enabled them to define anequivalent
action ofAut Fn
which is moremanageable.
The details withrespect
toT3
arenow
given following
theargument
indicated in[4].
Let G be a
3-generator
group. Agenerating
G-vector oflength
3 isdefined to be an ordered
triple (gl,
g2,g3)
where(gl,
g2,g3)
= G. Theset of all
generating
G-vectors oflength
3 is denotedby V(G, 3).
Fix a set of free
generators
xl, x2, x3 forF3
and let E be the set ofepimorphisms
fromF3
to G. Define an action ofAut F3
x Aut G on Eby
where
p E E
and(~, cm)
EAut F3
x Aut G.We can
identify Aut F3
and Aut G with theircopies
inAut F3
x Aut Gand
speak
of the action ofAut F3
or Aut G on E. Weclearly
have(2.2)
PI and p2 lie in the same Aut G-orbitof
Eif
andonly if
ker pi
= ker P2 .Suppose
thatkerp
= N. Thenker p«
= Ntoo,
and so we can asso-ciate N with the Aut G-orbit of E that contains p, a E
AutG}.
Notice that for all
a E Aut F3
we haveker (p(a, 1))
=ker (cr - 1p)
= Na.Hence N~ is associated with the Aut G-orbit of E
containing p(a, 1).
Moreover, N e .E(G, 3)
if andonly
if N = ker p for somep E E.
There-fore
(2.3)
The actionof Aut F3 on.E(G, 3)
isequivalent
to its action on the Aut G-orbitsof
E.The map 7r: E -~
V(G, 3) given by
(2.4)
p77 =(Xl P,
x2 p, is abijection. Furthermore, 7r
enables us tocarry over the action
of Aut F3
x Aut G on E to an action onV(G, 3).
This is
given by
The action of
Aut F3
x Aut G onV(G, 3) given by (2.5)
isequivalent
to its action on E. Therefore the action of
Aut F3
on the Aut G-orbits ofV(G, 3)
isequivalent
to its action on the Aut G-orbits of E.Combining
this last remark with
(2.3) gives
thefollowing
fundamental result.(2.6)
The actionof Aut F3
on the Aut G-orbitsof V(G, 3)
isequivalent
to its action on
1:( G, 3).
Let us now examine in
greater
detail the actions ofAut F3
and Aut Gon
V(G, 3).
Here weagain identify Aut F3
and Aut G with theircopies
inAut F3 x
Aut G.Suppose throughout
that(gl,
g2,g3)
is atypical
element ofV(G, 3).
By (2.4)
there existsp E E
with(g1,
g2,93)
= pn =(X1P,
x2 p, The action of Aut G onV(G, 3)
is noweasily given explicitly; by (2.5)
wehave
(91,
9’2~93) (1, «)
=p7r(l, a) _
X3pa) = (9’i
a, g2 a, 93a)-
Moreover since(gl,
g2,93)
= G we have(91,
g2,93) = (gl «,
g2 a, 93«).
if andonly
if « = 1. Hence(2.7)
The actionof
Aut G onV(G, 3)
isgiven by
«:(91,
g2,93)
--
(gl
a, g2 a, 93a) for all a E
Aut G and all(gl,
g2,V(G, 3).
We next consider the action of
Aut F3
onV(G, 3).
For all eAut F3
we have
(gl,
g2 ~(~ 1) 1) _ ~-1 p~ _ (Xl’7P9 X37P)
from(2.5). Suppose
thatwhere Wl
(Xl,
X2,X3)
is a word in(Xl,
X2,X3).
Now22
where c E Aut F3
and wl, w2, w3 aregiven by (2.8).
Therefore(2.9)
The actionof Aut F3
onV(G, 3)
isgiven by
We
continue, using
thefollowing result,
a convenient reference for which is[6] Chapter
3.(2.10) Aut F3
isgenerated by
theautomor~phisms given below,
where1
i, k ~ 3,
k and unmentionedgenerators of F3
arefixed.
These are called the
elementary automorphisms
ofF3.
Their effecton
(91,
g2,g3) E V(G, 3)
is tointerchange
any twoentries,
invert anyentry
ormultiply
anyentry by
any other on the left orright.
This isseen with the aid of
(2.9).
As
Aut F3
isgenerated by elementary automorphisms,
the above re-mark has an
important
consequence,namely
(2.11 )
Two elementsof V(G, 3)
lie in the sameAut F3-orbit if
andonly if
one can betransformed
into the otherby
afinite
se-quence
of
thefollowing operations:
We say that two elements of
V(G, 3)
areequivalent
ifthey
lie in thesame
Aut F3-orbit.
An
important property
ofA7
in our context is that it hasspread
2 inthe sense of Brenner and
Wiegold ([1]
and[2]).
This means that for anypair
x, y of non-trivial elements ofA7 ,
there is a third element z such that(x, z) = (y, z)
=A7 .
The connection withT3-systems
is the follow-ing simple
butimportant
result of Evans[i].
(2.12)
Let G be any groupof spread
2. Then all redundantgenerat- ing triple
areequivalent.
A redundant
generating triple (g1,
g2,g3)
is one where one of g1, g2, g3can be omitted and the
remaining
two elements stillgenerate
thegroup. Thus our
strategy
will be to show that everygenerating triple
for
A7
isequivalent
to a redundanttriple.
3.
T3-systems
ofA7-
The 2520 elements of
A7
are classified into distincttypes
ofpermuta-
tions. We shall use the
representation
of thesepermutations
asprod-
ucts of
disjoint cycles, omitting cycles
oflength
one. If an element is aproduct
ofdisjoint cycles
oflengths
rl, r2, ..., rk where r1 > 1 the wesay it is of
type
r1, r2, ..., rk . The table belowgives
the number of ele- ments of eachtype
inA7
and also in each of the maximalsubgroups
ofA7
which areisomorphic
toP,SL(2,’l).
There are 15 maximal
subgroups
ofA7
which areisomorphic
toP,SL(2, 7).
Each element oftype
7 ofA7
is in one andonly
one of thesemaximal
subgroups.
Thisproperty
is also true for each element oftype 4, 2 of A7 .
In order to show that every
generating
G-vector(gi, g2, g3),
isequivalent
to a redundant vector wesystematically
look at allpossible
cases.
24
CASE 1. If one of the elements of the
triple
is oftype 7,
say gl thenas we remarked
above,
it is one andonly
one of theP,SL(2, 7)
containedin
A7;
call this group B.If g2 E B
then g1, g2>
c B while if theng2 )
=A7
as B is amaximal
subgroup.
The same holds for g3.As
(gl,
g2,93)
is agenerating
set forA7,
one of g2, 93 is not an ele- ment of B and willgenerate A7
with gl . Thus anygenerating triple
con-taining
an element oftype
7 isequivalent
to a redundanttriple.
CASE 2.
Suppose
that g, is oftype 5,
without loss ofgenerality, (12345)
say. If(gl, g2)
is transitive over the set{1, 2, 3, 4, 5, 6, 71
then~1~2)= Ay.
So we look at the cases when
(gl, 92)
and~gl, g3)
are non transitivebut of course, g2 and 93 between them must move 6 and 7. We need to consider two cases.
i)
gl =(12345),
g2 =( ... ) (67),
93 =( ... 6) ( ... ) (7).
Then693
= i withi#6 and i#7 and so = 7 and = i.
This means that =
( ... 67i ... ) ( ... )
and hence(91,
is transi-tive and so must be
A7.
ii)
gl =(12345),
and let g2 move 6 but not 7 and 93 move 7 but not 6.Then will move 6 and 7 and then
(gl,
isagain
transitiveand so is
A7.
Thus if the
generating triple
contains an element oftype
5 it isequiva-
lent to a redundant
triple.
The further cases, with gl, g2 and 93
taking
allpossible types,
areshown in the
following table,
which indicates thelength
of the calcula- tionrequired.
We
investigate
the cases3, 4, 5,
6 and7, using
thefollowing
consideration.
i)
There is a need fortransitivity over {1,2,3,4,5,6,7}.
ii) Any triple equivalent
to atriple
with an element oftype
7 or oftype
5 is noproblem.
iii)
Two elementsgenerating
a transitivesubgroup
ofA7 ,
in whichone is of
type
3 willgenerate A7 ([7],
p.34).
iv)
Two elementsgenerating
a transitivesubgroup
ofA7
and each oftype 4, 2
in differentPSL(2, 7) subgroups
willgenerated A7 .
The
investigation
leads to the conclusion that if thegenerating triple
contains an element oftype 4, 2
it isequivalent
to a redundanttriple.
We
provide
here aproof
of some of Case 3 to demonstrate the methods used. Thecomplete proofs
of the assertions made here involvea
great
deal ofsimple
but tedious calculation.CASE 3. Let gl, g2 and g3 be each of
type 4,2
and each in a differ- entPSL(2, 7)-subgroup
ofA7.
As anexample
we consider thefollowing
case.
If
{~1~2}
is transitiveover {1,2,3,4,5,6,7}
there is noproblem.
We also find for the
remaining
elements g2 that gl g2 org1 g2 1
orgl g 2
isof
type
7 ortype
5except
for g2 =(2537) (16)
or(1567)(23)
and their inverses.If
(gl, g3)
is transitive over{1,2,3,4,5,6,7}
there is noproblem.
We also find for the
remaining
elements g3 that g1g3 or is oftype
726
or
type
5expect
for g3 =(3657) (12)
or(3567)(14)
or(3576)(24)
andtheir
inverses.
For these elements or their
inverses,
g2 g3 org2 g3 1 is
oftype
7 ortype
5.We see that for the selected g1 and the
subgroups concerned,
all thetriples
areequivalent
to redundanttriples.
This is found to be truewhichever of the 14
maximal subgroups
are chosen to contain elements g2 and g3. Thus anygenerating triple containing
three elements oftype 4, 2
each in a differentPSL(2, 7)
maximalsubgroup
isequivalent
to aredundant
triple.
We now consider the case with gl, g2 each of
type 4, 2
and each in adifferent
PsL(2, 7)-subgroup
ofA7
with g3 any element oftype
3. Weconsider the
following
case.g3 = any element of
type
3 inA7 ,
When we consider the
products
of gl g2 and gl g3 we findproblems only
occur when g2 =(2537) (16)
or(1567)(23)
and 93 =(124)
or(345)
or(346)
or(347)
or(456)
or(457).
For these elements we find that either an
equivalent triple
can beobtained with one
element,
aproduct
of gl, g2 and which is oftype
7or of
type 5,
or thetriple
is not agenerating triple.
We
again
see that for the selected gl and thesubgroups concerned,
all the
triples
areequivalent
to redundanttriples.
This is found to betrue whichever of the maximal
subgroups
are chosen to contain ele- ment g2. Thus anygenerating triple containing
two elements oftype 4, 2
each in a differentP,SL(2, 7)
maximalsubgroup
with the third ele- ment oftype
3 isequivalent
to a redundanttriple.
Case
3,
whencompleted,
and then cases4, 5,
6 and 7 all lead to thesame conclusion that the
generating triples
concerned are allequiva-
lent to a redundant
triple.
The information obtained from cases 1 to 7 is used in the other cases
in the order as shown in the table and with each case
leading
to a redun-dant
triple.
The final conclusion is that all the
generating
G-vectors areequiva-
lent to redundant vectors and
consequently A7
hasonly
oneT3-sys-
tem.
A further result of Evans
[4]
can now be used tocomplete
theproof.
(3.1)
Let G be a non-abelianfinite simple
group withd(G)
= k.Sup-
pose that G
= ~ g1,
g2,... , gk ~
wheregk
= 1. ThenAutFk+1 1 acts
asa
symmetric
oratternating
group on at least oneof its
orbits on+
1).
The
alternating
groupA7
may begenerated by ~ gl , g2 ~
where gl is anelement of
type
7 and g2 is an element oftype
2, 2 which is not in theP,SL(2, 7)
maximalsub-group containing
gl . Forexample
we haveA7
==
((1234567), (12) (45)).
We conclude that the action ofAut F3
on theA7 defining subgroups
isalternating
orsymmetric.
REFERENCES
[1] J. L. BRENNER - J. WIEGOLD,
Two-generator
groups I,Michigan
Math. J., 22 (1975), pp. 53- 64.[2] J. L. BRENNER - J. WIEGOLD,
Two-generator
groups II, Bull. Austral. Math.Soc., 22 (1980), pp. 113-124.
[3] M. J. DUNWOODY, On T-systems
of
groups, J. Austral. Math. Soc., 3 (1963),pp. 172-179.
[4] M. J. EVANS, Problems
concerning generating
setsfor
groups, Ph.D. Thesis,University
of Wales (1985).[5] R. GILMAN, Finite
quotients of
theautomorphism
groupof
afree
group, Canad. J. Math., 29, no. 3 (1977), pp. 541-551.[6] W. MAGNUS - A. KARRASS - D. SOLITAR, Combinatorial
Group Theory,
In- terscience, New York (1966).[7] B. H. NEUMANN - H. NEUMANN, Zwei Klassen charakteristischer Unter- gruppen und ihre
Faktorgruppen,
Math. Nachr., 4 (1951), pp. 106-125.[8] H. WIELANDT, Finite
permutation
groups, Lectures,University
of Tübin-gen
(1954/55); English
trans., Academic Press, New York (1964).Manoscritto pervenuto in redazione il 19