A NNALES DE LA FACULTÉ DES SCIENCES DE T OULOUSE
R OGER C. B AKER
G LYN H ARMAN
Sparsely totient numbers
Annales de la faculté des sciences de Toulouse 6
esérie, tome 5, n
o2 (1996), p. 183-190
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- 183 -
Sparsely totient numbers(*)
ROGER C.
BAKER(1)
and GLYNHARMAN(2)
Annales de la Faculté des Sciences de Toulouse Vol. V, n° 2, 1996
Soit Pl (n) > P2 (n) ... la suite décroissante des diviseurs premiers de l’entier n. Nous montrons le résultat suivant : si
(m
> n>
~(n)~
alors Pl (n) of C est une constanteabsolue. Nous utilisons le crible de Harman et les estimations de Fouvry
et Iwaniec pour les sommes trigonometriques.
ABSTRACT. - Let P~ (n) be the j-th largest prime dividing n. We
show the following result: if
(m
> ~ =~ ~ ( m ) >~ ( n ) ~ ,
then Pl ( n )C(log n)37/20,
where C is a an absolute constant. We use Harman’s sieve and the estimates of Fouvry and Iwaniec for trigonometric sums.1. Introduction A
positive integer
n is said to besparsely
totient iffor all m > n. This definition was introduced
by
Masser and Shiu[9],
whoproved
severalinteresting properties
ofsparsely
totient numbers.Subsequently
Harman[6] sharpened
some results from[9].
Inparticular,
heshowed that
Pj(n),
thej-th largest prime dividing n,
satisfies( *) ~ Reçu le 7 mars 1994
(1) Department of Mathematics, Brigham Young University, Provo, Utah 84602, U.S.A.
Reseach supported in part by grants from the National Science Foundation and the Ambrose Monell Foundation
(2) School of Mathematics, University of Wales, Senghennydd Road, Cardiff, CF2 4 AG, United Kingdom
for a
given j >
2 and £ > 0. Here wesuppose n > no ( j, ~)
.For j
=1,
thecorresponding
bound is of weaker order[6,
theorem1] :
As
regards Qj(n),
thej-th
smallestprime dividing
n, Harman showed in[6]
thatfor n > n1
(~, ~).
In the present paper we
sharpen
the bound{ 1.2) .
.THEOREM . - Let n be a
sparsely
totient number. Thenwhere C is an absolute constant.
The
key
to theimprovement
is work ofFouvry
and Iwaniec[4]
onexponential
sumsvhere = . The sums we need here are of the
particular
formIt is well-known that there are devices for
estimating
this sum moreefficiently
than(1.3) (e.g.
Iwaniec and Laborde[7],
Baker[I], Fouvry
andIwaniec
[4],
Wu[10],
Liu[8]
and Baker and Harman[2]).
These devices would make no difference to the final result if weemployed
themhere;
seethe remark
following
theproof
of Lemma 3.We shall deduce the theorem from the
following proposition.
PROPOSITION . - For all x, v with v
sufficiently large
andthere are
solutions in
primes
p toThe
proposition
isproved by
the sieve methoddeveloped by
Harman[5]
and
Baker,
Harman and Rivat[3].
We are able to use the same numericalwork as in
[3] ;
this saves agreat
deal of space. Sums(1.4) arise,
as onewould expect, in
bounding
the remainder terms of the sieve.The deduction of the Theorem from the
Proposition
follows[6] closely,
but we
give
it here forcompleteness. Suppose
that n is asparsely
totientnumber and
,
so that n is
large. By (1.2),
we know thatLet pi =
Pl (n)
and write m =n/p1.
Weapply
theProposition
with x = pl,v =
log n.
It follows that there aresolutions to
(1.5).
From(1.1),
there are at most threeprimes
between 2vand 3v which divide n. We deduce that
(1.5)
has a solution with pf
n. LetEvidently
mrp > n. We now use(1.5)
to show that~(~).
Wehave . , , ’" - ,
Now
from
(1.5).
HenceCombining (1.6)
and(1.7),
Since p
islarge,
we havewhich is absurd. The Theorem is
proved.
02.
Exp onential
sumsLet £ be a
sufficiently
smallpositive
number andlet ~
=~2.
Constantsimplied by
" «",
" ~> " and "OE( ~ )
" willdepend
at most on 6;. Constantsimplied by
"O( . )
" will be absolute. We use the abbreviation " m - M "for
We write a =
3/20.
LEMMA 1.2014
M~, lV~
becomplex
numbersof
modulus~
1.Suppose
thatThen
Proof.
- This follows from Lemma 9 of~1~,
with Hva+5’~
andQ
=using
the exponentpair (1/2, 1/2).
LEMMA 2. The conclusion
of
Lemma 1 holdsif
thehypothesis
isreplaced by
Proof.
-Using
thetechnique
in[1,
lemma15],
it suffices to show thatfor
H ?Ja+5’~,
whereas and bt
havemodulus ~
1. We obtain this boundby
anappeal
to Lemma 1 for[3] (a
variant of a result in[4]), taking (Ml, M2, M)
to be either(H, M, N)
or(H, N, ~).
.LEMMA 3.2014 Let
M v3i3~-~.
We havefor
anycomplex
numbers asof
modulus 1.Proof.
-Suppose
first thatThen
(2.5)
follows from Lemma 2 of[3],
withX, K replaced by v, M,
andwith H
va+5’~.
Now suppose thatThen Lemma 3 follows from Lemma 2.
We have not been able to
improve
the boundv3-3a-~ in
Lemma 3by
taking advantage
of the factthat bt
= 1 in(2.5), together
with thespecial
features of sums
(1.4)
mentioned in the section 1. This isperhaps surprising.
3. Proof of the
proposition
We write 6 =
x/(16 v2).
Let B be the set ofintegers
in(2v, 3v),
and letA be the set of k in B for which
For [ = A or
B,
we writeThus the number of
primes
in A isS’~A, (3v)1~2~ . We shall prove that
which establishes the
Proposition.
LEMMA 4. Let as, s
2M,
andbt,
t ~N,
,by complex
numbers with|bt|
« °For M
v1-3a-~,
we haveFor M in any
of
the intervalswe have
Proof.
- We prove{3 .1 ) by combining
theargument
of Lemma 2 of~5~
with Lemma 3. The
proof
of(3.4)
issimilar, using
Lemma 1 or Lemma 2in
place
of Lemma 3.We may now follow the
analysis
of[3]
veryclosely
indeed. Inplace
ofLemmas 6 and 7 of
[3]
we have Lemma4, with v,
aplaying
the roles of X and 1 - y. We summarize the resultsobtained, leaving
the details ofproof
to the reader. Let
LEMMA 5. - For
M
we haveHere 03BB =
30 ~, |am ( «
03C5~ and am = 0 unless(m,
= 1.LEMMA 6. - Let u > 1 be
given
and suppose that D C~ 1,
... ,u~
andM lies in one
of
the intervals~3.3~.
ThenHere * indicates that pi ... , pu
satisfy
together
with no more than~-1 further
conditions which theform
LEMMA 7. _ Let M We have
where v =
100 ~,
0 am « v’~ and am = 0 unless(m, P(vl/10-2~~~ = 1.
- 190 -
We may now carry out the
decomposition
ofS~,A, (3v)1~2~ in exactly
the
same fashion as
[3,
sect.5]
with v in the role of X. A fewchanges by
afactor 03C5~ in the
endpoints
of intervals will occur. These will in turn alter the coefficients in theinequalities defining
theregions
ofintegration by O{~).
this
clearly
does not alter the finalresult,
which is the lower bound(3.1).
This
completes
theproof
of theProposition.
Acknowledgments
The first named author would like to thank the
University
of Wales atCardiff,
where part of this work wasdone,
and the Institute for AdvancedStudy
atPrinceton,
where the final version wasprepared.
References
[1] BAKER (R. C.) . 2014 The greatest prime factor of the integers in an interval, Acta Arithmetica 47 (1986), pp. 193-231.
[2] BAKER (R. C.) and HARMAN .2014 Numbers with a large prime factor, Acta Arith.
73 (1995), pp. 119-145.
[3]
BAKER (R. C.), HARMAN and RIVAT (J.) .2014 Primes of the form [nc], J. ofNumber Theory, 50
(1995),
pp. 261-277.[4] FOUVRY (E.) and IWANIEC (H.) . 2014 Exponential sums with monomials, J. Number Theory 33 (1989), pp. 311-333.
[5]
HARMAN (G.) .2014 On the distribution of 03B1p modulo one, J. London Math. Soc.27 (1983), pp. 9-18.
[6] HARMAN (G.) . 2014 On sparsely totient numbers, Glasgow Math. J. 33 (1991),
pp. 349-358.
[7] IWANIEC (H.) and LABORDE (M.) .2014 P2 in short intervals, Ann. Inst. Fourier, Grenoble, 31 (1981), pp. 37-56.
[8] LIU (H.-Q.) .2014 The greatest prime factor of the integers in an interval, Acta Arith., 65 (1993), pp. 301-328.
[9] MASSER (D. W.) and SHIU (P.) . 2014 On sparsely totient numbers, Pacific J. Math.
121 (1986), pp. 407-426.
[10] WU (J.) .2014 P2 dans les petits intervalles, Séminaire de Théorie des Nombres de Paris (1989-90), Birkhaüser.