C OMPOSITIO M ATHEMATICA
J. H. E VERTSE
K. G YÖRY
On the numbers of solutions of weighted unit equations
Compositio Mathematica, tome 66, n
o3 (1988), p. 329-354
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329
On the numbers of solutions of weighted unit equations
J.H.
EVERTSE1 &
K.GYÖRY2
© Kluwer Academic Publishers, Dordrecht - Printed in the Netherlands
1 University of Leiden, Department of Mathematics, P.O. Box 9512, 2300 RA Leiden, The Netherland.s; ’Kossuth Lajos University, Mathematical Institute, 4010 Debrecen, Hungary
Received 6 October 1987; accepted in revised form 8 January 1988
§0.
IntroductionLet K be a
finitely generated
extension fieldof Q,
let r be afinitely generated subgroup
of themultiplicative
group K* of non-zero elements ofK,
and let0(j, ... , a,, E K*.
Many problems
of numbertheory
lead toequations
of thetypes
or more
generally
where,
inparticular,
0393 is the unit group of asubring
of K which isfinitely generated
over Z. Hence the aboveequations
are called unitequations
andweighted
unitequations, respectively.
For ageneral
survey on theseequations
and their
applications
we refer toEvertse, Gyôry,
Stewart andTijdeman [7].
For n =
2,
several results are known about the number of solutionsof ( 1 ).
In
1985,
Evertse andGyôry [6]
derived in case n - 2 anexplicit
upper bound for the number of solutions of(1)
which isindependent
of a, and a2. Twotuples (03B11,
... ,1 y,), (03B21,
... ,03B2n)
with non-zero entries in K* are calledF-equivalent
if there are El’ ... , e, E F such that03B2l
= 03B1l03B5l for i =1,
..., n.Obviously,
the number of solutionsof ( 1 )
does notchange
when(03B11,
... ,03B1n)
is
replaced by
ar-equivalent tuple.
In1987, Evertse, Gyôry,
Stewart andTijdeman [8] proved
that in case n =2 ( 1 )
has at most two solutions for all butfinitely
manyr-equivalence
classes ofpairs (03B11, e(2)
e(K* )2.
In the present paper we shall
partly generalize
the results mentioned above to the case n > 2. We shall prove(cf.
Theorem 1 in§1)
that the number of solutions of(1)
with03A3 03B1Jxj ~
0 for each non-empty subset Jof {1,
... ,n) (2)
/e7
can be bounded above
by
a number(not explicitly computable by
ourmethod)
which does notdepend
on a, , ... , 1 ot,. Thisprovides
a refinementof a theorem of Evertse
[2]
and van der Poorten and Schlickewei[ 11 ] which
says that
(1)
hasonly finitely
many solutions withproperty (2). By using
Theorem 1 we shall also extend our result on
equation (1)
tosystems
ofweighted
unitequations (cf.
Theorem2).
Our Theorem 1 will be deduced in§4
from thefollowing generalization (cf.
Theorem 4 in§1)
of the result ofEvertse, Gyôry,
Stewart andTijdeman [8]
mentioned above:apart
from thetuples (a, ,
... ,Lln) belonging
to at mostfinitely
manyr-equivalence
classesdepending only
on n andr,
the set of solutions of(1)
is contained in the union of fewer than2(n+1)!
proper linearsubspaces
of Kn. We shall derive this bound in§3, by combining
ageneralization
of the methodapplied
in[8]
forthe case n = 2 with the result
of [2]
and[11] quoted
above.Finally,
we shallgive
anapplication
of Theorem 4 to the case n = 3(cf.
Theorem 5 in§1).
We shall consider
equation (1)
also over function fields. Let K be afunction field of transcendence
degree
1 over analgebraically
closed field Ik of characteristic0,
let r be the group of S-units in K where S is a finite set of valuationson K,
and let a, , ... , an be non-zero elements of K. A solution(x, ,
... ,xn) of (1)
is calleddegenerate if 03B11x1,
..., 03B1nxnbelong
to Ik. Asan
analogue
of Theorem4,
we shall derive anexplicit
upper bound for the minimal number of proper linearsubspaces
of Kn in the union of which the setof non-degenerate
solutionsof ( 1 ) is
contained(cf.
Theorem 6 in§2).
Thisbound is also
independent of a, , ... ,
OCn - Inderiving
our bound we shall usean effective upper bound of Brownawell and Masser
[1] for
theheights
ofsolutions of
(1)
and a"higher
dimensional gapprinciple".
Applications
of our results aregiven
in the recent papers[13]
and[5].
§1. Weighted
unitéquations
overfinitely generated
fieldsLet K be a
finitely generated
extension field ofQ, n ~
1 aninteger,
a, , ... , an elements of
K*,
and r afinitely generated multiplicative
sub-group of K*. A solution
(x, , ... , xn)
of theweighted
unitequation
is called
non-degenerate
ifL 03B1JxJ ~
0 for each non-empty subset Jof {1,
... ,n}
/e7
and
degenerate
otherwise. It is clear that if F is infinite and if(1)
has adegenerate
solution then(1)
hasinfinitely
manydegenerate
solutions. Fornon-degenerate
solutions we have thefollowing
result.THEOREM 1. The number
of non-degenerate
solutionsof (1)
is at mostCj = C, (n, F),
whereCI
is a nuinberdepending only
on n and r.This is a refinement of a result of Evertse
[2]
and van der Poorten andSchlickewei
[11] (cf.
Lemma 1 in§3
and the Remark made after thelemma)
on the finiteness of the number of
non-degenerate
solutions of(1).
For n =
1,
Theorem 1 is trivial. For n =2,
the solutions of(1)
are allnon-degenerate.
In the case n = 2 anexplicit expression
forC,
has beenevaluated
by
Evertse andGyôry [6].
As we mentionedabove,
for n > 2 we are not able to makeexplicit
the boundC, occurring
in Theorem 1.Let k ~
1 be aninteger.
As ageneralization of equation (1),
consider the systemof’ weighted
unitequations
where 03B1lJ E K for i =
1,
... , kand j = 0,
... , n, and at least one of thea,o is different from zero. We shall say that a solution.
(xl,
...,x,,)
of(3)
isdegenerate
if03A3J~J
03B1lJxJ = 0 for i =1,
... , k and for a propernon-empty
subset Jof {1,
...,nl,
andnon-degenerate
otherwise. In§4
we shall deduce from Theorem 1 thefollowing
THEOREM 2. The number
of non-degenerate
solutionsof’ (3)
is at mostC2 == C2(n, F),
whereC2
is a numberdepending only
on n and r.For k = 1 Theorem 2 reduces to Theorem
1,
hence Theorem 2 and Theorem 1 areequivalent.
In the remainder of this section it will be assumed that n ~ 2. In
§4
weshall prove in an
elementary
way that Theorem 1 isequivalent
also to thefollowing
theorem.THEOREM 3. All solutions
of (1)
are contained in the unionof
at mostC3 - C3(n, r) (n - 1 )-dimensional linear subspaces of K’,
whereC3
is anumber
depending only
on and F.The
tuples (a, , ... , 1 Y,), (03B21,
... ,03B2n)
in(K*)"
are calledr-equivalent
if03B2l
= 03B1l03B5l for some e, E F for i =1, ... ,
n. It is obvious that the number of(non-degenerate)
solutionsof ( 1 )
as well as the minimal numberof (n - 1 )-
dimensionalsubspaces
of K’tcontaining
all the solutions of(1)
remainunchanged
if(a, , ... , 03B1n)
isreplaced by
ar-equivalent tuple.
The mainresult of this section is as follows.
THEOREM 4. For all but
finitely
manyF-equivalence
classesof tuples (03B11,
... ,03B1n)
E(K*)n, the
setof
solutionsof (1)
is contained in the unionof fewer
than 2(n+1)!(n - 1 )-dimensional linear subspaces of
Kn.As we shall see in
§4,
Theorem 3easily
follows from Theorem 4 and Lemma 1of §3.
It is
possible
togeneralize
Theorems 1 to 4 to the case that K is any subfield of C and r is anysubgroup
of finite rank of C*. For theproofs
itsufHces to
replace
Lemma 1 of§3
on unitequations
as we use itby
a moregeneral
version due to Laurent[9] (cf.
Remark 2 in§3).
For n -
2,
Theorem 4implies
that apart fromfinitely
manyT-equivalence
classes of
pairs (03B11, OC2)
E(K*)2, the equation
has fewer than 26 solutions. We note that
Evertse, Gyôry,
Stewart andTijdeman [8] proved
a similar result with the upper bound 2 which isalready
best
possible.
For n =
3,
a result of similartype
can be deduced from Theorem 4. To state this result we need some further notation. Let{z1,
... ,Z, 1
be atranscendence basis of K over Q. Then K is a finite extension
of degree d,
say, of the fieldK0 = Q(z1, ..., zq).
Thepolynomial ring O - Z[z1, z,]
is a
unique
factorization domain in which theprime
elements are the rationalprimes
and theprimitive
irreducible non-constantpolynomials
in Cc. Toevery
prime
element of (Çcorresponds
an(additive) valuation v03C0
onKo
withthe
property
thatv03C0(03C0)
= 1 andvn(alb) ==
0 if a, b are elements of O not divisibleby
n. Thus we have a set ofpairwise inequivalent
valuations onKo
with value group Z. Each of these valuations can be extended in at most d différent ways to K. Let mK denote the set of these
extensions,
and let S bea finite subset of mK of
cardinality
s. One can show thatis a
finitely generated multiplicative subgroup
of K*.Moreover,
everyfinitely generated multiplicative subgroup
of K* can be embedded in somesubgroup TS
of K*.THEOREM 5. For all
but, finitely
manyis-equivalence
classesofa.
=(LlI’
Ll2,03B13)
E(K*)3,
theequation
has
fe»’er
than 226 x73d+2B non-degenerate
solutions.Theorem 4
implies
that apart fromfinitely
manyFs-equivalence
classes ofa E
(K*)3,
the solutions of(6)
are contained in the union of at most24!
proper linear
subspaces
of K3.However,
thenon-degenerate
solutions(x, ,
X2’x3)
contained in such asubspace satisfy
aweighted
unitequation
ofthe form
for some distinct
il, i2 ~ {1, 2, 3}
and some03B2l1, y2 E
K*. Now Theorem 1 ofEvertse and
Gyôry [6] implies
that the number of solutions of(7)
is at most4 x
73d+2B
and hence Theorem 5 follows.We note that in view of an
example given by Evertse, Gyôry,
Stewart andTijdeman (cf. [8], §§0,5)
the boundoccurring
in Theorem 5 cannot bereplaced by
a bound which ispolynomial
in terms of s.The above results
suggest
thefollowing
CONJECTURE. It is
possible
togive
anexplicit expression C(n),
in termsof
nonly,
such thatfor
every a, , ... , 03B1n EK*,
the numberof non-degenerate
solutions
of
theequation
is at most
C(n)"’.
§2. Weighted
unitequations
over function fieldsLet K be a function field of transcendence
degree
1 withalgebraically
closedconstant field Ik of characteristic 0. Thus K is a finite extension of
|k(t),
wheret is a transcendental element of K over Ik. The field K can be endowed with
a set
MK
of additive valuations with valuegroup Z
for whichholds. Let S be a finite subset of
MK .
An element a of K is called an S-unitif v(a) -
0 for all v inMKBS.
The S-units form amultiplicative
group whichis denoted
by Us.
The groupUs
contains Ik* as asubgroup
andUs/lk*
isfinitely generated.
We shall prove thefollowing analogue
of Theorem 4 for the function field case. Asusual,
e denotes the number 2.71828 ....THEOREM 6. Let K,
Ik,
S be as above. Let g be the genusof Kllk,
s thecardinality of S,
and n ~ 2 aninteger.
Thenfor
every 03B11 , ..., 1 Y, EK*,
theset
of
solutionsof
is contained in the union
of
at most(n - 1 )-dimensional l inear subspaces of ’
Kn .Note that when oc,, ... , an are not all
S-units,
the condition that 03B11x1, ... , anxn do not allbelong
to Ik holds for all S-units x1 , ... , x,,. If 03B11, ... , an are allS-units,
then the solutionsof (9)
with 03B11x1, ... , an xn E Ikare not contained in the union of
finitely
many(n - 1 )-dimensional
linearsubspaces
of Kn.For n =
2,
Theorem 6gives
the upper boundfor the number of solutions of
(9).
We note that in case n = 2 Evertse[4]
established the upper bound 2 x 72s for the number of
solutions,
a boundwhich is better and
independent
of g.Theorem 6 will be
proved
in§5.
Theproof
will involve thefollowing
results: a
"gap principle" by
which one can estimate the minimal number of(n - 1 )-dimensional subspaces
of Kncontaining
all solutions of(9)
withbounded
heights;
and anexplicit
upperbound,
due to Brownawell and Masser[1],
for theheights
of thenon-degenerate
solutions of(9). (We
mention
that, independently,
J.F. Voloch[15],
Thm.4)
derived the sameupper bound for the
heights
of the solutions je,, ... , xn of(9),
butsubject
to the
slightly stronger
condition that al xl , ..., 03B1nxn arelinearly independent
over Ik. The bound obtained in
[1] and [ 15] sharpens
an earlierinequality
ofMason
[10].)
We remark thatby using
the method ofproof
of Theorem 4 instead of the gapprinciple just
mentioned it ispossible
toget
a bound similar to that of Theorem6,
but with a much worsedependence
on thenumber of unknowns n.
REMARK. The
higher
dimensional gapprinciple
forweighted
S-unitequations
over function fields has an
analogue
for number fields(cf. §5,
Lemma6)
which
gives
an upper bound for the number ofsubspaces containing
thesolutions of
(1)
with smallheight
if F is thegroup Us
of S-units in somealgebraic
number field K.By combining
this gapprinciple
with a mean todeal with the
large solutions,
such as aquantitative
version of Schlickewei’sp-adic subspace
theorem over numberfields,
it would bepossible
to obtainan
explicit
upperbound, independent
of thecoefficients,
for the number ofsubspaces containing
all solutions(or
for the number ofnon-degenerate solutions)
of(1)
with 0393 =Us.
Just before this paper went to press, at the Conference onDiophantine Approximations
in Oberwolfach(14-18 March, 1988),
Schlickewei announced that he succeeded inmaking
hissubspace
theoremquantitative.
He used thistogether
with a gapprinciple
that he obtained
independently
of us, to show that(1)
has at most(C(n, d)s)s6 non-degenerate solutions,
where r= Us
asabove, s
is thecardinality
ofS,
d -[K:Q]
andC(n, d )
is someexplicit
function of n and d.§3.
Proof of Theorem 4We shall use the same notation as in Section 1. Theorem 4 will be
proved by
an extension to the case n > 2 of the method used in[8]
for the casen = 2. The basic idea of our
proof
is as follows.Any n
+ 1 solutionsxl =
(x,, ,
...,Xln),
i =0,
... , n, of(1) satisfy
theequation
We shall show that if the set of solutions of
(1)
is not contained in the union of fewer than 2(n+1)! propersubspaces
ofK",
then there are asubsum 1 =
10
+03A31Xn-1
+ ··· +LnXnn
of thepolynomial 0394,
solutionsx0, ... , Xn -
of (1) with Î, = 03A3k(x0, ... , xn-1) ~
0(k = 0,
...,n),
and n
linearly independent
solutions yo, ... , yn-1of(l)
such that1r.(yJ == 0,
l03A3’(yl) ~
0 for each proper non-empty subsum E of 03A3 for i =0,
..., n -1,
where
IL
=i,
+1Xn1
+ ··· +nXnn
andl03A3’
is definedsimilarly.
Butl03A3(yl)
is the sum of at most(n
+1)!
elements fromr, hence, applying
Lemma 1 below with i =
0,..., n -
1 one can prove that theyij/y0j
(i
=0,..., n - 1 ; j
=1,..., n) belong
to a finite subset of K*depend- ing only on n and 0393. Since (yi1/y01,..., 1 Y,nIYOn)
for i =0,
..., n - 1 arelinearly independent and, by (1),
it will follow that the Y,yo,
( j
=1, ... , n) belong
to a finite subset of K*which
depends only
on n and r. This will prove the assertion of Theorem 4.We now turn to the detailed
proof
of Theorem 4. We shall need two lemmas.LEMMA 1. Let n ~ 1 be an
integer.
Theequation
has
only finitely
manynon-degenerate
solutions.REMARK 1. In case that r is contained in an
algebraic
number field(algebraic
number field
case),
this lemma has beenproved independently by
Evertse[2]
and van der Poorten and Schlickewei
[11].
In their paper, van der Poorten and Schlickewei gave arough
sketch of aspecialization
argumentby
whichthis lemma in the
general
case can be deduced from Lemma 1 in thealgebraic
number field case.
Up
to now, nocomplete exposition
of thisspecialization argument
has beenpublished.
For the sake ofcompleteness only,
we shallshow in the
Appendix
how to derive Lemma 1 in thegeneral
case fromLemma 1 in the
algebraic
number field case.However,
ourarguments
will be différent from those of van der Poorten and Schlickewei. Instead of aspecialization argument
we shall use our Theorem 6 on S-unitequations
over function fields.
REMARK 2.
Using
the above version of Lemma1,
Laurent[9] generalized
Lemma 1 to the case that K is any subfield of C and r is any
subgroup
offinite rank of C *.
To state Lemma 2 we need some further notation. Next
let n ~
2 be aninteger.
For every ce =(OC’
... ,an)
E(K*)n,
denoteby l03B1
the linearpolynomial a, X,
+ ··· +03B1nXn -
1 andby Hrx
the(n - 1 )-dimensional
linear
subvariety (i.e.,
ahyperplane
notnecessarily containing 0)
of K"which consists
of y e K"
withla ( y) -
0. For every subset Yof H03B1
we defineM(Y, Ha)
as the smallest numberof hyperspaces (i.e. (n - 1)-dimensional
linear
subspaces)
ofKn,
the union of which contains Y.If k ~
1 is aninteger
andwith a
finite,
non-empty subset I ofk-tuples
ofnon-negative integers,
thenby
a subsum of P we mean apolynomial
where J is a
non-empty
subset of I.LEMMA 2. Let a E
(K*)n
and let Y be a subsetof Ha
withM(Y, H,,)
~2(n+1)!. Then
for
k =1,
... , n thefollowing
holds: there are xo -(x01,..., x0n),...,
xk-1 =(xk-1,1,..., Xk-1,n)
E g such tha t all subsumsof
all(k
xk)
subdeterminantsof
the matrixare
non-zero for Xol -
X01, ...,Xk -Ln
= Xk -Ln’Proof of
Lemma 2. We shallproceed by
induction on k. For k = 1 thelemma is obvious.
Suppose
that the lemma holds for k = p - 1 wherep ~
1(induction hypothesis).
We shall prove it for k = p.For
convenience,
we shall assumethroughout
this section thatXoo - X10 = ··· = Xno - 1
and x00 = ··· =xn0 = 1. By
the inductionhypo-
thesis there are xo =
(xo, , ... , x0n),
... , xp-2 =(Xp-2,1,..., xp-2,n) ~ Y such that all subsums of all ( p - 1)
x( p - 1)
subdeterminants ofAp-1,n
are non-zero at xo, , ... , xp-2,n. Let B be a subsum of some p x p sub- determinant of
Apn,
say. Then B can be written as
B,, Xp-
1,1l + ... +BtpXp-1,lp,
where eachB,, is either identically 0 or, up to sign, a subsum of some ( p - 1)
x( p - 1)
subdeterminant ofAp-1,n.
To the subsum B we associate the linearpolynomial
where Bl,
is obtainedfrom B,, by replacing Xoo,..., Xp-2,n by
x00,..., Xp-2,fprespectively.
At least one of thepolynomials B,,
is notidentically 0,
whenceis,
up tosign,
a subsum of some( p - 1) (p - 1)
subdeterminant ofAp-1,n. Therefore,
none of thepolynomials lB is identically
0.Moreover,
eachpolynomial 1,
islinearly independent
ofl03B1,
since each1,
has at most p~ n
non-zero terms,
whereas l03B1
has n + 1 non-zero terms. There are at most(n+1p)
p x p subdeterminants ofAp"P
and each subdeteminant has less than 2p! subsums. Thisimplies
that there are at most(n+1p)
2P’polynomials IB’
But(n+1p 1)2P’ 2(n+1)’, hence, by
theassumption M (!/, H03B1) ~ 2(n+1)!,
there must be an xp-1 in Y with
1, (xp
~ 0 for each subsum B of each p x p subdeterminant ofAp,n.
Thisimplies at
once thatB(xo, ... , xp-1) ~
0for each subsum B of each p x p subdeterminant of
Ap,n.
DProqf of
Theorem 4. We have to prove thatM(F"
nH03B1, H03B1)
2(n+1)’ forall but
finitely
manyT-equivalence
classes of 03B1 E(K*)n. Suppose
thatM (r"
nH03B1, H03B1) ~
2(n+1)’ for some a E(K*)".
We shall show that the set ofoc
having
thisproperty
is contained in the union of at mostfinitely
manyr-equivalence
classes.Each subsum E of the determinant
can be written as
03A30Xn0
+LI Xnl
+ ··· +03A3nXnn where Y-,
is eitheridentically
0 or, up tosign,
a subsum of some n x n subdeterminant ofAn,n
for i =0,
... , n. L iscalled full
if none of thepolynomials Lo,
... ,Ln
is
identically
0.By
Lemma 2 there are xo -(xo, ,
... ,x0n),
... , xn-1 =(Xn-1,1, ... , xn-1,n)
in rn nH«
such that each subsum of each n x n sub- determinant ofAn,n
is different from zero in xo 1 ..., xn-I,n’ To each subsum E of 0394 we associate the linearpolynomial 1,
=0X0
+1X1
+ - - - +nXn
where
i,
is obtained from03A3l by substituting
xoo, ... , xn-,,n forXoo,
... ,Xn-1,n, respectively. By our choice of x0,...,
Xn -1’ none of thepolynomials
IL
isidentically
0.Further,
for every y in 0393n nHa
there is a subsum Esuch that
for each subsum with
This follows from the fact that
A(xo,
... , Xn-1,y) =
0 for each y in 0393n ~H(1.’
Elements y of F" nHa
withproperty (10)
are said to be E-associated.
The set of subsums of A is divided into three classes:
(I)
the subsums which are notfull;
(II)
the full subsums Y- for which the set of E-associated y in hn nH«
iscontained in a
single hyperspace
ofK",
(III)
the full subsums Y- for which rn~ H03B1
contains nlinearly independent
L-associated elements yo , ... , yn-1.
if Y- is not a full subsum of
A,
thenobviously 1,
islinearly independent
of1(1.’ Further, A
has fewer than 2(n+1)’ subsums. Hence the set of elements y in F"~ H03B1
which are 03A3-associated for some £ in class 1 or II is contained in the union of fewer than 2(n+1)!hyperspaces
of Kn.Therefore,
class III isnon-empty.
We shall show that thisimplies
that 03B1 mustbelong
to one of atmost
finitely
manyr-equivalence
classesdepending
on n and ronly.
Let 03A3 be a subsum of A in class III. Then Y- can be written as
where each
Pk
is amonomial, multiplied by
1 or -1,
and each indexset J,
is
non-empty.
Consider theequation
for each
tuple
of subsetsrespectively,
for whichat least one
L,
is non-empty and at least oneL,
is different fromJ,
The number of terms in
equation (11)
is at most(n
+1)!. Hence, by
Lemma
1,
eachquotient Z,k 1 Z/I
mustbelong
to a finite setf,
c K* whichdepends only
on n and r. Let y =(y1,
...,yn)
be a E-associated element of rn nH03B1,
and let yo - 1. Then zik =Pk(x0,
... ,xn-1)yl (i
=0,
..., n, k EJi )
is a solution of(11).
Hence for eachi, k, j, 1,
But this
implies
that for any two E-associated y =(y1,
...,Yn)’ y’ = ( y,,
... ,yn )
in I-’n nHa
and alli, j
in{0,
... ,1 nl
we havewhere
yo -
1and f,
is a finite subset ofK*, depending only
on nand
r,
which is obtainedby taking
allquotients
of the elementsof A.
Letnow yo, ... , Yn-, be n
linearly independent,
E-associated elements of rn nH,,,.
Theseexist,
sinceby assumption, Y- belongs
to class III. Letyi =
(yi1, ... , Yin)
for i =0,
..., n -1,
andput
and
Then 03B2 = (03B21, ... , 03B2n) is 0393-equivalent to 03B1. Further, w0, w1,
... , wn-1 arelinearly independent
inKn, and,
in viewof y0 , ... , yn-1 ~ H03B1,
By
Cramer’srule, 03B21, ... , 03B2n
areuniquely
determinedby
the wij.But, by (12),
each Wijbelongs
toY2.
Hence thetuple 03B2 = (03B21, ... , 03B2n) belongs
to a finite subset of
(K*)n
whichdepends only
on n and F. Since ce isr-equivalent to fi,
thisimplies
that abelongs
to one of at mostfinitely
manyr-equivalence
classesdepending only
on n and r. Thiscompletes
theproof
of Theorem 4. 0
§4. Equivalence
of Theorem 1 and Theorem 3. Proofs of Theorems 3 and 2 In this section we shall first show that Theorems 1 and 3 areequivalent.
Then we shall deduce Theorem 3 from Theorem
4,
and Theorem 2 from Theorem 1.We shall use the notation introduced in
§1.
Inparticular,
K is afinitely generated
extension field ofQ,
and r is afinitely generated multiplicative subgroup
of K*. Our aim is to prove that thefollowing
two statements areequivalent:
(i) For n ~ 1, and for
every(03B11, ... , 03B1n)
E(K*)n, the equation
has at most
C1 (n, F) non-degenerate solutions,
whereCI (n, 0393) depends only
on n and
r;
(ii)
For n ~2, and for
every(al, Yn)
E(K*)n,
the setof solutions of equation (1)
is contained in the unionof at
mostC3(n, r) (n - 1 )-dimensional
linear
subspaces of Kn,
whereC3(n, r ) depends only
on n and F.Proof.
First we shall prove theimplication (i)
~(ii). By (i),
the set ofnon-degenerate
solutions of(1)
is contained in at mostCl (n, r ) (n - 1)-
dimensional linear
subspaces
of Kn.Further,
the setof degenerate
solutionsof
( 1 ) is
contained in fewer than 2n(n - 1 )-dimensional linear subspaces
ofKn. This proves
(ii).
We shall now show that
(ii)
~(i).
We shall prove(i) by
induction on thenumber of unknowns n of
(1).
For n =1, (i)
istrivially
true withC1(1, F) =
1. Letp ? 2,
and suppose that(i)
has beenproved
for allpositive integers n
p. We shall show that thisimplies (i)
for n = p.By (ii),
the setof non-degenerate
solutionsof ( 1 ) is
contained in the union of at mostC3( p, 0393) ( p - 1 )-dimensional
linearsubspaces
of KP. Let Vdenote one of these
subspaces,
and consider thenon-degenerate
solutions(x1,
... ,xp) of ( 1 )
contained in V. There exist yi,... , yp
EK,
not all zero, such thatidentically
on V.This
implies
that each solution(x, ,
... ,Xp)
~ Vof (1)
satisfiesfor some
positive integer s
with s p, where03B4i1,
... ,03B4is
are non-zeroelements of K. For every
non-degenerate
solution(xl , ... , xp ) of ( 1 )
whichsatisfies
(13)
there is a non-empty subset Jof {1,
... ,sl
such thatfor each non-empty subset L of J.
Now the induction
hypothesis implies
that the numberof tuples (x,, : j
EJ )
where
(x1,
... ,xp)
is a solution of(1)
withproperty (14)
is at mostC1(|J|, r ) (here 1 JI
denotes thecardinality of J).
But it followsagain
fromthe induction
hypothesis
that the numberof non-degenerate
solutionsof ( 1 )
with
given
values forxij( j
EJ )
is at mostC, (p - |J|, 0393).
The total numberof non-degenerate
solutions of(1)
withproperty (14)
is therefore bounded aboveby C1(|J|, 0393) · C1(p - |J|, 0393). Further,
the number oftuples (Vt,
... ,03B3p)
and(03B4i1,
... ,ô,,)
considered above is at mostC3(p, F),
andthe number of subsets
of {1, sl
ofcardinality j
is at most(p).
Hence itfollows that the number of
non-degenerate
solutions of(1)
is at mostThis
completes
theproof
of(i).
0Proof of
Theorem 3. We may suppose without loss ofgenerality
that K isgenerated
over Qby
the elements of r.Indeed,
if(1)
has at most n - 1linearly independent
solutions then all solutions of(1)
are contained in asingle (n - 1 )-dimensional linear subspace
of Kn .Otherwise,
if there are nlinearly independent
solutionsof ( 1 ) then, by
Cramer’srule,
the coefficients a, , ... , an of(1)
areuniquely
determinedby
the coordinates of these solutions and hencebelong
to the fieldQ(0393).
It follows from Theorem 4 that there exists a finite set
Y
of elements ofKn, depending only
on n andr,
with thefollowing property:
If the set ofsolutions of (1)
is not contained in the union of fewer than 2(n+1)!(n - 1)-
dimensional linear
subspaces of Kn,
then(LlI’ ... , Lln)
isr-equivalent
to oneof the elements of
î. Further, denoting by F,
themultiplicative subgroup
of K*
generated by
F and the coordinates of the elements ofY,
we havea, , ... , an E
FI-
It is clear that the grouprrf
isfinitely generated
anddepends only
on n and F. For any solution(x1,..., Xn)
of(1), (a 1 x, , ... , 03B1nxn)
is a solution of theequation
It follows now from Lemma 1 and the
equivalence
of Theorem 1 and Theorem 3 that the set of solutions of(15)
is contained in the union of at COMP 2715-14most
C4(n, 0393) (n - 1 )-dimensional
linearsubspaces
of K" . Thisimplies, however,
that the set of solutions of(1)
is also contained in the union of at mostC4(n, r ) (n - 1 )-dimensional subspaces
of K". Thiscompletes
theproof
of Theorem 3. DProof of
Theorem 2. We shallproceed by
induction on n. For n =1,
Theorem 2 is true with
C2(1, 0393) =
1.Let
2 be aninteger,
and suppose that the assertion has beenalready proved
for allpositive integers n
p. Aswe shall see, this
implies
Theorem 2 for n - p.We may suppose without loss of
generality
that03B110 ~
0 and hence that ajo = 1. For everynon-degenerate
solution(x, , ... , xp) of (3)
there existsa
non-empty
subset Jof {1, ... , p}
such thatfor each non-empty subset L of J.
It follows from Theorem 1 that the number of
tuples (xj : j ~ J )
where(x, , ... , xp)
is anon-degenerate
solution of(3)
withproperty (16)
is atmost
C1(|J|, F). Further,
the inductionhypothesis implies
that(3)
has atmost
C2(p - JJJ, F) non-degenerate
solutions withgiven
valuesfor x,
( j
EJ),
whereC2(0, r) =
1. Hence the number ofnon-degenerate
solutionsof (3) having
property(16)
is at mostC1(|J|, 0393)
xC2(p - |J|, 0393). Finally, taking into
consideration allpossible non-empty
subsets Jof {1,
... ,Pl, we
obtain that the number of
non-degenerate
solutionsof (3)
is bounded aboveby
This proves Theorem 2. 0
§5.
Proof of Theorem 6We use the notation introduced in
§2.
Inparticular,
K is a finite extension ofIk(t),
where Ik is analgebraically
closed field of characteristic 0 and t is atranscendental element of K over Ik.
Further, g
denotes the genus ofK/Ik,
and
MK
the maximal set of additive valuations on K with value group Z.Then
MK
satisfies(8),
as well as the Sum Formula:for every a in
Let S be a finite subset of
MK
ofcardinality
s. If S =0 (i.e. s
=0)
then(8) implies
that the S-units in K arejust
the elements of lk*. In this case it follows from(9)
that03B1’xx1
+ ··· +03B1’nxn =
0 for all solutions of(9)
in S-units x, , ... , 1 XI,, where03B1’1, ... , 03B1’n,
denote the derivatives of oc,, ... , Lln,respectively,
withrespect
to t. This shows that for S =0
all solutions of(9)
are contained ina
single
propersubspace
of Kn .Therefore,
it sufïices to prove Theorem 6 fornon-empty
S.By P" (K)
we denote the n-dimensionalprojective
spaceover K,
that is the collection of lines of the vector space K"+through
theorigin;
these lines in K"+’ will be calledprojective points.
Theprojective point through
x =
(x1,
... ,xn)
~ 0 is denotedby x>
or(x0: ... : Xn),
wherexo, ... , Xn are called the
homogeneous
coordinates of theprojective point;
they
are determined up to a common factor.P"(1k) (n ~ 2)
denotes the set of lines in K" +’ 1through
thepoints
in Ikn+1B{0}.
ThusA
projective subspace
ofPn(K)
is the collection of lines of a linearsubspace
of Kn+1.
For each x ==
(xo,..., xn) ~ Kn+1B{0}
and v EMK
we putv(x) =
min(v(xo ),
... ,v(xn)).
Further,
for eachx>
EP"(K)
we define theheight H(x>) by
By
the SumFormula, H(x>)
iswell-defined,
that isindependent
of thechoice of the
projective
coordinates ofx>.
It is easy to check thatand
Let X be the
(n - 1 )-dimensional projective subspace
ofPn(K)
definedby
For any v =
(vo ,
... ,vn) ~ (K*)n+1
and anyfinite’, non-empty
subset S ofMK,
letY(v)
be the subset of X definedby
If 03B11 = -v1/v0,..., 03B1n = - vn/v0
then there is a one-to-onerelationship
between the elements of
Y(v)
and the solutions of theequation
Namely,
a solution(y1, ... , Yn)
of(17) corresponds
to theprojective point (vo :
v1y1 : ... :vnyn)
inY(v).
In order to prove Theorem6,
it suffices to prove thefollowing
THEOREM 6’. Let
K,
Ik be asabove,
and let S bea finite,
non-empty subsetof MK of cardinality
s.Then for
every v E(K*)" + 1 ,
the seto, f projective points
inY(v)
is contained in the unionof
at most(n - 2)-dimensional projective subspaces of ye.
In the
proof
of Theorem 6’ several lemmas will be needed. The first is acombinatorial lemma.
LEMMA 3. Let B be a real number with 0 B
1,
letq ~
1 be aninteger, and put R(B) = (1
-B)-1BB/(B-1).
Then there exists a set Wof cardinality
atmost max
(1, (2B)-1)R(B)q-1, consisting of tuples (rl ,
...,Uq)
with0393j ~
0forj = 1,
... , q andLi = 0393j
=B,
withthe following property: .for
every setof
realthere exists a
tuple (03931, ... , rq)
E 11/ such thatProof: Put 1;
=e-Gj6, ^
= e-M. Then 0Fj ~
1for j = 1,..., q and
A.
Further, Gj ~ 0393jM for j == 1, ... , q if and only if Fj ~
Ar,for j = 1,...,
q. Now Lemma 3 follows at once from Lemma 4 of[3].
D For each v =
(vo,
...,vn)
E(K*)n +’
and eachfinite, non-empty
subset Sof MK, put
The
quotient As(v)IH(v)
can be considered as some kind of S-defect for v, in the senseof Vojta’s conjectures (cf. [14], Chapter 3). As(v)
measures, insome
respect,
how far v is away from atuple
of S-units. Thequantity As(v)
will
play
animportant
rôle in theproof of Theorem
6’. In thesequel,
we fixa
tuple
v ==(vo,
... ,vn )
E(K*)n+1
and afinite,
non-empty subset S ofMK of cardinality
s. The next lemma states thatprojective points
ing(v)
cannothave
large heights.
LEMMA 4. For every
x> = (x,:
... :xn)
EY(v)
withnon-vanishing
subsums:03A3 xj ~ 0 for
each proper, non-empty subset Jof {0, nl, (18)
we have
H((x)) x i-n(n 1) {2g
+ s +As(v)}.
Proof.
Ifv(v0) = v(v1) = ··· = v(vn)
for all v inMKBS
thenAs(v) =
0and
v(x0) = ··· = v(xn )
for all(xo :
... :xn ) E Y(v)
and v inMKBS.
Further,
we have(x) = (1 : x, lx,: x,, Ixo)
where the coordinatesare all S-units. Hence Lemma 4 follows at once from Theorem B of Brownawell and Masser
[1].
Now suppose that there are v inMKBS
for whichv(v0), ... , v(vn)
are not allequal,
and let S’ be the set of these v. Let s’denote the