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On the shape of solutions of an asymptotically linear problem

MASSIMOGROSSI

Abstract. In this paper we study the problem u= |u|u in

u=0 on (0.1)

where is a smooth bounded domain ofRN, N 1, > 0. We will show that, under some assumptions, the solutions to (0.1) are close to suitable linear combinations of eigenfunctions of the problem

−u=λu in

u=0 on∂ .

Mathematics Subject Classification (2000):35J60.

1.

Introduction and statement of the main results

Let us consider the following problem

u= |u|p1u in

u=0 on (1.1)

where p > 1 and is a smooth bounded domain of

R

N, N 1. Problem (1.1) has been extensively studied in the last years; there is a wide literature on existence, multiplicity and qualitative properties of solutions to (1.1) as pandvary. Let us recall a classical result (see [7] for a proof).

Theorem 1.1. Let1< p< NN+22. Then there exist infinitely many pairs of solution to(1.1).

In this paper we study (1.1) whenpis close to 1,i.e. p=1+withpositive small enough and we try to characterize its set of solutions. Settingp=1+(1.1)

becomes

u= |u|u in

u=0 on∂. (1.2)

Supported by M.I.U.R., project “Variational methods and nonlinear differential equations”.

Received May 29, 2008; accepted in revised form October 23, 2008.

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To our knowledge in this case there are not many results. One of them is due to C. S. Lin (see [5]):

Theorem 1.2. Let be a convex domain and p sufficiently close to1. Then the positive solution to(1.2)is unique.

In [5] a crucial tool is the scaling invariance of the problem. Theorem 1.2 was extended by Dancer (see [3]) without assuming the convexity of the domain.

Another result for a similar problem can be found in [4].

In this paper we will use a different approach and we study the set of solutions to (1.2) as→0. Roughly speaking, we show that, forsmall enough, the problem (1.2) is “close” to the eigenvalue problem

u=λu in

u=0 on∂ .

Let us denote byσ (−)the set of the eigenvalues of−with Dirichlet boundary condition and, for anyλσ(−), bym(λ)the multiplicity of the eigenvalueλ. Finally, for any λσ (−), let W(λ) = span

e(λ)1 , ..,em(λ)(λ)

be the eigenspace associated to the eigenvalueλwith

e(λ)i e(λ)j =δij. We have the following result:

Theorem 1.3. Letλ¯ ∈σ (−). Then there exists0 =0(λ,¯ N, ) > 0such that for any0 < < 0and for any λ ≤ ¯λ, λσ(−), we have that(1.2)has the solutions

uj,= ±λ1 m(λ)

i=1

γi(j,λ)e(λ)i +φ

j =1, ..,m(λ) (1.3) whereφ →0in C2()and

γ1(j,λ), .., γm(j(λ),λ) is a critical point of the functional J :

R

m(λ)

R

,

J

1, .., m(λ)

=

m(λ)

i=1

ie(λ)i

2 2 log

m(λ) i=1

iei(λ) −1

(1.4) for any j =1, ..,m(λ).

Hence we have that any eigenspace W(λ) associated to λgenerates at least m(λ) solutions to (1.2) provided that is small enough. The proof of Theorem 1.3 uses a finite dimensional reduction of Liapounov-Schmidt type, a tool widely used in perturbation problem. Note that we do not require any “non-degeneracy”

assumption on the critical pointsγ1(1,λ),..,γ1(m(λ),λ).

Our aim is now to show that, under an a priori estimate on the solutions, the result in Theorem 1.2 is sharp. We have the following:

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Theorem 1.4. Let unbe a sequence of nontrivial solutions tou= |u|nu in

u=0 on∂ (1.5)

with n → 0as n → +∞and suppose that there exist Mλ1 1 is the first eigenvalue inσ (−)) and C>0such that

|un|2C Mn2. (1.6)

Then there existsλσ(−)such that, up to a subsequence again denoted by un,

|un|2 n

λσ(−), as n→ +∞, (1.7) and

un =λn1 m(λ)

i=1

γiei(λ)+φn

, (1.8)

with φn → 0in C2()as n → +∞ and

γ1, .., γm(λ)

is a critical point of the functional(1.4).

At this stage a question arises: Does each W(λ) generate exactly m(λ)solu- tions? The answer is affirmative under a non-degeneracy assumption on the critical points of the functional (1.4).

Theorem 1.5. Let us suppose that for any λ ≤ ¯λthe function J defined in(1.4) has exactly m(λ) nondegenerate critical points γ(1), .., γ(m(λ))

R

m(λ). Then, for small enough,(1.2)admits exactlyλ¯

i=1m(λi)pairs of nontrivial solutions

satisfying

|u|2C M2, (1.9)

for some Mλ1and C >0.

Note that if the eigenvalue is simple (i.e. m(λ)=1) it is possible to prove that any critical point of the functional J is nondegenerate (see proof of the Corollary 1.6). Then we have the following:

Corollary 1.6. Suppose that the any eigenvalue inσ(−)is si mple. Then for any λkσ(−)there exists¯0 = ¯0(λ,¯ N, ) >0such that for any0< < 0(1.2) has exactly k pairs of nontrivial solutions satisfying(1.9).

The last corollary can be applied to many situations; indeed, from a Michelet- ti’s result (see [6]) we have that all eigenvalues of − are simple for “generic”

domains close to(see also [8]).

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After this result was completed we have learned that some ideas of the paper can be found in [1] where the authors proved some qualitative properties of the solutions to (1.1).

The paper is organized as follows: in Sections 2-3 we give the proof of Theo- rem 1.3. In Section 4 we prove Theorem 1.4 and in Section 5 we prove Theorem 1.5 and its corollary.

2.

The Lyapunov-Schmidt reduction

Let us denote byσ (−)the set of the eigenvalues of−with zero Dirichlet bound- ary condition and, for anyλσ(−),m(λ)be the multiplicity of the eigenvalueλ. Finally, for anyλσ (−), denote byWk(λ)=span

e(λ)1 , ..,e(λ)m(λ)

the eigenspace associated to the eigenvalueλ.

In this section we fix λσ(−) and set k = m(λ), e(λ)i = ei, for i = 1, ..,m(λ)andWk(λ) =Wk. Forγ =1, .., γk)

R

kwe look for solutions to (1.2) as

u(x)=λ1 k

i=1

γiei(x)+φ(x)

withφH2()H01() (2.1) where H2()andH01()denote the usual Sobolev spaces.

Set byu = uH2()∩H01()andu2= uL2(). Moreover we require that

|γ| ≤γ0 (2.2)

whereγ0will be chosen later.

Set Wk=

uH2()H01():

uei =0 for anyi =1, ..,k

. (2.3)

Our first step is to derive the equation satisfied by the functionφ. Inserting (2.1) in (1.2) we get

k

i=1

γiei +φ

=λ

k

i=1

γiei +φ

k

i=1

γiei +φ

, (2.4) and using the mean value theorem we get thatφverifies

−φ−λφ= A(φ) (2.5)

with A: H2()L2(), A(φ)=λ

k

i=1

γiei +φ

k

i=1

γiei +φ

λ k

i=1

γiei +φ

. (2.6)

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Since the operator−−λI has a nontrivial kernel spanned by{e1, ..,ek}we will solve equation (2.5) inWk. To this end let us denote byk : H2()H01()Wkandk : H2()H01()Wkthe projections onWk andWkrespectively.

So we try to solve the problem

k [−φ− A(φ)]=0. (2.7)

Let us introduce

L

:WkWkdefined by

L

=k (−λI) . (2.8)

By classical results we get that

L

C. (2.9)

In this setting (2.7) is equivalent to find a functionφWkwhich verifies φ=

L

1k (A(φ))

. (2.10)

Proposition 2.1. Letγ = 0,γγ0. Then there exists0 > 0such that for any 0 < < 0 there exists a uniqueφWk = φ(γ,x)which verifies(2.10).

Moreoverφδwithδdepending only onλ, γ0,N, .

Proof. By the mean value theorem we can writeAin the following way,

A(φ)=λ k

i=1

γiei +φ

log

k i=1

γiei +φ

1

0

k i=1

γiei+φ

t

dt. (2.11)

Sinceφis bounded in H2()it is not difficult to show thatA(φ)L2(). Let us introduce the operatorF:WkWk

F(φ)=

L

1k (A(φ))

(2.12) and let us show thatFis a contraction fromB =

φWk: φ ≤δ

into itself (δwill be chosen later).

We divide the proof in two steps.

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Step 1: F maps Binto itself for a suitableδandsmall enough.

We have that

|A(φ)|2

=λ22

log

k i=1

γiei +φ

k

i=1

γiei+φ 1

0

k i=1

γiei +φ

t

dt

2

(2.13)

λ22

1 0

log

k i=1

γiei +φ

k i=1

γiei+φ

1+t

dt

2

using that |log|t|x|1+tC

|t|12 + |t|q2 for some 2<q≤ 2N N −2

C2

k

i=1

γiei+φ +

k i=1

γiei

q

C2

1+

|φ| +

|φ|q

(2.14)

C2

1+ φ + φq . Then we have that

A(φ)2C

1+ φ12+ φq2 (2.15)

and from the definition of Fwe get

F(φ) ≤

L

kA(φ)2C0

1+ φ12 + φq2 . (2.16) Assuming thatφ ≤δwithδ=2C0by (2.16) we get

F(φ) ≤2C0 (2.17)

which gives the claim of this step.

Step 2: F is a contraction mapping from Binto itself forsmall enough.

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Let us fixδ=2C0as in the previous step. We have F(φ1)F(φ2) ≤

L

kA(φ1)A(φ2)2

C

k i=1

γiei +φ1

k

i=1

γiei +φ1

1φ2)

k i=1

γiei +φ2

k

i=1

γiei +φ2

2

(using the mean value theorem)

=C

1

0

(1+)

k i=1

γiei +1+(1−s)φ2

−1

ds(φ1φ2)

2

. (2.18)

Let us splitin the following way,

= D1,,sD2,,sD3,,s (2.19) where

D1,,s =

x:

k i=1

γiei +1+(1−s)φ2

, (2.20)

D2,,s =

x: <

k i=1

γiei +1+(1−s)φ2

<2

k i=1

γiei

, (2.21)

D3,,s =

x:

k i=1

γiei +1+(1−s)φ2

≥2

k i=1

γiei

, (2.22) and also split the integral in (2.18) as

1

0

k i=1

γiei+1+(1−s)φ2

−1

ds(φ1φ2)

2

2

=

D1,,s· +

D2,,s· +

D3,,s· =I1+I2+I3.

(2.23)

Esti mate o f I1

First let us estimate the measure ofD1,,s. We want to show that meas

D1,,s

→0 as→0∀s∈ [0,1]. (2.24) By contradiction let us suppose that there exists0>0,s¯∈ [0,1]such that

meas D1,,¯s

δ >0 ∀∈(0, 0). (2.25)

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Set

D =

n1

D1,1

ns. (2.26)

Of course we have that

meas(D)δ (2.27)

and

D=

x: k i=1

γiei + ¯1+(1− ¯s)φ2=0

. (2.28)

Sinceφ1, φ2δwe derive from (2.28) that

k

i=1γiei2δfor any0. Thenk

i=1γiei =0 almost everywhere inDwith measD≥δ. Sincek

i=1γiei is an eigenfunction of−andγ =0 we reach a contradiction. So (2.24) holds. Then we have that

I1=

D1,,s

1

0

(1+)

k i=1

γiei+1+(1−s)φ2

−1

ds 2

1φ2|2

D1,,s

1

0

(1+)

k i=1

γiei +1+(1−s)φ2

−1

ds

N

2 N

·

D1,,s

1φ2|N−22N N−2N

C meas

D1,,s2

N φ1φ2 =o(1)φ1φ2.

(2.29)

Esti mate o f I2

SincexD2,,swe have that

k i=1

γiei +1+(1−s)φ2

−1→0. (2.30)

Hence I2=

D2,,s

1

0

(1+)

k i=1

γiei+1+(1−s)φ2

−1

ds 2

1−φ2|2

C

D2,,s

1

0

(1+)

k i=1

γiei+1+(1−s)φ2

−1

ds

N

2 N

φ1−φ2

=o(1)φ1φ2.

(2.31)

by the dominated convergence theorem.

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Esti mate o f I3

Let us remark that if xD3,,s then |1(x)+(1−s)φ2(x)| ≥k

i=1γiei

. Hence, using thatφ1, φ2δwe get

meas D3,,s

→0 as→0∀s∈ [0,1]. (2.32) Moreover, forxD3,,swe derive that

(1+)

k i=1

γiei+1+(1−s)φ2

−1 ≤C

1+ |φ1|N2 + |φ2|N2 . (2.33) Let us estimateI3,

I3=

D3,,s

1 0

(1+)

k i=1

γiei+1+(1−s)φ2

−1

ds 2

1−φ2|2

C



meas

D3,,s2

N+



D3,,s

1|



2 N

+



D3,,s

2|



2 N





D3,,s

1−φ2|N2N−2



N−2 N

=o(1)φ1φ2

(2.34)

Finally, from (2.29), (2.31), (2.34) we have that (2.18) becomes F(φ1)F(φ2) ≤C(1+)o(1)φ1φ2 ≤ 1

1φ2 (2.35) which proves that Fis a contraction fromB into itself withδ =2C0. Hence the contraction mapping theorem provides the existence of a unique fixed point for the operator Fwhich gives the claim.

Remark 2.2. From the computation in Step 1 it follows that the constantδis inde- pendent ofγ (it only depends onγ0).

The proof of the previous Proposition does not hold if γ = 0. Our aim is extend the definition ofφ =φ(a1, ..,ak,x)in order to cover this case.

Let us consider a sequenceγn → 0, γn = 0 and setφ,n = φn,x). By Remark 2.2 we deduce that there exists a subsequenceγn(denoted again byγn) and a functionφ¯such that

φ,n → ¯φasn→ +∞ (2.36)

weakly inH2()H01()and strongly in L2(). If we show thatφ¯ ≡0 we can define

φ(0,x)=0. (2.37)

It will be proved in next lemma.

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Lemma 2.3. We have thatφ¯ ≡0.

Proof. Let us write down the equation satisfied byφ,n,



















−φ,n−λφ,n−λ

k

i=1

γiei +φ,n

k

i=1

γiei +φ,n

k

i=1

γiei+φ,n

-

= k

i=1

Ci,n,ei in k

i=1

γiei +φ,n =0 on∂ .

(2.38)

Let us show that (up to a subsequence)

Ci,n,Ci, asn→ +∞ for anyi =1, ..,k. (2.39) To prove (2.39) it is enough to multiply (2.38) byej and integrate. We get

Cj,n,

e2jλ

k i=1

γiei(x)+φ,n

1+

+

k i=1

γiei(x)+φ,n

 (2.40)

and sinceγi,n are bounded andφ,nδ we get (2.39). Passing to the limit in (2.38) asn→ +∞we get thatφ¯satisfies



−φ¯λφ¯φ¯ = k

i=1

Ci,ei(x) in φ¯ =0 on∂ .

(2.41)

We argue by contradiction and suppose thatφ¯ ≡0. Define ψ = φ¯

¯φLq() (2.42)

for some 2 < q < N2N2. Let us show that

|∇ψ|2C whereC is a positive constant independent of. Multiplying (2.41) byψ and using that

ψei =0 for anyi =1, ..,kwe have

|∇ψ|2=λ

φ¯ψ2

φ¯q−2q q−2q

ψ¯q2q

C. (2.43) Hence we have that ψ ψ0 weakly in H01() andψ0Lq() = 1. Finally, multiplying (2.41) bye, whereeis an eigenfunction of−associated toµ =λwe get

µ

ψe=λ

φ¯ψe=λ

1+logφ¯ 1

0

φ¯tdt

ψe (2.44)

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which implies (µ−λ)

ψe=λ

logφ¯ 1

0

φ¯tdtψe (2.45)

= λ

¯φLq()

logφ¯ 1

0

φ¯tdtφ¯e

using that

logφ¯ 1

0

φ¯1+tdt

¯12

(2.46)

CeL() λ ¯φLq()

φ¯12C ¯φLq()C. (2.47) Passing to the limit in (2.45) we get

ψ0e=0. Since we also have that

ψ0ei=0 for anyi=1, ..,kwe derive thatψ≡0 and this is not possible sinceψ0Lq()=1.

So we reach a contradiction and thenφ¯ ≡0.

Corollary 2.4. For anyγ such that|γ| ≤ |γ0|there exists a unique functionφ = φ(γ ,x)B which satisfies

















− .

λk1 k

i=1

γiei -

−λ k

i=1

γiei .

λk1 k

i=1

γiei -

= k

i=1

Ci,ei in

λk1 k

i=1

γiei+φ

=0 on∂

(2.48)

for some constants Ci,

R

.

Proof. Writing down the equation satisfied by φ in (2.10) we get (2.48). The uniqueness of the functionφ follows by the contraction mapping theorem (see the proof of Proposition 2.1).

We end this section proving some properties of the functionφ(γ,x). Lemma 2.5. The functionφ(γ,x)satisfies

φ(−γ,x)= −φ(γ,x) . (2.49)

Proof. The claim is a consequence of the uniqueness of the functionφ. Indeed we have that−φ(−γ,x)satisfies the problem (2.48) and using again the uniqueness of the solution we get the claim.

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Lemma 2.6. The functionφ(γ,x)is C1inγ forγ =0.

Proof. The claim follows by the implicit function theorem applied to T(γ,u) : (0, γ0)×WkH2()H01()Wk,

T(γ,u)=

k

i=1

γiei+u

+

k i=1

γiei+u

k

i=1

γiei+u

(2.50) for(0, 0). We have thatT(γ, φ)=0. If we show thatT(γ, φ)is invertible, by the implicit function theorem we get the claim. We will show that

T(γ, φ)C >0 for any(0, 0) . (2.51) By contradiction let us suppose that there exists a sequencen → 0,vnWk

H2()H01()such that

vn =1 (2.52)

and T

n(γ, φn)vn

L2()→0 asn→ +∞. (2.53)

By (2.52) it follows that there existsv0WkH2()H01()such that

vnv0 (2.54)

weakly in H2()and strongly inL2(). Arguing as in Step 2 of Proposition 2.1 we can pass to the limit in (2.53) and then

(v0+λv0)

L2()=0. (2.55)

This implies thatv0=0. On the other hand, by (2.53) we get

vn+λ(1+n)

k i=1

γiei +φn

vn

2

=o(1) (2.56)

and sincevnWkandvn→0 inL2()we have

|vn|2+o(1)=o(1), (2.57) a contradiction with (2.52). So T(γ, φ) is an invertible operator and the claim follows.

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3.

The reduced problem

In this section we prove Theorem 1.3. Let J(u): H01()Rdefined by J(u)= 1

2

|∇u|2− 1 2+

|u|2+. (3.1)

It is well known that critical points of (3.1) provides solutions to (1.2). For|γ| ≤ γ0 let us consider the function φ = φ(γ,x) defined in Corollary 2.4. Using the same notation of the previous section let us introduce the reduced functional I():

R

k : || ≤γ0

R

defined by

I()= J

λ1 k

i=1

iei +φ(,x)

. (3.2)

We have the following:

Lemma 3.1. A function u =λ1 k

i=1

γiei +φ(γ,x)

is a solution to(1.2)if and only ifγ =1, .., γk)

R

k is a critical point to I.

Proof. Ifuis a solution to (1.2) we have thatJ(u)=0 and then

∂I(γ )

∂am = J(u1

em+∂φ(γ,x)

∂am

=0. (3.3)

Conversely, let us suppose thatγis a critical point toI.Differentiating again (3.19) we derive

0= ∂I(γ )

∂am = J k

i=1

γiei+φ(γ,x) em+ ∂φ(γ,x)

∂am

. (3.4)

From (2.48) we get that J

k

i=1

γiei +φ(γ,x)

Wk (3.5)

and then

J k

i=1

γiei +φ(γ,x) ∂φ(γ,x)

∂am

=0. (3.6)

Then (3.4) becomes

0= J k

i=1

γiei+φ(γ,x)

(em) . (3.7)

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From (3.7) we get that J k

i=1

γiei +φ(γ,x)

Wkand then we have

J k

i=1

γiei +φ(γ,x)

=0 (3.8)

which gives the claim.

Next result concerns the expansion of the reduced functional.

Lemma 3.2. We have that I()= λ1+2

4

k

i=1

iei

2 2 log

k i=1

iei −1

+O()

 (3.9)

uniformly with respect toas→0.

Proof. We have I()

λ2 = 1 2

k

i=1

iei+φ

2

λ 2+

k i=1

iei+φ

2+

= 1 2

λ k

i=1

iei 2

+2∇ k

i=1

iei

· ∇φ + |∇φ|2

 (3.10)

−λ 1

2− 4+O

2

k

i=1

iei 2

+2 k

i=1

iei

φ+φ2

·

1+log

k i=1

iei +φ

1

0

k i=1

iei +φ

t

dt

. (3.11)

Recalling thatφWkwe have that

k

i=1

iei

· ∇φ =0. Moreover since φδwithδindependent ofwe get that

I() λ2

=λ

2

k

i=1

iei 2

log

k i=1

iei

1

0

k i=1

iei

t

dt 4

k

i=1

iei 2

 +O

2 .

(3.12)

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Since the functionx2|x|tx2 uniformly on the compact set as → 0 for any t ∈ [0,1], arguing as in Step 2 of Proposition 2.1, we get

k

i=1

iei 2 1

0

k i=1

iei +φ

t

dtk

i=1

iei 2

(3.13) and the claim follows.

The main result of this section follows by a classical result of critical point theory due to Clark ( [2]). Here we mention a slightly different statement (see [7]).

Theorem 3.3. Let E a Banach space, IC1(E,

R

) with I bounded from below and satisfying the Palais-Smale condition. Suppose I(0)=0, there is a set K ⊂E such that K is homeomorphic to Sj1 by an odd map andsupK I < 0. Then I possesses at least j distinct pairs of critical points.

Remark 3.4. From the proof of previous theorem it is possible to see that the criti- cal pointsxofI satisfyI(x) <0.Hence it is enough to require the differentiability of the functional just forx =0 and we only need the validity of the Palais-Smale condition for negative values of I.

We will apply Theorem 3.3 to find at least j pairs of critical points to the functionalI forsmall enough.

Proposition 3.5. Forγ0sufficiently large and forsmall enough the functional I admits at least j distinct pairs of critical points.

Proof. We will apply Theorem 3.3 withI = 4

λ2 IandE =

γ

R

k : || ≤γ0

. Note that by Lemma 2.5 we have thatIis an even functional and by Lemma 2.6 it is differentiable inE\ {0}. Let us show thatI is bounded from below. By Lemma 3.2 it is enough to show that the functional

I0()=

k

i=1

iei

2 2 log

k i=1

iei −1

(3.14) is bounded from below. Since the functiong(t)=t2(2 log|t| −1)satisfiesg(t)

−1 we derive that

|I0()| ≥ −meas (3.15) which gives the claim.

Let us prove that I satisfies the Palais-Smale condition. Since I is defined for

|| ≤ |γ0|we have to check any Palais-Smale sequence is far away from the sphere

|| =γ0. By Remark 3.4 this leads to prove that

I() >0 if|| =γ0. (3.16)

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