R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
S TEVEN B ANK
An existence theorem for solutions of second order non-linear ordinary differential equations in the complex domain
Rendiconti del Seminario Matematico della Università di Padova, tome 41 (1968), p. 276-299
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OF SECOND ORDER NON-LINEAR
ORDINARY DIFFERENTIAL EQUATIONS
IN THE COMPLEX DOMAIN*)
STEVEN BANK
1.
Introduction.
In this paper we treat second order differential
polynomials
S~
(y)
= I(x) ym (y’)j (y")k ,
where the coefficientsfmjk (x)
arem, j, kaO
complex functions,
defined andanalytic
in a sectorialregion
whichis
approximately
of theform,
(for
some ~ ~0)
and where as x ~ oo in thisregion,
each non-zerofmjk (x)
has anasymptotic expansion
in terms oflogarithmic
mono-mzat8
(i.
e. functions of the formand real Thus the class of differential
polynomials
we treat con-tains,
inparticular,
thosehaving
rational functions forcoefficients).
In
(1 ; § 43]
and[5; § 122],
existence theorems wereproved
for solu-*)
This research was supported in part by the National Science Foundation (GP 7374).Indirizzo dell’A : University of Illinois. Urbana, Illinois USA.
tions
(y)
= 0 which areasymptotically equivalent
tologarith-
mic monomials as x --~ o0 over a filter base
consisting essentially
of the sectors
(1)
as 1 --+ oo. In this paper, we prove an existence theorem(§ 3 below)
for solutions of S~(y)
= 0 which are oflarger
rate of
growth
than alllogarithmic
monomials as x --~ o0 over sucha filter base.
(We are using
here theconcepts
ofasymptotic equi-
valence
(-)
andlarger
rate ofgrowth ( > )
as x --~ oo, introduced in[4; § 13].
For the reader’sconvenience,
theseconcepts
are re-viewed
in §
2below).
For a
given Q,
thecorresponding
first order differentialpolynomial,
plays
animportant
role in our existence theorem. Morespecifically,
y we are interested in the critical monomials of G(z) (i.
e. those lo-garithmic
monomials N for which there is a function h - N such that G(h)
is not - G(N)).
In~1 ; §§ 21, 26],
analgorithm
was in-troduced for
finding
the set of all critical monomials of agiven
differential
polynomial.
Toapply
our existence theoremhere,
we lookfor critical monomials N of G such that N
>
x-1.(Thus N
= ex-’+Yo(log x)’,
...(logt x)’’t
where(Yo ,
Y1 ~ ... ,yt)
islexicographically greater
than
(0, 0,
... ,0)).
Then if(a, b)
is an interval on which the function I(T)
= cos(yo
99+ argc)
ispositive,
the theoremin §
3 below asserts theexistence,
in sectorialsubregions
of theregion (1),
of at leasta
one-parameter family
of solutions of ,~(y)
=0,
eachhaving
theform
exp
W for some W -N, provided
certainsubsidiary
condi-tions are fulfilled.
(The
solutionsgiven by §
3 are shown to be au-tomatically
oflarger
rate ofgrowth
than alllogarithmic monomials).
The
subsidiary
conditions are of two maintypes.
Onetype requires
that N not be a critical monomial of certain other first order dif- ferential
polynomials.
Thistype
of condition is fulfilled ingeneral,
since
by [1; §
29(b), 21,
17(Remark (2))],
we see that for any non-zero first order differential
polynomial,
there arefinitely
many cri- tical monomials such that any other critical monomial is a constantmultiple
of one of these. The othertype
of condition is also seento be fulfilled in
general
since itrequires
that one or twologarith-
mic monomials which
arise,
do not have certainspecial
forms.(In
this
connection, see §
2(d)
and Remark(c) after § 3).
It should be noted that it is easy to test the conditions in anygiven example,
since those of the first
type
can be testedusing
thealgorithm
in[1 ; §§ 21, 26],
while those of the secondtype
can be testedby
ins-pection.
Also it should be remarked that thesetypes
of conditionsare similar to those
imposed
in the existence theorems in[1 ; § 42]
and
[4; § 127]
for solutions of first orderequations
which are -tologarithmic
monomials. Infact,
some of our conditions make it pos- sible toapply,
at theoutset,
a result in[4]
to assert the existence of a solution - N of the first order differentialequation
G(z)
= 0.The
remaining
conditions then enable us to use this solution of G(z)
= 0 to transform the second order differentialequation
Sa(y)
= 0into a
quasi-linear
form. Our conditionsplay
an essential role ineffecting
thistransformation,
sincethey permit
us, at a crucialstage,
to assert the existence of a
particular type
of solution of a certain second ordernon-homogeneous
linear differentialequation (see § 4).
Of course one can obtain information on the existence of so-
lutions
( y)
= 0 which are of smaller rate ofgrowth
than alllogarithmic monomials, by making
thechange
of variable y =zaw, multiplying by
a suitable power of and thenapplying
the theo-rem
in §
3 to theresulting equation.
In § 7,
weapply
our results to anexample.
2.
Concepts from [4, 6].
(a) [4; § 94].
For eachnon-negative
real-valuedfunction g
on(0, (b
-a)/2),
let E(g)
be the union(over ð E (0, (b
-a)/2))
of all
sectors, a + 6
arg(x
h(6)) b
- 3 where h(6)
= g(b)
exp
(i (a + b)/2).
The set of all E(g) (for
all choices ofg)
is denoted and is a filter base which converges to oo. EachE (g)
issimply-connected by [4 ; § 93].
If W isanalytic
in .E(g)
then thesymbol
W will stand for aprimitive
of ~ in.E (g).
If x and xoare in E
(g),
then the contour ofintegration
forrectifiable
path
inE (g)
from xo to x. A statement is said to holdexcelnt
in,fircitely
many directions(briefly,
e.f. d.)
inb),
if thereare
finitely
manypoints
r,C
... in(a, b)
such that the state-ment holds in each of F
(a, r1)’
F(r1 , r2)1 - - -,
,14’(rq , b) separately.
(b) [4; § 13]. If f
isanalytic
in someE (g), then f- 0
inF(a, b)
means that for any> 0,
there is a g1 such that1
8for all
f
1 inF (a, b)
means that in addition tof -~ 0,
all functions
Bjk f -~ 0 where 8; f
=(x log
x ...log;-i x) f ’.
Thenf 1 and f ~ f2
meanrespectively, f1 / f2 1 ~
7f1
-f2 , f1 ’" cf2
for some constant c~ 0,
andfinally
eitherf, If f 1,
thenby [4 ; § 28], (X log
x ...logq xj f’
1for all
q ~ 0.
If M =KxGo (log
...(logt
thenby simple
calcu-lation,
If .lll is notconstant,
then it follows from[4 ; § 28], that y
Mimplies ~’
lVl’. If for every realxa ,
we say
f
is trivial inF (a, b).
(c) [6 ;
p.247].
Alogarithmic
differential field(brietly
anLDF)
over
b),
is a differential field D of functions(each analytic
insome E
(g)),
for which there is aninteger q
> 0 such that D con-tains all
logarithmic
monomials of rankC q (i.
e. those of the form(log
...(logq X)lq ),
and such that every non-zero element of D is - to alogarithmic
monomial ofrank
q.(For
a fixed q, the set of rational combinations oflogarithmic
monomials of rank~ q,
is thesimplest example
of anLDF).
(d) [4 ; § 43, 100].
If inF (a, b),
W is - to a monomial of theform,
where k ~ 0 and t
> 0,
then we say W is in thedivergence
classin
F (a, b).
The indiciaLficnction
of W is the function on(a, b)
defi-ned
by
II’( ~P) (cp)
= costg +
arg.g )
where30k
is the Kronecker delta.Clearly IF (W)
has at mostfinitely
many zeros unless k>
0 and K ispurely imaginary.
3.
The Main Theorem :
be a second order differential
polynomial
with coefficients in an LDFover
F(a,b).
LetLet N be a critical monomial of G such that
(i) (ii)
IF (N) >
0 on(a, b), (iii)
N is not a critical monomialof z (a G/az) + +
z’(fJGj8z’), (iv) 8 GjBZ’ fl
0 and N is not a critical monomial ofa G/az’ ,
and(v)
if A[p)
isnon-empty
and r = max A - then Nis not a critical monomial of
H (z) _
E(x)
Zj(z’ + z2)k .
Let T =
(N’IN) + (N)/az) (aG (N)/az’)-1 . (Then
under theassumptions (iii)
and(iv),
T isautomatically
in thedivergence
class
by [1 ; §
40(b)]).
We assume T satisfies thefollowing
threeconditions :
(vi) (vii)
if it is the case thatT;14N,
say where a is a non-zero
constant,
then werequire
that and
(viii)
if itis the case that then we
require
that T isnot - N’/N.
(see
Remark(c) after proof ).
Then under these
conditions,
e. f. d. in ll’(a, b)
there exists afunction uo - N
such that G(uo)
= 0 and such that if xo is in the domain of uo , 1 then theequation Q (y)
= 0 possesses solutionsz
c
exp
uo for every constant c 0.Xu
The solutions
y*
have thefollowing properties : (A)
For every real a,y~‘
(B)
For each c# 0,
there is a function such thaty*
is of the form
exp We.
PROOF : In this
proof,
we will make use of the lemmas whichare stated and
proved
in§§ 49
5 and 6.By
conditions(iii)
and(iv) (and § 6)
it follows from[1 ; §
40(b)]
that there exists a
logarithmic.
=monomial Q (x),
such thatQ (x)
G(N --~- Nw)
isnormal (i.
e. has the formwhere in F
(a, b), doo C 1, 1, d;o §§
1for j > 1, lldo,
is in thedivergence class,
and thereexists q ~ 1
such that for lc ~ 1 andj +
7~ >2,
we haved c d where Lq x
= xlog
xx . By differentiating (1)
withrespect
to wandevaluating
atw = 0,
we
obtain, Q (N)/az) +
N’(a G (N)/8z’)) -
1 since 1. Simi-larly, differentiating (1)
withrespect
to w’ andevaluating
at w =0,
we obtain
QN (a G (N)lâz’) ’V dOt.
Thusclearly,
(2) (where
T is as defined in thehypothesis).
By assumption, I F (T ) ~ 0. Letting
I be any open subinterval of(a, b)
on whichIF (T)
is nowhere zero, it follows from[4 ; § 111] ] (if
or[4 ; § 117] (if
that there exists a func.tion wo 1 in F
(I )
suchthat Q (x)
G(N + Nwo)
= 0.Letting
uo = N
-f -
wehave,
Let xo
be apoint
in the domainof uo
andlet y,
= c expeach constant c
~
0. We now assert thatTo prove
(4),
let a begiven
and letZc = x-a Yc.
Thenby simple
calculation it is
easily
seen that zc is a solution of z -(uo
-= 0. But every non-zero solution of this
equation
is>
1by ~3 ;
p.271,
Lemma61,
since uo -- N andIF (N) >
0on I. Thus so
Note that if A = the theorem is
proved,
for in this caseS~
(Yc)
=(uo)
= 0 andletting 6
be a value oflog
c, we havewhich is of the form Yc = exp Thus we
may assume
A ~ (p).
We now write the
equation
SZ(y)
= 0 in theform,
In what follows let c be a non-zero constant.
Since y’ c
= Yc uo andy~~ == Yc (M + uo2),
it follows that under thechange
ofdependent
variable y =
ye (1 -E- v)
andmultiplication by (5)
is transfor-med into an
equation
of theform,
where it is
easily
veritied that(7) - (13)
below hold:(7)
Each is trivial(by (4)),
(8)
Each is some power of x(since
it is true ofuo
andeach
Now
by
definition of r asbeing
max(A
-(p)),
we haveby (10),
where
By hypothesis, N
is not a cri-tical monomial of H
(z)
=rr (z).
Thus12 (N) ~
0by [1 ; § 5],
andsince
U0 - N,
we haveTr (uo) - Fr (N ).
SinceFr (N ) clearly belongs
to an LDF
(namely
the fieldgenerated by
theoriginal
and set oflogarithmic
monomials of rank c rankN),
and sincerr (N)
is notzero, there is a
logarithmic
monomial B such thatTr (N) -
B.Hence,
Now for each
clearly (uo)
is some power of x(since
it is true of uo ,
uof
and each Thusby (16), (rr (uo))-l Ft (uo)
issome power of x for each t
r.
But if t r, thenby (4), y~-t
is
>
all powers of x. Hence(UO))-l 1~~ y~-t
and so§ (uo) r Ycr-p
for each t r. Henceby (15)
and(16),
From
(13),
wehave,
But from
(1),
Differentiating
this relation withrespect
toz’ ,
and then eva-luating at z = uo ,
we obtain(since
uo = N+ Nivo),
and
Ic 1.
Thusclearly
so
by (18), (19)
and(20),
Finally,
we determine golo · From(12), clearly
Differentiating (19)
withrespect
to z andevaluating
at z= uo ~
we obtain
(since
uo = N+ Nuy),
We now
COMPUte V2 -
We have 1 andfor j >
1.Thus since
wo 1,
we havedjO woj-l
1for j >
1 . Now ifj ~ 1
and k ~17
thendoi (Lq)k-l.
Since1/do1
is in the diver- genceclass,
there exists t>
0 such thatlldoi
> Thusdo1 Zt. Letting
= max(t, q),
we havewo’ C
sinceWo 1
(see §
2(b)).
Thusfor j >
~1,
we have(wo’)k 1,
soclearly,
Thus
by (23)
and(24),
we have(where vi
satisfies(25) and V2
satisfies(26)).
so
(6)
may bewritten,
where
by (7), (8), (14), (17), (22),
we have inF(T),
(29) S100
is trivial andN 1 do1 .
Now since
do1
is - to alogarithmic monomial,
we have inF (a, b)
that one of the
following
must hold:d01 N’IN
is> 1, ~
1 or 1.We
distinguish
these three cases :Case I :
do1 N’/N
> 1.Henee V2
1f1 so wehave,
We consider the
equation,
which may be written
logarithmic monomial, (see §
2(b)),
so ·Since
II’ ((r - p) uo)
0 onI~,
it followsby § 4,
that e. f. d. inF (I ), equation (31)
has asolution vo where,
Thus
by (4) (since r P),
vo istrivial,
andhence,
Let J be any open subinterval of
I,
suchthat vo
exists onF (J).
Asimple
calculation shows thatvo’/vo
= .lVl where ~I =(r
-
p)
Uo+
and hence l~1,.,(r
-p)
uo(see §
2(b)).
Thus sincevo solves
(31), clearly,
yWe now
subject equation (28)
to thechange
of variable v vo+
VO u, and divide the resultby vo .
0 Since v’= vo 01 (u) where 01 (u)
=We denote this
equation by
Now
clearly,
yIu view of
(33), (34)
and the fact thatSioo
is trivial we see thattooo
is trivial inF (J). Now,
By (33)
and(34),
we may writet100
=(- Sooowo) +
qi where q, is trivial in ]j!(J). By (29)
and the fact that vo =R1
whereR1
satisfies
(32),
we obtain(r - p)2 Ndo1 . Now,
By (33)
therefore =solo + where q2
is trivial inF (J).
Butby (29) (and
the fact that we see thatand so
by (33)
and(29),
we havetoos - Finally
in view of(33), (and
the fact that eachSijk
is some powerby (7)
and(8)),
weclearly
see that ifi -~- j -~- k ~ 2
thentijk
is trivial inF (J).
Hence if we divideequation (36) by (r
weobtain,
is trivial if
Now let
Wi
=W2
=(~ - r)
N.Define E2
=Wl
From
(42), a001 Wi
y so inF (J).
Now defineE1 =
WI’
=(p - r) N’,
we see thatyYl’ ( W2 W12)-1
=N’/(p r)2 N3
whichis
1IN
since x-1(see §
2(b)).
But+ W2-1
=2/(jp 2013~~
and
2/(p
-r) N by (42)
soclearly E1 - W1/N.
Thus1 in
.,F (J ). Finally
if we defineBo
= aloo -(1 + E2 + Bi),
then
Bo 1
since 1 · Since>
0 on Jfor j
=1, 2,
itfollows
from § 5,
thatequation (41)
possesses a solution u* 1 inF (J).
Thus the function v* = vo+
vo u. is a solution of(28),
andso the function
yc*
= Yc(1 + v*)
is a solution of ,~(y)
= 0- In viewof what I and J
represent,
it is clear that such ay/*
exists e. f. d.in
Since vo
is trivialby 33), v*
is trivial inF (J).
Thusclearly
and Part(A)
follows from(4).
Sinceyt
=-~- v*),
clearly (yc*I’
=y~~ (uo + (VII)’ /(1 -~- v*)).
Since v. is trivial in F(J),
sois
(v*)’ (see §,2 (b)).
Thus we may write(yc*I’
=Wd,
whereThus if x1 is a
point
in the domain ofW~ ,
then forsome constont Since
p~ .g ~
0. Thus forfor any value of
log~
which is of theform
exp We .
This proves Part(B)
in Case I.Case II : In this case, where 6 is
a non-zero constant.
By (2)
andhypothesis (viii), 8 ~ 1.
Thus in(27),
we have -6)/ N
soby (7),
We
again
consider theequation (31).
In this case,by (29)
and(43),
As in Case
1,
is of the form exp and in this case,N
since(see §
2(b)).
Henceby § 4,
e. f. d. inequation (31)
possesses a solution VO =B2 where,
As in Case
I, (33)
holds. Let J be any open subinterval of I suchthat vo
exists onF (J).
Asimple
calculation shows thatvo’ jvo
= Mwhere
Thus,
as in CaseI,
and since vo solves
(31),
we have that(34)
holds. We nowsubject equation (28)
to thechange
of variable v = vo+
vo u, and then divideby
vo . If we denote the resultby
then as in Case
I,
the coefficients andtoo1
aregiven by (37), (38), (39)
and(40) respectively,
and(in
view of(33)),
wealso have
In view of
(29), (33)
and(34),
it follows from therepresentation
in
(37)
thattooo
is trivial inh’ (J)~
and it follows from the repre- sentation in(38),
thatt100 (- 80001vo) +
q3 where q3 is trivial in F(J).
Since vo =R2
whereJR2
is as in(44),
we haveusing (29)
thatt10o’V (r
-p)2 Ndo1 .
In view of(29)
and(33),
it followsfrom the
representation
in(39)
thattoio
-S010 +
q4 where q4 is trivial in.R (J ).
Now2MSOOt’V
2(r - p) d01 by (29).
But inthis case
dOt> 1/N
since1/do1
N x-1(see
2(b)).
Thusclearly
from(43), toio -
2(r
-p) do1 .
*Finally
from(29), (33)
and therepresentation
in(40),
we see that N-1d01
* Hence if we di-vide
equation (45) by
we obtain anequation,
is trivial if i
+ j + k #
1. But these areprecisely
the same asymp- toticproperties
we found for the coefficients of(41)
in Case I(see (42)).
Thusletting Wi
=W2 = (~ - r) N,
we see that if wedefine
E2 , Eo
as in CaseI,
we will find that.E~
1 in F(J) ( j
=0, 1, 2),
and soby § 5,
it follows thatequation (47)
possessesa solution u* 1 in
F (J).
Thus as in CaseI,
theequation (y)
= 0possesses the solution
y,*
= yc(1 -~-
vo-~-
vo~~)
e. f. d. inF (a, b).
The
proof
the solutionyc*
has the desiredproperties
in this casefollows
exactly
as in Case I.Casc III :
do1
1. In this case, in(27)
we haveso we have
We
again
consider theequation (31).
In this caseby (29)
and(49),
lldo,
and N are both - tologarithmic monomials,
one of the foll-owing
three cases must hold:(a) C N, (b) > N
and(c)
N. In Case(a),
U-so
IF ( U) C 0
on I. In Case(b),
U -l/do1
soby (2), IF (U)
is nowhere zero on I. In Case(c), lldo1 rv
aN for some con-stant
a 0. By (2)
andhypothesis (vii), a p - r so U N (a -- + (r - p)) Nand
0 on I. Thus in all three casesF( U) 0.
Hence
by § 41
e. f. d. inF (I), equation (31)
possesses a solutionVo =
B3
whereAs in Case I
(33)
holds. Let J be any open subinterval of I suchthat v 0
exist onF (J).
Asimple
calculation shows thatwhere M =
(r
-~)
uo+
· Thus M ~(r
-p)
uo , andsince vo
solves
(31),
we have that(34)
holds. We nowsubject equation (28)
to the
change
variable v = vo+
vo u and then divideby
vo . If we denote the resultby
then as in Case
I,
the coefficientstooo ~ 9 tioo tolo
andtool
aregiven by (37), (38), (39),
and(40) respectively,
and(in
view of(33)),
wealso have
In view of
(29), (33)
and(34),
it follows from therepresentation
in
(37)
thatand it follows from
(38)
that -(- Sooowo) +
q5 where q5 is tri- vial inF (J ).
Since whereR3
is as in(50),
it followsfrom
(29)
thatIn view of
(29)
and(33)
it follows from(39)
thattolo + +
where q6 is trivial inF (~T ). By (29),
2(r-p) do1,
7and
by (49),
N-1 · Let U # =(1 /N ) +
2(r - p)
IBy hy- pothesis (vii), lldoi
is not - 2( p - r) N,
so is ~ to either N-1 ordo1
and so is nontrivial. Henceclearly,
Finally
from(29)
and(33),
it follows from(40),
thatHence if we divide
equation (51) by (r -~) do1 U,
we obtain anequation
where
by (52)-(56),
we have inF (J),
To
proceed
anyfurther,
we must consider each of the pos- sibilities for theasymptotic
behavior of U. Sincelldot
are~ to
logarithmic monomials,
one of thefollowing
cases must holdin
h’ (a, b) : N, 1/do1 > N, 1/do1
Wedistinguish
thesethree subcases.
Subcase A :
Ildo1
N. Thus in thissubcase, U - (r - p) N
and U # N 2
(r
-p)
* Henceby (58)
and(59), 1,
-
2/(r p) N, 1/(r p)21V 2
and aijk is trivial if i+ j -- k
1.But these are
precisely
the sameasymptotic properties
we foundfor the coefficients of
(41)
in Case I(see (42)).
Thusexactly
as inCase I
(i.
e.by letting W= W2
=( p - r) N,
anddefining E1 ,
as in Case
I),
we canapply §
5 to show thatequation (57)
pos-sesses a solution
u* 1
in.F’ (J ).
ThusS~ (y) = 0
possesses the so- lutiony*
=-~-
vo-~- v. u*) in F (J)
and hence e. f. d. inF (a, b).
The
proof
thatyt
has the desiredproperties
in this case followsexactly
as in Case I.Subcaae B :
lldo, >
N. Thus in thissubcase,
U -1/doi
andThus
by (58)
and(59),
we have19
aoio -1 /(r - p) N, do1/(r
-p)
N. LetW, = (p - r)
N andW2
De-fine
E2
= aOO1Wl W2 -
1 · Then.E2 1,
inF (J)
sinceclearly
aooi
Wi
1. Now(aolo+(l + E2) + W2 +
+ WI’(W2 WI2)-I)). By,this subcase, W2-1 C wi-i. Also,
=
do1 N’/(r
-p) N2
which is alsoWl-1
sinceby
this caseHence since -
W,-l ,
we see thatEi C - W, Wl
so
E1
1 inF (J). Finally
if we definejE7o
= a100 -(1 + E2 + Ei)
then
F (J)
since a100’V 1. Thus since>
0 on Jwhile on J
(since by (2)
andby assumption (vi)),
it followsfrom §
5 that e. f. d. in F(J ),
equation (57)
possesses a solutionu*
1. In view of what Jand I
represent, clearly
such a u* exists e. f. d. inF (a, b).
Thus(28)
possesses the solution vl = vo+ vo u~",
and hence(y)
= 0possesses, e. f. d. in
F (a, b),
the solutiony*
= y,(1 -~-
vo-E-
vou*).
The
proof
that the solutionyt
has the desiredproperties
followsexactly
as in Case I.Suboase
C ;
N. Thus there is a non-zero constant asuch that Since
l/do1
we haveby assumption (vii) that,
(60)
2( ~ - r))
and 0 where A = a+ (r - p).
In this
subcase, clearly
and~~-(y-p2(~2013~))/o~
soby (58)
and(59)
we have1,
aolo -(0 +
2(r - p))/(r
-p) Â.N,
aOOi I"V and is trivial fori -- j -- 1 1.
LetW1 - (~ - r)
N andW2
= -Define E2
=W2 -
1. Then.E2
1 inF (J)
since aoolW,
1. Now defineE1
= -Wi + + (1 -- ( Wl + W2-1 + Wl 2)-l)). Clearly,
since 2 =0
+ (~’ -1~),
we haveWi + W2-1
=(a +
2(r 1~))l~ (1~
-r) N.
Now
Wl" ( W2 W12)-l
=N’12 (r
-p) N3
which isWl-1 + W2-1
since
by
this subcaseN’/N3 ~ do1 N’IN2
which isby
thiscase. Since solo - -
( Wl 1 + W2 1) clearly,
we have thatEl
C - WI (W1-1 +
soEl
1 inF (J). Finally
if we defineEo
= aloo -(1 + E2 + El),
thenEo (J)
since 1 ·Thus since IF
>
0 onJ,
while IF( W2) ~
0 on J(in
viewof
(60)
and the fact thatIh’ (W2) _ -
IF(2N)),
it follows from§ 5
that e. f. d. inF (J), equation (57)
possesses a solution u* 1.In view of what J and I
represent, clearly
such a u* exists e. f. d.in
F (a, b).
Thus(28)
possesses the solution v* = vo+
vou*,
andhence Q
(y)
= 0 possesses, e. f. d. in F(a, b),
the solutionyc*
== Yc
(1 + vo + vo u*).
Theproof
that the solutionyc*
has the desiredproperties
followsexactly
as in Case I. This concludes theproof
of the theorem.
REMARKS :
(a)
If I is any open subinterval of(a, b)
on whichIF (T) > o,
then in view of(2),
it follows from[4; § 111J
thatthe
equation Q (x)
G(N + Nw)
= 0actually
possesses a wholeone-parameter family
of solutions 1 in.F ( I ), By using
thisfamily
for wo in the
proof,
it is clear that e. f. d. in F(I ),
we canactually expect
atwo-parameter family
of solutions of Q(y)
=0,
each
having
the form for some W - N.(b)
In each case in theproof
we showed that for each c~ 0,
the
equation Q (y) = 0
possesses an exact solutionx
where y, = c exp I
uo , u~ C 1
and v, =R~
for someRc -
to aXO
logarithmic
monomial. Thisrepresentation clearly gives
more infor-mation about
yt
than either of the statementsy* - y,
ory~= egp W
for some
Wc - N,
andfurtermore,
is useful inestimating
howgood
an
approximation
y, is to the exact solution(c)
Ingeneral
one can make nospecific
statement about therelation between N and its
corresponding
T. In fact for anygiven
logarithmic
monomials N andT*,
where T* is in thedivergence class,
one canalways produce
a second order S~(y),
whose correspon-ding
G(z)
has N as a critical monomial(which automatically
satisfies(iii), (iv)
and(v) of § 3),
and where T* is thecorresponding
T for N.To see
this,
consider Q(y)
=N) yy"
-N) (y’)2 -E- -(N’/T~N2))yy’-y2.
Hereand hence G
(llrw)
=(w’IT*) +
w - 1. Since T* is in thedivergence class,
an easyapplication
of[1; § 26]
to G(Nw),
followedby [1; §
30(b)]
shows that N is a critical monomial of G
satisfying (iii) by §
6.Clearly (iv)
and(v)
are also satisfied. Asimple
calculation shows that T* =(N’IN) + (0 G (N)/az) (BG (N)/az’)-1.
In view of this exam-ple,
one can view the situations where orTx5 N’/N (I,
e. thosewhere one would have to
verify (vii)
or(viii) of § 3),
asbeing
some-what
special
situations.4. LEMMA : Let
W,
V and .H- be functions - tologarithmic
monomials in some
F (1).
Let and W - - TT.(Then clearly
W
-~- Y ~ V,
soW + V
is also in thedivergence class).
LetIF(
and
LF ( W + V) ~
0. Let wo be a function of the form exp Then e. f. d. inF (1),
theequation +
v’ =Hwo
possessesf V.
asolution vo
=Rwo
where R -+ V ).
PROOF :
Let zo
=.F.fwo .
Under thechange
of variable za =v’,
the
equation
Under the
change
ofdependent
variable followedby
division
by
xzo , 7equation (b) becomes,
where U =
W ~-
V+ (H’/H) + ( W ’/ W ) +
x-1. Now since W - -V, clearly W -~-
V is - to alogarithmic
monomial which and hence>
x-1. Since H and W are - tologarithmic monomials, H’IH
and
W’/ W
are(see §
2(b)). Thus,
Hence in some element of
I’ (I ),
U is nowhere zero, so(c)
may be written u+ u’/ U
=By (d),
1 and 0.Letting
J be any open subinterval of I on which
IF (U)
is nowhere zero, it follows from(3 ;
p.271,
Lemma3]
that there is afunction ul
1in
F (J)
such that ul+ 1/x U.
Butxul
1(see §
2(b)),
soNow
clearly
the function solution of(b).
LetJi
be any open subinterval of J on which is nowherezero.
Since z.
is of the formV,
andW/W + V (by (d)),
it followsby [2; §
10(b)]
that theequation
v’ possessesa
solution vo
=Rwo
where V) in .F(J1). (Note : [2 ;
§
10(b)]
wasproved
under thehypothesis
for somet
> 0,
but it iseasily
seen that the exact sameproof
holds if the isreplaced by
the condition that Vbe ~
to alogarithmic
monomial which is> x-1),
Then vo isclearly
a solutionof
(a) proving
the lemma.5. LEMMA :
(a)
whereand
A2
areanalytic
in someF (I).
LetWi, W2
be ~ tologarithmic
monomials is
F(I ).
DefineE2 El
and.Eo
as follows :where
Wj
is theoperator 1fTj
y = y -y’/ W~ .
where aooo and
(for
i+ j
>2)
are trivial in.F (I ),
and where4S
(y)
is a second order linear differentialpolynomial
for which there exist functionsW,
andW2
in thedivergence
class inF (I ) (see §
2(d))
and functionsE1, E2
each 1 in1~ (I ),
such that(1)
aboveholds. Then for any open subinterval J of I on which both IF
(WI)
and IF
( W2)
are nowhere zero, theequation
tp(y)
= 0 possesses atleast one solution
y* C
1 in F(J).
PROOF : Part
(a)
isproved by directly computing
theright
sideof
(1)
andshowing
that(1)
holds ifE2 , E1 and Eo
are defined asin the statement.
To prove
(b),
let y =W1 y
andd2
y =W2 Wi
y. Asimple
calculation showsthat y’
andy"
are linearpolynomials
inand
(with
coefficients which are each some power ofx).
Thus when is written as apolynomial
in the weobtain
(using (1)),
where each
bmnq
is trivial(since
each istrivial).
SinceBO E1, E2
are each 1 in
I’ (I ),
it followsdirectly
from the remark after[5 ; § 99] (which
states that formulas(99.6)
and(99.7)
are sufficientfor a
strong
factorizationsequence),
that( W1,
is astrong facto-
rization sequence
(see [5; §
88(b)])
for tp(y).
Hence if J is any open subinterval of ~T on which bothIF(W,)
and are nowherezero, then
by [5; § 99,
Part5],
theequation P (y) = 0
possesses at least one solutiony*
1 inF (J), proving (b).
6. LEMMA. : Let G
(z) = ,¿ g1J Zi (z’) ~
have coefflicients in an ZDFover
F (a, b).
Let N be a critical monomial of G(z).
Then N is asimple non-parametric
critical monomial of G(as
defined in[1 ~ §§
28(d), 14])
if andonly
if N is not a critical monomial of =PROOF :
(For
notation and definitions used in thisproof,
see[1; §§ 7, 9, 28]).
Let N haveexponent fl
andmultiplicity
m in G.Let
H (z) = G (Nz),
sayH (z)
~hij (x)
zi(z’) j. By [1 ; §
30(b)],
1 isa critical monomial of g
having exponent P
andmultiplicity
m.Now for each s h
0,
there is alogarithmic
monomialQ (x)
suchthat
[1 ~
s,(2c, v)
=- I rij(u) va (v’) j,
where(where
isthe jth
iteration of theexponential function).
Thusby [1; § 27],
for ssufficiently large,
(b)
is trivialif j
and 1 is a root ofmultiplicity
m of C
(v)
= ~ rip(oo) vi, (where
rip(oo)
is the constant definedby :
rio
(oo)
= 0 if1,
while if ri,~ ";1 ~ (oo)).
Now let
A(z)=F(Nz).
Thenclearly,
we haveThus for all s >
0,
there is alogarithmic
monomial .R(x)
such that[ 1, s, A] (u, v) (v’) j,
whereLetting
B(u)
= 1~(es (u))/Q (es (u)),
we haveby (a)
and(c)
thatNow assume N is not critical of
.h (z).
Thenby [1; §
30(b)],
1is not critical of 11.. Now
if P
were> 0,
then in view of(b)
and(d), clearly [1~.4](~1)
would betrivial,
soby ~1; §§ 3,
11(b)],
1would be critical of 11 which is a contradiction.
Thas fl
= 0proving
hat N is