R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
M ARIAGRAZIA B IANCHI A NNA G ILLIO
C ARLO C ASOLO
A note on conjugacy class sizes of finite groups
Rendiconti del Seminario Matematico della Università di Padova, tome 106 (2001), p. 255-260
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MARIAGRAZIA
BIANCHI (*) -
ANNAGILLIO (*) -
CARLOCASOLO (**)
Dedicated to
prof
Cesarina Tibiletti on hereightieth birthday.
Let G be a finite group, and let
be all the distinct sizes of its
conjugacy
classes. The arithmetical nature of this sequence is far frombeing arbitrary,
andclearly
it has toenjoy
rather
special,
if notyet understood, properties. Often, imposing hy- potheses
on the sequence, orjust
on some of itsmembers, yields strong
restrictions on the structure of the group G
(e.g.
as in Burnside’s Lem-ma).
Forinstance,
it was firstproved by
Kazarin[3] (we
aregrateful
tothe referee for this
reference),
and laterby Bertram, Herzog
and Mann[1] and, independently,
Dolfi[2],
that if the set of sizes of the non centralconjugacy
classes of G can bepartitioned
in twonon-empty
subsets such that each member of one subset iscoprime
to any member of the other subset(fur
furtherreference,
a group with thisproperty
we call a classreparable group),
then G is metabelian andG/Z(G)
is a Frobeniusgroup.
In this note we show that the same conclusion holds if one
just
as-sumes that the two
largest
sizes arecoprime.
Moreprecisely,
we prove THEOREM. Let G be afinite
group, and n m be the twolatest
sizes
of the
non-centralconjugacy
classesof
G . Let a, b E G whose con-(*) Indirizzo
degli
AA.:Dipartimento
di Matematica «F.Enriques»,
Univer-sita di Milano, Via Saldini 50, 1-20133 Milano,
Italy.
E-mail:
[email protected]; [email protected]
(**) Indirizzo dell’A.:
Dipartimento
di Matematica «Ulisse Dini», Università di Firenze, VialeMorgagni 67/A,
1-50134 Firenze,Italy.
E-mail:
[email protected]
256
jugacy
classes have sizes n, mrespectively,
and set N =CG (a),
H ==
CG ( b ) .
Assume that( n , m ) =1;
then(i) N,
H are abeLian and N n H =Z(G);
(ii) G/Z(G)
is a Frobenius groups with kernelN/Z(G)
andcomple-
ment
H/Z( G ).
We
adopt
thefollowing
notations. If then[x)
denotes theconjugacy
class of x in G . If B is aconjugacy class,
also a
conjugacy
class. If is a subset ofG, following [1]
weset
Clearly, Ks
is asubgroup
ofG,
and it is normal if S is a normal subset.Also, S
is the union ofright
cosets ofKs,
whenceI
divides Therest of our notation is standard.
In our
arguments
we will make use of some ideas ofBertram, Herzog
and
Mann,
which prove to bequite
useful whendealing
with classes ofcoprime sizes,
and that we introduce in thefollowing Lemmas,
the firstof those goes back to Burnside.
LEMMA 1
([l]).
Let A =[a],
B =[b]
beconjugacy
classesof
thefi-
nite group G.
If
then AB is aconjugacy
class aytdCG (a) CG (b) = G.
LEMMA 2
([4]).
Let B be aconjugacy
classof largest
sizeof
thefi-
nite group G . Let A be a
conjugacy
classof
G such that( ~ I A I ,
= 1.Then
(A -lA) ~ KB,
and(A)
is a normal abeliansubgroup of
G.We now come to the
proof
of the Theorem. Let n m with(n, m)
= 1 be thelargest
sizes of the non-centralconjugacy
classes of G. Let a, b E G with[
= m;put A = [a], B = [b]
andWe
proceed
in a number ofsteps.
STEP 1. Let
x e Z(H);
then eitherr e Z(G)
orCG (x)
= H.PROOF. Let
x eZ(H)
and X =[x].
AsCG (x) > H, IXI
divides .Suppose CcM~~f. Then IXI IXI ~~ I and()Z),
Then XA is a
conjugacy
classand,
as it follows that eitherIXAI IBI [
orIXAI =
If it wereB ~ [ then, by
Lemma1,
XAA -1
would be aconjugacy
classcontaining X,
so that X =XAA -1;
onthe other hand
IAI
and so a con-tradiction. Therefore then
by
Lemma2, ((ZA)~XA) ~7~,
yielding (X -1 X) ~ KB
asKB
is normal.Also,
sinceXA I
=A ~ ,
is a
class,
so A and(X -1 X) ~ KA .
Thisimplies
since
(in
factI
dividesI A I
andI
divides sowe have X = and x e
Z(G).
STEP 2. We may assume
b ~ I
someprime
p.PROOF. Let x
= b
be aprimary component
of b such that G .Then, by Step 1, C(r) = H ,
and we can substitute bby
x .STEP 3. Let The
H = P x L ,
where L is an abelianp
-group.PROOF. Let y be
a p ’-element
of H . As ypermutes
withb ,
and(lyl,
,ibl)
=1, we
have =CG ( y )
nBy our choice
of B =[b]
as a class of maximal
size,
weget
H = hence H ; thusproving
the assertion.STEP 4. p does not divide m .
PROOF.
By
Lemma1,
G = NH.Suppose, by contradiction, that p I m.
Then p
does not divide n =[G : N] = [H :
H nN].
Thus P ~ N n H andso
(as &~?), yielding
and the contradiction H=PxL;N.STEP 5.
PROOF. Let x e
KB
n H . Then xb eB ,
so xb = b g for some g e G. AsGG (b)
weget
Mk . ~ . Mk .. ~. Mk . ~ ,y,k, ~ ~
But
I
dividesI
= m , andthis, by Step 4, implies
that p does not divideKB I
thusforcing x
= 1.STEP 6. We can choose a to be a
PROOF. Let be the
p-component
of a . Then al e H w for some w e G .Now,
and everyg e G
can be written as g = uv with258
u E N, Then, being (A)
normal and abelianbut we have also
r -- __ ~ I
By Step 5, [a1, g]
Hw =(KB
n= {1}.
Hence alE Z(G)
and wecan
replace
aby aal-l.
STEP 7. Assume H not
abelian;
then L ~Z(G)
andp for
some 1 E N.
PROOF.
Deny,
and suppose the existence of aprime
divisors q ofL ~ [
and of a
q-element x E LBZ(G). Now, Step
1 assures thatCG (x)
= H. Butthen if
arguing
as inStep 3,
weget H = Q
x T with Tabelian. This means in
particular
that P ~ T isabelian,
a contradic-tion.
STEP 8.
N n H = Z(G).
PROOF.
Clearly, Z(G) N n H.
To prove the reverseinclusion,
weconsider
separately
the cases H abelian and H not abelian(we
will see later on that the latter case does notoccur).
If H isabelian,
andy E N
nn H,
thenCG(y) ; (H, a) > H,
so,by Step 1, y E Z(G).
Let H be notabelian. Then L ~
Z(G) by Step
7. Lety E P
nN,
then as a is ap ’-ele- ment, CG (ya)
= n soCG (ya)
=CG (a) and, arguing
as inStep 6,
weget
We now set K =
(A). By
Lemma 2 andStep 6,
I~ is a normal abelianp’-subgroup
of G.STEP 9. Assume H not abelian. Then PIP n
Z(G)
acts as a groupof fixed point free a~tomor~phisms
on nZ(G).
PROOF. Write
Po
= P nZ(G)
andKo
= K nZ(G). By Steps
7 and8, Po
= and[P : Po ] =p~
= n .Suppose, by contradiction,
that thereexists
x E=- PBPo
such thatCx(x) > Ko.
Observe that p dividesI [xl 1;
forotherwise, x E Z(P 1)
for some c E G and so x E whence = H cby Step 1,
and = HC n K =(H
nI~)~ Z(G)
=Ko, against
ourassumption
on x .Now, by coprime action,
we have thedecomposition, I~ _ [K, x]
xX and we can write a = ~w with ~ e
[K, Take g
=then = n so
by
what we observedabove, p
dividesI [ g~ I
-Also, (Po , x), whence ~ p l . By
ourhypotheses
on n , m we then have( [ g] ~ I
n =[P : Po ].
Inparticular, [KP :
n . Butsince K is normal and
abelian,
= where D = nn
CP (w).
Soyielding [D : Po ]
>[K, x] (
. As D ~CP (x)
acts on[K, x],
thisimplies
that
CD(u)
>Po,
so there exists y eCD(u) BPo.
But y E D ~Cp (w) and, consequently,
y E nCp (uw)
=Cp (a)
=N,
whencey E H
n N =Z( G ),
a contradiction.STEP 10. H is abelian.
PROOF.
By Step 3, H
= P xL ,
where L is abelian.By Step 9,
P/P nn
Z( G )
iscyclic
orgeneralized quaternion. So,
if P is notabelian,
p = 2 and PIP nZ(G)
isgeneralized quaternion. Now,
be Z(P) BZ( G),
so thereexists,
in this case, an element y EPBZ(P)
such that b = with c EE Z( G )
n P . But thenCg ( b )
=H which implies
=H yielding
the contradiction y E
Z(P).
STEP 11. Conclusion.
PROOF. Let x be the set
of prime
divisors of m =[G : H] _ [N :
N nn
H]. By Step 8,
N n H =Z(G),
henceZ( G ),
and so N = R xW,
where R =
0, (N)
and W ~Z(G).
Let Then
CH ( y ) = Z( G );
infact,
suppose there existsxeCH(y)BZ(G),
thenCG(x) = H,
whenceyeHnN=Z(G), against
thechoice of y .
Thus, setting
Y =[y],
weget
Since
C( y ) ~ (Z(G), y)
and y is a non-central~-element,
we have thatthe
x-part
ofI
is smaller than m, henceI
= n.Therefore, by
Lem-ma
2, (r
is a normal abelian x-group. As( ~ R’ , [ G : N] ) = 1,
it followsThe same
argument
holds for any andso we obtain that = is normal in G and
nilpotent.
HenceN =
RZ(G)
is normal andnilpotent;
it is now immediate to conclude thatGIZ(G)
is a Frobenius group with kernelN/Z(G)
andcomplement
260
H/Z(G).
It remains to show that N is abelian. Let x EN~Z(G);
thenthus
which, by
ourhypotheses
on n, mimplies = N,
thus
completing
theproof.
As we mentioned at the
beginning, by
results in[1]
and[2],
the finitegroups
satisfying
the conclusion of our Theorem arejust
theclass-sepa-
rable groups. So we have the
following
COROLLAY 1. A
finite
group G is classseparable if
andonly if
thesizes
of
the twolargest
non-centralconjugacy
classesof
G arecoprime.
We also observe that such groups have
just
three classsizes, namely
1,
.Thus,
we have alsoCOROLLARY 2. Let 1
kl 1~2
...~ l~r
be the sizesof
theconjuga-
cy classes
of
afinite
group.Then, if
r ~3 , (kr-l,
1.REFERENCES
[1] E. BERTRAM - M. HERZOG - A. MANN, On a
graph
related toconjugacy
classesof
groups, Bull. London Math. Soc., 22 (1990), pp. 569-575.[2] S. DOLFI, Arithmetical Conditions on the
Length of the Conjugacy
Classesof
a Finite
Group,
J.Algebra,
174 (1995), pp. 753-771.[3] L. S. KAZARIN, On groups with isolated
conjugacy
classes (Russian), Izv.Vyssh.
Uchebn. Zaved. Mat., n. 7 (1981), pp. 40-45(English
translation: Sovi- et Math. (Iz. VUZ), 25, no. 7 (1981), pp. 43-49).[4] A. MANN, A Note on
Conjugacy
Class Sizes,Algebra
Coll., 4 (1997),pp. 169-174.
Manoscritto pervenuto in redazione il 18 dicembre 2000.