R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
A LMA D’A NIELLO
Groups in which n-maximal subgroups are dualpronormal
Rendiconti del Seminario Matematico della Università di Padova, tome 84 (1990), p. 83-90
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Groups subgroups
are
dualpronormal.
ALMA D’ANIELLO
(*)
1. - Introduction.
In the
theory
of finite soluble groups,embedding properties
ofsubgroups,
aspronormality,
normalembedding, etc.,
have a veryimportant
r61e.The
concept
ofpronormality
is one of the mostimportant,
it wasfirst introduced
by
P. Hall and theninvestigated by Gaschiitz, Fischer,
Mann and many others.Pronormality plays
apart
in thetheory
ofF-projectors,
F aformation,
and in this sense it can bedualized.
Let G be a group, U a
subgroup
ofG,
U is said to bedualpronormal,
in short U
dpn G,
if theFitting subgroup
ofU, UQ)
is contained inU,
for every g in G. In aprevious
work[1]
it wasproved
that ifevery maximal
subgroup
isdualpronormal
then the group isnilpotent.
Huppert [5],
Mann[6]
and Schmidt[7]
haveinvestigated
groups whose n-maximalsubgroups, n > 1 ,
arerespectively normal,
sub-normal,
modular. The purpose of this paper is tostudy
groups whose n-maximalsubgroups, n > 1,
aredualpronormal.
Groups
in which 2- or 3-maximalsubgroups
aredual-pronormal
are
completely described;
it isproved,
inparticular,
thatthey
are« almost all >>
supersoluble and,
as f or n =1, they
areexactly
thegroups in which 2- or 3-maximal
subgroups
are normal.Some
results, holding
f or n = 2 and n =3,
hold for every na- tural number n.(*) Indirizzo dell’A.:
Dipartimento
di Matematica eApplicazioni,
Uni-versith di
Napoli,
via Mezzocannone 8, 80134Napoli.
Research
supported by
a C.N.R.grant.
84
Throughout
this paper « group» is used to mean « finite soluble group ». The notation will bemostly
standard.I would like to thank Professor K. Doerk for his
helpful
sug-gestions
and the MathematicsDepartment, University
ofMainz,
fortheir
hospitality
while this work has been done.2. - Let G be a group, u-maximal sugroups of G are defined
by
induction: if U is a maximal
subgroup
ofG,
U is said to be 1-maximal inG;
let n >1,
asubgroup
U is said to be n-maximal inG,
if U is(n - 1)-magimal
in a maximal sugroup M of G.Observe that a
subgroup
of anilpotent
group isdualpronormal
if and
only
if it is normal.Many properties
ofdualpronormal
sub-groups can be founded in
[1],
the next will befrequently
used in thefollowing.
LEMMA 1
([1]
prop.2.4).
Let G be a group, V anof
G.Then:
(a)
V isduaZpron,ormat in
G.(b) Every nilpotente dualpronormal. subgroup o f
G is contained ina
conjugate o f
V.The
following
theorem describes the groups in which every 2-maximalsubgroup
isdualpronormal.
THEOREM 1.
I f
every 2-maximaZsubgroup o f
a group G is dual-pronormal,
then either:(a)
G isnilpotent, or
(b)
G is minimal nonnilpotent, IGI
=pq#, G, q jp -1.
In
particular
G issupersoluble
and every 2-maximalsubgroup
isnormal in G.
PROOF. Maximal
subgroups
of G arenilpotent ([1]
teoremaB),
so either G is
nilpotent
or minimal nonnilpotent.
Let G be minimalnon
nilpotent,
thenG ~
=ptXq!3, G~ _~ G, Ga cyclic.
TheFitting
sub-group M of G is a maximal
subgroup,
it is theunique N-injector
of Gand
[G : M]
= q. Let II be a maximalsubgroup
of G such thatU,
then
F(G)/ II n I’(G)
is a chief factor ofG,
this means[G : Z7] =
p =-
IF(G)¡U n
-Suppose Gr¡ U,
then there exists asubgroup X,
2-maximal in
G,
such that XU; X
isnilpotent
anddualpro- normal, hence, by
lemma1, X,
and must be contained inM,
a contradiction. It follows
Ga
= U and a = 1.Finally
it is clear that such a group issupersoluble
and every 2-maximalsubgroup
isnormal in it.
Our aim now is to
study
groups in which every 3-maximal sub- group isdualpronormal.
THEOREM 2. fihe
following
statements areequivalent:
(a) Every
3-maximalsubgroup o f
a group G isdualpronormal.
(b) Every
3-maximalsubgroup of
a group G is normal.PROOF. First suppose
(c~)
holds. Maximalsubgroups
of Gsatisfy
the
hypothesis
of theorem1,
sothey
arenilpotent
or minimal nonnilpotent
with the described structure. Letifg
be 3-maximal inG,
then there exists a chain
Ma .~VI2 ~ Ml
G.Every
2-maximal sub- group of isdualpronormal
in so,by
theorem1, normal,
itfollows
Ml. Suppose ~1
and let g be an element of G - If isnilpotent,
thena contradiction. If is not
nilpotent,
then it is either maxi- mal in G and minimal nonnilpotent
as in theorem1,
or it is the whole group G.Suppose ~M3 ,
is maximal in G. ThenI’( ~.1~3 , .~3~ ) C M3,
this meansM3
=M" 3)
’aM39)
=M1,
acontradiction.
Finally
supposeM3~ =
G and so.~’(G) ~13.
Let M be a maximal
subgroup
of G such that M -c::3 G. M is not nil-potent
so it is minimal nonnilpotent
as in theorem 1. AlsoF(M)
.F(G) C M3
and(r, t primes),
a contra-diction.
The last contradiction proves the first
part
of the theorem. Theconverse is trivial.
In
[7] (Satz 3)
R. Schmidtproved
that the same is true for mo-dularity :
moreprecisely
he describes nonsupersoluble
groups in which every 3-maximalsubgroup
is modulardiscovering
that such86
groups are
exactly
groups in which every 3-maximal isnormal,
whilethis
equivalence
is not true for n =1,
2.Using
theprevious
theorem and Schmidt’s result we can imme-diately get
thefollowing
result.COROLLARY 1. Let G be a group in which every 3-maximal
subgroup
is
dualpronormal,
then oneof
thefollowing
holds :(a)
G issupersoluble;
(b) IGI
=p2q,
p and qprimes
or(c)
G is the semidirectproduct of
thequaternion
groupo f
order 8and the
cyclic
groupo f
order 3.Viceversa the groups in
b)
andc)
have even normal 3-maximalsubgroups.
We have seen that the groups in which every 3-maximal
subgroup
is
dualpronormal (normal)
are «almost all ~)supersoluble,
next theo-rem describes
supersoluble
such groups.THEOREM 3. Let G be a
supersoluble
group.I f
every 3-macximal sub- groupo f
G isdualpronormal
then oneof
thefollowing
holds :(a)
Gnilpotent
with normal 3-maximalsubgroups.
(b)
G minimal nonnilpotent, IGI
=pqo,
G.(e) IGI
=rpqP,
r ~ qprimes, GrGq
andG1)Gq
minimal nonnilpotent, Gi v Gi Gq , if fl
> 1Gq
are normal in G.(d) IGI = p2 q-6, Gq cyclic, ~(Gq) Z(G), i f ~
> 1 thesubgroups o f G 1)
are normal in G.(e) I G
= G and oneo f
thefollowing
holds:(i) Gq cyclic, [Gq : CGq(Gp)]
=q2;
i(ii) Gq
abelianof type (q, qfl), OOq(G1))
abeliano f type (q, qfJ-l);
(iii) a,
- bq=1,
ab =a1+qØ-l), 4,
minimal nonabelian, aq, b);
Conversely
the groups in(a), (b), (c), (d)
and(e)
have normal3-maximal
subgroups.
PROOF. Maximal
subgroups
of Gsatisfy
thehypothesis
of theo-rem
1,
sothey
arenilpotent
or minimal nonnilpotent
with the de- scribedstructure,
y moreover,by
theorem2,
every 3-maximal sub- group of G is normal in G. Let G be minimal nonnilpotent,
then#(G) (= unique N-injector
ofG)
is maximal in G. Let =p"q*,
Since
Gq
is not normal inG,
andSuppose G1) elementary
abelian. The whole group G issupersoluble
and minimal non
nilpotent,
soGq
centralizes asubgroup P
of order p ;by
Mascke’s theorem P has acomplement Q
inGq-invariant.
SinceG is minimal non
nilpotent Q,
andGp,
is centralizedby Gq,
a con-tradiction. Therefore
G1)
iscyclic
and G minimal nonabelian,
thismeans
(cfr. [4]
pag.285) IG1)1
= p.Suppose
G has a maximalsubgroup, say U,
which is notnilpo- tent,
this means U minimal nonnilpotent.
and[G: U]
= r, r aprime.
There are threepossibilities:
(i)
In this caseIGI
=rpq~,
IGq = Uq
iscyclic
and~(6~)y
which centralizesGr
and is contained inZ(G). Let ~ > 1
and H it results and
=
pq2, so G1)H
andGrH
are3-maximal, nilpotent and, by hypo- thesis,
y normalsubgroups
ofG,
it followsGp, Gra
G.(ii) r
= p. In this caseIGI
andUq
iscyclic.
Mo-reover,
being
p > q and[G: ~(Gq)] = p2q, Gp
andØ(Gq)
are normalin
G,
inparticular Z(G). If @
>1,
as in case(i),
one caneasily
prove that everysubgroup
ofG1)
is normal in G.(iii) r
= q. In this caseIGI
=and, being
p > q,G1)
isnormal in G. G is
supposed
to be notnilpotent, Gq
is a Carter sub- group ofG,
therefore if M is maximal in G andnilpotent,
y then itmust be normal. This means G has at most one
nilpotent
maximalsubgroup, apart
fromq-Sylow subgroups,
and it is theFitting
sub-group of
G;
since and =q~-’-,
it results[Gq: q2.
First it will beproved
thatGq
iscyclic
if andonly
if
[Gq : CGa(G1))]
=q2,
inparticular q2/(p _ 1).
IfGq
iscyclic
then=
Uq
does not centralize this means[G,:
-q2.
Viceversa let
[Gq : OGa(Gj))]
=q2
and let H be a maximalsubgroup
ofis not
nilpotent
and maximal in G so U and H iscyclic. Every
maximalsubgroup
ofGq
iscyclic
so eitherGq
iscyclic
or
Suppose Gq = Q8,
thenAut Gp
iscyclic,
thismeans maximal in
Gq,
a contradiction. Therefore letGq
benot
cyclic
and = q. is a maximalsubgroup
ofG
88
every other maximal
subgroup
ofGq,
I sayM,
does not centralizeG,
so and if is
cyclic.
There are twopossibilities:
(1) G,, abelian,
then it can beeasily
seen thatG,
must be oftype (q, qfl)
and oftype (q,
(2) G,
not abelian:Gq
has at leastq -f- 1 > 3
maximal sub-groups, so at least
two,
say if and Ncyclic:
it can beeasily
seen that~(Ga) _
if n N =Z(Gq),
thereforeGq
is minimal non abelian. Then(cfr. [4]
pag.309)
either(a)
or(b) a,
c =[a, b]),
which is not verifiedbecause,
=a,
and N =aq, b, c>
aredifferent maximal
subgroups
notcyclic,
or(c) Gq ,~, ~a~
= bqU=1 ~ ab - a~+qs-1>> ~ 27 1, IGql
=2,
thenaq, bq) s O(G,)
is notcyclic.
So p = 1 andGq a, bfa,qIJ
= bq=1,
ab =a1+qIJ-1). If 03B2
= 2 or 3 thenb>
orare 3-maximal in G and not
normal,
so it must 4. This grouphas q +
1 maximalsubgroups,
oneaq, b)
is notcyclic.
It will beproved
thatthe q cyclic subgroups ~a~, ab),
... , are maximal.Consider G’q
=([a, b]>G
= for every t E{1,
..., q -1}
a andbf
are
permutable
with[a, b-t],
it follows(abt)q
=aq[a, b-t]~=>.
Ifq # 2,
then so
[a, b-t](q2)=1. If q
=2,
then2
and, 4,
it is~c~~~l+2~-$y
=~ac2~.
Therefore =and is maximal in
Gq.
Second-maximalsubgroups
ofOq
coincidewith the maximal
subgroups
ofaq, b), namely they
areaq=, b), aq~, ~aqb~, ... ,
At the same way, 3-maximalsubgroups
are(aq’, b),
... , Thesesubgroups
are normal inG.
since
G’
= is contained in each ofthem,
and centralizeG~,
therefore
they
are normal in G.Using
this fact it is easy to see that every 3-maximalsubgroup
of G is normal in G.COROLLARY 2.
If
every 3-maximalsubgroup of
a group G is dual-pronormal,
then:(a) In(G)1 ~
3 ~ G issupersoluble.
(b) In(G) ‘ >
4 ~ G isnilpotent.
COROLLARY 3.
I f
everysubgroup o f
a group G is dual-pronormal,
then:(a) In(G)1 ~
n ~ G issupersoluble.
(b) In(G)1 >_
n-~-1
~ G isnilpotent.
PROOF.
(a) By
induction on n. If n =1, 2,
3 thecorollary
holds.Let n > 3 and U a maximal
subgroup
ofG, >
n - 1 and(n - 1 )-maximal subgroups
of U aredualpronormal
in U.By
induc-tion U is
supersoluble,
so either G issupersoluble
or minimal nonsupersoluble.
But if G is minimal nonsupersoluble
thenIn(G)1 ( 3,
a contradiction. Hence G is
supersoluble.
(b) By
induction on n. If n =1, 2,
3 thecorollary
holds. Letn > 3. As in
(a) get easily, by induction,
Gnilpotent
or minimal nonnilpotent,
but if G is minimal nonnilpotent
then2,
a con- tradiction. Hence G isnilpotent.
LEMMA. 2.
I f
U isdualpronormal,
in a group G and V is asubgroup of
Gcontaining
then V isdualpronormal,
in G. Inparticular No(U)
isdu,actpronormat
in G.PROOF.
By hypothesis
By [1 ]
prop. 2.2.F’( Y, Y~~ ) c V,
for every g in G. Thismeans V is
dualpronormal
in G.LEMMA 3..Let H be a
subgroup of F(G), i f
H isdualpronormal
in Gthen H is normal in G.
PROOF.
By [1]
prop. 2.2 Hr’11’(G)
= H is normal in G.THEOREM 4. Let G be a
metanilpotent
group. Thefollowing
state-ments are
equivalent:
(a) Every
n-maximalsubgroup
isdualpronormal.
(b) Every
n-maximalsubgroup
is normal.90
PROOF.
(a )
-~(b ) .
If every n-maximalsubgroup
isdualpronormal, then, by [1]
theoremB, they
arenilpotent (in fact, (n - 1)-maximal
subgroups
havedualpronormal
maximalsubgroups, hence, by
thetheorem, they
arenilpotent).
Use induction on n. If n =1,
2 or 3the theorem holds. Let n >
3,
and let .bt be n-maximal in G.By
de-finition,
g is(n - 1 )-maximal
in a maximalsubgroup .M~;
every(n -1 )-magimal subgroup
of M isdualpronormal
inM,
so,by
in-duction,
normal in .lVl. It followsSuppose
M.By
lemma 4 if isdualpronormal
inG,
this means,being
G metanil-potent
and M maximal inG,
if normal in G. So H is subnormal in GF(G). By
lemma 4 g is normal inG,
a contradiction. SoNG(H) = G
asrequired.
(b)
-(a).
Trivial.Probably
thisequivalence
isalways true,
but at the moment asthe
proof
as acounterexample
seem to be hard to find.REFERENCES
[1] A. D’ANIELLO - A. LEONE, Su alcune classi di
sottogruppi pronormali
duali, Boll. U.M.I., Sez. D, Serie VI, Vol. V-D, N. 1 (1986), pp. 135-144.[2] K. DOERK, Minimal nicht
überauflosbare
endlicheGruppen,
Math. Z.,91,
(1966), pp. 198-205.[3] B. FISCHER - W. GASCHUTZ - B. HARTLEY,
Injectoren
endlicherauflösbare Gruppen,
Math. Z., 102(1967),
pp. 337-339.[4] B. HUPPERT, Endliche
Gruppen -
I,Springer-Verlag.
[5] B. HUPPERT, Normalteiler und maximale
Untergruppen
endlicherGruppen,
Math. Z., 60 (1954), 409-434.
[6] A. MANN, Finite groups whose n-maximal
subgroups
are subnormal, Amer.Math. Soc., 132 (1968), pp. 395-405.
[7] R. SCHMIDT, Endliche
Gruppen
mit vielen modularenUntergruppen,
Abh.Math. Sem.
Hamburg,
34 (1969), pp. 115-125.Manoscritto