Compact Subgroups of GL
n(C).
JEANFRESNEL(*) - MARIUS VAN DERPUT(**)
1. Introduction.
LetGGLn(C) be a compact subgroup. Using the Haar measure onG one obtains a positive definite Hermitian form on Cn which is invariant under G. In other words, Gis conjugated, with respect to GLn(C), to a subgroup of the standard unitary groupUn(C). In particular, everyg2G is semisimple and all its eigenvalues have absolute value 1.
The inverse problem was posed by K. Millet and I. Kaplansky (see [Ba]):
Suppose that the subgroup GGLn(C) has the property that every g2G is semisimple and all its eigenvalues have absolute value1. Is G conjugated to a subgroup of Un(C)?
Forn1;2 the answer is positive. A counterexample forn3 is given in ([Ba], Counterexample 1.10, p. 19). However, using the techniques of Burnside, it is shown in ([Ba], Corollary 1.8, p. 18), thatGis isomorphic to a subgroup ofUn(C). The aim of this paper is to present a proof of the fol- lowing positive result.
THEOREM1.1. Suppose that the subgroup GGLn(C)satisfies:
(i) Every element of G is semisimple and all its eigenvalues have absolute value1.
(ii) G isclosedwith respect to the ordinary topology ofGLn(C).
Then G is conjugated inGLn(C)to a subgroup of Un(C)and therefore compact.
The theorem has an almost immediate consequence.
(*) Indirizzo dell'A.: Laboratoire de TheÂorie des nombres et Algorithmique arithmeÂtique, Universite Bordeaux I, 351 cours de la LibeÂration, 33405 Talence, France. E-mail: fresnel@math.u-bordeaux1.fr
(**) Indirizzo dell'A.: Department of Mathematics, University of Groningen, P.O.Box 800, 9700 AV Groningen, The Netherlands. E-mail: mvdput@math.rug.nl
COROLLARY 1.2. Let E be an n-dimensional affine euclidean space andGa closed subgroup of the group of all isometries ofE. Suppose that each element ofGhas a fixed point. Then the groupGis compact and has a fixed point.
PROOF. The action ofg2GonRnis given byX2Rn7!gXUXA with U2On(R); A2Rn. One associates to g2G the matrix M(g)
U A
0 1
2GLn1(R). All eigenvalues of M(g) have absolute value 1.
SinceUis semisimple,M(g) is semisimple if and only if there exists a vector X2Rnsuch thatM(g) X
1 X
1 . This property ofXis equivalent toX is a fixed point forg. It follows thatM(g) is semisimple if and only ifghas a fixed point. The theorem implies thatfM(g)jg2Ggis compact. ThenGis
compact and has a fixed point. p
2. A result on real Lie algebras.
PROPOSITION2.1. V is a complex vector space of dimensionn1. L et gbe arealLie subalgebra ofEndC(V)satisfying:
(a) i1V 62g
(b) If VV1V2 with V1;V2 complex vector spaces invariant underg, then V10or V20.
(c) Every element ofgis semisimple and all its eigenvalues are in iR.
Then the following holds:
(1) gis a real semisimple Lie algebra,G:CRgis a complex semisimple Lie algebra and the canonical mapG!EndC(V)is injective.
(2) Lethbe a Cartan subalgebra ofg. ThenH:Chis a Cartan subalgebra for the complex Lie algebra ofG. Let R be the set of roots for the pair(G;H). Then
(2a) a(h)2iRfor every h2handa2R,
(2b) for everya2R, the real Lie subalgebra ofg, generated by g\(GaG a)is isomorphic tosu2.
(3) There exists a positive definite Hermitian form F such that for all x;y2V and g2gone has F(gx;y)F(x;gy)0.
PROOF. (1). Suppose thatgis not semisimple. Thenghas a non zero solvable ideal. Leta60 be a minimal solvable ideal, then [a;a]0. Since the elements of aare semisimple and commute there is a decomposition V :CnV1 Vrand there are distinctR-linear mapslj :a!iR such that the action ofaonVis given by
a Xr
j1
vj X
lj(a)vj fora2aandvj 2Vj for allj:
Choose an elementa2asuch that, say,l1(a)iand thelj(a) are distinct.
Forg2gone writesb:[g;a]ga ag2a. Consider for a givenu2Vj
the expression g(u)P
k vk with all vk2Vk. Now lj(b)ub(u) (ga ag)(u)lj(a)P
k vk P
k lk(a)vk. This implies vk0 for k6j and lj(b)u0. Thus the spacesVjare invariant underg. Condition (b) implies r1. Thenai1V, which contradicts condition (a). One concludes thatg is semisimple.
According to [F-H],G:CRgis semisimple, too. An element ofG can uniquely be written as 1aibwitha;b2g. If the image of this element is 0 in EndC(V), thena ib. This impliesab0 sinceaandb have their eigenvalues iniRand are semisimple.
(2). The first statement of (2) is immediate. We recall (see [F-H]) that the Cartan decomposition (or root decomposition) GH(aGa) has the following properties: For any non zero linear mapa:H!Cone has
Ga: fg2Gj[h;g]a(h)gfor allh2Hg :
IfGa60 thenais called a root and in that casedimCGa1. Ifais a root, thencawithc2Cis a root if and only ifc 1.
Fix an element h2End(V). The eigenvalues of the linear map End(V)!End(V), defined byg7!ad(h)(g):[h;g], are the differences of the eigenvalues ofh. In particular forh2handa2Rone hasa(h)2iR.
This proves (2a).
One writes a1; a1;. . .;ar; ar for the roots. Any g2g has a unique decompositiongg0Pr
j1(gajg aj) withg02H; gaj 2Gaj.
Choose a generic elementh02h, i.e., the 2relementsaj(h0)2iR are distinct. Form1 one has
ad(h0)m(g)X
j
aj(h0)mgaj( aj(h0))mg aj 2g:
Using this relation for m2n; n1;. . .;r and observing that the aj(h0)22R; j1;. . .;rare distinct, one finds that allgaj g aj are ing.
Then alsog02g. Similarly, one finds that eachigaj ig aj 2g.
Now we study the real vector spaceTj:g\(GajG aj). As shown above, any element of Gaj is nilpotent. Since the elements of g are semisimple one has g\Gaj 0. In particular the two projections Tj!Gaj are injective. We conclude from this thatTj has a real basis of the form XajX aj;iXaj iX aj, where Xaj are non zero elements of Gaj.
The complex Lie algebra generated by Xaj is easily seen to be the complex Lie algebra sl2;C. One easily verifies that the real Lie algebra generated byXajX aj;iXaj iX ajis isomorphic tosu2. This proves (2b).
(3). One applies [F-H], Proposition 26.4. The condition (i) of that pro- position is (2a) and (2b). The equivalent condition (iii) states that the real Lie algebra associated to g is compact. This implies the existence of a positive definite Hermitian formFonV such thatF(gx;y)F(x;gy)0
holds for allx;y2V andg2g. p
3. Proof of the theorem.
The caseGconnected.
Putg: fA2Matrn(C)jexp (tA)2Gfor allt2Rg. According to ([M-
T], Proposition 3.4.2 and 3.4.2.1.),gis a real Lie subalgebra of Matrn(C) and moreoverGis generated byfexp (g)jg2gg. The elementsg2gare clearly semisimple and all their eigenvalues are iniR.
LetV:CnV1 Vrdenote a maximal decomposition into (non trivial) complex subspaces invariant under g. This decomposition is also invariant under the action ofG. It suffices to prove the theorem for the restriction ofGto eachVj. In other words we may suppose thatr1. Thus gsatisfies the conditions (b) and (c) of Proposition 2.1.
Ifi1V 2g, then one replacesgbyg: fg2g jTr(g)0g. The latter is again a real Lie algebra, satisfies (a)-(c) and moreoverggRi1V. The positive definite Hermitian form of part (3) of Propostion 2.1 has clearly the propertyF(gx;gy)F(x;y) for allg2Gandx;y2V.
The general case.
NowGis a closed subgroup of GLn(C) (for the ordinary topology) such that every element ofGis semisimple and such that all its eigenvalues have
absolute value 1. Let Go denote the component of the identity of G. Ac- cording to the previous case, the groupGois compact.
LEMMA 3.1. G=Go is a torsion group, i.e., all its elements have finite order.
PROOF. Letgbe an element of G. Choose a basise1;. . .;en of eigen- vectors ofg. The groupT, consisting of all elementst2GLn(C) such that tejcjej; jcjj 1 for allj, is compact. The topological closureHGLn(C) of the group generated bygis a closed subgroup ofTand therefore com- pact. The component of the identityHoofHhas finite index inH, sinceHis compact. Moreover,HoGo. It follows that the image ofg inG=Go has
finite order. p
The groupGois conjugated to a subgroup ofUn(C) and hence compact.
One considers the real vector space Herm consisting of the Hermitian forms F on V. The group G acts linearly on Herm b y (gF)(x;y):
:F(gx;gy). The real linear subspace HermGo consisting of the Go-in- variant Hermitian forms is not 0 and contains in fact a positive definite Hermitian form. The space HermGo is invariant under G, since Go is a normal subgroup of G. The action of G on HermGo induces a homo- morphismG!GL(HermGo) with kernelG and imageI. SinceGGo the groupIis a torsion group.Gleaves a positive definite Hermitian form invariant and is closed. ThereforeGis compact.
We will need the following classical result and refer to ([Fr], p. 209, or [C-R] p. 252, or [S]) for a proof.
LEMMA3.2 (Schur's theorem). Let H be a torsion subgroup ofGLn(F), for some field F. Then:
Any finitely generated subgroup J of H is finite. As a consequence, H is the filtered union of its finite subgroups.
We apply the lemma toI. LetJIbe a finite subgroup. Its preimage JGis compact and the subspaceHermJ of the the J-invariant ele- ments of Hermis not 0 and contains a positive definite Hermitian form.
For finite subgroups J1J2 of I one has HermJ1HermJ2. Since the spacesHermJhave finite dimension andIis the filtered union of its finite subgroups, there exists a finite subgroup J0 of I such that HermJ0
HermKfor every finite subgroupK I, containingJ0. This implies the existence of a positive definite Hermitian form invariant underG.
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Manoscritto pervenuto in redazione il 4 luglio 2005.