C OMPOSITIO M ATHEMATICA
S. K WAPIE ´ N
A. P ELCZY ´ NSKI
Some linear topological properties of the hardy spaces H
pCompositio Mathematica, tome 33, n
o3 (1976), p. 261-288
<http://www.numdam.org/item?id=CM_1976__33_3_261_0>
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261
SOME LINEAR TOPOLOGICAL PROPERTIES OF THE HARDY SPACES Hp
S.
Kwapien
and A.Pelczy0144ski
Noordhoff International Publishing Printed in the Netherlands
Abstract
The classical
Hardy
classes Hp(1 ~ p ~) regarded
as Banachspaces are
investigated.
It isproved: (1) Every
reflexivesubspace
of L’ isisomorphic
to asubspace
of H1.(2)
Acomplemented
reflexivesubspace
ofH
1 isisomorphic
to a Hilbert space.(3) Every
infinite dimensionalsubspace
ofH
1 which isisomorphic
to a Hilbert space contains an infinite dimensionalsubspace
which iscomplemented
in Hl. The last result is aquantitative generalization
of a result ofPaley
that a sequence of characters
satisfying
the Hadamardlacunary
condition spans in H1 acomplemented subspace
which isisomorphic
to a Hilbert space.
Introduction
The purpose of the-
present
paper is toinvestigate
some lineartopological
and metricproperties
of the Banach spacesHP,
1 ~ p 00consisting
ofanalytic
functions whoseboundary
values are p-absolutely integrable.
Thestudy
of Hp spaces seems to beinteresting
for a
couple
of instances:(1)
itrequires
a newtechnique
which combines classical facts onanalytic
functions with recentdeep
resultson
LI-spaces;
several classical results on theHardy
classes seem tohave natural
Banach-space interpretation. (2)
The spaces Hp and the Sobolev spaces are the most naturalexamples
of"Lp-scales"
essen-tially
different from the scale LP.*Research of the second named author was partially supported by NSF Grant MPS 74-07509-A-02.
Boas
[4]
has observedthat,
for 1 p 00, the Banach space Hp isisomorphic
to LP. The situation in the "limit case" of H 1 isquite
different. For instance H1 is not
isomorphic
to anycomplemented subspace
ofLB
moregenerally-to
anyL1-space (cf. [16],
Pro-position 6.1);
Hl is a dual of aseparable
Banach space(cf. [14])
while L’ is not embeddable in anyseparable,
dual cf.[23];
in contrast withL1, by
a result ofPaley (cf. [21], [31], [7]
p.104),
H’ has com-plemented
hilbertiansubspaces
hence it fails to have the Dunford- P ettisproperty.
On the other hand in Section 2 of the
present
paper we show that every reflexivesubspace
of L’ isisomorphic
to asubspace
of H1.Furthermore an
analogue
of theprofound
result of H. P. Rosenthal[27]
on the nature of anembedding
of a reflexive space in L’ is also true forH1.
Thisimplies
that acomplemented
reflexivesubspace
ofH is necessarily isomorphic
to a Hilbert space. In Section 3 westudy
hilbertian
(= isomorphic
to a Hilbertspace) subspaces
of Hl. Weshow that H1 contains
"very many" complemented
hilbertian sub- spaces.Precisely:
everysubspace
of H 1 which isisomorphic
to t 2contains an infinite dimensional
subspace
which iscomplemented
in Hl. This fact is aquantitative generalization
of a result ofPaley,
mentioned
above,
on the boundedness in H1 of theorthogonal projection
from H1 onto the closed linearsubspace generated by
alacunary
sequence of characters.Section 4 contains some open
problems
and some results on thebehaviour of the Banach-Mazur distance
d(HP, Lp)
as p ~ 1 and as p ~ ~.1. Preliminaries
Let 0 p ~
oo. By
LI(resp. LI)
we denote the space of21T-periodic complex-valued (resp. real-valued)
measurable functions on the real line which arep-absolutely integrable
withrespect
to theLebesgue
measure on
[0, 21r]
for 0 p 00, andessentially
bounded for p = 00.C203C0
stands for the space of all continuous21r-periodic complex-valued
functions. We admitThe n-th
character Xn
is definedby
Given
f E
L weput
If 0 p 00, then Hp is the closed linear
subspace
of Lp which isgenerated by
thenon-negative characters, {Xn : n ~ 0}.
We defineBy
A we denote the closed linearsubspace
of HOOgenerated by
thenon-negative
characters. Weput Hp0 = {f ~ Hp: (0) = 0}
andAo =
U
EA:f(O) = 01.
Let
f
E HP. We denoteby f
aunique analytic
function on the unitdisc
{z: Izi 1}
such thatfor almost all t.
For u E
LR
we defineX(u)
= v to be theunique
real203C0-periodic
function such that for
f
= u + iv there exists anf analytic
on the unitdisc
satisfying (1.1)
and such thatf (0)
=203C0-1 f203C00 u(t)dt.
Recall(cf.
[33], Chap.
VII andChap. XII).
PROPOSITION 1.1:
(i)
X is a linear operatorof
weak type(1, 1).
(ii)
For every p E(0, 1)
there exists a constant pp such that(iii)
For every p E(1, ~)
there exists a constant 03C1p ~ C max(p, pl(p - 1)),
where C is an absolute constant, such thatNext,
forf
ELI,
we defineB(f)
to be theunique
function in~0p1 HP
such thatClearly B
is a one to oneoperator
andif g
=B(f),
thenCombining Proposition
1.1 with the above formulae weget (cf.
Boas
[4]).
PROPOSITION 1.2:
(i)
B is a linear operatorof
weak type(1, 1) from
L1 into~0p1
H,(ii)
For every p E(0, 1)
there exists a constant03B2p
such that(iii)
For every p C(1, ~)
B mapsisomorphically
L’ ontoHp ;
there exists a constant03B2p ~ 2pp
+ 3 such thatA relative of B is the
orthogonal projection 9-
definedby
where
g03C0 (t)
=g (t
+03C0). Clearly, by Proposition 1.2, 2(L1)
c~0p1Hp and,
for 1 p-, 9, regarded
as an operator from Lp is aprojection
onto Hp with
I/221/p
~JIB Ilp.
In fact we have2. Reflexive
subspaces
of H1PROPOSITION 2.1: A
reflexive
Banach space isisomorphic
to asubspace of Hl if (and only if)
it isisomorphic
to asubspace of
LI.PROOF:
By
a result of Rosenthal(cf. [27])
every reflexivesubspace
of
L1
isisomorphic
to a reflexivesubspace
of Lr for some r with1 r ::; 2. Therefore it is
enough
to provethat,
for every r with 1r~2,
the space Lr isisomorphic
to asubspace
ofHl.
It is wellknown
(cf.
e.g.[27],
p.354) that,
forr ~ [1, 2],
there exists in~0pr
L’ asubspace Er which,
for every fixed p E(0, r), regarded
asa
subspace
of LP isisometrically isomorphic
to Lr. Moreover(if
r >
1),
for every pand
P2 with 1 ~ p P2 r, there exists a constant03B3p1,p2 such that
Now fix p 1 and p, with
1 p1 p2 r. By Proposition 1.2(iii),
theoperator
B embedsisomorphically Er regarded
as asubspace
of Lplinto HP-.
Clearly
we have the set theoretical inclusion Hp1~H1.
Thus it suffices to prove that the norm~·~1
and~·~p1
areequivalent
onB(Er).
By (1.2)
and(2.1),
for everyg E B(Er)
we haveIlgllp2::; kllgilpi
wherek = 03B3p1,p2 ·
203B2p1. Letting s
=(pl - 1)(p2- 1)-1,
in view of thelogarithmic convexity
of the function p -~g~pp,
we havewhence
This
completes
theproof.
REMARK:
Using
thetechnique
of[15] (cf.
also[19])
instead of thelogarithmic convexity
of the functionp ~ ~·~pp
one can show that onB(Er)
all the norms~·~p
areequivalent
for 0 p r(in
factequivalent
to the
topology
of convergence inmeasure).
Hence if0 p ~ 1,
then Hp containsisomorphically
every reflexivesubspace
of L’. We donot know any
satisfactory description
of all Banachsubspaces
of H’for
0 p 1.
Our next result
provides
more information onisomorphic
em-beddings
of reflexive spaces into H’. It is acomplete analogue
ofRosenthal’s Theorem on reflexive
subspaces
ofL’ (cf. [27]).
PROPOSITION 2.2: Let X be a
reflexive subspace of
Hl. Then thereexists a p > 1 such that
for
every r with p > r > 1 the natural em-bedding j : X ~ H1 factors through Hr,
i.e. there are bounded linear operators U : X ~ Hr and V : Hr ~ Hl with VU =j.
Moreover U and V can be chosen to be operatorsof multiplication by analytic func-
tions.
PROOF:
By
a result of Rosenthal([27],
Theorem 5 and Theorem9),
there exists a p > 1 such that for every r with p > r > 1 there exist a
K > 0 and a
non-negative
function ç with1/203C0 ~203C00
’P(t)dt
= 1 suchthat
(In
this formula we admit0/0
=0).
Let usset Ji
= max(ç, 1).
Let g be the outer function definedby
and let
Then
(cf. [7], Chap. 2) g ~ Hr/(r-1), |g(t)|
=03C8(t)(r-1)/r
for t a.e.,|(z)| ~
1 forIzl
1 andg-’F-
H=.Let us set
U (x )
=x/g
for x E X andV(f)
= g -f
forf
E H r. Since~g~r/(r-1)
~2(r-1)/r,
V maps Hr intoH1 and Il VII
~2(r-1)/r. Finally,
for everyx
G X,
we haveThus
U (x) ~ Lr.
ThereforeU (x ) E H
r becauseU (x) ~ H1 being
aproduct
of an x EH’ by g-1 E
Hoo.COROLLARY 2.1: A
complemented reflexive subspace of Hl
isisomorphic
to a Hilbert space.PROOF: Let X be a
complemented
reflexivesubspace
ofH1. Then, by Proposition 2.2,
there exists a p > 1 such that for every r with p > r > 1 there are bounded linearoperators
U and V such that thefollowing diagram
is commutativewhere j : X ~ H
1 is the natural inclusion andP : H1 ~ X
is aprojection. Thus,
for every r E(1, p), P j
= theidentity operator
on X admits a factorizationthrough
Hr. Therefore X isisomorphic
to acomplemented subspace
of Lrbecause, by Proposition 1.2(iii),
Hr isisomorphic
to Lr. Since this holds for at least two different r E(1, p),
we infer that X is
isomorphic
to a Hilbert space(cf. [16]
and[18]).
REMARKS:
(1)
Thefollowing
result has beenkindly
communicated to usby
JoelShapiro.
If 0 p 1 and if a Banach
space X
isisomorphic
to acomple-
mented
subspace
ofHp,
then either X isisomorphic to ~1
or X isfinite dimensional.
The
proof (due
to J.Shapiro)
uses the result ofDuren, Romberg
and Shields
[8],
sections 2 and 3:(D.R.S)
theadjoint
of the naturalembedding g ~
of Hp into the space BP is anisomorphism
betweenconjugate
spaces. Here BP denotes the Banach space ofholomorphic
functions on the open unit disc with the normIt follows from
(D.R.S)
that acomplemented
Banachsubspace
of Hp(0
p1)
isisomorphic
to acomplemented subspace
of Bp. Nextusing technique
similar to that of[17],
Theorem 6.2(cf.
also[31])
onecan show that BP is
isomorphic
to ~1. Now the desired conclusion follows from[22],
Theorem 1.Problem
(J. Shapiro).
Does Hp(0 p 1) actually
contain a com-plemented subspace isomorphic
to ~1?(2) Slightly modifying
theproof
ofProposition
2.2 one can showthe
following
PROPOSITION 2.2a: Let 1 ~ po 2. Let X be a
subspace of
HP- whichdoes not contain any
subspace isomorphic
to tl-. Then there exists ap E
(po, 2)
suchthat, for
every r with po r p there exists an outer g EHp0r(r-p0)-1
withg ~
0 suchthat j
= VU where U : X - Hr and V : Hr ~ Hp0 are operatorsof multiplication by l/g
and grespectively and j : X ~ Hp0
denotes the natural inclusion.The
proof
imitates theproof
ofProposition 2.2;
instead of Rosen- thal’s result we use itsgeneralization
due toMaurey (cf. [19],
Théorème8 and
Proposition 97).
Our next result is in fact a
quantitative
version ofProposition
2.2afor hilbertian
subspaces.
PROPOSITION 2.3: Let K ~ 1 and let 1 s p ~ 2. Let X be a
subspace of HP
and letT : ~2 ~
X be anisomorphism
with~T~ ~T-1~ ~
K.Then there exists an outer cp
E Hl
such thatwhere y is an absolute constant, in
fact
03B3 ~4/Y;.
PROOF: A result of
Maurey ([19]
Théorème8, 50a,
cf. also[20]), applied
for theidentity
inclusionX ~ Lp, yields
the existence of ag e Lr where
1/r
=1/p - 1/2
such thatIlglir
= 1 andwhere C is the smallest constant such that
for every finite sequence
(f;)
in X. A standardapplication
of theintegration against
theindependent
standardcomplex
Gaussian vari- ablesei gives
where kp
=(1/03C0 ~+~-~ ~+~-~ (x2
+y2)p/2e-(x2+y2)dxdy)1/p. Since kp ~ k1
=V77/2,
one canreplace
C in(2.5)
and in(2.6) by KIkI
=2K/Vn-.
Now, by [14],
p.53,
there exists an outer function ~ EH satisfying (2.2), (2.3)
and such thatfor almo st all t
It can be
easily
checked that(2.7)
and(2.5) imply (2.4)
with y =2/k,.
Our last result in this section
gives
some information on reflexivesubspaces
of thequotient L1/H10.
PROPOSITION 2.4: Let X be a
reflexive subspace of
LI such that(k)
= 0for
k >0, f
E X. Then the sum X +Hô
isclosed, equivalently
the restriction
of
thequotient
map L1 ~L’lHo’
to X is anisomorphic embedding.
PROOF :
Let 9 (f)
=f - 2(f)
f orf
E L 1 where 21 is theprojection
defined, by (1.3).
It follows fromProposition 1.2(ii)
that there exists aconstant a > 0 such that
On the other hand if X is a reflexive
subspace
ofL’,
then X containsno
subspace isomorphic
to~1.
Hence(cf. [15], [19])
the normtopology
in X coincides with the
topology
of convergence in measure, inparticular
for every sequence Thus there exists a constant
bx
= b > 0 such thatNow fix
f E X
andg E Hô.
Then9P(g)
=0,
and9P(f)
=f
because(k)
= 0 for k > 0. HenceThus the sum X
+ Hô
is closed.REMARK:
Proposition
2.4yields,
inparticular,
thefollowing
"clas-sical" result.
If
(nk)
is a sequence ofnegative integers
such that the spaceis
isomorphic
to(2 (in particular
if lim(nk+llnk)
>1)
then the space~ + H1
is closed orequivalently
in the "duallanguage"
theoperator A ~ ~2
definedby f ~ ((- nk))
is asurjection.
3. Hilbertian
subspaces
of H’The existence of infinite-dimensional
complemented
hilbertiansubspaces
of H1 follows from the classical result of R.E.A.C.Paley (cf. [21], [29], [7]
p.104, [33], Chap. XII,
Theorem7.8)
whichyields (P).
If lim(nk+1/nk) > 1,
then the closed linearsubspace
of H1spanned by
the sequence of characters(~nk)1~k~
isisomorphic
to e2 andcomplemented
in Hl.On the other hand there are
subspaces
ofH1 spanned by
sequences of characters which areisomorphic
to t2 butuncomplemented
in H 1(cf.
Rudin[30]
and Rosenthal[26]).
In this section we shall show
that,
infact, H contains "very many"
complemented
and"very many" uncomplemented
hilbertian sub-spaces not
necessarily
translation invariant. The situation is similar to that in LI(and
thereforeHI, by Proposition 1.2(iii))
for 1 p 2(cf.
[25],
Theorem3.1)
but not inL’
which contains nocomplemented
infinite-dimensional hilbertiansubspaces ([13], [22]).
If
(xn)
is a sequence of elements of a Banachspace X
then[xn]
denotes the closed linear
subspace
of Xgenerated by
thexn’s.
Let 1 ~ K 00. Recall that a sequence
(xn)
of elements of a Banach space is said to beK-equivalent
to the unit vector basisof provided
there existpositive
constants a and b with ab = K such thatfor every finite sequence of scalars
(tn).
Now we are
ready
to state the main result of thepresent
section THEOREM 3.1: Let 1 ~ K ~. Let(fn)1~n~
be a sequence in Hl which isK-equivalent
to the unit vector basisof (2. Then, for
everyE >
0,
there exists aninfinite subsequence (nk)
such that the closed linearsubspace [fnk] spanned by
the sequence(fnk)
iscomplemented
in H’.Moreover,
there exists aprojection
Pfrom
Hl onto[fnk]
withJIP Il
4K + E.The
proof
of Theorem 3.1 followsimmediately
fromPropositions 3.1,
3.2 and 3.3given
below. Webegin
with thefollowing general
criterion
PROPOSITION 3.1: Let X be a Banach space with
separable
con-jugate
X*. Assume that there exists a constant c = cx such that everyweakly
convergent to zero sequence(ym)
in X contains aninfinite subsequence (ymk)
such thatfor
everyfinite
sequenceof
scalars(tk). Then, for
every K ~ 1 andfor
every E >
0,
every sequence(x*n)
in X* which isK-equivalent
to theunit vector basis
of (2
contains aninfinite subsequence (x*nk)
such thatthe closed linear
subspace [x *nk]
admits aprojection
P : X*
~ [x*nk]
onto withIIP Il
2Kc + E.PROOF : Define V :
~2 ~
X*by V((tn)) = 03A3n tnx*n
for(tn)
Ee2. Clearly
V is an
isomorphic embedding
with~V~ ~V-1~ ~ K (V-1
acts fromV(~2)
onto~2).
Sincee2
isreflexive,
V is weak-star continuous.Hence there exists an
operator U : X ~ ~2
whoseadjoint
is V. It iseasy to check that the
operator
U is definedby U(x) = (x*n(x))1~n~
for x E X. Since
~U*((tn))~ = ~V((tn))~ ~ ~V-1~-1(03A3n|tn|2)1/2
for every(tn)
E~2,
theoperator
U is asurjection
suchthat,
for every r >Il V-’ll,
the set
U((x
E X :~x~ ~ rl)
contains the unit ball of ~2(cf. [32] Chap.
VII, §5).
Hence there exists a sequence(xs)
in X such that sup~xs~ ~
rand
( U(xs ))
is the unit vector basis of~2, equivalently x*n(xs)
= Sn forn, s = 1, 2,....
Since X* isseparable
and sup~xs~ ~
r, there exists an infinitesubsequence (xsq)
which is a weakCauchy
sequence. Let usset Y- = xs2m -’xs2m-l for
m = 1, 2,.... Clearly
the sequence(ym)
tendsweakly
to zero. Thus the conditionimposed
on Xyields
the existence of an infinitesubsequence (ymk) satisfying (3.1).
Let us set nk = S2mk fork = 1, 2,...
andput
Clearly
we haveThus, by (3.1),
Thus P is a linear
operator
withIIP ~ ~ 2cr ~ VII (because
sup ~ymk~ ~ 2 sup ~xs~ ~ 2r). Letting r ~V-1~ + ~(2c~V~)-1,
weget
~P~ 2K + ~.
SinceP(x*) ~ [x*nk]
for every x* E X* and sinceP(x*nk) = x*nk
fork = 1, 2,...,
we infer that P is the desired pro-jection.
REMARK: The assertion of
Proposition
3.1 remains valid if wereplace
theassumption
ofseparability
of X*by
the weaker assump- tion that X does not containsubspace isomorphic
to ~1. To extract aweak
Cauchy subsequence
from the sequence(xs)
weapply
the resultof Rosenthal
[28].
To
apply Proposition
3.1 we need adescription
of apredual
ofH 1.
Our next
proposition
is known. Itspart (ii)
is aparticular
case of theCaratheodory-Fejer Theorem,
cf.[1].
PROPOSITION 3.2:
(i)
Theconjugate
spaceof
thequotient C27TIAo
isisometrically isomorphic
toHl.
(ii)
The spaceC27TIAo
isisometrically isomorphic
to asubspace of
the space
of
compactoperators
on a Hilbert space.PROOF:
(i)
The desired isometricisomorphism assigns
to eachf
EH the
linear functionalx*f
definedby
for the coset
The fact that this map is onto
(C2,IA,,,)*
follows from the F. and M.Riesz Theorem. For details cf.
[14],
p.137,
the second Theorem.(ii)
To eachcoset {f+A0}
weassign
the linearoperator Tf : H2 ~ H2
defined
by
Clearly
the definition ofTf
isindependent
of the choice of a re-presentative
in the coset{f + A0}. Moreover,
for everyf,
E{f + A0},
we have
Thus
~Tf~ ~
inf{~f1~~: f,
Elf
+A0}} = Iltf
+Aolll.
Conversely,
it follows frompart (i)
and the Hahn Banach Theorem that there exists a ç E H withIl’P III
= 1 such that1/203C0 ~203C0 f(t)~ (t )dt
=~{f + A0}~. By
the factorization theorem(cf. [14],
p.67),
wepick functions g
andhl
inH2
withghl
= ç andIIgll2
=~h1~2
= 1(cf. [14],
p.71),
and we defineh E H2 by h(t) = hl(- t).
Then(Tf(g), h) =
~{f + A0~ = ~{f + A0}~~g~2~h~2.
Hence~Tf~ litf
+A0}~.
This shows that the map{f + A0} ~ Tf
is anisometrically isomorphic embedding
ofC203C0/A0
into the space of boundedoperators
onH2. Finally
observethat each
operator Tf
iscompact
because the cosets{{~-n
+A0}: n
=0, 1, 2,...}
arelinearly
dense inC2jr/Ao (by
theFejer Theorem)
andTx-n
=03A3nj=0 (., Xj)Xn -j
is an(n
+1)-dimensional operator (n
=0, 1, ...).
This
completes
theproof.
To
complete
theproof
of Theorem 3.1 it isenough
to show that the spaceK(h)
of thecompact operators
on an infinite-dimensional Hilbertspace h (and
therefore everysubspace
ofK(h))
satisfies theassumption
ofProposition
3.1.Precisely
we havePROPOSITION 3.3: Let h be an
infinite-dimensional
Hilbert space.Let
(Tm)
be aweakly
convergent to zero sequence inK(h). Then, for
every E >
0,
there exists aninfinite subsequence (mk)
such thatfor
everyfinite
sequenceof
scalars(tk).
PROOF: The
assumption
that the sequence(Tm)
convergesweakly
to zero in
K(h)
meansHere
(·,·)
denotes the innerproduct
in h. Let(e03B1)03B1~H
be an or-thonormal basis for h. Since each
Tm
iscompact,
the ranges ofTm
and itsadjoint Tm
areseparable.
Hence there exists a countable set9to
such
that Tm(x), e03B1> = T*m(x), e03B1>
= 0 for every m =1, 2, ...
for everyx ~ h and for every a E
H/H0. Let j~ 03B1(j)
be an enumeration of the elements of9to.
Let furthermore Pn denote theorthogonal projection
onto the n-dimensional
subspace generated by
the elements e03B1(1), ea(2), ..., ea(n). Since dimPn (h)
= n, it follows from(3.2)
thatNext the
compactness
of eachTm
and the definition of the setH0 yield
Let E > 0 be
given. Assuming
that supmIITml1
> 0 we fix apositive
sequence
(Ek)
with(03A3~k=1 4~2k) ~ ~
sup-Il T,. il.
Nowusing (3.3)
and(3.4)
we define
inductively increasing
sequences of indices(mk)k~1
and(nk)kao
withm1 = 1
and no = 0 so that(admitting Po
=0)
Let us
put,
fork = 1, 2,...,
Clearly (3.5)
and(3.6) yield
Let
(tk)
be a fixed finite sequence of scalars. Since theprojections Pnk - Pnk-1 (k = 1, 2,...)
areorthogonal
andmutually disjoint,
forevery x E
h,
we haveHence
Similarly
Thus
This
completes
theproof
ofProposition
3.3 and therefore of Theorem 3.1.REMARKS:
(1)
Let us sketch aproof
ofPaley’s
result(P )
whichuses the
technique
of theproof
of Theorem 3.1.Assume first that
(mk)
is a sequence ofpositive integers
such thatLet
Tm
=Tx-m
for m =0, 1,...
be thecompact operator
onH2
which is theimage
of the coset{~-m + A0} by
theisometry C203C0/A0 ~ K(H2)
defined in theproof
ofProposition 3.2(ii).
Then(TmXh Xk)
= 0for j
+ k ~ mand (T-Xi, ~k>
= 1for j
+ k = m. LetPm : H2 ~
span(~0, ~1, ..., Xm-1)
be theorthogonal projection.
It follows from(3.7)
that
Pmk-ITm,l’mk-1
= 0 andTmk
=PmkTm,l’mk
for k =1, 2,... (i.e.
thesequences
(Pnk)
and(Tmk) satisfy (3.5)
and(3.6) with nk
= mk andEk = 0 for all
k).
Thus the argument used in theproof
ofProposition
3.3 yields
for every finite sequence of scalars
(tk). Obviously (1 tkTmk)(03A3 tk~mk) = 03A3k Itkl2.
HenceThus the
subspace [ Tmk]
isisomorphic
to~2.
MoreoverQ
definedby Q(S) = 03A3k S(x0), Xmk)Tmk
for S EK(H2)
is aprojection
onto[Tmk]
with
~Q~ ~ 2.
Let usregard Q
as an operator from[Tm] (= the
isometric
image
ofC203C0/A0)
into itself and let P be theadjoint
ofQ.
Then, by Proposition 3.1(ii),
P can beregarded
as anoperator
fromH into
itself.Obviously IIP ~
=~Q~ ~
2. A directcomputation
showsthat P is the
orthogonal projection
of H’ onto[~mk].
Tocomplete
theproof
of(P )
in thegeneral
case observe that everylacunary
sequence admits adecomposition
into a finite number of sequencessatisfying (3.7).
(2)
A similarargument gives
also thefollowing
relative result.Let
(fn)
be a sequence inH1.
Assume that + 00 > supn~fn~~ ~
infn ~fn~1
> 0 andThen there exists an infinite
subsequence (nk)
and a 1 ~ K 00 suchthat the sequence
(fnk)
isK-equivalent
to the unit vector basis of t2 and theorthogonal projection
from H’ onto[fnk]
is a boundedoperator.
Our next aim is to
give
aquantitative generalization
of Theorem 3.1 to the case of HP spaces(1
p ~2).
THEOREM 3.2: Let
1 p ~ 2
and let K ~ 1. Then there exists anabsolute constant c
(independent of
K andp)
such thatif (fn)
is asequence in HP which is
K-equivalent
to the unit vector basisof t2,
then there exists a
subsequence (nk)
such that there exists aprojection
P
from
HP onto[fnk]-the
closed linear spanof (fnk)
withIIP ~ ~ cK2.
PROOF: Let X
= [fn]. By
theassumption,
there exists an isomor-phism T : ~2 ~ X
with~T~~T-1~ ~ K. Hence, by Proposition 2.3,
there exists acp E H
1 which satisfies an outer(2.2), (2.3), (2.4).
Let us set
~f~~,q = (1/(203C0) ~203C00 |f(t)|q |~(t)|dt)1/q
forf
measurable and for1 S q
00. It follows from(2.2)
that there exists in the open unit disc aholomorphic function,
sayg,
suchthat
= epg. Let us setSince
0 ~~ ~ H1,
the limit exists for almost all t and’P l/p
=1/~-1/p~Hp.
Furthermore observe that(2.4)
isequivalent
towhere y is the absolute constant
appearing
inProposition
2.2. On the otherhand, by
thelogarithmic convexity
of the functionq ~ ~f~-1/p~qq,
we get
Thus
Now,
letH1~
denote the Banach spacebeing
thecompletion
of thetrigonometric polynomials 03A3n~0
CnXn in the norm~·~1,~.
Iteasily
followsfrom
(2.2)
and(2.3)
thatHq
isisometrically isomorphic
to H’. Thedesired
isometry
is definedby f - fç
forf ~ H1~.
Next(3.9)
and the obvious relationimply
that the sequence(fn’P -l/P) belongs
toH1~
and inH1~
isK(2p-2)/(2-p)+103B3(2p-2)/(2-p)-equivalent
to the unit vector basis of ~2.Hence, by
Theorem 3.1 which weapply
toH1~2013the
isometricimage
of
H1,
there exists asubsequence (nk)
and aprojection
Let us set
To see that P is well defined observe first that if
f
EHP, then, by
theHôlder
inequality
andby (2.3),
Thus, by (3.9),
for everyf ~ Hp,
we haveThus P is bounded.
Obviously P(Hp)
ex andPif)
=f
forf
E[fnk].
Hence P is a
projection. Now, f or p ~ 6 5
weget (remembering
that 03B3 ~ 1 and K ~1)
If p
> 6 5,
then aninspection
of theproof
ofProposition
2.1 showsthat there exists an
isomorphism
T from LP onto asubspace
of H1with
~T~~T-1~ ~ k
= 03B311/10,6/5.2f311!10 (we put
in(2.1)
and further p2= 6 5, p1 = 11 10). Thus, by
Theorem3.1,
we infer that every sequence in LP(p > 6 5) (particularly
inH’)
which isK-equivalent
to the unit vectorbasis
of t2
contains an infinitesubsequence
whose closed linear span is the range of aprojection
from Lp of norm ~ 5k - K. Thiscompletes
the
proof.
COROLLARY 3.1: There exists an absolute constant c ~ 1 such
that, for
1
::; p ::s; 2,
everyinfinite-dimensional
hilbertiansubspace of HP
containsan
infinite
dimensionalsubspace
which is the rangeof
aprojection from
Hp
of norm ~
c and which is a rangeof
anisomorphism from ~2,
sayT,
with~ T~ ~T-1~ ~
c.PROOF: Combine Theorems 3.1 and 3.2 with the recent result of Dacunha-Castelle and Krivine
[5]
fromwhich,
inparticular,
followsthat every infinite-dimensional hilbertian
subspace
of LPcontains,
forevery E >
0,
asubspace
which is(1
+~)2013isomorphic
to (2.Since the
argument
of Dacunha-Castelle and Krivine isquite involved,
to make the paper self contained we include aproof
of aslightly
weakerProposition
3.4(which
suffices for theproof
ofCorollary 3.1).
This result and the argument below is due to H. P.Rosenthall
and ispublished
here with hispermission.
PROPOSITION 3.4: There exists an absolute constant c such that every
infinite-dimensional
hilbertiansubspace
Xof
Lp(1 ~ p ~ 2)
contains an
infinite
dimensionalsubspace
E such that there exists anisomorphism
T :~2 ~
onto E with~T~~T-1~ ~
c.PROOF: Since LP is
isometrically isomorphic
to asubspace
of L’(1
p ~2),
it isenough
to consider the case p = 1. For X C L and X lIt was presented at the Functional Analysis Seminar in Warsaw in October 1973.isomorphic to (2
weput
’
isomorphisml
positive isometry
Recall
that,
for thecomplex LB
if Z C L and Z isisomorphic
to(2,
then
(This
is a result of Grothendieck[12],
cf. also Rosenthal[27].
It can beeasily
deduced from a result ofMaurey [20],
cf. theproof
of ourProposition 2.3). Clearly
Now fix X
isomorphic
tot2
andpick
Y C X with dimXI Y
00 so thatI2( Y) 2Í2(X). Replacing,
if necessary Xby T(X)
for an ap-propriate positive isometry
T(depending only
on Y but not onsubspaces
of Y of finitecodimension),
one may assume without loss ofgenerality
thatWe claim that
(3.11) implies
(3.12)
for every Z C Y with dimY/Z
00 there exists a y E Z suchthat A
Hence, by (3.10),
Hence m
4/V7r
and this proves(3.12).
Let
(h;)
denote the Haar orthonormal basis. It follows from(3.12)
that one can define
inductively
a sequence(yn)
in Y sothat,
for all n,By
a result of[2], passing again
to asubsequence (if necessary)
we may also assume that(yn)
isequivalent
to a block basic sequence withrespect
to the Haar basis
regarded
as a basis inL3!2.
Nowusing
the Orliczinequality (cf.
e.g.[25],
p.283),
forarbitrary
finite sequence of scalars(tn)
weget
where a is an absolute constant
depending only
on the unconditional constant of the Haar basis inL3/2
and the constant in the Orliczinequality
forL3/2. Thus,
for everyf
E span(yn),
Hence
by
thelogarithmic convexity
of the functionr ~ ~f~rr
Thus the same
inequality
holds forf ~ [yn].
Therefore[yn]
is asubspace
of X withd([yn], ~2) ~ (4/(a03C0))3.
Thiscompletes
theproof.
It is
interesting
to compareCorollary
2.1 with thefollowing
fact
PROPOSITION 3.5: Let
1 ~ p 2, let
Y be a hilbertiansubspace of
HI. Then there exists a non
complemented
hilbertiansubspace
Xof
Hl 1 which contains Y.
PROOF: Observe first that there exists a non
complemented
hil- bertiansubspace
of Hp(1 ~ p 2).
This follows fromProposition 1.2(iii)
and from thecorresponding
fact for LI(1
p2) (If
1p ~ 4 3
then, by
an observation of Rosenthal[26],
p.52,
a result of Rudin[30]
yields
the existence of anon-complemented
hilbertiansubspace.
If4 3
p2,
then the same fact for L’ was veryrecently
observedby
several mathematicians(cf. Bennet, Dor, Goodman,
Johnson andNewman
[9]), finally H contains
anuncomplemented
hilbertian sub- spacebecause, by Proposition 2.1, H1
contains H’isomorphically
for2 > p > 1.
Now
Proposition
3.5 is an immediate consequence of thefollowing general
factPROPOSITION 3.6:
If a
Banach space Z contains a non com-plemented
hilbertiansubspace,
sayE,
then every hilbertiansubspace of
Z is contained in a noncomplemented
hilbertiansubspace.
PROOF: Let Y be a hilbertian
subspace
of Z. If Y is finitedimensional,
then the desiredsubspace
is Y + E. If Y isuncomple-
mented then there is
nothing
to prove. In thesequel
suppose that Y is infinite dimensional and that there exists aprojection
P : Z ~ Y.Let El denote any
subspace
of E with dimE/E1
00. LetPE,
denotethe restriction of P to El. If
PE,
were anisomorphic embedding,
thenthe formula
,SQP
would define aprojection
from Z onto El whereQ
is a
projection
from a hilbertiansubspace
Y onto its closedsubspace PE1(E1)
andS : PE1(E1) ~ E12013the
inverse ofPE,.
Since E is uncom-plemented
inZ,
so is El. Hence the restriction of P to nosubspace
ofE of finite codimension is an
isomorphism. Combining
this fact with the standardgliding hump procedure
and the blockhomogeneity
ofthe unit vector basis in t2
(cf. [2])
we define a sequence(en )
in E which isequivalent
to the unit vector basis of lC2 and satisfies the conditionIIP (en)~ 2-n Ilenlifor
n =1, 2, ....
Thisimplies that,
for some no, theperturbed
sequence(en - P (en))n>n0
isequivalent
to the unitvector basis of
~2;
hence the spaceF = [en - P (en)] ~ ker P
is hil- bertian. If F is notcomplemented
inZ,
then the desiredsubspace
isF + Y. If F is
complemented
in Z and therefore in kerP,
then the standarddecomposition
method(cf. [22]) yields
that ker P isisomorphic
to Z. Thus ker P contains a noncomplemented
hilbertiansubspace,
say Fi. The desiredsubspace
can be defined now asFI
+ Y.A modification of the above
argument gives
PROPOSITION 3.7: Let Z be a
separable
Banach space such that(i)
there exists a non
complemented
hilbertiansubspace of Z, (ii)
everyinfinite
dimensional hilbertiansubspace of
Z contains aninfinite
dimensional
subspace
which iscomplemented
in Z. Then(*) given infinite
dimensionalcomplemented
hilbertiansubspaces of Z,
sayY,
andY2,
there exists anisomorphism of
Z ontoitself
whichcarries YI onto Y2.
In
particular
H’satisfies (*) for
1 ~ p 2.PROOF: Let
Pj
be aprojection
from Z ontoY; (j
=1, 2). Using (i)
we construct
similarly
as in theproof
ofProposition
3.6subspaces Fi
of ker
Pj
which areisomorphic
toe2 . By (ii)
we may assume without loss ofgenerality that Fi
arecomplemented
in Z and therefore in kerPj (j
=1, 2).
Now thedecomposition technique gives
that kerPj
isisomorphic
to Zfor j
=1,
2. This allows to construct anisomorphism
of Z onto itself which carries ker P 1 onto
ker P2
andP1(Z)
ontoP2(Z).
4. Remarks and open
problems
We
begin
this section with a discussion of the behavior of the Banach Mazur distancesd(Lp, Hp), d(Lp, Lp/Hp0), d(Hp, Lp/Hp0)
forp ~ ~ and for p - 1.
Recall that if X and Y are
isomorphic
Banach spaces, thend (X, Y)
= inf111 TII ~ T-1~:
T : X ~Y,
T -isomorphism};
if X and Yare not
isomorphic,
thend (X, Y) =
00. Letp *
=p (p - l)-’.
ThenHence the map
{f + Hp*0} ~ x*f
wherexj(g) = 1/(203C0) ~203C00 f(t)g(t)dt
forg E HP
is a natural isometricisomorphism
fromLp*/Hp*0
onto theconjugate (Hp)*. Thus,
for 1 p ~,(4.1) d(LP, Hp)
=d(LP*, LP*/HÕ*); d(HP, Lp/Hp0)
=d(HP*, Lp*/Hp*0).
The formulae
(4.1)
allow us to restrict our attention to the case wherep - 1. In the
sequel
we assume that1 ~ p
~ 2.The results enlisted in section 1
give
upper estimates for the distances inquestion.
We havePROPOSITION 4.1: There exists an absolute constant K such that
PROOF: