R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
O RAZIO P UGLISI
On outer automorphisms of ˇ Cernikov p-groups
Rendiconti del Seminario Matematico della Università di Padova, tome 83 (1990), p. 97-106
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On Outer Automorphisms of 010Cernikov p-Groups
ORAZIO PUGLISI
(*)
0. Introduction.
As is well
known,
every finite p-group that isnot cyclic
of order p, has non innerp-automorphisms.
Thistheorem, proved by
Gaschftzin
[1 ],
was later made moreprecise by
Schmid and then extendedby Menegazzo
and Stonehewer. In[2]
infact,
Schmid provesthat, apart
from some
exceptions,
Out G has a normalp-subgroup (always
in thehypothesis
that G is a finitep-group)
while in[3] Menegazzo
andStonehewer prove an
analogous
theorem to that one of Gaschftz in the case of infinitenilpotent
p-groups. Even in the case that G is infinite the normalp-subgroups
of Out G have been studied and in[4],
Marconi has reached an
analogous
result to the one obtainedby
Schmid. In this paper the
problem
of the existence of outerp-auto- morphisms
is studied in thehypothesis
that G is an infinitelernikov
p-group,
obtaining
an affirmative answer for a certain class of such groups. To be moreprecise,
if G is aCernikov
p-group,indicating
withGo
its finite residual and with Fit G itsFitting subgroup,
we have thefollowing
THEOREM. - Let G be a non
nilpotent Cernikov
p-group. If Fit G >Go
andG0 n Z(G)
is divisible then G has outerp-auto- morphisms.
(*) Indirizzo dell’A.:
Dipartimento
di Matematica Pura edApplicata,
Via Belzoni 7 - 35121 Padova
(Italy).
Even the case Fit G =
Go
is examinedobtaining
THEOREM. - Let G be a non
nilpotent Cernikov
p-group and assume Fit G =Go
andZ(G)
divisible. Then G has non innerp-automorphisms
or
Go)
= 0 and the naturalimage
ofG/Go
in AutGo
is aSylow p-subgroup
of AutGo .
The last section of this work is devoted to the construction of
some
examples
which show what canhappen
if Fit G =Go, Z(G)
is divisible and the
image
ofG/Go
in AutGo
is aSylow p-subgroup.
1. Preliminaries.
If G is a
Cernikov
p-group we shall indicate from now on withGo
its finite residual that is an artinian divisible abelian group and with Fit G the
Fitting subgroup
of G. It is worth whileremembering
thatG/Go
is a finite group so that while Fit G =Go(Go)
isnilpotent
and its centralizer in G coincides with
Z(Fit G).
In theproof
of theo-rem
2.1,
we shall use the results aboutnilpotent
p-groups cited in theintroduction,
which are here below listed for the readers’ use.THEOREM 1.1
(Gaschiitz [1]).
If G is a finite p-group that is notcyclic
of order p, then G has a non innerp-automorphism.
THEOREM 1.2
(Schmid [2]).
Let G be a finite non abelian p-group.Then p divides the order of
THEOREM 1.3
(Menegazzo-Stonehewer [3]).
Let G be anilpotent
p-group. If G is neither
cyclic
of order p norisomorphic
to a directproduct
of kquasi-cyclic
p-groups with kp --- 1,
then G has anouter
automorphism
of order p.THEOREM 1.4
(Marconi [4]).
Let H~ be an infinitenilpotent
p-groupThen
.H)
= 1 if andonly
if one of thefollowing
conditionsholds:
i)
H iselementary
abelianii)
.g is divisible and p is odd99
iii)
.H~ is the centralproduct
of and of aquasi cyclic
p-group with extraspecial
ofexponent p #
2.First of all we want to prove that a
lernikov
p-groupalways
has outerautomorphisms,
a fact which comeseasily
from thefollowing
theoremTHEOREM 1.5
(Pettet [5]).
Let G beperiodic
and.H c G
aCernikov
group such that
JG : NG(H) J is
finite. If is finite or countable andOInnG(H)
isCernikov,
then G isCernikov
andGo = H§.
COROLLARY 1.1. Let G be an infinite
Cernikov
p-group. Thenlaut G > Ho.
Inparticular
OutG ~
1.PROOF. If
laut GI
=No then,
with the same notations of Theo-rem 1.5 let g = 1. H and G
satisfy
thehypotheses
of Theorem 1.5so
Go
=.go =1, a
contradiction. Solaut
Gand, therefore,
#
The
proof
of theorem 2.1 is based ingreat part
on thefollowing
fact
concerning
thecohomology
groups ofG/Fit
G.LEMMA 1.1. Let G be a
Cernikov
p-group,Go
its finiteresidual,
1~ = Fit G.
Suppose Z(G)
divisible. IfZ(F))
= 0 thenZ(F))
= 0 ’B1m > 0.PROOF. Let X =
G/F
and ..A =Z(.F’}.
F isnilpotent
soA ~ Go
and therefore we can write A =
L,
whereLl
is finite. AlsoZ(G)
=D @ L,
with D divisible andL2
finite. Let pn = maxand consider the
following
short exact sequence in G-Mod(and
there-fore in
K-Mod)
where j
is the multicationby
pn. We have also the relatedlong
exactsequence
For every K-module we have
H°(K, M) =
mx = m b’x E~~;
so that we can rewrite this sequence as follows
because
Z(F))
= 0. Now 0 issurjective
andGo
r1Z(G)
isdivisible,
so.g1 (g, A[pn]) =
0 because it is a finite group.Then, by [1], Hm(K, A[pn]) =
0 ’B1m > 0 sothat,
as it is easy to see,Hi(K, Go)
= 0 andA)
isisomorphic
toHm(K, Go)
’B1m > 0.Now consider the exact sequence
where j
is themultiplication by
pn, and the relatedcohomology
sequence
As before we can see that
gm(g,
= 0 Vm > 0 sothat,
we have
But j
is the trivialmorphism
because theexponent
ofGo)
divides
~.g (
and thereforeHm(K, Go )
= 0 =A )
as claimed.#
2. Main theorems.
By
theorem 1.3 we can limit ourselves to the case in which G isnon
nilpotent.
Theprincipal
result obtained is thefollowing
THEOREM 2.1. Let G be a non
nilpotent Cernikov
p-group,Go
itsfinite residual. If Fit. G >
Go
andG0 n Z(G)
is divisible then G has outerp-automorphisms.
101
PROOF. Consider the extension e : 1 --~ .F’ --~ G -~ g -~ 1 where .F = Fit G =
C,(G,)
and K = 1~’ is characteristic in G soOut e = Out G. The Wells sequence
(Wells [6])
associated to e isHere D is the
image
of .K in Out F obtainedby
the naturalmorphism
x : K - Out F associated to the extension D because
C~(F)
_-
Z(F) ~ .F’.
IfZ(1~)) ~
0 then it is easy to construct a noninner
p-automorphism
of Gchoosing
an outer derivation 3 : K -Z(F)
and
setting
x" = It is well know that a is an outerp-auto- morphism
of G. Then we may assumeZ(I’))
= 0.By
lem-ma 1.1 we have
.H2 (.g, Z(F)) -
0 so that the Wells sequence becomesOut G r-.J
Our purpose is now to prove thatNOutF(D)jD
has non trivial
p-subgroups.
The firststep
is to show that0~(Out F) =1=
1using
Theorem 1.3.Surely
.F doesn’tsatisfy
conditionsi)
orii)
of that theorem.Furthermore,
Gbeing
nonnilpotent,
so that
rg Go > 1
and F doesn’tsatisfy
conditioniii).
Two cases are to be examined:
We can write F =
BZ(F)
with B a finite characteristicsubgroup
such that
I’/B
divisible. If B is abelian so is F.is a normal
p-subgroup
of Aut F = Out .F so it is contained in D.But this is
impossible
because theonly
element in Dcentralizing Go
is 1. Then B cannot be abelian.
By
Theorem 1.2 there exist an outerp-automorphism
a of Bcentralizing Z(B) > B
r)Z(G).
We can extendthis
automorphism
a to anautomorphism f3
of Fsetting
xfl = x" ifx E = x if x E is well
defined,
it is outer and hasthe same
period
of a. Thisimplies
that .H~ =CoutF(Z(F))
has nontrivial
p-subgroups.
If a E there exist aninteger n
suchthat an is the
identity
onF/Z(F),
that is a~ EZ(F))
that is a p-group of finiteexponent.
Sois
periodic
and therefore .H is finite. D acts on .Hby conjugation,
then it normalizes a non trivial
p-Sylow subgroup
ofH,
say P. D isstrictly
contained in PD because D (1 H = 1 and therefore >> D. This
implies
thatN outF(D)/D
has non trivialp-subgroups.
Let T =
F)D.
T is aCernikov
p-group so D isstrictly
contained in its
normalizer and,
for this reason,NAutF(D)/D
hasnon trivial
p-subgroups. #
We are then left to examine the case in which
Go
= Fit G. Inthese
hypotheses
the existence of outerp-automorphisms
in nolonger
certain. We have in fact
THEOREM 2.2. Let G be a non
nilpotent Cernikov
p-group,Go
itsfinite residual and assume Fit G =
Go(Go)
=Go, H’(K, Z(F))
= 0 andZ(G)
divisible. Then G has outerp-automorphisms
if andonly
if thenatural
image
ofG/Go
in AutGo
is not aSylow p-subgroup
of AutGo .
PROOF. - As in the
proof
of Theorem 2.1 we obtainOut G gz
If D is not a
Sylow p-subgroup
of AutGo ,
then thereexists a
p-subgroup P
of AutGo
such that D P. P is finite so D henceNAut Go(D)/D
has non trivialp-subgroups.
On theother
hand,
if G has an outerp-automorphism then 3CXENAutGo(D)/D
such that
1,
then the group .R =(a)D
is a p-group, R > Dand, therefore,
D cannot be aSylow p-subgroup
of AutGo . #
COROLLARY 2.1. Let G be a non
nilpotent Cernikov
p-group.Suppose CG(Go)
=Go,
yZ(G)
divisible and that theimage
ofG/Go
inAut
Go
is aSylow p-subgroup
of AutGo .
Then G has outerp-auto- morphisms
if andonly
ifHI(G/Go, Go)
=1= 0.3.
Examples.
Corollary 2.1, though establishing
a necessary and sufficient con- dition for the existence of outerp-automorphisms,
doesnt allow to establish the existence ofCernikov
p-groups for which this condition is verified. In this section we shall construct someexamples
whichprove
how,
if a group satisfies thehypotheses
ofcorollary 2.1,
wecan have either
H1(G/Go, Go)
= 0 orHI(G/Go, Go) =1=
0. From hereonwards we shall indicate with
1~~
andQp respectively
thering
ofp-adic integer
and its field of fractions. Let also remember that ifGo
= then AutGL(n, R~).
The results about the struc-103
ture of
Sylow p-subgroups
ofGL(n, Q~)
we shall use, have beenproved by
y"ol’vacev in[7].
REMARK. If p = 2 there are no
Cernikov 2-groups satisfying
thehypotheses
ofCorollary
2.1. Infact,
if a is the element of AutGo sending
every element a ofGo
in its inversea-’,
abelongs
to thecentre of Aut
Go
so, if D(the image
ofG/Go
in AutGo)
is aSylow 2-subgroup
of AutGo
then it contains a. Hence there is anelement g
of G such that ag = aw Va E
Go .
ThenZ(G}
cannot be divisible becauseEXAMPLE 1. Let C be the
companion
matrix of thepolynomial
1--~- t + t2 +
....-f-
tP-11 and set A =(1 1 0
...0).
where 0 is a column
of p -
1 zeroes. If(A
1we have The
Sylow p-subgro-ups
ofG.L(p, Qp)
have order p because henceX~
is aSylow p-subgroup
of
GL(p,
Consider the group G =G~ x~
whereGo
=(Z(p-)) -0
the direct sum of p
copies
ofZ(p-)
and x is theautomorphism
rep- resentedby
the matrix .X. An easy calculation shows that G satisfies’the
hypotheses
ofCorollary
2.1. We claim that.H1(G/Go, Go)
= 0.Let ~, z :
Go
be themorphisms
definedby
We know that
More difficult is to find Ker r. The matrix associated to r is that is Y ===
( 0 0)
for some J5 eWe claim that the first element of B is p - 2. Infact we have The elements of
place (1,1 )
and(2, 1)
of the matrix are,respectively,
yp - 1 and - 1 so that the first element of B is p - 2 as claimed.
Let a =
(ai, ...,(2))
be an element ofGo, aiEZ(pOO). By
a direct cal-M_"
culation we see that
But p - 2 is a unit in
B,
so we haveDefine
A
iis, obviously,
a divisiblesubgroup
ofGo
of rank 1. Furthermore,Ai n Y Ai
= 0 so that Ker 7: is the direct sum of thesubgroups Ai
j#i
and, therefore,
is divisible of rankp - 1.
HenceH1(G/Go, Go)
= 0and G has no outer
p-automorphisms.
EXAMPLE 2. Let p > 3. With the same notations of
example 1,
let X is an element of
GL(p + 1,
(J~
as inexample 1,
is aSylow p-subgroup
of+ 1,
sothe group
(where (~o
= and x is the auto-morphism
inducedby X)
satisfies thehypotheses
ofcorollary
2.1.Using
the samearguments
ofexample
1 we can see that Im a is adivisible group of rank p - 1.
If a =
(a1,
... ,a9+1)
EQ’-a ,
thenSo Ker r = where B is
cyclic
of order p.Then,
in thisi=2
case,
HI(G/GO’ Go) =1=
0 and G has non innerp-automorphisms.
EXAMPLE 3. In this
example
we will construct a group G such that theimage
ofG/Go
is aSylow p-subgroup
ofGL(n, Rp)
but notof
GL(n7 Q2))’
as it was in theprevious examples.
Let p = 3 and105
.~~
is not aSylow 3-subgroup
ofGL(4, Qa)
becausethey
areelementary
abelian of order 9.
Suppose
there exists s.t. Y3= 1 andY)
= 9. SetGo
=(Z(3°°))~.
Let xand y
be theautomorphisms
of
Go
inducedby
.X and Y. =0,
0"b) :
a,& eZ(3~)}.
== = and therefore Y has the form Y
_ ’
From this
point
on we set S= (0 -1 1 -1)
andT = 1 1 . Using
the relation xv = x we deduce that L-18L = S and a routine cal- culation proves that the
only possibilities
are L =I, S,
82. If L = S2the first block of Y2 is
S,
so we can reduce our discussion to the casesL = I or L = S. Note that N3 = I and that x acts as the
identity
on the last two
components
ofC~o
so we may assume N = S or N = I.Four cases are to be examined:
I ,
lution,
in of theequations
But these
equations
have no solutions inRa.
and this
gives
xy = yx « T
+
M =+
ST =>(m, n,
r,s)
is a solution of thefollowing equations
But the solution of these
equations
is not in1~3.
This proves that
.X~
is aSylow 3-subgroup
ofGL(4, .N3). Now,
as in
example 2,
we deduce thatH1(G/Go , Go )
iscyclic
of order 3 sothat G has outer
3-automorphisms.
Acknowledgement.
This paper ispart
of the T esi di Laureapresented by
the Author in PadovaUniversity
onl0th
November 1986. The A.would like to thank Prof. F.
Menegazzo
for hissupport
andencouragement.
REFERENCES
[1]
W. GASCHÜTZ, Nichtabelschep-Gruppen
besitzen äusserep-Automorphismen,
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Algebra,
4 (1966), pp. 1-2.[2] P. SCHMID, Normal
p-subgroups
in the groupof automorphisms of
afinite
p-group, Math. Z., 147 (1976), pp. 271-277.
[3] F. MENEGAZZO - S.
STONEHEWER,
On theautomorphism
groupof a
nil-potent
p-group, J. London Math. Soc., (2) 31 (1985), pp. 272-276.[4] R. MARCONI, Il gruppo
degli automorfismi
esterni di un p-grupponilpotente infinito
e i suoip-sottogruppi
normali, Rend. Sem. Mat. Univ. Padova, 74(1985),
pp. 123-127.[5]
M. PETTET,Groups
whoseautomorphisms
are almost determinedby
theirrestriction to a
subgroup, Glasgow
Mat. J., 28(1986),
pp. 87-89.[6] C. WELLS,
Automorphisms of
group extension, Trans. Amer. Math. Soc., 155(1971),
pp. 189-194.[7] VOL’VACEV,
Sylow p-subgroup of
thegeneral
linear group, Isv. Akad. Nauk Ser.Mat.,
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pp. 216-240.Manoscritto