R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
F EDERICO M ENEGAZZO
Automorphisms of p-groups with cyclic commutator subgroup
Rendiconti del Seminario Matematico della Università di Padova, tome 90 (1993), p. 81-101
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Automorphisms of p-Groups
with Cyclic Commutator Subgroup.
FEDERICO MENEGAZZO
(*) with Cyclic Commutator Subgroup.
FEDERICO
MENEGAZZO (*)
ABSTRACT - We
study
theautomorphism
groups of finite, non abelian, 2-generat-ed p-groups with
cyclic
commutatorsubgroup,
for oddprimes
p. We exhibitpresentations
of the relevant groups, and compute the orders of Aut G,Op (Aut G ),
and of the linear group induced on the factor groupIn this paper we
give
asystematic
account of theautomorphism
groups of
finite,
nonabelian, 2-generated
p-groups withcyclic
commu-tator
subgroup,
for oddprimes
p.Special
cases of thisproblem
have of course been studied in connec-tion with many
questions,
with the aim ofproviding examples
andcounterexamples; still,
thegeneral
information available isremarkably
scarce.
It is a remark
by Ying Cheng [2]
that in such groups G the central factor groupG/2(G)
ismetacyclic,
hencemodular;
it followsthat
G ~ 1
divides the order of Aut G[3].
Another known fact is that in any metabelian2-generated
p-group G =(a, b),
for all choicesof x, y E G’,
there is anautomorphism % mapping
a to ax and bto
by [1];
moreover, if G’ iscyclic and p
isodd,
suchautomorphisms
are
inner [2].
Thisimplies
that the order of Inn G isG’ ~ 2.
Aut Gnaturally
induces a group of linear transformations of theZ/pZ-vector
space where
4l(G)
is the Frattinisubgroup;
we denote thisgroup which
in our case is asubgroup
ofGL(2, Z/pZ)-by Aut,G,
the 1
beeing
a reminder of «linear». The kernel of thisaction,
i.e.(*) Indirizzo dell’A.:
Dipartimento
di Matematica Pura edApplicata,
Uni-versità di Padova, via Belzoni 7, 35131 Padova
(Italy).
The author
acknowledges
support from the Italian MURST (40%).{x
EAutGlgCXØ(G) = ~( G ), Vg
EG},
is sometimes denotedby Aut~ ( G );
for every p-group Inn G ~
Aut~ ( G ) ~ Op (Aut G ).
We found it necessary to analise
separately
several cases;indeed,
what we
got
is almost a classification(a
classification offinite,
nonabelian, 2-generated
p-groups withcyclic
commutatorsubgroup,
forodd
primes
p, has beengiven by
Miech in[4]).
For each case, we willexhibit
presentations
of the relevant groups andcompute
the orders ofAut G, Op (Aut G), Autl G.
In manyinstances,
we have been able to dis-play
the effect of Aut G on two chosengenerators
ofG;
wehope
thatalso in the
remaining
cases the information weprovide
ishelpful.
1. In this section we will deal with
metacyclic
groups.Accordingly,
we suppose that a group G has a
cyclic
normalsubgroup
N =(b)
of or-der
p~,
say, withcyclic
factor groupG/N = (aN)
oforder p .
We may choose a such that b a = for some s, 1 ~ s m. Since the order of 1 is we also have m - s ~ l. The centre isSuppose
that Gsplits
over N. Then G =( a,
== b1+ps) is a presentation of G. If b
= a z b W is a candidate for an Aut G-im- age ofb,
we must have(bP8)
= G’ =(bP8) and
a’ = bb -w ECG(G’).
It fol-lows
that
and thenazps = 1,
w
z ( 28)
- z w 8 8 We also have(azb w)a
z w a -= a z = such a b is in fact in the Aut G-orbit of
b,
and anautomorphism mapping
b to b and a to a exists if andonly
if a has orderpl
andbä
= = i.e. a E whereCG(b) _ (b)
x(apm-8).
We summarize our results:
where 1 ~ s ~n and
The
effect of
Aut G on thegenerators
a, b iswhere
Suppose
now that in ourmetacyclic
p-group G there is nocyclic
normal
subgroup
Nhaving
acyclic complement.
G has apresenta-
tion
G = (a, b ~ bpm - 1, yields
m > h ~ m - s; b cannot have maximum
order,
so 1 >h;
for the samereason,
G’ 1- (a),
which means s h. As a firstapproximation
to theAut G-orbit of
b,
we look for elements g = a’b’generating
normal sub-groups N of
order pm containing
G’ = Thishappens
if andonly
if(gpS) =
i.e.(a)
A(b) = (apl),
or az E(a P ~),
and w 0 0(p).
We have such elements g,
where ~
is theEuler
function,
whichgenerate p~ subgroups
N as above. For every choice ofN,
G =(a, N)
and theautomorphism
group induced on Nby conjugation
in G is the groupgenerated by
the power 1 +p_~;
it is there- forepossible
to choose a E G so thatG/N
= and = forevery
generator g
of N. The choice of a is notunique:
all the elements in thecoset aCG (N ) (and they only)
share the sameproperties.
The orderof
CG(N )
= =N(aPm-S) is pl+s:
once N isgiven,
we havep l+s
possible
choices for a.Comparing
theorders,
for every such a we find(a)
A N =Nph:
it is thenpossible
to choose agenerator b
of N such thatapl
=bph. Again,
the choice ofb
is notunique:
thepossible
choices are the elements of the All
told,
the number ofpairs (a, b) satisfying
thegiven presentation
of G is(p ~
choices forN)
times choicesof a)
times choices ofb).
In summarywhere 1 ~shm
REMARK. For
any n > 6,
fix m such that 3 £ m %n/2, 1
= n - m,s = 1,
h = m - 1: weget
a group G of order withIAutGI =
= pn+1.
2. In this section we will deal with groups G which are not meta-
cyclic,
and havenilpotency
class 2. We first fix the notation: c~ b aregenerators
for G such thatGIG’ = (aG’)
x(bG’),
aG’ has orderp
Land bG’ has order
p m.
Then u =[b, a] generates G’, u
hasorder pn
with1 ~ n ~ ~ n ~ m,
and of course u EZ(G), Z(G) = bpn, u).
Suppose
first that(b) A
G’ =(a) A
G’ = 1. G has apresentation
G =(a, b, bp = up - 1,
=bu,
u a= u b
=u),
and the ele- ments of G can beuniquely
written in the form E y E z EZlpn Z.
We can also assume l > m. If 0 is any auto-morphism
ofG/G’
and we fix elements a E and set u =[ b, -a],
it isimmediately
seenthat (a, b) =
G anda, b, u satisfy
therelations,
so that theassignment a H a, b H b, u H u
extends to an auto-morphism
of G. This means that the obvioushomomorphism
Aut G -~ Aut
(G/G’)
isonto;
its kernel is InnG,
of orderp 2n.
The struc-ture of
Aut (G/G’ )
is well known: if 1 = m it isisomorphic
withGL( 2, Z/p Z),
while if 1 > m it isisomorphic
to the group of all matri-We obtained:
with l > m > n >1.
[Notice that,
ifG/G’ - (aG’}
x(bG’ ~,
for somea E Aut
G,
so inparticular (a)
A G’ =( b ~
A G’ = 1. This fact will avoid anyoverlapping
with the discussion thatfollows.]
Suppose
now that for no directdecomposition
xx
(bG’)
it ispossible
to choose a and b such that(a) A
G’ ==
~b~ ~
G’ -1,
but there is one suchdecomposition
with(a) A
G’ = 1(and (b) A
G’ #1).
G has apresentation
G =(a, b, u I apl
=1,
bpm
=upk,
ba =bu,
ua= Ub
=u),
where 1k n(we
are nolonger
as-suming l > m).
Ifb
=ar b s ut
is in the Aut G-orbit ofb,
then(5P’) =
=
(G’ )pk
= thishappens
if andonly
ifa rpm =
1 and s ~ 0(p).
Forsuch a b we have
[b, a] = ups, bP
=bSP
=usp
= =(a, 5),
so that there is in fact an
automorphism
of Gmapping
b tob
andfixing
a. If 0 is any
automorphism
of Gmapping
b tob,
then[ b,
==
[b, a]pkand
=1;
so the condition ona 0
isa
E whereb, G’),
hence We maynow state
1 ~1~n.
The
effect of
Aut G on thegenerators
a, b isTo finish with the class 2 case, we have to deal with the
following
situation: for any choice of
generators
a,~ b of G such thatGIG’ =
we have and
~b) ~ G’ ~ 1.
G will have apresentation G = ~a, b, u I upn = 1, bpm
=upk,
I b a =bu,
ua ==Ub=u),
where1 h n, 1 k n,
and we may assume l > m.There are further
restrictions, namely: h
> 1~ and 1 > m + h -1~. Infact,
from h ~ k it would followbpm
=Upk = (Uph)pk-h = a p I+k-h9
,1 and the
generators
a,bo
=b(a
wouldsatisfy G/G’ = (aG’) and (bo)
A G ’ = 1.Similarly,
if h > k butL ~ m + h -1~,
we could set and obtainG/G’ _
= (ao G’) x (bG’)
and We then assume h > k and1 > m + h - k and look for
subgroups
C =(c)
where c andD =
(d)
where d = such thatCp -
andDp -
Now l = =
generates
ifand
only
if(p):
there are suchelements,
which gener- atepm+h subgroups
C. Anddpm = arpmbspm =
=
generates (Upk)
if andonly
ifa rpm
E(a)
A G ’ =(aP’) =
and s *0
(p):
there are suchelements,
whichgenerate
p(pm)pm+n /~(pm+n-k) = pm+k subgroups
D. It is also clearthat,
forany choice of C and D as
above,
G =(C, D)
andarbitrary generators
cof C
(in place
ofa)
and d of D(in place
ofb) satisfy, together
withv
= [c~ c]
inplace
of u, relations very similar to theoriginal
ones, the differencebeing
that some coefficientsh, g might
appear inc p
=dpm - VfJ.pk (~, ~ ~
0(p)).
But therecertainly
areparticular generators a, b
ofC,
Drespectively (a
convenient choice isc ; d ~),
whichsatisfy,
with u =
[b, a],
all the relations(e.g., ab,
b is not a«good pair»,
butab, one).
For such a choice ofa, b,
we find that(i 0 0,
~0 (p))
willagain satisfy
the relations if andonly
if =uij
issuch that =
a ipl
anduJP = Ejpm
= i. e. if andonly if j =
- 1 i = 1
(pn-k ):
and we have suchpairs.
So the number ofautomorphisms
of G is:(number
ofC’s)
times(number
ofD’s)
timesWe can now state:
where
3. From now on, we suppose G is not
metacyclic,
and itsnilpotency
class is
greater
than two. Let us fix some notation. G’ iscyclic
of orderand is
cyclic
andnon-trivial,
so that G isgenerated by
two
elements (4
b such that b ECG ( G ’ ), a
acts on G’ as the power 1+ p~
(0
sn)
and G’ =([b, a]);
we denote the order of bG’ andby
p~
the order ofa(b, G’).
The Aut G-orbit of b is contained inCG ( G ’ )
=and the AutG-orbit of a is contained in the
coset aCG(G’ ).
We setu = [b, a];
since~b, G’~
is abelian andnormal, [byu’, a]
We will show that if i ~ 0 then[b, uPi
(mod
This is true for i =0;
so, suppose i > 0and, by
induc-tion,
acts on G’ as somepower 1 +
tAp’+ i-1,
and 1 +( 1
+(J.ps+i-1)
+ ... +( 1
+(J.ps+i-1)P-l
==
p( 1
+ for some v, so that(on G’ )
theendomorphism
1 + ++ ... +
(api-l)p-1
is the power +vps+i-1).
And then[b, apil =
=
[b,
E which establishes ourclaim.
So,
inparticular, [b,
Andifaxpn-s bY uZ,
are
arbitrary
elements ofCG(G’)
andaCG(G’), respect- ively,
we cancompute
the useful formulaWe can now
easily compute (a)
ACG(b) = (a)
AZ(G) = (a)
AA (b, G’) =
whichgives l >
n;CG (b) = (aPn, b, u)
andZ(G) _ (apn, bpn,
Since(aZ(G)) A (bZ(G))
=Z(G),
we see thatG/Z(G)
ismetacyclic
of orderand
bZ(G)aZ~G> = bZ(G)l+ps.
*In this section we deal with the
following special
case:CG ( G ’ ) /G ’
contains a direct factor
(bG’)
ofG/G’;
and(bG’)
has acomplement (aG’ )
inG/G’
such that(a) A
G’ = 1.To
begin,
we suppose, inaddition,
that b can be chosen tosatisfy (b) A
G’ = 1. Then G has apresentation
G =(a, b,
==
be in the Aut G-orbit of
b,
thenb E CG ( G ’ ), 6,o (P(G), 1,
so thata" e
0 (p).
And if a is in the Aut G-orbit of a, then a == ac for some
(u). Conversely,
for any choice ofa, b
inagreement
with theserequirements,
if we set f ==
[b, a],
weget
agenerating triple
for G which satisfies thedefining
re-lations. Hence we can state:
where
m->n,
0sn.The
effect of
Aut G on thegenerators
a, b isIn this second
part
of the section we still assume that G has genera- tors a, b such thatGIG’ = (aG’)
x(bG’)
and(a)
A G’ = 1 as in thefirst
part,
but now(b) A
G’ # 1. G can bepresented
in the form: G =m > k, (p), conversely,
fromthe
presentation
above one caneasily
read that no element g ECG(G’)
exists such that
(gG’)
is a non-trivial direct factor ofG/G’
and~g)l~G’=1.
_If
b
ECG(G’ )
is in the Aut G-orbit ofb,
thenthe group
CG ( G ’ )
has class - 2 andbelongs
to itscentre,
so thata xpn-s+m b ypm u zpm,
and(G’)Pk
if andonly ifaxpn-s+m =
= 1 and
y =t= 0 (p).
On the otherhand,
supposea xpn-s
and(p); set b
= and £ =[b, a] = [byuz, a]
=uy+’P’.
Then G =(a, b~,
all the relationsexcept maybe
the last onehold,
and= =
hence,
there is an automor-phism
of Gmapping
b to b andfixing
a. For agiven b
asabove,
the con-ditions on a = ac, where c E
CG(G’),
in order that some 0 e Aut G exists which satisfiesa, b’
= b are thefollowing: apl
=1,
and[b, a]pk
=To
compute
the ordersexplicitly,
we nowonly
have tomake the necessary
distinctions, according
to the relative sizes of 1~ andI
=pm+n-k
andpl, lapn-sl I -
and Weget
thefollowing
summary:
where
4. In this section we retain the
general hypotheses
and the notation established at thebeginning
of section3,
and we still assumethat contains a direct factor
(bG’)
ofG/G’,
but we nowsuppose that for all
complements (aG’)
of(bG’)
inG/G’
we have(a)
A G’ # 1.The easy case in this context is when
~b~ ~
G’ = 1. G has then a pre-sentation
( 1 h 1+
su b
=u)
with the usualinequalities
0 s n ;b ]
= 1gives
9
l ~ n, and of course n > h >
0;
moreover,[ u p h, a] =
1yields h ~ n -
s.If c = E
CG (G ’)
and a = ac is in the Aut G-orbit of a, thenso that
bPP’
= 1 and ifb
is in the Aut G-orbit of b theny 0 0 (p),
and 1gives axpn-s+m = 1. Also, u
=[b , E]
=and an
automorphism
0 of Gmapping
a to a and b to b exists if andonly if apl = Uph:
we have tostudy
the solutions of the congruencewith the conditions
fl-pl
=0 (pm)
and 0 This con-gruence has solutions in y
(precisely
solutionsmodpm)
for anygiven A,
p, v, x, zsatisfying
the conditions above. So we havewith l>n, m>n, h>n-s, 0s,n
The
effect of
Aut G on thegenerators
a, b is- If m>l and ml+s-h:
5.
Suppose
now thatC(G ’)/G ’
contains a direct factor ofG/G’,
but for all
generating pairs
a, b(with
b E for whichGIG’ =
=
(aG’)
x(bG’)
one has(a) A
G’ ~1, (b) A
G’ # 1. With our usualnotation
(u
=[b, a]
of orderp n,
u aetc.)
we find that G has apresentation
G =(a, b, 1,
, ba =bu,
, ua = ,ub
= u, ,aP 1
bpm=urp),
with r * 0(p),
k m and
~’~ - rpk+s (pn).
Some cases have to be excluded. If 1~ hthen 1 + l~ > m
+ h,
otherwise(b t p m+h-k-l )P l =
- apl (for
the inverse t of r mod~n);
hence with ao =ab - t P m+h-k-l
weget
a 0 P
= 1 and thepair
ao , b satisfiesand a0>
AA G’ = 1.
Similarly,
sinceA G ’ = 1.
Similarly,
if h we must 1+k-h-. s > I + k -h, since
otherwise with
E
CG(G’)
and we could substitutebo
= a forb;
butb0>AG’=1.
To determine Aut
G,
thepoint
is to find allpairs a, B
with a EE
aCG(G’ ),
Bcyclic,
B ~CG(G’ )
such thatBp m = (G’ )pk, (ap 1 (G’ )ph,
G =
(a, B)
andgpm - [ g, a]rpk
for somegenerator g
of B: infact,
if thisis
true,
then for everygenerator g
of B we have andit is clear that there is one
particular generator b satisfying
==
[ b, a ] p h. Moreover,
we can theneasily
determine all the« good »
genera- tors :b3 (p))
is one if andonly
if z. e.E]
= 1. This meansE(6)
AZ(G) = (bpn), j
== 1(pn
so there are
precisely «good» generators
of B. ~Now,
take a = we have E G’implies [Apl
* 0 which in turn_ ( G ’ ) p h
>h;
but if k 5 h we have 1 > m
+ h -1~,
and then =(urp.P)P k l-m
Eand
If g
=(y ~ 0 (p)),
we findaxpn-s+m bypm u zpm (since
m ~ s).
In case h ~ k we have and so EE (G’ )pk+1,
whichimplies (gPm) = (bpm) = (G,)pk.
If instead kh,
thengpm E
G’ forces EG’,
i.e. 0(pl),
andagain
- (G , )pk.
kFinally,
westudy
the condition[ g, a]rpk
for g, a asabove,
with
tAp
* 0 and 0(p 1).
The condition isAt, this
point,
wehave
found allpairs
and ~ is determined
(modulo
the order ofby
As we
expected,
the conditionsdepend only
onB,
and not on theparticular generator
g. Thenumber ,
1 ofsubgroups
B is thenwhere 6
is the Euler func-The
possibilities
for a =I
are thefollowing (we
use the factthat
For a
given
choice ofB,
the number of a’s is Bpn|(Ql(bG’>)|I
where[3
stands for the number of distinct cosets
a Àpn-s (apl)
when ~ satisfies(*).
In case k ; s A is
arbitrary, hence 03B2
= on the otherhand,
when1~ s the is
fixed,
whichsplits
cosetsin this case
~3
=pl-n+k.
In the end weget:
6. From now on, we shall deal with the case when no nontrivial direct factor of
G/G’
is contained inCG ( G ’)1 G ’.
With our usual sym-bols,
G isgenerated by
a andb,
b ECG(G’), u
=[b, a]
has orderp n, ua = ul+p$ (~ s n)~
for some
h,
0 h ~n.G/G’
does notsplit
over(bG’),
hence 1 >h;
and[b,
= 1implies
n. We also have n - s > 1 -h,
because from n - s 1 - h it would followapH E CG(G’)
andconversely, bG’) A
A for all
h, g and
indeed does not containany direct factor of
GIG’.
In this section we further assume that
(b, G’ ) _ (b)
xG’,
i. e.bp~ - 1;
theremaining
cases will be discussed from section 7 on-wards.
The
simplest
instance of this class is when m b can be chosen so that(a) (b)
fl G’ = 1. G has then apresentation
G =(a, b, bpm - 1,
ba=bu, ub=u,
where0sn,
0 1 - h n - s,
h ~ n(the
lastinequality coming
from the fact thatbph E Z(G)).
If we takeE with
y 0
0(p),
and u =[b, a],
then G =(a, b), bpm =
1 becauseI only
remains to check the rela-tlon other
termS,
x, y,
h, g
have to be solutions ofx,
h, g
can be taken atwill,
and then y + is determined. In par- ticulary --_ 1 (p),
so Aut G is a p-group. We have= choices for a. Once ac is
given,
ac-cording
to(**)
we can choose barbitrarily
in the cosetorder p1-n+s
9I = ~ h,
and thesesubgroups
ofG/G’
are inde-pendent,
we choices forb.
We obtainedIn the
setting
recorded at thebeginning
of thissection,
we supposenow that the
generators
a, bsatisfy (a) A
G’ =~b~ ~
G’ =1,
but(b)
1. G has now apresentation
G =(a, b, ulupn
=bpm
=1,
ba =
bu,
ua = u, where(p), 0 £ j n,
and the usual conditions
0 s n, 0 h m,
01-hn-s,
m ~ nhold,
and(which
meansWe also
assume j h,
since otherwisebo = butpJ-h
would
satisfy
and Wealso have !
/B G’ = 1
gives
the furthercondition j
+ m - h a n.Here
(and
in the rest of thepaper)
it isexpedient
to use the directdecomposition
where .The order is
easily computed.
The natural candidates fora 8, b B (0
E AutG)
can be written asac’‘
b 11 u’ and c x b yu z, respect- ively (y =1= 0 (p)).
Some tedious butelementary
calculationsgive:
If we take the relation
acpl = bph utp’ into account,
we can also com-pute
in our case
It remains to check the relation and
(3)
the condition readsNow
(b, u) = (b~
x(u)
andph
+ = 0(~n);
so, we arelooking
forthe solutions of the
system
We also
have n - j ~
m - h.Substituting
y from(I)
into(II) gives
if
(h, g,
x,y)
is a solution of thesystem,
thentAp 1-h
= 0 and y =- 1 + and
conversely
any4-tuple (À,
x, 1 + + + with =0 (pn - j)
is a solution.To determine
|Aut G|,
we need tocompute
the orders ofwhich is if and
p2l+m-n+s+j-h if l-
and of(c, G’~,
which ispl+s+h.
Weconclude:
To conclude this
section,
we nowstudy
the groupsgiven by
a pre-sentation G
=(a, b, u I upn
= =1,
ba =bu, u a
= =u,apl
== as in
(E.2),
but with n> j
+ m - h(we
retain the other condi- tions on theparameters).
This means thatCG(G’ ’)1 G’
I does not containdirect factors of
G/G’,
there is such that(b, G’) = (b)
xG’,
and for all elements a E Gwhich, together
withb, generate G, we
have(a) A
G’ ~ 1. As inthe previous
case, we set a =b where c = =
[b, a]
and check whetherthey satisfy
the relations. Sincebpm =
we see that for all choices of xif j
+ 7% a I + s; on the otherhand,
ifj
+ m 1 + s we must take x --_ oExactly
as in the discus-sion
leading
to(E.2), equivalent
to thesystem
but in this
case n - j
> m - h. If wemultiply (I) through
1 +write
(II)
in the form + = 1 + + andsubstitute into
(I)
weget
+I m
then 03BC
must be - 0(pm-l).
And(II)
may also be rewritten as(y - 1)( 1
+ = or y = 1 + where ais the inverse of 1 + in
Zlpm Z.
Hence,
the solutions of oursystem
are all the4-tuples (À,
p., x, 1 + + +where 03BC
= 0 m and x = 0To
compute
the order of AutG,
we note that forp. = 0
(pm-l)
m; and for any 03BC ifm)
- ~ cG’ _~ ,
sothat
and the setsand have
and,
We state our results:The
effect of
Aut G on thegenerators
a, b is- If l m and j + m l + s:
7. In order to
complete
ouranalysis,
we still have to consider thefollowing
situation: for every we have-
(bG’)
is not a direct factor ofG/G’;
and-
(b)
is not a direct factor of(b, G’).
We
again
use our standard notation: G =~a, b),
b ECG ( G ’ ),
u =
[b, a]
has orderIbG’1 [
=p m, u a
= with 0 s n,la(b, G’) [ = pl.
As we saw at thebeginning
of theprevious section,
the first condition is
equivalent
to:bph u tpJ
m > h andn - s > 1
- h,
t =1= 0(p) (at
least for themoment,
we are notexcluding
the
possibility that j ~ n); [apl, b]
= 1implies ph
+ = 0(~~).
Andthe second condition says some
(p), 0 k n;
a]
=a]
thenimplies p m - ( p n );
so, inparticular,
m > k and m > s.
Any cyclic subgroup
ofCG ( G ’ ),
not contained in~(G),
isgenerated by
some element g =a xpn-s
an easy calculationgives
If
j
+ m + n ~ L + s+ k,
the congruence + + + 0 in theunknowns x,
z has a solution(~0),
and then On the otherhand, if~+m+~>~+s+~
then for all choices of x, z g as above satisfies 1. Hence our second condition isequivalent
toNext,
we determine(a) A
G’ . we have,
-h
.In this section we
study
thespecial
case in which(a) A
G’ =1,
i. e.(~ n ),
Sincek n,
thisimplies h + 1~ = j + m,
andthe reduces to n - s > l - h. Once
more, we set
(p)), (where
c =
apn-s b _pn-s-z+h)
and check the relations.Using (1), (2), (3),
it is easi-ly
seen thatUrpk
translates intoi. e.
Similarly,
we may write both asand as
In our case
(a)
A G’ = =1,
so these conditions areequivalent
to the
system
note that
m-h=k-j n-j.
Suppose
first thatm-h~s-j,
so thatthe first congruence is trivial. Since
n + s + m - h ~ n - j,
from(II)
and(III)
weget
and then = 0 y = 1
Conversely,
any4-tuple (~, ,u, x, y)
with(J-pl-h
=0 ( p n -~ )
and y = 1 is a solution of thesystem.
If,
on the otherhand,
m - hs - j s),
weproceed
as fol-lows. If
(À,
,u, x,y)
is asolution, then y
= 1(p);
lety’
be the inverse of y inZlpn
Z. From(I)
and(II)
we can write A =y’ x(J-
+ y = 1 +for some a, p and then
(III)
becomesforcing ~p~=0 (we
used theequality (n-s)+(s-k)+
+
(~n - h) _ - n - j ).
And now(II) implies
y = 1(pm-h). Moreover,
so
g m 0
yields k
= 0 Vice versa, it is clear that any4-tuple (h, g, r, y)
with A * 0 = 0 y - 1
(pm-h)
is a solution of the sys-tem.
So,
we haveThe
effect of
Aut G on thegenerators
ci, b is8. In this final
section,
we will use the notation established in section 7 tostudy
theonly
caseleft, namely:
for all b E(bG’)
is not a direct factor ofG/G’
and(b)
is not a direct factor of(b, G’),
and also(a) A
G’ ~ 1 for every a EGB b, O(G)
>. We sawthat G has a
presentation
G =(a, b, Ulupn = 1
ba =bu,
ua =U1+p8
u b
= u,b p - urp , (with
some conditions on the numbersn, s, l, h, t, j, 1!4 r, k,
for which we refer to theprevious section).
And(a~ l~ G’ - (ap L+m-h ~,
, wherea P 1+.-h
= , so that ++tpj+m-h=1=O (p n).
We set(a~ /~ G’ _ (up2~;
we have 0 i n. Ofcourse, i
=1~ in andi = j + m - h
in casethen
i=k+i’,
where r+t=0(pi’),
r +
(~ i’ + 1 ).
We claim that i k + l- h. This is obvious in the first two cases.Suppose k = j + m - h;
ifi ~ l~ + L - h,
then r + t = 0 and the congruence r + t = 0 has a sol-ution go:
using (2)
weget
=contradicting
an earlier as-sumption.
_ _Set
K = [b, El,
where c ==
aP
b -pn-s-l+h andy =
0(p).
There exists 0 E Aut G such thata° = a, b 8
= b if andonly
ifbpm
=Urpk
andaPl
= if andonly
if(4)
and(6)
hold.Suppose
first that then(4)
and(6)
withA~=0
are,
respectively:
whose solutions are: x --_ o
(and x arbitrary
ify - 1
In this way we determineI
=p2h+i-.n if
i s ++ 1 - h
(notice
thatZ( G ),
hence i ~ n - s and h + i - n ~~ h - s >
0)).
We will riow use
(4)
and(6) again,
in order to find the Aut G-orbit ofa. If
(ac, b) = (a’, 0 e AutG,
then from(6)
weget apl(1+p.pl-h_y) E
E
(a)
A(u),
hence 1 +tapl-h - y
= 0(pm-h)
and y - 1pm-h
for some p. Note
- A > z implies
so thatagain (6) yields
+
1)
== 0(p j).
And we have shown that ff -a is in the Aut G-orbit of a, thenj+l-h = h -
For the converse, suppose
[Ap
for some a, and setppm-h =
= 1 + y
and ~
= Then(4)
and(6)
translate intowhere
(p)
is such thatuqpi.
Since
k+n-s-i-(n-s-l+h)=
all the coeffi- cients are divisible hence
(4)
and(6)
areequivalent
to thesystem
2: of congruences
(in
theunknowns ~, p)
The determinant of E is invertible in for any choice of ~
and g
(with [AP j+l-h implies
that the solution
for ~ (which
isunique
inZlpn-i Z,
forgiven ~
andp.)
isdivisible
by
so we can solvefor x,
and take y = 1 +And then we conclude that the Aut G-orbit of a is the set
whose
cardinality is j
otherwise. We can now state
REFERENCES
[1] A. CARANTI - C. M. SCOPPOLA,
Endomorphisms of two-generated
metabeliangroups that induce the
identity
modulo the derivedsubgroup,
Arch. Math.,56 (1991), pp. 218-227.
[2] Y. CHENG, On
finite
p-groups withcyclic
commutatorsubgroups,
Arch.Math., 39 (1982), pp. 295-298.
[3] R. M. DAVITT - A. D. OTTO, On the
automorphism
groupof
afinite
p-group with centralquotient metacyclic,
Proc. Amer. Math. Soc., 30 (1971),pp. 467-472.
[4] R. J. MIECH, On p-groups with a
cyclic
commutatorsubgroup,
J. Austral.Math. Soc., 20 (1975), pp. 178-198.
Manoscritto pervenuto in redazione il 23