R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
A LIREZA A BDOLLAHI
B IJAN T AERI
A condition on a certain variety of groups
Rendiconti del Seminario Matematico della Università di Padova, tome 104 (2000), p. 129-134
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ALIREZA ABDOLLAHI
(*) -
BIJAN TAERI(*)
ABSTRACT - Let a,, ..., a n be nonzero
integers
whose greatest common divisor isd . We prove that an infinite group G is of finite exponent
dividing
d if andonly
if for every n infinite subsets Xl , ... , Xn of G there exist x, E Xl , ... , xn E
Xn
such that
1. Introduction.
Let V be a
variety
of groups definedby
the lawv(xl,
... ,xn)
= 1. Wesay that G is a if for every n infinite subsets
Xl , ... , Xn
of Gthere exist
xn E Xn
such thatv(xl,
... , = 1.In
[4]
P.S.Kim,
A.H. Rhemtulla and H. Smithposed
thefollowing question:
for whichvariety W,
is every infinite aBJ-group?
There exist
positive
answers for thevariety
C~ of abelian groups de- finedby
the law[x, y]
= 1(see [7]),
thevariety C~,2
definedby
the law[x, y]2
= 1(see [5]),
the varieties62
and63
of2-Engel
and3-Engel
groups defined
by
the laws[ x , y , y ] =
1 and[x, y , y , y ] = 1, respect- ively (see [10]
and[11]),
thevariety
of groups ofexponent dividing
n,defined
by
the law x n = 1(see [6]),
thevariety .Nk
ofnilpotent
groups ofnilpotency
class at mostk ,
definedby
the law[xl, - - -,
xk+ 1 ]
= 1(see [6]),
the
variety
of 3-abelian groups definedby
the law = 1(*) Indirizzo
degli
AA.:Department
of Mathematics,University
of Isfahan, Isfahan 81744, Iran;Department
of Mathematics,University
ofTechnology
of Isfahan, Isfahan, Iran.We would like to express our
appreciation
to our supervisor Professor A.Mohammadi Hassanabadi, who first drew our attention to the
subject,
and his encouragement and numeroushelpful
comments. We also wouldsincerely
like tothank the Referee for
improving
theoriginal
result of the paper.130
(see [1]) and,
thevariety generated by
the law xl ... xn = 1(see [3]).
Now let V and W be varieties of groups defined
by
different laws... ,
= 1 and ... ,
Ym)
=1, respectively.
C. Delizia in[2]
posed
thequestion
of whetherV# = W# when V = W,
and for k >1,
heinvestigated
thequestion
for thevarieties V = Vk (the variety
definedby
the law ... ,xl ]
=I)
and ’~ _For nonzero
integers
aI, ... , a n with thegreatest
common divisord ,
we have considered the
question
for the varieties V definedby
the law~...~=1
and83d; proving
THEOREM.
2. Proofs.
LEMMA 1. Let ’V be the
variety defined by
the laww (xl, - - -, xn ) _
=1.
If
G is aninfinite FC-group
inV*,
then G E V.~ is infinite. Let A be an infinite abelian
subgroup
ofn Ca(gi).
Then Aby
Lemma 3 of[3].
Now consider the infinite sets... ,
gn A . By
theproperty BJ
there exist a1, ... ,an E A ,
such thatSo
and G E V. m
From now on, for nonzero constant
integers
a 1, ... , a n and anynonzero
integer
a we denote the varieties definedby
the laws w =Xal 1... xn n
and w =x a , respectively, by
’V andMa.
Also we denote thegreatest
common divisor of a i , ... , a nby
d.LEMMA 2. Let G E
B)#
be aninfinite
group.If
the set T= ~ g
EE G
I gd
=1 ~
isinfinite,
then G E ’V. Inparticular
aninfinite
group in’V-* BV
can not have aninfinite subgroup
in V.PROOF. Let X be an infinite subset of G. Let
1 ~ j ~
n be fixed.By considering
the infinite subsetsXi
=T ,
i =1, ... , j - 1,
j
+1,
... , n andXj
=X,
andusing
theproperty V*,
we find the ele- ments gi ET ,
i =1, ... , j - 1, j
+1,
... , n and x E X such thatgn n
= 1. But =1,
so we have Xa) = 1. Thus G Ee
83t ,
forall j
=1,
... , n . Since =83a U ff, we
have G e83a ,
forall j
==1,
... , n . So asrequired.
We define the class
B?( 00 ) including
all groups G in which any infinite subset X contains distinct elements Xl’ ... , xn such that~~...~"=1.
Also,
if k ~ n is aninteger,
we define the class’~(k) including
all groups G in which any subset X withI X I = k ,
contains distinct elements... , 1. It is clear
that,
andV# c V( oo ).
LEMMA 3. Let G E an
infinite
groups. ThenI
is
finite, for
any g EG ,
and anyinfinite subgroup H of
G .PROOF. Let H be an infinite
subgroup
of G and suppose, for a contra-diction,
that there is anelement g
eG ,
suchthat H : I
is infinite.Let T be a
right
transversal to in H . List the elements of T astl, t2 ,
... under some wellordering ~ ,
sothat ti
if ij .
Consider the set of all n-element subsets of T . For each t e
T(n),
list the elements ... ,
tin
of t inascending
ordergiven by ~ ,
and writet
= ... , Create n! + 1 sets, oneU a
for eachpermutation a
of theset {1,2, ... , n ~
and V: For each... , t2n ) put
if
and
put t
E V if t f1.Ua,
for any a.By Ramsey’s Theorem,
there exists an infinite subset!ToC7B
suchthat
U,,
for some a, or V.Suppose,
for acontradiction,
that then the is infinite.
By
theproperty
there exist n distinct elements such that
1,
but thent = ~ tl ,
lies in someUa,
a contra-diction.
Thus
To - for
some a.Moreover, by restricting
the order - toTo
we may assume thatTo = ~ tl , t2 , ...I and ti tj
if ij .
Hence for anyil i2
...in,
we haveNow consider a sequence
132
of 2 n + 1 indices and suppose that
2,
... ,n ~
is fixed and leta(s)
=1~. Define a sequencejl
... as follows: the first 1~ - 1 ele- mentsik -1
1(if k
= 1 this isempty), jk
=in + 1,
andthe last n - k elements
are jk +
=in+3, ---,in= (if k
= n this isempty).
ThusNow if we
put jk = in + 2
in the above sequence, we haveand thus Therefore Now if k
runs
through
theset {1,2,
... ,n ~,
so does s . Thusn
a contradiction.
It is natural to ask whether every infinite
)-group belongs
to V.The answer, in
general,
isnegative.
Infact,
there is an infinite groupsatisfying
the condition for somepositive integer
which does notbelong
to W.For
example,
we can take a group K(with
m = 2 and n to be a suffi-ciently large prime,
n >101° )
in Theorem 31.5 in[8].
Thisgroup K
isgiven by
all relations of the form A n 2 - 1 and A n =B. ,
where A and Brun
through
aspecial
set of words. Thegroup K
is2-generated
and of ex-ponent n2,
and it is a central extensionof B(2, n) (this
is the2-generat-
ed free Burnside group of
exponent n) by
acyclic
centralsubgroup ( z ~
oforder n.
Thus K is
infinite,
sinceB( 2 , n )
isinfinite,
and K n =( z ~
is a finite(central) cyclic subgroup
of K. Now we show that the set X of all ele- ments of order n in K coincides with(z~
and thus is finite. For this pur- pose we need to show that all non-central elements of K have ordern 2 .
Take an element x outside
Z(K) = ( z ~.
It follows from the construction of K that x isconjugate
in K to aproduct
where A n = z . Then= =
1,
since k is not dividedby
n . Thus x is of or-der
n 2
asrequired.
Let,
now 0 be thevariety
definedby
the law 1. ThenK E
0(n 2 ). For,
let xl , ... , xn2 be distinct elements of K. Thus ... ,X;:2
are in Kn and so there exists such that
yi
=Therefore
y1 ... yn
= c n =1,
sinceCOROLLARY 4. Let be an
infinite
group, thenis , finite.
PROOF.
By
Lemma3, ~
G :CG ( g d ) ~
isfinite,
forall g
E G. ThusG d ~
~ F,
the FC-center of G . If F is infinite then F EB1, by
Lemma1,
and so Gu lfby
Lemma2,
and thusG d
= 1. If F isfinite,
thenG d
isalso
finite,
asrequired.
PROOF OF THE THEOREM. Let G be an infinite group in
B1#
and as- sumeG fI- B1.
ThenG d
isfinite, by Corollary
4. Write H : =CG (G d ).
ThenG/H is finite and
a d E Z(H),
for any a E H. We show thatH/FC(H)
hasexponent
2 whereFC(H)
is the FC-centrea 20 FC(H).
Then the set is infinite. Let
Xl = X2 = ... = Xn = X . Then,
since G EB1#,
there exist gl , ... ,gn E H
such thatsince Write
i for
alli E { 1, ..., n 1.
ThenNow let then Y is
infinite,
sincea2f1.FC(H).
Forthere exist such that
Then
a~~"~ ~~=1
andFrom
(*)
and(**),
weget
=1,
andarguing similarly
with X == X1 = ... = Xi - 1 = Xi + 1 = ... = Xn and Xi = Y, we obtain (ad)Bi = 1 for any
i in the
set {1,
... ,n 1.
Thenad = 1,
sinceB2, ..., P ,) = 1.
Butfrom
a d
=1,
we have( a g )d
=1,
forany g in
Hand, by
Lemma2,
the set isfinite,
that is a EFC(H),
a contradiction.Therefore
H/FC(H)
is alocally
finite group,FC(H)
is finiteby
Lem-mas 1 and
2,
and so H islocally
finite. Then H can not be infiniteby
Lem-ma 2. Thus H is finite which forces G to be finite. This is a
contradiction,
which
completes
theproof.
134
REFERENCES
[1] A. ABDOLLAHI, A characterization
of infinite
3-abelian groups, Arch. Math.(Basel), 73 (1999), pp. 104-108.
[2] C. DELIZIA, On groups with a
nilpotence
condition oninfinite
subsets,Alge-
bra
Colloq.,
2 (1995), pp. 97-104.[3] G. ENDIMIONI, On a combinatorial
problem in
varietiesof
groups, Comm.Algebra,
23 (1995), pp. 5297-5307.[4] P. S. KIM - A. H. RHEMTULLA - H. SMITH, A characterization
of infinite
metabelian groups, Houston J. Math., 17 (1991), pp. 429-437.
[5] P. LONGOBARDI - M. MAJ, A
finiteness
conditionconcerning
commutators in groups, Houston J. Math., 19 (1993), pp. 505-512.[6] P. LONGOBARDI - M. MAJ - A. RHEMTULLA,
Infinite groups in
agiven variety
and
Ramsey’s
theorem, Comm.Algebra,
20 (1992), pp. 127-139.[7] B. H. NEUMANN, A
problem of Paul
Erdös on groups, J. Austral. Math. Soc.(Series A), 21 (1976), pp. 467-472.
[8] A. YU. OL’SHANSKII,
Geometry of defining
relations in groups, Kluwer Aca- demic Publishers (1991).[9] D. J. S. ROBINSON, A course in the
theory of
groups,Springer-Verlag,
NewYork (1982).
[10] L. S. SPIEZIA, A property
of
the varietyof 2-Engel
groups, Rend. Sem. Mat.Univ. Padova, 91 (1994), pp. 225-228.
[11] L. S. SPIEZIA, A characterization
of
thirdEngel
groups, Arch. Math. (Basel),64 (1995), pp. 369-373.
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