C OMPOSITIO M ATHEMATICA
J. J. M ALONE C. G. L YONS
Finite dihedral groups and D. G. near rings I
Compositio Mathematica, tome 24, n
o3 (1972), p. 305-312
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305
FINITE DIHEDRAL GROUPS AND D. G. NEAR RINGS I by
J. J. Malone and C. G.
Lyons
Wolters-Noordhoff Publishing Printed in the Netherlands
In this paper two
major questions concerning
finite dihedral groups of order2n, n odd,
anddistributively generated (d. g.)
nearrings
areinvestigated.
It is shown that the d. g. nearrings generated, respectively, by
the innerautomorphisms, automorphisms,
andendomorphisms
ofsuch a group aie
identical,
the orderbeing 2n3.
Results are also obtainedabout the ideal structure of these near
rings.
The radical isdisplayed
and it is shown that the
endomorphism
nearring
modulo the radical isisomorphic
to thering I/(q), where q depends
on n. The number of non-isomorphic
d. g. nearrings
which can be defined on such a dihedralgroup is determined. This number is
1 + 2r,
where r is the number of distinctprimes occurring
in the factorization of n.Finally,
some resultson
embeddings
aregiven.
1.
Properties
ofD2n
The finite dihedral group of order 2n will be
designated by D2n
andwill be
presented
as(a, blan, b2, abab).
Elements ofD2n
will begiven
inthe form
aXbs,
0 ~ x ~n - l,
0 ~ s ~ 1. For the remainder of this paper it is assumed that n is odd.LEMMA
1.1)
Thesubgroups of (a)
are normal inD2n.
These are theonly
proper normal
subgroups of D2n .
2)
Letk|n, k
> 1. ThenD2n/(ak) ~ D2k. D 2n
containsn/k
= t distinctcopies of D2k .
PROOF.
1)
Thenormality
of thesubgroups
of(a)
is clear. lf H aD2n
and a"b E
H, x ~ 0,
thena2
E H and H =D2n .
2)
InD2n/(ak)
the classcontaining at
serves as thegenerator
of order k and the classcontaining
b serves as thegenerator
of order 2. For any value of x,(at, axb) ~ D2k.
For0 ~ x ~ t-1,
thesesubgroups
aredistinct.
THEOREM 2.
D2n
has(n)~·n automorphisms,
2n innerautomorphisms,
and n2 + 1 endomorphisms.
306
PROOF. Under an
automorphism
a, a must map to somea’’,
with(n, y)
= 1 and b must map to an element of order2,
say aZb. Thus(a’b-’)a
=
axy+szbs.
It is a routine matter to show that any such a is an auto-morphism.
There are(n)~ possibilities for y
and npossibilities
for z.D2n
is centerless. Thus distinct elementsgenerate
distinct inner auto-morphisms.
As was noted
above, D2n
containsn/k
= tcopies
ofD2k.
The numberof ways
D2n/(ak)
may bemapped
onto any of these is the same as thenumber of
automorphisms
ofD2k, namely (k)~·
k. Thus the number ofendomorphisms
with(ak)
as the kernel is t·(k)~·k
= n·(k)~.
Fork =
1, D2n/(ak) ~ C2
which has ncopies
inD2n.
Write n = n .(1)~.
Fork = n, we have
(e)
as the kernel and areconsidering
theautomorphisms.
The
only
other normalsubgroup
isD2n itself,
which as akernel, gives
the 0 map. Thus the number of
endomorphisms
ofD2n
is2.
Properties
ofE(D2n)
E(D2n) (A(D2n), I(D2n)) designates
the d. g. nearring generated additively by
theendomorphisms (automorphisms,
innerautomorphisms)
of
D2n . (In
cases where no confusion wouldarise, En
orAn
orIn
will beused.)
In this section we use thetheory developed
in[8]
to find theproperties
ofE(D2n).
Forterminology
used but not defined in thissection,
see[8].
Let the inner
automorphism generated by
axbs bedesignated by [axbs].
In
general,
let theendomorphism
oc such that(axbs)a
=axy+szbs,
0 ~ y,z ~ n -1,
be denotedby [aY, aZb ]
where thegiven
elements arerespective- ly,
theimages
of a and b. Note that[ax]
=[a, a-2xb]
and[axb]
=la-l, a2x].
The function onD2n
which maps each power of a to e and each element of order 2 to some fixedd ~ D2n
will begiven
as(e, d).
If d has order
2, (e, d)
=[e, d].
THEOREM 3.
I(D2n)
=A(D2n)
=E(D2n)
andIEnl = 2n3.
PROOF. We use the
technique
of Theorem 2.3 of[8 ]
tostudy In . (If R
is a near
ring
such that(R, + )
isgenerated by
the elementsof S, S ~ R,
and e is anidempotent
ofR,
then R =Ae + Me
whereAe
is the normalsubgroup
of(R, + ) generated by {s - es|s
ES}
andMe
is thesubgroup
of
(R, +) generated by {es|s ~ S}.
Infact, Ae
is aright
ideal of R andMe
is a subnearring
ofR.)
First we need anidempotent of In
which willinduce a non-trivial
decomposition
ofIn . This
is furnishedby
So
[e, b]
is the ’e’ of Theorem 2.3.Working
with the innerautomorphisms
as thegenerating
set of thed. g. near
ring In ,
we see that[e, b][ax]
=[e, a- 2xb and [e, b][a’b]
=(e, a2x).
ThusMe = {(e, d)|d ~ D2n}
and!Me! =
2n. Alsowhere the
2n-tuple
is used toindicate,
inorder,
theimages
ofThe
bar 1
is inserted as matter of convenience between theimages
ofan -1
and b. Inaddition, [aXb]-(e, a2x) = (n-1)03B2.
ThusAe
is the normalsubgroup generated by fi.
Consider thatis in
Ae
and thatis in
Ae .
Itfollows
thatAe = (y)
E9(03B4)
andIAel = n2.
Thus|In|
=2n3.
An
arbitrary automorphism [aY, aZb], ( y, n)
=1,
isgiven
asyy +yô + [e, azb]. Thus In = An.
Note that all
endomorphisms
with kernel(a)
are inMe .
Considerthen an
endomorphism ’JI
with kernel(ak), kin,
1 k n. Theimage
of IF
(see
Lemma1, part 2)
isgenerated by at, t
=n/k,
andaxb, x
afixed
integer
such that0 ~ x ~ t-1.
Thus a IF =a’’t, (y, k)
=1,
andb03A8 =
ax+mtb, 0 m ::g
k -1.However, [ayt, ax+mtb] = yt03B3 + yt03B4
+[e, ax+mt].
ThusIn = En
and the theorem isproved.
Since a subnear
ring
of a d. g. nearring
need not be d. g. it is of interest to note thatCorollary
2.4 of[8]
shows thatMe
is d. g.Moreover,
M+e ~ D2n.
The nearring (03B4)
is a zeroring
whose grouppart
isCn .
The near
ring (y)
isisomorphic
toE(Cn),
i.e. it isisomorphic
to thering I/(n).
ThusAe
is a commutativering.
3. Ideals in
E(D2n)
Several authors have characterized the radical of a near
ring (for
instance, [1]
and[3]).
This radical is theanalogue
of the Jacobsonradical of
ring theory
and has the usual radicalproperties.
DEFINITION 4. A
subgroup
H of the nearring R
is anR-subgroup
ifHR c H. The radical
J(R)
is the intersection of theright
ideals of R which are maximalR-subgroups.
We now find all maximal
right
ideals ofEn .
The set of all elements ofEn
of oddorder, namely (03B3) + (03B4) + ((e, a)),
iseasily
seen to be aright
308
(left)
ideal of ordern3. Obviously,
this is theonly
maximalright (left)
ideal of odd order. Since this ideal
is,
inparticular,
a maximalsubgroup
of
En’
it is a maximalEn-subgroup.
Let 03C4 E
En
be an element of order 2 not of the form(e, d )
and leta E
En
be an element of order 2 of the form(e, d).
Then theproducts
1: . 6 and 03C3· 1: each have the form
(e, d )
and it follows that theright (left)
ideal
generated by
an element of order 2 must contain an element of the form(e, axb). Let J1 = 03B4 + (e, b).
Then theright (left)
idealgenerated by
an element of order 2 must contain
In
En
the elements of order 2 form amultiplicative semigroup
in whichIl is an
identity.
We claim that v is a unit in thissemigroup,
that p =(03B4 + (e, ax)) [a(n+ 1 )/2, b] + [e, b] is
the inverse of v. Note thatwhere t =
(n + 1 )/2.
Inparticular (ayb)03C1 = at(x+y)b,
0 ~y ~
n -1. Forv we have that
(aYb)v
=a2y-xb.
Thusand
So p and, consequently,
each element of order 2 is in theright (left)
ideal
generated by
an element of order 2. It follows that this ideal is K =(c5)+Me.
We summarize this discussion inTHEOREM 5. K =
(c5)+Me is
theprincipal right (left)
idealgenerated by
anarbitrary
elementof
order 2.Recall that
(03B3) ~ I/(n).
SinceEn - (03B3) + (03B4) + Me
it follows that anysubgroup
of(03B3)+
isactually
aright (but
notleft)
ideal inEn . Adjoining
any element to
K+
isequivalent
toadjoining
an element of(03B3)
toK + .
Thus the number of non-zero even ordered
right
ideals ofEn
isequal
tothe number of divisors of n. If
Y+
is a maximalsubgroup
of(y),
thenY+K is a maximal
right
idealwhich, automatically,
is maximal as anEn-subgroup.
Each even ordered maximalright
idealof En
is of this form.Let n
= pr11pr22 ··· prnn.
The m maximalsubgroups
of(y)
aregiven by
((eapa2p ··· a(n-1)p|e ··· e))
as p ranges over the distinctprime
factorsof n. The
intersection
of all these maximalsubgroups
isBut this says that k is
nilpotent
inII(n)
and thatis
nilpotent
inEn .
Hence the intersection iswhere w = p1p2···pm,
and |03BE| = n/w.
The intersection of all the maximalright
ideals of even order is K+(03BE)
which has order2n3/w.
Itis
interesting
to note that K+(03BE)
consists of all elements ofEn
whichare either
nilpotent
or of order 2(the
’or’ isexclusive). Intersecting
K+
(03BE)
with the ideal of ordern3,
we find thatJ(En) = (03BE) + (03B4)
+((e, a))
so that
J(En)
has ordern3/w,
consists of allnilpotent
elements ofEn’
and,
as a sum ofrings,
is aring.
THEOREM 6.
PROOF. Let
H +
be thesubgroup
of ordern3.
Then the orderof E+n/H+
is
prime
andH+
itself is abelian so thatE’
is a solvable group.By (2.2)
Theorem of
[2] En/J(En)
is aring.
But the classcontaining [a, b]
hasorder q
in thequotient
structure so thatEnIJ(En)
is a rmg withidentity
whose group
part
is acyclic
group of order q.Thus, by
thecorollary
ofp. 147 of
[4], En/J(En) ~ I/(q).
4. D. g. near
rings
onD2a
In this section we
display
allnon-isomorphic
d. g. nearrings
whichcan be defined on the group
D2n .
Since twobinary operations
onD2n
will be
studied,
the groupD2n
will be written in additive notation in this section and the secondoperation
will be referred to as themultiplica-
tion. One near
ring
of thetype
we seek is the zero nearring
onD2n,
i.e.each
product
is 0. Unless otherwisestated,
in what follows it ispresumed
that the near
rings
dealt with are not zero nearrings.
Let
(D2n, +, ’)
be a nearring.
In what follows theproperties
of multi-plication
in such a nearring
are studied. Eachendomorphic image
ofD2n
other than thesubgroup {0}
must contain an element of order 2.Hence,
in order for d ED2n
to beright
distributive and not be aright annihilating
element in the nearring
D =(D2n,
+,·), {xd|x
ED}
mustcontain an element of order 2.
But,
since the nearring obeys
the leftdistributive
law,
each row in themultiplication
tablerepresents
an endo-morphism
ofD + .
Since no element of order 2 can be anendomorphic image
of an element of(a)+,
no element of(a)+
can beright
distributive withoutbeing
aright
annihilator. Thus thegenerating (in
the d. g. nearring sense)
set must contain at least one element of order 2. Let d E Dbe a
right
distributive element of order 2. Each elementxd, x
ED,
looked at from theviewpoint
of the rows of themultiplication
table isan
endomorphic image
of d and so xd is either 0 or is an element of order310
two. In
particular,
we have ad = 0. Since not everygenerating
elementis a
right annihilator,
we have for at least one d that the kemel of theendomorphism of D+
determinedby right multiplication by d is precisely (a)+.
Thus thisendomorphism
is onto asubgroup
of order 2.Another
way of
saying
this isthat fd
=gd for any f and g
of order 2 in D. In factthis condition holds for
any d
in thegenerating set,
notjust
for d oforder 2. If d~
(a), fd
= 0 =gd.
Thus we see that themultiplication
table row of any element of
(a)
consists of 0 entries and that the rows of any two elements of order 2 are identical. This row common to the ele- ments of order 2 will be called the 2-row. Because of the additive arith- metic ofD +
and because no element of order 2 can be in the kemel of the 2-rowendomorphism,
it follows that theproduct
of two elements oforder 2 is an element of order 2 and that each element of order two is
right
distributive.Thus,
without loss ofgenerality,
we mayidentify
thegenerating
set with the set of elements of order 2.We
proceed
to determine the form of the 2-row. Let(xa + b)(xa + b) =
za + b.
Then it is also true that(za + b)(xa + b) =
za + b. Butza + b = (za + b)(xa + b) = (za + b)(xa + b)(xa + b) = (za + b)(za + b)
shows thatan element of order 2 in the range of the 2-row
endomorphism
is idem-potent.
Now let(xa)2
= ya and let d be anidempotent
element of order 2.Then ya
=d(xa) = dd(xa)
=d(ya)
and ya is fixedby
the 2-row endo-morphism.
Since any elementoccurring
in the 2-row is a fixedpoint
forthe
endomorphism,
the 2-rowendomorphism
is anidempotent
endo-morphism of D+ and,
inparticular,
the restriction to(a)+
is an idem-potent endomorphism
of acyclic
group of order n.But these last maps are determined
by mapping a
toka,
where k is anidempotent
inI/(n).
As is wellknown, II(n)
has 2ridempotents
wherer is the number of distinct
prime
factors in the factorization of n.(An
outline of the
proof
of this fact isgiven
later in thissection.)
To finishthe determination of a 2-row
endomorphism,
we must find theproduct db, d
any element of order 2. Let da = ka and db =ya+b.
Thenya+b = (ya+b)2 - (ya+b)ya+(ya+b)b = kya+ya+b.
Thusn|ky.
Let y
be selected tosatisfy
this condition. Then the 2-rowendomorphism
has the form
[ka,ya+b]
and(xa + sb) [ka, ya + b ]
=(xk+sy)a+sb.
Moreover,
((xk + sy)a + sb) [ka, ya+b]
=(k(xk+sy)+sy)a+sb = (xk+sy)a+sb,
so that each
endomorphism satisfying
the conditions on kand y
has eachelement in its range as a fixed
point.
The
multiplication being
defined iscertainly
left distributive. Considerassociativity.
Letd, f, g
E D. If d E(a)
or if d has order 2and f ~ (a),
then
d(fg) =
0 =(df)g.
Let dand f be
of order 2.Then fg
is an elementin the range of the 2-row
endomorphism
andd(fg)
=fg.
On the otherhand, df is
an element of order 2 asis f,
so that(df)g = fg. So, indeed,
the
systems
we have constructed are d. g. nearrings.
Recall that the
idempotents of I/(n)
are found two at a timeby
consider-ing integers
mi, m2 such that m1m2 = n and(m1, m2) -
1. For ml andm2 there exist
integers
cland c2
such that cl ml + c2 m2 - 1. Then cl ml and c2 m2 areidempotents
ofI/(n).
Since(c1, m2) = (c2, m1)
=1,
|c1m1| =
m2and |c2m2| = ml in I/(n). If,
for agiven
ml and m2 , thereexist ci and ci
such thatc’1m1 + c’2m2 = 1,
then cl ml -c’1m1
andc2 m2 -
c’2m2 (mod n).
Thus two 2-rowendomorphisms having
differentvalues of k lead to
non-isomorphic
nearrings
since the two k’s have dif-ferent orders. We now show that the near
rings corresponding
to[ka, yl a + b]
and[ka, y2 a + b]
areisomorphic. Thus,
for a fixedk,
we mayas well use
[ka, b] as
the 2-rowendomorphism
and we may say that thenon-isomorphic
d. g. nearrings
are the zero nearring
and those deter-mined
by
the[ka, b]
as k ranges over the 2ridempotents
ofI/(n).
Let
iD = (D2n’
+,·i)
be determinedby [ka, yia + b]; i
=1, 2.
Toshow
1D ~ 2D,
define amap 03A8
on1D
to2D
such that all’ = a. We alsowant
(y1a+b)03A8 = y2 a + b. But, having fixed a,
it is seen that this isequivalent
tohaving
b03A8 =(y2-y1)a+b.
As ll’then,
take the groupautomorphism [a, (y2 - y1)a+b]. If d, f ~ iD
and de(a),
then(df)P =
0 =
(dP)(fP).
IfIdl =
2and f
= xa, then(df)03A8
= kxa =(d03A8)(f03A8).
If
Idl
= 2and f
=xa+b,
then(df)03A8 = (Y2 + xk)a + b = (d03A8)(f03A8).
Wesummarize with
THEOREM 7. The number
of non-isomorphic
d. g. nearrings definable
onD2n is 1 + 2’’,
where r is the numberof
distinctprimes occurring
in thefactorization of n.
5. Comments on
embeddings
The theorem
given
in[7]
has as acorollary
the statement that any finite d. g. nearring
can be embedded in someE(G). However,
certain of the d. g. nearrings
of the last section can be embedded inE(G1 ) where |G1|
is much smaller than
IGI,
with G is asgiven
in[7].
Note that
D2n
QC2 ~ D4n.
ThenProposition
2 of[5]
says that thezero near
ring
onD2n
embeds inE(D4n).
The d. g. nearring
with 2-rowendomorphism [a, b]
can be embedded inE(D2n) by
thetechnique
of’right multiplications’
that is used inembedding
aring R
withidentity
in
E(R+).
Theembedding given
in[6] shows, essentially,
how to embedthe near
ring
with 2-rowendomorphism [0, b]
inE(D4n).
One wonders if each of the d. g. nearrings
of Section 4 can be embedded inE(D4n).
312
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[1] A radical for near-ring modules, Michigan Math. J. 12 (1965), 377-383.
J. C. BEIDLEMAN
[2] Distributively generated near-rings with descending chain condition, Math. Z.
91 (1966), 65-69.
G. BETSCH
[3] Ein Radikal für Fastringe, Math. Z. 78 (1962), 86-90.
J. R. CLAY AND J. J. MALONE
[4] The near-rings with identities on certain finite groups, Math. Scand. 19 (1966),
146-150.
H. E. HEATHERLY AND J. J. MALONE
[5 ] Some near-ring embeddings II, Quart. J. Math. Oxford Ser. (2) 21 (1970), 445-448.
J. D. MCCRACKEN
[6 ] Some results on embeddings of near rings, Master’s Thesis, Texas A & M Universi- ty, 1970.
J. J. MALONE
[7] A near ring analogue of a ring embedding theorem, J. Algebra 16 (1970), 237-238.
J. J. MALONE AND C. G. LYONS
[8] Endomorphism near rings, Proc. Edingburgh Math. Soc. 17 (1970), 71-78.
Oblatum 15-VI-1970 Department of Mathematics Worcester Polytechnic Institute Worcester, Mass., U.S.A.