A NNALES DE L ’I. H. P., SECTION A
M. S IRUGUE J. C. T ROTIN
Finite groups generated by symmetries
Annales de l’I. H. P., section A, tome 3, n
o2 (1965), p. 161-174
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161
Finite groups generated by symmetries
M. SIRUGUE and
J.
C. TROTINAnn. Inst. Henri Poincaré,
iaIll!. aW 1II. .
Vol. III, nO 2, 196,
Section A :
Physique théorique.
SUMMARY. 2014 In this paper, we
study
the finite groupsgenerated by
sym- metries in a n-dimensional vector-space over thereal,
and also the rational -numbers;
we define also a « root pattern », a «simple
root system », andnew
diagrams including
the setof Dynkin diagrams
as asubset;
the alloweddiagrams
areshown;
if n >2,
two newdiagrams
arefound,
when we choosethe field of real
numbers ;
over the field of rationalnumbers,
the solutionsare
precisely
theWeyl
groups ofsimple
LieAlgebras.
These groups can be used as an essential tool to introduce certain LieAlgebras,
and for classi-fying
the irreducible modules[1] [3].
I - SYMMETRIES
Let us denote
by
V a finite-dimensional vector-space over the field R of realnumbers,
or over the fieldQ
of rational numbers. If S is a linear involutivemapping
inV,
i. e.satisfying
S2 = I(identity),
we define the follow-ing
operators :One can
easily verify
the relations :It follows that
E+
and E_ areprojection
operators associated with adecomposition
of V into a direct sum ofsubspaces V+
andV-;
we have then:The elements
belonging
toV ~
arespecified by
the conditionReciprocally,
if V is a direct sum ofsubspaces V+
andV-,
the formula(2)
defines an involutive operator. S is a symmetry when V- is one-dimen-
sional ;
thus :DEFINITION. - A symmetry S is a linear involutive operator
acting
in afinite-dimensional vector-space V
[over
the field of real numbers or overthe field of rational
numbers],
the subset of its fixedpoints being
anhyper- plane [i.
e. asubspace
with one dimension less thanV].
Let E be a linear
mapping
from V into thefield,
such that for agiven
element the
following
relations hold :Since
S(x) -
x and ifjc e V_, S(x)
=S(Àa) == - x
= 2014 ~thus,
Vx EV, S(x)
= x - the symmetryverifying S(a) _ -
a.From now on, we shall write such a symmetry as
S~
II. - ROOT-SYSTEM
Let G be a finite group
generated by symmetries acting
in V. We suppose that G is an irreducible set ofmappings.
If we know a finite set of symme- triesgenerating G,
we can choose for any symmetryS;
amongthese,
and also among those obtainedthrough products
of suchgenerating symmetries,
a vector such that
Si
=Sa; ;
we call A the set ofvectors { ± ai },
or « root- system »,satisfying:
c)
V isspanned by
A.a)
Derives from the definition of the setA;
we can takeSa(b)
e A sincethe
following mapping
is a symmetrybelonging
toG,
as aproduct
of gene-(1) i. e. : « for every x belonging to V ».
FINITE GROUPS GENERATED BY SYMMETRIES 163
rating symmetries : SaSbSa =
so,(b)
results from apeculiar
choice.Clearly,
ifSa(b)
=xb, 1,
fromS;
=I;
thus(b)
is inagreement
with
(a). Now,
if Aonly
spans a propersubspace
ofV,
it wouldbe,
atleast,
a vector x #0, belonging
to everyhyperplane Hai
=i is fixed but X runs over the
field) ;
so, it would be a vector x E nand x would be an invariant vector
by
eachS~,
and alsoby
the wholegroup
G,
but G isirreducible,
andonly
the null vector is invariantby
G.REMARK. - From
(2),
we see :it follows :
Each
element g
E G can be written as a finiteproduct
ofsymmetries (since
G isfinite) ;
from(3),
we derive :By
a recurrent process itimmediately
follows :SnSm
...SbSa
= A and :Further,
if a is a root with ga = aa, since G isfinite,
aninteger
p can be found with: gpa = apa = a, and necessary À = ± 1. Over the dual- space V* ofV,
apositive
definite scalarproduct
is definedthrough
theformula :
if f and g
are two linearmappings
from V into thefield; by duality,
aposi-
tive definite scalar
product (x I y)
is defined ontoV,
which is an invariantproduct by
every linear operatorconserving
the setA,
thus[from (4)], by
every g E G.
From now on,
consequently,
V is an euclidean space and everymapping
of G is
orthogonal
with respect to thisproduct.
G is asubgroup
of theorthogonal
group. It will be easier to write down a symmetryacting
as :Or,
morebriefly:
III. - SIMPLE ROOTS
The set A
being
a finite setgenerating V,
we may conclude:3xo E V (i.
e. xo can befound, belonging
toV)
such that(xo a) ~
0(Va
EA).
Weshall
always
denoteby E
the set of roots « a » such that(xo
>0, (- ~)
the set of roots such that
(xo [ a)
0. ~ and(- ~) give
apartition
for A:V will be
equipped
with apartial ordering compatible
with its structure ofvector-space
over the real(or
therational) numbers ;
let us write :[K(E)
is the set of linear combinations with coefficients >0,
of elementsbelonging
to~] ;
thus thepositive
roots are the roots whichbelong
to E.Let us consider the subsets Q c E such that :
(the
inclusionclearly suffices)
and define the system ofsimple
roots asThis is a rather direct
(but
difficult tohandle),
definition ofII ;
let usgive
two remarks which characterize the elements of II.
REMARK. -
If xi
~ 03A3and xi ~ K(03A3 - xi), ((E - Xi)
is the set Swith x;
missing) then x;
E n.It suffices to prove that if it exists an Q such that
Q, K(S~) ~ K( ~) ; actually,
if Qand
which is not
equal
to sinceK( ~ -
Remark Xj E IIimplies K~ ~ - x~).
If not, the set E - Xi = Q generates
K(03A3)
and does notcontain xi
soas n = II n
Q,
there is a contradiction.It is necessary to prove that n is not empty, or
equivalently
that there165
FINITE GROUPS GENERATED BY SYMMETRIES
exist roots such
that xi ~ K(S 2014
this isclear, according
to thefollowing
remark : if then
According
to the fact that(x xo)
> 0 for every x EK(~)
so
and
So if every x; E ~ was such that x E
K(~ - Xi)
one could construct asequence of
03A9i, 01
== S 2014 xi,03A92
=03A91 -
x2, ... ,Qp
=C,
each of themgenerating K(~),
which is absurd.- It is clear then that from the
previous
remarks ,and we shall derive with the
help
of a lemma that II is in fact a basis for V.LEMMA I. - a e A cannot be written as with
Indeed,
we can suppose a »0; then,
one would getand then the
following
relation would be deduced :Such a system is not
possible (since x,
> 00).
If 03BBi
> it would follow:But this
relation,
written as :shows that x, would not
belong
to M.Now if OGi, x/ e
II,
x~ OCj :and from condition
(b)
for root-systems, EA;
from the lemma I weconclude that
and:
Now we are able to prove the linear
independence
of theocis (over
thecorresponding
field R orQ according
to ourprimitive
choice of thefield).
If the
«js
werelinearly dependent,
one could writeEvkak
= 0(vk # 0,
k
necessarily
somevgs
would be >0,
others0);
one coulddeduce,
consider-ing separately
these terms :(with InJ==~;~,~>0
and the familiesI,
J ofindices I, j verifying I,
J #0).
Using (ai x,) 0,
one could obtain from :contrary to > 0
(it
makes no difference between R andQ).
FINITE GROUPS GENERATED BY SYMMETRIES 167
LEMMA II.
2014 V(w, x,),
(X E~,
x, E II(with
x 7~a ),
then E. Wecan write :
« is not
proportional
to the numbersÀj (./ 7~)
are > 0 and at least oneamong
them 03BBj0 ~
0. ~ 0394 and its coefficients are alltogether > 0,
or all
together 0; Àjo
>0,
thus all are > 0 and E E.= - «i E
(- ~),
there isonly
onepositive
root, «;, such that itsimage through Sai belongs
to(- L).
IV. - TOTAL ORDERING
E is
always
considered as a fixed set; with respect to the basis(«i,
«2, ...,«n)
we consider the
lexicographic ordering,
noticed as x > y(we
decide«1 > «2 ... >
«n) ;
it is a totalordering
over Vcompatible
with its structureof vector-space over R or over
Q
if the elements x > 0 are those written asIf x » y
then x > y, and if a e A with a >0,
then a E ~.LEMMA III. - Yx E
K(~) (= K(II)),
E II such that x >(x # 0). If,
V«; EII, (x 0,
one could deduce’
it would follow x =
0;
thus Xio can befound,
such that(x I OCio)
>0 ;
fromFundamental theorem. -
Every root
can be written asSIS; ... Sk«l,
where (1..;, (1..j, ..., «k, «i are
simple
roots[S
=SC(i’ Sj
-SC(j’
and so on... ] :
Let us denote
by
W the set of roots which have the formS~Sj
...(these
are roots from property(b)
ofroot-systems) ;
since = (1..1, x/ E W and everysimple
rootbelongs
toW; further, S,W c:
If « is aposi-
tive root, let us suppose that all the
positive roots p satisfying
« >p, belong
to the set
W ;
«; can be found(from
lemmaIII)
such that « (Xi,from lemma
II,
we deduceS;« » 0,
thusS,x
EW,
and « = W too;if « = «;, then « E W
(since M c= W):
in both cases « E W and «n is asimple
root
belonging
to W andsatisfying
« > «n(V Cl
E~),
so that we seeby
arecurrent process that
W =~ S; further,
if « EW, (- a)
E W because ifThus W >
(- ~)
and we conclude W = A.From the formula
gSexg-l
=(Vg
EG),
which is an immediate gene- ralization ofSaSbSa
=SSa(b),
we see that for every root rJ.. =SiSj
...Skal,
the
corresponding
symmetry is’
Sa = (SiSj
... ...Sk)-l
=S;Sj
...SkSlSk
...S/S,.
And every symmetry
Sa
is obtainedthrough products of symmetries Sex corresponding
tosimple
rootsonly.
V. - CLASSIFICATION
Now,
in order to obtainG,
we must consider allpossible
sets of roots,or all
possible corresponding
sets ofsimple
roots ; ifS
andSj
are two sym-metries, H~
and Hjthe corresponding
fixedhyperplanes, Ht
nHj
is a sub-space of two dimensions less than
V,
which is left fixedby
themapping
V is the direct sum V =
(Hi
nHj)
+ whererij
is aplane,
overwhich
SiSj
induces arotation;
the rotationangle
is necessary commensurable with 7c, since the order ofSiSj is
finite.Further,
there are at least two rootsin a,
b,
theangle
between thembeing precisely
the rotationangle,
whichcan be written as
2014 , - being
an irreduciblefraction;
we can now, in them m g ’ ’
rij-plane,
construct asubsystem
of roots,departing
from both the roots a,b, constructing
the rootsSa(b)
andSb(a),
then the new ones obtainedby
sym-metries of these roots,
through
eachother,
and so on. We obtain a sub- system as thefollowing
one :169
FINITE GROUPS GENERATED BY SYMMETRIES
Looking
at such a system, since everypositive
root must be a linear combination ofsimple
roots withpositive coefficients,
we see that the twosimple
roots which generate the system, are in thefollowing position :
the
angle
between them is m2014. Thus,
between any system of twosimple
roots, ex, and rJ.j, the
angle
is7u 2014 2014
=6~ where nij
is aninteger.
Then,y
simple
roots can bereplaced
with unitlength
vectors ai, ay, and we have to search for allowableconfigurations
definedby
cos2aij
= cos2i5 where
isnij
an
integer >
2(cos eij 0).
It is useful to consider
4(a;
= 4 cos22014,
and to define adiagram
forany one allowable
configuration,
as a collection ofpoints
=1, 2,
..., n, and linesconnecting
theseaccording
to the rule : ui and uj are not connected if(a; I aj)
= 0 and ui and Uj are connectedby 4(a;
=1,
2 or 3 lines when thisequality
holds[i.
e.respectively when nij
=3,4
or6] ;
the casenij = 2
corresponds
to(a;
= 0. If is not aninteger
butverifies :
p an
integer,
u~ and Uj will be connectedwith p lines, together
with another dashed line. Forexample,
if ni, =5,
24(a; 3,
thediagram
isThus,
when n~, =3,4
or6,
werecognize
theDynkin diagrams,
and thecorresponding
groups are the well-knownWeyl
groupsof simple
LieAlgebras.
But, otherwise,
if n =2,
all values =2, 3,
4 ... aresolutions,
and ifn >
2,
there areonly
twosolutions, because, looking
at connecteddiagrams,
one sees :
1 ~
If
n is the numberof
vertices(points) of
adiagram,
then the numberof pairs of
connectedpoints
is less than n.PROOF. - Let
If
(a; I a;) ~ 0,
then2(at I a;)
- 1 .Hence the
inequality
shows that the number ofpairs
a~, OJ with(a
0is less than n.
20 A
diagram
contains nocycles (a cycle
is a sequence ofpoints
Ub ..., uk such that ui is connected to i k - 1 and uk connected toui).
PROOF. - The subset
forming
acycle
violates the former condition.30 The number
of
non-dashed lines(counting multiplicities) issuing from
avertex is less than
four.
PROOF. - Let u be a vertex, vi, V2, ..., vk the vertices connected to u.
No two v; are connected since there are no
cycles.
Hence(v
=0,
i# j (now
forsimplicity,
we denote in the same waysimple
roots andvertices).
In the space
spanned by
u andthe Vi
we can choose a vector vo such that(vo
= 1 and vo, vi, ..., vk aremutually orthogonal.
Since u and thev1, i >
l,
arelinearly independent,
u is notorthogonal
to vo and so(u [
0.Since
Hence
Since
4(u v~)~
is the number of non-dashed linesconnecting
uand vl
whenever there is no dashed line betweenthem,
or otherwise is greater than thisnumber,
the result follows.4° With any dashed
line,
there are at least two non-dashed linesissuing
from a vertex
the
first case, nijincreasing,
is nij =5,
when~~;
=7c 2014 .~.
It
readily
follows that when the dimension of V is n >3, and nij 7,
there is no solution because the
corresponding diagrams (we speak
aboutconnected
diagrams)
are such that there are at least four non-dashed linesissuing
from one vertex :171
FINITE GROUPS GENERATED BY SYMMETRIES
5° Let IT be an allowable
configuration
and let Vb v2, ..., vk be vectorsof 03A0
such that the
corresponding points of
thediagram form
asimple
chain inthe sense that each one is connected to the next
by
asingle
line. Let H’ bethe collection
of
vectorsof
IT which are not in thesimple
chain Vb ..., vkk
together
with the vector v =vt;
then II’ is an allowableconfiguration :
1
PROOF. We have
2(v~ ~ vl+I)
==-.1,
for i =1, 2,
..., k - I . HenceSince there are no
cycles (v;
= 0 if ij, unless j
= i + 1. Henceand v is a unit vector.
Now let u E
M,
u # v;. Then u is connected with at most one of the v;, say vj, since there are nocycles.
Thenas
required;
thediagram
of FT is obtained from that of IIby shrinking
thesimple
chain to apoint ;
thus wereplace
all the verticesby
thesingle
vertex vand we
join
this to any u EII,
u # v;by
the total number of non-dashed linesconnecting
u to any one ofthe vj
in theoriginal diagram;
we get the same result for dashedlines,
butalways
one dashed line will connect two vertices.Application
of this to thefollowing graphs :
reduces these
respectively
to :But these last ones are not allowable
(four
non-dashed linesissuing
froma
vertex).
The
possibilities
are among thefollowing
type ofdiagrams :
(i.
e. thereis,
on eachside,
a finitechain).
Consider the
peculiar
one :And let us write
Since
we have :
173
FINITE GROUPS GENERATED BY SYMMETRIES
And
By
Schwarzinequality :
p
and q
areintegers > 1;
if n >3,
q, forinstance,
is > 1. The solutionsare:
corresponding
to thefollowing diagrams :
When the field is
R,
the field of realnumbers,
it is easy to see that these twodiagrams give
actual solutions since thecorresponding
euclidean systemscan be constructed.
When the field is
Q,
the field of rationalnumbers,
one canmultiply
thenon-simple
rootsby integer multipliers
in such a way that the new ones canbe written as :
with m;
integers > 0, «;
EIT;
now, these are considered as newnon-simple
roots, and the condition :
shows that
necessarily,
the scalars -~!~
now on, we
drop
the~!~7
’((
prime
)) forbrevity)
arcintegers.
Moregenerally,
the scalars- 2 (03B1 | 03B2)
(P)P)
(Vx, ~
EE)
arenecessarily integers,
since every root can be considered assimple, according
to the choice of xo, and E. From :We deduce that the
scalars 2014 ’ ’ ’
areintegers verifying:
So we find
precisely
as solutions allWeyl
groups ofsimple
LieAlgebras,
whatever the dimension of V may be.
BIBLIOGRAPHIE
[1] N. JACOBSON, Lie Algebras, chap. VII, Interscience Publishers, 1962.
[2] Séminaire C. CHEVALLEY, 1956-1958, exposé n° 4.
[3] N. STRAUMANN, Branching rules and Clebsh-Gordan’ Series of semi-simple.
Lie Algebras (preprint).
ACKNOWLEDGEMENTS
We are indebted to Dr. H.
Bacry
and Dr. N. Straumann forreading
themanuscript
and for their critical comments..