C OMPOSITIO M ATHEMATICA
R. R AGHAVENDRAN Finite associative rings
Compositio Mathematica, tome 21, n
o2 (1969), p. 195-229
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195
Finite Associative Rings1
by
R.
Raghavendran
Wolters-Noordhoff Publishing Printed in the Netherlands
Introduction
Throughout
this paper thesymbol
R will be used to denote afinite associative
ring
with amultiplicative identity
1 :A 0. Weuse the notation
GR
for themultiplicative
group of the invertible elements of thering
under consideration. Thesymbol
S will beused to denote an
arbitrary ring -
notnecessarily finite,
and notnecessarily possessing
anidentity
element. The term"subring"
isused to mean a
subring containing
theidentity element,
when oneexists,
of thelarger ring.
Alsoby
"subfield" we mean asubring which,
whenregarded by itself,
is a field(commutative).
As isusual,
Z denotes thering
of allintegers
and p denotes anyprime integer greater
than orequal
to 2. We use F to denote the Galoisfield
GF(q) where q
=pr. Finally,
for any set A weuse |A|
todenote the cardinal number of elements in that set.
In this paper we determine the structures of
prime-power rings, (i.e. ) rings
whose orders are powers ofprimes,
under various condi- tions. For this purpose webegin by considering, in §
1, a set W1which is
simultaneously
a left vector space and aright
vectorspace over the same field
P,
and which issubject
to the condition thata(xb)
=(ax)b
for all a, b in P and for all x in W1. When W1 hasonly
a finite number of elements we show that it will have at least one"distinguished
basis" - fordefinition,
refer to thebody
of the paper - over the field
P,
and remark as to how this resultcan be used to
give
aproof
of the well-known theorem of Wedder- burn on finite divisionrings.
Twogeneralisations
of this theorem to the case ofcompletely primary rings
with a finite number ofelements are also
given
in the later sections of this paper.(Cf.
Ths. 5 and
7.)
1 This is a revised version of the thesis submitted by the author for a Doctorate
degree of the Annamalai University, under the guidance of Professor V. Ganapathy Iyer. This work was supported in part by the Government of India through a Scholarship.
In §
2 we consider the situation where the zero divisors of thering
R form a group under addition. Afternoting
that thering
must then be a
completely primary ring (not necessarily
commuta-tive),
we exhibitR,
in twospecial
cases, as aring
of matrices over a field.(Cf. § (2.4).)
In §
3 westudy
aspecial
class ofrings
which includes the Galois fields and therings Z/(pn).
It seemsappropriate
to callthese
rings by
the name Galoisrings.
For their definition see§ (3.1)
and for some of theirproperties refer § (3.8) and § (3.9)
below.
In §
4 we consider the situation where aring
R contains a sub-field F. After
noting that |R|
=(|F|)n
for somepositive integer
n,we describe
(in
Ths. 10 and11 )
the structures of all suchrings
when n = 2 and when n = 3.
In §
5 we consider aproblem posed by
Ganesan[1,
Remark 1, p216]
andgeneralised by Eldridge
in twoprivate
communications to Ganesan. Theproblem
may be stated as follows: "S is anyring
with N2 elements
exactly
N of which are left zero divisors in S.To find all the
possible
structures of thering
S." Acomplete
solution of this
problem
may be found in Th. 12 below. Onespecial
case of this theorem may however be mentioned here. If such a
ring
S does not possess anidentity element,
then S will be iso-morphic
to thering
of all 2 X 2 matrices of theform a o)
witha, b
ranging
over a finite field.In the final section of this paper we determine the structures of all
rings (not necessarily possessing identity)
withp2 elements,
andthe structures of all
rings, possessing identity,
withp3 elements, where p
is anyprime.
It isfound,
inparticular,
that(i)
there isessentially only
one noncommutativering
of orderp2,
e.g. aring
which is
isomorphic
oranti-isomorphic
to thering
of all 2 X 2matrices oi the form
(a0 ô
with a, b in the fieldGF(p),
and(ii)
towithin
isomorphism
there isonly
onering
of orderp3,
withidentity,
which is not
commutative,
e.g. thering
of all 2 X 2 uppertriangular
matrices over the field
GF(p).
In conclusion the author wishes to thank Professor V. Ganapathy Iyer for his encouragement and guidance during the preparation of this paper. Thanks are due to N. Ganesan for having shown the author the two communications received from
Eldridge, referred to above. Special thanks are due to J.-E. Bjôrk (of Stockholm University) for having gone through an earlier version of this paper and for giving
some suggestions which enabled the author to make some improvements in the contents, as well as in the presentation, of the paper.
Section 1
(1.1)
In this section we consider a set 9N whichis,
at the sametime,
a left vector space and aright
vector space over a fieldP,
and which is
subject
to the condition thata(xb) = (ax)b
for alla, b in P and for all x in 3R. Thus M is a
( P, P )-unital
module with P a field. We nowgive
two definitions which will be convenient in thesequel.
DEFINITIONS. Let m be a
(P,P)-unital
module with P a field.(i)
If x is an element of 3R such that there exists anautomorphism
a of the field P with xa = a03C3 · x for all a in
P,
then x is to be calleda
distinguished
elementof
9N over P.(ii)
Let{xi :
i~ I}
be a basisof 3R
regarded
as a left vector space over the field P. If each element of this basis is adistinguished
element overP,
then theset
{xi : i
EIl
is to be called adistinguished
basisof
W1 over thefield
P.The
following
comments are in order. First of all we remark thatthere is no
point
in these definitions if 3K =(0),
or if 3R is one-dimensional over
P,
or if we hadpresupposed
that xa = ax for alla in P and all x in m. We may,
therefore, neglect
these rathertrivial cases.
Secondly
we notethat,
in Definition(i),
if the ele-men t x were not zero, then the
automorphism 03C3
will beuniquely
determined
by x
so that a may be called theautomorphism
of Passociated with the
distinguished (nonzero)
element x of W1. Third-ly,
we remarkthat,
in Definition(ii),
theautomorphisms
associatedwith any two distinct elements of a
distinguished
basis may be different from each other.Finally,
we note that adistinguished
basis of 9N is a basis for 9N also when it is
regarded
as aright
vectorspace over P - but it is clear that the notion of
"distinguished
basis" is more
special
than that of a "two-sided-basis".The
question
thatnaturally
arises now is whether there existsa
distinguished
basis for any two-sided unital module M over anygiven
field P. Thefollowing
theorem shows that when M has afinite number of elements - the case which is more than
adequate
for
applications
in thepresent
paper - the answer is in the affirmative.THEOREM 1. Let WC be a
f inite-dimensional ( F, F)-unital module,
where F is the Galois
field GF(q).
Then W1 possesses at least onedistinguished
basis over thefield
F.PROOF. We suppose
that m ~ (0),
and start with anarbitrary
basis
{y1, ···, yn}
of 3Rregarded
as a left vector space over F. Letg be a fixed
cyclic generator 2 (=
agenerator
of thecyclic
multi-plicative
group of the nonzeroéléments)
of the fieldF,
and letfor some elements gij in F. We can have these n
equations together
in the matrix form
Yg
=GY,
where Y =(Y1’...’ Yn)T
is thetranspose
of the row matrix formedby
the basis elements yi, and G =(gij)
is an n X n matrix over the field F. We thenget
Y .
gk
= G k. Y for everypositive integer
k.Now,
forarbitrary
n X n matrices
A,
B overF,
theequation
A Y = BYimplies
thatA =
B,
since the set{y1, ···, yn}
is leftlinearly independent
overF. This observation shows that G(q-1)
equals
theidentity
matrixof order n over
F,
and that themapping
is a
ring isomorphism.
So we see that the zero matrix of order nand the powers of the
(nonsingular)
matrix G form a field L(say)
of order q. As the minimal
polynomial
of the matrix Gsplits
overthe field F into distinct linear
factors,
there is anonsingular
matrix
Q
of order n such thatQ ’
G ’Q-1
=diag (g1, ···, gn )
- D(say)
is adiagonal
matrix over the field F. For eachfixed i,
andfor
arbitrary integers
s, t we find that theequation gsi
=g’
implies
that Gs - Gt is asingular
matrixbelonging
to the field Lobtained
above,
and hence that Gs = Gt. From this we can con-clude
that,
for eachfixed i,
themapping
is an
automorphism
of the field F.If X =
Ç ’
Y is thetranspose
of the row matrix(x1, ···, xn )
ofelements xi in
m,
then asXg
= DX and as g is acyclic generator
of the field
F,
we see that(xi , ..., xn}
is adistinguished
basis of3R over F.
This
completes
theproof
of the theorem.(1.2)
REMARK. We can use the above theorem togive
aproof
ofthe celebrated theorem of Wedderburn on finite division
rings.
More
specifically,
we may use the above theorem in theplace
of the2 The author owes this terminology to Mr. Bjôrk.
last theorem in a paper of Zassenhaus
[5]
in order tocomplete
theproof
of Wedderburn’s theorem.Section 2
(2.1)
Thefollowing easily proved results,
due to Ganesan[2],
are needed for our purpose, and so are stated here for convenient reference.
Let S be a
finite
associativering,
notnecessarily possessing
amultiplicative identity.
Then thefollowing
results hold:(i ) 1 f
there is an element x in S which is not aleft
zerodivisor,
then the
ring
S possesses at least oneleft identity.
(ii) Il
there is an element x which is aright
zero divisor but is not aleft
zero divisor inS,
then every element in thering
S(==
x -S)
is a
right
zero divisor in S.(iii) Il
S possesses amultiplicative identity,
then every non- invertible elementof
S is a two-sided zero divisor in S.(2.2)
Let R be a finitering
withidentity
1 =1=- 0, and letJ
denote the set of all the zero divisors in R.
Obviously
we needconsider
only
the case where1 =1=- (0),
and we assume this in this section. A consideration of the situationwhere 1
is an additivegroup is found to be fruitful. As an immediate consequence we have the result that R
will, then,
be acompletely primary ring
with
i
as its radical.For,
as R cannot have one-sided zerodivisors,
we see
that J
will be an ideal in R - infact, J
will be theunique
maximal left ideal in
R,
sothat J
will be the Jacobson radical of thering.
As every element of R notin J
is an invertibleelement,
we see that the
quotient ring R/J
is a divisionring,
so that R isa
completely primary ring.
We
proceed
to obtain some moreproperties
of such aring
R inthe
following
theorem which is fundamental for the purposes of thepresent
paper.THEOREM 2. Let R be a
f inite ring
withmultiplicative identity
1 =1=- 0, whose zero divisors
form
an additive groupJ.
Then(i) J
isthe Jacobson
radicalo f R;
(ii) I RI
-pnr,
andIII = p(n-1)r for
someprime
p, and somepositive integers
n, r;(iii) Jn
=(0); 3
3 In an earlier version of this paper, this was given as: x c- j implie s xn = 0. The present form is due to Mr. Bjôrk.
(iv)
the characteristicof
thering
R ispk for
someinteger
k with1 k ç n; and
(v) i f
the characteristic ispn,
then R will be commutative.PROOF. We have
already proved (i)
and noted thatRj J
is adivision
ring.
AsR/J
isfinite,
we see that it is the Galois fieldGF(pT)
for someprime
p and somepositive integer
r. As the ele-ment p -
1belongs
to the nil idealJ,
we find that the additive order of 1 ispk
for somepositive integer
k. Thisimplies
that|R| (
=pN,
and thenthat |J| = ?’JN-r
for somepositive integer
N(greater
thanr).
So we haveonly
to provethat r N
in order tocomplete
theproof
of(ii).
For this purpose we choose a fixed element gl in R such that(g1+J)
is acyclic generator
of the fieldR/J ~ GF(pr).
As the invertible elements of thering
R form amultiplicative
groupGR
of order(pr-1) · pN-r,
we see that themultiplicative
order of gl is(pr-1) · ps.
for somenonnegative integer
s.Wiiting
g =gle’
we find that we have obtained anelement g with the
following properties:
(A)
g is an element ofGR
withmultiplicative
order(pr-1), (B)
forintegers ce, fl
the statement(ga_gP)EJ implies ga
=g .
(A)
isobvious,
and(B)
then follows from the fact that(g + J)
alsois a
cyclic generator
of the fieldR/ J.
The existence of an element g with the above-mentionedproperties
will be found useful on a number of occasions in thesequel.
If we now ivrite x - y
for x,
y in Rwhen,
andonly
whenx =
g’ -
y for aninteger
«, we see that ~ is anequivalence
relationon the elements of R.
As,
for any nonzero element x of R theéquation g03B1 · x
=e - x implies (g03B1-g03B2)
EJ
and therefore thatg03B1 = g03B2,
we see that thepN-1
nonzero elements of Rsplit
intoequivalence
classes where each class containsexactly pT-1
elements. It follows that
(pr-1)|(pN-1)
and then thatriN.
If wewrite N = nr, we see that the
proof
of(ii)
iscomplete.
The
argument
of theprevious paragraph
shows also that the number of elements in any left ideal in R is a power ofpr.
So in thestrictly descending sequence J, J2, ... ,Jm
of the powers of thenilpotent ideal J
we must havem n,
and in any case, we haveJn
=(0).
Thus(iii)
isproved,
and(iv)
followsimmediately.
In order to prove
(v)
we first form the setof
pr
elements and observethat,
for elements a, b inF1
the state-ment
a - b ~ J implies a
= b. If we now assume that the character-istic of R is
pn,
we canshow, by
induction onk, that,
for elementsak ,
bk
ofFi
theequation 03A3n-1k=0 pk·ak
=03A3n-1k=0 pk - bk
willimply
thatpn-1 · (ak-bk)
= 0, and thenthat ak = bk
for k = 0, ’ ’ , n -1.This shows that every element of R will be
(uniquely) expressible
in the form
Y"-l pk ·
akwith ak
inF1,
so that R will be a commuta-tive
ring.
This
completes
theproof
of the theorem.(2.3)
In this subsection we collecttogether
a number of mis- cellaneousproperties
of aring
of thetype
considered in Th. 2.Throughout
this subsection thesymbols R, J,
p, r, n are as in Th. 2.(i)
We first remark that anysubring R1 of
R is also aring of
the
type
considered in Th. 2.For,
if x is any element ofR,
thereexists a
positive integer
m such that xm = 0 or aem = 1according
as x does or does not
belong
to the setJ.
From this we see that anelement x of the
subring R1
will be invertible(a
zerodivisor)
inR1 if,
andonly
if it is invertible(resp.
a zerodivis or )
in thelarger ring R,
so that the setJ’1
of all the zero divisors ofRi
isJ
nR1.
This proves the remark made
earlier,
and if pi, ri, ni(with
obvious
notation)
refer to thesubring Ri,
we have pi = p, and r1 as a factor of r, becauseGRl
is asubgroup
ofGR.
There seemsto be no such
simple relationship
between theintegers
ni and n.Of course, the characteristic of
Ri
is the same as that of R.(ii)
We next observe that anyhomomorphie image R1 -=F (0) of
R is also a
ring of
thetype
considered in Th. 2.For,
the kernel K ofa nontrivial
homomorphism
of R is a nil ideal inR,
and it can beeasily
verified that an element x of R will be invertible in Rif,
andonly
if the element(x+K)
is invertible in thequotient ring R/K.
This proves the assertion made
above,
and ifJ1’
p1, ri , ni refer to thehomomorphic image R1 ~ (0)
ofR,
we see that pi = p, r1 = r(this because IKI
is a power ofpr), n1 ~
n, andJn1 Ç K.
In caseJn-1 =F (o )
we haveactually Jnl
=K,
from which we can conclude that there are at least n -1 nontrivialhomomorphisms
on aring
of Th. 2 when
Jn-1 ~ (0).
(iii)
Then we remark that themultiplicative
groupGR
is solvable.For,
as thequotient ring R/J
iscommutative,
we find thata-1 . b-1 - a - b e
{1+J}
for all a, b inGR,
and as1+J
is amultipli-
cative
subgroup
whose order is a power of aprime
we can con-clude that
GR
is solvable.(iv)
LetG1 be
thecyclic
groupof
orderpr-1 generated by
theelement g introduced in the
proof of
Th.2(ii). Il G2
is anysubgroup
o f
orderpr-1 in the
groupGR,
then thesubgroups G1
andG2
areconjugate
with each other inGR.
This follows from theSylow theory
of finite solvable groups, since the order of the
subgroup G1
isprime
to its index in the(solvable)
groupGR.
(v)
LetG1
be as in(iv)
above and let N denote the normaliser ofG1
in the groupGR.
For elements a inG1,
b in N we havea-1 · b-1 · a · b E
G1
n{1+J} = {1},
so that we find that the norma-liser
of
thesubgroup G1
coincides with the centraliserof G1
in thegroup
GR .
(vi)
LetF1
be the set introduced in theproof of
Th.2(v). Il
thegroup
GR
contains a normalsubgroup of
orderpr -l,
then the setF1
will be contained in the centre
of
thering
R.For,
ifG1
is themultiplicative
group of thepr -1
nonzeroelements of the set
F1,
the result in(iv)
above shows thatG1
isthe
unique
normalsubgroup
of orderp’’-1
inGR,
and the result in(v)
above then shows thatG1
is contained in the centre of the groupGR. Now,
as the statements x ER, x ~ GR imply
1+x EGR,
we see that every element of the
ring
R commutes with every element ofG1.
The desired result now follows.(vii)
In theproof
of Th. 2 we introduced the setof
pr elemcnts,
whieh looks very much like the fieldGF(pg).
Sowe will be
naturally
interested inknowing
as to when this set willbe a subfield of R. The obvious necessary condition -
namely
that the characteristic of R should
be p -
iseasily
found to bealso sufficient. To see
this,
assume that the characteristic of Ris p
and take two distinctelements a,
b ofF1
so that a-b EGR .
If
R1
is thesubring
of Rgenerated by
the elements ofFl ,
we seethat
G1 (as
in(iv) above)
is theunique subgroup
of orderpT-1
in the
(commutative)
groupGR,.
As(a-b)q
= aq-bq =a-b,
andso
(a-b)q-1
= 1, where q =pT,
we see that a-b EG1
CF1.
Thuswe have
proved
the first of thefollowing
two results:Let
R,
p, r be as in Th. 2. Then R contains asubfield of
orderpr i f ,
andonly i f
the characteristicof
R is p. A lsoi f Fl , F2
are twosub f ields of
orderpr
inR,
then there is an invertible element aof
Rsuch that a-1 .
F1 · a
=F2.
The second statement follows from the result in
(iv)
above.These results will be
generalised
in the next section.(2.4)
IfR,
p, r, n are as in Th. 2 weconsider,
in thissubsection,
the situation where R contains a subfield F of order
pr.
Wesuppose first that F is contained in the centre of the
ring
R. Then(and only then)
we canregard
R as a linearalgebra
over the fieldF. Once a basis for R over F is chosen we can use the
right regular representation
of R to exhibit it as aring
of matrices of order nover the field
GF(pT).
Thissimple
process forexhibiting
R as aring
of matrices of(this particular)
order n over the field F will notbe available if we do not presuppose that the subfield F of
(the maximal)
orderpr
is contained in the centre of thering
R. Thefollowing
two theorems show howeverthat,
in twospecial
cases,it is
possible
torepresent
R as aring
of n X n matrices over thefield
G F(pT) -
even if the subfield F is not contained in the centre of thering
R.THEOREM 3. Let
R, J,
p, r, n be as in Th. 2, and let the character- isticof
R be p.I f J2
=(0),
then R isisomorphic
to thering of
alln X n matrices
of
theform
where
hl, f2’ ..., fn
range over thefield GF(pr),
andf or
i = 2, ..., n,hi
=h1si
with si= pti for
somefixed integers ti
with 1ç ti
r.Conversely, for
every choiceof
theintegers ti
thering of
matricesdescribed above is a
ring o f
thetype
considered in Th. 2 with character-istic p
whoseradical J satisfies J2
=(0).
PROOF. The
straightforward proof
of the conversepart
will beomitted. For the direct
part,
we supposethat n ~
2, and note that thering
R contains a subfield F of orderpre Keeping
Ffixed,
we
get
adistinguished
basis(refer § 1) {x2, ···, xn}
of n -1 elementsfor y
over F. If g is a fixedcyclic generator
of the fieldF,
and ifxi = g, we see that
{X1,
X2’ ...,xn}
is adistinguished
basis for the entirering
R over the field F.Let,
foreach i ~
2, xi - g =g-i -
xiwith si
=pti
for someintegers ti
such that 1ç ti ç
r. Ourhypothesis
that,J’2
=(0) implies that xi ’
x, = 0 for all i > 2, andall j
> 2.Now we define n square matrices
X1, X 2 , ’ ’ ’, X n of
order n overthe field F as follows:
X1 =
G ==diag (g, g82, g83, ..., g8n),
and foreach i greater
than one,X;
is the matrix with 1 in the(1, j)-th entry
and zeros elsewhere. Thefollowing
results are theneasily
verified:
X i ’
Gk = Gksi ·X i ,
G k.X
=gk ’ X i ,
andX i ’ Xj
= 0, forall i
>
2,all i ~
2, and allk ~
1. Themapping
is
easily
verified to be anisomorphism
of the field F into thering
of all n n matrices over
F;
we shall denote theimage
of any elementhl
orfj
of F under thisisomorphism by
thecorresponding capital letter (viz) H1
orF, respectively.
Then themapping
as the elements
hl, f2’ ..., f n
range over the fieldF,
can be verifiedto be an
isomorphism
defined on all of thering
R onto thering
of alln X n matrices of the form
given
in the statement of the theorem.This
completes
theproof
of the theorem.THEOREM 4. Let
R, J,
p, r, n be as in Theorem 2, and let the characteristicof
R be p.I f jn-1 A(0),
then R will beisomorphic
tothe
ring of
all n X n uppertriangular
matrices(aij)
over thefield GF(pr)
whichsatisfy
the conditionwhere s =
pt
and t is somefixed positive integer
with tç
r.Conversely, for
every choiceof
thepositive integer
t, thering o f
matrices described above is a
ring of
thetype
considered in Theorem 2 withcharacteristic p
whoseradical J satifies
the conditionJn-1
~(0).
PROOF. In view of Theorem 3, we may suppose that n > 3. We take a fixed subfield F of order
pr
in thering R,
and then obtain adistinguished
basis{y2, ···, yn} of J
over the field F. We note that at least one of the basis elements yi does notbelong
to the idealJ2 (which
is of orderp(n-2)r).
If y is adistinguished
elementof J
over F such that
y e J’2,
then we assert thatyn-1 *
0. 4 To seethis,
suppose thecontrary
thatyn-1
= 0.Firstly,
forarbitrary
elements
f1, f2, ···, f n-i
of the fieldF,
we haveif
yn-1
= 0, since y is adistinguished
element overF;
andthen,
for
arbitrary
éléments z1, ···,zn-1 of J2
we findsince jn
=(0).
But as every one of thep(n-1)r
elements ofJ
isuniquely expressible
in the formfy+z
withf
in F and z inJ2, the
4 This observation is due to Mr. Bjôrk.
above shows that the
supposition yn-1
= 0 will lead toJ’n-1
=(0),
a contradiction. Thus our assertion that
yn-1
~ 0 isproved.
Letnow y · h = hs · y for all h in the field
F,
where s= pt
with t afixed
positive integer (independent
of h inF )
suchthat t
r.We then take the n X n matrix Y =
(yii)
with Yij = 1if j-i
= 1( i
= 1, ···,n-1) and yij
= 0, otherwise. After thisstage,
theproof proceeds exactly
as in theprevious
theorem. Moreexplicitly,
we have to consider the
isomorphisms
and
with the convention of the
previous
theorem. Thiscompletes
theproof
of the directpart
of the theorem.(2.5)
REMARK. Forgiven
p, r, n(with n greater
thanone)
wesee that there are at most r
mutually nonisomorphic rings
of thetype
considered in Th. 4, and when r ~ 2 there are at least two distincttypes. For,
if we suppose that r isgreater
than one, wehave for
t = 1 ( r) a
noncommutativering,
while for t = r(> 1)
we have a commutative
ring
which can also be described asP[x]/(xn),
thering
ofpolynomials
in the indeterminate x over the fieldF,
modulo the idealgenerated by
the element xn in it.(2.6)
Thefollowing
theorem mentions two conditions which aresufficient to force a
ring
of Th. 2 to be commutative.THEOREM 5. Let
R, J,
p, r, be as in Th. 2. Let(1 )
any two elementso f J
commute with eachother,
and(2)
themultiplicative
groupGR of
the invertible elementsof
R contain a normalsubgroup of
orderp’’-1.
Then R will be commutative.PROOF. Let
Fi
be the set introduced in theproof
of Th. 2. Ifthe condition
(2)
of this theoremholds,
the result in§(2.3) (vi)
shows that the set
F1
will be contained in the centre of thering
R.As every element of R is
uniquely expressible
in the formf+x
with
f
inFi
and x inJ,
we see that the condition(1 )
of this theoremwill, then, imply
that the entirering R
is commutative.(2.7)
REMnRxs.(i)
IfR, J,
p, r, n be as in Th. 2, thering
R willreduce to the field
GF(p’) when /
=(0) (i.e.) n
== 1. So Th. 5 isa
generalisation
of Wedderburn’s theorem tocompletely primary rings
of finite order. Of course, theproof
of Th. 5 makes essentialuse of Wedderburn’s theorem.
(ii)
There are two conditions in thehypothesis
of Th. 5. Thefirst of these is
obviously
necessary for thevalidity
of the conclu- sion of the theorem. It may be asked whether this condition alone is sufficient. That the answer to thisquestion
is in thenegative
isseen in the
example
of aring
R of Th. 4 for n = 2, r~
2, and t = 1.As J2
==(0),
the first condition in thehypothesis
of Th. 5 issatisfied,
but thisring
is not commutative.(See §(2.5)).
Section 3
(3.1)
LetR,
p, r, n be as in Th. 2. We have seen that the charac- teristic of R ispk
for someinteger
k with 1~ k ~ n,
and in theprevious
section we considered two cases where k was the smallestpossible (i.e.)
where the characteristic of R was p. In thepresent
section we will consider the other extreme - the case where the characteristic ispn.
We recall that we havealready proved
thatthe
ring
must be commutative in this case. When n = 1(and
p, rare
arbitrary)
we note that thering
R of Th. 2 reduces to the Galoisfield
GF(pr),
while when r = 1(and
p, n arearbitrary)
we notethat the
ring
of Th.2(v)
is thering Zj(pn)
ofintegers
modulopn.
More
generally
we will prove, in the course of thissection,
thatthere exists one
and,
in the sense ofisomorphism, only
onering
of the
type
considered in Th.2(v)
for anygiven prime
p, and for anygiven positive integers
n, r. Asregards existence,
we canverify
that thering
of Witt vectors oflength n (refer
Jacobson[3,
Ch.III, §
4,especially
Ths. Il and12])
over the fieldGF(pr)
is a
ring
of thetype
considered in Th.2(v).
We shall however establish the desired results withoutappealing
to the construction of Wittrings.
For this purpose, webegin
with a tentative définition.DEFINITION. Let Z denote the
ring
of allintegers, x
an indeter-minate,
p aprime,
and n, rarbitrary positive integers.
Letbe a monic
polynomial
ofdegree r
which is irreducible modulo theprime
p, and let(pn, f )
denote the idealgenerated by
the twoelements
pn
andf
in thepolynomial ring Z[x].
Then thequotient ring
is to be called the Galois
ring
of orderpnr
and characteristicpn,
and is to be denoted
by
thesymbol GR(pnr, pn).
The
following
remarks are in order.Firstly,
we note that if the numerical values of the order(viz ) pnr
and the characteristic(viz) pn
aregiven,
with theunderstanding
that p is aprime,
then thevalues of p, n, and r are
uniquely
determined.Secondly,
we notethat at least one
polynomial f
with therequired properties
existsin
Z[x]
for anygiven prime
p, and for anygiven positive integers
n, and r. To show that the definition makes sense we have
only
toprove that the
ring
R’ isactually independent
of theparticular polynomial f
used in its construction. This will beaccomplished by showing
that thefollowing
two statements are true.( I )
For anyparticular
choiceof
thepolynomial f
as in the abovedefinition,
thering
R’o f
thedefinition
is aring of
thetype
considered in Th.2(v).
( II ) A ny ring of
thetype
considered in Th.2(v)
isisomorphic
to the
ring
R’(for
suitable valuesof
p, r,n)
obtained in(I).
While the first statement can be
proved straightaway,
theproof
of the second one
requires
somepreliminary
results(Th.
6 and itscorollaries) which, however,
appear to be ofindependent
interest.We
proceed
to prove the statement(I), assuming
that n is afixed
integer greater
than one. First of all we note that R’ is acommutative
ring
with amultiplicative identity,
that its character-istic is
pn,
and that it haspnr
elements. So it remainsonly
to showthat the
ring
containsexactly p(n-1)r
zerodivisors,
and that thesezero divisors form an additive group. We note that the set K = p - R’ is a
nilpotent
ideal of orderp(n-1)r
in R’. So theproof
of the statement
( I )
will becomplete
if we show that every element of R’ not in the ideal K is an invertible element of R’.We now denote
by
A the ideal(pn, f )
andby
B the ideal(p, f)
in the
polynomial ring Z[x].
Then we note thatZ[x]/A
is thering
R’ and that
Z[x]/B
= F is the Galois fieldGF(pr).
As the ideal A is contained inB,
we see that theidentity mapping
on thering Z[x]
induces a well-definedhomomorphism
on R’ onto F whosekernel is the ideal K in R’. Now if an element a of R’ does not
belong
toK,
it will bemapped by
the abovehomomorphism
intoa nonzero element of the field
F;
as K is a nilideal,
thisimplies
that a is invertible in R’. This
completes
theproof
of the state-ment
(1).
(3.2) Throughout
this subsection and the next, thesymbol x
will be used to denote an indeterminate. For any