C OMPOSITIO M ATHEMATICA
R OBERT S. W ILSON
On the structure of finite rings
Compositio Mathematica, tome 26, n
o1 (1973), p. 79-93
<http://www.numdam.org/item?id=CM_1973__26_1_79_0>
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79
ON THE STRUCTURE OF FINITE RINGS by
Robert S. Wilson *
MATHEMATICA, 26, 1, 1973, pag.
Noordhoff International Publishing Printed in the Netherlands
Introduction
In this paper we shall concern ourselves
primarily
withcompletely primary
finiterings
and shall obtain results about othertypes
ofrings by
means of the Peircedecomposition
and other methods. Recall that anArtinian
ring R
with radical J is calledprimary
ifR/J
issimple
and iscalled
completely primary
ifR/J
is a divisionring
Thedeepest study
intothe nature of
completely primary
finiterings
appears to have been madeby Raghavendran [5].
We first state some of hismajor
results.In what follows Z will denote the rational
integers,
and if S is a finiteset,
#(S)
will denote the number of elements in S.THEOREM A. Let R be a
completely primary finite ring
with radical J and letR/J ~ GF(pr).
Then(1) #(R) = p’ir and #(J)
=p(n-1)r for
someprime
p and somepositive integer
n,(2)
Jn =(0);
(3)
The characteristicof
R ispk for
somepositive integer
k ~ n.This is
essentially
Theorem 2 of[5].
Ofspecial
interest is the casek = n. To consider this case
Raghavendran
introduced thefollowing
class of
rings.
DEFINITION.
Let f(x)
EZ[x]
be a monicpolynomial
ofdegree
r whichis irreducible modulo p. Then the
ring Z[x]/(pn, f )
is called the Galoisring
of orderpur
and characteristicpn,
and will be denotedby Gn, r;
theprime p
will be clear from the context. ThatGn, r
is well definedindepen- dently
off
the monicpolynomial
ofdegree
r follows from§§ (3.4), (3.5)
of[5] where
it is shown that any twocompletely primary rings R
ofcharacteristic
p"
with radical J such that#(R) = pnr
and#(R/J)
=pr
are
isomorphic.
Note thatGF(pr) ~ G1, r
andZ/(pk) ~ Gk,1.
The im-portance
of this class ofrings
is illustrated in* Written while the author was an NSF Trainee at the University of California at Santa Barbara, California, working on his dissertation under the direction of Professor Adil Yaqub.
THEOREM B. Let
R,
p, r, be as in Theorem A. Then(1) R
will contain asubring isomorphic
toGk,, if
andonly if
the charac-teristic
of R
ispk.
(2) If R2, R3
are any twosubrings of
R bothisomorphic
toGk,r
thenthere will be an invertible element a in R such that
R2 = a-1 R3
a. This isTheorem 8 of
[5].
In §
1 we obtain some alternate characterizations of Galoisrings,
show that any Galois
ring
is thehomomorphic image
of aprincipal
idealdomain,
andcompute
the tensorproduct
of two Galoisrings.
Since the additive group of a finite
ring
is a finite Abelian group, the additive structure of a finitering
is in a sensecompletely
determinedby
the fundamental theorem of finite Abelian groups as a direct sum
of cyclic
groups of
prime
power order.In §
2 we use the resultsfrom §
1 to es-tablish a connection between the
multiplicative
structure of thering
andthe
cyclic decomposition
of its additive group.In §
3 we prove that anycompletely primary
finitering
forwhich p, n,
r, and k are as in Theorem A is thehomomorphic image
of aring
of m x mmatrices over
Gk, r(p)
for somem ~ n
inwhich p
divides all entries below the maindiagonal
of each matrix. As a result we can also prove that any finitenilpotent ring
of characteristicpk
is thehomomorphic image
of aring
of matrices overZ/(pk)
inwhich p
divides all entries on and belowthe main
diagonal
of each matrix. We thus obtain characterizations ofcompletely primary
finiterings
and finitenilpotent rings
ofprime
powercharacteristic. It should be
pointed
out here that some time ago Szele[6]
reduced allproblems
on the structure ofnilpotent
Artinianrings
toproblems
aboutnilpotent
finiterings
ofprime
powercharacteristic,
andtherefore,
our result takentogether
with[6] yields
a characterization of allnilpotent
Artinianrings.
1. Remarks on Galois
rings
We first remark that any finite
ring
is the direct sum of finiterings
ofprime
power characteristic. This follows fromnoticing
that when wedecompose
the additive group of thering
into a direct sum ofsubgroups
of distinct
prime
powerorders,
that thecomponent subgroups
are ideals.See
[2]
for further information on thisquestion.
So without loss of
generality (up
to direct sumformation),
we needonly
considerrings
ofprime
power order. For the remainder of this paper theletter p
will denote anarbitrary
fixed rationalprime
and unless other- wisestated,
allrings
considered will be of characteristicpk
for some pos- itiveinteger
k. If’ x is an element of such aring
we call the smallestpositive
integer e
suchthat pe x
= 0 the orderof x.
In this section we prove some results on Galois
rings
which will be used in what follows.PROPOSITION 1.1.
Any
Galoisring
is thehomomorphic image
of alocal PID whose
unique
maximal ideal isgenerated by
the rationalprime
p.PROOF.
Gn, r
is aring
of Witt vectors oflength n [5;
p.212, § (3.5)].
Hence
Gn, r
is thehomomorphic image
of thering
of Witt vectorsW (K)
of infinite
length,
K =GF(pr),
a discrete valuationring
whoseunique
maximal ideal is
generated by
the rationalprime p ([8],
pp.234-236).
COROLLARY 1.
Any
idealof Gk, r is of
theform piGk,r
i= 0, l, ...,
k.COROLLARY 2.
Any finite Gk,r-module
M is a direct sumof cyclic Gk,,-modules. If
are two
decompositions of
M intocyclic
submodules then s = t and the ordersof the
xi are(perhaps after reindexing) equal
to the ordersof
theyJ .
PROOF. IfW(K)
is the PIDmapping
ontoGk,r by Proposition
1.1then R possesses the structure of a torsion
W(K)-module.
As is wellknown,
theproof of the
fundamental theorem of finite abelian groups(see [3])
translates into a fundamental theorem forfinitely generated
torsionmodules over
PID’S,
andapplying
this latter theorem to theW(K)-
module structure of R we see that R is a direct sum of
cyclic
torsionW(K)-modules. As pkW(K)
annihilates R we conclu de that R is a directsum of
cyclic Gk, r-modules.
REMARK. An
important example
of a finitering
of characteristicpk
which contains
Gk, r
isGk,,-
where m is amultiple
of rby Proposition
1of § (3.8)
of[5].
As a consequence ofCorollary
1 the elements ofGk,m
oforder 1 for i k are
precisely
the elements ofpGk,m .
If on the otherhand,
we viewGk,m
as a direct sum ofcyclic Gm, r-modules
and count ele-ments of
order pi
for i k we conclude thatGk, m
is free overGk,r
onm/r generators.
We shall make
repeated
use ofPROPOSITION 1.2. Let
kl , k2,
rl , r2 bepositive integers.
Let k = min(ki, k2 ),
andspace d
=gcd(r1, r2 ),
and m =lcm (rl , r2).
ThenPROOF. We first note that
Now
by Proposition 1, § (3.8)
of[5]
everysubring
ofGk,r
isisomorphic
to
Gk,s
where s dividesr and, conversely
for everypositive integer s
whichdivides r,
Gk"
contains asubring isomorphic
toGk, s.
Therefore bothGk, rl
andGk, r2
containsubrings isomorphic
toGk, d .
We thus haveGk,r1
and
Gk,’2
as left andright Gk,d-modules.
Thereforeso we first seek to de termine
Gk,d ~Z/(pk)Gk,d.
It isstraightforward
toshow that
where
f(x)~ (Zj(pk))[X]
is theimage
of apolynomial
ofdegree d,
f(x)
EZ[x]
which is irreduciblemod p. Let f (x)
be theimage off(x)
andhence
of J(x)
in(Z/(p))[x].
Asf(x)
issupposed
to be irreducible ofdegree d mod p
it follows thatf(x) splits
into distinct linear factors overGF(P’).
Thereforeby
Theorem 6 of[5] J(x) splits
into d distinct linear factors overGk,d. Say (x-a1), ···, (X-âd).
ThenFrom
(2)
we thus haveThus to prove the lemma we need
only
show thatWe first prove
(3)
in case k =1, i.e.,
for the case of fields. Since m =lcm(’l, r2)
it follows thatGF(pm)
contains a subfieldisomorphic
toGF(pr1)
and a subfieldisomorphic
toGF(p"2)
so we may considerGF(pr1), GF(pr2)
cGF(pm)
withGF(pri)
nGF(pr2) = GF(pd).
LetF
being
asubring
of finite field is a finite fieldwith p’
elements for somepositive integer
s. SinceGF(prl), GF(pr2)
~ F we have that r, and r2 both divide s. Therefore m divides s. Since F cGF(pm)
we concludethat F =
GF(pm)
and hence any element inGF(pm)
can berepresented
in the form
Liaibi
with ai EGF(prl), bi
EGF(pr2).
We now define amap from
GF(p") Q9GF(pd) GF(pr2)
toGF(pm) by
By
the remarksabove,
this map is onto, andby counting
dimensionsover
GF(pd)
we conclude that it is anisomorphism,
and we conclude thatWe now consider the
diagram
where
qJ(a, b) = 03C81(a) Q9 42(b)
witht/1i being
the mapJi
the radical ofGk, r1 i
=1,
2. It is clear that 9 is bilinear overGk,d
andmultiplicative
in each variable so there exists an inducedhomomorphism
h from
Gk.r1 ~ Gk, d Gk, r2
ontoGF(pr). Gk,r1 O Gk, d Gk, r2
is thus acompletely
primary ring homomorphic
toGF(pm)
of characteristicpk.
SinceGk,r1
and
Gk,,.2
are free overGk,d
onrl/d respectively r2/d generators,
it follows thatGk,r, C8JGktd Gk,r2 is
free overGk,d
on(rl/d)(r2/d)
=m/d generators
and henceand therefore
(3)
is established and theproposition
isproved.
2. The additive structure of finite
rings
As in the last
section,
allrings
will be of characteristicp’
for somepositive integer
k.In this section we delve
deeper
into the additive structure ofcompletely primary
finiterings.
Inparticular,
we will later need information aboutcompletely primary
finiterings
viewed as(Gk,r, Gk,r)-modules.
As is wellknown,
if A and B are commutativerings,
an abelian group M admitsan
(A, B)-module
structure if andonly
if it admits a leftA ~Z
B-modulestructure: the scalar
multiplications being
relatedby
the ruleWe are thus led to consider the structure of a
Gk1,r1 ~z Gk2, r2-module.
THEOREM 2.1. Let M be a
Gk1,r1 ~Z Gk2,r2-module,
and let k = min(k1, k2),
d =ged(rl, r2 ),
m =lcm(r1, r2). Then
M is a direct sumof Gk1,r1
~Gk2,,.2-submodules
which arecyclic left Gk,m-modules,
andgiven
any twodecompositions of
M intoGk¡,rl Q9z Gk2,,.2-submodules.
s = t and the order
of aq
is(after
apossible reordering of
thebq)
the orderof bq .
PROOF. We know from
Proposition
1.2 thatso we consider M as
a L1. Gk, m-module.
Let el , ..., ed be anorthogonal
system
ofprimitive idempotents
forL1. Gk,m, i.e.,
Then M = 1 M =
(e1+···+ed)M = e1 M + ··· + ed M. We wish to show
that this sum is direct. Let m E
ei M
nej M
fori ~ j.
Then m Eei M implies
that eim = mand m ~ ej M implies
thatej m
= m. Thereforeand the sum is direct.
But ei
is themultiplicative identity
of theith component
of the directsum 03A3di Gk, m
and hence the structure ofei M
asa 03A3d1 Gk,m-module
isthe same as its structure as a
Gk,m-module
with scalarmultiplication
de-fined
by
gei m =(g, ···, g)eim
and the result now follows from Corol-lary
2 ofProposition
1.1.COROLLARY. Let R be a
finite ring
with 1of
characteristicpk
and lete1, ···, em be a
complete
setof primitive idempotents for
R. Letelrei
have characteristic
pki
and suppose thateiRei/eiJei ~ GF(pri).
Letkij
= min(ki, kj), dij
=gcd (rb rj)
andmij
=lcm(mi, mj).
Then inthe Peirce
decomposition of
R[4;
pp.48, 50]
eiRej
isisomorphic
as a(Gki,ri’ Gkj,rj)-module
to a direct sumof cyclic
left Gkij,mij-modules
and the ordersof
thegenerators for
onedecomposi-
tion are the orders
of
the generators obtained in any other suchdecompo-
sition.
PROOF. Since
eiRei
iscompletely primary
of characteristicpki
andradical
eiJei
such thateiRei/eiJei ~ GF(pri),
it follows from Theorem B thateiRei
contains asubring isomorphic
toGki,ri.
SinceeiRej
is a(eirei, ejRej)-module
it is thus a(Gki,ri’ Gkj,rj)-module
and hence aleft
Gkbri ~Z Gkj,rj-module.
The result now follows from Theorem2.1.
PROPOSITION 2.2. Let R be a
completely primary finite ring of
charac-teristic
pk
with radical J such thatR/J ~ GF(pr).
Then there exists anindependent generating
setbl, b2, ···, bm
of R as aleft Gk, r-module
suchthat:
PROOF. We first note that
Gk, r ·
1 is a(Gk, r, Gk, r)-submodule.
More-over,
Gk, r .
1 is(Gk, r, Gk, r)-module isomorphic
to a direct summandof
Gk,,. Q9 Z Gk, r by Proposition
1.2. NowGk, r being
thehomomorphic image
of a PID is aquasi-Frobenius ring (Exercise
2cof §
58 of[1 ]).
Asis well known and easy to see, a direct sum of
quasi-Frobenius rings
isalso
quasi-Frobenius.
HenceGk, r ~Z Gk, r ~ 03A3r1 Gk, r
isquasi-Frobenius.
Therefore
Gk, r
is a direct summand ofGk, r ~Z Gk,r and
hence a pro-jective Gk, r ~Z Gk,r-module.
Butprojective
modules overquasi-Frobe-
nius
rings
are alsoinjective,
soGk,r
is aninjective Gk, r ~Z Gk, r-module,
hence an
injective (Gk,,., Gk,r)-module, i.e., Gk,r
1 is a(Gk,r, Gk,r)-mo-
dule direct summand of R. Therefore there exists another
(Gk, r’ Gk, r)-
submodule M of R such that R =
Gk, r . 1 +
M. We now need to showthat M can be
generated by nilpotents.
We first obtain a leftGk, r module
decomposition
R =Gk, r . 1+L
where L isgenerated by nilpotents.
Letbe a left
Gk,r-module decomposition
of R. Let ei be the order ofbi.
Ifei ~
k -1 thenbi ~ {x ~ R|pk-1 x
=0}
which is a proper ideal of Rand hence contained in the
unique
maximal ideal J. Thus we conclude thatif ei ~
k-1then bi
E J. Next suppose ei = k. Let (p : R -R/J
~
GF(pr)
be the cannonicalsurjection.
Since qJ takesGk, ,.
ontoGF(pr)
it follows that there is a gi E
Gk,r
such thatqJ(g i) = qJ(bi), i.e., qJ(bi - 9 i)
= 0
which implies that bi-gi ~ J.
We thus obtain a newset {1, b’2 , ···,
b’m} where b’i = bi - gi if ei = k and b’i = bi if ei ~ k - 1 , and b’2 , ..., b’m
m i =bi-gi if
ei = k and b’i =bi
if e - k -1,
and b’2 , ···,bm
E J. It is
straightforward
toverify
that1, b’2,
...,bm
is anindependent generating
set of R as a leftGk,r-module.
We thus have thatpGk,r +
03A3mi=2 Gk,rb’i is
adecomposition
of J.Next,
since J is an ideal of R and hence a(Gk,,., Gk, r)-submodule,
we let J =03A3si=1 Gx,rai
be adecompo-
sition of J into a direct sum of
(Gk,,, Gk, r)-submodules
which arecyclic
left
Gk, -modules
as in Theorem 2.1. Then afortiori
the latterdecompo-
sition is a left
Gk, r-module decomposition
of J so we know that s = mand the orders
of ai
is the orderof b’i
after apossible reindexing.
Letfi
be the order of ai. Assume that
the ai
are ordered such thatfl - ’ ’ ’
= f
=k, ft+1, ···, fm ~
k -1. We wish to prove that1,
al , ’ ’ ’, at areindependent
overGk,r . Suppose
that there is a lineardependence
relationamong them. Such a relation can be written
If go - 0 then the relation becomes
But
the ai
aresupposed
to beindependent
so giai =0,
i =1, ···,
t, and the relation is trivial. So suppose thatg0 ~ pfoGk,r
but not inhfo+10 Gk,r with fo ~
k -1. Thenand
hence pk-f°giai
= 0 i =1, ···, t.
and asf i = k
for i =1, ···, t we condude that pk-fogi
= 0 i =1, ···, t. Thus gi ~ pfoGk,r i
=1, ···,
t.Let g
= pfog’i i
=1, ···, t
and let g o= pfog’0 .
Sinceg0 ~ ffo+1Gk,r
we see that
g’o ~ pGm,r
and henceg’0
is a unit. We can thus rewrite theintégrât dependence
relation asBut al , ...,
am ~ J
so(1 - 03A3ti=1g’-10 g’iai)
is aunit,
and thus we havepfo
= 0.Hence fo
= k and g o = 0 which forces the relation to be trivial.Therefore
Gx,r + 03A3ti=1 Gk,rai
is a(Gx,r, Gx, r)-module
which is isomor-phic
to a direct sum of t+ 1injective (Gk,r, Gx,r)-modules,
and is hence it-self injective.
Therefore we can write R as a(Gx,r, Gk,r)-module
direct sumNow if we express
M1 = 03A3m-t-1j=1 Gk,rCj
as a direct sum of(Gk, r)-sub-
modules we have that
is a
cyclic decomposition
of R as a leftGk, r-module.
But since the ordersof the
ai’s
are the same as the orders of thebÿ’s
we conclude from theuniqueness
of acyclic decomposition
that there areonly
t + 1generators
of order k in anydecomposition
and therefore all of thec/s
haveorder ~ k -1. Therefore
Mi
c{x ~ R|pk-1x
=01
c J andby setting
M =
03A3ti=1 Gk,rai + Ml
we obtain the desireddecomposition.
§
3. Characterizations ofcompletely primary
andnilpotent
finiterings
THEOREM 3.1. Let R be a
completely primary finite ring of
characteristicpk
with radical J such thatR/J ~ GF(pr),
and let R have anindependent generating
setconsisting of
"1 generators overGk,r.
Then R is the homo-morphic image of
aring
Tof m
x m matrices overGk, r
in which every entrybelow the main
diagonal of
every matrix in T is amultiple of p, and,
more-over, every main
diagonal entry of
every matrixof
T which is in the pre-image of
J is also amultiple of
p.PROOF. We must first obtain the correct
independent generating
setof R over
Gk, r .
Let e be the smallestpositive integer
such that Je =(0).
Let us consider the set of
independent generating
sets of R which sa-tisfy
the conditions ofProposition
2.2.Suppose that ql
is the maximum number of elements of any of thesegenerating
sets which are inJe -1.
Say b2 , ···, bq1 + 1 are in Je-1
and are elements of somegenerating
setsatisfying Proposition
2.2. We now consider all suchindependent
gen-erating
sets which includeb2, - - -, bq1+1. Suppose
q2 is the maximum number of elements in any of thesegenerating
sets which are inJe- 2.
Say bq1 + 2 , ···, bq2+q1+1
are inJe - 2
and are elements of somegenerating
set
satisfying Proposition
2.2 which also containb2 ,···, bq1+1.
We con-tinue
choosing
elements or ourgenerating
set in this way: at theith step
we have
already
chosen1, b2 , ···, bqi-1
+ ... +q2+ql + 1 and we supposethat the maximum number of elements in
je-1
in anygenerating
setsatisfying Proposition
2.2 which also includesb2 , ···, bqi-1 + ··· +qi+1
is qi . We choose
bqi-1+ ... + q1 + a , ···, bqae + ... + qae + 1 ~ Je-i
i which areelements of some
generating
setsatisfying
the conditions ofPropo-
sition 2.2 which also contain
b2 , ’ ’ ’, bqi-1 + ···
+q1 + 1 · After e -1steps
we have
that p, b2 , ···, bqe-1+ ...
+ ql + 1generate
all of J and hence1, b2 , ’ ’ ’, bm
is agenerating
setsatisfying
the conditions ofProposition
2.2.
Next let M =
03A3mi=1 Gk,r ci
be a freeGk,r-module
ongenerators
Ci, ..cn . Let ei be the order of
bi.
We embed R into Mby identifying bi
-pk-ei
Ci , It is easy to check that this map is anisomorphism
of R into M.We next consider R as a
subring
of thering
ofendomorphisms
of Rconsidered as a left
Gk, r-module HomGk,r(R, R)
via theright regular representation, i.e.,
we consider x ~ R to be theendomorphism
definedby x : a -
ax for all a E R. We shall thus write all maps inHomGk, r(R, R)
and in
HomGk,r(M, M)
on theright.
Let T ={03B1
EHomGk, r(M, M)
thereexists an a E R such that for all x ~
R, (x)oc
=xa}.
Given an oc EHomGk, r (M, M),
if there exists an a E R such that(x)oc
= xa for all x ~ R thena is
uniquely
determinedby
the fact that(1)03B1
= 1 a = a. It isstraight-
forward to check that T is a
ring
and that the map v : T ~ R definedby
v : oc -
(1)03B1
is aring homomorphism.
Since R cM,
we consider anyx e R to be a
homomorphism
overGk, r
into Mby x : a ~
ax ER c M,
and since M is a free module over a
quasi-Frobenius ring
it isinjective
and the
homomorphism x
can be extended to anendomorphism
of M.We conclude that v is onto. We want to prove that T satisfies the con-
ditions of the theorem.
The matrix
representation
we obtain for T is the matrixrepresentation
obtained over M with
respect
to the basis el’ ..., c.i.e.,
ifthen the map from T to
Mm(Gk,r) given by
a ~[03B3ij(03B1)]
is anisomorphism.
However,
this matrixrepresentation depends
on the order in which weindex the ci . We index the ci
by specifying
the order of thebi.
We takebl -
1. We then assume thatif ei
is the orderof bi
thate2 ~ e3 ~ ···
~
em . Nextlet f be
thepositive integer
such thatb
i ~Jf
butbi ~ Jfi+1.
We
call fi
the radical indexof bi.
We shall further assume thatif ei = ej
with i
~ j then fi ~ f .
We prove that the matrixrepresentation
of T withrespect
to thisordering
of the basis cl , ’ ’ ’, c. of M is of the desiredtype.
Let a E T. We must
compute
the action of a on each ci .pk-CiCi
=bi
E Rso let a =
(1)03B1 ~ R. a
=03A3mq=1 gq bq .
HenceNow
bi
EGx,,,bi
which is a(Gx,,., Gk,r)
submodule of R. Hencebigq G b. say bigq
=g(i)qbi
for some(i) G
So(pk-eici)03B1 = 03A3mq=1 gq (i) bibq.
We now let
bi bq
=03A3mj=103B3(q)ijbj.
ThenNow suppose that
i ~ j. Then ei ~
ej . If ei> ej then pk-ei properly
divides
pk-e’.
We conclude that if 1> j
sothat ei > ej
thenthe i, jth
entry
of the matrixrepresentation
of oc is amultiple of p
for all ce E T. Sowe restrict our attention to
those i, j
such that i~ j
but ei = ej. In thiscase
and thus
03B3ij(03B1) - 03A3mq=1 g(i)q03B3(q)ij
is amultiple of pej.
Therefore if03A3mq=1 g (i) 03B3(q)ij
E pGk, r
then so is03B3ij(03B1).
To show then that everyentry
below the main dia-gonal
of each matrix on T is amultiple of p,
it will sufhce to show thatfor
all q
=1, ···,
m,03B3(q)ij
is amultiple of p
for all i> j
such that ei = ej . Moreover if a E T is in thepreimage
of J theng(i)1
= 0 for all i =1, ···,
m,and, tberefore,
to show that the maindiagonal
entriesyi(ce)
are allmultiples
of p it will sufhce to show that03B3(q)jj
is amultiple of p
for allq = 2,
..., m. .If q
= 1 thenbibI = bi
and so03B3(1)ij
=03B4ij
and thus03B3(1)ij
is amultiple
of p
for all i >j.
So theproof
of the theorem will becomplete
if we canshow that for
all q
=2, ···,
m03B3(q)ij
is amultiple of p
for all i~j
such thatei = ej.
We shall assume that there is
a q ~
2 for which there exists an i~ j
suchthat ei
= ej but03B3(q)ij
is not amultiple of p,
and we shall derive acontradiction.
Since q ~ 2 bq
E J so the radical index ofbibq
isstrictly
greater
than the radical indexof bi
whichis, by hypothesis, greater
thanor
equal
to the radical index ofbJ .
So from the construction of the gener-ating
set1, b2,
...,bm
of R overGk,r
we will have our contradiction ifwe can show that
1, b2 , ···, bj-1, bibq, bj+1, ···, bm is
agenerating
setof R over
Gk, r satisfying
the conditions ofProposition
2.2.and p
does not divide03B3(q)ij
so it follows that1, b2, - - -, b-1, bibq, bj+1,
···,
bm
is agenerating
set of R overGk,r.
To showindependence,
wefirst note that
pej(bibq)
=pei(bibq)
= 0 so the order ofbibq
is less thanor
equal
toej. However, 03B3(q)ij
is not amultiple of p
and so we concludethat
ps(bibq) = 03A3mt=1 y1i)psbt ¥=
0 ifs ej
and thus the order ofb1 bq
is the order of
bj.
Now since1, b2 , ···, bj-1, bibq , bj+1, ···, bm
is agenerating
set the map from the external direct sumto R
given by
is onto. But as the order
of bibq is ej
we conclude thatwhich is
equivalent
tosaying
that1, b2 , ···, bj-1, bibq, bj+1 , ···, bm
are
independent. Moreover, if g
EGk, r ,
then sinceGk,rbq
is a(Gk,,. , Gk, r)-
submodule,
there exists ag’
EGk, r
such thatbq g = g’ bq . Similarly given
g’
there exists ag" E Gk,,.
such thatbig’ = g"bi.
Hence(bibq)g = g", (bibq)
and we conclude thatGk,rbibq
is a(Gk,r, Gx,r)-submodule
of Rand, therefore, 1, b2, ···, bj-1, bibq, bj+1, ···, bm
satisfies the conditionsof
Proposition
2.2 and theproof
iscomplete.
As a consequence of this result we obtain the
following
classification of finitenilpotent rings.
THEOREM 3.2. Let R be a
finite nilpotent ring
with characteristic n,and let n =
pii ... prr be
theprime
powerfactorization of
n. Then R is adirect sum
where
Ri
is ahomomorphic image of
aring Ti of
matrices overZ/(pkii)
in which every
entry
on or below the maindiagonal of
each matrix inTi
is a
multiple of
pi .PROOF. As was noted at the
beginning of § 1,
a finitering
with charac- teristic n is a direct sum ofrings
of characteristicpkii. Moreover,
eachdirect summand of a finite
nilpotent ring
must itself benilpotent.
Sowe need
only
consider the case where n =pk
for someprime
p.We embed R into the radical of a
completely primary
finitering
asfollows.
Let R
=Z/(pk) + R
be the usualembedding
of R as an idealinto a
ring
with1, i.e.,
the elementsof R are
orderedpairs (n, r) n ~ Z/(pk),
r e R with addition defined coordinate-wise and
multiplication
definedby
(nI’ r1)(n2, r2) = (nl n2 , n1 r2 + n2 r1 + r1 r2).
It is easy to see that(n, r)
is a unit
in R
if andonly
if n is not amultiple of p.
Hence the nonunits ofR
form an ideal Jand R
iscompletely primary
with Risomorphic
to asubring
of J.R
is of characteristicpk
andR/J ~ Z/(p)
and the resultfollows
immediately
from Theorem 3.1.NOTE. The
special
cases of Theorem 3.1 in which k = 1 and eitherJ2 = (0)
orJn-1 ~ (0) where #R = pnr
have beenproved
in Theorems 3and 4 of
[5].
Thespecial
case of Theoi em 3.2 in which n = p for someprime p
follows from a very old result which can be found on page 202 of[4].
In
[6]
Szeleessentially
reduced allquestions
aboutnilpotent
Artinianrings
toquestions
about finitenilpotent rings
ofprime
power charac- teristic.Let p
be aprime.
Anilpotent
Artinianp-ring
is anilpotent
Ar-tinian
ring R
in which for every x E R there exists apositive integer k(x)
such that
pk(x) x
= 0. Szeleproved
that anynilpotent
Artinianring
is adirect sum of a finite number of
nilpotent
Artinianp-rings
and that a nil-potent
Artinianp-ring
is a direct sum of a finitenilpotent ring
of charac-teristic
pk
for somepositive integer
k and a nullring
whose additive group is a direct sum of a finite number ofquasi-cyclic
groups,i.e.,
groups iso-morphic
to the additive group mod 1 of all rationalswith p-power
denomi-nators. If we combine this result with Theorem 3.2 we obtain the
following
COROLLARY.
Any nilpotent
Artinianring
isisomorphic
to a directsum
of a ring of the
type described in Theorem 3.2 and a nullring
whose additive group is a direct sumof quasi-cyclic
groups.REMARK. It could be asked whether
completely primary
andnilpotent
finite
rings
are ingeneral
notonly homomorphic images
ofsubrings
ofmatrix
rings
as described in Theorems 3.1 and 3.2 but in factisomorphic
to
subrings
of such matrixrings.
If thering
is ofprime
characteristic(or
of square free characteristic in the case ofnilpotent rings)
the answeris yes.
If pk
= p thenG1,r ~ GF(pr)
and R itself is thus a free module overGl,,
so we could take both M and T in theproof
of Theorem 3.1 to beR.
However,
ingeneral,
the answer to thisquestion
isnegative
as the fol-lowing example
shows.Let 9 : Z/(4)
~Z(2)
be the usualhomomorphism; i.e., ~(0) = ~(2)
= 0, ~(1)
=ç(3)
= 1 eZ/(2).
We consider the set of matrices with en-tries in both
Z/(4)
andZ/(2)
of the formas a,
b,
c,d, e, f,
g,h,
1 EZ(4).
Call this set of mixed matrices R and define addition in R coordinatewise andmultiplication by
The reader can check that these
operations
are well defined and that R with theseoperations
is acompletely primary
finitering
of characteristic 4 whose radical J consists of all matrices of the formsuch that
R/J ~ GF(2),
and that J is anilpotent
finitering
of character-istic 4. Consider the element
Note that
so if R or J were
isomorphic
to asubring
ofMn(Z/(4))
for some n thenwe would have
and hence
But
a contradiction.
NOTE. The author wishes to thank the referee for his
helpful suggestions.
REFERENCES
CHARLES W. CURTIS and IRVING REINER
[1] Representation theory of finite groups and associative algebras. (Interscience 1962).
L. FUCHS
[2] Ringe und ihre additive Gruppe. Publ. Math. Debrecen 4 (1956), 488-508.
E. HECKE
[3] Vorlesungen über algebraische Zahlentheorie. (Chelsea 1948).
NATHAN JACOBSON
[4] Structure of rings. (Amer. Math. Soc. Colloq. Publ. XXXVII 1964).
R. RAGHAVENDRAN
[5] Finite associative rings. Compositio Math. 21 (1969), 195-229.
T. SZELE
[6] Nilpotent Artinian rings. Publ. Math. Debrecen 4 (1955), 71-78.
OSCAR ZARISKI and PIERRE SAMUEL
[7] Commutative algebra (Van Nostrand 1959).
NATHAN JACOBSON
[8] Lectures on abstract algebra, Vol. III (Van Nostrand, 1964).
(Oblatum 5-X-71)
University of California
Santa Barbara, California 93106
University of Texas Austin, Texas 78712