A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
C HRISTOPHER J. L ARSEN
Distance between components in optimal design problems with perimeter penalization
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 28, n
o4 (1999), p. 641-649
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Distance Between Components
inOptimal Design Problems
with Perimeter Penalization
CHRISTOPHER J. LARSEN
Abstract. We consider minimal energy configurations of mixtures of two materials in Q c
I1~2,
where the energy includes a penalization of the length of the interfacebetween the materials. We show that the distance between any two components of either material is positive away from the boundary.
Mathematics Subject Classification (1991): 49Q20 (primary), 49N60, 49Q 10, 35A 15 (secondary).
(1999), pp.
1. - Introduction
Many problems
in materialsscience,
such asoptimal design, phase
transi-tions, liquid crystals,
etc., involve interfacialenergies.
A modelproblem
is theoptimal design
ofcomposites
of two or morematerials,
with an energypenalty
on the
length
of the interfaceseparating
the materials.Optimal design
withoutsuch a
penalty
has been thesubject
of extensivestudy (see especially [8], [7],
and the
English
translations of these and other papers in[2]).
Morerecently, [1] ]
and[6] independently investigated
effects due to the presence of interfacial en-ergy in a broad class of
problems
that includesproblems
ofoptimal design
ofcomposites
of two materials.They
consideredminimizing
functionals of theform A
where A c Q c
R N
ismeasurable,
a A is apositive
two-valued functiontaking
the smaller value in A and the
larger
inA~,
u EH1(Q),
and is theperimeter
of A in Q. In[6],
thisproblem
is consideredsubject
to a Dirichletcondition on u and a constraint with respect to where A meets
a 0,
and in[ 1 ],
a zero Dirichlet condition is
assumed,
but there are additional terms in the energy motivatedby problems
ofoptimal design.
A isinterpreted
to be theregion occupied by
one material and A~ isoccupied by
theother,
a A representsPervenuto alla Redazione il 4 gennaio 1999 e in forma definitiva il 10 giugno 1999.
642
the conductivities of the two
materials,
u is the temperature, and a term of the form-2JQfudx
can be included in the energy, wheref
E representsa source
density (see Example
2.5 in[1]).
In this paper, we
study
the components ofoptimal
sets A when Q C~2.
First,
we consider theproblem
ofminimizing
over u E and measurable A. We take aA = 1 in A and L > 1 in A~.
Typically
inoptimal design,
one assumes a fixed amount of the material A(i.e.,
fixed measure ofA). Here,
we firstreplace
this constraint with theterm
(where JAI
is theLebesgue
measure ofA).
This eases some of theanalysis,
as well as
possibly reflecting
the fact that inpractice
A wouldsimply
be themore
expensive material, resulting
in an added cost of At the end of the paper, we indicatewhy
theI
term can bereplaced by
a constraint on themeasure of A. As we
explain below,
our results are easy when there is no termin (A I
or constrainton I A 1,
but instead there is a constraintinvolving
a A nThis energy E is in the class considered in
[1].
The main results in[1] ]
are the existence of minimizers and a
proof
thatoptimal
sets A areessentially
open. In
fact, they
prove that up to a set ofHI
1 measure zero, there is nodifference between the measure theoretic
boundary
of A and itstopological boundary (see
theproof
of Theorem 2.2 in[1]). [6]
proves the critical Holderregularity
u ECO,112(Q),
and thepartial regularity
of a A.It is our
conjecture
that strongerregularity
holds. Inparticular,
that op- timal u areLipschitz.
Fromthis,
it would follow fromquasiminimal
surfacetheory
that A and itscomplement
each occupy a finite number of connectedregions
withC
1 boundaries(for
arelatively quick proof
that does notrely
onquasiminimal
surfacetheory,
see[5]).
The idea to show u isLipschitz
is basedon the fact that Vu can
only
blow up at asingularity
in a A . Here we show that there cannot besingularities
in a A due to boundaries of different componentsintersecting, thereby demonstrating
thatpairs
of components of either materialmust be a
positive
distance apart in any Q’ c c Q. Note that this issimple
in the case of the
problem
considered in[6],
since the constraint on A there doesn’t affect compactperturbations
of A. In that case, it is immediate fromequation (3.1 )
below(with
C =0)
thatcomponents
cannot touch. We alsopoint
out
that,
in any case, it is immediate from the relativeisoperimetric inequality
for Q c
R"
that A‘’ has a finite number of components.Our
approach
is as follows. For aminimizing pair (u, A),
we know from theanalysis
in[6]
thatfor some k > 0 and all C Q .
Furthermore, since
u satisfies a
Caccioppoli inequality.
Inparticular,
it is easy to see from Sec- tion 2.2 of[4]
that for c >0,
there exists c’ > 0 such that,then
where u is the average of u over We can then
study
the minimization of the functionalassuming only
that u satisfies(1.2)
and the aboveCaccioppoli inequality (1.3) (and knowing
that for a minimizerA,
we havepartial regularity
ofa A, etc.).
We first
show,
in Lemma3.1,
that if two components of a minimizer A meetat a
point
inQ,
then in smallneighborhoods
of thispoint,
the components must becomeelongated
and fit in arelatively
narrowrectangle
T. In Theorem3.3,
we then consider small
disjoint
balls whose union contains most of T, andwhose radii are
large compared
to T’s width. It follows that there must behigh
concentrationsof IVul2
in theseballs,
yet the measure of these components of A arerelatively
small.Using
Lemma3.2,
we show that either asignificant proportion
of must"spill
over" to A~ in theseballs,
or there must bea
quantity
of Anearby
besides what lies in T. In either case, it reduces E toexpand
A, as thisexpansion
eitherweighs
moreof by
the lowervalue of a A in
A,
or it consumespart
of the boundaries of the othernearby
components, which
outweighs
the increase inperimeter
causedby
theexpansion.
We then show that our
analysis applies
to components of A~ .Finally,
we indicatewhy
our results hold if theC ~ A ~ I
term isreplaced by
a constraint on the totalmeasure of A.
We note that
proving
a version of Lemma 3.1 for dimensions greater than 2seems to be
significantly
morecomplicated (or
evenimpossible),
while theproof
of Lemma 3.2 is not dimension
dependent (except
that for Q cR ,
factorsof r would be
replaced by
factors ofrN-1 ).
2. - Preliminaries and notation
For a measurable set E C Q c
~2, E I
denotes itsLebesgue
measure andthe
perimeter
of E in Q is644
We denote
by Br (x )
the open ball centered at x with radius r. IfPQ (E)
oo, then we define the measure theoreticboundary
8*E in Q to beand there exists a
HI
1 measurable function vE :8*E - S
1satisfying
for
all q5
ER~),
whereHI
is the 1 dimensional Hausdorff measure andS’
is the unit circle. Note that we then have
PQ (E)
=It is easy to see from the definition of measure theoretic
boundary
that ifE =
El U E2,
thenand this
inequality
can be strict.However,
it follows from theproof
of The-orem 2.2 in
[1] ]
that anoptimal
A satisfies isequivalent
to a set that is the interior of its
closure,
andtaking
A to be this open set,we have = 0. Hence, we can consider the at most countable
components Ai
of A, and write A =UA1.
It follows from Lemma 3.3 and theproof
of Lemma 3.4 in[5] ]
thatand this
equality
holds ifAi
isreplaced with Ai
UAj,
or any union of com-ponents. The effect of this is that if we add a set S to A, then from
(2.2),
U
S)
US)
~-- and soby (2.3)
US) >
U S). Again,
the same holds ifAi
isreplaced
with any union of components. This fact will be usedrepeatedly
below.3. - Distance between
components
We first
study
the localgeometry
of A near intersections of its components in Q.LEMMA 3.1.
Let A1
be componentsof A, and suppose x
EForO r dist
(x, aS2),
we can choose componentsA; and o,f’Ai
nBr(x)
andAj
nBr (x ) respectively,
such that x Ea Al
n and there exists arectangle Tr
containing A;
UAi
withlength
2r and widtho(r).
PROOF. Notice first that for r > 0,
only
a finite number of components ofAi
nBr(x)
intersectBr/2(x) (since
A has finiteperimeter),
and so x is in theboundary
of one(or more)
of these components. The same is true forAj,
andso we can choose
components A~ Aj
whose boundaries contain x. For the restof this
proof,
we will writeAi
forA~,
etc.Let Zi
EAi,
Zj EAj,
and let I be the line segmentfrom zi to zj
and dbe the diameter of
Br (x ) parallel
to l . := dist(d, l )
and let 0 EP.
Set D :=
Ai
UAj
UB8(x),
which is connected. Let r c D be asimple
arccontaining
x andintersecting
lonly
at theendpoints
ofr,
so that for a segment l’ Cl,
r U l’ is a Jordan curve. We denote its interiorby
I, and note that I isconnected.
Take a basis vector e 1 to be
parallel
to l andconstruct 0 = Ole, + Ø2e2 E
with
10 1 1, Ø2
=0, and I fA, I arbitrarily
close tofJ.
It then0 i i
follows from
(2.1)
that(
>P.
The same holds forAj,
anda similar argument shows
We then have
Adding
I U to A therefore reducesperimeter by
at least UAj]) -
2n 8 and increases Eby
no more thanCnr2.
Hence, it must be thatIt follows
that f3
iso(r),
and the lemma follows. DThe Holder
continuity
of u follows from natural modifications to theproof
in
[6]. Indeed,
the limits of theblow-up
sequences in Lemma 2.2 of that paper and thecorresponding
limits for theproblem
here are the same. Theorem2,
0,1
,showing
u EC0 2 , 1 applies
here with very minor modification. Infact,
we won’tactually
use Holdercontinuity,
but rather theinequality (1.2)
from which theHolder
continuity
follows.We now show
that,
in balls where there is a concentrationof
thereis a lower bound on either the
proportion
of A, or on how muchof |VU|2
must
"spill
over" from A to A~. The strategy for thisproof
wasinspired by
Lemma 2.2 in
[6].
LEMMA 3.2. Given c > 0, there exists y > 0 such that
if 0
rdist(y,
and _
646 then either
PROOF.
Suppose
to the contrary that there exists a sequenceixi, ri }
suchthat
I
and
where Bi
denotesB,, (xi). Define vi
EHI (Bl (0)) by
where
U-i
i is the average of u onBi. Also,
defineAi : _ ri
1 and now denoteB (0) by B 1.
Thenand
Notice
that vi
are bounded in so, for asubsequence,
inH 1 ( B 1 )
for some v. Note also thata) implies B I
- 0. Fromb),
andsince vi
are bounded in it followsthat
- 0. Let 6 >0,
and choose
Ts
CB,
measurable suchthat [
8 and XAi ~ 0uniformly
on
Ts.
Then for isufficiently large, Ts
nAi =
0 and we haveIt follows that =
0,
and so v = constant = 0 since the average of v is 0.We now have
that vi
-~ 0 in = 1. We show that this contradicts theCaccioppoli inequality
from(1.3)
It is easy to see
that vi
inherit acorresponding inequality
Since vi
-~ 0 inL2(Bl),
both terms in thisinequality
go to 0.However,
we have from(1.2)
that , and sowhich is a contradiction. o
We now prove our main
result,
a theoremshowing
that E can be reducednear
points
in Q where boundaries of components intersect.THEOREM 3.3.
Let Ai and Aj
be componentsof A.
Thendist(Ai,
> 0 awayfrom
PROOF. We suppose xo E
a Ai
n8Aj
n Q and show that E can be reducedin
Br (xo)
forsufficiently
small r.Using
Lemma 3.2 with c = we find yas
specified by
that lemma and for each 0 rdist(xo, aS2),
we consider arectangle Tr guaranteed by
Lemma3.1. We also will use the notationAi
forA~,
etc., as we did in the
proof
of Lemma 3.1. We thenessentially
cover thelonger
axis of
Tr
withdisjoint
ballsBr’ (xa),
where r’ = qr and r~ is thereciprocal
ofa
positive integer (the
number ofballs)
and will bespecified
later.We first estimate r /2 a Define
A
:=AB(Br’/2(Xa)
n(Ai
UAj)),
and note that
replacing
A withA
reducesperimeter by
i U8Aj)
nand increases
perimeter by
which we knowfrom Lemma 3.1 is
o (r ) .
For r > 0 smallenough,
is
arbitrarily
close to 4(or
is greater than4),
whileis
arbitrarily
close to zero.Hence,
for r smallenough, replacing
A withA
reduces
perimeter by
at least r’.However,
thisreplacement
shifts some Dirichletenergy off of
A, resulting
in an increase in energy of no more thanSince this
replacement
cannot reduceE,
we must haveand so
648
Now consider the smallest
rectangle
T’enclosing
all the ballsBr’ (xa).
Ifwe add this set to A,
perimeter
is increasedby
no more than 4r’ andI
isincreased
by
no more than 4Crr’. We now show that this is more than offsetby
the total reduction in E.To see the reduction in each
ball,
consider one of the balls and suppose firstinequality ii)
of Lemma 3.2 holds. Thenadding
T’ to A reducesenergy in this ball
by
at least(L - Next,
supposeinequality i)
holds.Since
it must be
that,
for rsufficiently small,
Hence,
denoting by
B one of the two components ofthe relative
isoperimetric inequality (see,
e.g., Theorem 2(ii)
in Section 5.6.2of
[3],
Theorem 5.4.3 in[9]),
it follows thatwhere c is the constant from this
isoperimetric inequality. Adding
T’ to Aremoves this
boundary,
and so reduces E in this ballby
at leastSetting
as T’
contains )
17balls,
there is a total reduction of atleast!!! r’.
17Finally,
sinceE7r’
> 4r’ +4Crr’ for qsufficiently small,
E is reducedby adding
T’ to A. Thiscontradicts
(u, A) being
aminimizer,
and it must be thataA~
=0. DIf
Oi, Oj
are components ofA~,
it is not hard to extend theprevious analysis
to show thatthey
too cannot meet.Considering
a ball of radius rcentered at a
point
ina Oi
n80j,
an argument similar to Lemma 3.1 showsthat a component of A in this ball must be contained in a
rectangle Tr
asspecified by
that lemma. Theorem 3.3 thenapplies just
as for intersections ofa Ai
and8Aj .
Lastly,
we sketchwhy
thisanalysis
holds when the termI
isreplaced by
a constrainton JAI. Throughout,
the role ofC I A I
has been toprovide
theability
to make small additions to A with a costproportional
to area, and thiscost has been overcome
by
other energy reductions.If A ~ I
isconstrained,
such additions are notpossible.
However, it isenough
to showthat,
for a minimizer(u, A)
of the constrainedproblem,
the small additions to A can be achievedby removing
the same amount of A from elsewhere. Aslong
as this can be donewith a cost bounded
by
a constant times the measure of the removed set, ouranalysis
holds for the constrainedproblem.
From
[6],
we know that~
1 almost everypoint
in a A has aneighborhood
in which a A is Consider such a
point
x, and choose r > 0 such that a A f1Br (x)
can be considered thegraph
of a functionf : [-r, r]
- I1~, with A theepigraph
off. If f is
not concave, then some of A can be removedwhile
reducing perimeter.
Since within this ball Vu eL 00, removing
a subsetof A from this ball increases the first term of E in
proportion
to the measureof the subset.
Hence,
we needonly
consider the case where any removal of A increasesperimeter, i.e., f
is concave(and
so it hasnegative
meancurvature).
If we then
keep
ufixed,
add aI
term, and minimize overonly
variationsof
f,
asimple
calculation shows that for Cbig enough,
for the newminimizing
function
f
andcorresponding
setA,
the mean curvature off
will be less thanthat of
f,
sof > f. Hence, i
will have less areaby
AA, will belarger by Al,
and so so that if A isreplaced by
A in the constrainedproblem,
the energy cost per area is boundedby
C. Wenote that the idea behind these calculations is similar to that for the existence of
Lagrange multipliers
for the constrainedproblem.
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Math. 96 (1998), 247-262.
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Department of Mathematical Sciences Worcester Polytechnic Institute Worcester, MA 01609