UPMC Basic functional analysis
Master 1, MM05E 2011-2012
Lebesgue spaces
In the sequel,(X,M, µ)stands for a measure space.
1) Interpolation inequality. Let1≤p≤q≤+∞.
a) Show that if f ∈Lp(X, µ)∩Lq(X, µ), thenf ∈Lr(X, µ)for allr∈[p, q], and that
kfkr≤ kfkαpkfk1−αq ,
whereα∈[0,1]is defined by 1r =αp +1−αq .
b) Show that ifµ(X)<+∞andf ∈Lp(X, µ), thenf ∈Lr(X, µ)for allr∈[1, p], and that there exists a constantC >0 (independent off) such that
kfkr≤Ckfkp.
2) Generalized Hölder inequality. Letf1∈Lp1(X, µ), . . . , fk∈Lpk(X, µ)be such that 1
p1 +· · ·+ 1 pk =: 1
r ≤1.
Show that the productQk
i=1fi belongs toLr(X, µ)and
k
Y
i=1
fi r
≤
k
Y
i=1
kfikpi.
3) Let1≤p0<+∞.
a) Show that if f ∈Lp0(X, µ)∩L∞(X, µ), then
p→∞lim kfkp=kfk∞.
b) Let f ∈Lp(X, µ)for allp∈[p0,+∞)such thatkfkp→ ∞asp→ ∞. Show thatf /∈L∞(X, µ).
c) Letf ∈Lp(X, µ)for allp∈[p0,+∞)such thatf /∈L∞(X, µ). Show thatkfkp→ ∞asp→ ∞.
4) Continuity of the translation inLp(RN). LetX =RN,M=L(RN)be theσ-algebra of all Lebesgue measurable subsets ofRN, andµ=LN be the Lebesgue measure. Let1≤p <∞andf ∈Lp(RN). For each h∈RN, we define the translation off by
τhf(x) :=f(x−h) ∀x∈RN.
Show that
lim
|h|→0kτhf−fkp= 0.
5) Assume thatµis a probability measure, i.e.,µ(X) = 1. Letf :X →[0,+∞)be a function inL1(X, µ).
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a) Using Hölder’s inequality, show that ifµ({f >0})<1, thenkfkp→0 asp→0.
b) Show that
p→0lim Z
X
fpdµ=µ({f >0}).
c) Show that for allp∈(0,1), and ally∈(0,+∞), then
|yp−1|
p ≤y+|logy|.
d) From now on, we assume thatf >0 onX, and thatlogf ∈L1(X, µ). Show that
p→0lim Z
X
fp−1 p dµ=
Z
X
logf dµ.
e) Show that
p→0limkfkp= exp Z
X
logf dµ
.
6) Jensen’s inequality. Assume thatµ is a probability measure,i.e., µ(X) = 1. Letϕ: (a, b)→Rbe a convex function (with−∞ ≤a < b≤+∞).
a) Show that
ϕ(t)−ϕ(s)
t−s ≤ ϕ(u)−ϕ(t) u−t whenevera < s < t < u < b.
b) Deduce thatϕis continuous, and that for eachs∈(a, b), there existsβs∈Rsuch that
ϕ(t)≥ϕ(s) +βs(t−s)
for everyt∈(a, b).
c) Letf :X →(a, b)such thatf ∈L1(X, µ). Show thatϕ◦f is measurable and that
ϕ Z
X
f dµ
≤ Z
X
ϕ◦f dµ.
7) Let1≤p <∞andp0=p/(p−1). Show that for everyu∈Lp(X, µ), then
kukp= sup Z
X
|uv|dµ:v∈Lp0(X, µ),kvkp0 ≤1
.
Ifp=∞andX isσ-finite, show that for everyu∈L∞(X, µ), then
kuk∞= sup Z
X
|uv|dµ:v∈L1(X, µ),kvk1≤1
.
We recall thatX isσ-finite is there exists an increasing sequence of measurable sets (Xn)n∈N⊂Msuch that X =S
n∈N andµ(Xn)<∞for each n∈N.
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