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Bulletin

SOCIÉTÉ MATHÉMATIQUE DE FRANCE

3XEOLpDYHFOHFRQFRXUVGX&HQWUHQDWLRQDOGHODUHFKHUFKHVFLHQWL TXH

de la SOCIÉTÉ MATHÉMATIQUE DE FRANCE

Tome 136 Fascicule 2 2008

pages 167-193

GEOMETRIC INSTABILITY FOR NLS ON SURFACES

Laurent Thomann

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THE WKB METHOD AND GEOMETRIC INSTABILITY FOR NONLINEAR SCHRÖDINGER EQUATIONS ON SURFACES

by Laurent Thomann

Abstract. — In this paper we are interested in constructing WKB approximations for the nonlinear cubic Schrödinger equation on a Riemannian surface which has a stable geodesic. These approximate solutions will lead to some instability properties of the equation.

Résumé(Méthode WKB et instabilité géométrique pour les équations de Schrödinger non linéaires sur des surfaces)

À l’aide de la méthode WKB nous construisons des solutions approchées à l’équa- tion de Schrödinger cubique sur une variété qui possède une géodésique stable. Cette construction permet d’obtenir des résultats d’instabilités dans des espaces de Sobolev.

1. Introduction

Let(M, g)be a Riemannian surface (i.e., a Riemannian manifold of dimen- sion2), orientable or not. We assume thatM is either compact or a compact perturbation of the euclidian space, so that the Sobolev embeddings are true.

Consider ∆ = ∆g the Laplace-Beltrami operator. In this paper we are inter- ested in constructing WKB approximations for the nonlinear cubic Schrödinger equation

Texte reçu le 20 octobre 2006, révisé le 23 avril 2007 et le 22 janvier 2008

Laurent Thomann, Université Paris-Sud, Mathématiques, Bât 425, 91405 Orsay Cedex, France E-mail :laurent.thomann@math.u-psud.fr Url :http://www.math.u- psud.fr/~thomann

2000 Mathematics Subject Classification. — 35Q55; 35B35; 35R25.

Key words and phrases. — nonlinear Schrödinger equation, instability, quasimode.

BULLETIN DE LA SOCIÉTÉ MATHÉMATIQUE DE FRANCE 0037-9484/2008/167/$ 5.00

©Société Mathématique de France

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(1)

® i∂tu(t, x) + ∆u(t, x) =ε|u|2u(t, x), ε=±1, u(0, x) =u0(x)∈Hσ(M),

that is, given a small parameter0< h <1 and an integerN, functionsuN(h) satisfying

(2) i∂tuN(h) + ∆uN(h) =ε|uN(h)|2uN(h) +RN(h), with�uN(h)�Hσ ∼1and�RN(h)�Hσ ≤CNhN.

Here his introduced so thatuN(h)oscillates with frequency∼h1.

These approximate solutions to (1) will lead to some instability properties in the following sense (where h1 will play the role of n):

Definition 1.1. — We say that the Cauchy problem (1) is unstable near 0 in Hσ(M), if for all C >0 there exist timestn−→0 andu1,n, u2,n ∈Hσ(M) solutions of (1) so that

�u1,n(0)�Hσ(M), �u2,n(0)�Hσ(M) ≤ C,

�u1,n(0)−u2,n(0)�Hσ(M)−→0, lim sup�u1,n(tn)−u2,n(tn)�Hσ(M) ≥ 1

2C, whenn−→+∞.

This means that the problem is not uniformly well-posed, if we refer to the following definition:

Definition 1.2. — Let σ∈R. Denote by BR,σ the ball of radius R in Hσ. We say that the Cauchy problem (1)is uniformly well-posed inHσ if the flow map

u0∈BR,σ∩H1(M)�−→Φt(u0)∈Hσ(M), is uniformly continuous for anyt.

We now state our instability result:

Proposition 1.3. — Let 0 < σ < 14, and assume that M has a stable and non degenerated periodic geodesic (see Assumptions1and2), then the Cauchy problem(1)is not uniformly well-posed.

This problem is motivated by the following results: Let(M, g)be a riemannian compact surface, then in [5], N. Burq, P. Gérard and N. Tzvetkov prove that (1) is uniformly well-posed inHσ(M)for σ > 12. Whereas, in [4], they show that (1) is unstable on the sphere S2 for0 < σ < 14. In fact they construct solutions of (1) of the form

(3) uκn(t, x) =κeκnt(n14−σψn(x) +rn(t, x)),

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where0< κ <1,ψn= (x1+ix2)n is a spherical harmonic which concentrates on the equator of the sphere when n−→ +∞ and where rn is an error term which is small. To obtain instability, they considerκn −→κ, then

�uκn(0)−uκnn(0)�Hσ(S2)�|κ−κn| −→0, but

�uκn(tn)−uκnn(tn)�Hσ(S2)�κ|eκntn−eκnn tn| −→2κ, with a suitable choice oftn −→0.

We follow this strategy but as the surface is not rotation invariant, the ansatz will be more complicated than (3).

This result is sharp, because in [6] they show that(1)is uniformly well-posed onS2 whenσ > 14.

On the other hand, in [3] J. Bourgain shows that (1) is uniformly well-posed on the rational torus T2whenσ >0.

These results show how the geometry of M can lead to instability for the equation (1). Therefore it seems reasonable to obtain a result like Proposition 1.3with purely geometric assumptions.

We first make the following assumption onM:

Assumption 1. — The manifoldM has a periodic geodesic.

Denote by γ such a geodesic, then there exists a system of coordinates (s, r) near γ, say for(s, r)∈S1×]−r0, r0[, called Fermi coordinates such that (see [13], p. 80)

1. The curver= 0is the geodesic γparametrized by arclength and 2. The curves s= constant are geodesics parametrized by arclength. The

curvesr=constant meet these curves perpendicularly.

3. In this system the metric writes g=

�1 0 0a2(s, r)

� .

We set the length of γequal to 2π. Denote byR(s, r)the Gauss curvature at (s, r), thenais the unique solution of

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





2a

∂r2 +R(s, r)a= 0, a(s,0) = 1, ∂a

∂r(s,0) = 0.

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The initial conditions traduce the fact that the curve r = 0 is a unit-speed geodesic. In these coordinates the Laplace-Beltrami operator is

∆ := 1

√detgdiv(�

detg g1∇) = 1 a∂s(1

a∂s) +1

a∂r(a∂r).

A function on M, defined locally near γ, can be identified with a function of [0,2π]×]−r0, r0[such that

∀(s, r)∈[0,2π]×]−r0, r0[ f(s+ 2π, r) =f(s, ωr) where ω= 1ifM is orientable andω=−1 ifM is not. Define

(5) ω1= 1

2(ω−1)∈ {−1,0}. From (4)we deduce thataadmits the Taylor expansion

(6) a= 1−1

2R(s)r2+R3(s)r3+· · ·+Rp(s)rp+o(rp), withR(s) =R(s,0) and

(7) Rk(s) = 1

k!

ka

∂rk(s,0), fork≥3.

As a(s+ 2π, r) = a(s, ωr), we deduce R(s+ 2π) = R(s) and for all j ≥ 3, Rj(s+ 2π) =ωjRj(s).

Letp2= a12σ22 be the principal symbol of∆, and

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









 d

dts(t) = ∂p2

∂σ =2σ a2, d

dtσ(t) =−∂p2

∂s =−∂s( 1 a22, d

dtr(t) =∂p2

∂ρ = 2ρ, d

dtρ(t) =−∂p2

∂r =−∂r(1 a22, s(0) =s0, σ(0) =σ0, r(0) =r0, ρ(0) =ρ0,

its associated hamiltonian system, where p2 = p2(s(t), r(t), σ(t), ρ(t)). The system (8) admits a unique solution and defines the hamiltonian flow

Φt: (s0, σ0, r0, ρ0)�−→(s(t), σ(t), r(t), ρ(t)).

The curveΓ ={(s(t) =t, σ(t) = 1/2, r(t) = 0, ρ(t) = 0), t∈[0,2π]} is solution of (8)and its projection in the (s, r) space is the curve γ. Now denote by φ the Poincaré map associated to the trajectory Γ and to the hyperplane Σ = {s = 0}. There exists a neighborhood N of (σ = 1/2, r = 0, ρ = 0) such that the following makes sense: solve the system(8)with the initial conditions (0, σ0, r0, ρ0) ∈ {0} × N and let T be such that s(T) = 2π, then φ is the application

φ: (r0, ρ0)�−→(r(T), ρ(T)).

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Moreover, the Poincaré map is continuously differentiable (see [14] p. 193). To obtain its differential dφ(0,0) at (0,0), we linearize the system (8) about the orbitΓ, i.e.,

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





 d

dts(t) = 2σ, d

dtσ(t) = 0, d

dtr(t) = 2ρ, d

dtρ(t) =−1

2R(s(t))r, thenσ=12,s(t) =tand

(10) d

dt

�r ρ

=

� 0 2

−R/2 0

� �r ρ

� . Hence the application dφ(0,0) is

(11) dφ(0,0) : (r0, ρ0)�−→(r(2π), ρ(2π)),

where(r, ρ)solves (10). As dφ(0,0)is symplectic, it admits two eigenvaluesΛ and Λ1 that are called the characteristic multipliers of the system (10). We add the following assumption on γ, which can be formulated in terms of the eigenvalues of dφ(0,0):

Assumption 2. — The geodesicγ is stable, i.e., dφ(0,0) is a rotation. Then the multipliers take the form Λ =e andΛ1=e withλ∈R. We assume moreover that there existτ, µ >0 such that

(12) ∀(p, q)∈Z×N |p−qλ

π| ≥ µ

|(p, q)|τ,

where |(p, q)|=|p|+|q|. When this condition is fulfilled, we say that γ is non degenerated.

Remark 1.4. — Almost everyλ∈Rsatisfies (12) withτ >1. This is an easy consequence of [1] p. 159, e.g.

Examples 1. — Let M be a surface which has a periodic geodesic γ. In the general case, the eigenvalues of dφ(0,0) defined by (11) are Λ = ρe and Λ11e, withΛ + Λ1∈R+, i.e.,

(13) (ρ−ρ1) sinλ= 0.

Assume that M is a surface of revolution and that R > 0 on γ. Then the characteristic multipliers are

Λ =ρe2πiR and Λ11e2πiR. i) If λ= 2π√

Rsatisfies (12)thenρ= 1andM satisfies the assumptions.

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ii) Let 2√

R�∈N. LetM˜ be a perturbation ofM, and denote by Λ = ˜˜ ρei˜λ and Λ˜1= ˜ρ1eiλ˜,

the new characteristic multipliers.

By (13),ρ˜= 1, and Assumption 2 is satisfied almost surely.

iii) Let a >0, then the torus M =R/Z×R/aZis not under the hypotheses:

in this case dφ(0,0) is not diagonalizable.

Notice that the functionrwhich satisfies (10) is solution of

(14) y(s) +¨ R(s)y(s) = 0.

Considera0the solution of (14) with initial conditionsa0(0) = 1anda˙0(0) =i. Then, from the Floquet theory, there exists a 2π-periodic functionP so that

a0(s) =eiλsP(s)

(ora0(s) = exp (−iλs)P(s), butλcan be replaced with−λ).

Here, and in all the paper we denote by f˙= dsdf if f is differentiable. This notation is motived by the fact thatswill play the role of a time variable (see section2).

In order to prove Proposition 1.3, we construct stationnary approximate solu- tions of (1), as stated in the following theorem

Theorem 1.5. — Assume 1and2. Leth∈]0,1]such that 1h ∈N, letκ, σ >0 andk∈N. Letλbe given by Assumption2andω1 by (5).

Define E0(k) =−1 λ+12k(ω1λπ).

Then for all N∈N, there existλN(k)∈R and a familyuN(h)such that C1hσ ≤ �uN(h)�L2(M)≤C2hσ with C1, C2>0 independent ofN andh, and (15) −∆uN(h) =λN(k)uN(h)−ε|uN(h)|2uN(h) +hNgN(h)

with for all N ∈N

�hNgN(h)�Hn(M)�hNn. Moreover

λN(k) = 1 h2 −2

hE0(k) + 1

√hεκ2hC0+O(1), where C0>0 is independent ofε,κandσ.

Remark 1.6. — The analog of Theorem1.5was proved by J. Ralston in [15]

for the linear case(ε= 0), with the same type of assumptions.

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Remark 1.7. — Consider the more general equations

(16) i∂tu+ ∆u=F(u),

where F : C −→C is a C function. The result of Theorem 1.5 is likely to hold with other nonlinearities F(u), for example for F(z) = z3, F(z) = z4 or F(z) = (1 +|z|2)αz with α < 1. However, the instability phenomenon is strongly related to the gauge invariance of the equation (16).

The scheme of the paper is the following: Thanks to a scaling, we reduce the problem(15)to the resolution of linear Schrödinger equations with a harmonic time dependent potential, and we will see, using Assumption 2, that these equations have periodic solutions. To prove Proposition 1.3we show that the family uN(h) provides good approximations of (1) in times where instability occurs.

Notations 1.8. — In this paperc,Cdenote constants the value of which may change from line to line. We use the notations a∼b,a�b if C1b≤a≤Cb, a≤Cb respectively. By δi,j we mean the Kronecker symbol, i.e., δi,j = 0 for i�=j andδi,i= 1.

Remark 1.9. — In the sequel we do not always mention the dependence on hof the functions: we will writeu,f,ri,. . . instead ofuh,fh,ri,h,. . . Acknowledgements. — The author would like to thank his adviser N. Burq for his constant guidance in this work, P. Pansu for his help in the frame of geometry, and B. Helffer for having pointed out the reference [11].

2. The WKB construction Consider the equation

(17) −∆u=λu−ε|u|2u.

Given h >0, we are looking for a solution of the form (18) u=δh14eihsf(s, r, h),

where δ=κhσ, withκ >0and 0≤σ≤ 14. In all this section,δ will play the role of a parameter.

We try to find a solution (u, λ)of (17) of the form u∼�

j0

hj/2uj, λ∼h2

j0

hj/2λj.

As we will see, identifying each power ofhwill lead to a linear equation which can be solved with a suitable choice of λj.

Choose hsuch thath1 ∈N, this ensures that expihs is2π−periodic. Such a

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condition on h is natural and is known as a Bohr-Sommerfeld quantification condition.

With the ansatz (18), equation(17)becomes

− 1 a2

Å2i

h∂sf+∂s2f− 1 h2f

ã

−1 a∂s

Å1 a

ã Åi

hf +∂sf ã

−∂r2f −∂ra

a ∂rf =λf−εδ2h12|f|2f.

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We make the change of variables x = r

h and set v(s, x, h) = f(s,√ hx, h).

Thus∂rf =1

hxv and∂r2f =h1x2v. Therefore we now have to find v∼�

j0hj/2vj.

Using(6)we obtain the following Taylor expansions inh 1

a2 = 1 +hRx2−2h32R3x3+O(h2), a−1s(a−1) =O(h) and a−1ra=O(h12).

Equation(19)can therefore be written, after multiplication by 12h i∂sv+1

2∂x2v−1 2Rx2v

=1−λh2

2h v+h12R3x3v+1

2εδ2h12|v|2v+hP v, (20)

where

(21) P =A1s2+A2s+A3x+A4

is a second order differential operator with coefficients Aj =Aj(s, x, h)satis- fying Aj(s+ 2π, x, h) =Aj(s, ωx, h)for0≤j≤4.

Denote by E = 12hλh2 = E0+h12E1+· · ·+hp2Ep +o(hp2) and write v = v0+h12v1+· · ·+hp2vp+o(hp2)and by identifying the powers of hwe obtain the system of equations:

Å i∂s+1

2∂x2−1

2Rx2−E0

ã v0= 0, (22)

Å i∂s+1

2∂x2−1

2Rx2−E0

ã

v1=E1v0+R3x3v0+1

2εδ2|v0|2v0, (23)

· · ·=· · · Å

i∂s+1 2∂x2−1

2Rx2−E0

ã

vp =Epv0+Qp. (24)

· · ·=· · ·

so that the(j+ 1)th equation of unknown(vj, Ej)corresponds to the annihi- lation of the coefficient ofhj2 in (20).

Here Qp is a function which only depends onx, s,(vj)jp1 and(Ej)jp1.

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Remark 2.1. — Notice that thanks to the scaling, we have reduced the prob- lem (17)to the resolution of linear equations. However we have to solve them exactly; no smallness assumption onxis possible, asxcan be of size∼ 1h. In this section we will show

Proposition 2.2. — For all p ∈ N, there exist (E0,· · ·, Ep) ∈ Rp+1 and (v0,· · ·, vp)∈(C([0,2π],S(R)))p+1 withv0�= 0, which solve the system (22)- (24).

This permits us to construct approximate solutions of (17); more precisely, we will obtain the following proposition, which is the main result of this section.

Proposition 2.3. — Let χ ∈ C0(]−r0, r0[) be such that 0 ≤χ≤1,χ = 1 on [−r0/2, r0/2]and suppose moreover that χ is an even function. Letδ >0.

Denote by

(25) up(s, r) =δh14χ(r)eish(v0+h12v1+· · ·+hp2vp)(s, r

√h) and by

(26) λp= 1

h2 −2

h(E0+h12E1+· · ·+hp2Ep).

Thenup satisfies�upL2(M)∼δ and

(27) −∆uppup−ε|up|2up+hp21gp(h) with

∀h∈]0,1], ∀n∈N, �hp−12 gp(h)�Hn([0,2π]×R)�δhp−12 n.

2.1. Preliminaries: the analysis of the linear equations. — We will solve the sys- tem (22)-(24) for x∈ R. Notice that the Fermi coordinates are only defined for |r| ≤r0 i.e., forx≤ r0h. That’s the reason why we need the cutoff which appears in the Proposition2.3.

We first give an expansion of the operator P defined by (21).

Lemma 2.4. — Let

P(s, x, h) =A1(s, x, h)∂2s+A2(s, x, h)∂s+A3(s, x, h)∂x+A4(s, x, h), be the differential operator defined by (21). Then for allp≥2,P can be written (28) P(s, x, h) =

p1

k=0

hk2Pk(s, x) +hp2p(s, x, h),

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so that

i) For all0≤k≤p−1,

Pk(s, x) =Ak1(s, x)∂s2+Ak2(s, x)∂s+Ak3(s, x)∂x+Ak4(s, x),

where Akj ∈ C([0,2π]×R), for alls∈[0,2π]the function x�→Akj(s, x) is a polynomial and Akj(s+ 2π, x) =Akj(s, ωx).

ii) Letχ∈ C0(]−r0, r0[)andv∈ C([0,2π],S(R)), then for alln∈N, there existsC=C(p, n)independent ofh∈]0,1]so that

(29) �χ(h12x) ˜Ppv(s, x)�Hn([0,2π]×R)≤C.

Proof. — We first compute the coefficients ofP.

By the Taylor formula near r= 0we have 1

a2(s, r) = 1 +R(s)r2−2R3(s)r3+

p+3 k=4

rkRk(s)

+ rp+4 (p+ 3)!

1 0

(1−t)p+3p+4

∂rp+4 Å 1

a2 ã

(s, tr) dt, where Rk is given by (7).

Now write r=√

hxand obtain

(30) 1

a2(s,√

hx) = 1 +hR(s)x2−2h32R3(s)x3+h2I1(s, x, h), where

(31) I1(s, x, h) =

p+3

k=4

hk24xkRk(s)+

+hp2 xp+4 (p+ 3)!

1 0

(1−t)p+3p+4

∂rp+4 Å 1

a2 ã

(s,√ hxt) dt.

Similarly

(32) 1

a∂s(1 a)(s,√

hx) =hI2(s, x, h), with

(33) I2(s, x, h) =

p+1

k=2

hk22xk k!

1 a∂s(1

a)(s,0)+

+hp2 xp+2 (p+ 1)!

1 0

(1−t)p+1p+2

∂rp+2 Å1

a∂s(1 a)

ã (s,√

hxt) dt,

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and

(34) ∂ra

a (s,√

hx) =h12I3(s, x, h), where

(35) I3(s, x, h) =

p k=1

hk21xk k!

k

∂rk Å∂ra

a ã

(s,0)+

+hp2xp+1 p!

1 0

(1−t)pp+1

∂rp+1 Å∂ra

a ã

(s,√ hxt) dt.

Plug the expressions (30), (32) and (34) in equation (20), and deduce that coefficientsAj are

A1 = 1

2(−1−hRx2+ 2h32R3x3−h2I1), A2 =−iRx2+ 2ih12R3x3−ihI1−1

2I2, A3 =−1

2I3, A4 = 1

2(I1−iI2).

Then with the developments (31), (33) and (35), we see that for all1≤j≤4 and 0≤k≤p−1,x�→Akj(s, x)is a polynomial. Moreover asa(s+ 2π, x) = a(s, ωx), we also haveAkj(s+ 2π, x) =Akj(s, ωx).

To obtain the bound (29), we now have to control the integral rests which appear in (31),(33) and (35).

Letq∈N and let(s, r)�→f(s, r)be one of the functions a2,a1s(a1)or a−1r. Letχ∈ C(]−r0, r0[)and defineFq by

Fq(s, x) =χ(√ hx)

1 0

(1−t)q1q

∂rqf(s,√ hxt) dt.

As f ∈ C([0,2π]×]−r0, r0[), we deduce that for alln1, n2 ∈Nthere exists C=C(q, n1, n2), independent ofh∈]0,1]so that

∀(s, x)∈[0,2π]×R, |∂sn1xn2Fq(s, x)| ≤C.

(36)

Now letv∈ C([0,2π],S(R))andn∈N. We can assume thatn≥2, so that Hn is an algebra. Then by (36)

(37) �xqFqv�Hn([0,2π]×R)≤C�FqHn([0,2π]×R)�xqv�Hn([0,2π]×R)≤C, and this yields ii).

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Consider the Hilbertian basis of L2(R) composed of the Hermite functions (ϕk)k0 which are the eigenfunctions of the harmonic oscillator H =−12x2+

1

2x2, i.e., Hϕk = (k+ 12k. Moreover ϕk(x) = Pk(x)ex2/2 where Pk is a polynomial of degree k with Pk(−x) = (−1)kPk(x). The link between the s- dependent operator −122x+ 12R(s)x2 and H is given by the following result proved by M. Combescure in [11].

Theorem 2.5. — Let a0 : R −→ C be the solution of (14) with a0(0) = 1,

˙

a0(0) =i. Define

α= log|a0|, β= 1 2iloga0

a0

, let the unitary transformT(s)be defined by

T(s) =eiα(s)x˙ 2/2e−iα(s)D, whereD=−i

2(x· ∇+∇ ·x),

and let U(s, τ) be the unitary evolution operator for −122x+ 12R(s)x2, i.e., U(s, τ)ϕis the unique solution of the problem



 Å

i∂s+1 2∂x2−1

2R(s)x2 ã

u= 0, u(τ, x) =ϕ(x)∈L2(R).

Then we have for anys, τ ∈R

U(s, τ) =T(s)ei(β(s)(β(τ))HT(τ)1.

Remark 2.6. — The functions αand β are well defined: suppose that there exists s0 such that a0(s0) = 0, then Rea0 and Ima0 are linearly dependent, which is impossible with this choice of the initial conditions.

Remark 2.7. — Defineθ(s) =β(s)−λswhereλis given by Assumption2.

Then αand θare 2π-periodic real functions. Moreoverα(0) = ˙α(0) =β(0) = θ(0) = 0.

Denote by S(R)the Schwartz space, i.e., the space of smooth functions which are fast decreasing and their derivatives too.

Proposition 2.8. — Let ψ0 ∈ S(R) andE ∈C. Letf ∈ C([0,2π]×R,R) be such that

∀n∈N, ∀s∈[0,2π], ∂snf(s,·)∈ S(R), in other words f ∈ C([0,2π],S(R)).

Let ψ∈ C1

[0,2π], L2(R)�

∩ C0

[0,2π], H2(R)�

be the solution of

o

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(38)



i∂sψ+1

2∂2xψ−1

2R(s)x2ψ−Eψ=f, ψ(0, x) =ψ0(x).

Thenψ∈ C([0,2π],S(R)).

Proof. — By replacingψwith eiEtψ, we can assume thatE= 0. The solution of equation(38)is given by

ψ(s,·) =U(s,0)ψ0−i

s 0

U(s, τ)f(τ,·) dτ

=T(s)e−iβ(s)H Å

ψ0−i

s 0

eiβ(τ)HT(τ)−1f(τ,·) dτ ã (39) .

AsD is a transport operator, we have

T, T−1:C([0,2π],S(R))−→ C([0,2π],S(R)), we only have to show that

eiβH :C([0,2π],S(R))−→ C([0,2π],S(R)). This follows from the fact thatβ is regular and eiH :S(R)−→ S(R).

The description ofU given in Theorem2.5yields the following representation ofU(s,0)ϕk:

Proposition 2.9. — For allk∈N ands, x∈Rwe have (40) U(s,0)ϕk(x) =eiα(s)x˙ 2/2e−i(12+k)β(s)e12α(s)ϕk

Äxe−α(s)ä . Proof. — According to Theorem2.5, and asHϕk = (k+12k,

U(s,0)ϕk =eiα(s)x˙ 2/2ei(k+12)β(s)eiα(s)Dϕk.

Denote byf(s) =eiα(s)Dϕk. Thenf is solution of the transport equation

sf =−1

2α(s) (x∂˙ xf+∂x(xf)) =−1

2α(s) (f˙ + 2x∂xf)

with Cauchy dataf(0, x) =ϕk(x). Make the change of variablesσ=α(s)and set g(σ) = f(s). Therefore g satisfies ∂σg = −12(g+ 2x∂xg). The equation x = ˙x, x(0) = x0 admits the solution x(τ) = x0eτ and the characteristics method givesg(τ, x(τ)) =e12τϕk(x0) =e12τϕk(x(τ)eτ), hence

f(s) =e12α(s)ϕk(xeα(s)).

(15)

Corollary 2.10. — Let k∈N, define ω1=12(ω−1) and E0(k) =−1λ+12k(ω1λπ). Then

wk =eisE0(k)U(s,0)ϕk

=eisE0(k)eiα(s)x˙ 2/2ei(12+k)β(s)e12α(s)ϕk

Äxeα(s)ä (41)

is solution of the equation Å

i∂s+1 2∂x2−1

2R(s)x2−E0(k) ã

wk(s, x) = 0.

Proof. — On the one hand, from Proposition2.9we deduce

wk(s+ 2π, x) =e2iπE0(k)eiλ(12+k)wk(s, x) =eikω1πwk(s, x)

= (−1)1wk(s, x) =wk(s, ωx).

On the other hand, wk satisfies(22)because of the definition of U(s,0).

Fixk0∈Nand takev0=wk0 with the previous choice ofE0(k0). This choice corresponds to thek0th level of energy for the harmonic oscillator.

Remark 2.11. — Until now we did not use the restriction (12), but it will be crucial in the following.

Proposition 2.12. — For allp≥0, there existEp∈Cand vp∈ C([0,2π],S(R))which solve(24).

Remark 2.13. — As stated in Theorem1.5, theEj’s are in fact real numbers.

This will be proved in Lemma2.17.

Proof. — We proceed by induction onp∈N.

Forp= 0the result was proved in Corollary2.10.

Let p ≥ 1, and suppose that for all j ≤ p−1 there exist Ej ∈ C and vj ∈ C([0,2π],S(R))which solve the(j+ 1)th equation of (22). Whenp≥2, set

˜

vp−1=h12v1+· · ·+hp−12 vp−1, E˜p1=h12E1+· · ·+hp21Ep1

and ˜v0 = ˜E0 = 0. By (28), the function Qp given by (24) is the coefficient of hp2 in the expansion in h of

p−1˜vp−1+1

2εδ2|v0+ ˜vp−1|2(v0+ ˜vp−1) +h

p1

k=0

hk2Pk

(v0+ ˜vp−1).

Now using the regularity of thevj’s and the fact that for all0≤k≤p−1,Pk

is an operator

Pk :C([0,2π],S(R))−→ C([0,2π],S(R)),

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we obtain Qp∈ C([0,2π],S(R)).

MoreoverQp satisfies,∀(s, x)∈[0,2π]×R

Qp(s+ 2π, x) =Qp(s, ωx) because this property holds for the vj’s, anda.

Define Fp(s, x) = e−iα(s)e˙ 2α(s)x2/2Qp(s, xeα(s)), then Fp ∈ C([0,2π],S(R)) and satisfies Qp(s, x) =eiα(s)x˙ 2/2Fp(s, xeα(s))and Fp(s+ 2π, x) =Fp(s, ωx). Let us decompose Fp on the basis (ϕj)j≥0: there exists a unique family of smooth functions (gjp(s))j0∈l2(N)so that

(42) Fp(s, y) =�

j0

gpj(s)ϕj(y).

Then

(43) Qp(s, x) =�

j0

gjp(s)eiα(s)x˙ 2/2ϕj(xeα(s)) =�

j0

hpj(s)wj(s, x), where according to(41)

(44) hpj(s) =eisE0(j)ei(12+j)β(s)e12α(s)gjp(s).

We have

Qp(s, ωx) =�

j0

hpj(s)wj(s, ωx), but also

Qp(s, ωx) =Qp(s+ 2π, x) =�

j0

hpj(s+ 2π)wj(s+ 2π, x)

=�

j0

hpj(s+ 2π)wj(s, ωx), and from the uniqueness of thehpj’s we deducehpj(s+ 2π) =hpj(s).

We are now looking for a solution of(24)of the form

(45) vp(s, x) =�

j0

epj(s)wj(s, x)

where the epj’s are 2π-periodic functions. For all j ≥0, by Corollary2.10 we have Å

i∂s+1 2∂2x−1

2Rx2ã Ä epjwj

ä=ie˙pjwj+ (E0(k0)−E0(j))epjwj,

hence we have to solve the equations

(46) ie˙pj+ (E0(k0)−E0(j))epj =hpjj,k0Ep.

(17)

AsE0(k0)−E0(j) = 12(k0−j)(ω1λπ), the solutions of (46) take the form (47) epj(s) =e12i(k0−j)(ω1λπ)s

Å Cjp−i

s 0

hpj(τ)e12i(k0−j)(ω1λπdτ ã

forj�=k0, and

epk0(s) =Ckp0−i

s 0

hpk0(τ) dτ−iEps.

The constantsCjp∈CandEp ∈Chave to be determined such thatepj(s+2π) = epj(s).

• Casej=k0:

epk0(s+ 2π) =−i

0

hpk0(τ) dτ−2πiEp+epk0(s), thusepk0 is2π-periodic iff

(48) Ep=− 1

0

hpk0(τ) dτ.

• Casej�=k0:

Denote by ˜hpj : τ �−→ hpj(τ)e−i12(k0−j)(ω1λπ and by K = ei(k0−j)(πω1−λ). Then

s+2π 0

˜hpj(τ) dτ =

0

˜hpj(τ) dτ+

s+2π

˜hpj(τ) dτ

=

0

˜hpj(τ) dτ+K−1

s 0

pj(τ) dτ,

and by (47)

epj(s+ 2π) =Kei12(k0j)(ω1λπ)s Ç

Cjp−i

s+2π 0

˜hpj(τ) dτ å

=ei12(k0−j)(ω1λπ)s Ç

KCjp−iK

0

pj(τ) dτ−i

s 0

˜hpj(τ) dτ å (49) .

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Notice that K�= 1, asλ�∈πQand choose Cjp= iK

K−1

0

pj(τ) dτ,

then according to (47)and (49), the functionepj is2π−periodic.

Now, we show that the constants Cjp are uniformly bounded in j ≥ 0, so that the functionvp given by (45) is well defined. We first need the

Lemma 2.14. — Let (hpj)j0 ∈ l2(N) be the family of 2π−periodic functions defined by (44)andhpj(s) =�

n∈Zcpl,jeils its Fourier decomposition. Then for all n1, n2∈Nthere existsCp>0 such that for allj ∈N

l∈Z

j2n1l2n2|cpl,j|2≤Cp.

Proof. — Consider the functionFp∈ C([0,2π],S(R))which defines the fam- ily (gpj(s))j≥0 ∈l2(N)with (42). Denote by H =−12x2+12x2. Letn1, n2∈N and decompose the function ∂sn2Hn1Fp on the basis(ϕj)j≥0

sn2Hn1Fp(s, y) =�

j0

˜

gjp(s)ϕj(y) where (˜gjp)j0is a smooth family of functions inl2(N).

Using thatHϕj = (j+12j and thatFp ∈ C([0,2π],S(R)), we have for all n1, n2∈N

sn2Hn1Fp(s, y) =�

j0

(j+1

2)n1(gjp)(n2)(s)ϕj(y).

By uniqueness of such a decomposition, Å

(j+1

2)n1(gpj)(n2) ã

j0

= (˜gpj)j0∈l2(N).

Then by the definition (44) of hpj, an easy induction on n1, n2∈Nshows that Äjn1(hpj)(n2)ä

j≥0∈l2(N). Write the Fourier decomposition of hpj hpj(s) =�

n∈Z

cpl,jeils and by Parseval

j≥0

l∈Z

j2n1l2n2(s)|cpl,j|2=�

j≥0

j2n1

0 |(hpj)(n2)(s)|2ds≤Cp. In particular, for all j∈N

(19)

l∈Z

j2n1l2n2|cpl,j|2≤Cp, hence the result.

End of the proof of Proposition 2.12: Using the Fourier decomposition ofhj

we obtain

Cjp= iK K−1

0

˜hpj(τ) dτ

= iK K−1

l∈Z

cpl,j

0

ei(l−12(k0−j)(ω1λπ))τ

=−i�

l∈Z

cpl,j

l−12(k0−j)(ω1λπ). (50)

With Assumption 2we have

��l−1

2(k0−j)(ω1−λ π)��= 1

2|(2l−(k0−j)ω1) + (k0−j)λ π|

≥ 1 2

µ

|(2l−(k0−j)ω1, k0−j)|τ, and forj≥k0,|2l−(k0−j)ω1|+|k0−j| ≤2(|l|+|j|), then

(51) ��l−1

2(k0−j)(ω1−λ

π)��≥ cµ (|l|+|j|)τ. Hence, from (50) and (51) we deduce

(52) |Cjp|��

l∈Z

|cpl,j|(|j|+|l|)τ��

l∈Z

|cpl,j|(|j|τ+|l|τ).

By Cauchy-Schwarz and Lemma2.14, from (52) we obtain

|Cjp|��

l∈Z

1 +|l|

1 +|l||cpl,j|(|j|τ+|l|τ)

��

l∈Z

1 (1 +|l|)2

12

l∈Z

|cpl,j|2(1 +|l|)2(|j|+|l|)

12

≤Cp. (53)

Set

vp(s, x) =�

j0

epj(s)wj(s, x).

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For allj∈N,s�−→epj(s)wj(s, x)is continuous and there existsc >0such that for allj > k0, and for alls∈[0,2π]

|epj(s)wj(s, x)|�|gjp(s)||ϕj(cx)| and this shows that vp ∈ C�

[0,2π], L2(R)�. Now using Proposition 2.8 we conclude, by uniqueness of such a solution, thatvp∈ C([0,2π],S(R)).

2.2. The nonlinear analysis and proof of Proposition2.3

Lemma 2.15. — The constantE1 given by Proposition2.12writes E1=−εδ2C0 whereC0>0 is independent ofεandδ.

Proof. — Consider the equation Å

i∂s+1 2∂2x−1

2Rx2−E0

ã

v1=E1v0+R3x3v0+1

2εδ2|v0|2v0, with

v0(s, x) =eisE0(k0)eiα(s)x˙ 2/2ei(12+k0)β(s)e12α(s)ϕk0

Äxeα(s)ä . By the definition ofQp (see (24)),

Q1(s, x) =R3(s)x3v0(s, x) +1

2εδ2|v0|2v0(s, x), and by (43),Q1 can be written

Q1(s, x) =�

j0

h1j(s)wj(s, x).

According to formula (48), we only have to compute the termh1k0in the previous expansion.

Write the expansion of|ϕk0|2ϕk0 on the basis (ϕj)j≥0:

(54) |ϕk0|2ϕk0 =�

j0

pjϕj,

withpj∈Randpj= 0forj−k0= 1mod2as ϕk(−x) = (−1)kϕk(x).

Then by (54) and the expression (41) ofwj

|v0|2v0(s, x) =e−isE0(k0)eiα(s)x˙ 2/2e−i(12+k0)β(s)e32α(s)k0|2ϕk0

Äxe−α(s)ä

=�

j0

pjeisE0(k0)eiα(s)x˙ 2/2ei(12+k0)β(s)e32α(s)ϕj

Äxeα(s)ä

=�

j0

fj(s)wj(s, x)

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