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www.elsevier.com/locate/anihpc

On the Schrödinger–Maxwell equations under the effect of a general nonlinear term

A. Azzollini

a

, P. d’Avenia

b

, A. Pomponio

b,

aDipartimento di Matematica ed Informatica, Università degli Studi della Basilicata, Via dell’Ateneo Lucano 10, I-85100 Potenza, Italy bDipartimento di Matematica, Politecnico di Bari, Via E. Orabona 4, I-70125 Bari, Italy

Received 14 May 2009; received in revised form 9 November 2009; accepted 9 November 2009 Available online 3 December 2009

Abstract

In this paper we prove the existence of a nontrivial solution to the nonlinear Schrödinger–Maxwell equations inR3, assuming on the nonlinearity the general hypotheses introduced by Berestycki and Lions.

©2009 Elsevier Masson SAS. All rights reserved.

Résumé

Dans cet article on démontre l’existence d’une solution non-banale et positive pour les équations non-linéaires de Schrödinger–

Maxwell dansR3en supposant que le terme non-linéaire satisfait les hypothèses introduites par Berestycki et Lions.

©2009 Elsevier Masson SAS. All rights reserved.

1. Introduction

In the recent years, the following electrostatic nonlinear Schrödinger–Maxwell equations, also known as nonlinear Schrödinger–Poisson system,

u+qφu=g(u) inR3,

φ=qu2 inR3, (SM)

have been object of interest for many authors. Indeed a similar system arises in many mathematical physics contexts, such as in quantum electrodynamics, to describe the interaction between a charge particle interacting with the electro- magnetic field, and also in semiconductor theory, in nonlinear optics and in plasma physics. We refer to [4] for more details in the physics aspects.

The greatest part of the literature focuses on the study of the previous system for the very special nonlinearity g(u)= −u+ |u|p1u, and existence, nonexistence and multiplicity results are provided in many papers for this particular problem (see [1,2,10,12–14,19–21,24,28]). In [9,11,27], also the linear and the asymptotic linear cases have

The authors are supported by M.I.U.R.-P.R.I.N. “Metodi variazionali e topologici nello studio di fenomeni non lineari”.

* Corresponding author.

E-mail addresses:antonio.azzollini@unibas.it (A. Azzollini), p.davenia@poliba.it (P. d’Avenia), a.pomponio@poliba.it (A. Pomponio).

0294-1449/$ – see front matter ©2009 Elsevier Masson SAS. All rights reserved.

doi:10.1016/j.anihpc.2009.11.012

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been studied, whereas in [22] the problem has been dealt with in a bounded domain, with Neumann conditions on the boundary.

The aim of this paper is to study the Schrödinger–Maxwell system assuming the same very general hypotheses introduced by Berestycki & Lions, in their celebrated paper [7]. Actually, we assume that the following hold forg:

(g1) gC(R,R);

(g2) −∞<lim infs0+g(s)/slim sups0+g(s)/s= −m <0;

(g3) −∞lim sups→+∞g(s)/s50;

(g4) there existsζ >0 such thatG(ζ ):=ζ

0 g(s) ds >0.

Using similar assumptions on the nonlinearity g, [3,18] and [23] studied, respectively, a nonlinear Schrödinger equation in presence of an external potential and a system of weakly coupled nonlinear Schrödinger equations. We mention also [5] where the Klein–Gordon and in Klein–Gordon–Maxwell equations are considered.

The main result of the paper is

Theorem 1.1.Ifgsatisfies(g1)–(g4), then there existsq0>0such that, for any0< q < q0, problem(SM)admits a nontrivial positive radial solution(u, φ)H1(R3)×D1,2(R3).

Some remarks on this result are in order:

• the assumptions are trivially satisfied by nonlinearities likeg(u)= −u+ |u|p1u, for anyp∈ ]1,5[;

• hypotheses ongarealmost necessaryin the sense specified in [7, Subsection 2.2];

• the fact that the result is obtained for smallqis not surprising for at least two reasons: first, because smallqmakes, in some sense, less strong the influence of the termφu, which constitutes, in the first equation, a perturbation with respect to the classical nonlinear Schrödinger equation treated in [7]; second, there is a nonexistence result for largeq andg(u)= −u+ |u|p1uwithp∈ ]1,2](see [24]).

From the technical point of view, dealing with (SM) under the effect of a general nonlinear term presents several difficulties. Indeed the lack of the following global Ambrosetti–Rabinowitz growth hypothesis ong:

there exists μ >2 such that 0< μG(s)g(s)s, for alls∈R,

brings on two obstacles to the standard Mountain Pass arguments both in checking the geometrical assumptions in the functional and in proving the boundedness of its Palais–Smale sequences. To overcome these difficulties, we will use a combined technique consisting in a truncation argument (see [17,21]) and a monotonicity trickà laJeanjean [15]

(see also Struwe [26]).

It is natural to ask about multiplicity of solutions of (SM). However, our approach does not seem to work in this direction.

The paper is organized as follows. In Section 2 we introduce the functional framework for solving our problem by a variational approach. In Section 3 we define a sequence of modified functionals on which we can easily apply the Mountain Pass Theorem. Then we study the convergence of the sequence of critical points obtained. Finally Appendix A is devoted to prove a Pohozaev type identity which we use, in Section 3, as a fundamental tool in our arguments.

Notation.

• For any 1s+∞, we denote by · s the usual norm of the Lebesgue spaceLs(R3);

H1(R3)is the usual Sobolev space endowed with the norm u2:=

R3

|∇u|2+u2;

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D1,2(R3)is completion ofC0(R3)(the compactly supported functions inC(R3)) with respect to the norm u2D1,2(R3):=

R3

|∇u|2;

• for brevity, we denoteα=12/5.

2. Functional setting

We first recall the following well-known facts (see, for instance [4,6,12,24]).

Lemma 2.1.For everyuH1(R3), there exists a uniqueφuD1,2(R3)solution of

φ=qu2, inR3. Moreover,

(i) φu2D1,2(R3)=q

R3φuu2; (ii) φu0;

(iii) for anyθ >0:φuθ(x)=θ2φu(x/θ ), whereuθ(x)=u(x/θ );

(iv) there existC, C>0independent ofuH1(R3)such that φuD1,2(R3)Cqu2α,

and

R3

φuu2Cqu4α; (1)

(v) ifuis a radial function thenφuis radial, too.

Following [7], defines0:=min{s∈ [ζ,+∞[ |g(s)=0}(s0= +∞ifg(s) =0 for any). We setg˜:R→R the function such that

˜ g(s)=

⎧⎨

g(s) on[0, s0];

0 onR+\ [0, s0];

(g(s)ms)+g(s) onR.

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By the strong maximum principle and by (ii) of Lemma 2.1, ifuis a nontrivial solution of (SM) withg˜in the place ofg, then 0< u < s0and so it is a positive solution of (SM). Therefore we can suppose thatgis defined as in (2), so that (g1), (g2), (g4) and then the following limit

s→±∞lim g(s)

s5 =0 (3)

hold.

We set g1(s):=

(g(s)+ms)+, ifs0, 0, ifs <0, g2(s):=g1(s)g(s), fors∈R. Since

slim0

g1(s) s =0,

s→±∞lim g1(s)

s5 =0, (4)

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and

g2(s)ms,s0, (5)

by some computations, we have that for anyε >0 there existsCε>0 such that

g1(s)Cεs5+εg2(s),s0. (6)

If we set Gi(t ):=

t 0

gi(s) ds, i=1,2, then, by (5) and (6), we have

G2(s)m

2s2,s∈R (7)

and for anyε >0 there existsCε>0 such that G1(s)Cε

6 s6+εG2(s),s∈R. (8)

The solutions(u, φ)H1(R3)×D1,2(R3)of (SM) are the critical points of the action functionalE:H1(R3)× D1,2(R3)→R, defined as

Eq(u, φ):=1 2

R3

|∇u|2−1 4

R3

|∇φ|2+q 2

R3

φu2

R3

G(u).

The action functionalEqexhibits a strong indefiniteness, namely it is unbounded both from below and from above on infinite dimensional subspaces. This indefiniteness can be removed using the reduction method described in [4,6], by which we are led to study a one variable functional that does not present such a strongly indefinite nature. Hence, it can be proved that(u, φ)H1(R3)×D1,2(R3)is a solution of (SM) (critical point of functionalEq) if and only if uH1(R3)is a critical point of the functionalIq:H1(R3)→Rdefined as

Iq(u)=1 2

R3

|∇u|2+q 4

R3

φuu2

R3

G(u),

andφ=φu.

We will look for critical points ofIqonHr1(R3):= {uH1(R3)|uis radial}, which is a natural constraint.

3. The perturbed functional

Kikuchi, in [21], considered (SM), whereg(u)= −u+ |u|p1u, with 1< p <5. To overcome the difficulty in finding bounded Palais–Smale sequences for the associated functionalIq, following [17], he introduced the cut-off functionχC(R+,R)satisfying

⎧⎪

⎪⎩

χ (s)=1, fors∈ [0,1], 0χ (s)1, fors∈ ]1,2[, χ (s)=0, fors∈ [2,+∞[, χ2,

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and studied the following modified functionalIqT :H1(R3)→R IqT(u)=1

2

R3

|∇u|2+q 4k˜T(u)

R3

φuu2

R3

G(u),

where, for everyT >0, k˜T(u)=χ

u2 T2

.

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With this penalization, forT sufficiently large and forqsufficiently small, he is able to find a critical pointu¯such that ¯uT and so he concludes thatu¯is a critical point ofIq.

Let us observe that ifg(u)=f (u)uwithf satisfying the Ambrosetti–Rabinowitz growth condition, the argu- ments of Kikuchi still hold with slide modifications.

On the other hand, in presence of nonlinearities satisfying Berestycki–Lions assumptions, further difficulties arise about the geometry of our functional and compactness. First of all, as in [21], we introduce a similar truncated func- tionalIqT :Hr1(R3)→R

IqT(u)=1 2

R3

|∇u|2+q 4kT(u)

R3

φuu2

R3

G(u),

where, now, kT(u)=χ

uαα Tα

.

TheC1-functionalIqT satisfies the geometrical assumptions of the Mountain–Pass Theorem but, under our general as- sumptions on the nonlinearity, we are not able to obtain the boundedness of the Palais–Smale sequences. Therefore we use an indirect approach developed by Jeanjean. We apply the following slight modified version of [15, Theorem 1.1]

(see [16]).

Theorem 3.1.Let(X, · )be a Banach space andJ⊂R+an interval. Consider the family ofC1functionals onX Iλ(u)=A(u)λB(u),λJ,

withBnonnegative and eitherA(u)→ +∞orB(u)→ +∞asu → ∞and such thatIλ(0)=0.

For anyλJ we set Γλ:=

γC

[0,1], X γ (0)=0, Iλ

γ (1)

<0 . If for everyλJ the setΓλis nonempty and

cλ:= inf

γΓλ

tmax∈[0,1]Iλ γ (t )

>0, (10)

then for almost everyλJ there is a sequence(vn)nXsuch that (i) (vn)nis bounded;

(ii) Iλ(vn)cλ;

(iii) (Iλ)(vn)→0in the dualX1ofX.

In our case,X=Hr1(R3), A(u):=1

2

R3

|∇u|2+q 4kT(u)

R3

φuu2+

R3

G2(u),

B(u):=

R3

G1(u),

so that the perturbed functional we study is Iq,λT (u)=1

2

R3

|∇u|2+q 4kT(u)

R3

φuu2+

R3

G2(u)λ

R3

G1(u).

Actually, this functional is the restriction to the radial functions of a C1-functional defined on the whole space H1(R3)and for everyu, vH1(R3)

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IqT (u), v

=

R3

(u| ∇v)+qkT(u)

R3

φuuv

+ 4Tαχ

uαα

Tα

R3

φuu2

R3

|u|α2uv+

R3

g2(u)vλ

R3

g1(u)v.

In order to apply Theorem 3.1, we have just to define a suitable intervalJ such thatΓλ = ∅, for anyλJ, and (10) holds.

Observe that, according to [7], as a consequence of (g4), there exists a functionzHr1(R3)such that

R3

G1(z)

R3

G2(z)=

R3

G(z) >0. (11)

Then there exists 0<δ <¯ 1 such that

¯ δ

R3

G1(z)

R3

G2(z) >0. (12)

We defineJ as the interval[¯δ,1]. Lemma 3.2.Γλ = ∅, for anyλJ. Proof. LetλJ. Setθ >¯ 0 andz¯=z(·/θ ).¯

Defineγ: [0,1] →Hr1(R3)in the following way γ (t )=

0, ift=0,

¯

z(·/t ), if 0< t1.

It is easy to see thatγ is a continuous path from 0 toz. Moreover, we have that¯ Iq,λT

γ (1) θ¯

2

R3

|∇z|2+q 4θ¯5χ

θ¯3zαα Tα

R3

φzz2

+ ¯θ3

R3

G2(z)− ¯δ

R3

G1(z)

and then, ifθ¯is sufficiently large, by (12) and (9) we getIq,λT (γ (1)) <0. 2 Lemma 3.3.There exists a constantc >˜ 0such thatcλc >˜ 0for allλJ.

Proof. Observe that for anyuHr1(R3)andλJ, using (7) and (8) forε <1, we have Iq,λT (u)1

2

R3

|∇u|2+q 4kT(u)

R3

φuu2+

R3

G2(u)

R3

G1(u)

1

2

R3

|∇u|2+(1ε)m 2

R3

u2Cε 6

R3

|u|6

and then, by Sobolev embeddings, we conclude that there existsρ >0 such that, for anyλJanduHr1(R3)with u =0 anduρ,it resultsIq,λT (u) >0. In particular, for anyu =ρ,we haveIq,λT (u)c >˜ 0.Now fixλJ andγΓλ.Sinceγ (0)=0 and Iq,λT (γ (1)) <0, certainlyγ (1)> ρ. By continuity, we deduce that there exists tγ∈ ]0,1[such thatγ (tγ) =ρ.Therefore, for anyλJ,

cλ inf

γΓλIq,λT γ (tγ)

c >˜ 0. 2

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We present a variant of the Strauss’ compactness result [25] (see also [7, Theorem A.1]). It will be a fundamental tool in our arguments:

Theorem 3.4.LetP andQ:R→Rbe two continuous functions satisfying

slim→∞

P (s) Q(s)=0,

(vn)n, vandwbe measurable functions fromRNtoR, withzbounded, such that sup

n

RN

Q vn(x)

wdx <+∞, P

vn(x)

v(x) a.e. inRN.

Then(P (vn)v)wL1(B)→0, for any bounded Borel setB.

Moreover, if we have also

slim0

P (s) Q(s)=0,

xlim→∞sup

n

vn(x)=0,

then(P (vn)v)wL1(RN)→0.

In analogy with the well-known compactness result in [8], we state the following result

Lemma 3.5.For anyλJ, each bounded Palais–Smale sequence for the functionalIq,λT admits a convergent subse- quence.

Proof. LetλJ and(un)nbe a bounded (PS) sequence forIq,λT , namely Iq,λT (un)

n is bounded, Iq,λT

(un)→0 in Hr1

R3

. (13)

Up to a subsequence, we can suppose that there existsuHr1(R3)such that un u weakly inHr1

R3

, (14)

unu inLp R3

, 2< p <6, (15)

unu a.e. inRN. (16)

If we apply Theorem 3.4 for P (s)=gi(s), i=1,2, Q(s)= |s|5, (vn)n=(un)n, v=gi(u), i =1,2 and wC0(RN),by (3), (4) and (16) we deduce that

R3

gi(un)w

R3

gi(u)w, i=1,2.

Moreover, by (15) and [24, Lemma 2.1], we have kT(un)

R3

φununwkT(u)

R3

φuuw,

χ unαα

Tα

R3

φunu2n

R3

|un|25unwχ uαα

Tα

R3

φuu2

R3

|u|25uw.

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As a consequence, by (13) and (14) we deduce(Iq,λT )(u)=0 and hence

R3

|∇u|2+qkT(u)

R3

φuu2+ 4Tαχ

uαα Tα

uαα

R3

φuu2+

R3

g2(u)u=λ

R3

g1(u)u. (17)

By weak lower semicontinuity we have:

R3

|∇u|2lim inf

n

R3

|∇un|2. (18)

Again, by (15) we have kT(un)

R3

φunu2nkT(u)

R3

φuu2, (19)

χ unαα

Tα

unαα

R3

φunu2nχ uαα

Tα

uαα

R3

φuu2. (20)

If we apply Theorem 3.4 forP (s)=g1(s)s, Q(s)=s2+s6, (vn)n=(un)n, v=g1(u)u,andw=1,by (3), (4) and (16), we deduce that

R3

g1(un)un

R3

g1(u)u. (21)

Moreover, by (16) and Fatou’s lemma

R3

g2(u)ulim inf

n

R3

g2(un)un. (22)

By (17), (19), (20), (21) and (22), and since(Iλ)(un), un →0, we have lim sup

n

R3

|∇un|2=lim sup

n

λ

R3

g1(un)un

R3

g2(un)un

qkT(un)

R3

φunu2n 4Tαχ

unαα Tα

unαα

R3

φunu2n

λ

R3

g1(u)u

R3

g2(u)uqkT(u)

R3

φuu2 4Tαχ

uαα

Tα

uαα

R3

φuu2

=

R3

|∇u|2. (23)

By (18) and (23), we get limn

R3

|∇un|2=

R3

|∇u|2, (24)

hence limn

R3

g2(un)un=

R3

g2(u)u. (25)

Sinceg2(s)s=ms2+h(s), withha positive and continuous function, by Fatou’s lemma we have

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R3

h(u)lim inf

n

R3

h(un),

R3

u2lim inf

n

R3

u2n.

These last two inequalities and (25) imply that, up to a subsequence,

R3

u2=lim

n

R3

u2n,

which, together with (24), shows thatunustrongly inHr1(R3). 2

Lemma 3.6.For almost everyλJ, there existsuλHr1(R3),uλ =0, such that(Iq,λT )(uλ)=0andIq,λT (uλ)=cλ. Proof. By Theorem 3.1, for almost everyλJ, there exists a bounded sequence(uλn)nHr1(R3)such that

Iq,λT uλn

cλ; (26)

Iq,λT uλn

→0 in Hr1

R3

. (27)

Up to a subsequence, by Lemma 3.5, we can suppose that there existsuλHr1(R3)such thatuλnuλ inHr1(R3).

By Lemma 3.3, (26) and (27) we conclude. 2

Therefore there existn)nJ and(un)nHr1(R3)such that Iq,λT

n(un)=cλn, Iq,λT

n

(un)=0. (28)

Lemma 3.7.Letunbe a critical point forIq,λT

nat levelcλn. Then, forT >0sufficiently large, there existsq0=q0(T ) such that for any0< q < q0, up to a subsequence,unαT, for anyn1.

Proof. We will argue by contradiction.

First of all, since(Iq,λT

n)(un)=0,unsatisfies the following Pohozaev type identity 1

2

R3

|∇un|2+5q 4 kT(un)

R3

φunu2n+ 3q Tαχ

unαα Tα

unαα

R3

φunu2n

=3λn

R3

G1(un)−3

R3

G2(un) (29)

(see Appendix A for the proof).

Moreover, combining (29) with the first of (28) and by (1), we get

R3

|∇un|2=3cλn+q 2kT(un)

R3

φunu2n+ 3q Tαχ

unαα Tα

unαα

R3

φunu2n

3cλn+C1q2kT(un)un4α+C2χ unαα

Tα q2

Tαun4α+α. (30)

We are going to estimate the right part of the previous inequality. By the min–max definition of the Mountain Pass level, we have

cλnmax

θ Iq,λT

n

z(·/θ )

max

θ

θ 2

R3

|∇z|2+θ3

R3

G2(z)− ¯δ

R3

G1(z)

(10)

+max

θ

q 4θ5χ

θ3zαα

Tα

R3

φzz2

=A1+A2(T )

wherezis the function such that (11) holds.

Now, ifθ32Tα/zααthenA2(T )=0,otherwise we compute A2(T )q

4 2Tα

zαα 53

R3

φzz2=C3q2T4.

We also have

C1q2kT(un)un4αC4q2T4 C2χ

unαα

Tα q2

Tαun4α+αC5q2T4. Then, from (30) we deduce that

R3

|∇un|23A1+C6q2T4. (31)

On the other hand, since(Iq,λT

n)(un), (un) =0, by (6) we have that

R3

|∇un|2+qkT(un)

R3

φunu2n+ 4Tαχ

unαα

Tα

unαα

R3

φunu2n+

R3

g2(un)un

=λn

R3

g1(un)unCε

R3

|un|6+ε

R3

g2(un)un. (32)

Now, by (5) and (32), we obtain m(1ε)

R3

u2n(1ε)

R3

g2(un)un

Cε

R3

|un|6 4Tαχ

unαα

Tα

unαα

R3

φnu2n

C

R3

|∇un|2 3

+ ¯Cq2T4

C

3A1+C6q2T43

+ ¯Cq2T4 (33)

where in the last inequality we have used (31).

We suppose by contradiction that there exists no subsequence of (un)n which is uniformly bounded byT in the α-norm. As a consequence, for a certainn¯it should result that

unα> T ,nn.¯ (34)

Without any loss of generality, we are supposing that (34) is true for anyun. Therefore, by (31) and (33), we conclude that

T2<un2αCun2C7+C8q2T4+C9q4T8+C10q6T12

which is not true forT large andqsmall enough: indeed we can findT0>0 such thatT02> C7+1 andq0=q0(T0) such thatC8q2T04+C9q4T08+C10q6T012<1, for anyq < q0, and we find a contradiction. 2

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Proof of Theorem 1.1. LetT , q0 be as in Lemma 3.7 and fix 0< q < q0. Let un be a critical point for Iq,λT

n at levelcλn. We prove that(un)nis aH1-bounded Palais–Smale sequence forIq.

Since by Lemma 3.7

unαT , (35)

the boundedness in theH1-norm trivially follows from arguments such as those in (31) and (33). Finally, by (35), certainly we have that

Iq,λT

n(un)=1 2

R3

|∇u|2+q 4

R3

φuu2+

R3

G2(u)λn

R3

G1(u),

and then, sinceλn1, we can prove that(un)nis a (PS) sequence forIqby similar argument as in [3, Theorem 1.1].

Now we conclude arguing as in Lemma 3.5. 2 Appendix A. A Pohozaev type identity

In this section we show that ifu, φHloc2 (R3)solve

⎧⎪

⎪⎨

⎪⎪

u+qkT(u)φu+q α Tαχ

uαα

Tα

|u|2/5u

R3

φu2=g(u) inR3,

φ=qu2 inR3,

(36)

then the following Pohozaev type identity 1

2

R3

|∇u|2+5q 4 kT(u)

R3

φu2+ 3q Tαχ

uαα

Tα

uαα

R3

φu2=3

R3

G(u) (37)

holds.

Indeed, by [13, Lemma 3.1], for everyR >0, we have

BR

u(x· ∇u)= −1 2

BR

|∇u|2− 1 R

∂BR

|x· ∇u|2+R 2

∂BR

|∇u|2, (38)

BR

φu(x· ∇u)= −1 2

BR

u2(x· ∇φ)−3 2

BR

φu2+R 2

∂BR

φu2, (39)

BR

g(u)(x· ∇u)= −3

BR

G(u)+R

∂BR

G(u), (40)

BR

|u|2/5u(x· ∇u)= −3 α

BR

|u|α+R α

∂BR

|u|α, (41)

whereBRis the ball ofR3centered in the origin and with radiusR.

Multiplying the first equation of (36) byx· ∇uand the second equation byx· ∇φand integrating onBR, by (38), (39), (40) and (41) we get

−1 2

BR

|∇u|2− 1 R

∂BR

|x· ∇u|2+R 2

∂BR

|∇u|2

q 2kT(u)

BR

u2(x· ∇φ)−3q 2 kT(u)

BR

φu2+Rq 2 kT(u)

∂BR

φu2

(12)

− 3q Tαχ

uαα

Tα

R3

φu2

BR

|u|α+Rq Tαχ

uαα

Tα

R3

φu2

∂BR

|u|α

= −3

BR

G(u)+R

∂BR

G(u) (42)

and q

BR

u2(x· ∇φ)= −1 2

BR

|∇φ|2− 1 R

∂BR

|x· ∇φ|2+R 2

∂BR

|∇φ|2. (43)

Substituting (43) into (42) we obtain

−1 2

BR

|∇u|2−3q 2 kT(u)

BR

φu2+1 4kT(u)

BR

|∇φ|2

− 3q Tαχ

uαα

Tα

R3

φu2

BR

|u|α+3

BR

G(u)

= 1 R

∂BR

|x· ∇u|2R 2

∂BR

|∇u|2− 1 2RkT(u)

∂BR

|x· ∇φ|2

+R 4kT(u)

∂BR

|∇φ|2Rq 2 kT(u)

∂BR

φu2

Rq Tαχ

uαα Tα

R3

φu2

∂BR

|u|α+R

∂BR

G(u).

As in [13], the right-hand side goes to zero asR→ +∞and so we get

−1 2

R3

|∇u|2−3q 2 kT(u)

R3

φu2+1 4kT(u)

R3

|∇φ|2

− 3q Tαχ

uαα Tα

R3

φu2

R3

|u|α+3

R3

G(u)=0.

If(u, φu)H1(R3)×D1,2(R3)is a solution of (36), by standard regularity results,u, φuHloc2 (R3)and, by (i) of Lemma 2.1, we get (37).

References

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[9] G.M. Coclite, A multiplicity result for the linear Schrödinger–Maxwell equations with negative potential, Ann. Polon. Math. 79 (2002) 21–30.

[10] G.M. Coclite, A multiplicity result for the nonlinear Schrödinger–Maxwell equations, Commun. Appl. Anal. 7 (2003) 417–423.

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(13)

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[13] T. D’Aprile, D. Mugnai, Non-existence results for the coupled Klein–Gordon–Maxwell equations, Adv. Nonlinear Stud. 4 (2004) 307–322.

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