C AHIERS DE
TOPOLOGIE ET GÉOMÉTRIE DIFFÉRENTIELLE CATÉGORIQUES
S USAN B. N IEFIELD
S HU -H AO S UN
Algebraic de Morgan’s laws for non-commutative rings
Cahiers de topologie et géométrie différentielle catégoriques, tome 36, no2 (1995), p. 127-140
<http://www.numdam.org/item?id=CTGDC_1995__36_2_127_0>
© Andrée C. Ehresmann et les auteurs, 1995, tous droits réservés.
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ALGEBRAIC DE MORGAN’S LAWS FOR
NON-COMMUTATIVE RINGS
by
Susan B. NIEFIELD and Shu-Hao SUNCAHIERS DE TOPOLOGIE ET
GEOMETRIE DIFFERENTIELLE CATEGORIQUES
Yolume XXXVI-2 (1995)
R6sum6. Les
analogues alg6briques (dans
un anneaucommutatif)
de
principes logiques
connus comme la loi forte et la deuxi6me loi deMorgan
sont donn6s par les6quations
entre id6aux(I : J)
+(J:I) = R et Ann(I
nJ)
=Ann(I)
+A7-in(J).
Lespropri6t6s
des anneaux
qui
satisfont ces lois ont 6t6 6tudi6es par Niefield etRosenthal
[8], [9].
Dans le presentarticle,
cette 6tude estprolong6e
et de nouveaux r6sultats sont obtenus dans le cas non commutatif.
Introduction.
The
logical principles
and
known as second de
Morgan’s
law and strong deMorgan law, respectively,
are not in
general
valid in intuitionisticlogic.
Johnstone[4]
showed that inthe topos
Sh(X)
of set-valued sheaves on atopological
space X(and
hencein the locale
O(X)
of open subsets ofX)
second deMorgan’s
law holds ifand
only
if .4 isextremally disconnected,
and strong deMorgan’s
law holdsif and
only
if every closedsubspace
of .Y isextremally
disconnected.The
algebraic analogues
of these laws for ideals of a commutativering
Rwith
identity
wereinvestigated by
Niefield and Rosenthal in[8]
and[9]. First,
in[8], they proved
that a Noetherian domain R satisfies the strongalgebraic
de
Morgan’s
lawif and
only
if R is a Dedekind domain.Then,
in[9], they
showed that a re-duced
(i.e.
with no nontrivialnilpotents) ring
R satifies thealgebraic
de Mor-if and
only
if R is a Baerring
if andonly
if R satisfies the weak deMorgan’s
law
for all r, s E
R,
andAnn(I)
isprincipal
for all ideals I.Using
theseresults, they
characterized those R for whichSpcc(R)
isextremally disconnected,
and those for which every closedsubspace
ofSpec(R)
isextremally
discon-nected.
Weak de
Morgan’s
law has also been related to a weakened form of the definition of a Baerring,
which we will call a weak Baerring.
In[12],
Sim-mons showed that a reduced commutative
ring
R withidentity
is a weak Baerring
if andonly
if the distributive latticeL(R) generated by
radicals ofprin- cipal
ideals is a Stonian lattice.Recently,
Belluci[1] partially
extended this result to the noncommutative caseby showing
that if R is asemiprime
qcring
with unit
(i.e.
aring
for whichSpec(R)
is aspectral space),
then R is weakBaer if and
only
ifL(R)
is a Stonian lattice.The
goal
of this paper is to extend the main results of[8]
and[9],
as wellas the
Simmons/Belluce theorem,
to thegeneral
noncommutative case.1.
Ring
Theoretic Preliminaries.Thoughout
this paper R is a(not necessarily commutative) ring
withidentity,
all ideals are2-sided, (r)
is theprincipal
idealgenerated by
r ER,
and
Id(R)
denotes the set of ideals of R. If I and J areideals,
thenare the
usual left
andright
residuatedideals, respectively.
It is not difficultto show that K C
I:l
J if andonly
if I1 J CI,
and K CI:r
J if andonly
ifJK C I.
Note that if I:l J
=I:, J,
then we will write I : J for their commonvalue and say that I: J is well-defined. In the
special
case where I =0, 1:
J andI:r
J are theleft
andright
annihilator idealsAnni(J)
andAnnr(J), respectively.
As in the case of residuatedideals,
we write orAn,n ( J ),
ifthey
are
equal,
and say thatAnn(J)
is well-defined.Recall that an ideal I of R is called
semiprime
ifJ2
C Iimplies
J CI,
for all ideals J. If R iscommutative,
then these arejust
the radical ideals. It is well know that an ideal issemiprime
if andonly
if it is an intersection ofprime
ideals.Also,
it is not difficult to show that the setSI d( R)
ofsemiprime
ideals of R is closed under
arbitrary
intersections.Thus,
if I is any ideal ofR,
then the smallestsemiprime
ideal of Rcontaining
I is defi ned and is denotedby VI. Also, SId(R)
is a locale which isisomorphic
to the open set lattice ofSpec(R),
with I A J = I n J and I V J =VI+J.
Infact, SId(R)
isthe
largest
localicquotient
of thequantale Id(R) (c.f. Corollary
3.6 in[10]).
As
such,
one obtains thefollowing proposition (c.f. [10]),
which can also beverified
directly
if the reader so desires.Proposition
1.1.If I
is asemiprime
idealof R,
then(a) J1 ... In 9
Iiff J6(1)... Ju(n)
9I, for
allpermutations
aand for
allideals
J1
...In.
(b) J1 ... Jn C
Iiff J1
n ... flJn 9 I, for
all idealsJl
...Jn.
(c)
I : J is awell-defined semiprime ideal, for
all ideals J.(d)
I:VJ
= I:J, for
all ideals J.(e) VJ->
I = I:J, for
all ideals J, where - is theHeyting implication
inSId(R).
Recall that R is called
semiprime
if the zero ideal 0 issemiprime,
i.e. Rhas no nontrivial
idempotent
ideals. If R iscommutative,
this says that R hasno nontrivial
nilpotent elements,
i.e. R is reduced.Proposition
1.2.If R
issemiprime
then,for
all idealsI, (a) Ann(I)
is awell-defined semiprime
ideal.where - is the locale nega- tion in
SId(R).
The
following
iseasily
establishedusing Proposition
1.1 .Proposition
1.3.Suppose
R issemiprime. If A11n(II)
=Ann(I2)
andAnn(Ji)
=Ann(J2),
thenAnn(Ii J1 )
=Artn( 12 J2 ).
Now,
we turn to the definition of a Baerring,
of which there are many in the literature. Somepertain
to annihilators of subsets of R(c.f. [5]),
some toannihilators of
ideals,
some to annihilators of elements(c.f. [2]),
and some toannihilators of
principal
ideals(c.f. [1]).
For the purposes of this paper, we will consideronly
annihilators of ideals and use theadjective
"weak" to dis-tinguish
between the twopossible
definitions. Webegin
with aproposition,
part
(i.e. (a)-> (b))
of which is similar to oneappearing
in[5].
Proposition
1.4.The following
areequivalent for
aring
R.(a) Annl (r) is a principal
idealgenerated by
a centralÙlempotent, for
all r E R.(b) Annr (r) is a principal
idealgenerated by
a centralidempotent, for
allrER.
(c)
R issemiprime,
andAnn (r)
is aprincipal
idealgenerated by
a centralidempotent, for all r E
R.Proof. We will show that
(a)->(c).
The converse is clear and theproof
of(a)4->(b)
is similar. To show that R issemiprime,
assumeI’
= 0 and r E I.Then
Anni(r) = (e),
for some centralidempotent
e. Sincer(7-)
CI’
=0,
we know that r E
Ann, (r),
and so r = ero. But, e7- = 0, since e EAnn(r),
and so r = 0.
Therefore,
I = 0, as desired.A
ring satisfying
theequivalent
conditions ofProposition
1.4 will be called a weak Baerring.
It is not difficult to show that thisproposition
re-mains valid if the annihilators of
principal
ideals arereplace by
annihilators ofarbitrary
ideals. Aring satisfying
theequivalent
conditions of this stronger version of theproposition
will be called a Baerring.
Next,
we consider someproperties
of centralidempotents, starting
withtheir
relationship
tocomplemented
ideals. Recall that an ideal I is calledcomplemented
inId(R)
if there is an ideal J such that I + J = R and I J = JI = 0. Note that ifI,
and12
arecomplemented,
withcomplements J1
andJ2,
then so areh +I2
andI1I2,
and theircomplements
aregiven by J1 J2
andJ1
+J2, respectively. Also,
any direct summand of R iscomple-
mented since 7JCInJ.
Proposition
1.5. I iscomplemented if and only if I
is aprincipal
ideal gen-erated
by
a centralidempotent.
Proof.
Suppose
I iscomplemented
and let J be itscomplement.
Then e +f
=1,
for some e E I andf
EJ,
and soclearly
e andf
areidempotent
andeR C I. Given
r E I,
we have r = ero +fro
= er since JI = 0.Thus,
r E
eR,
and so I = eR =(e). Similarly,
I =Re,
and so eR = Re. Itremains to show that er = re, for all r E R. Since er
E Re,
we know thater = ere since e is
idempotent. Similarly,
re = ere, and so er = re, asdesired.
For the converse, let I =
(e),
where e is centralidempotent.
Then J =(1 - e)
isclearly
thecomplement
of 1.Note that I + J = R if and
only
ifI
+ J =R,
and if R issemiprime,
then 1.7 = 0 if and
only
if I n .1 = 0,by Proposition 1.1 (b).
Thus, forsemiprime ideals,
the above notion ofcomplemented
inId(R)
agrees with the lattice theoretic definition ofcomplemented
element ofSId(R).
Actu-ally,
we arereally
interested incomplemented
elements of a certain sublattice ofSId(R).
Let
L(R)
denote the distributive latticegenerated by {V(r)|rE R}.
Then, using Proposition 1.1,
it is not difficult to show that thetypical
elementin
L(R)
is of the formIi
+ ... +In,
where theIj
are finiteproducts
ofprincipal
ideals of R.Lemma 1.6.
If e is a
centralidempotent of
asemiprime ring
R, then(e)
issemiprime.
Proof.
Suppose
e is a centralidempotent
and12
C(e).
To show that I C(e),
it suffices to show that
I(1 - e)
= 0, orequivalently (I(1- e))2
= 0, sinceR is
semiprime. But, (1(1 _ e))2
=12(1 _ e)
= 0, since e is a centralidempotent.
Proposition
1.7.The following
areequivalent for
an ideal Iof a semiprime ring
R.(a)
I iscomplemented
inL(R).
(b)
I iscomplemented
inId(R).
(c)
I is aprincipal
idealgenerated by
a centralidempotent.
Proof. Since R is the top element of
L(R), (a) -> (b)
follows from the remark afterProposition
1.5.Also, (b)->(c)
holdsby Proposition
1.5. For(c)->(a),
since the
complement
of(e)
is(1 - e)
and 1- e is a centralidempotent
when-ever e
is,
it suffices to show that if e isidempotent,
then(e)
EL(R). But, (e)
EL(R)
sinceV(e)= (e), by
Lemma 1.6.2.
Algebraic
deMorgan’s
Law.In this
section,
we introduce secondalgebraic
deMorgan’s
law(DML)
and weak
algebraic
deMorgan’s
law(WDML),
and relate them to Baerrings
and weak Baer
rings.
We also showthat,
if R issemiprime,
thenSpec(R)
satisfies second de
Morgan’s
law if andonly
if R satisfies DML.Proposition
2.1.The following
areequivalent for
aring
R.Proof. To prove
(a)=>(c),
we will show that(a) implies
that R issemiprime.
The
proof
for(b)
issimilar,
and theremaining implications
are clear.Suppose (a)
holds and1’
= 0. Given r ER,
we know that(r)2
CJ2
=0,
and soR =
Anni((r)2)
=Annl(r). Thus,
r =0,
and so I =0,
as desired.Definition 2.2. A
ring
R for which theequivalent
conditions of 2.1 hold will be said tosatisfy
weakalgebraic
deMorgan’s
law(WDML).
Recall that a distributive lattice L is called Stonian if for every a E L, there is a
complemented
b E L such that x b if andonly
if x A a = 0.Theorem 2.3.
The following
areequivalent for
aring
R.(a)
Rsatisfies
WDML andAnn(r)
isprincipal for
all 7- E R.(b) Ann (r) ED Ann(Ann(r))
=R, for all r
E R.(c)
R issemiprime
andL(R)
is a Stonian lattice.(d) R is
weak Baer.Proof.
(a)=(b)
R issemiprime by Proposition 2.1,
and soA11n.(r)
is well-defined,
for all r E R. Since eachAnn(r)
isprincipal,
we can writeAnn(r)
=
(s),
for some s ER,
and it follows thatAnn(r)
+Ann (4nn (r)) = Ann(r)
+Ann(s)
=An,n( (r)(s))
=Ann((r)Ann(r))
=Ann(0)=
R. Since
Ann(r)Ann(Ann(r))
= 0 and R issemiprime,
it follows thatAnn(r)
nAnn(Ann(r))
=0,
and soAnn(r)
OAnn(Ann(r))
= R.(b) => (c)
Note that R issemiprime by Proposition 1.4,
sinceAnn (r)
is a directsummand of
R,
and hence aprincipal
idealgenerated by
a centralidempo-
tent.
Suppose
I EL(R).
Then I =Ii
+ ... +In,
where eachIj
is a finiteproduct
ofprincipal
ideals. Since R issemiprime, using Proposition 1.1,
it isnot difficult to show
that VIn d7
= 0 if andonly
if J CAnn (I),
and so itsuffices to show that
Ann(I)
iscomplemented
inL(R).
Since eachAnn (r)
is a direct summand of
R,
it is aprincipal
idealgenerated by
a central idem-potent.
By Proposition 1.3,
the same is true for any finiteproduct
ofprincipal
ideals. Since
Ann(Ii
+...+In)
=Anrr.(Il )
n ...n Ann(In), using Propo-
sition
1.2,
it follows thatAnn.(I)
iscomplemented
inL(R).
(c)=>(d)
Given r ER,
sinceB/(r)
EL(R)
andL(R)
isStonian,
there existsa
complemented
I EL(R)
such that J C I if andonly
if J nB/(r)
= 0, forall J E
L(R),
i.e. I =Ann(r).
SinceA11n(r)
iscomplemented
inL(R), by Proposition 1.7,
we know thatAnn(r) = (e),
for some centralidempotent
e.
Therefore,
R is a weak Baerring.
(d)=>(a)
Given r, s ER,
writeAnn(r) = (e)
=Ann(1 - e)
andAnn(s)=
(f)
=Ann(1 - f),
where eandf
are centralidempotents.
Since R is semi-prime, applying Proposition 1.3,
we getAn.n((r)(s)) = Ann(1 - e>1 - f>)
=Ann1 - e)
+Ann(1 - f)
=An,11(r)
+Ann(s),
as desired.Note that the
equivalence
of(c)
and(d)
in the commutative case ap-peared
in[12].
Bulluce[1] generalized
theequivalence
to the case whereR is a qc
ring,
i.e. aring
for whichSl)ec(R)
is aspectral
space. In[14],
Sun showed that the free
ring
R on two generators is not a qcring.
SinceR is
clearly
aprime ring
and hence weakBaer,
it follows that Theorem 2.3(c)b(d)
is an extension of Belluce’s result.Also, using
Theorem 2.3 and a characterizationby
Sun[13;
Theorem2.6],
one can show that the minimalprime
ideal spaceMinSpec(L(R))
iscompact, whenever R is weak Baer. Since
L(R)
is a distributivelattice,
weknow
MinSpec(L(R))
iszero-dimensional,
and soMinSpec(L(R))
is aStone space.
By
a resultgiven
in Sun’sforthcoming
paper[15],
we also havethat,
for a weak Baerring
R with no non-zeronilpotents,
the minimalprime
ideal space
MinSpec(R)
of R ishomeomorphic
toMinSpec(L(R)),
andhence is a Stone space.
Next,
we consider second deMorgan’s
law. Unlike forWDML, R
is notnecessarily semiprime,
and so one mustdistinguish
between left andright
an-nihilators. Our definition will be in terms of left annihilators. Similar ones can be made
using right
annihilators. Now, one can consider the twoalge-
braic de
Morgan’s
lawsAnn(I
+J)
=A7znl(l)
nAnn,(J)
andAnn(I
nJ)
=Anni(I)
+Anni(J).
As in the case oflocales,
the first deMorgan’s
law holds for all ideals I and J.
Definition 2.4. A
ring
R satifies secondalgebraic
deMorgan’s
law(DML)
if
for all ideals I and J.
Theorem 2.5. The
following
areequivalent for
aring
R.(a)
R issemiprime
andsatisfies
DML(b) Ann(IJ)
=Ann(I)
+Ann(J), for all
ideals I and J.(c) Ann(I) EÐ Ann(Ann(I))
=R, for
all ideals I.(d) Ann(I)
is a direct summandof R, for
all ideals I.(e)
R is a Baerring.
(fi
R is weak Baer andAnn(I)
isprincipal, for
all ideals I.(g)
Rsatisfies
WDML andAnn(I)
isprincipal, for
all ideals I.Proof.
(a)=>(b)
sinceAnn(IJ)
=Ann(I
nJ)
in asemiprime ring.
(b)=>(c)
Note that R issemiprime by Proposition 2.1,
since(b) implies
thatWDML holds.
Thus, Ann(I)
flAnn(An.n(I))
=Ann(I)Ann(Ann(I))n(I))=
0.
Also, Ann(I)
+Ann(Ann(I))
=Ann(I Ann(I))
=Ann(0)
=R,
asdesired.
(c)=>(d)
is clear.(d)=> (e) by Proposition
1.5.(e) => (f)
is clear.(f)=>(g) by
Theorem 2.3.(g)=>(a)
Since R issemiprime (by Proposition 2.1),
it suffices to show that for every idealI, Ann(I)
=Ann(r),
for some r E R. SinceAn7i(l)
isprinci- pal,
we can writeAnn(I) = (s)
andAnn,(s) = (r),
for some r, s E R. Thenusing
the fact thatAnn3=Ann,
we getAnnr>
=..4n.n2 s>
=Ann3(I) = Ann(I),
as desired.Recall that open sets of
Spec(R)
are of the formwhere I E
Id(R).
Thecomplement
ofD(I)
is denotedby V( 1).
Proposition
2.6.Proof. If P is
prime
andI g P,
thenf : I
CP,
since(B/0:I)I
CVO-
CP. Thus
D(I
CV(V0: I)
and soD(I)
CV( V0 : I).
We will show that if P EV( 0 : 1),
then every openneighbourhood
of P meetsD(I).
LetD(J)
be such a set, i.e.J g
P. SinceJ g
P andJ0 : 1
CP,
it follows thatJ 9 V0:I,
and henceIJ g ui.
ThereforeD(I)
nD(J) = 0,
as desired.Corollary
2.7.If R is semiprime,
thenD(I)
=V(An11(I)).
Recall that a
space X
is calledextremally
disconnected if the closure of every open subset of X is open.Theorem 2.8.
If R is semiprime,
thenSpec(R)
isextremally
disconnectedif
and
only if R satisfies
DML.Proof. Since every open set of
Spec(R)
is of the formD(I),
for some idealI, by Corollary 2.7, Spec(R)
isextremally
disconnected iffV(Ann(I))
is open for all I. But,V(J)
is open for some ideal J if andonly
if J is a direct sum-mand of
R,
and so the desired result follows from(a)=>(d)
of Theorem 2.5.Since
Spec(R) = Spec(R/V0),
we get thefollowing corollary.
Corollary
2.9.The following
areequivalent for
anyring
R.(a) Spec(R)
isextremally
disconnected.(b) R/V0 satisfies
DML.(c) R/V0 is
a Baerring.
Note that Niefield and Rosenthal
[9] proved
versions of Theorem2.5, Corollary 2.7,
Theorem2.8,
andCorollary
2.9 for commutativerings.
Onthe other
hand,
the commutative version of Theorem 2.3 did not appear in[9].
3.
Strong
deMorgan’s
Law.In this section we introduce
algebraic
strong deMorgan’s law,
and relate it to strong deMorgan’s
law for the localeO(Spec(R)).
As in the case ofDML,
we will consideronly
left annihilators. Similar results can be obtained forright
annihilators.Definition 3.1. A
ring R
satisfiesalgebraic
strong deMorgan’s
law(SDML)
if
for all ideals I and J.
Proposition
3.2.The following
areequivalent for
aring
R.(a)
Rsatisfies
SDML.(b) (I
+J):r K
=(I:r K)
+(J: r K), for
all idealsI,
J, 1B.for
all idealsProof.
(a) => (b) First,
For the reversecontainment,
sinceby (a),
it suffices to show that andBut,
and so
Similarly,
as desired.
For the reverse containment, since
to show that
[
andBut,
and so
, Similarly,
Clearly,
Note that
(a)=>(c)
says that SDMLimplies
DML.Also,
theproof
wehave
given
is valid in anarbitrary quantale.
Theequivalence
of(a) through (c)
for commutativequantales
was firstproved by
Ward and Dilworth in[16].
Theorem 3.3.
The following
areequivalent for
aring
R.(a) Every
closedsubspace of Spec(R)
isextremally
disconnected.(b) O(Spec(R)) satisfies
strong deMorgan’s
law.(c) (VI: J)
+(VJ:I)
=R, for
all ideals I and J.(d) (VI
+VJ):
K =(VI: K)
+(VJ: K), for
all idealsI,
J, K.(e) VI: (J n Ii)
=(VI: J)
+(VI: K), for
all idealsI, J,
K.(f) R/VI satisfies
thealgebraic
second deMorgan’s
law,for
all ideals I.Proof.
(a)=>(b)
follows from a theorem in[4].
(b)=>(c)
follows fromProposition 1.1,
since andonly
if(c)=>(d)=>(e)
follows fromPorposition I.1(d)
and the remarkpreceding
thistheorem.
(e) => (f)
follows from that fact that every ideal ofR/ f
is of the formJ/VI,
where J is an ideal of R
containing VI,
and the left annihilator ofJ/VI
inR/VI is (VI:r J)VI.
(f)=>(a)
follows from the fact that every closedsubspace
ofSpec(R)
is home-omorphic
toSpec(R/I),
for somesemiprime
ideal I of R.Note that Niefield and Rosenthal
[8] proved
a commutative version of Theorem 3.3.Recall that the locale
Spec(R)
is called Noetherian if thesemiprime
ide-als of R
satisfy
theascending
chain condition. If R is a Noetherianring,
thenSpec(R)
isNoetherian,
but the converse does not hold(c.f [6]).
On the otherhand,
as in the commutative case, ifSpec(R)
isNoetherian,
then the num- ber of minimalprimes
is finite(cf. [3,
Theorem2.4]). Moreover,
ifSpec(R)
is
Noetherian,
so isSpec(R/I),
for everysemiprime
idealI,
and it followsthat every
semiprime
ideal is a finite intersection ofprimes.
Motivatedby
the characterization of Noetherian domains in
[7],
Niefield and Rosenthal[8]
showed that if R is commutative and
Spec(R)
isNoetherian,
then the condi- tions of Theorem 3.3 areequivalent
to thedistributivity
ofSId(R),
as wellas the property P C
Q, Q
CP,
orQ
+ P =R,
for allprime
ideals P andQ.
Although
this result does not seem togeneralize
to the noncommutative case(if
the two additional conditions are takenseparately),
we have thefollowing
theorem.
Theorem 3.4.
The following
areequivalent for
aring
R such thatSpec(R)
is Noetherian.
(a) Every
closedsubspace of Spec(R)
isextremally
disconnected.(b) O(Spec(R)) satisfies
strong deMorgan’s
law.(c) ( J7 : J)
+( J7 : I)
=R, for
all ideals I and J.(d) (VI
+VJ) :
Ii =(VI:K)
+(VJ:K), for
all idealsI, J,
K.(e) VI: (J n K) = (VI:J) + (VI:K), for all ideals I, J, K.
(f) R/VI satisfies
thealgebraic
second deMorgan’s
law,for
all ideals I.(g)
Theconjunction of:
(i)
I n(J
+K) = (I
nJ)
+(I
flK), for
allsemiprime
idealsI, J,
K(ii)
P CQ, Q
CP, or Q
+ P =R, for
allprime
ideals P andQ.
Proof. The
equivalence
of(a) through (0
isclearly
Theorem 3.3. We will show that(b)
isequivalent
to(g).
(b)=> (g)
SinceO(Spec(R))
satisfies strong deMorgan’s law,
we knowor
equivalently (I: J)
+(J: I)
=R,
for allsemiprime
ideals I and J. Thus,if
I, J,
and li aresemiprime ideals,
then I n(J
+A) -(J:l A’)(7
n(J
+K))
+(K :r J)( In (J+K)),
and so it suffices to show that(J: K)(In (J
+K)) C I n J and (K:r J)(I n (J + K))
C I n Il. But,(J:r K)(J
+AT) 9 J+(J:r K) K
CJ+J
CJ and so (J:r K)(In(J+K))
C InJ.Similarly, (K:r J)(I
n(J + K)) C
I n K.Next,
suppose P andQ are prime
ideals ofR such that
P g Q
andQ g
P. Then(Q:i P)
CQ,
since(Q:r P)P
CQ.
Similarly, (P:1 Q)
C P.Thus,
R =(P:1 Q)
+(Q:1 P)
C P +Q,
as desired.(g)=>(b)
GivenI,
J ESId(R),
write I =P1
n ... nPn
and J =QI
n ... nQm,
where allPi
andQj
areprimes.
ThenThus,
it suffices to show that(P: Q)
+(Q: P)
= R, for allprimes
P andQ
of R. If P C
Q or Q
CP, then we have Q : P = R or P: Q = R, and the
desired conclusion follows.If P g Q
andQ C P,
thenas desired.
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The second author
gratefully acknowledges
the support of the Australian Re- search Council.Susan B. Niefield
Department
of Mathematics UnionCollege
Schenectady,
N.Y. 12308U.S.A.
Shu-Hao Sun
School of Mathematics F07
University
ofSydney
NSW 2006Australia