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Prouver que les expressions 3x22–27 ; 3x –1x5 et 3x212x –15 sont trois formes littérales d'une même fonction f.
Choisir l'expression la mieux adaptée pour calculer les antécédents par f de 0 ; –15 et de –27 .
Résoudre l'équation 1–5x2=1–5x3–4x
Résoudre l'équation –5 2x1=1
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