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www.elsevier.com/locate/anihpc

Essential Dynamics for Lorenz maps on the real line and the Lexicographical World

Rafael Labarca

a,

, Carlos Gustavo Moreira

b

aDepartamento de Matematica y CC, Universidad de Santiago de Chile, Casilla 307 Correo 2, Santiago, Chile bIMPA, Estrada Dona Castorina 110, CEP 22460-320, Jardim Botanico, Rio de Janeiro, Brasil

Received 11 March 2005; received in revised form 11 July 2005; accepted 19 September 2005 Available online 19 January 2006

Dedicated to the memory of Professor Jorge Billeke G.

Abstract

In this paper we describe some topological and geometric properties of the set of sequencesLW= {(a, b)∈Σ0×Σ1; a σn(a)b, aσn(b)b,n∈N}, which essentially represents all the allowed dynamics for piecewise continuous increasing maps with one discontinuity. In particular, we describe the first main bifurcations inLWwhich generate non-trivial dynamics, and we study (fractal) geometric properties ofLWand of the phase spacesΣa,bassociated to it.

©2005 Elsevier SAS. All rights reserved.

Résumé

Dans ce travail nous décrivons quelques proprietés topologiques et géometriques de l’ensemble de suites LW= {(a, b)Σ0×Σ1; n(a)b, aσn(b)b, ∀n∈N}, que répresentent essentiellement toutes les dynamiques permises pour des fonctions continues et croissantes par morceaux avec un point de discontinuité. En particulier, on décrit les premières bifurcations dansLWqui produisent des dynamiques non-triviales et nous étudions des proprietés géometriques (fractales) deLWet des espaces de phaseΣa,bassociés.

©2005 Elsevier SAS. All rights reserved.

Keywords:Essential Dynamics; Lexicographical World; Lorenz maps; Hausdorff dimension; Entropy

1. Introduction

In the remarkable work [13], a meteorologist, E.N. Lorenz, showed numerical evidence of the existence of a strange attractor for a quadratic system of ordinary differential equations in three variables. Some time later J. Guckenheimer, [7], produced a work where he introduced symbolic dynamics in order to understand the topological equivalence classes for nearly similar attractors. At that time R.F. Williams, [26], introduced a geometrical model in order to understand the dynamics of these Lorenz attractors. In Fig. 1 we give a sketch of the geometric attractor. Moreover,

Partially supported by Fondecyt-CHILE grant # 1000098 and PRONEX-BRAZIL on Dynamical Systems, Brazil.

* Corresponding author.

E-mail address:rlabarca@lauca.usach.cl (R. Labarca).

0294-1449/$ – see front matter ©2005 Elsevier SAS. All rights reserved.

doi:10.1016/j.anihpc.2005.09.001

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Fig. 1. Geometric Lorenz attractor. Fig. 2. One-dimensional return map.

in Fig. 2 we represent the one-dimensional models associated to the attractor. The right-hand side of this picture corresponds to the numerical experiments of Lorenz, who used a cross-section different from that of Guckenheimer and Williams, who obtained a map as in the left-hand side of the figure. The combinatorial dynamics of both one- dimensional maps sketched in this figure are equivalent. In this work we will concentrate our attention on piecewise increasing one-dimensional maps.

Using this geometrical model the dynamical behavior of the three-dimensional vector field can be reduced to the dynamical behavior of a one-dimensional map with one discontinuity and Guckenheimer and Williams, [8], used this fact to show uncountable many classes of non-equivalent geometric Lorenz attractors. The evidence of the non- equivalence were the kneading sequences associated to these one-dimensional maps. The class of one-dimensional maps defined in this way is included in the class of one-dimensional maps which we work here (see the definition of the setDM0given in Section 2.1).

Associated to anyfDM0we have two kneading sequences(af, bf)=I (f )(see Section 2.3 for the definition of these sequences) that satisfy af =inf{σk(af), k∈N}, bf =sup{σk(bf), k∈N}and{af, bf} ⊂Σaf,bf (here Σa,bdenotes the set

i=0σi([a, b]); see Section 2.3 for details). These properties inspired (see [22]) the following definitions. A sequence of two symbolsa=(0, . . .)Σ2(resp.b=(1, . . .)Σ2)is calledminimal(resp.maximal) if a=inf{σk(a), k∈N}(resp.b=sup{σk(b), k∈N}. Hereσ:Σ2Σ2denotes the usual shift map. We will denote by Min2(resp. Max2) the set of minimal (resp. maximal) sequences inΣ2. These two properties allow us to define theLexicographical WorldasLW= {(a, b)∈Min2×Max2, {a, b} ⊂Σa,b}. The itinerary

I:DM0LW, f(af, bf)

defines a continuous and surjective map (see Section 2.5). We will say that the mapfDM0hasessentiallythe same dynamics asgDM0ifI (f )=I (g). It is clear that two topologically equivalent maps are essentially equivalent.

Notice that one of the main topological obstructions for two maps inDM0with essentially the same dynamics being conjugated is the presence of wandering intervals for some of these maps. We prove in Proposition 1 that genericC2 maps inDM0do not have non-trivial wandering intervals.

Therefore, the lexicographical world provide auniversal modelfor (essentially) equivalent dynamics in this con- text. This means the following: given(a, b)LW, there isfDM0such thatΣa,b=Σaf,bf and a surjective map If:ΓfΣa,b such that Iff =σIf and reciprocally (see Section 2.3 for the definition of the set Γf, the definition of the mapIf and the proof of the realization lemma). Clearly, if we are able to describe the different dy- namics present in this universal model then we are able to prove some dynamical properties of the elements inDM0. Also our set,DM0, contains the topologically expanding Lorenz maps as defined in [9]. The kneading sequences, (a, b)LW associated to expanding maps satisfies the conditionn(a) < b anda < σn(b)b,n0. Let denote byTELWthis set. One of the problems posed in [9] is to describe the setTE. In Section 4 we characterize the local fractal properties ofTE(andLW).

In these directions are the main results of the present paper: we describe some metric and geometrical properties of the lexicographical world which “essentially” represents all the allowed dynamics for piecewise continuous increasing maps and we use these properties to establish some results for the elements inDM0. For instance, among other results, we prove

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Theorem 1.The mapsϕ, ψ, χ: Min2→Max2given by

ϕ(a)=inf{bΣ1; Σa,b = ∅}, ψ (a)=inf{bΣ1; Σa,bis infinite} and χ (a)=inf{bΣ1; Σa,bis uncountable}

satisfy the following recursive formulas(see Section3for the definition of the mapsTa,bandTa b ) (i) (1) fora001we have0ϕ(a)=T0,01ϕT0,01 (a),

(2) for01< a <01we haveϕ(a)=T10,1ϕT10,1 (1a), (3) for001a01we haveϕ(a)=10.

(ii) (1) fora <001,χ (a)=σT0,01χT0,01 (a),

(2) for001a00110,χ (a)=1T01,10χT01,10 (σ (a)), (3) for00110a01,χ (a)=110,

(4) for01a01,χ (a)=T10,1χT10,1 (1a).

(iii) (1) fora001,ψ (a)=σT0,01ψT0,01 (a),

(2) for001< a00110,ψ (a)=1T01,10ϕT01,10 (σ (a)), (3) for00110a01,ψ (a)=110and

(4) for01< a01we haveψ (a)=T10,1ψT10,1 (1a).

We notice that{(a, b)Σ0×Σ1; Σa,b = ∅} = {(a, b)Σ0×Σ1; bϕ(a)}.

Another characterization of the mapχis given by the following

Theorem 2.The set{(a, b)Σ0×Σ1;the topological entropy of the map(σ|Σa,b): Σa,bΣa,bis zero}is equal to the set{(a, b)Σ0×Σ1; bχ (a)}.

We observe that a consequence of Theorem 2 is the following: The setEZ0= {maps inDM0with zero topological entropy}is equal to the set{fDM0; bf χ (af)}(we observe that related problems of characterizing the boundary of the set of maps of zero entropy were focused by several authors in this and other contexts; see for instance [2,23, 19,15,24,5,20,21]).

Also we prove the following result about (fractal) geometric properties ofLW:

Theorem 3.LetD:Σ0×Σ1→Rbe the map defined asD(a, b)=HD(Σa,b), where HD(Σa,b)denotes the Haus- dorff dimension of the set Σa,b (here we consider the set Σ0×Σ1 equipped with the usual diadic metric; see Section2.2). ThenDis a continuous map.

For(a, b)Σ0×Σ1defineΩ(a, b)= {(α, β)LW; aαβb}andΩ(a, b) = {(α, β)Ω(a, b); (α, β)TE}then

HDΩ(a, b)

=HD

Ω(a, b)

=2D(a, b)= 2

log(2)htopa,b)

(herehtopa,b)means the topological entropy of the restriction of the shift map to the setΣa,b).

Clearly, the described structure of the setLW reflects in the bifurcation theory associated to any parameterized family of maps inDM0(also an extremely interesting problem focused for several authors in this an other contexts, see for instance [14,2,1,4]). In [10,11] and [12] we applied these results for contracting, expanding and linear families of Lorenz maps.

This paper is organized as follows: In Section 2 we introduce the lexicographical world, we describe the setDM0

(that we recognize as the set ofLorenz Maps) and we prove the realization lemma. In Section 3 we prove Theorem 1 and part of Theorem 2. In Section 4 we prove Theorem 3 and we complete the proof of Theorem 2.

There are several works related to the symbolic dynamics associated to one dimensional Lorenz maps. For instance, in the papers by Hubbard and Sparrow [9] and Glendinnig and Sparrow [6] a study of the symbolic dy- namics associated to topologically expansive one-dimensional Lorenz maps is performed. We note that the equality D(a, b)=log(2)1 htopa,b)follows from results by H. Furstenberg [3] and also by Urba´nski [25].

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2. Lorenz maps and symbolic dynamics

2.1. The set DM0

In the sequelDM0will denote the set of mapsf:(R\ {0})→Rsuch that:

(1) The restriction mapsf|(−∞,0):(−∞,0)→Randf|(0,):(0,)→Rare continuous and non-decreasing maps.

(2) f (0+)=limx0f (x)(−∞,0]andf (0)=limx0f (x)∈ [0,∞[. 2.2. The lexicographical order

LetΣ2denote the set of sequencesθ:N→ {0,1}endowed with the topology given by the metric d(α, β)= 1

2n, where

n=min{k∈N; αk =βk}.

Letσ:Σ2Σ2 be the shift mapσ (θ0, θ1, θ2, . . .)=1, θ2, . . .). LetΣ0 andΣ1denote the sets{θΣ2; θ0=0}

and{θΣ2; θ0=1}respectively. It is clear thatΣ2=Σ0Σ1.

InΣ2we consider thelexicographical order:θ < αfor anyθΣ0andαΣ1orθ < αif there isn∈Nsuch that θi=αi fori=0,1,2, . . . , n−1 andθn=0 andαn=1.

ForabinΣ2let[a, b]denote the interval{θΣ2|aθb}.Σa,bwill denote the set

n=0σn([a, b]).

Leta=a0, a1, . . . , an be a finite word. We will denote bya the infinite sequence(a0, a1, . . . , an;a0, a1, . . . , an; a0, a1, . . . , an;. . .)Σ2.

2.3. The setΣaf,bf

ForfDM0letΓf=(R\

j=0fj(0))denote the set of “continuity” of the mapf. ForxΓf we defineIf(x)Σ2by

If(x)(i)=0 iffi(x) <0 and If(x)(i)=1 iffi(x) >0.

Forx=0 we define:

If(0+)= lim

x0, xΓf

If(x)

and

If(0)= lim

x0, xΓfIf(x).

In the same way to anyx

j=0fj(0)such thatfi(x) =0, 0i < n;fn(x)=0 we associate the sequences:

If(x+)=

If(x)(0), . . . , If(x)(n−1), If(0+) and

If(x)=

If(x)(0), . . . , If(x)(n−1), If(0) . ForxΓf we defineIf(x+)=If(x)=If(x).

LetIf = {If(x+); x∈ [f (0+), f (0)[} ∪ {If(x); x∈ ]f (0+), f (0)]}.

Let us denoteaf =If((f (0+))+)andbf =If((f (0))). The following lemma is a classical fact which asso- ciates a symbolic dynamical system to a Lorenz map on the interval, via kneading sequences. See, for instance, [22].

Lemma 1.If =

n=0σn([af, bf])=Σaf,bf.

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Proof. We haveIf(f (x))=σ (If(x)), by definition ofIf(x), so σ (If)If. This also implies that, sinceIf ⊂ [af, bf],Ifσn([af, bf])for every natural numbern. Let nowθ

n=0σn([af, bf]), that isaf σn(θ )bf

for n=0,1,2, . . .. Clearly we must haveaf σn(θ )0bf or 1af σn(θ )bf for every n=0,1,2, . . .. Let I0= [f (0+),0[andI1= ]0, f (0)]. The opposite inclusion follows from the following facts:

(i) If(0+)=1af,If(0)=0bf;

(ii) Iθ0f1(Iθ1)f2(Iθ2)∩ · · · ∩fn(Iθn) = ∅forn=0,1, . . .and (iii) the continuity of the mapf onI0I1. 2

We observe that associated to anyfDM0we can define a continuous map (see [16] for details) h:

f (0+), f (0)

ΓfΣaf,bfΣ2,

such thathf =σh. The maphis given byh(x)=If(x)and could collapse some intervals into points. This map cannot be extended, continuously, to the set

i=0fi(0).

There are two kinds of intervals that are collapsed by the maph: The wandering intervals and the intervals that are contained in the stable manifolds of the periodic sinks. An intervalI⊂ [f (0+), f (0)]is called awandering interval, for the mapf, if for anyxI we have thatx is a wandering point. We will call a pointx anon-wanderingpoint if for any neighborhoodUxofx and any positive integerN we can findnN such thatfn(Ux)Ux = ∅. The set of non-wandering points of the mapf is denoted byΩf. A pointx /Ωf is called awandering point. Given any intervalI,the orbitof this interval is the sequence of iterations(fn(I ), n∈N).

We say that a wandering interval isnon-trivialif it is not contained in a basin of attraction of a periodic orbit.

Concerning the existence of wandering intervals we have the following:

Proposition 1.Let{ϕλ, λ∈R} ⊂DM0be a one parameter family ofC2 piecewise increasing maps(for instance, elements of DM0)such that for eachλthere are sequencesλnλandμnλwithϕλn(x) > ϕλ(x)andϕμn(x) <

ϕλ(x),x then there is a residual set of parametersλfor whichϕλhas no non-trivial wandering intervals.

Proof. The orbit of any non-trivial wandering interval must accumulate in the discontinuity (it is a consequence of the Schwarz lemma or of Mañé’s Theorem on hyperbolicity for one-dimensional maps; see [16]). To get the result it is enough to prove that for anya, b∈Q, witha < bthe interval]a, b[is not contained in a wandering interval for an open and dense set of parameterλ. If, for some parameterλthe interval]a, b[is contained in a wandering interval then its orbit accumulates the discontinuity. Assume that 0 is accumulated by the left side by the orbit of the interval ]a, b[. Letλnλbe the sequence, associated toλ, given by the hypothesis. Sinceϕλn> ϕλwe can find an iterate of ]a, b[, sayϕλkn(]a, b[)such thatϕkλn(]a, b[)⊂ ]−∞,0[andϕλkn

n(]a, b[)⊂]0,∞[(since the length ofϕn(]a, b[)must converge to 0 and all the mapsϕλare increasing). Joiningλtoλnby a continuous path we find a parameter value,ρn betweenλandλnsuch thatϕρknn(]a, b[)contains 0 and then]a, b[cannot be contained in a wandering interval forϕρn. The same is true for parameters nearρnand alsoρnλasn→ ∞. This completes the proof of the proposition. 2 Remark 1.

(a) The previous argument also shows that the set

{fDM0; f has no non-trivial wandering intervals} is residual inDM0.

(b) The result is true also with an arbitrary number of parameters.

Definition 1.Letf, gDM0. We will say thatf hasessentiallythe same dynamics asgifIf=Ig.

We observe that in this situation, up to the existence of some intervals where the itineraries of the points are the same, the dynamics of the mapsf andgare topologically equivalent (see [16]).

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2.4. The Lexicographical World

Let Min2= {aΣ0; σk(a)a,k∈N}and Max2= {bΣb; σk(b)b,k∈N}. Elements in Min2 (resp.

Max2) will be calledminimal(resp.maximal) elements inΣ2. Remark 2.

(1) Assume that aΣ0 is a periodic sequence in Min2. Leta0a1· · ·ak be its period. Then, necessarily, we have a0=0 andak=1.

(2) Assume thatbΣ1is a periodic sequence in Min2. Letb0b1· · ·bkbe its period then, necessarily, we haveb0=1 andbk=0.

(3) Clearly, Min2and Max2are closed sets inΣ2.

Definition 2.The setLW= {(a, b)∈Min2×Max2; {a, b} ⊂Σa,b}will be called thelexicographical world.

Fora∈Min2 itsLW-fiber is the setLW0(a)= {b∈Max2; (a, b)LW}. Forb∈Max2 itsLW-fiber is the set LW1(b)= {a∈Min2; (a, b)LW}.

Remark 3.It is clear that if(a, b)LWthenΣa,b = ∅,since it contains{a, b}. 2.5. The realization lemma

Let us now consider(a, b)LW.

Lemma 2.There isfDM0such thatIf =Σa,b. Proof. Let us consider the mapg:(R\ {0})→Rgiven by

g(x)=

2x−1, x >0, 2x+1, x <0.

In this caseIg=Σ2. Letxa<0 andxb>0 be the points such thatIg(xa+)=a,Ig(xb)=b. Letxa< xb<0<

xa< xb, be the points that satisfyg(xb)=xbandg(xa)=xa. Letf:(R\ {0})→Rbe the map defined by:

f (x)=

⎧⎪

⎪⎩

g(x), xxb, xb, xbx <0, xa, 0< xxa, g(x), xax.

The mapf satisfyIf =Σa,b. In fact:af =a,bf =band the itinerary,θ, send points in the set{x∈ [xa, xb] ∪ [xa, xb](=Jf);fn(x)Jfn∈N}into points inIf which is equal toΣa,b. 2

Therefore, we have a surjective mapI:DM0LW,I (f )=(af, bf). Also, usingC0proximity of maps inDM0

(with respect tof|]−∞,0]andf|[0,∞[) on compact sets, this map is continuous.

3. Structure of the Lexicographical World

3.1. The mapsϕ, ψ, χ

It is clear thatΣa,1 = ∅for anyaΣ0. Hence we can define mapsϕ, ψ, χ:Σ0Σ1by:

ϕ(a)=inf{bΣ1|Σa,b = ∅},

ψ (a)=inf{bΣ1; Σa,bcontains infinitely many elements}

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and

χ (a)=inf{bΣ1; Σa,bis uncountable}.

Clearly,a1a2implyϕ(a1)ϕ(a2),ψ (a1)ψ (a2)andχ (a1)χ (a2)and for allcΣ1such that c < ϕ(a) we haveΣa,c= ∅. Moreover, for anyaΣ0we have that 1aϕ(a)(in fact, anyb <1a satisfyb /Σa,dfor any dΣ1).

Examples.We have:ϕ(0)=ψ (0)=χ (0)=10;ϕ(01)=ψ (01)=1.

IfΣa,bis uncountable then we can define

˜

a=inf{θΣa,b, θis a condensation point ofΣa,b} and

˜

b=sup{θΣa,b, θ is a condensation point ofΣa,b}.

Let us recall that acondensationpoint of a setXΣ2 is a point with the property that any neighborhood of it contains an uncountable subset ofX.

It is clear that the seta,b\Σa,˜b˜)is countable, since it has no condensation points, and we have

˜

n(a) <˜ b˜ and a < σ˜ n(b)˜ b,˜ ∀n∈N,

so, by [9],Σa,˜˜bis a perfect set and the restriction of the shift map,σ|Σa,˜˜b, is topologically expansive.

We observe that for anyaΣ0we haveϕ(a)ψ (a)χ (a).

3.2. The recurrence formula of the mapsϕ,ψandχ

Let m0 < m1 be two finite words of 0’s and 1’s. Let Tm0,m1:Σ2Σ2 be the map Tm0,m10, θ1, . . .)= (mθ0, mθ1, . . .). About this map we make the following considerations:

(1) Θ1Θ2implyTm0,m11)Tm0,m12).

(2) IfΣm0,m1 = {Θ: N→ {m0, m1}}thenTm0,m12)=Σm0,m1 and it is an homeomorphism onto its image. The inverse map is constructed in the following way: let(m0)=0,(m1)=1 forαΣm0,m1 we haveTm1

0,m1(α)= ((α0), (α1), . . .).

(3) An extension of the mapTm1

0,m1 is given by the mapTm

0,m1 defined, forαm1, asTm

0,m1(α)=inf{βΣ2; Tm0,m1(β)α}.

(4) We define the mapσm0,m1:Σm0,m1Σm0,m1, by σm0,m1

Tm0,m1(a)

=Tm0,m1

σ (a)

,aΣ2.

Proposition 2.The mapϕsatisfies:

(1) fora001we have0ϕ(a)=T0,01ϕT0,01 (a), (2) for01< a <01we haveϕ(a)=T10,1ϕT10,1 (1a), (3) for001a01we haveϕ(a)=10.

Proof. Let us prove (2). By the definition ofϕ,ΣT

10,1(1a),ϕ(T10,1 (1a))is a non-empty set. Hence, T10,1T

10,1(1a),ϕ(T10,1 (1a)))

is an invariant, non-empty set forσ10,1:Σ10,1Σ10,1. So, sinceT10,1is a conjugacy betweenσandσ10,1, T10,1T

10,1(1a),ϕ(T10,1 (1a)))σ

T10,1T

10,1(1a),ϕ(T10,1 (1a)))

is a non-empty, invariant set for σ. Therefore ϕ(a)T10,1ϕT10,1 (1a). If ϕ(a) < T10,1ϕT10,1 (1a) then [1a, ϕ(a)] ∩Σa,ϕ(a) = ∅andT10,1 ([1a, ϕ(a)] ∩Σa,ϕ(a))⊂ [T10,1 (1a), ϕ(T10,1 (1a)[)is a non-empty,σ-invariant set (sincea >01 impliesΣa,1Σ1Σ01,1, and so, in particular,ϕ(a)Σ10,1). This is a contradiction.

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The proof of (1) follows in a similar way since∅ =Σa,01Σ0Σ0,01.

The proof of (3) follows from Σ01,10 = ∅ andϕ(001)=10 which gives 10=ϕ(001)ϕ(a)ϕ(01)10,

a∈ [001,01]. 2 Note 1.

(i) We observe thatϕis not a continuous map since lima01+ϕ(a)=110 =10=ϕ(01). In fact, foran=(01)n011 we have thatϕ(an)=1(10)n+1. Thereforean→01 andϕ(an)→110.

(ii) As a consequence of Proposition 2 we note that the graph of the mapϕ is a kind of “devil stair” (although not continuous) inΣ0×Σ1: it is locally constant in an open and dense set. In fact, let Adenote the mapT0,01,B denote the mapσT10,1andI be the interval[0010,01]. LetA0=I,A1=A0A(A0)B(A0),A2=A1A(A1)B(A1)and, inductively,An+1=AnA(An)B(An). It is not hard to see, from the recursive formulas at Proposition 2 that the setA=

n=0Anis a dense set inΣ0and|J)is constant for any intervalJA. Proposition 3.The mapsχandψsatisfy:

(a) fora <001,χ (a)=σT0,01χT0,01 (a),

(b) for001a00110, χ (a)=1T01,10χT01,10 (σ (a)), (c) for00110a01, χ (a)=110,

(d) for01a01, χ (a)=T10,1χT10,1 (1a), (a) fora001, ψ (a)=σT0,01ψT0,01 (a),

(b) for001< a00110, ψ (a)=1T01,10ϕT01,10 (σ (a)), (c) for00110a01, ψ (a)=110and

(d) for01< a01we haveψ (a)=T10,1ψT10,1 (1a).

Proof. Let us first remark that ifΣa,b = ∅anda00110 begins with 00 then2(a)110. Ifabegins with 01 then there is no pair of consecutive 0’s in any element ofΣa,b, so for the interestingawe havea01, and ifbbegins with 11 then (for the interestingb) we haveb110. Ifb begins with 10 then there is no pair of consecutive 1’s in any element ofΣa,b, sob10 in this case and, henceΣa,bΣ01,10= {01,10}is finite. This impliesχ (a)110 andψ (a)110 fora00110.

To show thatχ (a)110 fora01 it is enough to notice that the setΣ01,1(10)n is uncountable for eachn∈N. The proof in the casesa001 anda >01 is analogous to the previous proof for the mapϕ.

In the case 001a00110, 11001b110, let Ca,b= {xΣa,b, 01x10}thenCa,bΣ01,10, and the first return map ofσ to the setCa,b isσ2, that isT01,10σ2T01,10 restricted toCa,b. Moreover,Σa,b= [a, b] ∩

n∈Nσn(Ca,b)soΣa,bis uncountable if and only ifCa,bis uncountable, andΣa,bis infinite if and only ifCa,bis non-empty. This gives the result. 2

Now, Theorem 1 follows from Propositions 2 and 3.

Note 2.

(i) The mapψ, χ are discontinuous. In fact, foran=001(01)n we haveχ (an)=(10)n101001(01)n and then we obtain limn→∞χ (an)=10 =110010=χ (00101). Also, forαn=00(10)n11 we haveψ (αn)=1100(10)nand then we get limn→∞ψ (αn)=110010 =10=ψ (0010).

(ii) As a consequence of Proposition 3 ((a)–(c) and (d)) we observe that the graph of the mapχ is a devil stair in Σ0×Σ1. In fact, letAdenote the mapT0,01, B denote the mapσT10,1, Cdenote the map 0T01,10andJbe the interval[001101,01]. LetA¯0=J,A¯1= ¯A0A(A¯0)B(A¯0)C(A¯0),A¯2=A1A(A¯1)B(A¯1)C(A¯1) and, inductively,A¯n+1=AnA(A¯n)B(A¯n)C(A¯n). Now it is not hard to see thatA¯=

n=0Anis a dense set inΣ0and|L)is constant for any intervalL⊂ ¯A.

Similarly, as a consequence of Proposition 3 ((a)–(c) and (d)) we verify that|L)is constant for any interval L⊂ ¯A.

(iii) We observe that the mapψis lower semicontinuous while the mapχis upper semicontinuous.

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To complete the proof of Theorem 2 let us prove the following

Proposition 4. Let χ (a)=inf{bΣ1; Σa,b is uncountable}. Then, for any b > χ (a) the topological entropy htop|Σ a,b)of the restriction of the shift map,σ, toΣa,bis positive.

Proof. Letb˜∈Σ1be such thatχ (a) <b < b. By the definition of˜ χ (a), Σa,b˜is uncountable. Letn∈Nbe such that d(b, b)˜ =1/2n, and letA= {α∈ {0,1}n+1;αappears as a subsequence of(n+1)consecutive terms of some element θΣa,b˜}.

LetMAbe the matrix(aαβ)α,βAgiven byaαβ=1 if every subsequence of(n+1)consecutive terms ofαβbelongs toAandaαβ=0 otherwise.

LetΣA= {α1α2α3· · · |αiA, aαiαi+1 =1∀i1}be the subshift of finite type induced byMA. SinceΣa,b˜ is invariant byσ,ΣAis also invariant byσ, and sinceΣa,b˜is uncountable, andΣa,b˜ΣAthenΣAis also uncountable and we havehtopA) >0, becauseΣAis a shift of finite type.

Notice now thatΣAΣa,b. In fact, for anyθΣA there isθ˜∈Σa,b˜ whose first(n+1)terms are the same as those ofθ, sod(θ,θ ) >˜ 1

2n+1. Sinced(b,b)˜ =21n,b >b˜andb˜θ, we have˜ b > θ. So, we conclude thathtopa,b) htopA) >0. 2

4. Hausdorff dimensions and the Lexicographical World

We will discuss in this section some results on geometrical properties of invariant sets for shifts as the setsΣa,b

and of the natural parameter space associated to them. We will study the Hausdorff dimension of such sets, which equipped with natural diadic metrics, and prove a general result of continuity. In the case of Σa,b, the Hausdorff dimension is related to the topological entropy. The continuity of the topological entropy in related cases was studied by Urba´nski [25] and also by Misiurewicz and Szlenk [17], among other authors.

In this sectionNn(a, b)will denote the number of different sequences of sizenthat appears as a subsequence of some element inΣa,b. Clearly,Nkn(a, b)(Nn(a, b))k,∀n, k∈N. In this situation, sinceNn(a, b)is an increasing function ofn, the number limn→∞(log(Nn(a, b)))/(n·log(2))exists and is equal to

ninf∈N

log(Nn(a, b)) n·log(2) . Indeed, given a natural numberk,

lim sup

n→∞

log(Nn(a, b))

n·log(2) lim sup

n→∞

log(Nk·n/ k(a, b)) n·log(2) lim

m→∞

m·log(Nk(a, b))

k·(m−1)log(2)=log(Nk(a, b)) k·log(2) . We will denote byD(a, b)this number. Notice thatD(0,1)=1.

Definition 3.A complete shift is a subset,Σ (B), ofΣ2obtained by arbitrary concatenations of elements of a fixed finite set of finite wordsB.

Now we have the following lemma, assumingD(a, b) >0 analogous to the main lemma of [18].

Lemma 3.For anya, bΣ2witha <01<10< band >0there are sequencesa < c <01<10< d < band a complete shift contained inΣc,dwith Hausdorff dimension at leastD(a, b).

Proof. Fix a largen0∈Nand let Bn0 be the set of sequences of size n0 that appear as a subsequence of some element of Σa,b. Let N =Nn0(a, b)=#(Bn0). Without loss of generality we may assume that the numberd˜= (log(Nn0(a, b)))/(n0log(2))is very close toD(a, b), soλ:=1−/D(a, b) < D(a, b)/d. Let˜ k=2N2.We note that the setBkn0 has (at least) 2kn0D(a,b)elements. An element ofBkn0 can be written asβ1β2· · ·βk whereβiBn0 for i=1,2, . . . , k.

Let γ =β1β2· · ·βk be an element in Bkn0. We say that βiBn0, 2ik−1, is goodif there are words β(s)Bkn0,s∈ {1,2}, such that β(s)=β1β2· · ·βiβ˜i(s)+1· · · ˜βk(s), andβ(s)= ˜β1(s)β˜2(s)· · · ˜βi(s)1βiβi+1· · ·βk such that β˜i(1)+1< βi+1˜i(2)+1.

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We can prove, as in [18], that at least 34kelementsβi of most wordsγBkn0 are good. Indeed, we can estimate the number of sequences inBkn0for which there are (at least) k4 positions 2i1< i2<· · ·< ik/4(k−1)such that βij is not good for 1jk4as follows: there are at most k

k/4

<2k choices of theij, 1j k4, and, given a choice ofij, 1j k4, the number of sequences for whichβij is not good for 1j k/4 is bounded by 2k/4N3k/4 N4k/52kn0D(a,b)#(Bkn0), since at the positionsij we have at most 2 choices of βij (the extreme options) to continue the sequence.

For each of these words, in which at least 34k = 32N2 elements are good we can choose good elements βi1, βi2· · ·βi3N/2 withir1ir N forr=1,2, . . . ,3N2 −1. The number of such words isNρk withρ close to 1 (and bigger thanλ). We note, as in [18], that there are: a fixed set of indexes{i1, i2, . . . , i3N/2} ⊂ {1,2, . . . , k}with ir+1irN for 1r <3N2 and a subset{βi1, βi2, . . . , βi3N/2} ⊂Bn0 such that for at least

Nρk

Ck3N/2N3N/2 Nρk

(kN )3N/2Nρk

(withρstill close to 1 and bigger thanλ) elementsβ1, . . . , βkofBkn0we haveβir =βir and it is a good element for 1r3N2 (here we have usedCrp=p!(rr!p)!rp).

Let us call the set of these sequencesB. For 1r < s3N2 letπr,s:BBnis0ir be defined by πr,s1, . . . , αk)=ir+1, . . . , αis).

If #πr,s(B) < Nλ(isir), we exclude from{1,2, . . . ,3N2 }the set of indexes{r, r+1, . . . , s−1}.The total number of indexes excluded is less than N2, provided that ρ is close enough to 1 (otherwiseB would not have so many elements), so there is a set of indexes{j0, j1, . . . , jN} ⊂ {0,1, . . . ,3N2 }which are not excluded, and there arer < s such thatβijr =βijs.

The promised complete shift is Σ (A), where A=πjr,js(B) is a set of at least Nλ(ijsijr) words of length n0(ijsijr), so the Hausdorff dimension ofΣ (A)is at least

log

Nλ(ijsijr)

/n0(ijsijr)log 2=λ·logN/n0log 2> D(a, b). Hence, in this way, we conclude the proof of the lemma. 2

We will use this lemma in order to prove

Theorem 4.With the diadic metric, defined in Section2.2, for every(a, b)Σ0×Σ1, HD(Σa,b)=D(a, b)= lim

n→∞

log(Nn(a, b)) nlog(2)

is a continuous function of(a, b). We haveD(a, b)=htop|Σa,b)/log(2). Moreover,Ω(a, b)= {(α, β)LW; a α < βb}andΩ(a, b) = {(α, β)Ω(a, b); σn(α) < βandα < σn(β)n∈N}have Hausdorff dimension equal to2D(a, b).

Proof. Let us notice, that a finite sequence that appears as a subsequence of some element ofΣc,dforc < a < b < d forcanddarbitrarily nearaandbdoes appear as a subsequence of some element ofΣa,bby compactness. Hence, for eachn∈Nwe have limca,dbNn(c, d)=Nn(a, b). Also, for eachn∈N, the number(log(Nn(a, b)))/(nlog(2))is an upper bound forHD(Σa,b). All of this imply thatHD(Σa,b)=D(a, b); that the Hausdorff dimension is a continuous function of(a, b)and thatΣa,bcan be approximated, from inside, by complete shifts with almost the same dimension.

Let us now show that Ω(a, b)= {(α, β)LW; a α < βb}and Ω(a, b) = {(α, β)Ω(a, b); σn(α) <

βandα < σn(β)n∈N}have Hausdorff dimension equal to 2D(a, b).

We can suppose, without loss of generality, that all the finite sequences1, β2, . . . , βk)that generate the referred complete shift (see previous lemma) contained in Σc,d have a large number of elements. Let us denote byΣ this complete shift. Consider theσ-invariant subshiftΣ=

n∈Nσn(Σ ). Let α˜ (resp.β˜) be the smallest (resp. the largest) element inΣ. Take a large initial finite sequence γ (resp.γ) ofα˜ (resp.β)˜ ending with some of the βi. We have

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