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Preprint submitted on 27 Jun 2021
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An expansion of the Riemann Zeta function on the critical line
Bernard Candelpergher
To cite this version:
Bernard Candelpergher. An expansion of the Riemann Zeta function on the critical line. 2021. �hal- 03271709�
An expansion of the Riemann Zeta function on the critical line B.Candelpergher
Universit´e Cˆote d’Azur, CNRS, LJAD (UMR 7351), Nice, France. candel@unice.fr
Abstract
We give an expansion of the Riemann Zeta function on the critical line as a converging series P
m≥0amqm(12 +it) in the space L2(R,cosh(πt)dt ), where the functions qm are related to Meixner polynomials of the first kind and the coefficients am are linear combinations of the Euler constant γ and the values ζ(2), ζ(3), . . . , ζ(m+ 1).
1 Laguerre functions
The Laguerre polynomials x7→Lm(2x) are defined by the generating function (cf. [6]) 1
1−ae−1−a2ax = 1 1 +a
+∞
X
m=0
Lm(2x)am where |a|<1.
They are given by Lm(2x) =Pm
k=0Cmk(−2)k xk!k. The Laguerre functions ϕm(x) =√
2 e−xLm(2x),
form an orthonormal basis of L2(]0,+∞[, dx), and we have the generating function
√2
1−ue−x1+u1−u =
+∞
X
m=0
ϕm(x)um where |u|<1. (1)
With z = 1+u1−u, we get for Re(z)>0
e−xz =√ 2π
+∞
X
m=0
ϕm(x)ψm(z), (2)
where ψm is the function defined in the half-plane {Re(z)>0} by ψm(z) = 1
√π(1 +z)
z−1 z+ 1
m
. By (2) we see that the function ψm is related toϕm by
ψm(z) = (e−xz
√2π, ϕm) = Z +∞
0
e−xz
√2π ϕm(x)dx.
Thus we have ψm(z) = √1
2π Lϕm(z), where L is the Laplace transform Lf(z) =
Z +∞
0
e−xzf(x) dx.
This transformation maps the space L2(]0,+∞[, dx) to the Hardy spaceH2(P) of analytic functions g in the half-plane P ={Re(z >0}such that: there exists Mg >0 with
Z
R
|g(x+iy)|2 dy≤Mg for all x >0.
By a theorem of Paley and Wiener each such g has non-tangential limits g(iy) = limx→0g(x+iy) at almost every point of the imaginary axis. The space H2(P) is an Hilbert space with the inner product
(g, h)H2 = Z
R
g(iy)h(iy)dy,
and the functions ψm (m ≥0), form an orthonormal basis ofH2(P). If f ∈L2(]0,+∞[, dx) then f =X
m≥0
(f, ϕm)ϕm ⇔ Lf(z) =√ 2πX
m≥0
(f, ϕm)ψm(z).
2 Mellin transform and Meixner polynomials
For a function f on ]0,+∞[, we define the Mellin transform of f by M(f)(s) =
Z +∞
0
xs−1f(x)dx, which is supposed to be defined for s∈C such that 0< Re(s)<1.
We have MLf(s) = Γ(s)Mf(1−s) for 0< Re(s)< 1, and iff and g are in L2(]0,+∞[), we have the Parseval-Mellin formula (cf. [4]) :
1 2iπ
Z 12+i∞
1 2−i∞
M(f)(z)M(g)(z) dz = Z +∞
0
f(x)g(x) dx.
The Mellin transform of ϕm is given by Z +∞
0
ϕm(x)xs−1 dx=√ 2
m
X
k=0
Cmk(−2)k k!
Z +∞
0
e−xxs+k−1 dx=√
2 Γ(s)qm(s), with
qm(s) =
m
X
k=0
Cmk(−2)k (s)k
k! where (s)k=s(s+ 1)· · ·(s+k−1) (with (s0) = 1).
We have (cf. [2])qm(s) =F(−m, s; 1; 2) whereF is the Gauss hypergeometric function (also denoted by 2F1). We have also qk(s) = k!1mk(−s,1,−1), wheremk is a Meixner polynomial of the first kind.
Since Mϕm(s) = √
2 Γ(s)qm(s) and ψm = √1
2πLϕm, we get for 0< Re(s)<1 Mψm(s) = 1
√2πMLϕm(s) = 1
√2πΓ(s)Γ(1−s)Mϕm(1−s) =
√π
sin(πs)qm(1−s).
By the definition of ψm we verify that 1xψm(1x) = (−1)mψm(x), thus we have Mψm(1−s) = (−1)mMψm(s),
this gives
qm(1−s) = (−1)mqm(s).
By the Parseval-Mellin formula we get 1
2π Z +∞
−∞
M(ϕm)(1
2+it)M(ϕn)(1
2+it) dt = Z +∞
0
ϕm(x)ϕn(x) dx=δm,n
(with δm,n = 1 ifm =n and δm,n = 0 ifm 6=m). This gives δm,n =
Z +∞
−∞
Γ(1
2 +it)qm(1
2+it)Γ(1
2+it)qn(1
2 +it) dt π =
Z +∞
−∞
qm(1
2 +it)qn(1
2+it) dt cosh(πt) Thus the polynomials t7→qm(12+it) form an orthonormal basis ofL2(R,cosh(πt)dt ) with respect to the scalar product
(f|g) = Z +∞
−∞
f(t)g(t) dt cosh(πt)
This implies that all the zeros of the polynomials t7→qm(12 +it) are real.
We have q0 = 1 and
q1(1
2 +it) = −2it q2(1
2 +it) = 1 2 −2t2 q3(1
2 +it) = −5 3it+4
3it3 q4(1
2 +it) = 3 8 −7
3t2+ 2 3t4 . . .
By Mellin transform of (1), we see that the generating function of the polynomials qm is
+∞
X
m=0
qm(s)um = 1 1−u
1 +u 1−u
−s
for u∈]−1,1[. (3)
This gives, with y= 1+u1−u, the relation y−s = 2√
π
+∞
X
m=0
ψm(y)qm(s) for y >0. (4)
Let s= 12 +it with t ∈Rand y=e−ξ, we get eitξ = 2√
πe−ξ/2
+∞
X
m=0
ψm(e−ξ)qm(1
2+it) for ξ ∈R.
The latter series converges in L2(R,cosh(πt)dt ) since P+∞
m=0|ψm(e−ξ)|2 <+∞.
If a function h∈L2(R,cosh(πt)dt ) has, in this space, an expansion kike h(t) =X
n≥0
anqn(1 2 +it), then we have
(h|eitξ) = 2√ πe−ξ/2
+∞
X
m=0
amψm(e−ξ), that is
F h(t) cosh(πt)
(ξ) = 2√ πe−ξ/2
+∞
X
m=0
amψm(e−ξ) (5)
where F is the Fourier transform defined by Fg(ξ) =R+∞
−∞ g(t)e−itξdt.
3 An expansion of Zeta
3.1 A Fourier transform
In the critical strip 0< Re(s)<1, we have (cf. [7]) ζ(s) = 1
Γ(s) Z +∞
0
f(x)xs−1dx= 1
Γ(s)Mf(s) where f(x) = 1
ex−1 − 1 x (also we have ζ(s) =sR+∞
0 ([x]−x)x−s−1dx, which gives |ζ(12 +it)|=O(|t|) for t→ ±∞).
Since we have (cf.[2]) for x >0
L(f)(x) = log(x)−Ψ(1 +x) where Ψ = Γ0 Γ, then we get for 0< Re(s)<1
M(log(x)−Ψ(1 +x))(s) =ML(f)(s) = Γ(s)M(f)(1−s) = Γ(s)Γ(1−s)ζ(1−s),
thus π
sin(πs)ζ(1−s) =M(log(x)−Ψ(1 +x))(s).
By Mellin inversion, we obtain for x >0 log(x)−Ψ(1 +x) = 1
2iπ
Z c+i∞
c−i∞
π
sin(πs)ζ(1−s)x−s ds for all 0< c <1.
With c= 12, we have for x >0
log(x)−Ψ(1 +x) = 1 2
Z +∞
−∞
ζ(1
2+it) 1
√xeitlog(x) dt cosh(πt).
Let x=e−ξ with ξ ∈R, then we get the Fourier transform Fζ(12 +it)
cosh(πt)
(ξ) = −2e−ξ/2(ξ+ Ψ(1 +e−ξ)) = 2e−ξ/2Lf(e−ξ). (6) Remark. The Fourier transform given by the relation (6), gives for g ∈L2(R), the relation
Z +∞
−∞
ζ(1
2 +it)Fg(t) dt
cosh(πt) =−2 Z +∞
−∞
g(ξ)e−ξ/2(ξ+ Ψ(1 +e−ξ))dξ.
For example, let g(t) = ts−1e−atχ[0,+∞[(t) with a > 0 and Re(s) > 12. Then Fg(t) = (a+it)Γ(s)s and we have
−1 2
Z +∞
−∞
ζ(1
2+it) 1 (a+it)s
dt
cosh(πt) = 1 Γ(s)
Z +∞
0
ξs−1e−ξ(a+12)(ξ+ Ψ(1 +e−ξ)) dξ.
Expanding the Ψ function as
Ψ(1 +e−ξ) =−γ+
+∞
X
n=1
(−1)n+1ζ(n+ 1)e−nξ since 0< e−ξ <1, we get for α=a+ 12 > 12
−1 2
Z +∞
−∞
ζ(1
2 +it) 1 (α− 12 +it)s
dt
cosh(πt) = s
αs+1 −γ 1 αs +
+∞
X
n=1
(−1)n+1ζ(n+ 1) 1 (n+α)s, Thus, for x >−12 and Re(s)> 12, we have a generalization of a formula of I.V.Blagouchine (cf.[1])
γ (x+ 1)s +
+∞
X
n=2
(−1)n−1 ζ(n)
(n+x)s = s
(x+ 1)s+1 +1 2
Z +∞
−∞
ζ(1
2+it) 1 (x+12 +it)s
dt
cosh(πt) (7)
3.2 Expansion of ζ (
12+ it)
By (5) and (6), the coefficients am of the expansion ζ(12 +it) = P
m≥0amqm(12 +it) in the space L2(R,cosh(πt)dt ) are given by
Lf(e−ξ) =√ π
+∞
X
m=0
amψm(e−ξ). (8)
For an explicit evaluation of am, let u= ee−ξ−ξ−1+1 in the relation (8), then we get for −1< u <1 1
1−u
log(1 +u
1−u)−Ψ(1 + 1 +u 1−u)
=
+∞
X
m=0
bmum where bm = am
2 . (9)
Now, take the Taylor expansion of the left side of (8). For the logarithmic part, we have simply 1
1−ulog(1 +u
1−u) = 1 1−u
+∞
X
n=0
1−(−1)n n un=
+∞
X
n=1
Xn
p=1
1−(−1)p p
un,
For the part involving the function Ψ, we need the help of (cf.[2]) the integral formula Ψ(x+ 1) = 1
x + Ψ(x) = 1
x −γ+ Z +∞
0
e−t−e−xt 1−e−t dt, this gives
− 1 1−uΨ
1 + 1 +u 1−u)
=− 1
1 +u + 1
1−uγ− 1 1−u
Z +∞
0
e−t−e−1+u1−ut 1−e−t dt, and, with (1), we get
− 1 1−uΨ
1 + 1 +u 1−u
=− 1
1 +u+ 1 1−uγ−
+∞
X
m=1
Z +∞
0
e−t(1−Lm(2t))
1−e−t dt um. Since, for m integer ≥1, we have
− Z +∞
0
e−t(1−Lm(2t)) 1−e−t dt =
Z +∞
0
e−t 1−e−t(
m
X
k=1
Cmk(−2)ktk k!)dt=
m
X
k=1
Cmk(−2)kζ(k+ 1).
then we have proved the following theorem.
Theorem. The expansion of t7→ζ(12 +it) in the space L2(R,cosh(πt)dt ) is given by ζ(1
2+it) = 2X
m≥0
bmqm(1
2+it) (10)
with b0 =−1 +γ, and for m≥1 bm =
m
X
p=1
1−(−1)p
p + (−1)m+1+γ+
m
X
k=1
(−2)kCmk ζ(k+ 1). (11) For example, we have b1 = 3 +γ−2ζ(2), and
b2 = 1 +γ−4ζ(2) + 4ζ(3) b3 = 11
3 +γ−6ζ(2) + 12ζ(3)−8ζ(4) b4 = 5
3 +γ−8ζ(2) + 24ζ(3)−32ζ(4) + 16ζ(5) Since we have, for m ≥1, the combinatorial identity
m
X
p=1
1−(−1)p
p =−
m
X
k=1
Cmk(−2)k1 k,
then we get, for the coefficients of (11), the simple expression bm =
m
X
k=0
Cmk(−1)kzk with z0 =γ−1 and zk = 2k ζ(k+ 1)−1− 1 k
if k ≥1. (12) Remark. We have for any integer k ≥0
Z +∞
0
1
ex−1 − 1 x
e−x2kxk k! =zk, thus we get
bm = Z +∞
0
1
ex−1− 1 x
e−xLm(2x)dx= 1
√2(f, ϕm), as we expected, since by Mellin transform we have formally
ζ(1
2 +it) = 2X
m≥0
bmqm(1
2+it)⇔f =√ 2
+∞
X
m=0
bmϕm
3.3 An integral formula
Since the binomial transform bvm =Pm
k=0(−1)kCmkvk is involutive then we have by (12) zm =
m
X
k=0
(−1)kCmkbk.
From (10), we have for m ≥0 bm = 1
2 Z +∞
−∞
ζ(1
2 +it)qm(1
2 −it) dt
cosh(πt), (13)
thus the binomial transform of (bm) is given by the binomial transform of (qm(s)). We have qm(s) =
m
X
k=0
Cmk(−2)k (s)k
k! ⇒2m (s)m m! =
m
X
k=0
(−1)kCmkqk(s), thus
m
X
k=0
(−1)kCmkbk = 2m Z +∞
−∞
ζ(1
2+it)(12 −it)m m!
dt cosh(πt). Finally we get the integral expression γ = 1 + 12R+∞
−∞ ζ(12 +it)cosh(πt)dt ,and ζ(m+ 1) = 1 + 1
m + 1 2π
Z +∞
−∞
ζ(1
2 +it)Γ(12 +it)Γ(12 −it+m)
Γ(m+ 1) dt for m≥1.
We see that the analytic functions f and g defined by f(s) =ζ(s+ 1)− 1
s for s6= 0 with f(0) =γ, and
g(s) = 1 + 1 2π
Z +∞
−∞
ζ(1
2+iu)Γ(12 +iu)Γ(12 −iu+s)
Γ(s+ 1) du for Re(s)>−1 2.
are such that f(m) = g(m) for all integersm ≥0. Then by the Carlson’s theorem we get f(s) = g(s) for Re(s)>−12. This gives the integral formula
ζ(s+ 1)− 1
s = 1 + 1 2π
Z +∞
−∞
ζ(1
2 +iu)Γ(12 +iu)Γ(12 −iu+s)
Γ(s+ 1) du for Re(s)>−1
2, s6= 0. (14) Remark. Let the function defined for Re(s)>0 by ζa(s) =P+∞
n=1
(−1)n−1
ns = (1− 22s)ζ(s). We have ζa(s) = 1
Γ(s) Z +∞
0
f(x)xs−1dx where fa(x) = 1 ex+ 1.
By similar calculations as before we get the following expansion in the space L2(R,cosh(πt)dt ) (1−√
2 2−it)ζ(1
2+it) = 2X
m≥0
cmqm(1
2+it) with cm = (−1)m−Log(2)−
m
X
k=1
Cmk(−1)k(2k−1)ζ(k+1).
We have c0 := 1−ln (2), and
c1 = −1−ln (2) +ζ(2)
c2 = 1−ln(2) + 2ζ(2)−3ζ(3)
c3 = −1−ln +3ζ(2)−9ζ(3) + 7ζ(4)
c4 = 1−ln (2) + 4ζ(2)−18ζ(3) + 28ζ(4)−15ζ(5)
Acknowledgments.
My warmest thanks go to F.Rouvi`ere for his helpful comments.4 Bibliography
[1] I.V.Blagouchine. A complement to a recent paper on some infinite sums with the zeta values, preprint, 2020. Available at https://arxiv.org/abs/2001.00108.
[2] I.S.Gradshteyn and I.M.Ryzhik. Tables of Integrals, Series and Products. Academic Press.
[3] G.Hetyei. Meixner polynomials of second kind and quantum algebras representing su(1,1).
Proceedings of the Royal Society A 466 (2010) (p.1409-1428)
[4] A.Ivic. The Riemann Zeta-function. Theory and Applications. Dover (2003)
[5] A. Kuznetsov. Expansion of the Riemann Ξ Function in Meixner-Pollaczec Polynomials.
Canad. Math. Bull. Vol. 51 (4), 2008 (p.561-569).
[6] N.N.Lebedev. Special functions and their applications. Dover (1972)
[7] E.C. Titchmarsh. The theory of the Riemann Zeta-function. Second Edition revised by D.R.
Heath-Brown. Clarendon Press Oxford. (1988)