R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
H. H EINEKEN
A remark on subgroup lattices of finite soluble groups
Rendiconti del Seminario Matematico della Università di Padova, tome 77 (1987), p. 135-147
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Subgroup
of Finite Soluble Groups.
(*)
H. HEINEKENIntroduction.
It is a
long standing conjecture
that every finite lattice is isomor-phic
to a section of thesubgroup
lattice of a suitable finite group.This note does not aim at
proving
ordisproving
thisconjecture
butto
provide
material for the fact that theconjecture
is false if restricted to finite soluble groups. Inparticular,
y we want toimprove
know-ledge
about the structure of minimal nontrivial sections.Subgroups
of soluble groups are soluble. It suffices therefore to consider the set of allsubgroups
of Gcontaining
agiven subgroup U
r this section is nontrivial whenever U is not a maximalsubgroup
ofG. We will see
(Lemma 1)
that a minimal nontrivial section includesa maximal chain of
length two,
and that there is at most oneneigh-
bour of the maximal element
belonging
to alonger
chain. The number ofneighbours
of the maximal element is notarbitrary (Lemma 2)
and restricts the form of the proper subsections. Also
pairs
of minimalsections
having
a member different from G in common can not be chosenarbitrarily (Theorem
2 and3).
The results
given
heredepend strongly
on the famous theorem of 0. Ore on maximalsubgroups
of finite soluble groups. More at- tention to the way Goperates
on a chief factor ispaid
in thepartic-
ular situation that U r1 V is not the proper intersection of two sub- groups of Z7
(Theorem 1). Examples
show that there are still manypossibilities
left.(*) Indirizzo dell’A.: Mathematisches Institut der Universitat, am Hub- land, D-87
Wiirzburg,
Rep. Fed. Tedesca.CONVENTIONS. If the smallest convex sublattice of the sub- group lattice of B
containing
~4. and B is denotedby ~B;
We willalso use the word « section)> in this situation.
Let L be maximal in ~ wich is in turn maximal in G. If T:) L is a maximal
subgroup
of G and L is not maximal inT,
we will say that T isexceptional
in{G; Ll.
If furthermore L is contained in morethan two maximal
subgroups
ofG,
we call{G, L}
extensive.The
linearly
ordered lattice(((chain ») consisting
of k -E-1 memberswill be denoted
by C~;
the modular latticeconsisting
of n + 2 members among which are npairwise incomparable by fIn .
This nomenclature is introduced for briefnessonly.
Fordistinction,
Zn is thecyclic
group of order n. Other group theoretic notation isstandard;
all groups considered finite and soluble.1. We remind the reader here of the Theorem of Ore to have it at our
disposal,
and we will incidate first consequences.THEOREM OF ORE. Let G be a finite soluble group and M a max- imal
subgroup
of G and the intersction of allconjugates
of M.Then we have
(1) 6f/Mc
possesses one andonly
one minimal normalsubgroup, (2)
If 8 is another maximalsubgroup
of Gand SG
= thenS and .~1 are
conjugate
in G.For a
proof
see Ore[Theorem 11, 12,
p.451, 452].
We will denotethe minimal normal
subgroup
mentioned in(1) by
hence M*is
unique
withrespect
to M*M=G,
M* rB M==MG.
We make a first use of this in
LEMMA 1. Assume that there are two different maximal sub- groups of the
group G conatining
agiven subgroup
U. Then thereare two different maximal
subgroups
of Gcontaining
U suchthat R n 8 is a maximal
subgroup
of .R.COROLLARY. Minimal sections with at least two different maximal
objects
possess at least one maximal chain oflenght
two.PROOF. We consider two different maximal
subgroups
~4. and Bof G which contain U. We
distinguish
at first two cases:Aa
=Ba
ornot.
By (2)
of the theorem ofOre,
A and B areconjugate,
and A* = B*.Now
(A
r1B)A*
is a propersubgroup
ofG,
since(A *fAG)
=GIA,,
is a semidirect
product.
There is a maximalsubgroup
C of Gcontaining (A
r1B)A*. Obviously
U c C andOG:2 AG.
We have thereforereduced this case to the second one,
namely
Without loss of
generality
we may assume Ba.Then
and since
is a chief factor of
G,
so isa chief factor of
B,
and thecorresponding subgroup
of Bavoiding
this chief
factor, namely
A nB,
is maximal in B.The Lemma is
proved
for A = S and B = .R.2. We will now take stock of the different minimal
top
sectionsthat are
possible.
LEMMA 2. Assume that
fG; t7}
is a section ofL(G) containing
more than one maximal
subgroup
of G and that{G; ~7}
is minimal among all sections{G; V}
in thisrespect.
Then there is aprime p
such that
(1)
the number of maximalsubgroups containing
U is1 + q, where q
is a power of p,(2)
there is at most oneexceptional
maximalsubgroup
in thesection
{G; .K,
say, and~.g’;
is modular with minimal non-distributive subsections
isomorphic
to where t isvariable, (3)
1 and there is anexceptional
maximalsubgroup K,
then there is a subsection of
~.g’; U}
which isisomorphic
to the sub-group lattice of the
elementary
abelian group of order q.PROOF. We take two maximal
subgroups A,
B of G which contain U and are notconjugate, By
Lemma 1 this ispossible. Minimality
of the section
yields
U = A r1 B.Again
wedistinguish
two cases:AG and Ba
areincomparable
orcomparable.
Case 1.
Aa
andBa
areincomparable.
In this casepossesses two minimal normal
subgroups
A* r1Bo/Ao n
Ba andAa n B*/Aa n Ba
such that any minimal normalsubgroup
is contained in theproduct
of these two. IfBa
is such a minimal normalsubgroup, R(A
r1B)
is a maximalsubgroup
ofG,
and all maximalsubgroups
of Gconta,ining
A. = U are obtained in this manner.It is well known that such further minimal normal
subgroups
existif and
only
if A* nBGIAGN Ba
andAGn Ba
areoperator isomorphic
in and that the number of minimal normal sub- groups is in this case1 + q, where q
is the number of minimal normal of centralG-endomorphisms
in thefactor,
a divisor of the order of the factor. Since chief factors are p-groups, q is a power of aprime.
If the two factors are not
operator isomorphic, q
= 1. The section is modular and no lowerneighbour
of G isexceptional.
Case
2. Aa D
In this case B n A is maximal in B and~ B*. If x E
N(A
nB)
r1A,
then n A = B nA,
and if x is not contained inB,
the two maximalsubgroups B
and x-1 Bx are differentsince B is
self normalizing.
To find the number of theseconjugates
of
B,
we need theindex JA
nN(A
nB) :
A nBi.
Nowand
Since
B*fBa
is anelementary
abelian p-group, there are some powerof p
manyconjugates
of .Acontaining
A n B. On the other hand A =(A
r1B)B*,
and there are noconjugates
of A different from Acontaining
A r1 B. Since maximalsubgroups containing
A r1 B avoidone of the two chief factors or
B* jBa,
we find 1 ~--pk
maximalsubgroups containing
.A r1 B(where again pk
may be1).
We have found that U = A n B is a maximal
subgroup
of B andall its
conjugates.
Theonly exceptional
lowerneighbour
of G in the section{G; P}
is therefore A if there is one at all. If A r1 B c T cA,
then
by
and T n B* is a
subgroup
of A which contains BG. So the sect- isisomorphic
to the lattice of all A-invariantsubgroups
contained in B* and
containing
BG . This is a modularlattice,
andsince
B* jBa
is anelementary
abelian p group, minimal nondistributive subsections possess 1-~- pm lowerneighbours
of thetop element,
wherem varies. This follows from case 1 of this
proof.
Theprime occurring
in
(1)
and(2)
is the onedividing
the order ofB*JBG’
so bothprimes
are the same.
If there is an
exceptional
maximalsubgroup,
thenumber q
is theindex |A
nN(A
nB) :
A nBI.
Since A =
(A
nB)B*
we haveand
So A n
N(A
nB)fBo
is the directproduct
of(B*
r1N(A
r1B))fBa
andin
particular
This
yields (3).
LEMMA 3. Assume that ~I and V are maximal
subgroups
of Gand
[G : V]
is a nondistributive modular section. Then either(i)
andV*¡VG
areoperator isomorphic
and II* =V*,
thenumber of maximal
subgroups containing
U r1 V is1-~-- q, where q
isa
prime
power,or
(ii)
the number of maximalsubgroups containing
U r1 V is1 + p,
where p is aprime,
and ZJ and V can be chosen such thatis a
prime dividing p -1.
PROOF. We
distinguish
two cases:(i)
no two maximalsubgroups containing
U r1 V areconjugate, (ii)
there is aconjugate of,
say, ZJcontaining
ZT r1 V.In case
(i),
we have at least three maximalsubgroups U, V,
W con-taining
and(since
no two of them are
conjugate).
Now U* contains and is the
unique
minimalnormal
subgroup
ofG/ Uo.
Since all threeUG, VG,
andWa
are incom-parable,
we findand
by symmetry
and the three
quotients Ua/( U
c)Y)G, YG/( U
r1V)G
and r1V)a
are
operator isomorphic.
On the otherhand,
ifV)G
is someminimal normal
subgroup
ofGI(U n V),,
contained inU*/( U
r1then
( U r1 Y)S
is another maximalsubgroup
of Gcontaining
U r1 V.The number of maximal
subgroups containing
U n V is therefore thenumber of such normal
subgroups,
which in turn is 1 + q,where q
isthe number of
operator isomorphisms
of r1V)G
intoVGI(U n Y)a,
a power of p if the
quotients
are p-groups.In case
(ii)
and if U is notconjugate
toV,
we haveSince
[G:
ismodular,
y is maximal inU,
and sois not a proper
subgroup
ofU,
therefore U r1 V is a normalsubgroup
of U and is a
cyclic
group ofprime
order. Since thereare
conjugates
of Ucontaining
U ~’1V,
whichobviously satisfy
thesame conditions as
U,
and since U is maximal inG,
we find that Vis a normal
subgroup
ofG,
alsoU*,
assubgroup
ofprime index,
isa maximal
subgroup
of G and so identical with V. Since there are no propersubgroups
of nV),
thisquotient
group is also of ordera
(different) prime,
and this order coincides with the number of con-jugates
of thesylow subgroup
r1V)
ofV).
This concludes theproof:
the cases(i)
and(ii)
areexactly
those of the lemma.3. We consider here the case that U r1 V has
only
one upperneighbour
and find restrictions on U nVI.
THEOREM 1. Let U and V be two maximal
subgroups
of the solublegroup G such that
(i)
U r1 V is maximal inV9
(ii)
there isonly
one upperneighbour
.g of U r1VI,
(iii)
there are r > 2 lowerneighbours
of G intG;
U r1V}.
Then
(a)
p = r -1 is aprime,
(b) K,
where = U and forall i, Fi+,
is the intersection of all lowerneighbours
of Piin ~ U;
U r1V},
(c)
if furthermorePr-2 = K,
Un VI -
PROOF.
By (iii),
YG = U* and We may as- sume UG = 1. SinceN( U
nV) = ( U
nV) (C( U
nV)
nU*),
the sect-ion
~N( U
r’1V);
U r1VI
isisomorphic
to thesubgroup
lattice of someelementary
abelian p-group.By (ii),
which istherefore of order p. So the number r -1 of
conjugates
of V contain-ing
U r1 V is thisprime p,
and(a)
is shown.By (ii),
U* is anoncyclic
p-group; it is the directproduct
ofsuitably
chosen minimal normal
subgroups
of V*.Forming
theproducts Li
of those minimal normal
subgroups
of V* which areoperator
iso-morphic
we have witha
description
of U* as a directproduct
with factors that arepermuted by
G. Since ZI* is a minimal normalsubgroup
ofG,
we haveand for we find
Now
(Lj
is a minimal mornalsubgroup
ofV*,
andSo
and any two different minimal normal
subgroups
of V* are notoperator isorphic.
Choose a minimal normal
subgroup Q
of U r’1 V.If Q
is not ap-group, we have
and since the
right
factor is different from 1by (iii)
and different fromby uniqueness
of U* as minimal normalsubgroup,
we find thatthe direct
product
isnontrivial,
a contradiction to the existence of Kas described in
(ii). So Q
is a p-group. Assume now the existence of some element y inQ
which does not leave allLie
invariantby
con-jugation. Then y
willpermute p
differen t of the.Li’s
into eachother,
let
Lj
be one of them. So[L. , y] # 1,
and ifthen
On the other
hand,
if all yin Q
leave allLie invariant,
thenif y
isdifferent from 1 it is not contained in and so y
operates
asa nontrivial power
automorphism
on some V*.Now y
will
permute
a suitable basis of.Lj
andagain
Now
obviously
on the other hand
since all minimal factors are centralized
by Q.
We deriveshowing (b).
If furthermore ==
.g’,
we have twopossibilities:
Case A : U* is a minimal normal
subgroup
of V*.Then is
cyclic
of order someprime q
and U r’1 Vis
cyclic
of orderdividing q
-1 and possesses no minimal normal sub - groups of orderprime
to p. We deduce that is of order pexactly and q
dividespp -1 (but
notp -1).
Case B: U* is not minimal normal in V*.
Then the minimal normal
cubgroups
of V* have order p and is a q-groupwhere q
dividesp -1.
Theelement y #
1of Q
wiolpermute exactly
p of theLi’s
andSo U* is the direct
product of p
factorsLi,
and is a(nontrivial)
normal
subgroup
ofHol(Zp).
Now(c)
followseasily.
REMARKS. Condition
(iii)
isindispensable
for(b)
as is shownby
and its maximal
subgroups
of index 4 and 9. Also theequality
= .~ isindispensable
in(c) :
For this consider the maximalsubgroups
of index 28 and 9 of the extension of theelementary
abeliangroup of order 28
by
4. Examples.
We will use asimple
constructionprinciple
to pro- vide us with a wider range ofexamples.
Webegin
with a well knowngeneral
statement.LEMMA 4. Let A and B be two groups, a chief factor of A.
We consider the factor of the wreath
product
A wr B.(i)
If is notcentral,
thenMBIN B
is a non-central chief factor of A wr B.(ii)
If is a central chief factor ofA,
the lattice of normalsubgroups
of A wr Blying
between NB and MB isisomorphic
to thelattice of B-invariant
subgroups
of(MIN)B
in wr B.The
proof
followseasily
from the definition of the standard wreathproduct.
COROLLARY 1. Consider two groups A and B with the
following properties:
(1)
A possessesonly
one minimal normalsubgroup,
denote itby .K,
further B~ is a p-group andcomplemented by
T.(2)
possessesonly
one minimal normalsubgroup LIK
whichis
complemented by
Denote
by £
the lattice of all B-invariantsubgroups
of(Z(S)
wr .I~ which are contained in
(Z(~)
Then we find for the wreathproduct
A wr B :LB IEB
andKB/1
= KB are chief factors of A wr B withcomplements
TBB andSBB,
andfurthermore
PROOF.
By (4),
there is no central chief factor of 8 in~[~S, .g] ; 11,
so this section is transferred
directly
into the wreathproduct according
to Lemma 6
(i).
ForZ(S)
n K weapply
Lemma 6(ii), obtaining
also the order of
Z(SBB)
(’B KB.For the
examples
formedaccording
to theCorollary
we willonly
~state A and B and the section 8 = r1
SBR) KB; (T’B.R
nthe
subgroups ~,
T and Kbeing
clear from the context.(I)
Take aprime
p different from 2 and 3 and defineIf
p _--__ 1
mod3,
we ifp = -1
k timea
mod 3 one direct factor
e1
ismissing.
The number k is the number of irreducible factors of xa -1 inZ~[x].
(II)
Choose A =(Dg
wr =ZaCq
to obtain the anal-ogous result
(with
one factorCi)
for8,
with 3 substituted for p.(III)
Choose A = Aut(F),
where F is the group of all one-to-one
transformations y ~
ay + b of the field of order 8 ontoitself,
and B =
Z2CQ
to obtain theanalogous
result(with
one factor for8,
with 2 substituted for p.(IV)
Choose two different oddprimes
p, r. Construct A such thatlEI
= pQ,]LjK]
=2m,
= r and all these factors are chief factors ofA,
also .g andLIK
are non central. If B = we haveagain
that 8 is a direct
product
of chainse1
and where the number of factorse1
is the number ofprime
factors of x’’-1 in(V)
In thisexample
we will not use a wreathproduct:
choosea
prime
p and aprime divisor q
of but not of 1(this q
exists since
gcd (pP" -1, (pp" 1-~ 1)2)
=gcd (pl" - 1, pp" ~-1)~.
Thenon-central extension N of the
elementary
abelian p-group .~ of rank p"by
thecyclic
group oforder q
admits anautomorphism
oforder pn. Consider as G the extension of If
by
thisautomorphism;
choose as maximal
subgroups
ap-sylow subgroup
tT and the normalizer V of aq-sylow subgroup.
lr7 nV}
is a chainCf)n.
COROLLARY 2. Consider two groups A and B with the notation and
properties
as inCorollary
1except
for(4);
instead weimpose
such that are chief factors of ~S and
S]
=Ri-l-
the successive
multiple
extension of Cby itself, t
times in all.
PROOF.
By construction,
all arecyclic,
andIt is therefore sufhcient to prove the
following
statement:(*)
If X is a(TBB
nSBB)
invariantsubgroup
of .~ which is not con-tained in then X contains
Rf.
For the moment we fix one direct factor .g of the
product
.A.B inA for our consideration. We may suppose without loss of gener-
ality
that X is contained inR:+1.
If t is an element of X which is not contained in there is at least onecomponent of t,
consisered ad element of the directproduct AB,
which is not contained in Con-jugating by
an element ofB,
if necessary, we obtain a new element t* with acomponent
y in Y which is not contained inForming
commutation
of y
with elements of Y we conclude that Y is contained in ~. Nowapplication
ofconjugation by
elementsof B
yields
that .X containsRf.
This shows(*)
andCorollary
2.(VI)
Choose .A =~’4,
and =Z .
If V and U are thecomple-
ments of the lowest 2- and 3-chief factors
respectively, IG;
possesses three
neighbours
ofG,
among which U isexceptional
andis the extension of the Boole lattice
by
itself.(VII) Taking A == 84
wrZ3
and B =Z, yelds {U;
U nV}
isomor-phic
to the extension of the Boole lattice with three atomsby itself;
by
induction the extension of any finite Boole latticeby
itself can beacchieved.
5.
Considering
more than onetop
section at the same time leadsto further relations. This is shown
by
thefollowing
two statements.THEOREM 2. Assume that
ZJ,
~’ and Ware maximalsubgroups
of G and and are modular and nondis-
tributive. If furthermore one of the sections is
isomoprhic
towhere q
is not aprime,
then and areisomorphic.
PROOF. Assume first that
~G; ( U
r1V)}
issiomorphic
to whereq is not a
prime
but aprime
power. Then is not ofprime order,
so case
(ii)
of our lemma can notapply.
Therefore isoperator isomorphic
toV*/Fc
and to The number of maximal sub- groups is one more than the number of operarorisomorphisms,
whichis the same in both these cases. So the sections are
isomorphis.
REMARK. In the dihedral group G of order
30,
choose1 us
=15, 1111
=10, 1 Wi
= 6. Then{G;
and( U
ai e mod-ular,
but the sections arenonisomorphic.
This shows thenecessity
of the condition on the number of elements in the theorem.
THEOREM 3.
(i)
IfU, Vl,
andV2
are maximal in G and U is maximal inVi ,
then theVj
are modular with minimal non-distributive sections
(for
the sameprime p).
(ii)
If in addition to thehypotheses
of(i)
there are more thantwo maximal
subgroups containing
U r’1 Vi(for i = 1, 2)
and none ofthe is maximal in
U, then, ~ U;
U U r1Y2~.
PROOF. Under the
hypotheses
of(i), {G;
is a minimalnontrivial
top section, and {U;
isisomorphic
to the latticeof all
( U
r1Vi)-invariant subgroups
ofU*¡UG,
which is a p-group.This shows
(i).
To see
(ii),
we find(V1)G
= U* ==(V2)a
and soY1
andV2
are con-jugate
in G. SinceUV1
=G,
we have that U r1Vi
and U r1V2
areconjugate
and the sections and are iso-morphic
with Umapped
onto itself.REFERENCES
[1] G. D. BIRKHOFF, Lattice theory, New York, 1940.
[2] O. ORE, Contributions to the theory
of
groupsof finite
order, Duke Math.J., 5 (1939), pp. 431-460.
[3] R. SCHMIDT, Über verbandstheoretische
Charakterisierung
derauflösbaren
und der
überauflösbaren Gruppen,
Arch. Math., 19 (1968), pp. 949-452.Manoscritto pervenuto in redazione il 26 ottobre 1985.