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The Stationary Boltzmann Equation inRnwith Given Indata

LEIF ARKERYD – ANNE NOURI

Abstract.AnL1-existence theorem is proved for the nonlinear stationary Boltz- mann equation for soft and hard forces inRnwith given indata on the boundary, when the collision operator is truncated for small velocities.

Mathematics Subject Classification (2000):76P05.

1. – Introduction

Consider the stationary Boltzmann equation (cf. [10]) in ⊂Rn, (1.1) v· $xf(x, v)=Q(f, f), x, v∈Rn,

where is a strictly convex domain with C1 boundary. The nonnegative function f represents the density of a rarefied gas with x the position and v the velocity. The operator Q is the nonlinear Boltzmann collision operator with angular cut-off and a truncation for small velocities,

Q(f, f)(v)=

Rn

Sn1χη(v, v, σ )B(vv, σ )(f(x, v)f(x, v)

f(x, v)f(x, v))dvdσ .

Here Sn1 is the (n−1)-dimensional unit sphere in Rn for η >0 and fixed,

(1.2)

χη(v, v, σ)=

0 if |v|< η or |v|< η or |v|< η or |v|< η , 1 otherwise,

v=V(v, v, σ):= v+v

2 + |v−v| 2 σ , v =V(v, v, σ):= v+v

2 − |v−v| 2 σ . This research was supported under EU contract ERB FMRX CT97 0157.

Pervenuto alla Redazione il 14 marzo 2001.

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The function B is the kernel of the classical nonlinear Boltzmann operator,

|v−v|βb(σ) with −n< β <2, bL1+(Sn1), b(σ )c>0, a.e.

The inward and outward boundaries in phase space are

+= {(x, v)×Rn;v·n(x) >0},

= {(x, v)×Rn;v·n(x) <0}, where n(x) denotes the inward normal on .

Given a function fb>0 defined on+, solutions f to (1.1) are sought with (1.3) f(x, v)= fb(x, v), (x, v)+.

Here solutions are understood in renormalized sense or an equivalent one, such as mild, exponential, iterated integral form (cf. [16], [2]). In particular those last two solution types are much used in the paper. Test functions ϕ are taken in L¯ Rn)with compact support, with v·$xϕL(×Rn), continuously differentiable along characteristics, and vanishing on .

An existence theorem for the stationary Boltzmann equation in an n- dimensional setup with only the profile of fb given, was obtained in [1] with the use of non-standard analysis. The main result of the present paper – existence of a solution to (1.1), (1.3) with any given boundary indata – is obtained by standard methods, with the presentation focusing on those aspects which are particular for the proof below.

Theorem 1.1.Suppose that fb>aedv2for some a,d>0and a.a.(x, v)∈∂+, and that

(x,v)∈∂+[v·n(x)(1+v2+ln+ fb(x, v))+1]fb(x, v)d x dv <. Then the equation(1.1)has a solution satisfying the boundary condition(1.3).

With some extra technical arguments added in the proof, the result can also be obtained under the weaker condition fb > 0, b(σ) > 0 a.e., and the condition of strict convexity of the domain relaxed. For clarity of presentation, the proof below is given in the case n=3, but no new ideas or techniques are needed for a general n.

For the linear Boltzmann equation, existence of stationary measure solutions was obtained in [14] via measure compactness, existence of stationary L1- solutions in [18], and uniqueness of L1-solutions in [27], [28] based on a study of the relative entropy. Concerning the linearized Boltzmann equation, existence and uniqueness of stationary solutions in a bounded domain is discussed in [23].

In the close to equilibrium case, there are a number of results concerning the nonlinear stationary Boltzmann equation in Rn, see [19], [20], [21], [30] and others. In those papers general techniques, such as contraction mappings, can

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be used. Stationary problems in small domains have been solved in similar ways in [26], [22], and the unique solvability of internal stationary problems for the Boltzmann equation at large Knudsen numbers was likewise established in [24].

For discrete velocity models, in particular the Broadwell model, there are stationary results in two dimensions, among them [8], [9], [12], [13], [15]. In the slab case for the BGK equation, results on stationary boundary-value problems with large indata are presented in [29]. Existence results far from equilibrium for the stationary Povzner equation in bounded domains of Rn were obtained in [6], [25]. Measure solutions of the stationary, fully nonlinear Boltzmann equation in a slab are studied in [3], [11], and general L1 solutions in [4], [5].

A half-space problem for the stationary, fully nonlinear Boltzmann equation in the slab with given indata far from equilibrium, is solved in [7], when the collision operator is truncated for large velocities and for small values of the velocity component in the slab direction. For more complete references the reader is referred to the above cited papers.

Entropy related quantities are widely used to study kinetic equations and kinetic formulations of conservation laws. In the context of Povzner and 1D Boltzmann papers [4], [5], [6], the entropy dissipation term gives quite pre- cise information, and this term is an important tool to obtain solutions of (1.1) and (1.3), via weakL1-compactness as in the time-dependent case. In the present paper, approximations to the problem at hand are first constructed in Section 2 similarly to our earlier, stationary papers, by extending techniques from, among others, the time-dependent case ([16], [10]). However, the compactness argu- ments from the earlier papers for reaching the limits of the approximations, are no longer available. Instead in Section 3, besides the earlier implications of the entropy dissipation control, new local aspects of the entropy dissipation integral are used to prove that the characteristics of the approximations can be split into a large set of “good” and a small set of “bad” ones, supporting what in the limit generates respectively an L1-solution to (1.1), (1.3), and – possibly – a

“decoupling, singular” contribution. A key point is Lemma 3.3, the compactness related aspect that in the limit the contribution from large function values van- ishes, with respect to space points that support a non-negligible set of “good”

characteristics. Section 4 performs the passage to the limit. The whole analysis can be carried through also without the χη-factor in the kernel of Q. But then the arguments of this paper by themselves do not exclude the alternative possibility, that an infinite mass in the limit may end up in the ’singular’ part at v=0, in which case the present method does not deliver any solution.

2. – Approximations

Lemma 2.1.For0< α <1, there is a function fα solution to αfα+v· $x fα = Q(fα, fα), (x, v)×R3, (2.1)

fα(x, v)= fb(x, v), (x, v)+.

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Moreover, (2.2)

v2fα(x, v)d x dvcb, m0

ψ(v)fα(x, v)d x dvm1,

and

(2.3)

×R6×S2χηB(fαfαfαfα)ln fαfα

fαfα d x dvdvc2,

whereψ(v):=(1+ |v|max(0,β)), f= f(x, v), f= f(x, v), f = f(x, v), and m0, m1, cb, and c2are positive constants, depending on fbbut independent ofα.

Proof.Only the main lines of the proof are given, similar arguments being developped in [4], [5], [6].

Let 0 < j, p, n, µ∈ N, η >r > 0, ρ ≥ 1 be given, as well as a C regularization b˜ of b. Let K be the closed and convex subset of L1(×R3), defined by

K =

fL1+(×R3);mn j

ψ(v)f(x, v)d xdvCn α

.

Here Cn depends on n and fb, and mn j depends on n, j, and fb. They are defined in the discussion following (2.4) below. Set

s+(x, v):=inf{s∈R+;(xsv, v)+}, s+j =min(s+,j) , and

s(x, v):=inf{s ∈R+;(x+sv, v)}.

Define the map T on K by T(f)= F, where F is the solution to

(2.4)

αF+v· $xF=

R3×S2

χrχpnBµ



F 1+ F

j

(x, v) fϕρ 1+ fϕρ

j

(x, v)

F(x, v) fϕρ 1+ fϕρ

j

(x, v)



dvdσ, (x, v)×R3,

F(x, v)= fb(x, v)j, (x, v)+. Here,

Bµ(v, v, σ )=max 1

µ,minµ,|v−v|βb˜(θ) .

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The functions χr(v, v, σ) and χpn(v, v, σ ) are taken in C, invariant under an exchange of v and v, invariant with respect to the collision transformation J(v, v, σ )=(v, v, σ), and such that 0≤χr, χpn≤1. Moreover, they satisfy

χr(v, v, σ)=

1 if |v| ≥η+r,|v| ≥η+r,|v| ≥η+r,|v| ≥η+r, 0 if |v| ≤ηr or |v| ≤η−r or |v| ≤ηr or |v| ≤η−r,

χpn(v, v, σ)=





1 if v2+v2n2

2 , v−v

|v−v| ·σ≤1− 1

p, |v−v| ≥ 1 p, 0 if v2+v2n2 or v−v

|v−v| ·σ≥1− 1

2p or |v−v| ≤ 1 2p. The functions ϕρ are mollifiers in x defined by

ϕρ(x)=ρϕ(ρx), 0≤ϕC0(R3) , ϕ(x)=0 for |x| ≥1,

ϕ(x)d x =1.

By a monotone iteration scheme applied to (2.4), it is easy to see that T is well defined. Green’s formula gives the existence of Cn > 0 depending on fb and n, such that αψ(v)F(x, v)d xdvCn for any fL1+(×R3) and n. From the exponential form of F, obtained by integration of (2.4) along characteristics,

F(x, v)fb(xs+(x, v)v, v)j

exp



−αs+(x, v) 0

s+(x,v)

χrχpnBµ fϕρ 1+ fϕρ

j

(x+sv, v)dvdσds



for (x, v)×R3. Hence,

F(x, v)(fb(xs+(x, v)v, v)j)exp

1+8

3π2n3j| ˜b|L1

diam

, x,|v| ≥1. So there is mn j >0 and independent of f, with

ψ(v)F(x, v)d xdvmn j.

The mappingT takes K into K. As in [4], [5], [6], the mapT is continuous and compact for the strong L1 topology. Hence the Schauder fixed point theorem

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applies. A fixed point f satisfies

(2.5)

αf +v· $xf =

χrχpnBµ



f 1+ f

j

(x, v) fϕρ

1+ fϕρ j

(x, v)

f(x, v) fϕρ 1+ fϕρ

j

(x, v)



dvdσ, (x, v)×R3,

f(x, v)= fb(x, v)j, (x, v)+, with

mn j ψ(v)f(x, v)d x dvCn α .

Again following the proof in [4], [5], [6], a strong L1 compactness argument can be used to pass to the limit in (2.5) when ρ tends to infinity. It gives rise to a solution f of

(2.6)

αf +v· $xf =

χrχpnBµ



f 1+ f

j

(x, v) f

1+ fj(x, v)

f(x, v) f 1+ f

j (x, v)



dvdσ, (x, v)×R3,

f(x, v)= fb(x, v)j, (x, v)+, with

(2.7) mn j

ψ(v)f(x, v)d x dvCn

α .

Denote the solution of (2.6) by f j. Multiplying (2.6) by (1+ln fj/(1+ fjj)), then integrating the resulting equation on ×R3, and using Green’s formula, implies that

α

×R3 fj(1+ln f j)(x, v)d x dvc<+∞,

uniformly with respect to j. And so, also using (2.7) and going to the limit as in the time-dependent case, the weak L1 limit f of f j when j tends to infinity, satisfies

(2.8)

αf+v·$xf =

χrχpnBµ(f(x, v)f(x, v)f(x, v)f(x, v))dvdσ , (x, v)×R3, f(x, v)=fb(x, v), (x, v)+.

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Given α >0, write fn,p,r for f in (2.8) to stress the parameter depen- dence. Multiplying (2.8) by 1+v2 and by ln fn,p,r, then integrating both resulting equations on ×R3 and using Green’s formula, implies that

α

(1+v2+ln fn,p,r)fn,p,r(x, v)d x dvc<+∞,

uniformly with respect to n, p, r, µ, and b. So, when˜ b˜ tends to b, n and p tend to infinity, µ tends to zero, and χr tends to χη, the weak limit fα of fn,p,r satisfies

(2.9) αfα+v· $xfα =

χηB(fαfαfαfα)dvdσ, (x, v)×R3, fα(x, v)= fb(x, v), (x, v)+,

with ψ(v)fα(x, v)d x dvCαb. Moreover,

v2fα(x, v)d x dvc1,

for some c1 > 0, uniformly with respect to α. Indeed, multiplying (2.9) by 1+v2 and integrating over ×R3, leads to

(2.10) α

(1+v2)fα(x, v)d x dv+

|v·n(x)|(1+v2)fα(x, v)d xdv

=

+v·n(x)(1+v2)fb(x, v)d x dv .

Denote by (ξ, η, ζ) the three components of the velocity v. Multiply (2.9) by ξ and integrate it over a×R3, where a is the part of with x1<a.

Set Sa:=∩ {x1=a} and a:=∩ ¯a. This gives

(2.11) α

a×R3ξfα(x, v)d x dv+

Sa×R3ξ2fα(a,x2,x3, v)d x2d x3dv

a×R3ξv·n(x)fα(x, v)d x dv=0. Integrating (2.11) on [l,L], where l := inf{a;Sa = ∅}, L := sup{a;Sa = ∅}, leads to

×R3ξ2fα(x, v)d x dvα(Ll)

×R3(1+v2)fα(x, v)d x dv +

L

l

a×R3ξv·n(x)fα(x, v)d x dvda<c1,

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the last inequality by (2.10). Analogously, η2fα(x, v)d xdv and ζ2fα (x, v)d x dv are bounded from above, uniformly with respect to α. And so, the boundedness of energy in (2.2) follows. Recalling the small velocity cut- off χη, this in turn implies the upper m1−bound of (2.2), and then the lower m0−bound by using the exponential estimates to ingoing boundary as in (3.6) below. Finally, Green’s formula for fαln fα implies that, for some c2>0, (2.12)

×R6×S2χηB(fαfαfαfα)ln fαfα

fαfα d x dvdvc2, uniformly with respect to α. This ends the proof of Lemma 2.1.

The final limit procedure of our previous papers [4]-[7] was based on equi- integrability obtained from the entropy dissipation control, but that argument could not be invoked here to pass to the limit when α tends to zero. Instead, the rest of the paper is devoted to other ideas also giving a passage to the limit in (2.1) under the energy bound (2.2) and the entropy dissipation bound (2.3).

3. – The behaviour of fαalong characteristics

The first topic of this section concerns boundedness along characteristics for the solutions of (2.1). For (x, v), denote by ζx,v the characteristic through (x, v),

ζx,v:= {(x+sv, v);x+sv}.

Lemma 3.2. Let V > ηbe given. Denote byCαk the set of characteristics for which the solution fαof(2.1)satisfies

(3.1) 1

kfα(x+sv, v)k, (x+sv, v)ζx,v, ζx,vCkα, |v| ≤V. For k large enough the restriction of(Ckα)cto{(x+sv, v);x+sv,|v| ≤ V} has measure smaller than(ln lnk)18 (uniformly inα).

Proof.This preliminary lemma is a consequence of Chebyshev’s inequality applied to the exponential form of equation (2.1).

Given k ∈N large enough, let k be such that

(3.2) kexp(C2|b|L1k) <k and k<

ln

k inf

|v|≤V,0<α≤1 fb

C2|b|L1 . Here C2 is chosen so that (3.5) below holds. By Green’s formula,

|v·n(x)|fα(x, v)d x dv <c.

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Hence there is a subset αk of S2 such that |(kα)c|<ck(−14) and

∂,±γ·n(x)<0

0 |v|3|γ ·n(x)|fα(x,±γ|v|)d|v|d x <k14, γαk

in each of the two cases ±.

Let x1 be the ingoing and x2 the outgoing intersection with of the characteristic in direction γ through x. For γkα, there is a subset Xαk,1(γ ) of such that |(Xkα,1(γ ))c|<2k(−14) and for xXαk,1(γ ),

(3.3)

|v|3γ ·n(x1)fα(x1,−γ|v|)d|v|<k12,

|v|3|γ ·n(x2)|fα(x2, γ|v|)d|v|<k12,

For γαk, xXαk,1(γ ) satisfying |γ ·n(xj)| > k(−14), j = 1,2, together with (3.3), it holds that

|v|3fα(xj, (−1)jγ|v|)d|v|<k34, j =1,2.

For such (γ,x), there is a subset Wαk(γ,x) of the interval [η,+∞[ such that

|(Wkα(γ,x))c|<2η3k(−14) and

fα(xj, (−1)jγ|v|) <k, |v| ∈Wkα(γ,x), j =1,2. Consequently, these (γ,x,|v|) with γ = |v|v , satisfy

x±s(x, γ )γ =x±s(x, γ|v|)|v|γ ∈

Xαk,2(γ ):= Xαk,1(γ )y∂; |γ ·n(y)|>k(−14) (both cases), and when |v| ∈Wkα(γ,x±s(x, γ )γ ), it holds that (3.4) fαx+(−1)js(−)j+1(x, v)v, (−1)j|v|γ<k.

The boundedness of energy (2.2) implies that

R3

η≤ |v| ≤V|v−v|βfα(x, v)d xdvdv <c(V) ,

uniformly with respect to α. For γS2, let "γ be a plane in R3 orthogonal to γ. Denote by γ the orthogonal projection of on "γ. For any x, denote by xγ its orthogonal projection on γ. Obviously infγ∈S2|γ|>0, and

ψ(v)f(x, v)d xdv=

γ

;xγ+τγ∈}

ψ(v)f(xγ+τγ, v)d xγdτdv, γS2.

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Writing v = |v|γ and considering only the integration over those γ which belong to kα and over those x =xγ+τγ, where xγ belongs to the orthogonal projection pγ of Xαk,2(γ ) on γ, it holds that

αk

R3

η≤ |v| ≤V

xγγ,pγ1(xγ)⊂Xkα,2(γ )

xγ+τγ∈||v|γ −v|β fα(xγ+τγ, v)

× |v|2dτd xγd|v|dvdγ <c(V) . Hence, from kα, a suitable subset may be removed of magnitude ≤c(V)k(−14), so that in what remains of the set (keeping the old notation for the new smaller set)

R3

η≤ |v| ≤V

xγγ,p−1γ (xγ)⊂Xkα,2(γ )

xγ+τγ∈||v|γ −v|β fα(xγ+τγ, v)

× |v|2dτd xγd|v|dv<k14, γαk . Consequently, there is a subsetXαk,3(γ )ofγsuch that|(Xαk,3(γ ))c|<k(−12) and pγ1(xγ)Xkα,2(γ ) if xγXkα,3(γ ), satisfying

s(x,γ )

s+(x,γ )

R3

η≤ |v| ≤V||v|γ −v|βfα(xγ +τγ, v)|v|2d|v|dvdτ <k34, if xγXkα,3(γ ). For xpγ1(xγ) with xγXαk,3(γ ), from Wαk(γ,x) a suitable subset in [η,V] of magnitude ≤ η2k(−14) may be removed so that in what remains of the set (and keeping the old notation for the new smaller set)

s(x,γ )

s+(x,γ )

R3||v|γ −v|βfα(xγ +τγ, v)dτdv<k. And so for these (x, v)

(3.5)

s(x,v)

s+(x,v)ν(fα)(xγ +sv, v)ds=

s−(x,γ )

|v|

s+(x,v)

|v|

ν(fα)(xγ +s|v|γ,|v|γ )ds

= 1

|v|

s(x,γ )

s+(x,γ )

χη||v|γ −v|βb(θ)fα(xγ+τγ, v)dσdv

C2|b|L1k, xγXαk,3(γ ) . Take

Xαk(γ):=x∈;xs+(x, γ)γXkα,2(−γ),x+s(x, γ)γXαk,2(γ), xγXαk,3(γ).

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Define the set of characteristics αk by

ζx,|v|γ; γkα, xXkα(γ ), |v| ∈Wkα(γ,x).

By the exponential form,

(3.6)

fb(xs+(x, v)v, v)exp

0

s+(x,v)+ν(fα)(x+sv, v))ds

fα(x, v)

fα(x+s(x, v)v, v)exp

s(x,v) 0

+ν(fα)(x+sv, v))ds

.

The previous discussion implies that for k large enough, k can be chosen so that (3.2) holds together with

|(C˜kα)c| ≤k(−18)(ln lnk)18, and by (3.2), (3.4-6)

fα(x, v)k, ζx,v∈ ˜Ckα, |v| ≤V.

The inequality 1kfα(x, v) follows similarly. That completes the proof of the lemma. Also notice that the choice of k can be made so that k increases with k.

The rest of the section is devoted to a study of the large function values for fα. For λ >0, denote by (ai)iN the sequence of functions

a0(λ):=max{1,lnλ}, . . . ,ai+1(λ):=max{1,lnai(λ)}, and take

f˜λα := fα if fαλ, f˜λα :=0 else , fλα := fα− ˜fλα. Define

Oα,λ:=

x;

η≤ |v| ≤V

fλα(x, v)dv >0

, and

Oα,i,n:=

xOα,λ;meas{µ∈S2;xXαn(µ)}> 4π i

. For γS2, set

Aγ,α,i,n:= Xαn(γ )(Oα,λ\Oα,i,n) .

The contribution of the large fα-values is small from those space points that support a non-negligible amount of “good” characteristics, namely

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Lemma 3.3.Let V,i,n be given inNand sufficiently large. Forλlarge enough with respect to V,i,n, it holds that

Oα,i,n

η≤ |v| ≤V

fλα(x, v)dvd xg1(i,n, λ) ,

where the function g1does not depend onα,

g1(i,n, λ):= ci9n2ai3(λ) ai31(λ) , with c not depending on V,i,n, λ, α.

The lemma holds for λ=ee..

en

with i4 exponentials and neeei, which are the values used for the applications in Section 4 below.

Proof. Take i = 2j for j ∈ N. Split S2 into i disjoint neighborhoods S1, . . . ,Si with piecewise smooth boundaries,

|Sk| = 4π

i , diam(Sk)c¯

i, for 1≤ki,

Sk =Sl, for some 1≤li,

where c¯ ≥ 4π is an i-independent constant. Consider xOα,i,n. Take 1≤ki such that |Ix| ≥ 4iπ2, where

Ix:=Sk∩ {µ∈S2;xXnα(µ)},

Notice the symmetry in this construction, i.e. −Ix =Sl∩ {µ∈S2;xXαn(µ)}. Define

Vx:=v∈R3; η≤ |v| ≤V, where fλα(x, v) the largest and

Vx

fλα(x, v)dv=i5

η≤ |v| ≤V

fλα(x, v)dv

.

It holds that

|Vx| ≤ 4

3π(V3η3)i5.

Divide Ix into four quarters of equal area, and defined by two orthogonally intersecting geodesics in S2. Let the direction O z, in velocity space R3, be parallel to the element γoS2 defining at the intersection of those two orthog- onal geodesics. For v in Vx, consider the plane in velocity space R3, defined by v and O z. In this plane denote the coordinate of v in the γo-direction by ζ and the orthogonal coordinate by ξ. We assume V &η. The proof will be split into three cases, depending on the position of v in this plane.

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(i) |ξ| ≤ r and |ζ| ≥ η, where r = 10V. For symmetry reasons it is enough to consider ξ ≥ 0 and ζη. Take v with V3 ≤ |v| ≤ 2V3 , with

v

|v| in that quarter of −Ix corresponding to ξξ < 0 and ζζ < 0, and with

|v| ∈Wnα(|vv|,x). Take σS2 such that for V(v, v, σ) as defined by (1.2),

V

|V| belongs to Ix, |V| > η, and ζζ > 0. Such σ’s form a set of area of magnitude ≥i2. For each v already chosen, also restrict the set of σ’s so that |V| ∈ Wnα(|VV|,x). For these v the measure of the corresponding (v, σ) is ≥ci4, and fα(V(v, v, σ))n.

Denote by Wx1 :=

vVx; |ξ| ≤r, ζη and meas Txvci4 2

,

where Txv:=

(v, σ) as defined above;fα(x,V(v, v, σ))λ a2(λ)

,

and by

Wx2:= {v∈Vx; |ξ| ≤r, ζη} \Wx1. (i)(a) For vWx1, (v, σ)Txv, and writing fα = f,

f f

ffa2(λ)

n2a3(λ) .

Here given n, the second inequality holds for λ large enough, and implies ln f f

ffa4(λ). Moreover, fff λ

a2(λ)f f

a2(λ)n f a2(λ)f

2n ≤ f f 2 . Hence

f ≤ 2n

a4(λ)cbc˜B(f fff)ln f f ff,

where cb is a positive lower bound of b, and c˜ =1 if 0≤β <2, c˜=(2V)β if −3 < β < 0. And so by (2.12), integration of this last inequality for xOα,i,n, vWx1 and (v, σ)Txv gives that

Oα,i,n

Wx1

fλα(x, v)d x dvc ni4 a4(λ).

(i)(b) For vWx2, consider as a new set of v, the set {V(v, v, σ );(v, σ ) /Txv} with elements now denoted by v1. Its volume is of order of magnitude at

(14)

least i2. From this set of v1, define v1 and v1 either as in (i)(a), or take v1 correspondingly but with ζζ1<0, so that, again with fα = f,

|V(v, v1, σ)|,|V(v, v1, σ)|> η, f(x, v1)λ

a2(λ)a1(λ) ,

for λlarge enough, and f(x, v1)n. Since the volume of v1 is of magnitude

i3, there is no loss of generality to restrict the domain of (v1, σ) so that f(x, v1)f(x, v). Hence,

f(x, v)f(x, v1)f(x, v1)f(x, v1)f(x, v)(a1(λ)n)f(x, v)a2(λ) , for λ so large that a1(λ)a2(λ)n. Moreover,

f(x, v)f(x, v1)

f(x, v1)f(x, v1)a1(λ)

na2(λ) , for λ large enough, so that

ln f(x, v)f(x, v1)

f(x, v1)f(x, v1)a3(λ) . And so by (2.12),

Oα,i,n

Wx2

fλα(x, v)d x dvci4 a2(λ)a3(λ). Together (a) and (b) give for case (i) that

Oα,i,n

η≤ |v| ≤V,|ξ|≤r,ζ≥η fλα(x, v)d x dvci9 n

a4(λ) + 1 a2(λ)a3(λ)

.

(ii) |ξ| ≥r. Consider ξr, the case ξ ≤ −r being analogous. In this case, a bound from above of O

α,λ,i,n

v∈Vx;ξ≥r fλα(x, v)d x dv is obtained in a number of steps not exceeding i2. The “extreme case” is |v| = V and v orthogonal to the z-axis. Define a second plane through the O z-axis and orthogonal to the vO z-plane. At least a fourth of the area of Ix corresponds under γ = |v|v to a preimage to the left of this second plane, and a fourth of the area of Ix corresponds to one to the right of this plane. Withv to the right, take v to the left with −|vv|Ix, v with negative ζ-component between −23V and −13V and with |v| ∈Wnα(|vv|,x). For each such v, take σ such that −|vv|Ix, v with negative ζ-component, and such that v belongs to the right of the second

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