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www.elsevier.com/locate/anihpc

C 1 -regularity of the Aronsson equation in R 2

Changyou Wang

a,

, Yifeng Yu

b

aDepartment of Mathematics, University of Kentucky, Lexington, KY 40506, USA bDepartment of Mathematics, University of Texas at Austin, Austin, TX 78712, USA Received 2 May 2006; received in revised form 26 January 2007; accepted 5 March 2007

Available online 2 August 2007

Abstract

For a nonnegative, uniformly convexHC2(R2)withH (0)=0, ifuC(Ω),ΩR2, is a viscosity solution of the Aronsson equation (1.7), then uC1(Ω). This generalizes theC1-regularity theorem on infinity harmonic functions in R2 by Savin [O. Savin,C1-regularity for infinity harmonic functions in dimensions two, Arch. Ration. Mech. Anal. 176 (3) (2005) 351–361] to the Aronsson equation.

©2007 Elsevier Masson SAS. All rights reserved.

Résumé

SiHC2(R2)est une fonction uniformément convexe telle queH (0)=0, et siuC(Ω), ΩR2, est une solution de viscosité de l’équation d’Aronsson (1.7), alorsuC1(Ω). Ceci généralise à l’équation d’Aronsson le théorème deC1-régularité de Savin [O. Savin,C1-regularity for infinity harmonic functions in dimensions two, Arch. Ration. Mech. Anal. 176 (3) (2005) 351–361]

pour les fonctions∞-harmoniques dansR2.

©2007 Elsevier Masson SAS. All rights reserved.

MSC:35J60; 35J70

Keywords:Viscosity solution; Discrete gradient flow

1. Introduction

Calculus of variations inLwas initiated by Aronsson [1–4] in 1960s. Thanks to both the development of theory of viscosity solutions of elliptic equations by Crandall and Lions (cf. [17]) and several applications to applied fields (cf. Barron [8], Barron and Jensen [9], Aronsson, Crandall and Juutinen [7], and Crandall [13]), there have been great interests in the last few years to study the minimization problem of thesupremalfunctional:

F (u, Ω)=ess sup

xΩ

H

x, u(x),u(x)

, ΩRn, uW1, Ω,Rl

. (1.1)

Barron, Jensen and Wang [10] have established both necessary and sufficient conditions for the sequentially lower semicontinuity property of the supremal functional F inW1,, which are suitable L-versions of Morrey’s qua-

* Corresponding author.

E-mail address:cywang@ms.uky.edu (C. Wang).

0294-1449/$ – see front matter ©2007 Elsevier Masson SAS. All rights reserved.

doi:10.1016/j.anihpc.2007.03.003

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siconvexity (cf. [20]) for integral functionals. In the scalar case (l=1), Barron, Jensen and Wang [11] (see also Crandall [12]) have established, under appropriate conditions, the existence ofabsolute minimizersand proved that any absolute minimizer is a viscosity solution of the Aronsson equation

−∇x

H

x, u(x),u(x)

·Hp

x, u(x),u(x)

=0, xΩ. (1.2)

Among other results in [22], the second author has showed that the convexity ofH (·, p)are sufficient for viscosity solutions of the Aronsson equation (1.2) to be absolute minimizers ofF.

Partially motivated by [22] and Crandall, Evans and Gariepy [16], Gariepy, Wang and Yu [18] have established the equivalence between absolute minimizers of F and viscosity solutions of Aronsson equation (1.2) for quasiconvex HamiltoniansH=H (p)C2(Rn)by introducing the comparison principle ofgeneralized cones(see Theorem 2.1 in Section 2 below).

In this paper, we are mainly interested in the regularity (e.g. differentiability orC1) of viscosity solutions of the Aronsson equation.

Before stating the main results, we would like to review some of previous results forH (p)= |p|2,pRn. It is well known (cf. [5,6,19]) that Eq. (1.2) is the infinity-Laplace equation, of which a viscosity solution is called an infinity harmonic function,

u:= − n

i,j=1

uiujuij=0, inΩ, (1.3)

and the absolute minimality is called absolute minimal Lipschitz extension (or AMLE) property:

for any open subsetUΩ andvW1,(U )C(U )¯ withv=uon∂U,we have

uL(U )vL(U ). (1.4)

Aronsson [5] proved that anyC2-infinity harmonic function satisfies the AMLE property. Jensen [19] has proved the equivalence between an infinity harmonic function and the AML property, and the unique solvability of the Dirich- let problem of Eq. (1.3).

Crandall, Evans and Gariepy [16] have recently showed that uC0(Ω)is an infinity harmonic function iff u enjoys comparison with cones inΩ:

for any open subsetUΩ,a, bR, andx0Ω, u(x)()a+b|xx0| on

U\ {x0}

u(x)()a+b|xx0| inU. (1.5)

In a very recent important paper [21], Savin has utilized [16] and Crandall and Evans [15] to prove that any C0-infinity harmonic function inΩR2is inC1(Ω).

In this paper, we extend the main theorems of [21] to the Aronsson equation for a class of Hamiltonian functions HC2(R2).

First we extend [15] and obtain the following theorem on blow-up limits of viscosity solutions of the Aronsson equation onRnforn2, which may have its own interests.

Theorem A.Assume thatHC2(Rn)is nonnegative and uniformly convex, i.e. there isαH >0such that

pT ·Hpp(p)·H|p|2,pRn, (1.6)

andH (0)=0. Suppose thatuC0(Ω),ΩRn, is a viscosity solution of the Aronsson equation:

Hp

u(x)

Hp

u(x)

: ∇2u(x)=0, inΩ, (1.7)

then for any xΩ, there exists a ex,rRn, with H (ex,r)=S+(H, u, x) (see Section 2 for the definition of S+(H, u, x)), such that

rlim0max

Br(x)

|u(y)u(x)ex,r·(yx)|

r =0. (1.8)

Based on Theorem A and the main theorem of [18], we are able to make necessary modifications of the idea of [21] to prove

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Theorem B.Under the same assumptions of TheoremA. IfuC0(Ω),ΩR2, is a viscosity solution of the Aronsson equation(1.7), thenuC1(Ω).

A compactness argument from the proof of Theorem B yields

Theorem C. Under the same assumptions of Theorem A. There exists a monotonically nondecreasing function ρ:[0,1] →R+, withlimr0ρ(r)=0, such that ifuis a viscosity solution of the Aronsson equation(1.7)inB1R2, withH (u)L(B1)C, then

oscBr|∇u|ρ(r),r1

2. (1.9)

A direct consequence of Theorem C is the following Liouville property.

Theorem D.Under the same assumptions of TheoremA. IfuC0(R2)is a viscosity solution of the Aronsson equation (1.7)inR2and

u(x)C 1+ |x|

, thenuis linear.

Due to the local Lipschitz continuity for viscosity solutions of (1.7), the uniform convexity condition (1.6) can be slightly relaxed. In fact, we have the following remark.

Remark E.Theorems B, C, and D remain to be true, provided thatHC2(R2)satisfies:

(i) H (0)=0 andH (p)0 for anypR2. (ii) H is coercive, i.e. lim|p|→+∞H (p)= +∞. (iii) (Hpipj)(p)is positive definite for anypR2.

The paper is written as follows. In Section 2, we review the main theorems of [18]. In Section 3, we outline some basic properties of the Aronsson equation (1.7) and prove of Theorem A. In Section 4, we establish three key propositions which are needed to prove Theorem B. In Section 5, we prove both Theorems B, C, D, and Remark E.

2. Review of the main theorems by [18]

In this section, we review the main theorems of [18] which are needed for the paper. We assume that the Hamil- tonian functionH (x, u, p)=H (p)C2(Rn)depends only on thep-variable. First, we recall a few definitions.

Definition 2.1.A functionuWloc1,(Ω)is an absolute minimizer of the supremal functionalF, if for any open subset and anyvW1,(U )C(U )¯ withv=uon∂U, then

F (u, U )=H

u(x)

L(U )F (v, U )=H

v(x)

L(U ). (2.1)

Definition 2.2.For anyk0, the generalized cone centered at the origin with slopek,CkH(x), is defined by CkH(x)= max

{pRn:H (p)=k}p·x, xRn, (2.2)

where·is the inner product inRn.

Definition 2.3.A upper semicontinuous functionu∈USC(Ω)enjoys comparison with generalized cones from above (abbreviatedu∈CGCA(Ω)) if we have, for anyV Ω,x0Ω, andk0,

u(x)u(x0)+CkH(xx0)x∂Vu(x)u(x0)+CkH(xx0),xV . (2.3)

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A lower semicontinuous functionv∈LSC(Ω)enjoys comparison with generalized cones from below (abbreviated v∈CGCB(Ω)) if−venjoys comparison with generalized cones from above, withHreplaced byHˆ(H (p)ˆ ≡H (p) for all pRn). A continuous function wC(Ω) enjoys comparison with generalized cones (or abbreviated w∈CGC(Ω)) ifw∈CGCA(Ω)∩CGCB(Ω).

Definition 2.4.A functionu∈USC(Ω)is a viscosity subsolution of the Aronsson equation (1.7), if for any(x0, φ)Ω×C2(Ω)

u(x0)φ(x0)u(x)φ(x),xΩ then

Hp(φ)Hp(φ): ∇2φ|x=x00. (2.4)

A functionu∈LSC(Ω)is a viscosity supersolution of the Aronsson equation (1.7), if−uis a viscosity subsolution of (1.7) withHreplaced byHˆ, whereH (p)ˆ =H (p)forpRn. A functionuC(Ω)is a viscosity solution of the Aronsson equation (1.7), ifuis both a viscosity subsolution and supersolution of (1.7).

Now we state the main theorem proved by [18] on the equivalence among absolute minimizers, viscosity solutions of the Aronsson equation (1.7), and comparison with generalized cones.

Theorem 2.1.(See [18].) Assume thatH satisfies:

H1. HC2(Rn),H (0)=0, andH (p)0for anypRn. H2. H is quasi-convex, i.e.

H

tp+(1t )q

max

H (p), H (q)

,p, qRn, 0t1. (2.5)

H3. H is coercive:

|p|→+∞lim H (p)= +∞. (2.6)

Then the following three statements are equivalent:

(a) uWloc1,(Ω)is an absolute minimizer ofF (v,·)= H (v)L(·). (b) u∈CGC(Ω).

(c) uC(Ω)is a viscosity solution of the Aronsson equation(1.7).

In particular, Theorem 2.1 implies that any viscosity solution of (1.7) enjoys comparison withCkH(·). This plays a crucial role in the paper.

In [18] Proposition 3.1, the following properties of CGC(Ω)have been established.

Proposition 2.2.(See [18].) Under the same assumptions as in Theorem2.1. Ifu∈CGC(Ω), thenuWloc1,(Ω), and, for anyx0Ωand0< r < d(x0, ∂Ω), we have(i)

Sr+(H, u, x0):=inf

k0|u(x)u(x0)+CkH(xx0),x∂Br(x0)

(2.7) exists and is monotonically nondecreasing with respect tor >0. In particular,

S+(H, u, x0)= lim

r0+

Sr+(H, u, x0) (2.8)

exists for any x0Ω and is upper semicontinuous; (ii) Sr(H, u, x0):=Sr+(H ,ˆ −u, x0) exists and is monoton- ically nondecreasing with respect to r >0, where H (p)ˆ =H (p) for pRn. In particular, S(H, u, x0)= limr0+Sr(H, u, x0) exists for any x0Ω and is upper semicontinuous; and (iii) for any x0Ω, we have S+(H, u, x0)=S(H, u, x0). Moreover, ifu(x0)exists forx0Ω, then we have

H

u(x0)

=S+(H, u, x0)=S(H, u, x0). (2.9)

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Proposition 2.3.(See [18].) Assumeu∈CGC(Ω). For anyx0Ω,0< r < d(x0, ∂Ω), ifxr∂Br(x0)satisfies u(xr)u(x0)=CH

Sr+(H,u,x0)(xrx0) (2.10)

then for any0< R < d(xr, ∂Ω)we have

SR+(H, u, xr)Sr+(H, u, x0). (2.11)

For this paper, we also need the comparison property of viscosity solutions for (1.7) with linear functions.

Proposition 2.4.Under the same assumptions as in Theorem2.1, letψ (x)=a·x+b (a∈Rn,bR)be a linear function such that ifa=0thenHp(a)=0. For any open subsetUΩ, ifuC0(Ω)is a viscosity solution of the Aronsson equation(1.7)anduψon∂U, thenuψinU.

Proof. Ifa=0, thenψ=bso thatψ (x)=b+C0H(x)is a generalized cone with slopek=0. Hence Proposition 2.4 follows from Theorem 2.1.

Ifa=0, then we have|Hp(a)| =δ >0 for someδ >0. Suppose that the conclusion were false, then there exist an open subsetVˆ Ωandxˆ∈V such thatu=ψon∂Vˆ, and

maxVˆ

(uψ )=(uψ )(x) >ˆ 0.

LetR >0 be such thatVBR, and >0 be sufficiently small. Then we have u(x)ψ (x)+

R2− |x|2

on∂V ,ˆ but

u(x) > ψ (ˆ x)ˆ +

R2− | ˆx|2 . For simplicity, we may assume

uψ+

R2− |x|2

(x)ˆ =max

ˆ V

uψ+

R2− |x|2 .

Sinceψ+(R2− |x|2)C2(V )ˆ anduis a viscosity solution of (1.7), we have

0−

i,j

Hpi(a−2x)Hˆ pj(a−2x)(ˆ −2δij)=2Hp(a−2x)ˆ 2. (2.12) This is impossible, since

Hp(a−2x)ˆ 1

2Hp(a)=δ 2>0

if >0 is sufficiently small. This completes the proof of Proposition 2.4. 2 3. Some preliminary results of (1.7) and proof of Theorem A

This section is devoted to the proof of Theorem A. To do it, we need several lemmas. The first lemma asserts that the assumption of Theorem A implies that of Theorem 2.1.

Lemma 3.1.Suppose thatHC2(Rn)is a nonnegative, uniformly convex function, withH (0)=0. ThenHsatisfies the conditions(H1)–(H3)in Theorem2.1. Moreover,H (p) >0andHp(p)=0for all0=pRn.

Proof. Since a uniformly convex function is quasi-convex,Hsatisfies H2. SinceHis uniformly convex, there exists aαH>0 such that

Hpp(p)αHIn,pRn. (3.1)

This, combined with the Taylor expansion up to second order, implies H (p)H (q)+Hp(q)·(pq)+αH

2 |pq|2,p, qRn. (3.2)

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It follows from 0=H (0)=minpRnH (p)thatHp(0)=0. Therefore, by (3.2), we have H (p)αH

2 |p|2,pRn, this yields H3.

Suppose that there exists 0=p0Rn such thatH (p0)=0. Then the convexity and nonnegativity ofH imply H (tp0)=0 for all 0t1. This implies

0= d2 dt2

t=0+

H (tp0)=p0T ·Hpp(0)·p0αH|p0|2, this is impossible.

Suppose that there exists 0=p1Rnsuch thatH (p1) >0, butHp(p1)=0. Then (3.2) implies 0=H (0)H (p1)Hp(p1)·p1=H (p1).

This is also impossible. Hence the proof of Lemma 3.1 is complete. 2

Denote bySn1Rnthe unit sphere ofRn, and letH1(c)= {pRn: H (p)=c}(c >0) be the level set ofH. Now we have

Lemma 3.2. Under the same assumptions as in Lemma 3.1. Then for any c > 0, the Gauss map ν(p)=

Hp(p)

|Hp(p)|:H1(c)Sn1is aC1diffeomorphism.

Proof. It follows from Lemma 3.1 and the implicit function theorem that for anyc >0,H1(c)Rnis a strictly convex C2-hypersurface. Hence, by (3.1),νC1(H1(c),Sn1)is one to one, and onto. In particular,ν is aC1- diffeomorphism. 2

Lemma 3.3.Under the same assumptions as in Lemma3.1. For anyk0,CkH(·)is convex and positively homoge- neous of degree one. Moreover,CkH(x)C1(Rn\ {0}).

Proof. It follows from the definition thatCHk (·)is the supremum of a family of linear functions so that it convex and satisfies

CkH(t x)=t CkH(x),t >0, ∀xRn.

To seeCkHC1(Rn\ {0}), it suffices to prove that fork >0CHkC1(Sn1). By the Lagrange Multiple Theorem, for anyxSn1there exists apˆ∈H1(k)such that

CkH(x)= ˆp·x, and Hp(p)ˆ

|Hp(p)ˆ |=x (3.3)

so thatν(p)ˆ =x orpˆ=ν1(x)C1(Sn1). ThereforeCkH(x)=ν1(x)·xC1(Sn1). 2

Lemma 3.4. Under the same assumptions as in Lemma3.1. IfuC0(Rn)is a viscosity solution of the Aronsson equation(1.7)satisfyingS+(H, u,0)= H (u)L(Rn)<, then there existsp0Rn, withH (p0)=S+(H, u,0), such that

u(x)=u(0)+p0·x,xRn. (3.4)

Proof. First we claim that

Sr+(H, u,0)=S+(H, u,0), ∀r >0, (3.5)

SR+(H, u, y)S+(H, u,0), 0=yRn,R >0. (3.6)

To see (3.6), observe that for anyyRnand xRn, with|xy| =R, we have

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u(x)=u(y)+

1

0

u

t x+(1t )y

·(xy) dt

u(y)+

1

0

H (p)maxH (u)L∞p·(xy)

=u(y)+CHH (u)L∞(xy).

This implies

SR+(H, u, y)H (u)

L(Rn)=S+(H, u,0).

It is easy to see that (3.5) follows from (3.6) and the factSr+(H, u,0)S+(H, u,0).

IfS+(H, u,0)=0, thenH (u(x))=0 for a.e.xRn. Hence∇u(x)=0 for a.e.xRnso thatuis constant and (3.4) holds withp0=0.

We may assume thatS+(H, u,0) >0. ForR >1, there existsxR∂BRsuch that

u(xR)=u(0)+CSH+(H,u,0)(xR). (3.7)

On the other hand, for anyxRn, we have, by (3.6), u(xR)u(x)CH

S|+

xR−x|(H,u,x)(xRx)CSH+(H,u,0)(xRx). (3.8)

(3.7) and (3.8) imply u(x)u(0)+ |xR|

CHS+(H,u,0) xR

|xR|

CSH+(H,u,0)

xRx

|xR|

. (3.9)

For any xRn, let R >1 be sufficiently large so that xRx =0. By Lemma 3.3, we have that CSH+(H,u,0)C1(Rn\ {0})is convex. Hence we have

CSH+(H,u,0) xR

|xR|

CSH+(H,u,0)

xRx

|xR|

CSH+(H,u,0)

xRx

|xR|

· x

|xR|. (3.10)

Combining (3.9) with (3.10), we obtain u(x)u(0)+ ∇CSH+(H,u,0)

xRx

|xR|

·x,xRn. (3.11)

We may assume that there exists aqSn1such that limR→∞ xR

|xR|=q. It is clear that limR→∞xRx

|xR| =q. Hence (3.11) yields

u(x)u(0)+ ∇CSH+(H,u,0)(q)·x,xRn. (3.12)

Applying the same argument withuandH replaced by−uandH (p)ˆ =H (p)forpRn, we have that there is a ˆ

qSn1such that

u(x)u(0)+ ∇CSH+(H,u,0)(q)ˆ ·x,xRn. (3.13)

Comparing (3.12) with (3.13), we conclude that

CSH+(H,u,0)(q)= ∇CSH+(H,u,0)(q)ˆ =p0 and

u(x)=u(0)+p0·x,xRn.

It is easy to see thatH (p0)=S+(H, u,0). Hence the proof of Lemma 3.4 is complete. 2 Now we are ready to give the proof of Theorem A.

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Proof of Theorem A. For simplicity, we assume thatx0=0 andu(0)=0. It follows from Theorem 2.1 and Propo- sition 2.2 thatuWloc1,(Ω). For anyrk↓0, letvk(x)=u(rrkkx):Br−1

kR. Then for anyR >0, we have

vkL(BR)uL(Brk R)RCR,vkL(BR)uL(Brk R)C. (3.14) Therefore we may assume that there existsvLloc(Rn), withvL(Rn), such that for anyR >0

vkvC0(BR)→0, ∇vk→ ∇v weakinL(BR). (3.15)

Sincevk is a viscosity solution of (1.7) onBr

k1, we see thatvis a viscosity solution of (1.7) onRn. Moreover, by the lower semicontinuity (cf. [10]), we have

H (∇v)

L(BR)lim inf

k→∞H (∇vk)

L(BR)=lim inf

k→∞H (∇u)

L(Brk R)

=lim inf

k→∞S+(H, u, x)

L(Brk R)=S+(H, u,0). (3.16)

In particular, we have

S+(H, v,0)H (v)

L(Rn)S+(H, u,0). (3.17)

On the other hand, for anyr >0 there exists axrk∂Br such that vk(xrk)vk(0)=CH

Sr+(H,vk,0)

xrk

. (3.18)

It is readily seen that Sr+(H, vk,0)=Sr+

kr(H, u,0)S+(H, u,0). (3.19)

After passing to subsequences, we may assume that there existsxr∂Br such that limk→∞xrk=xr. Then (3.18) and (3.19) imply

v(xr)v(0)CHS+(H,u,0)(xr). (3.20)

This implies

Sr+(H, v,0)S+(H, u,0), ∀r >0. (3.21)

Takingrinto zero, (3.17) and (3.21) imply S+(H, v,0)=H (∇v)

L(Rn)=S+(H, u,0). (3.22)

Hence Lemma 3.4 implies thatv=a·x, for someaRn, and we have

rlimk0

u(rkx)u(0)

rka·x L(B1)

=0. (3.23)

This implies (1.8). Suppose not, then there exists rk ↓0+, xkRn with |xk| =rk, and δ >0 such that for any eH1(S+(H, u,0)), we have

|u(xk)e·xk|

rk δ,k1. (3.24)

But, on the other hand, there existsaH1(S+(H, u,0))such that after passing to subsequences,vk(x)u(|xrkk|x)a·xuniformly onB1. This contradicts (3.24). Therefore the proof of Theorem A is complete. 2

4. Propositions

This section is to establish the differentiability for any viscosity solution of the Aronsson equation (1.7) by showing that there is a unique blow-up limit at any point forn=2: for anyx0Ω, limr0ex0,rexists and its limit is continuous with respect tox0.

To do this, we follow the clever idea of [21] and the strategy is as follows. Consider the generic case that x0Ω such that S+(H, u, x0) >0 and u is nonlinear near x0. Then there exists r0 >0 and a linear seg- ment [y0, z0] ⊂Br0/6(x0) and a linear function l(x) =a0·x +b0 such that for some x0(y0, z0), one may

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have either (i) u(x)l(x),x ∈ [y0, z0];u(x0)=l(x0);u(y0) > l(y0), u(z0) > l(z0), or (ii) u(x)l(x),x ∈ [y0, z0];u(x0)=l(x0);u(y0) < l(y0), u(z0) < l(z0). Assume the first case happens, then the first observation is that there is an affine plane P containing the graph ofl such that y0, z0 belong to two different connected com- ponents of{u > P} ∩Br0(x0)(see Lemma 4.2 below). Since Theorem A implies that there existsex0,rR2 such that maxxBr(x0)|u(x)u(x0)ex0,r·(xx0)|

r =o(1)for smallr >0, we want to prove|ex0,ra0| =o(1)for smallr >0 (see Lemmas 4.3 and 4.4 below). The proof of Lemma 4.5 is different from that of [21] Lemma 3, here we use the discrete gradient flow which has originated from [15] when they studied the regularity of the infinity Laplace equation.

A continuous version of this type of gradient flow by [15] was communicated to us by Crandall [14].

The following proposition is the crucial step to prove Theorem B.

Proposition 4.1.Under the same assumptions as in TheoremA, letuC0,1(B6),B6R2, be a viscosity solution of the Aronsson equation(1.7). For any >0, there isδ=δ(, H,uL(B6)) >0such that if

ue6·xL(B6)δ, 1H (e6)2, (4.1)

and if, for0< r12,

ue0,6r·xL(B6r)δr, (4.2)

for somee0,6rR2withH (e0,6r)=S+(H, u,0). Then

|e6e0,6r|2C (4.3)

for some1C=C(H ) <∞.

Proof. We divide the proof into two cases.

Case A.uis nonlinear inBr: There are a line segment[z1, z2] ⊂Br, a linear functionl(x)=a0·x+b0, x∈ [z1, z2] witha0=u(z|z22)u(zz1|1), and az3(z1, z2)such that either (1)

ul on[z1, z2], u(z1) > l(z1), u(z3)=l(z3), u(z2) > l(z2), or (2)

ul on[z1, z2], u(z1) < l(z1), u(z3)=l(z3), u(z2) < l(z2).

For simplicity, assume that (1) holds. Then we have

Lemma 4.2.Under the same notations. Then there exists eR2, with H (e)=S+(H, u, z3), such thatz1and z2 belong to two distinct connected components of the set{yR2: u(y) > u(z3)+e·(yz3)} ∩B6.

Proof of Lemma 4.2. It follows from Theorem A that forsk↓0 there existseR2, withH (e)=S+(H, u, z3), such that

slimk0

u(y)u(z3)e·(yz3)L(Bsk(z3))

sk =0. (4.4)

We first claim thatz1, z2∈ {yR2: u(y) > u(z3)+e·(yz3)}. In fact, by the assumption (1) and (4.4), we have, for anyzk∈ [z1, z2] ∩∂Bsk(z3),

(a0e)·

zkz3 sk

=l(zk)l(z3)e·(zkz3) sk

u(zk)u(z3)e·(zkz3)

sk →0,

ask→ ∞. Hence, we have(a0e)·(zz3)=0 for anyz∈ [z1, z2]. This implies u(zi)u(z3) > l(zi)l(z3)=a0·(ziz3)=e·(ziz3), i=1,2.

(10)

Now, suppose thatz1, z2belong to the same connected component of{yR2: u(y) > u(z3)+e·(yz3)} ∩B6. Then there exists a polygonal lineΓ ⊂ {yR2:u(y) > u(z3)+e·(yz3)}∩B6joiningz1toz2. LetS=Γ∪[z1, z2] be the closed curve andUB6be the open set such thatS=∂U. Without loss of generality, we assume that there exists aβ >0 such that

Bβ+(z3)=Bβ(z3)

yR2: 0< (yz3, z2z1) < π

U.

Note that there exists anδ0>0 such thatu(y)u(z3)e·(yz30for anyyΓ. Therefore there are a small >0 and a unit vectorvR2, with (v, z2z1)=π2 ande+v=0, such that

u(y)u(z3)+(e+v)·(yz3),yS.

Note thatψ (y)=u(z3)+(e+v)·(yz3)is linear and∇ψ=e+v=0 so that Lemma 3.1 implies thatH (ψ ) >0 andHp(ψ )=0. Therefore, Proposition 2.3 implies

u(y)u(z3)+(e+v)·(yz3),yU.

In particular, we have

slimk0 max

yBsk(z3)B+β(z3)

|u(y)u(z3)e·(yz3)|

sk >0,

this contradicts (4.4). Therefore Lemma 4.2 is proven. 2 Now we want to prove

|e6e|2C. (4.5)

To prove (4.5), we may assume|e6e|2. Denotef=e6eand form the stripS:= {yR2| |f·(yz3)| 2δ}. It is easy to see the width ofSis at most . Moreover, (4.1) implies

u(y)u(z3)e6·(yz3)2δ, ∀yB6. (4.6)

One can check

yR2|f ·(yz3) <−2δ

B6

yR2: u(y) < u(z3)+e·(yz3) ,

yR2|f ·(yz3) >

B6

yR2: u(y) > u(z3)+e·(yz3) .

Therefore, by Lemma 4.2, there is a connected component of{yR2: u(y) > u(z3)+e·(yz3)} ∩B6, calledU, that intersectsB1and is contained in the stripS.

We claim thatUB6. For, otherwise, we haveu(y)=u(z3)+e·(yz3)for ally∂U, Proposition 2.3 implies uu(z3)+e·(yz3)inU. This contradicts with the definition ofU. Therefore there exists a polygonal lineΓ insideUstarting inB1and exitingB6.

Now we can find a pointz4B6, with|z4z3| =3 andz4z3f, such that (A1) u(y)u(z3)e6·(yz3)L(B2(z4))2δ, 1H (e6)2.

(A2) {yR2: u(y) > u(z3)+e·(yz3)} ∩B6has a connected componentUSthat contains a polygonal lineΓ connecting the two arcsS∂B2(z4).

The estimate (4.5) follows from the following two lemmas.

Lemma 4.3.Under the same notations. There isδ=δ(, H ) >0such that

H (e)H (e6)−2. (4.7)

Proof of Lemma 4.3. We may assume thatH (e)H (e6). The convexity ofHimplies

Hp(e6)·f H (e6)H (e). (4.8)

Now we have

(11)

Claim 4.3(a).There areδ=δ(H ) >0andC=C(H ) >0, with2, such that for anyxUB1(z4), we have

CH (e)H +(yx)e·(yx)+4δ, ∀y∂B1(x). (4.9)

Proof of Claim 4.3(a). AsH (e)H (e6)2 and2, we haveH (p)4 for anypH1(H (e)+Cδ).

For anyy∂B1(x), letp0H1(H (e)+Cδ)be such that CH (e)H +(yx)=p0·(yx).

By the Lagrange Multiple Theorem, we have Hp(p0)

|Hp(p0)| =yx.

By the convexity, we have

=H (p0)H (e)Hp(p0)·(p0e).

Hence we have

CH (e)H +(yx)e·(yx)=(p0e)·(yx)=(p0e)· Hp(p0)

|Hp(p0)|

C

|Hp(p0)|δ C

maxH (p)4|Hp(p)|δ4δ provided thatC4 max{H (p)4}|Hp(p)|. This implies (4.9). 2

Claim 4.3(b).There areδ=δ(H ) >0andC=C(H ) >0, with2, such that for anyxUB1(z4), we have

S+(H, u, x)H (e)+Cδ. (4.10)

Proof of Claim 4.3(b). For anyx0B1(z4)U, we have thatB1(x0)B2(z4)andu(z3)+e·(x0z3) < u(x0).

Note that

u(y)=u(z3)+e·(yz3) < u(x0)+e·(yx0)u(x0)+CH (e)H (yx0),y∂UB1(x0), and

u(y)u(z3)+e·(yz3)+4δ < u(x0)+e·(yx0)+4δ, ∀y∂B1(x0)U. (4.11) It follows from (4.9) that we have

u(y)u(x0)+CH (e)H +(yx0), on∂(UB1(x0)).

Hence Theorem 2.1 implies

u(y)u(x0)+CH (e)H +(yx0), inUB1(x0).

This, combined with Proposition 2.2, implies (4.10). 2 Now we have

Claim 4.3(c).There existsy0L= {z4+t|HHp(e6)

p(e6)|: −13t14}such that

S+(H, u, y0)H (e6)−50Hp(e6)δ. (4.12)

Proof of Claim 4.3(c). SinceLB2(z4), A1 implies u

z4−1

3 Hp(e6)

|Hp(e6)

u

z4−1 4

Hp(e6)

|Hp(e6)|

1

12e6· Hp(e6)

|Hp(e6)|−4δ. (4.13)

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