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Construction of isodual codes from polycirculant matrices

Minjia Shi, Li Xu, Patrick Solé

To cite this version:

Minjia Shi, Li Xu, Patrick Solé. Construction of isodual codes from polycirculant matrices. Designs, Codes and Cryptography, Springer Verlag, 2020, �10.1007/s10623-020-00799-8�. �hal-02944227�

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https://doi.org/10.1007/s10623-020-00799-8

Construction of isodual codes from polycirculant matrices

Minjia Shi1 ·Li Xu1·Patrick Solé2

Received: 30 November 2019 / Revised: 15 July 2020 / Accepted: 25 August 2020

© Springer Science+Business Media, LLC, part of Springer Nature 2020

Abstract

Double polycirculant codes are introduced here as a generalization of double circulant codes. When the matrix of the polyshift is a companion matrix of a trinomial, we show that such a code is isodual, hence formally self-dual. Numerical examples show that the codes constructed have optimal or quasi-optimal parameters amongst formally self-dual codes.

Self-duality, the trivial case of isoduality, can only occur overF2in the double circulant case.

Building on an explicit infinite sequence of irreducible trinomials overF2,we show that binary double polycirculant codes are asymptotically good.

Keywords Quasi-polycyclic codes·Isodual codes·Formally self-dual codes·Double circulant codes·Trinomials

Mathematics Subject Classification Primary 94B05·Secondary 11C08

1 Introduction

Self-dual codes is one of the most fascinating class of codes as witnessed by their many connections with modular forms [25], invariant theory and combinatorial designs [21]. This class has been enlarged, in recent years, toisodualcodes that is to say codes that are equivalent

Communicated by V. A. Zinoviev.

This research is supported by National Natural Science Foundation of China (61672036), Excellent Youth Foundation of Natural Science Foundation of Anhui Province (1808085J20), Academic fund for outstanding talents in universities (gxbjZD03).

B Minjia Shi

smjwcl.good@163.com Li Xu

xuli1451@163.com Patrick Solé sole@enst.fr

1 Key Laboratory of Intelligent Computing and Signal Processing of Ministry of Education, School of Mathematical Sciences, Anhui University, Anhui 230601, China

2 CNRS, University of Aix Marseille, Centrale Marseille, I2M, Marseille, France

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to their duals [1,7,17,21]. These constitute in turn a subclass of the larger class offormally self-dual codesthat is to say codes the weight enumerator of which is a fixed point of the MacWilliams transform [6,8–10]. A very popular and successful construction technique for isodual codes is the use of circulant matrices. In particular double circulant codes are easily shown to be isodual [5]. In the present paper, we generalize this technique to polycirculant matrices, and introduce double polycirculant codes.

In [2,20] was studied the notion of polycyclic codes, that is linear codes over a finite fieldF, that are invariant under a generalized shift (called here apolyshift), and affording a structure of ideal over a ring of the formRf = F[x]/ffor some f F[x](the case f =xn1 is that of classical cyclic codes). While the name was coined in [20], the concept (under the name pseudo-cyclic code) has been known for a long time [23]. As is well known, polycyclic codes are shortened cyclic codes, and conversely shortened cyclic codes are polycyclic [23, p .241].

In the present paper, we introduce and study a class of codes called double polycirculant codes (DP) from the standpoint of duality, minimum distance, and asymptotic performance.

A matrix is calledpolycirculantif its rows are successive polyshifts of its first row. A DP code is then a linear code with generator matrix of the form(I,A)whereIis an identity matrix, and Aa polycirculant matrix. Thus DP codes reduce to double circulant codes when the polyshift is the classical shift. WhenAt=Q A QforQa permutation matrix it is easy to show that the DP code is equivalent to its dual, and is, in particular, formally self-dual (FSD). FSD codes have been studied extensively overF2[6,10,18],F3[8],F4[12], and even overF5,orF7[9].

Indeed, we can show that DP codes can be binary self-dual only if they are double circulant.

We focus on the special case when the matrix of the polyshift is the companion matrix of a trinomial with nonzero constant term. In that situation, every polycirculant matrix satisfies the condition on its transpose mentioned above. Forq =2,3,5,7 numerical examples in short to medium lengths show the DP codes have parameters equal or up to one unit of the best-known FSD codes. Further, by random coding, we can show that the relative distances of long binary codes in that family satisfy a family of lower bounds that is, up to epsilons, the Gilbert–Varshamov bound for linear codes of rate one half. They thus constitute a class of asymptotically good codes. The argument relies on the construction of an infinite family of irreducible trinomials, a fact of independent interest, and on some properties of cyclic vectors in linear algebra [13, chap. 7]. This generalizes the asymptotic properties of self-dual double-circulant codes [3], and of self-dual negacirculant codes [4,24]. The proof is restricted toF2where we can show that an infinite family of irreducible trinomials exists.

The material is arranged as follows. Section2collects the notations and notions needed to follow the rest of the paper. Section3studies duality properties of DP codes: isoduality, self-duality and evenness. Section4derives asymptotic bounds by random coding. Section5 displays some numerical examples of parameters of DP codes. Section6concludes the article and points out some significant and challenging open problems.

2 Preliminaries

Throughout the paper the notationMt denotes the transpose of the matrixM.

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2.1 Linear codes

Throughout,Fdenotes a finite field. Ifqis a prime power, we denote byFqthe finite field of orderq.LetNdenote a nonnegative integer. A(linear) codeCof lengthNover a finite field Fq is aFqvector subspace ofFqN.The dimension of the code is its dimension as aFqvector space, and is denoted byk.The elements ofC are calledcodewords. Two codesC andD are (monomially)equivalentif there is a monomial matrixMsuch thatMC=D[14, §1.7]

(recall that a matrix ismonomialif it contains exactly one nonzero element per row and per column; in particular any permutation matrix is a monomial matrix). The(Hamming) weightofx FqN is denoted byW(x).Theweight distributionof a codeC is the set of numbersAi’s fori =0,1, . . . ,n,where

Ai= |{x C |W(x)=i}|.

The minimum nonzero weightdof a linear code is called theminimum distance. Thedual C of a codeCis understood w.r.t. the standard inner product. A code isself-dual if it is equal to its dual, andisodual if it is equivalent to its dual. A code isformally self-dual (FSD) if it has the same weight distribution as its dual. Thus isodual codes are FSD. A binary code isevenif the weights of all its codewords are even, andoddotherwise. IfC(N)is a sequence of codes of parameters[N,kN,dN], theraterandrelative distanceδare defined as

r=lim sup

N→∞

kN

N andδ=lim inf

N→∞

dN

N .

A family of codes is said to beasymptotically goodif it contains a sequence with rate and relative distance such thatrδ > 0.Recall the classicalentropy functionH(x)of the real variablexdefined for 0<x <1,by the formula

H(x)= −xlog(x)(1x)log(1x).

See [21, Chap. 10, §11] for background material. We recall, for context, but are not going to invoke, the classical Gilbert–Varshamov bound

r1H(δ).

2.2 Polycyclic codes

We say that a linear codeC of lengthnover a field Fispolycyclicif there exists a vector c=(c0,c1, . . . ,cn−1)Fn such that for every(a0,a1, . . . ,an−1)Cwe have

(0,a0,a1, . . . ,an−2)+an−1(c0,c1, . . . ,cn−1)C.

We refer tocas anassociate vectorofC. Note that such a vector may be not unique.

To an associate vectorc we attach the polynomial c(x) = c0 +c1x +c2x2+ · · · + cn1xn−1.Let f(x) = xn c(x).It is shown in [20] that polycyclic codes are ideals in Rf =F[x]/f(x)with the usual correspondence between vectors and polynomials.

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It is shown in [20], that a polycyclic code with the associate vectorcis left invariant by right multiplication of the matrixDof the form:

D=

0 1 0 . . . 0 0 0 1 . . . 0

...

0 0 0 . . . 1 c0 c1 c2 . . .cn−1

. (1)

We call the endomorphism of Fn with matrix Dt thepolyshiftassociated withc,and denote it byTc.The matrixDtis called in linear algebra thecompanion matrixof f(x)[13,

§7.1]. Ifc=(1,0, . . . ,0)thenTcis just the standard cyclic shift to the right. Sometimes, to avoid double indices, we will writeTforTc.

2.3 Double polycirculant codes

A matrixAof sizen×nispolycirculantfor a polyshiftTcif its rows are in succession a,Tc(a),Tc2(a), . . . ,Tcn−1(a).

Such a matrix is uniquely determined by its first row and the associate vectorc.If c = (1,0, . . . ,0)then Ais just a circulant matrix. A linear codeC of length 2nis said to be double polycirculant(DP) if its generator matrixG is of the formG = (I,A),whereI is the identity matrix of sizen×n,and Ais a polycirculant matrix of the same size. If c=(1,0, . . . ,0), thenC is a (pure) double circulant code [3].

Caveat:We use N for the length of the DP code, andnfor the size of A. ThusN =2n in the whole paper.

3 Duality results 3.1 Isoduality

The following proposition is our main motivation to introduce double polycirculant codes.

Proposition 1 Let A be a matrix satisfying At = Q A Q,with Q a monomial matrix that satisfies Q2= I,where I is identity of order n.The code C = (I,A)is an isodual code of length2n.

Proof The parity-check matrix ofCis thenH =(−At,I).Recall thatHspansC.Using the hypothesis, we haveHQ=(−Q A,Q),whereQ=

Q 0

0 Q .HenceQ HQ=(−A,I), a matrix which spans a code equivalent toC.The result follows.

Remark 1 In general it is known that any matrixA,invertible over some field satisfiesAt= u Au,withu2=I[11]. It is not known whenucan be a monomial matrix.

Now we exhibit a class of DP codes where this proposition applies.

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Theorem 1 Given an associate vector c = (c0,c1, . . . ,cn−1), and the vector a = (a1,a2, . . . ,an), define the polycirculant matrix A by the equation

A=

a Tc(a) Tc2(a) . . . Tcn−1(a)

.

The matrix Tcis the companion matrix of some polynomial f . If f is of the form xnaxmb with a,b F\ {0},then there is a monomial matrix Q of order 2 such that A Q = Q At. Namely, one can take

Qi,j=

1, if i+j=m+1,

b, if i+ j=n+m+1, 0, otherwise.

In particular, under these hypotheses, the code C= (I,A)is isodual.

Proof We know that for any vectorc=(c0,c1, . . . ,cn−1), the matrix

Tc=T =

0 0 · · · 0 c0 1 0 · · · 0 c1 0 1 · · · 0 c2

· · · · · · · 0 0 · · · 0 cn2

0 0 · · · 1 cn−1

,

and it’s the companion matrix of f(x)=xncn1xn−1− · · · −c1xc0overFq.So, if f(x)=xnaxmb,thenc0 =b,cm=a,c1= · · · =cm−1=cm+1= · · · =cn−1=0.

If we letE = A Q,F = Q At,E =(Ei,j)n×n,F =(Fi,j)n×n,A=(Ai,j)n×n,then we obtainEi,j= n

k=1Ai,kQk,j,Fi,j= n

k=1Qi,kAj,k, and, by the definition ofQ, we can obtain Ei,j =

Ai,m+1−j, 1 j m;

b Ai,n+m+1j,m< j n;Fi,j=

Aj,m+1−i, 1im;

b Aj,n+m+1i,m<in.

Now we have to proveEi,j =Fi,j fori,j =1,2, . . . ,n.

LetTjbe the j-th row of the matrixT. By the definition ofA, we can get Ai,1,Ai,2, . . . ,Ai,n

=Tc

Ai−1,1,Ai−1,2, . . . ,Ai−1,n

=

Ai−1,1,Ai−1,2, . . . ,Ai−1,n Tt.

Then

Ai,j =(Ai1,1,Ai1,2, . . . ,Ai1,n)Tjt =

b Ai−1,n, j=1;

Ai1,m+a Ai1,n, j=m+1;

Ai−1,j−1, ot herwi se.

We distinguish four cases depending on the relative positions ofiand jwith respect tom.

(i) If1imand1 jm,then we have Ei,j = Ai,m+1−j andFi,j = Aj,m+1−i. In this case, 1 m+1i m and 1 m +1 j m. If i j, when j = m, we can geti = j = m, Ei,j = Am,i = Fi,j; when 1 j < m, we can get Ai,m+1j = Ai−(ij),m+1j−(ij) = Aj,m+1i.If i < j, we can get Aj,m+1i = Aj−(j−i),m+1−i−(j−i)=Ai,m+1−j.It means thatEi,j=Fi,j.

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(ii) If1imandm< j n,then we haveEi,j =b Ai,n+m+1−jandFi,j =Aj,m+1−i. In this case 1 m +1i m andm+1 n+m+1 j n. Furthermore, m +1i j i, implying Aj,m+1−i = Aj−(m−i),m+1−i−(m−i) = Ai+j−m,1 = b Ai+j−m−1,n =b Ai,n+m+1−j,thusEi,j =Fi,j.

(iii) Ifm<inand1 jm,then we haveEi,j =Ai,m+1jandFi,j =b Aj,n+m+1i. The proof follows as in case (ii).

(iv) Ifm<inandm< j n, then we have Ei,j = b Ai,n+m+1−j and Fi,j = b Aj,n+m+1−i. In this casem+1n+m+1inandm+1n+m+1j n.

The proof follows as in case (i).

The last assertion follows by Proposition1. This completes the proof.

3.2 Self-duality criterion whenq=2

In this subsection, and the next one, we work overF2.Given the vectorc=(c1,c2, . . . ,cn) wherec1 = cm = 1,ci = 0,i =1,m, and the first rowa =(a1,a2, . . . ,an)define the

matrixA=

a Tc(a) Tc2(a) . . . Tcn−1(a)

. Whencsatisfies the above conditions,Tcis the companion matrix of the trinomial f(x)=xnxm−11.

Theorem 2 With the above notation, the code C = (I,A)where I is identity matrix of order n is a binary self-dual code if and only if A= I.In other words, a binary DP code with a trinomial induced polyshift is a self-dual code iff it is equivalent to a direct sum of repetition codes of length2.

Proof The codeC = (I,A)is a self-dual code iffA At= −I=IoverF2, whereAtis the transpose ofA. Now we need to proveA At =I iffA=I. On the one hand, letB= A At, B=(Bi,j)n×n,A=(Ai,j)n×n, thenBi,j = n

k=1

Ai,kAj,k. With the definition ofA, we can get thei-th row of Ais

(Ai,1,Ai,2, . . . ,Ai,n)=(0,Ai−1,1,Ai−1,2, . . . ,Ai−1,n−1)+Ai−1,nc

=(0,Ai−1,1,Ai−1,2, . . . ,Ai−1,n−1)+Ai−1,n(1,0, . . . ,0,1,0, . . . ,0),

then

A2i,1+A2i,2+ · · · +A2i,n =A2i1,1+Ai21,2+ · · · +A2i1,n1+A2i1,n+A2i1,n, n

k=1

Ai,k= n k=1

Ai1,k+Ai1,n.

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With the definition ofB, we have B1,1=

n k=1

A21,k= n k=1

A1,k=a1+a2+ · · · +an1+an;

B2,2= n k=1

A22,k= n k=1

A2,k=B1,1+A1,n;

B3,3= n k=1

A23,k= n k=1

A3,k=B2,2+A2,n; . . .

Bn−1,n−1= n k=1

A2n1,k= n k=1

An−1,k=Bn−2,n−2+An−2,n;

Bn,n = n k=1

A2n,k= n k=1

An,k=Bn1,n1+An1,n.

IfB=I,B1,1= B2,2= · · · =Bn,n =1, then we can getA1,n=A2,n = · · · =An−1,n =0.

LetTj be thej-th row of matrixT.Since the vectorc=(c1,c2, . . . ,cn)withc1=cm=1, ci =0,i=1,m, we have

Tj =

en, j =1;

em1+en, j =m;

ej−1, ot herwi se.

where ei,i = 1,2, . . . ,n is the canonical basis of Fn,defined by (ei) = δi j,i,j = 1,2, . . . ,n. Thus, by computations similar to those in the proof of Theorem 1, we have

Ai,j =Tj

Ai−1,1 Ai1,2

. . . Ai−1,n

=

Ai−1,n, j=1; (1)

Ai−1,m−1+Ai−1,n, j=m; (2) Ai−1,j−1, ot herwi se(3) If 1t nm, by(3)we can get

At,n =At−(t−1),n−(t−1)=A1,n−t+1=an−t+1. So for eachm+1j nwe have

aj =Anj+1,n. Ifnm+1tn, by(3)we can get

At,n= At−(n−m),n−(n−m)= At+m−n,m. So for each 1imwe have

Ai,m=An−m+i,n.

By applying(2)and then(3), it follows that for each 1<imwe have Ai,m= Ai1,m1+Ai1,n =A1,mi+1+Ai1,n =ami+1+Ai1,n. Then for 1 j<mwe have

aj =Am−j+1,mAm−j,n =An−j+1,nAm−j,n.

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What’s more,am=A1,m =An−m+1,n.

Because A1,n = A2,n = · · · = An−1,n = 0, soan = an−1 = · · · =a2 = 0; further, B1,1 =1, yieldinga1=1. Then witha=(a1,a2, . . . ,an)=(1,0, . . . ,0), we check from

its definition the matrixA=

1 0 · · · 0 0 0 1 · · · 0 0

· · · · 0 0 · · · 1 0 0 0 · · · 0 1

=I.

On the other hand, ifA=I, it is immediate thatA At=I. 3.3 Even isodual codes

An important class of binary isodual codes is the class of even isodual codes that is those isodual codes all weights of which are even [10,18]. The next result shows that overF2many isodual codes coming from our construction are odd.

Theorem 3 Let A be a polycirculant matrix of size n×n,for a polyshift Tc.Ifcis an even weight vector, then the binary code C= (I,A)is an even code if and only if the first row of A isa=(1,0, . . . ,0).

Proof IfC = (I,A)is an even code, then each row of Ahas an odd weight.

Firstly, suppose the weight ofaisW(a) = 1, namely,a = (a1,a2, . . . ,an)with only am=1. By the definition ofA, we can get the firstnm+1 rows of Aas:

a=(0, . . . ,0,1,0,0,0, . . . ,0,0);

Tc(a)=(0, . . . ,0,0,1,0,0, . . . ,0,0);

Tc2(a)=(0, . . . ,0,0,0,1,0, . . . ,0,0);

. . .

Tcn−m(a)=(0, . . . ,0,0,0,0,0, . . . ,0,1).

Then the(nm+2)-th row is

Tcn−m+1(a)=(0,0, . . . ,0,0)+1·c,

and the weight of this row isW(Tcn−m+1(a))=W(c)0 (mod 2).So in this case, if we expect that the weight of each row ofAis odd, it requiresnm=n1, thenm =1 and a=(1,0, . . . ,0).

More generally, suppose that the weight ofais odd, with rightmost nonzeroaifori=t. If we letW(a) = 2k +1, k 0, anda = (0, . . . ,1,0, . . . ,1,0, . . . ,1,0, . . . ,0)with rightmost nonzeroat =1, reasoning as before, by the definition of A, we can get the first nt+1 rows ofAas:

a=(0, . . . ,1,0, . . . ,1,0, . . . ,1,0,0,0, . . . ,0);

Tc(a)=(0,0, . . . ,1,0, . . . ,1,0, . . . ,1,0,0, . . . ,0);

Tc2(a)=(0,0,0, . . . ,1,0, . . . ,1,0, . . . ,1,0, . . . ,0);

. . .

Tcnt(a)=(0, . . . ,0,0,0,0, . . . ,1,0, . . . ,1,0, . . . ,1).

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