C OMPOSITIO M ATHEMATICA
G EORGE C HOGOSHVILI
On a theorem in the theory of dimensionality
Compositio Mathematica, tome 5 (1938), p. 292-298
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by
George Chogoshvili
Moscow
1. In his note
"Zum allgemeinen Dimensionsproblem" 1)
Professor Alexandroff
proved
thefollowing
theorem:A
compact
set A of the n-dimensional space Rn has a dimen-sionality
r if andonly
if for every e > 0 it is e-removable from anarbitrary (n -r -1 )-dimensional polyhedron.
In this theorem a set A is called e-removable from a set B
(where
A and B are subsets of the same metric spaceR )
whenthere exists an e-transformation
f
of A with theproperty:
f(A) - B == 0.
The main purpose of this note is to
generalize
and to makemore
precise
the above result establishedby
Prof. Alexandroff:THEOREM:
Any
subset Aof
the n-dimensional euclidean space Rn has a dimension r then andonly then,
whenfor
any e > 0 it is e-removablef rom
every(n -r -1 )-dimensional plane. 2)
Remark I. The theorem holds if the word
"plane"
isreplaced by
the word"simplex".
Remark II. An r-dimensional set A is e-removable even from every countable
complex
of thedimension n -
r - 1.Remark III.
3)
If a set A is r-dimensional there is an(n-r)-
dimensional
plane (or simplex), parallel
to a certain(n-r)-
dimensional coordinate
plane
ofRn,
from which A is not ë-re-movable.
Consequently,
any space R is r-dimensional then andonly then,
when itstopological image
in euclidian space of a suffi-ciently large
dimension answers the conditions described. The1) Gôtt. Nachrichten 1928, 37.
2) r-dimensional plane of Rn is an r-dimensional euclidian subspace of Rn.
3) This remark is due to Prof. Pontrjagin.
293
problem
of such ageneralization
of his theorem wasproposed
to me
by
Prof. Alexandroff to whom I wish to express here my best thanks for the kind attention he has shown me.Here we shall dwell for a while on some theorems
concerning
the e-transformations which have been
proved only
as tocompact
or, in the best cases, as to
totally
bounded spaces. This will enable us togive
a more directproof
of our theorem.2. The theorem we start from is the
following:
Any
r-dimensional subset Aof a
metricseparable
space R may be coveredby arbitrarily
small open sets, each r + 2of
which has avacuous
intersection;
their numberbeing finite
in the caseof
thesubset
being totally
bounded and countable4)
in theopposite
case.The
proof
of the theorem in the case when the set is not neces-sarily totally
bounded is the same as when it istotally
bounded5) except
for the number(finite
orinfinite)
of thecovering
setsinvolved.
With every countable
system
of sets 6= {U1, U2, ..., U2, ...}
we
associate,
as in the case of the finitesystem,
a certain countablecomplex N,
which is said to be the nerve of thissystem.
Verticesof N are in
( 1-1 )-correspondence
with the sets of thesystem 6,
and some subset of them form the vertices of a
simplex
then andonly
then when thecorresponding
sets do not have a null inter-section. The nerve N is realized in the
field of
verticesE,
if allthe vertices
belong
to this field. N is realized in 6 or near6,
if all the elements of 6
belong
to the same spaceR,
and eachvertex of N is a
point
of itscorresponding
element or of a definiteneighborhood
of that element.6)
If R =
Rn,
then N may be considered as ageometrical complex.
If n is
sufficiently great
and the vertices of N are in ageneral position
then the interiors of thesimplexes
of N do not intersecteach other.
Such a realization of a nerve, which is
always possible
inR2’’+1,
when 6 has an orderequal
to r, i.e. if dim N = r, is calledan euclidian realization of the nerve N of @).
Having
anarbitrarily
small finite or countablecovering
ofthe order r of an r-dimensional space
R,
and the realization of4) but locally finite, i.e. any element can intersect only a finite number of other elements of the covering.
5) See K. MENGER’S Dimensionstheorie [1928], 158.
6) P. ALEXANDROFF & H. HOPF: Topologie 1 [1935], Neuntes Kapitel, § 3.
the nerve of this
covering,
we can, as in the finite case, constructa
single-valued
continuous transformation of the space R inN;
especially
we canapply
the so-called Kuratowski-transformationX(p)
which in the euclidian casegives:
here
hi
is the vertex of Ncorresponding
to the elementUi
i of@,
and[bi o ... bi h ]
is the interior of thesimplex bi 0 ... bi h
C N.It follows that if a
system
6 is ane-covering
of a spaceR,
thenX(p)
is ane-mapping
of R onN,
i.e. on an r-dimensionalcomplex.
If
f
is asingle-valued
continuous transformation of a space R inRn, then,
as in the case when R iscompact
weget
thatfor a
sufficiently
smallcovering
of R and for a suitable realization of the nerve of thiscovering
inRn, X ( p ) represents
ane-approxi-
mation of the
given transformation f:
Supposing
that A C Rn andf
is an identicaltransformation,
we
get an 2
-deformation of the set A into thepolyhedron N,
i.e. into an r-dimensional
complex.
On the other hand it may beshown, using
our chieftheorem7) (from
which the above isindependent),
thatby
anarbitrarily
small deformation of anr-dimensional set A it is
impossible
to transform A into a set ofa dimension less than r. In fact it would be
possible
otherwiseto remove A
by
anarbitrarily
small deformation of it from every(n-r)-dimensional plane,
but that contradicts theassumption
that A is of the dimension r.
Thus we
get
thefollowing theorem,
the firstpart
of which will be wanted later:An r-dimensional set A
of
the space Rn ise-deformable
into anr-dimensional
polyhedron ( finite
or countableaccording
as the setA is bounded or
not),
but not into apolyhedron (not
into anyset) of a
lower dimension.3. We shall
require
further thefollowing
LEMMA:
If a
set A does not intersect thesimplex
S(A,
S CRn)
it is
possible
toget
apositive
distance between the set A and thesimplex
Sby
anarbitrarily
smalldeformation of
the set A.7) Prof. Ephrâmowitsch has been so kind as to indicate to me this consequence of our theorem.
295
Furthermore,
at the endof §
4 it will be shownthat,
if a set A is removableby
anarbitrarily
small deformation from eachsimplex
of agiven
finitecomplex K,
then apositive
distancebetween the
polyhedron
and the set A may be establishedby
an
arbitrarily
small deformation of the latter.Proof of
the lemma:given
8 > 0 let us choose such a numberd,
that: 0 d e and consider the set Fconsisting
of allpoints
whose distance from S is less than or
equal
to d.Especially,
letT C F be the set of those
points
whose distance from S isequal
to d. Let us connect
by segments
eachpoint
of S with all thepoints
of the set T which are at the distance d from thispoint.
We shall call the
points
of thesesegments
whichbelong
to thesimplex S, s-points
and those whichbelong
toT, t-points.
It isnot difficult to show that the set of all these
segments
fills thewhole set F - S. No one of these
segments
intersects any other at apoint
which does notbelong
to S.Suppose
thecontrary:
let the
segments
P andQ
intersect in thepoint
o,o G
S.Denoting
the
s-points
of thesegments
P andQ by
s p andsQ
and thet-points by t p and tQ respectively,
we have:Bp =F BQ (for,
other-wise,
P andQ
would coincide with eachother)
andtp --A t. (as,
otherwise,
thepoint t p
=tQ being equally
distant from the twopoints s p, sQ
of S would be less distant from S than from thesepoints,
which isimpossible). Suppose
thatthen
for, otherwise,
thelength
of P would be less than that ofQ.
Therefore we have:
But that is
impossible.
Theimpossibility
of theinequality
isevident;
but noequality
can existeither, since,
asalready
men-tioned
above,
apoint
which is at distance d from asimplex
cannot be at this distance from two different
points
of thesimplex.
Thus,
thesegments
do not intersect one another. Let us shift eachpoint
of the setA (F -5)
with uniformvelocity
in unittime
along
thesegment
on which it lies to thet-point
of thissegment.
We obtain in this way asingle-valued
continuous8) If o(tQ, o) p(p, o), then, in the following argument P and Q must replace
each other.
transformation
f
of A(F - S)
intoRn - U ( S, d ) ;
we definemoreover
f
as the identical transformation in allpoints
ofA [Rn - U(S, d)].
Thenf
is a continuous s-transformation of A all over andf(A)
has apositive
distance fromS, q.e.d.
4. We
get
now the firstpart
of our theorem direct from what has been saidin §
2:by
anarbitrarily
small deformation of the setA,
we transform it into an r-dimensionalcomplex and, by arbitrarily
small shifts of the vertices of the latter removeit from any
(n -r --1 )-dimensional
finite or even countablepolyhedron,
inparticular
from any Rn-r-1 CRn, and,
moreoverfrom any
(n -r - -1 )-dimensional
element.In order to prove the second
part,
let us prove first of all thatby sufficiently
small deformation of thegiven
bounded setA of dimension r it is
impossible
to remove it from a certain(n -r )-dimensional
finitepolyhedron.
From herenaturally
followsan
analoguous
statement as to an unbounded set. Let 8 > 0 be so small that at a finitee-covering
of the set Aby
sets closedin it there should be at least one
point belonging
to r + 1 elementsof the
covering.
Let us,following Lebesgue 9), decompose
thespace Rn in cubes with the
side n -
3nso that thepoints belonging
to, at
least,
s,1 s n + 1,
cubes lie on(n-s+l)-dimen-
sional sides of these cubes.
Let
Ql, Q,,
...,Q
t be all the cubes of thepolyhedral neigh-
borhood of that
polyhedron 10)
of thisdecomposition
whose cubes intersect the set A.Let us dénote
by
K the(n-r)-dimensional polyhedron
formedby
all(n-r)-dimensional
sides of these cubes. It is clear thatSuppose
thatby 1’j-deformation
of the set A which transforms A intoA’,
it ispossible
to remove A from K. SetsQiA’,
1ç i Ç t,
closed in
A’, form e -covering
of the set A’ of the order r at most. Let the setsAi
be theoriginals (,,Urbild")
of the setsQiA’
of the deformation inquestion.
Asoriginals
of sets closed inA’ the sets
A i
are closed inA ;
theiraggregate
coversA ;
their9) Fund. Math. 2 (1921), 256-285.
10) i.e. the aggregate of all the cubes of the decomposition in question inter- secting that polyhedron.
297
diameters are less
than e,
and each r + 1 of them has a nullset in its
intersection;
but all this contradicts the choice of the number e.It remains to prove the
impossibility
ofremoving
thegiven
set from a certain
(n-r)-dimensional simplex and,
thereforefrom the
(n-r)-dimensional plane
which is determinedby
thissimplex.
Suppose
that it ispossible:
A may bee-removed, by arbitrarily
small e > 0, from every
(n-r)-dimensional simplex.
Let us haveany
(n-r)-dimensional polyhedron
and any
positive
number e. Let us choose el, so that 0 ele/k
and
by
an81-deformation f 1
of A establish apositive
distancebetween
f1(A)
=Al
andSl:
This is
possible
in virtue of the aboveassumption
and the lemmaof §
3 from whichevidently
follows: ifby
anarbitrarily
smalldeformation of a set A it is
possible
to remove the latter from asimplex S,
then it ispossible
to establish apositive
distancebetween A and S
by
anarbitrarily
small deformation of A . Letbe
already
constructed.Let us
ehoose ej
so thatand, by
anej-deformation fi
of the setAj-1,
sayf;(A;-i)
=Aj,
establish a
positive
distance betweenAi
andSj:
We shall
get
for
when i
= t we hadand with the
following i - t
deformations all theshifts,
in virtue of theproperties
of e,, r = t + 1,..., i,
were lessthan k-t.
dt
Let us
perform
the same constructionfor i
= 1, 2 , ..., kand consider the
mapping
, f * being
the result of ksuccessive -î--deformations
of A is an £-deformation of this set. A * does not intersect the
polyhedron K,
moreover,
they
are at apositive
distance from eachother,
sinceand
The contradiction of the fact
just
established with our former statement proves our theoremcompletely.
The above considera- tions prove also thegeneralizations
of the lemma mentionedin §
3.Remarks 1 and II are
already proved.
It is obvious that remark III holds too. Infact,
inLebesgue’s decomposition
of Rn every(n -r )-dimensional
side isparallel
to a certain(n -r )-dimensional
coordinate
plane; but,
on the otherhand,
it wasproved already
that the set A cannot be removed
by
anarbitrarily
small defor- mation from one of these sides.(Received, February 10th, 1937.)
k-k
determ . ed
11 ) The expression e(Ak, St)
> - dt,
for t = k, is not undetermined, as, k-1 taccording to the definition of fl.: