C OMPOSITIO M ATHEMATICA
A. M. O STROWSKI
Three theorems on products of power series
Compositio Mathematica, tome 14 (1959-1960), p. 41-49
<http://www.numdam.org/item?id=CM_1959-1960__14__41_0>
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Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
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by
A. M. Ostrowski
1)
1. All numbers considered in the
following
are real.By
awell-known theorem of
Cauchy,
from the relationsfollows
More
generally
we haveThis can be
interpreted
in thefollowing
way. Putand
then we have
We are first
going
to prove that this result remains true if the séries1 1-z
isreplaced by
1) The preparation of this paper was sponsored in part by the Office of Naval Research.
42
provided
that we haveWe then obtain the
following
theorem which appears to bequite
useful
although
very easy to prove.2. THEOREM 1. Consider the power series
(1)
and(3)
withposi-
tive
S)1’ T"
and assume thatand
(4)
holds.I f
me thenput
zve have the relation
(2).
3. We prove first the
LEMMA. Undef the
hypothesis of
the theorem 1 we havefor
anyfixed integer
mPROOF. We have
by (4)
for any fixed k > 0and therefore
It is therefore sufficient to prove that for
m ~
0Choose an
integer
k > m, then we haveby (8)
and our assertion follows from
(5).
4. PROOF OF THE THEOREM 1. It is sufficient to prove the
right
hand
inequality
in(2),
since we canreplace .9, by
-s"; thus wehave to prove
We can assume that the
right
hand side of(9)
is oo. But then(9)
follows at once if we prove:Il for
a constant c and aninteger
m we havethen we have also
To prove
(11)
under the condition(10), put
and consider
But
by
our Lemma each of them+ 1
termsTn-03BC D n
on theright
tends to 0 and
(11)
follows.5. If one of the conditions
(4)
or(5)
of the theorem 1 is not satisfied sometimes thefollowing corollary
can be used.COROLLARY 1. The relation
(2) of
the theorem 1 remains trueif
the conditions
(4)
and(5)
arereplaced by
To prove this choose a
positive
y such thatand
put
Then in
multiplying (13) by y
we obtain from(14)
44
00
But then it follows that the radius of convergence
of 1 S’vzv
is 1and
therefore Y S’v
= oo. The theorem 1 can beapplied
to theséquences (l’4)
and weobtain, putting
from
again (2).
6. If we take in the theorem 1,
Sv =1,
then our result containsa
,,suminability"
statement; thecorresponding
transformation is then inHardy’s terminology 2 )
aregular
andpositive tran,9/orma-
tion
(Hardy
p.52).
If the theorem 1 isapplied
twicestarting
withSv
~ 1 we obtain an "inclusion theorem"(Hardy
p.66)
with astatement
more special
and moregeneral
than thatgiven by Hardy (Hardy
p. 67, Theorem19),
since this inclusion theorem does not assume the convergence of theS"
but refers to the moregeneral
situation(2).
7. We obtain another
corollary
from theorem 1 if weput
thereSv =
Sv+1.
Then we haveBut
hère
we haveby
the lemma of No.3, v+1 Rv ~
0( v
-~),
therefore
and obtain from
(2)
theCOROLLARY 2. Consider the power series
1) G. H. Hardy, Divergent Series, Oxford (1949).
and assume that
Sv
andTv
arepositive
and the relations(4)
and(5)
hold. Then we have
8. If we
drop
now theassumption (5)
we can still prove a result in the direction of theCorollary
2though considerably
weaker.THEOREM 2. Consider two power series with
positive coefficients
and assume that we have
then
putting
zve have
9. PROOF. Assume a
arbitrary
with 0 e1;
then there exists anno = no ( e )
such that for v>
noFor an
integer
m > no and for n >m+n0
we useApply
theright
handinequalities
of(22)
and(23)
in the first resp.the second
parenthesis;
then we havewhich
gives
Applying
the left hand sides ofinequalities (22)
and(23)
in thesame way, we
get
46
Take an
arbitrarily great
but fixedinteger
K and assume 8and m such that
.Then for any n >
m+K+n0
we havehence from
(24)
and
(21)
isproved.
10. We
.give finally
a third theorem onproducts
of power series which followseasily
from the theorem 1.THEOREM 3. Consider the
four
seriesput
and assume that
S,
andT,
arepositive
andAssume
further
that we have as v ~ oowith
finite
oc and03B2.
Then we have11. PROOF.
Since rv Rv
ishomogeneous
both in s,,S,
and int",
T,
of dimension 0, each of the constants a,03B2,
which is=1=
0, canbe assumed as 1. We have therefore
only
three cases to considera) 03B1 = 03B2 = 1; b) 03B1 = 1, 03B2 = 0; c) 03B1 = 03B2 = 0.
(The
caseb’ )
a =0, j8
= 1 isby symmetry equivalent
to thecase
b)).
Consider first the case
a).
In
applying
then the theorem 1 we haveOn the other hand it follows from
(28)
thatWe can
therefore, assuming
thatall s,
are >0, apply
the theorem 1 inreplacing
there99(z) by y(z), O(z) by 03A8(z)
andY(z) by ~(z).
Weobtain then
In
multiplying (31)
and(32)
we obtainrn ~ 1, n
that is(29),
proved
now in the case(30)
underthe
additionalassumption
that alls,, are > 0.
12. It is now easy to prove the case
a)
zvithout theassumption
that
all s,
arepositive.
Indeed we can find in any case apositive
number
A,
such that under theassumption (30)
the sumsSv Sv+ASv 1+A
arepositive
for all v = 0, 1, .... But then wehave,.
since
s’v ~ 1,
Sy
48
Here the second term on the left tends to A
by
the theorem 1(applied
ininterchanging
theS,
and theTv)
and we obtainagain rn
~ 1. The casea)
is nowcompletely proved.
R.
SI,t,
13.
Assume now the caseb),
thatis s’’ ~1, tv Tv ~
0. If we thenput t’ IV
=tv+Tv
wehave tv Tv ~
1 and it followsby
the firstpart
ofour
theorem, already
proven,Here the second term on the left tends to 1
by
the theorem 1 andwe obtain rn - 0
(n
-~).
Thus our theorem isproved
in theRn
case
b).
The case
c) sv Sv ~
0,tv Tv ~
0is
reduced to the caseb) by exactly
the same
argument.
The theorem 3 isproved.
14. If we take in the theorem 3 e.g.
we obtain
It follows
therefore,
that if we havethen
This is the theorem 41 in
Hardy (l.c.
p.98).
15. The above results are
probably
valid under much moregeneral
conditions. Here we have gone into themonly
as far asthey
arosenaturally
in the course of otherinvestigations.
(Oblatum 3-3-58).
Numerical Analysis Rèsearch, University of California in Los Angeles, U.S.A.
and
Mathematische Anstalt der Universitât Basel, Switzerland.