R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
G. N AVARRO
A note on the converse of the Clifford’s theorem and some consequences
Rendiconti del Seminario Matematico della Università di Padova, tome 77 (1987), p. 189-191
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A Note
onthe Converse of the Clifford’s Theorem and Some Consequences.
G. NAVARRO
(*)
Throughout
this paper « group » means « finite group ». All char- acters considered are C-characters. We use the standard notation from the books of B.Huppert [1]
and I. M. Isaacs[2].
It is well known that the class of
p-decomposable
groups, where p is aprime,
is a saturatedFitting
formation. The purpose of this paper is to prove thefollowing
THEOREM A. Let G be a group. Let P be a
Sylow p-subgroup of
G.Then G = P X .K’
if
andonly if
b’8 EIrrc (G) op
= nx, where v EIrrc (P)
and n is some
integer.
Before
proving
TheoremA,
we show that the converse of the Clifford’s Theorem is true.Exactly,
wegive
thefollowing
resultTHEOREM B. Let G be a group and
N G
such that d’8 EIrrc (G) ON
= + ...+
where gj ENG(N),
X EIrrc (N)
and n is someinteger.
T hen Na G.PROOF OF THEOREM B. Let
IN
be theprincipal
character of N.If x E
G,
then(*)
Indirizzo dell’A. :Departamento
deAlgebra
y Fundamentos, Facultad de Ciencias Matematicas,C/Coctor
Moliners/n. Burjasot (Valencia),
ySpain.
190
If X
is an irreducible character ofG,
thenBy
Frobeniusreciprocity:
Suppose
that there is aninteger s satisfying
Then n"
=IN, Vi,
and so, weget
In
particular:
Then
Inducing
on both sides:the last
equality gives
us~G~
==Hence, x belongs
to allconjugates
of N.Consequently,
191
PROOF OF THEOREM A:
By
TheoremB,
P«G. It isenough
tosee that G is
p-nilpotent.
We use induction on~G~
and we can assumethat If N is a normal
subgroup
ofG,
it is not difficult to seethat
G/N
satisfies the inductionhypothesis.
Assume that there exists 0 E
Irrc (G)
such that ker 0 = 1.By hypothesis, 0, = nX,
X EIrrc (P).
Since
P > 1,
it follows thatZ(P)
> 1. Let x EZ(P) .
X is irreducible andfaithful,
then= x(1 ). Thus,
which
implies
that x EZ(G).
Then, Z(G)
> 1 andGfZ(G)
isp-nilpotent.
From this it follows that there exits
M G p-nilpotent
such thatG =
MZ(G).
Butthen,
MaG and G isp-nilpotent.
So,
we can suppose thatker 0>1,
V0 EIrrc (G).
Now, by
the inductionhypothesis G/ker
0 isp-nilpotent.
Hence,
G ~G/ n
ker0 isp-nilpotent.
6EIrra(G)
Clearly,
the converse holds.REFERENCES
[1] B. HUPPERT, Endliche
Gruppen
I,Springer-Verlag,
1967.[2] I. MARTIN ISAACS, Character
Theory of
FiniteGroups,
Academic Press,1976.
Manoscritto