Comparing orders of Selmer groups
par SÉBASTIEN BOSCA
RÉSUMÉ. En utilisant la théorie du corps de classes et la théorie de
Kummer,
nous calculons l’ordre de deux groupes de Selmer, etnous les comparons: le quotient des deux ordres ne
dépend
que de conditions locales.ABSTRACT.
Using
both class field and Kummer theories, we pro- pose calculations of orders of two Selmer groups, and compare them: the quotient of the ordersonly depends
on local criteria.Notations
- K is a number field.
-
EK
is the unit group of K.- ILK,n is the set of
nth
roots ofunity
in K.-
Pl(K)
is the set ofplaces
of K.- ri is the number of real
places
of K.- r2 is the number of
complex places
of K.-
(~)
theprincipal
fractionnal idealgenberated by
x, with x E KX.-
IK
is the group of fractionnal ideals of K.-
IK
CIK
is thesubgroup
of fractionnal ideals of Kprime
to someset S of
prime
ideals(to
be namedafter).
-
PK
CIK
is the group ofprincipal
fractionnal ideals of K.- C
PK
is the group ofprincipal
fractionnal ideals of Kprime
toS.
-
CIK
= is the class group of K.-
.K"~
C KX is thesubgroup
of elementsprime
to S.-
~K
is the idele group of K.-
Uv
CKv
is thesubgroup
of v-units for agiven
finiteplace v
of K.When v is an infinite
place
ofK,
our convention is to noteUv
for thewhole group
Kv .
- ev is the ramification index of v in
F/K
for agiven
finiteplace v
ofK. When v is an infinite
place
ofK,
our convention is: ev = 1 when vtotally splits
at v and ev = 2 in the other case; with thisconvention,
we see v as a ramified
place
if ev = 2.-
K
=1 Kv TI Uv is the subgroup of "units" of VIOC vtoo
- 9n c
ùK
is an opensubgroup
of the unit idele group ofK;
moreprecisely,
9J1 =Il 9Xv
is aproduct
of opensubgroups
of the multi-v
plicative
groupsKvx,
and9nv
=Uv
if v is a finiteplace
which is notin S.
- C
PK
is thesubgroup
ofprincipal
idealsgenerated by
an element~ of K" whose
image
inJ K
is in9nv
for all v in S ordividing
theinfinite
place
ofQ.
- N =
NF;K
is the norm map.Finally,
for agiven
finite abelian group G and agiven integer
n, we noteand
and
G(n)
arerespectively
the maximalsubgroup
andquotient
of Gwith n as an
exponant. They
have the same order.Introduction
For a
given cyclic
extension of number fieldsF/K
withdegree
n, toanswer a
question by
Henri Cohen(asked
in theparticular
case F =K(i)),
we propose to calculate the orders of
and
In
fact,
calculations of the orders of these groups are not very usefull because we cannot express themonly
with local criteria(however
we expressthem with
only
classicalthings manipulated
in class fieldtheory).
But thepoint
is that thequotient
of these two ordersonly depends
on localcriteria,
and that was
enough
to solve theproblem
of H. Cohen.So,
the main resultis the
following:
Theorem.
I f F/K is
acyclic
extensionof
numberfields
withdegree
n, onehas:
Two ways are
given
to prove this result: the first one uses class fieldtheory
andinterpretations
of some groups as Galois groups or Kummer radicals of someextensions;
the second one is faster andonly
uses theambigous
classes formula fromChevalley;
it wasproposed by Georges Gras,
who referred the first version of this article. I thank him for his work.
So,
the second way is more
acheived,
while the first one shows more how to find the result. Note also that in section 1(the
firstway),
we suppose that K contains allnth
roots ofunity,
while in section 2(the
secondway),
thishypothesis
isuseless;
that’s apity,
but thequestion
wasinitially
asked forn = 2
(see [1]),
and all number fields contains 1 and-1;
moreover, the calculus made in section 1 can beadapted
when K doesn’t contain allnth
roots of
unity, replacing
withK[lLn]
andthings
likethis,
but that seemcomplications
fornothing
since the second way prove the result in all cases.An interested reader may examine that.
1.
Using
Class Fieldtheory
1.1. Calculation of the order of
S(F/K)
as a Galois group.Here,
we seeS(F/K)
as a ray class group,according
to class fieldtheory.
One has a natural map
whose kernel is
- 1 T I T V
To
study
Im~,
let’snote,
for eachplace
v of K withww
inNv
=N(Fw ),
andwe also note S the set of ramified
places
in the extensionF/K.
The Hasseprinciple applied
in thecyclic
extensionF/K,
leads toso that
On the other
hand,
K X n 9Rdenoting
the group of elements of K" whoseimage
in1K
is in9R,
one has the exact sequenceso that
Using
the facts thatIS(FIK)I = IKer 1>1
and that1.2. Calculation of the order of
S(F/K)
as a radical.In subsections 1.2 and 1.3 we suppose = n.
S(F/K)
is asubgroup
of so that it is the radical of someKummer extension L of
K,
withexponant
n. We shouldstudy
the localnorm group to calculate the
degree
ofLIK.
Let x e
according
to the Hasseprinciple,
x ES(F/K)
if andonly
if:- is for each
prime S1J;
For any
prime
idealS1J,
we note 17~ theunique
element of such that is theunique
non ramified extension ofKçp
withdegree
n.The first condition about the elements of the radical of
L/K
isequivalent
to the fact that ~1~
(use
thesymetry
of the localnth
Hilbertsymbol
to see this: for a local Kummer extension withexponant n
Rad(Lw /Kv)
C X ~ > = 1 ~X1-).
The last condition is
equivalent
to the fact that containsboth 17v
and xo for each v in S.
Finally,
L is then definedby
the fact thatwhere
Note that C
ùK. So,
one has:the last
equality coming
from = is a well known Galois group with ray 9R*.1.3. Calculation of the order of
G(F/K).
One has:
note now that
Im
= for M = F and lVl =K,
so thatOn the other
hand,
the Hasseprinciple
leads toso that
We now
interprete
this formula: atfirst,
is, according
to class fieldtheory,
the Galois group of the maximal abelian extension of K which is not more ramified than F(note
also that isequal
to 9R defined in subsection1.1).
Call T this extension. Afterthis,
is just
=Gal(T’IK),
where T’ C T is the maximal subexten- sion with exponant n.So,
is thesubgroup
ofwhose elements are norms from
J F (since 3~
CBut the
subgroup
of norms from F on the idele sidecorresponds
with thesubgroup
obtainedby
restriction from F on the Galoisside,
so thatr.-.., r -1
The subsections 1.1 and 1.3 prove the theorem.
2.
Using Ambigous
classes formulaOne has the
following
4 short exact sequences, for anycyclic
extensionF/K
withdegree
n and a as agenerator
ofGal(F/K) (j
denotes naturalmaps):
So,
one hasand
so that
Remember now the well known
ambigous
classes formula fromChevalley (see [2]):
for anycyclic
extension withdegree
n, one has:Then,
it comesas wished.
References
[1] HENRI COHEN, FRANCISCO DIAZ Y DIAZ, MICHEL OLIVIER, Counting Cyclic Quartic Exten-
sions of a Number Field. Journal de Théorie des Nombres de Bordeaux 17 (2005), 475-510.
[2] GEORGES GRAS, Class Field Theory, from theory to practice. Springer Monographs in Math- ematics, second edition 2005.
Sébastien BoscA Université de Bordeaux I Laboratoire A2X 351, cours de la libération 33405 TALENCE Cedex, France
E-mail: Sebastien.Bosca@math.u-bordeauxl.ir