R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
C ARLO T OFFALORI
On some model theoretic problems concerning certain extensions of abelian groups by
groups of finite exponent
Rendiconti del Seminario Matematico della Università di Padova, tome 103 (2000), p. 113-131
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Concerning Certain Extensions of Abelian Groups by Groups of Finite Exponent.
CARLO
TOFFALORI (*)
1. Introduction.
For every group
G,
let denote the class ofgroups admitting
anormal abelian
subgroup
A such that thequotient
,S/A iselementarily equivalent
toG ,
S/A = G . For Gabelian,
letXe (G)
denote the class of abelian groups in~,( G ).
The aim of this note is to
investigate and, possibly, Xe (G)
forsome
given
G . Of course, one may wonder which is the interest of thisanalysis.
As we will seejust
a few linesbelow,
theoriginating question
was the first order
axiomatizability
of in thelanguage
for groups.But it is worth
emphasizing
that(and
soXab(G))
do admit somenatural
algebraic characterization,
notonly
because theelementary equivalence
between twogiven
structures can begenerally
translated inalgebraic
termsby using ultraproducts (and
the Keisler-Shelah Theo-rem)
or, for finitelanguages, partial isomorphisms (and
the Fraisse The-orem),
but also because we will see laterthat,
at least for some suitableG , ~,( G )
can be introduced in agenuine
group theoretic way.The
starting
line of the matter was the case «G finite». Here the ax-iomatizability problem
seems solved in apositive
way[02]: for,
in thiscase,
X( G)
isjust
the class ofabelian-by-G
groups,namely
the class of the groups ,Sadmitting
a normal abeliansubgroup
A such that S/A is iso-morphic
to G(« = G»
means « = G» under the finitenessassumption);
and the latter class is
elementary,
and evenfinitely
axiomatizable. No- ticethat,
for Gfinite,
theanalysis
benefitsby (at least)
twosignificant
(*) Indirizzo dell’A.:
Dipartimento
di Matematica e Fisica, Universita di Ca- merino, Via Madonna delle Carceri, 62032 Camerino(Italy).
advantages.
The former is that any group inX( G)
is stableand,
accord-ingly, enjoys
some usefulalgebraic properties,
like chainconditions,
de-finability
ofcentralizers,
and so on. The latteradvantage
is related to the former one:for,
A has a natural structure ofZ[ G ]-module
and mostmodel
theory (including stability)
of S -as a group- reduces to A -as amodule-.
Now assume G infinite. As we will see
below,
both theprevious
ad-vantages
fail. Nevertheless somepartial
results were obtained in[MaT]
and
[T].
Inparticular
(a)
if G is abelian of boundedexponent,
thenXe (G)
iselementary (but
needsinfinitely
many sentences to be axiomatized in the first orderlanguage
ofgroups);
(b)
if G is abelian ofprime exponent,
then~,( G )
iselementary [T]
(by
the way, there is aslight inaccuracy
in the final Lemma in[T];
seeLemma 3.2 below for a
sharp
statement andproof);
(c)
if G is abelian of unboundedexponent, then,
in most cases,Xab(G) and, consequently,
are notelementary.
With
respect
to first orderaxiomatizability,
let us also recallthat,
forevery group
G ,
-and for G abelian- arealways
closed underultraproducts;
so, in order to testelementarity,
we have to check that~(G),
or are closed underhence that,
if S EX(G),
then every model of thetheory
of S is inK(G),
too.Moreover, by
a L6wenheim-Skolem
argument,
we can assume S countable. Infact, given 8 E X( G)
and a
corresponding
normal abeliansubgroup
A with81A = G ,
a count-able model
(So, Ao)
of thetheory
of(S, A )
still satisfies andS0/A0 = G.
Another useful remark is
that, owing
to theOger
resultquoted
be-fore
[02],
the groups S which are notabelian-by-finite
are anelementary
class
(just
list finite groups G and state that S is notabelian-by-G
forevery
G).
The main purpose of this note is to deal with when G is
infinite,
of finite
exponent (and possibly nonabelian).
We aim to find somesignifi-
cant and direct group theoretic
characterizations,
and to discuss first or-der
axiomatizability.
Moreprecisely,
ourproject
is to consider G ==
C(~)~~~~ EÐ H
where H is a finite group and the order of H isprime to p (hereafter,
for everypositive integer
m,C(m)
is themultiplicative cyclic
group of order
m);
notice that this extends the casequoted
in(b)
and in- tersects(c).
Let us summarize here the
plan
of the paper.In § 2,
wegive
some al-gebraic
characterizations of thegroups S
EX( G), featuring
the derivedsubgroups
S’ and thesubgroup
Srgenerated by
the r-th powers in S(r
apositive integer); by
the way, recall that both S ’ and S r arefully
invari-ant
subgroups
of ,S .Consequently in §
3 we discuss thedefinability
of S ’and this
overlaps
thestability question
for groups in~,( G );
we willsee
that,
even in the easiest case H= 1,
there do exist unstable groups in~,( G ).
In the finalsections,
westudy elementarity
in the«simplest»
non-trivial case for
H, namely
when H is asimple
group. Inparticular,
in §4,
we deal with first order
axiomatizability
when H issimple
and non-abelian.
In §
5 we obtain a fullpositive
result when H issimple
abelianand is not
abelian; finally
we discuss the case when both H andare abelian
(and
the order of H issquarefree);
wegive
a morepregnant
group theoretic characterization and we prove first order ax-iomatizability
at least for nil-2 groups S.We refer to
[H]
for modeltheory
and to[R]
for grouptheory.
L is thefirst order
language
for groups.Among groups, ~
will denote the rela- tion «to be asubgroup»,
and will mean «to be a propersubgroup».
Wegratefully acknowledge helpful suggestions
from Prof. GuidoZappa
andProf. Andreas Baudisch.
2.
Algebraic
characterizations.Let G =
Qi H where p
is aprime
and H is a finite group whoseorder q
isprime to p .
We arelooking
for a group theoretic characteriza- tion of~,( G ).
Notice that H is definable in G as thesubgroup
of the ele- ments whoseperiod
divides q . A(comparatively easy) algebraic
defini-tion of is
obviously provided by
the fact that the first ordertheory
of G is
totally categorical:
up toisomorphism,
its models arejust
those ofthe form
C(~)~°‘~
® H where a is an infinite cardinal.Accordingly,
« * G»means « =
c(p ia)
® H» for some infinite a . But now we wish to propose anotheralgebraic characterization,
which involves a sort of in- termediate group, and which will be useful later.THEOREM 2.1. Let G =
EÐ H where p
is aprime, H
is a finitegroup and the
order q
of H isprime
to p . Then a group S is in~,( G )
if andonly
if ,S satisfies thefollowing assumptions:
(i)
has infinite index inS;
(ii)
S ’ S p has an abeliansubgroup
N such that N is normal in,S ,
and every element s E S whoseperiod
modulo N divides p commutes with both commutators andp-th
powers modulo N.PROOF. First assume S E
~,( G ).
Then there is a normal abelian sub- group A of S such that,S~A
=C(~)~a~
Qi H for some infinite cardinal a .Choose
bo , ... , br
in ,S - A such thatbo A ,
... ,brA generate
the copy of H inS/A
withrespect
to some fixedpresentation.
PutSince A is normal in
,S,
every element in B can beexpressed
as ab wherea E A and b is a word on
bo ,
... ,br .
We claim that B is normal in ,S . Infact,
leta E A ,
b be a word onbo ,
... ,br ;
notice thatOwing
to the structure of
,S ,
there exista ’ E A ,
a word b ’ onbo ,
... ,br and r z S
such that xA is in the copy of
C(p)(a)
inS/A (hence
andAs and A is
normal,
henceconsequently
Notice that b ’ and x commute with each other modulo A and b ’q E A .Accordingly xq E A.
But wehence,
asp
and q
arecoprime,
we can deduce xE A ,
and(ab)S
E B .Clearly
A is anormal
subgroup
of B and thequotient
group B/A isisomorphic
to H.Moreover
Consequently,
for everys E S,
So S P is a normal
subgroup
of B .Furthermore,
asS/B
isabelian,
,S ’ is in-cluded in
B ,
and hence is a(normal) subgroup
of B . Inparticular
the index of is
infinite, namely (i)
holds. Now consider A n We knowwhere the latter
quotient
is asubgroup
of B/A = H .Suppose
Then
I
divides ,and this is
prime
to p. On the otherside,
every element in B has aperiod dividing p
modulo So weget
a contradiction.Consequently
and
Put abelian because N is a
subgroup
ofA ;
N is nor-mal because both and A are. We have
just
seen that = H .Finally
let SESsatisfy
hence s p E A and theperiod
of sA in ,S/Adivides p .
Accordingly
sA commutes with any element inB/A,
inparticu-
lar with any element tA in for all
[ s ,
But[ s , t ]
hence[ s , t ]
E N . So(ii)
holds.Conversely,
suppose that S satisfies both(i)
and(ii).
Then N is a nor- malsubgroup
of ,S and thequotient S/N
is an extension of = Hby
SIS’S P. is abelian(because S ’ ~ ,S ’ ,S ~ ),
infinite(owing
to(i)),
of
exponent p (because
hence is an infinite elemen-tary
abelian p-group. As the order q of H isprime to p ,
we canapply
aSchur-Zassenhaus
argument
to deduce thatS/N
is a semidirectproduct
of for some infinite a.
Accordingly
put
for a suitable K. In order to show that
actually S/N
is a directproduct
ofand
K/N (and
hence to finish theproof),
we have to prove that actsidentically
on But any element s has aperiod
di-viding p
modulo N and so,by (ii),
commutes modulo N with all the ele- ments of This isjust
what we need to show.When H
(hence G)
isabelian,
we can obtain thefollowing,
more di-rect characterization.
COROLLARY 2.2. Let G be as in Theorem
2.1,
H be abelian. Then agroup S is in
X( G)
if andonly
if S satisfies(i)
S’S P has infinite index inS ;
(ii)’
there is an abeliansubgroup
N of such that N contains S’ andPROOF. It suffices to show
that,
for H(and G) abelian, (ii)’
isequiva-
lent to
(ii)
in Theorem 2.1. First assume(ii).
Four 8 EX( G), SIA
G isabelian;
hence S ’ is asubgroup
ofA ,
andconsequently
So
(ii)’
holds.Conversely,
assume(ii) ".
As 8’ ~N,
N is normal in,S ;
thesame reason proves 81N
abelian; consequently
the final condition in(ii)
istrivially
satisfied. 0Let
X’ (G), ~t," ( G ) respectively
denote the classes of groupssatisfy- ing (i), (ii) (or (ii)’). Clearly,
if both~,’ ( G )
and~," ( G )
areelementary,
then
X( G)
is. Thefollowing
sections will be devoted todiscussing (sepa- ratedly or jointly)
first orderaxiomatizability
forK’(G)
andK"(G). But,
before
concluding
thissection,
let us underlinethat,
for H abelian and S e~t,( G ), S ’ ~ A ,
hence ,S ’ is abelian. In otherwords,
any group 8 EE
X( G)
is solvable of class 2.3.
Definability
andstability.
The reference to S’ and Sp for G =
EÐ H
in Theorem 2.1 and thenecessity
oftranslating (i), (ii)
or(ii)’
in a first order waysuggest
toexplore
if thesesubgroups
-S ’ and SP- are definable in oursetting.
It is known that a
preliminary assumption ensuring
some more defin-ability
isstability. By
the way, recallthat,
for Gfinite,
anygroup S
EE
~f,( G )
isstable,
because most modeltheory
of 8 reduces toA ,
viewed as aZ[ G ]-module
withrespect
to the action of S/A = G onA ,
and every mod- ule is stable. So let us dealbriefly
with the connection with modules when G is infinite. Let S EX( G),
A be a normal abeliansubgroup satisfy- ing
SIA G. ThenS/A
acts onA,
andconsequently
A still inherits astructure of module over the group
ring flS/A];
but thisring depends
on,S ,
and may be uncountable. Of course,by replacing (S, A )
with a count-able
elementary substructure,
we can assume Scountable;
notice thatthis does not
affect,
forinstance, stability;
moreover we have seen in § 1that,
in order to establish the first orderaxiomatizability
ofX( G),
insome sense it is sufficient to examine the countable groups in
X( G);
fi-nally,
when G is of the formC(~)~x°~ ® H
for pprime,
H finite and= 1,
then G isNo-categorical
andhence,
for every countable S ES/A is fixed up to
isomorphism. Nevertheless, A ,
as aZ[ G ]-mod- ule,
isalways stable,
and we will see soon that S may be not.So,
in any case, the connection fails.Now let us treat
stability.
We have saidthat,
for Gfinite,
every group in is stable. Butnothing
similar ispreserved
for Ginfinite,
even inthe
simplest
case G =C( p )~~° ~ with p prime,
as thefollowing proposition
shows.
PROPOSITION 3.1. Let G =
C(p)~x°~
with pprime.
Then there aregroups ,S E
~,(G)
in allstability
classes.Moreover, for p prime,
theprob-
lem of
characterizing
astability
class isequivalent
tocharacterizing
thegroups S
Ebelonging
to the class.PROOF. It is easy to
provide m-stable, superstable non-m-stable,
stable
unsuperstable
groups inX( G): just
take ancv-stable, superstable non-a)-stable,
stableunsuperstable
abelian group A and form S = A 0153 G.With
respect
to unstableexamples
in~,( G ) for p
=2,
look at5f1° ;
it isknown that this group is not
stable;
but it admits a normal abelian sub- group whosequotient
group is an(abelian) elementary
infinite 2-group. In order to handle the odd case and to prove the second state- ment of our
proposition,
let us recall some facts from[Me].
In that paper, fixed aprime p
>2,
it is described an effectiveprocedure providing,
forevery
(infinite)
structure M in a finitelanguage,
a nil-2 goup,S(M)
of ex-ponent p
such that M is first order definable in,S(M)
andM, ,S(M)
are in the samestability
class. In moredetail, given M, firstly
one defines an(infinite) graph T(M) satisfying
some suitableassumptions;
then one re-places
every node y inF(M)
with a copyS.,
ofC(p),
and one forms thefree nil-2
product ,S(M)
isjust
thequotient
of withrespect
to the normalsubgroup generated by
the commutators[say , ba ]
where y and 3 are
adjacent
nodes in thegraph,
and So,S =
,S(M)
is in~,( G )
because S is nil-2(hence
,S ’ isabelian)
and Sis’ is an infiniteelementary
abelian p-group.Now let us discuss the
definability
of ,S ’ and for S e~,( G).
It is knownthat,
as a consequence of Zil’berIndecomposability Theorem,
thederived
subgroup
S ’ is definable when ,S is cv-stable of finiteMorley
rank. But this
definability
resultalready
fails for cv-stable groups of infi- niteMorley rank,
inparticular
for a free infinite group S in the class of nil-2 groups ofprime exponent p
> 2[B],
and we have seen that thiscounterexample
is inX( G)
forG = C( p )~x° ~ .
In any case, let usquote
some very
partial
resultsconcerning
thedefinability
ofS ’ ;
these facts will be useful later.LEMMA 3.2
[T].
Let S EX( G)
where G is a finite abelian group of order n and let p be apositive integer.
Then every element in canbe
expressed
as theproduct
of(at most) 2 n 2
+ commutators and 2p-th
powers.PROOF. Recall that every element c in can be written as a
prod-
uct of commutators and
p-th
powers; we can arrange these factors and to obtain that commutatorsprecede p-th
powers. Theproblem
is to bounduniformly
the number of commutators andp-th
powersoccurring
inthese
decompositions.
Forinstance,
one can factorize cusing
at most onep-th
powerfollowing suitably
manycommutators,
but this does not bind -a
priori-
the number of involved commutators. However let us fix such adecomposition.
Let A be a normal abeliansubgroup
of S such that57A
isisomorphic
to G. Since G isabelian,
S ’ is included inA ,
and hence ,S ’ is abelian. Let xl, ... , xn be a set ofrepresentatives
for the cosetsof A in S,
then every element in S
decomposes uniquely
as ax~ with a E A and 1 ~x j x
n . Now consider the commutators in thedecomposition
of c .Using
some basic identities and the fact that A is abelian and includes
S ’ ,
onesees
that,
for a, b in A and 1 ~i, j ~
n,and
Hence every element in ,S ’ can be
expressed
as aproduct
ofwith a E A and 1 ~
i , j ~
n , andwhere
1 ~ i , j ~ n and h
ranges over theintegers; consequently
everyelement in S ’ is a
product
of at most2 n 2
commutators of the formerkind,
at most commutators of the latter kind(with
0 ~ hpn)
andpowers.
Actually,
as S’ ’ isabelian,
aunique pn-th
power occurs.Clearly
anypn-th
power is also ap-th
power. Hence thegiven
element cis the
product
of2 n 2 +
commutators and 2p-th
powers. 0(Notice that,
in[T],
thisadaptation
of the final Lemma still ensuresthe
definability
of when is abelian and has finiteindex,
andhence still
guarantees
the MainTheorem, quoted
as(b)
in §1).
LEMMA 3.3. Let S e
~,(G)
where G = is aprime
andH is a finite group whose
order q
isprime to p .
Let N be a normal abeliansubgroup
of ,S such that and(see
Theorem2.1).
Then every element in ,S ’ is a
product
of(at most) q
commutators modulo N.(For
theproof, just
use the fact that is finite of orderq).
With
respect
toS r,
there are somedefinability
results in[01]
and[02], mainly concerning polyciclic-by-finite
groups,hence,
inparticular, finitely generated nilpotent-by-finite
groups(see [01], Proposition 2.1,
and
[02], Proposition 1).
But notice that no group ,S EX( G)
isfinitely generated
when G is of the form EÐ H for someprime
p.3. The
simple
nonabelian case.Throughout
thissection,
assume G = Q3 Hwhere p
is aprime
and H is a
simple
nonabelian finite group of orderprime to p .
Our aim isto
study
theelementarity
of under thishypothesis.
We will express(ii)
in a first order way, and then we will discuss(i).
First let us underline thefollowing
fact.Fact 4.1. Let F be a group,
Ko, Kl
be normalsubgroups
of F suchthat
Ko
is abelian and bothF/Ko
andFIK1
areisomorphic
to H . ThenK0 = K1.
Otherwise
Ko. K1 properly
includes bothKo
andKl ,
so, as H issimple,
F .
Accordingly
where
Ko
isabelian,
and H is not -a contradiction-.THEOREM 4.2. Let G = fli H where p is a
prime,
H is a finitegroup of order q
prime
to p , and H issimple
and not abelian. ThenX" (G)
is
elementary.
PROOF. Assume S e
~," ( G ).
Then there is a normal abeliansubgroup
N of S such that and
= H ; furthermore,
for all s ES,
if
then,
for every choice of a and b in,S,
s commutes with both a Pand
[a, b]
modulo N. Notice that «H nonabelian»implies
non-abelian»,
and that every element in can beexpressed
in the forms P c for some s e S and c E S ’ . Choose
bo , ... , br
in a set ofrepresentatives
of cosets of N in S such that
generate
H withrespect
to a fixedpresentation
of H . Lemma 3.3applies
to oursetting,
and so every element in ,S ’ is aproduct
of(at most)
q commutators modulo N. Hence we canput,
forevery j ~
r,where si
E S and cj is aproduct of q
commutators.Actually,
asS/N
is notabelian,
N isproperly
included in(N, S’),
and so in so the sim-plicity
of H forces(N, S’)
= S ’ S ~ ~S p ; consequently
every element in ,S ’ isdirectly
aproduct of q
commutators moduloN,
and we can supposethat bj
is theproduct of q
commutators for r. Now wedistinguish
two cases.
Case 1:
for
all a EN and j ~
r, a centralizesbj.
This means that thecentralizer of a in
Cs,sp(a) equals
for alla E N,
henceCs’sP(N) =
S’SP.Consequently
N is a(normal) subgroup
of the centerZ(S’SP)
On the otherside,
is notabelian,
soand the
simplicity
of Himplies
Recall thatCs(S’SP)
is 0-definable and includesZ(S ’ ,SP).
Now consider the first order sentences in thelanguage
L of groupsstating
what follows:(a 1)
everyproduct of q
+ 1 commutators isexpressible
as aprod-
uct of q commutators modulo
(hence
moduloZ(S’SP));
(a 2)
there arebo ,
... ,br
in S suchthat,
forevery j x
r,bj
is aprod-
uct of q
commutators, bj E CS(S’Sp), bj
centralizes anyproduct of q
com-mutators and a
p-th
power modulo(hence
moduloZ(S’SP)),
and
finally bo ,
... ,br just satisfy
modulo(hence Z(S’ SP»
therelations in the
given presentation
ofH;
( a 3 )
for every s E S such that sP is in(hence
ins centralizes the commutators and the
p-th
powers modulo(so
moduloZ(S’ SP».
It is clear that a i , a 2 and a 3 are first order sentences of L . Let a de- notes their
conjunction. Also,
under ourassumptions, (ii) implies
a . Con-versely,
let a hold inS,
andput
Then N is a normalabelian
subgroup
ofS ,
N ~ a 2(and a 1 ) imply
that is ahomomorphic image
ofH ;
a 2again
ensuresN ;
so thesimplicity
of H forces These facts and a 3
yield (ii).
Case 2: there are
a E N and j ~ r
such that[a,
1. ThenNotice that
Cs,sp(N)
is a normalsubgroup
of ,S’ S p(because
Nis) and, using again
thesimplicity
ofH,
one can conclude oralso
where
Cs (N)
isnormal,
too. As the index one can find anatural number t q and ao , ..., at - 1 in N such that
In
fact,
take ao E N and look at n ,S ’ IfCs (ao)
n S ’ ,S pfor all al
E N,
thenCS (N) D
and we are done.Otherwise,
pick al E N satisfying
and formn S ’ S p .
Repeat
thisprocedure,
and notice that themachinery
muststop
in at
most q steps, producing t x q
and a,o , ... , at - 1 E N asrequired.
Ofcourse we can assume
t = q .
Recall thatbo ,
... , so, forevery j x
r, there is some i q for which Inconclusion,
thereare ao , ... , aq _ 1 and
bo , ... , br
in S such that thefollowing
conditionshold:
(p
forall j x
r, there is i qsatisfying [ ai , [bj, ai ];
(P 2)
forall j x r, bj
is aproduct of q commutators;
(P3)
for every a and b inS,
both aP and[ a , b ]
can beexpressed
inthe form
where
w( bo , ... , br )
is in a fixed set of words onbo , ... , br (depending
only
onH)
and sbelongs
to(hence
toCs ( ao , ... , aq _ 1 ) n ,S ’ ,S p );
(~3 4 ) bo,
... ,br just satisfy
moduloCS (ao,
...,aq _ 1 ) (hence
modulo... ,
aq _ 1 ) n S ’ S P)
the relations in thegiven presentation
ofH;
(~3 5 ) CS ( ao , ... , aq _ 1 )
is normal inS;
(B6)
if s , a, b E S and sp E CS(a0, ..., aq-1)(so
sP E... ,
aq _ 1 )
n,S ’ S p ),
then s commutes with both a p and[ a , b ]
mod-ulo ... ,
aq _ 1 ) (hence
moduloC s (ao, ..., aq - 1) n S ’ S P ).
Notice that ... , can be
expressed
as first order formulas in L.Let
be their
conjunction.
Sojust
translates theprevious
condition. Now choosesatisfying
HenceK1=CS(aü,
is asubgroup
ofnormal
(by
and proper(owing to P
1 andP 2);
moreoverS ’ is a
homomorphic image
of H(by B3
andB4),
and so isjust
iso-morphic
to H because H issimple.
Then we canapply
Fact 4.1 toand
recalling
thatKo
isabelian,
we can concludeNotice that y may need
infinitely
many L-sentences to be translated in a first order way, because is notnecessarily
definable. However this(possibly infinite)
translation can be done.In
conclusion,
when E satisfies Case2,
thenLet us check that the converse is also true. So assume that there are
ao , ... , aq -1 and
bo , ... , br
in Ssatisfying
andthat,
for alla’ .. a’ b’ .. b’)
in/3o(,Sq+r+1)
, isabelian. First of
all,
ensuresbo ,
... , Nowput
bo ,
... ,br ~ N . (N 9 bog
... ,br): for,
every commuta- tor orp-th
power in Sdecomposes
as aproduct
where is a word on
bo , ... , br
and sbelongs
toCS ( ao , ... , aq _ 1 ),
so that s E N .By ~8 5 ,
N is normal in,S ,
hence inBy fl 4 ,
is ahomomorphic image
ofH ;
but = N -as statedin and
f3 2-,
so isjust isomorphic
to N because H issimple; f3 6
ensures the last condition in
(ii). Finally,
N is abelianowing
to y . Hence~f." ( G )
is the class of the groupssatisfying
either a or~3
andthe sentences in y ; so
~f," ( G )
iselementary.
Now let us discuss the
elementarity
ofX’ (G)
for G as before. In or-der to express
(i)
in a first order way, we cannot use Lemma 3.2 and the relatedapproach already
followed in[T]
forfor,
neithernor S/N are abelian.
By
the way, notice that nogroup S
E isnilpotent (because
,S has asubgroup
S’ Spprojecting
ontoH).
On the otherside,
ifI
isfinite,
thenI
is apower p m
of p andthe
quotient
group is of the formfurthermore,
if S EE
X"(G),
then SIN isC(p)mEÐH,
and hence S isabelian-by-(C(p)mEÐH),
more
generally
S isabelian-by-finite
because N is abelian. So we canstate at least this
positive
result.COROLLARY 4.3. Let G be as above. Then the class of groups S E E
~,( G )
which are notabelian-by-finite (as
well as the class of groups which are not for anynonnegative integer
iselementary.
PROOF. Just recall that the class of groups which are not
abelian-by-
finite is
elementary,
as well as the class of the groups which are not QiH),
and use theprevious
remarks. o5. The
squarefree
order abelian case.In the
previous section,
we discussed theelementarity
ofX( G)
when G =C(p)~~°~
Q3 H where H is finitesimple
nonabelian and the order of H isprime
Now let us deal withwhere H is
simple abelian,
hence H =C( q )
for someprime
q . Of course,we still assume q # ~ro .
By
the way, noticethat,
for Habelian,
G isabelian, too;
and recallthat,
in this case, a group S E~,( G )
is solvable of class 2.With
respect
to theelementarity problem,
we divide the groups S Ee X( G )
in twosubclasses, according
to whether S ’ 8P is abelian or not. No- tice that the condition abelian » can beeasily expressed by
a firstorder sentence in the
language
L of groups.Moreover,
for 8 EE
S’SP is abelian if and
only
ifIn
fact,
lest 8 EX( G),
so S satisfies the conditions(i)
and(ii)’
inCorollary
2.2. If S is not in
~t, (C( p )~~° ~ ) ,
then S ’ SP cannot be commutative because S’SP has infinite index in Sowing
to(i)
and thequotient
group is an ele-mentary
abelian p-group.Conversely,
let 8 E X(C(p)~~°~ ) ,
and let A be anormal abelian
subgroup
such that S/A is an infiniteelementary
abelianp-group. Then both 8’ and S P are
subgroups of A , ,S ’ ,S p ~ A and S ’ ,S p is
abelian.
First let us treat the
groups S
E~,( G )
for which is not abelian.A
simplified
version of theprocedure
in Theorem 4.2 and Lemma 3.2yields
THEOREM 5.1. Let G =
C(~)~~°~
(DC(q) where p # q
areprime.
Thenthe class of the groups
8 E X(G)
such that is not abelian iselementary.
PROOF. In order to write
(ii) (or
also(ii)’)
in a first order way, we havesimply
toadapt
Theorem 4.2 and use ourhypothesis
that isnot abelian. But now the obvious remark that G is abelian
improves
thesituation with
respect
to(i).
Infact,
what we have to prove is that(i)
can be writtenby
suitable first order sentences in L . Of course we can as- sume that(ii)’
holds. Assume that S does notsatisfy (i). Consequently
has a finite index n in S . Then the
subgroup
N in(ii)’
has a finiteindex qn in S . So we can
apply
Lemma3.2;
infact,
S has a normal abeliansubgroup
N such that S/N is abelian and has a finite order qn . Accord-ingly
every element of is theproduct
of auniformly
bounded num-ber of commutators and
p-th
powers. This lets us define in a first order way S’SP inside S.Hence,
if the index of in S is n , then we canwrite this
property by
a first order sentence3n
in L. It follows that~ -~ d n : n > 0 1
expresses(i)
in L .So we can limit our
analysis
to thegroups S
Esatisfying
«S ’ S pabelian». In this case, we can
slightly enlarge
oursetting
and assumewhere q
issquarefree (and prime to p).
Even under thisassumption, Corollary
2.2 ensures that there is a normal abeliansubgroup
N of Ssuch that
N and S’SP IN = C(q) (consequently, C(p)(a) EÐ EÐ C( q)
for some infinite cardinala).
Put(the
centralizer of inS );
C includes S’SP(because
isabelian),
is normal
(because is)
and 0-definable(even
if isnot).
How-ever C may be nonabelian. So consider
(the
center ofC);
Z still includes S’SP and is normal in S and 0-defin-able ;
furthermore Z is abelian. Inparticular,
as Z ~ S/Z is a(pos- sibly finite) elementary
abelian p-group because,S/Z
is ahomomorphic image
ofS/S ’ ,S p . Z/N
is asubgroup
ofS/N including
and so is of the form
for some
(possibly finite)
cardinalP.
LEMMA 5.2. Let S be a group such is
abelian, r
be aposi-
tive
integer prime to p.
Then thefollowing propositions
areequiva-
lent :
PROOF
(1)=> (3).
For everya E sr,
a can beexpressed
aswhere k is a
nonnegative integer
andbo ,
... ,bk E S .
Somodulo
S ’ ,
hence aP E S’SP. It follows S ’ The converse is clear.(3)
=~(2)
Let x and y beintegers satisfying
1 = px + ry . For all ahence
(2)
=~(1) Clearly
,S = sois
abelian, ,S r ~ ,S ’ ,
hence S = ,S ’ ,S’’ _ ,S’’ .(1)
«(4)
We know S = SP sr andZ,
so S = ZS’r. It followsAccordingly
it suffices to show istrivial,
because S ’ ~~ Z and we have seen
that,
for S Pabelian,
S ’ ~ S 1.Conversely
take a EThen there are a natural k and
bo, ... , satisfying
modulo S ’ . Put
b = bo ... bk
forsimplicity.
As,S ’ ~ Z ,
Useagain (and SP x Z)
and deduceb E Z,
soTHEOREM 5.3. Let S be a group, be
abelian,
G =C(~)~~°~
0153fl3
C( q )
where q issquarefree
andprime to p .
Then S E~,( G )
if andonly
if Ssatisfies the
following
conditions:(i)
has infinite index in,S ;
(ii)"
for everyprime r dividing
q , S # S 1" .(Of
course, as qand p
arecoprime,
we canreplace
in(ii)"
withone of the
equivalent propositions
in Lemma5.2).
PROOF. Let S E
~t,( G ).
We know that(i)
holds and there exists a nor-mal
subgroup N
of S such that andC( q );
further-more for some infinite cardinal a . Then S
projects
itself onto
C( q).
Let r be aprime dividing
q ; thenC( q ) ~ C(q)1" and,
con-sequently,
so(ii)"
holds.Conversely
let S be a groupsatisfying abelian», (i)
and(ii)" .
HenceS/,S ’ ,S p
is an infiniteelementary
abelian p-group.Furthermore,
for every
prime
rdividing
Choose ar E S’S Pr.Form
Notice
that,
for everyprime
rdividing
q , ar hasperiod r
hence a
period multiple
of r modulo S ’ Then theperiod
of amodulo ,S ’ S pq is
just
q . As S ’ is an abelian group ofexponent dividing
q , thecyclic subgroup generated by
is a non-zero direct summand of S ’ 8pq. Let M be acomplement
of this summand in S ’8 p 18 ’
and let N be thepreimage
of M in the canonical homomor-phism
of 8’ 8P onto(hence N
isabelian)
and N ~ ,S ’
(hence
8’ ~ N and N is normal in8); finally
Hence
Corollary
2.2implies
E~f,(G).
Theorem 5.3
provides
apossible approach
to prove theelementarity
of is our
setting.
Of course, we have to handle S ’ and so in somedefinable way. Here is a
partial positive
result.COROLLARY 5.4. Let G =
C(q) where q
issquarefree
andprime to p .
Then the class of the nil-2 groups ,S EX( G)
for which isabelian is
elementary.
Recall that S is nil-2
(nilpotent
of class2)
if andonly
if its derivedsubgroup
,S’ is contained in the centerZ(S) of S;
this condition can beeasily
written as a first order sentence in L . Recall also that a group in is solvable of class 2.PROOF. Let S’ be a group such that is abelian. As
before, put
Z = Let r be a
positive integer. Clearly,
if Z =Z r,
then S satisfies all theequivalent
conditions in Lemma5.2; for,
,S ’ ~Z,
so Z r == S ’ Z ~’ and Z = 5" Z~. We claim
that,
when isnil-2,
the converse is alsotrue: In fact
,S = S ’ S r,
so, for everya E ,S ,
acan be
expressed
aswhere d E S and CESB Let a, b e S and
decompose
a = d r c as before.Then
(see [R],
ex. 5.46 p.118)
(because
S isnil-2,
and hence c eZ(S) )
(because [ b , d] E Z(S);
see[R],
5.42 p.119).
Hence ,S ’ Z r. Conse-quently
Z’’ _ and Z =In
conclusion,
for S nil-2 and S’S Pabelian, S
E if andonly
if Ssatisfies
(i)
andZ # Z’ for all
primes r dividing
q .We
already
know how to express(i)
in a first order way(see
Theorem5.1).
Infact,
if(i) fails, then S’SP,
henceZ ,
have finite index in,S ;
in par- ticular let n be the index of S’SP in ,S . Notice that both Z andS/Z
areabelian;
so use Lemma 3.2 to define and toexpress :
S’S PI
= nby
a first order sentence of L . Concludejust
as in Theorem 5.1. Now re-call that Z is 0-definable and
abelian,
so even Z’ is definable. Hence the statementZ # Z r for all
primes r dividing
q .can be written as a first order sentence of L . In
conclusion,
the nil-2groups such that is abelian are an
elementary
class.
Finally
let usgive
a short look at theproblem
ofavoiding
the nil-2 as-sumption
inCorollary 5.4,
and henceshowing
theelementarity
of thewhole class
~,( G ),
at least when G =C( q )
with qprime and (so
G =C(p)(10)
fl3 H with Hsimple abelian).
REMARKS 5.5
(1).
SIZ q abelian» can beeasily expressed
in a firstorder way,
(namely obviously
ensures theelementarity
of the class of the groups S Esatisfying
this assump- tion and «S ’ S P abelian »(for,
isequivalent
to whenS’ Zq).
Now assume that is not abelian.
(2)
The conditions «I
= n- for agiven positive integer n
isstill first
order;
if S satisfies thisassumption,
then Lemma 3.2applies (for,
Z is abelian and ,S/Z isabelian, too,
because S’ ~Z). By adapting
the
corresponding proof
andusing
,S ’ ~Z,
one sees that ,S ’ Z q is defin-able,
and so can be translated in a first order sentence.(3)
Also ZI
= n», for a fixed n >1,
is first order. Let ,S sat-isfy
thisassumption.
Notice that n is a power of q , n =q h
with h >0,
and Z/Z q is aZ/qZ-vectorspace
of dimension h .Accordingly
one can express«Z ~ S’ Z q» in a first order way,
by simply stating
that there is some ele- ment in Z which is not of the formwith
Z E Z,
co , ... , ch _ 1 commutators and0 ~ qo ,
... , qh -1 q .For,
ifZ = ,S ’
Z q ,
then the commutatorsgenerate
Z modulo Z q overZ/qZ,
andone can extract a basis of h commutators of Z modulo Z q .
REFERENCES
[B] A. BAUDISCH,
Decidability
andstability of free nilpotent
Liealgebras
and
free nilpotent
p-groupsof finite
exponent, Ann. Math.Logic,
23 (1982), pp. 1-25.[H] W. HODGES, Model
Theory, Cambridge University
Press,Cambridge,
1993.
[MaT] A. MARCJA - C. TOFFALORI, On the
elementarity of
some classesof abelian-by-infinite
groups, StudiaLogica,
62 (1999), pp. 201-213.[Me] A. MEKLER,
Stability of nilpotent
groupsof
class 2 andprime
expo- nent, J.Symbolic Logic,
46 (1981), pp. 781-788.[O1] F. OGER,
Equivalence
élémentaire entre groupesfinis-par-abéliens
de typefini,
Comment. Math. Helv., 57 (1982), pp. 469-480.[O2] F. OGER, Axiomatization
of
the classof abelian-by-G
groupsfor
afi-
nite group G,
preprint.
[R] J. ROTMAN, An Introduction to the
Theory of Groups, Springer,
New York, 1995.[T] C. TOFFALORI, An
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G
infinite,
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