R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
J URGEN B IERBRAUER
On a certain class of 2-local subgroups in finite simple groups
Rendiconti del Seminario Matematico della Università di Padova, tome 62 (1980), p. 137-163
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in Finite Simple Groups.
JURGEN BIERBRAUER
(*)
The
object
of this paper is tostudy
a class ofspecial 2-groups
which occur as the maximal normal
2-subgroups
in 2-localsubgroups
of ~ finite
simple
groups.Among
thesesimple
groups are theChevalleygroups Dn(2),
n ~ 4and the
Steinberg
groups2Dn (2 ),
n > 4 as well as thesporadic
groupsJ4
and
M(24)’.
We consider a
special
groupQo
of order 29 withelementary
abeliancenter of order
8,
which admits1:3 x L,(2)
as anautomorphism
group.Let
Qn,
n ~ 1 denote theautomorphism type
of the centralproduct
of n
copies
ofQo .
We determine theautomorphism
group ofQn
andwe
show,
thatJ4
contains a maximal 2-localsubgroup
of the formQ2(1:sxL3(2))
and that.11~1(24)’
contains a maximal 2-localsubgroup
of the form
Q2(A6XL3(2)).
The groupsDn(2 )
resp.2Dn(2 )
contain para- bolicsubgroups
of the formQn-3(Dn-3(2) X L3(2) )
resp.Qn-3( 2.Dn-3(2)
Xx~3(2))y
which are maximal with theexception
of the caseD4(2 ).
These results and several characterizations of the groups
Qn by properties
of groups ofautomorphisms
are collected in the firstpart
of the paper. The second
part
contains a characterization oflVl (24 )’
by
the 2-localsubgroup
mentioned above. In[19]
Tran vanTrung gives
ananalogous
characterization of Janko’s groupJ4.
Standard notation is like in
[6].
In additionDg
resp.Qg
denotesthe dihedral resp.
quaternion
group of order 8 andD8
resp.Q8
the(*) Indirizzo dell’A.: Mathematisches Institut der Universität
Heidelberg -
69
Heidelberg,
Im Neuenheimer Feld 288, W.Germany.
central
product
of ncopies
ofDg
resp. The centralproduct
withamalgamated
centers ofgroups H
and K is denoted H * K.For a
regular
matrixA,
thetransposed-inverse
of A shall be written A*.If an
element g
of the group Goperates
on somev ectorspace
Vwith fixed
basis,
thesymbol
g, denotes the matrixgiving
theoperation of g
withrespect
to the fixed basis.1.
Properties
of some2-groups.
(1.1)
LEMMA. LetQ
be a p-group of class 2 and let N be an auto-morphism-group of Q
such thatINI)
= 1. Assume further[Q’,
1. Set A =CQ(N)
and B =[Q, N]. ~
(Then we
have Q = A * (BZ(Q)).
PROOF. This follows from the
3-subgroup-lemma
like in the casethat
Q
is anextraspecial 2-group
and N acyclic
group of odd order[12,
prop.4].
(1.2)
LEMMA. LetQ
be aspecial
group of order 29 with center Z of order 8. Let n be an element of order7,
whichoperates fixed-point- freely
onQ.
Assumefurther, that
=QIZ
is the direct sum of twoisomorphic
irreduciblen~-modules.
ThenQ
isisomorphic
to one ofthe
following
groups:(1)
aSuzuki-2-group
oftype (B ) ;
(2)
a centralproduct
of twoSuzuki-2-groups
oftype (A )
andorder 26.
(3)
a group oftype ~3(8);
(4)
a groupQo
which has thefollowing
structure:as
n>-modules,
and
Qo
containsexactly
3elementary
abeliansubgroups
of order64, namely A,
B and A + B = X2Y2,X3Y3).
·PROOF. If Z is
isomorphic
as an to the irreducible submodules ofQ,
then it follows from[9, (2.5)], that Q
is oftype 1/3(8).
So we shall assume, that Z is not
isomorphic
to a submodule ofQ.
(1) Assume,
thatQ - Z
doesn’t contain involutions. ThenQ
isa
Suzuki-2-group
oftype (B )
or( C )
in the sense of[7].
If
4911Aut (Q) 1,
there is an element m of order 7 in Aut(Q),
whichcentralizes Z. Because of
(1.1 ),
we haveCQ(m)
= Z. This contradictsa result of
Beisiegel [1].
So we have49||Aut (Q)l
for every Suzuki-2-group
oftype (B )
or(C)
and order 29.It follows now from
[7],
that theSuzuki-2-groups
oftype (B)
andorder 29 possess an
automorphism n
with therequired properties,
whereas the groups of
type (C)
and order 29 don’t.(2) Assume,
thatQ - Z
containsexactly
7 X 8 involutions.Let
H Z, I H
= 4. The number of cosets in which contain elements with square inH,
is then 7 +3x56/7 ==
31.It follows
QIH Z2 X Z4 * (Qg)2
or Let A de-note the
unique elementary
abeliansubgroup
of order 26 ofQ.
Assume
E8 XZ4 * Qg .
The maximalelementary
abelian sub- groups ofQIH
have order 32 and we n It fol-lows,
thatQ] ~
= 2 for every x E A - Z. Thisshows,
thata contradiction. We have (n)
Set
Q/H =
whereThen Set B =
vl>.
Then B isisomorphic
tothe
Suzuki-2-group
oftype (A)
and order 26. AsQ] C H,
we have[~9]=[~~]-~.
°
Assume
YI] *-1.
Set[xl ,
= zl . We can choose bases~x x x ~ ~ ~ ~ ~ ~
and of resp.Z
such thatWe have = z, and further commutator relations follow
by
application
of theautomorphism
n.Especially
and thus
Z2Z3EH.
It follows H =z2 z3~ .
On the other handand thus
zlz2 E H,
a contradiction. We have[Xl’ y,]
= 1. Ift[x, Q] ) I
- 2for x E
A - Z,
weget
thecontradiction A = Z again.
It followsThen we can assume
and we have
[xi , 2/J
= = 1 and thusy;]
_ for(1 , 2, 3} .
SetY2]
==[x2 , ~ y1]
= zi = = Z3’ Thenwith
respect
to the basis(zi, z3}
andThus
Y3]
= z2 ~ z3 and H =Z2Z3)’
Further[x2 , Y3]
= Z2’ We havey1 E H = z1, z2z3>. Assume y21 =
ZIZ2’Then y23
=(y1y3)2 =
- zlz2z3 and
Y3]
= a contradiction.Similar calculations show and It
follows Yî
== Z2,y2 ---
Z3,y23
= z1z3 and thegroup-table of Q
is determined. We haveQ
=2/i?2/2) 2/3) * ~2’~2?
~3 y3 ~ andQ
is a centralproduct
oftwo
Suzuki-2-groups
oftype (A )
and order 26.(3) Assume,
thatQ - Z
containsexactly
14x8 involutions.Then
Q
=AB,
where A and B are theonly subgroups of Q isomorphic
to Let A = and B = as Choose
yl E Bo
and setYl].
Thenz1 ~ 1.
Set further x2 =We can assume, that
we have
IXI
~=yl]
and thusfollows
Assume
first,
thaty2]
= zlz2 , y[x2 , yl]
= zlz3 . Then = z2z3 , 7hx3 2/2]
- As z, =[xg !
-C’"~’3 ! 7 Yll Y2]’
we have[x~ ! y,]
==== Z2Z3’ From
y2]
= Zl Z2 ZS it follows[XlX2’ Y3]
= Thus[0153l, y3]
=== zlz3.
Identify Aa, Bo
and Z with the additive group ofGF(8),
i.e.Ao = Joe
EGI’(8)~ ,
9Bo
=!~
EG.F’(8)~ ,
Z = E(7F(8)}
with the obvious
multiplication.
Let ;1, be agenerator
ofInterpret
theoperation
of n onBo
resp. Z asmultiplication
withÄ,
;1,4 resp. )..5. Choose xl ---0153(l),
2/1=2/(1)? ~(1)’
It is then easy tocheck,
that[x(a),
= for every EGF(8).
ThusQ
isof
type .L3(8)
in this case.If
x2]
=[x2 , yl]
= weget
the same resultby
a similarcalculation. In this case, the
operation
of n onAo , Bo
resp. Z has to beinterpreted
asmultiplication
resp. A3.(4) Assume, that Q - Z
containsexactly
21 x 8 involutions. Like under(3 ),
7 letQ = AB,
whereA ~ B ~ Eg4 ,
letA = Ao ~+ Z,
B =-
BotBZ
be thedecompositions
asn~ -modules, Ao = x2 , x3~,
9-Bo = yi,
y2, 9 where = andwith
respect
to the bases~xl, x2, x3~
resp.(yi ,
y2,y3~.
Assume
)[~ Q] == 2,
let ==z,, 0 1
and[v2, WI] =~3~1
forThen Further
and thus This shows
.9 - Z,
a contradic-(n)
tion. We have
I [xy Q]
== 4 forZ, X2
== 1. Sety Y2]
== Z3and = Z2 - It follows
and thus
[x2 , yl]
= ~3)[x3 , yl]
= z2 . FurtherWith
respect
to the basis(zi,
z2 ,Z31
we haveThe structure of
Q
is nowuniquely
determined. Let HZ,
- 4.Then
Q
containsexactly 21+3x42/7 ==39
cosets which contain elements with square in H. It followsE4
X(QS)2.
(5)
AssumeQ - Z
contains more than 21 x 8 involutions. ThenQ = AB,
and for x E A - Z we haveIGB(x)1 [ =
25. Itfollows
[ [x, Q]
[ = 2 and as a contradiction.(1.3)
LEMMA. LetQ
be aspecial 2-group
of order 29 with ele-mentary
abelian center Z of order 8. Let F be aFrobenius-group
oforder 21
operating
onQ, F
==n, r>,
n7 - r3 =1,
nr = n2.Assume,
ythat n
operates fixed-point-freely
onQ
and that gzThen Q
is
isomorphic
to the groupQo
in(1.2) (4)
and theoperation
of Fon Q
is
uniquely
determined.PROOF.
Let V
be an irreducible F-submoduleof Q = Q/Z.
Theoperation
of rshows,
that V - Z contains involutions. ThusT7 =
We have
Q = AB,
A n B = Z and F normalizes A and B.Set
Xl), C.,,(r) = zn.
Assume
Ã
Then we can choose basesx2, x3}, 1 fgl y2, y3,
1n>
of
A, .7~
resp. Z such thatIt follows
We have
Assume Then
a contradiction. The same calculation shows ~ z~ z~ . Thus = z~ ~
[Xl’
= Z2Z3,[~2 ~ Y.]
= ~3.On the
other
handand thus
[x2 ,
= Z2Z3, a contradiction. WeB.
It follows from(1.2),
thatQ
isisomorphic
to the groupQo
of(1.2) (4)
and thatthe
operation
of non Q
isuniquely
determined. Choose notation forQo
and for the
operation
of n line in(1.2) (4).
Then
(1.4)
EXAMPLE. Let D be theDempwolffgroup,
i.e. theunique nonsplit
extension ofE32 by L5(2 ) [3].
For adescription
of D see[11].
Let V=
02(D) rov E32’
XV, IXI
= 4. ThenND(X)/V
has the struc-ture
Eg4(~3 X L3(2 ) ).
LetR¡==
ThenR1/X
is iso-morphic
toQo
andND(X)jX
is asplit
extension ofby 17s xLs(2)
From now on
Qo
denotes the groupgiven
in(1.2) (4).
We shallnow describe the
automorphism
group ofQo .
(1.5)
COROLLARY. Let A = Aut(Qo), B
=[a, Z]
=11,
C = E
.A, [a, Z~ .
Then B and C are normalsubgroups
of A.We have
G’ B, CrovE2l8, AjBrovLs(2),
PROOF. It follows from
(1.4),
thatL3(2).
Anautomorphism
of
Qo ,
which induces theidentity
on Z andoperates
on each of the threeE64-subgroups
ofQo
has to lie in C. Thus and C is the kernel of therepresentation
of B on the set ofE64-subgroups
ofQo
:Clearly ° rov E2l8.
The
following
isprobably
well known(1.6)
LEMMA. LetLs(2).
Let Loperate
on"f7.,
Z anirreducible L-submodule of V.
Assume,
that Z andVIZ
are non-isomorphic
natural L-modules. Then either V is acompletely
redu-cible L-module or V is a
uniquely
determinedindecomposable
L-module.Choose
n, r)
L such that n 7 = r3 == n 2, Z
=z3~
andlet V =
Z QQ Vo
as an~n, r~-module.
We can choose a basis I V2 ofVo,
such thatand for every x E L we
have xz
= Choose t e Z such thatThen If V is an
indecomposable
L-module wehave vx
= vl,v2
= VaZ2’ yv3 =
V2Za. Then > and thusICv(t)1 = 16.
(1.7)
Let Loperate
onQo,
where FixF L,
.F’ _ ~n, r~, n’ = r3 = 1,
nr = n2. ThenE8
and one of thefollowing
holds:(1 )
Loperates completely reducibly
on two of theE64-subgroups
of
Qo
andindecomposably
on the third.,
(2 )
Loperates indecomposably
on all of theE64-subgroups
ofQo .
We shall refer to the
operations
under(1)
resp.(2)
asoperations
of « dihedral >> resp. «
quaternion » type.
PROOF.
Clearly n operates fixed-point-freely
onQo
andCQo(r)
~Es.
We choose notation like in
(1.3).
Let t e L such thatThen
(tr) 2 = (tn)3
= 1.(a) Assume,
that .Loperates completely reducibly
onA,
i.e.L
operates
onAo = Xl’
X21X3)’
(a1) Assume,
that Loperates
onBo = Y1,
y2,Y3)’
The F-com-plement
of Z in A + B is(A
-E-B )o We
have 9 and
Thus A
--~- B
is anindecomposable
L-module.(a2) Assume,
that B is anindecomposable
L-module. Then we see likeabove,
that A-f- B
is acompletely
reducible L-module.((3)
Let Loperate indecomposably on A, B
and d+
B. Withrespect
to the basisZ31
resp. Y3,Z31
wehave then
We
note,
that in both cases,(a)
and(fl), Z2
X(D8)~, CQ. (t, t2)
~2t~gg
(DS)2
andCQo(t, tl)
^~EIs,
The
following
iseasily
verified:(1.8)
Lemma. Let theoperation ’of
L onQo
be of dihedraltype,
where
L ~ L~(2).
Choose notation like in(1.7 ) («1).
Thenand the
operation
ofF,
onQo
is of qua- terniontype.
(1.9)
NOTATION. LetQ n
denote theisomorphism-type
of the centralproduct (with amalgamated centers)
of ncopies
ofQo
and letQi ,
1 i n be groups which are
isomorphic
toQo .
Further l ~ i ~ nare
isomorphisms
fromQo
onQi . Consider Q
=Qi * Q2
* ... *Qn r’J Qn.
We can assume Z =
Z(Qo )
=Z(Qi )
=Z(Q),
and weset =
V(i), 99i (yj)
= 1 ~ in, j = 1, 2,
3. Set A = Aut(Q),
B = E
A, [a, Z] = 1 } ,
C = EA, [a, Z}.
Here the indexn> is omitted as no confusion will occur. We
set Q
=QIZ
and iden-tify Q
with asubgroup
of A.Then
C B A and the groupsB,
C are normalsubgroups
of A. FurtherL3(2).
Set
For elements oci, a_i of
GF(2),
not all zero, setConsider the set
Then t8 is a
GF(2)-vectorspace
withrespect
to the additionThe is a basis of 8. We consider
further the
non-singular
scalarproduct ( , )
on ?given by ( Y, ~W )
= 0if V = 0 or W = 0 or
[V, W]
=1 ~
and( Y, W )
= 1 otherwise.Then
Ex ~ E~2n -E- 3.
Set~,=~=Z~~,...,~~B ~=1,2,3.
We have
Ek]
=zr~,
where~~, k, r)
-{l, 2, 3}.
Set
Ej - ?7-1,
... ,-n ~ ? _ 1, 2,
3 andFor 2 E
(1 , 2, ... , ~}
letBL =~ bi , b_i~
B withQ j] --- 1 Cb~ ~ v-~ ] =- 1 - Cb-~ ~ Yi]
andThen b2i
=b2-i = 1, Bi = E3
and[B, , Bj]
= 1 fori # j.
Let L be a
complement
of B in A = Aut(Q).
(1.10 )
LEMMA. Letq E Q - Z.
Then[q, Q] ~ Z
isequivalent
toq E .Ex
for anE specially,
is a characteristic subset ofQ.
We haveQ] _ [q, Q]
for every q eEx -
Z, It followsfor
every
PROOF. Let If for an in-
verse
image
qi ofqi ,
we have ZCq, [q, Q].
Assume
[q, Q] =1=
Z. Then[qi , Qi]
==[qj, Qj]
wherever and This shows for an x E
Ao.
(1.11)
LEMMA.CBo , Bo rov Sp (2n, 2), Bo
r1 C =1,
AIB - Z3(2 ).
PROOF. It is
clear,
thatC rov E2l8n
andAIB - L3(2).
Let X Ec- {0}.
Then X satisfies thefollowing
conditions:( a )
..where
BQn-i.
(y) Q = Rl * .R,
where( 3) C(X)
= 2 for eachx E Ao.
(8)
For every such that we haveConsider the set satisfies conditions
(x)-(e)}.
n
(1 ) ~0~ :
let X E M. For write1
Assume
[x, Q]
= Z. ThenIQ:
- 8 andCQ(x)
=CQ(X) by (~8),
a contradiction to(s).
Thusy E Ao by (1.10 ).
It fol-lows from
(y),
that we can write ~ ~Xo = q, r, s~ - E8 , r E E2, 8 E Ea. By ( 3 )
we haveC(X) m (v§’~, wi)) # (1)
forevery j E (1 , 2, 3}.
Choose 2 E2,
... ,n~ .
Assume
v=", v~’i~ c CQ(~)
for Without restrictionwe can
choose j = 1.
It followsri, si> Z
and from(e)
weget
n
C~(8)
=C(X)
and thus qi e Z. We now choose i Ee{ly2y...~}
such thatqa , ri , sv ~ ~ Z. By
the above we have n = 2 forevery j
e{l, 2, 3}
andx, y) 6 Z
for every~x, ~q~ ,
ri ,si}
such thatx ~y.
Without loss It follows ri eva2’> Z,
8i ev23’~
Z. Assume 8i e Z. ThenCQc(X)
= -by (s).
It follows a contradiction.We It and
by
the sameoperation
as above This holds for every~e{ly2~...~}
such that
qi , r~ , si~ ~
Z, This shows~e~2013 {O}.
We have shownM === t8- {O}.
(2)
It follows from( 1 ),
that theautomorphism-group
Boperates
on t8. Further B
respects
the linear structure and thesymplectic
scalar
product
of 3S. The kernel of thisrepresentation
of B isexactly C,
as
-- Q
andA/B ~ L3(2 ).
HenceB/C
isisomorphic
to a
subgroup
ofSp(2n, 2).
(3)
Define asymplectic non-singular scalar-product
on overGF(2) by
= 1exactly
if 1~ _ - r(and
0otherwise).
LetSp(2n, 2)
and letBo
berepresented
in the natural way on.E2o’
and
E(O). Let q
EQ. Then q
possesses aunique representation
of theform q
= qi EE Z, i = ~ , 2, 3 .
We extend theoperation
of
Bo
onQ by setting
for It is now easy to see, thatBo
is a group ofautomorphisms
ofQ.
(1.12)
LEMMA. LetQ
be aspecial 2-group, Z(Q) =
andlet a group
L, L "-/ L3(2), operate nontrivially
onQ. Suppose ... Q+ T~~,t
as an L-module such thatPi
~T7j *
Z forE
119
... , Here17i
and Z are natural L-modules.Then m = 2n
and Q "-/ Qn.
If r is an element of order 3 inL,
thenCQ(r)
~2t~E2 2n
+ 1.PROOF.
(1)
Let be an irreducible L-submodule and V be the inverseimage
of9.
Then V cannot be aSuzuki-2-group
of(A)-type
asL3 (2 ) operates
on V. AsV ~ Z
as anL-module,
we musthave It follows +
1,
when r is an element oforder 3 in L.
(2) Consider Q
as aGF(2)-vectorspace.
Then it is easy to see, that X =C(L)
~1 Aut(Q)
~Lrn(2) and
EXI =
2m-1. SetflJ’ -
(3) V
is an irreducible L-submodule of~~ .
Let an irreducible L-submodule of
~~ .
Clearly
S. Let V E 0’ and let 2 be anL-isomorphism of 9
on Then r can be extended to an
L-isomorphism
of~,
thatis 7: E X.
(4)
Then 6 is anGF(2)-vectorspace by
thefollowing
definition:0 --f- Y -- Y -~- 0 - Y, Y -I- Y = 0
forLet S’ such that
V #
W. ThenV + ’W
is defined as theunique
irreducible L-submodule of
P7 W ~
which is differentfrom 9
andW .
Then
clearly
V + ~tY = W I V. Theassociativity
of the so definedaddition is
easily proved
with thehelp
of thefact,
that a 9-dimensionalL-invariant subspace of Q contains exactly
7 irreducibleL-submodules.
(5)
We define asymplectic non-singular GF(2)-scalar product ( , ) on ftJ by (o, o ) = (o, V) - (Y,0)=O and,
forV, (V, W) == 0
if and
only
if[ Y, W ==
1.Clearly (V, W) = ( W, V)
and{ Y~, V)
= 0. We show(A -~- B, C)
=- {A, C)
+(B, C)
for allA, B,
C We can assume0 ~ {A, B, C}
and
If
[A, C] = 1 = [B, C],
we have[A + ~ C] = 1,
as A-~- B ~ A, B~ .
If[A, C] =
1 ~[B, C],
we have[A
+B,
So we can assume
[~C]=~1~[2~C]~
and we have to show[A
+B, C] =
1. This however followsdirectly
from the structureof
Qo ,
asA, 0) ro.J B, C~ ^~ Qo .
AsQ
E?’),
it is clear that( , )
isnon-singular.
(6)
Itdim Z ’
2n. Let ? = ... bea
decomposition
of * inhyperbolic planes
withrespect
to( , ).
ThenThe
groupQi
isspecial
of order 29 with center Z. Theoperation
of an element of order 7 and(1.2)
showQiro.JQO,
1 2 ~ n. ThusThe
following
lemmagives
f urther motivation for the term « dihe- draltype »
resp. «quaternion type ».
introduced in(1.7).
(1.13)
LEMMA. LetQ
= like in(1.9)
for n = 2. LetL ~ L3(2 )
and assume theoperation
of L onQi
andQ2
is ofquaternion type
like in(1.7) (2).
Then we can choose1~2 Q,
I IQ - RI * R2 ,
such that Loperates
on =1, 2,
and theoperation
of L on
R~
is of dihedraltype.
PROOF.
Let ggi
be theisomorphism
fromQo
onQi , i
=1, 2,
andlet the
operation
of L onQ
i be like in(1.7) (2).
Set
Y-1
+ IR2 + Vi + V 2 ~
·From
(1.12)
and(1.13)
weget
thefollowing
(1.14)
COROLLARY. Let L be acomplement
of B in A = Aut(Q)
such that the
operation
of L onQ
satisfies thehypothesis
of(1.12).
Then L is
conjugate
in A to one of thefollowing
twoautomorphism-
groups of
Q (notation
like in(1.9)).
(1 ) L+,
where theoperation
ofL+
onQi ,
1 c z n is of dihedraltype
likegiven
in(1.7) (1).
(2 ) .L_,
where theoperation
of L- onQi
is of dihedraltype
like above for 2 i n and ofquaternion type
like in(1.7) (2)
for i = 1,(1.15)
LEMMA. Consider thesubgroups L+
and L- of A as intro- duced in(1.14).
ThenL+
n L_ =F21
and F =n, r>,
where n7 -- r3
= 1,
nr = n2 and theoperation
of F onQi
is described in(1.7),
1 ~ 2 ~ n. We have
CB(I’) = CB(n) =
B* -Sp(2n, 2)
and B* is a com-plement
of C in B.Further
El’)
is anindecomposable B*-module, i ~= 1, 2, 3
and2),
where BE~-~-, -}.
PROOF. It follows from
(1.7),
that As it iseasy to see, that n
operates fixed-point -freely
onC,
we have thatCB(n)
isisomorphic
to asubgroup
of~Sp(2n, 2).
The groupB/C
isrepresented
in the natural way on thevector-space E1/Z
and the com-plement Bo
of C in B isrepresented
on thecomplement
of Zin
E (1.11 ).
Fix the basis{ (1) v2(1),
...(1)
... for E( 0) andthe
analogous
basis forE,IZ. Identify
each element ofB/C
resp.Bo
with the matrix
representing
theoperation
of the element withrespect
to the above basis. Then
BjC
resp.Bo
isgenerated by
the matricesof the
following
form( see [ 1 ~ ] ) :
Here I denotes the
(2n, 2n)-unit
matrix and denotes the matrix withentry
1 at the intersection of row k and column r and 0 other- wise. LetBi’
be thesubgroup
ofBo generated by
the elements whichcorrespond
to the matrices of forms(1)-(4).
ThenB:’ "’-/ Q+(2n, 2).
Set The involutoric
generators
ofBi ,
1 ~ i ~ n
( 1.9 )
are elements ofB,
which are not contained inBo . They correspond
to the matrices of forms(5)
and(6).
It follows from(1.9),
that B*
operates
on Thisoperation
isclearly indecomposable.
Further it is a matter of direct
calculation,
that B*C(F).
AsCc(n)
=1,
we haveCB(n) = CB(I’) = B* ~ Sp(2n, 2).
Let q~,
8 E { +, -}
be defined on the vectorspace 6
with values inGF(2) by
= 0 and = 0 if andonly
ifL,, operates
com-pletely reducibly
on V forIt is then easy to see with the
help
of( 1. 7 ), that qe
arequadratic
forms on 6 with
respect
to the scalarproduct ( , ) .
Let+ X-t. Thus the indices of q+ , q- are n resp. n - 1.
Let
B8
be thesubgroup
of B*respecting
the form q,,. ThenB*
isisomorphic
to011(2n, 2). Clearly CB(Le) C
Theequality
-=B~
will follow from the
examples (1.15) (i)
and(ii).
(1.15)
EXAMPLES.(i)
Consider theChevalleygroup Dl(2 ), ~>4.
We use the nota- tion of[2].
So let el, ... , el be an orthonormal basis for an euclidean vector space.:t
=1, 2, ...Z}
is a root-system
oftype Di .
The vectors ri , 1 i I with ri = ei - for i 1and ri
= + e, form asystem
of fundamental roots. This choicecorresponds
to thefollowing labelling
of theDynkin-diagram
for I = 4. Then P is a
parabolic subgroup
ofDz(2). Set Q = 0,(P).
ThenFor 4jl set
Then with Further
is
isomorphic
to~~(2 )
andThen and The group L
operates
oneach of the
subgroups
i3> and
i3>
94 j
1.== ~20133, and the
operation
of .~ on each ofthe
subgroups Q i of
is of dihedraltype.
The group P is a maximalparabolic subgroup
ofDt(2 )
with theexception
of the caseI =
4,
where P is contained in a maximalparabolic subgroup,
whichis a
split
extension ofEg4 by S~+(6, 2).
(ii)
Consider theSteinberg
group2D,(2)
forZ ~ 4. Let e
be thesymmetry
of theDynkin diagram
forD, interchanging and ri
and
fixing
the fundamental roots ri 7 1~~20132. TheDynkin- diagram
for2DL(2 )
is thenLet P =
P3
be a maximalparabolic subgroup
ofID,(2), Q
=0,(P).
If r is a root
and r:k rl,
set = E where I~ _GF(4)
and or is the non-trivial
field-automorphism
of K. ThenIf r =
rl,
set where.Ko
is theprime
field of K.Then
Set
for
4~~20131.
Then whereWe have
[Z, .x]
=1,
P =Q r-v Qn
and theoperation
of Lon
Q~
i is of dihedraltype
fori ~ 2,
ofquaternion type
for i == 1.(iii)
Janko has shown[8, Prop. 13],
thatJ,
contains anelementary
abelian
subgroup
V of order 8 such that L = is aspecial
group of order 215 with center
V, N(V)
=J X C,
whereand
0 L,(2).
Here J=C(V),
an element of order 5 ofJ operates fixed-point-freely
onLjV
and an element of order 7 in Coperates fixed-point-freely
on L. Further an element of order 3 in Joperates fixed-point-freely
onLIV.
Tran VanTrung
has characterized thesimple
groupJ, by
a maximal 2-localsubgroup having
the abovestructure
[19].
It is easy to see and follows from Tran VanTrung’s proof,
that theoperation
of C onL/ Y
and TT satisfies the conditions of(1.12).
It follows then from(1.12),
thatQ 2.
It should be
noted,
that0-(10, 2)
possesses a maximal 2-localsubgroup
M such thatE,,
C ~ L3(2 ),
where an element of order 5 in .M~operates fixed-point- freely
on and an element of order 7operates
fixed-point-freely
on02(M)-
In this case,however,
an element d of order 3 in J will notoperate fixed-point-freely
on In fact wehave =
(C(d) [d,
where(iv)
Let G =lVl(24)’
be one of theFischer-groups,
let z be a2-central involution of G and set H =
CG(z),
K =H’,
J=0,(H)
like in
[13].
ThenJ r-v (DS)6, I02,3(H)/JI
=3, K/02,3(H) r-v U4(3)
and== 2. Let
j2
be an involution in J -~)
such thatE181 A6
· ThenE32A6’
· Let R =02( CK(j2))’ H
=1i
= and use the « bar convention ».Then
-=Cj(JS)
r-vE64
andFurther
Set M = Like in
[8, Prop. 13]
consider the inverseimage
Uin M of a maximal
2-local-subgroup
of which is a faithfuland
splitting
extension ofEg4 by ~3 X L3 (2 ) .
Set Z =Z( 02 ( U) ~,
I let Pbe a
subgroup
of order 3 in02,3( U)
and let C be asubgroup
of order 7in U.
Similarly
like in[8, Prop 13],
weget Cv(P)
= FurtherZ-
1~
consists of 2-central involutions of G. We can choosez, j2~
Z. Set B =CH(Z)
andQ
=02(B).
Theoperation
of Pshows Z F. Further
Q
=CR(Z),
= 215 and Roperates
fixed-point-freely
on We have andAs elements of order 7 of
L3(2 )
and elements of order 5 inA. operate fixed-point-freely
on the groupQ
has to bespecial
with center Z.Let S be an element of order 3 in
B,
which doesn’toperate
fixed-point-freely
onQjZ.
Thenby (1.1)
,,1"e have whereQl = Q2 = Z[Q, S]
andQi, Q2
areL3(2)-admissible special
groups of order 29 with center Z. It follows from(1.2),
thatand thus
Q r-v Q2. Obviously, NG(Z)
is a maximal 2-localsubgroup
of
M(24)B
Further(1.16)
LEMMA. For every there is agroup X
with the follow-ing properties:
(iv)
Theoperation
ofL/Q
onQ/Z
and Z satisfies thehypothesis
of
(1.12).
Then the sequence 0 is
non-split
for n >1, split
for n = 1. Further the structure ofX /Z
isuniquely
determined.PROOF. It follows from
(1.14), (1.8)
and(1.5),
that there is a group Xsatisfying (i)-(iv).
FurtherXjZ
isisomorphic
to asubgroup
of Aut(Q)
and its structure is
uniquely
determinedby
the same lemmas mentioned above. It follows from(1.1 ~),
that the above sequencesplits only
for n = 1.
2. A 2 -local characterization of Fischer’s
simple
group-ill(24)’.
THEOREM. Let G be a finite
simple
grouppossessing
a 2-local sub- group Jf with thefollowing properties:
(i) Q =
is aspecial
group of order 215 withelementary
abelian center Z of order 8.
Then G has a 2-local
subgroup
of the formB211 ’ M24’
COROLLARY. Under the additional
assumption,
that0(C~)) ~
1for a 2-central involution z in
G,
it follows from[16] and _ [14],
that Gis
isomorphic
to.lVl(24)’.
PROOF. Let_G be a group which satisfies the
assumptions
of thetheorem. Set
9
=M/Q, 1fl == M/Z
and use the «bar convention ».Let B resp. L be the inverse
images
of B resp. L. Then B =C(Z).
Let F =
~n, r)
be aFrobeniusgroup
of order 21 contained inL,
where n7 = r3 = 1, nr = n2.
Clearly,
elements of order 5 and 7 of M have tooperate fixed-point-freely
onQ.
As noperates fixed-point- freely
onQ,
we haveCB(n) ---
We use the
symbol
- to denote thecorrespondence
of elements in theisomorphism
Let D ESyl3 (BI),
D ==d2),
wheredl ~---> (1,2,3), d2 ~ -~ (4, 5, 6 ) .
Asdl
anddld2
areconjugate
underAut
(As),
we can assume = -26.
Assume =
CQ(d2).
Then[dl, Q]
=[d2,Q]. As Q -
d E
D~,
there such that nQ] ~
1. Theoperation
of n shows then[d~ d2 , ~] = 1,
a contradiction. Thus[d2, Q], CQ(d2) = [dl, Q],
the elementsdld2
andd, d2l operate fixed-point-freely
on~.
Set
Q1= Q]
andQ2 =
=Z[d2, Q].
It followsfrom
(1.1),
that Further Z =Z(Ql)
=Z(Q2)
and thegroups
Qi
arespecial
groups of order29, i - 1, 2.
As
BI operates
onCQ(r),
we haveCQ(r) By (1.3)
and thus
Q ^~ Q 2.
FurtherL C N(Qi ), i = 1, ~ .
Set
Lo
=CL(dld2).
Then and it follows from the structure of Aut(Q2),
thatLo
isconjugate
toL+
as asubgroup
ofAut
(Q2)
in the sense of(1.14). Especially, Lo
is auniquely
determinedsubgroup
of Aut(Q)
and thusM
isuniquely
determined. Itfollows,
that M has the structure
given
in thefollowing
lemma :(2.1). LEMMA. Q
=Ql * Q2 ’"’"’ Q2.
For elements ofQ
we use the nota-tion of
(1.9). L
=QLo, Lo
=ZF, t~, L3(2).
Withrespect
to thebases
vi2’, v23’~
ofi E {::l:: 1, :::l::: 2}
andz3~
of Z we haveand
(gq)*
for every-Further
C’B (.F’ )
=Sp~ ( 2 )’
and the elements ofB1
arerepresent-
ed in the natural way on the
elementary
abelian groups~,~==1,2~3.
The
operation
ofB,
on has beengiven
in(1.15)
withrespect
tothe bases
V(i) zl,
where z = z1 for i =1, z
= fori = 2 and z = f or i = 3.
We have
CB(Lo)
= =N(K)
r1-81,
where K =k2~
EE
(B1), k1 ’-~ (1, 3, 5), k2-,--~ (2, 4, 6),
vw(1, 2) (3, 6, 5, 4)
andSet
vo E Bl
such thatv~ ~ (3, 4 ) ( 5, 6 ) .
ThenC’Q(v2)
=V -1(V2
+Y-~) Bl
containsexactly
twoconjugacy-
classes of
elementary
abelian groups of order 4 withrepresentatives .~1
and where
We have =
E84
and =-~-
rvE2’.
SetV =
X2CQ(X2).
ThenV -
PROOF. The bulk of the lemma follows from the
fact,
that wecan choose so, that
Q
--- and that theoperation
of
Lo
onQ1
andQ2
is of dihedraltype
in the sense of(1.7).
It is a mat-ter of direct
calculation,
thatC(L,) n B =
It follows from the3-subgroup-lemma,
that[(Kv~ )’, Lo] _ [K, Lo].
As v centralizesLQ/Z
and
Z,
weget [Kw~, Lo]
= 1.(2.2)
LEMMA. Let TT c T E(M).
Then V is theonly elementary
abelian
subgroup
of order 211 of T.PROOF. We have
T/Q
=Ð1
xD2,
whereDie
ESyl2 (B), D2 E Syl2 (L).
Denote
by Di
the inverseimage
in T =1,
2.Let
.E211.
(1 )
ThenA n Q
is contained in the inverseimage
U of Butii - t
andso
V;2), v~3~ ~~ E ~ ~ 1,
::i::21 >
7.E4
X(DS)4
andZ( U) =
Z.Further
C(a) ~
Z. ThusCQ(a)
doesn’t contain anelementary
abeliansubgroup
of order 27. It followsj.AI:>32,
a contradiction.(2 )
A CDl :
IfA çt D1,
there is an involution aE A - Q
suchD2.
As ii inverts an element of order 5 inB,
we haveI~Q((i)1
=26. Further Z ~ C(a)
and thus It follows~ A ~ ~ 8
and a contradiction to(1).
..We have A
C DI ,
7 A nQ ~ B297
= 4. All the involutions in the cosetv2Q
are contained inQ).
ThusY n Q c A
andA= V.
PROOF. Set J = x2 =
1, ~Q: - 4}.
We have W = - Y =~W
nJ~..Assume (M), (G).
Then T CTl, )TijT)
= 2. Choose x ET1-T.
ThenQ, Z,
butZx_C Q,
as>219
for z E Z. ThusQx
iselementary
abelian andIQael : 16.
(1) Qx r)
V =1>:
Assume thecontrary.
We haveQx n
V =Wx. So there is an
element y
yY such thatV ) - Q.
As we have =W ^J E29.
On theother hand and as So
C(yx) W ç Q
and a contradiction.Clearly
_