C OMPOSITIO M ATHEMATICA
K ENNETH A. B ROWN
Quotient rings of group rings
Compositio Mathematica, tome 36, n
o3 (1978), p. 243-254
<http://www.numdam.org/item?id=CM_1978__36_3_243_0>
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243
QUOTIENT
RINGS OF GROUP RINGSKenneth A. Brown
Sijthoff & Noordhoff International Publishers - Alphen aan den Rijn Printed in the Netherlands
1. Introduction
In this paper we continue the
study
of the maximalquotient ring
ofa group
algebra,
initiatedby
Formanek[3].
Webegin by fixing
somenotation.
Throughout,
G will denote a fixed group, K afield,
and KG the groupalgebra
of G over K. Inaddition,
we writeso that
4 (G)
is theFC-subgroup
ofG,
andThus à(G) and à’(G)
are characteristicsubgroups
ofG;
see[8]
Lemma 19.3 for details.
If R is a
ring, (with 1),
we shall denote the maximalright quotient ring
of Rby Qmax(R),
and the classicalright quotient ring
of Rby Q,I(R),
whenever this latterring
exists. For basicproperties
ofmaximal
right quotient rings,
we refer to[6].
The centre of thering R
will be denoted
by C(R).
The
study
ofquotient rings
ofarbitrary
groupalgebras
wasbegun by
M. Smith[9],
who showed that if KG is asemiprime
groupalgebra
for which
Q,I(KG) exists,
thenIn
[7],
Passman demonstrated that(1)
remains true without theassumption
that KG issemiprime.
In[3],
Formanek showedthat,
assuming
once more that KG issemiprime,
an identification analo- gous to(1)
can be made for maximalright quotient rings.
In this paper, we extend Formanek’s work
by showing
that if wereplace
theassumption
that KG issemiprime by
thehypothesis
that4+(G)
isfinite,
the main result of[3]
remains true. Thatis,
we proveTHEOREM A: Let KG be a group
algebra,
and supposethat 4+(G)
is
finite.
ThenQmuX(C(KG))
may beidentified
with the centreof Qmax(KG).
The identification described in Theorem A is "natural" in the sense
that it
corresponds
to the identification obtained in thesemiprime
case
by Formanek,
and it will beexplicitly
described in the course ofthe
proof
of the theorem.There are two main ideas involved in the
proof
of Theorem A. The first was observedby Formanek,
whoproved
in[3],
Theorem7,
that if KG is any groupalgebra, C(Qmax(KG»
is asubring
ofQmaX(K4 (G)).
The second is a result from[2],
also obtainedby Horn, [4],
which states that if4 +(G )
isfinite, QcI(K,j(G»
exists and is aQF-ring,
and so inparticular
isequal toQma,(KA(G».
Oncombining
these two
facts,
weobtain,
as an intermediate stage in theproof
ofTheorem A:
PROPOSITION 8:
If,j + (G)
isfinite,
Theorem A is deduced from
Proposition
8by examining
the struc-ture of
Qci(C(KG».
2. Basic results
In this section we restate, in forms
adapted
to our purpose, some results from[2], [3]
and[7].
We also assemble some facts aboutquotient rings.
We shall for the most part use the formulation of the maximalright quotient ring
of aring
in terms ofhomomorphisms
defined on dense
right ideals,
as introducedby Utumi;
see[6], §4.3.
Inbrief,
the maximalright quotient ring Q
of aring R
may be viewed asthe set of
pairs (D, f),
where D is a denseright
ideal of R and f is anR-homomorphism
from D toR,
and where two suchpairs (D,, f,)
and(D2, f2)
are identified iff1(d)
=f2(d)
for all dEDi
nD2.
Let R be a
subring
of aring
S. Then S is called apartial right quotient ring of
Rif,
for every O;j:s E S,
is a dense
right
ideal ofR,
ands(s-lR) -#
0.We shall denote the set of
regular
elements of thering
Rby ’CR(O)-
We
require
thefollowing elementary
facts aboutquotient rings
anddense
right
ideals.LEMMA 1: Let
Q
be the maximalright quotient ring of
aring
R.(a)
An element aof Q
lies inC(Q)::>a
commutes with everyelement
of
R.(b) If
S is apartial right quotient ring of R,
theidentity
map on Rcan be
uniquely
extended to amonomorphism of SR
intoQR,
and thismap is a
ring homomorphism.
(c)
Let T be amultiplicatively
closed setof regular
elementsof R,
and suppose that R
satisfies
theright
Ore condition with respect to T.Then the
over-ring of
R obtainedby inverting
the elementsof
T is apartial right quotient ring of
R.(d) If
D and E are denseright
idealsof R,
so is D f1 E.(e) If
D is a denseright
idealof R,
and S is apartial right quotient ring of R,
then DS is a denseright
idealof
S.(f) If
I --iR,
I is a denseright
idealof
R::>theleft
annihilatorof
I iszero.
PROOF:
(a) =>
Clear.Ç:
LetIR
denote theinjective
hull ofRR,
and put H =HomR(IR, IR).
Then
Q
=HomH (HI, HI ), (see [6], §4.3),
and if a commutes withevery element of
R,
a E H. Thus a commutes with every element ofQ.
(b)
See[6], §4.3, Proposition
8.(c)
Thisis
immediate from the definition.(d)
See[6], §4.3,
Lemma 3.(e) By [6], §4.3, Proposition 4,
we must show that if 0 7é si E,S,
S2 E
S,
then there exists s E S such that sls:,é 0 and S2S E DS.By (b),
we can consider S as a
subring
ofQ,
andby definition, s11R
is adense
right
ideal of R.By [6], §4.3,
Lemma2, s2’D
is a denseright
ideal of
R,
soby (d), s11R n s2’D
is a denseright
ideal of R. Itfollows from the
proof
of[6], §4.3, Proposition
5 thatsince
S ç Q.
If we choose s E(sllR
ns2’D)
such that sis #0,
then s2s ED,
and theproof
iscomplete.
(f)
See[6], §4.3, Corollary
toProposition
4.LEMMA 2
[3,
Theorem1]: If
H is a subnormalsubgroup of G,
and D is a denseright
idealof KH,
then DG is a denseright
idealof
KG.Using
Lemma2,
Formanek showed in[3],
Theorem 2that,
when H is subnormal inG, Qmax(KH)
may be viewed as a certainsubring
ofQmax(KG).
This is doneby identifying
the element(D, f)
ofQmax(KH)
with the element(DG, f)
ofQmax(KG),
wherewhere
{gi:
i EIl
is aright
transversal to H in G. Formanek shows thatf
is well-defined. Note that DG is a denseright
ideal of KGby
Lemma 2.
THEOREM 3
[3,
Theorem7]: C(QmaX(KG))
is asubring of Qmax(K4 (G)).
In
considering
the aboveresult,
it isimportant
to bear in mind thenature of the
embedding
ofC(Qmax(KG»
inQmax(K¿j(G».
Formanekshows that if a e
C(Qmax(KG»,
then we can represent a as(D1G, f 1),
where
Dl
is a G-invariant dense ideal ofK4 (G), (so
thatD1G
is an ideal ofKG), f1(D1)
çK4 (G),
andfi
is a bimodulehomomorphism.
Theorem 3 follows from this fact via the
embedding
ofQmax(K4 (G))
in
Qmax(KG)
described above.The results of this paper will follow from an examination of
QmaX(K4(G)),
under theassumption
thatd+(G)
is finite. Crucial tothis
approach
is thefollowing special
case of[2],
Theorem B.THEOREM 4:
If A l(G)
isfinite,
PROOF:
By [8],
Lemma19.3, à(G)1,1+(G)
is a torsion-free abelian group, so4 (G)
is contained in the class 3 defined in[2].
In terms of the
representation
ofQmax(K4 (G)) by
means of denseright ideals, (2)
can beexpressed
as follows. The elementac-1
ofQci(K.d(G» corresponds
to the element(cK.d(G), [ac-1])
ofQmax (K4 ( G )),
wherethe
identity (2) implies
that every element ofQmax(K4 (G))
can be sorepresented.
If we now embedQmaX(K4(G))
inQmax(KG)
as des- cribedabove,
we see that each element ofQmaX(Kd (G))
can berepresented by
apair (cKG, [ac-’]), where a,
c EK4 (G),
cE KG(O),
and
Theorem 4 allows us to
apply
in the present context the results of Passman[7]
on the structure of the centre of the classicalright quotient ring
of a groupalgebra.
Infact,
an examination of theproof
of the main result of
[7]
shows that Passmanactually
obtains thefollowing
result.THEOREM 5
[7,
p.224]:
Let T be amultiplicatively
closed setof regular
elementsof
the groupalgebra KG,
such that KGsatisfies
theright
Ore condition with respect to T.Suppose
thatIf
a EC(Q),
whereQ
denotes thepartial right quotient ring of
KGobtained
by inverting
the elementsof T,
then there exist elements a, c EC(KG),
c E(CKG(O),
such that a =ac-1.
An
important ingredient
of Passman’sproof
of the above result is Lemma 2 of[7],
which states that an element ofC(KG)
isregular
inC(KG)
if andonly
if it isregular
in KG. Infact,
Passman provesslightly
more thanthis,
and it is this stronger form of his result thatwe shall need.
LEMMA 6
[7,
Lemma2]:
Let a be a central elementof KG,
and put H =(supp a).
Then a isregular
in KGif
andonly if
a is aregular
element
of
thering C(KG)
n KH.3. Proof of Theorem A
Theorem A will be
proved by showing
that whenL1 +(G)
isfinite,
therings
with which we are concerned areactually
classicalquotient
rings;
inparticular
we shall show thatC(QmaX(KG))
may be identified withQci(C(KG».
Withoutassuming 4+(G)
to befinite,
we havePROOF: If a E
C(KG)
and c EWCÇKG)(0),
it follows from Lemma 6 that cKG is a two-sided ideal of KG with zero lef t annihilator - inparticular,
cKG is a denseright
ideal ofKG, by
Lemma1(f).
Thus(cKG, [ac-’])
represents, in ournotation,
an element ofQmax(KG)"
and it is easy to check that this affords an
embedding
ofQc/( C(KG»
in
Qmax(KG).
Now under therepresentation
ofQmax(KG) by homomorphisms
on denseright ideals,
KG embeds inQmax(KG)
viathe map
where
It follows
that,
with a and c asabove,
the element(cKG, [ac-’])
ofQmax(KG)
commutes with every element ofKG,
and so lies in the centre ofQmax(KG), by
Lemma1(a).
PROPOSITION 8:
PROOF: We have to prove that the
embedding
described in Lemma7 is
actually
ontowhen J’(G)
is finite.By
Theorems 3 and4,
and inparticular
theidentity (3),
each element a ofC(Qmax(KG»
can berepresented by
apair (cKG, [ac-’]),
where a, c EKd (G),
c EcgKG(O),
andIf r is any element of
KG,
then since a EC( Qmax(KG»,
we havefor all d E
D,
whereD,
the intersection of the domains of the maps[ac-’r)
and[rac-’],
is a denseright
ideal ofKG, by
Lemma1(d).
NowK4 (G)
has a classicalright quotient ring, by
Theorem4,
so the subsetcgK.1(GlO)
ofcgKG(O)
is aright
Ore set inKG, by [10],
Lemma 2.6. Thusby
Lemma1 (c)
we can form thepartial right quotient ring Q
of KG obtainedby inverting
the elements ofcg K.1(GlO). By
Lemma1(b), Q
isa
subring
ofQmax(KG),
andby (4),
where we view the
multiplication
astaking place
inQ.
However,by
Lemma
1(e), DQ
is a denseright
ideal ofQ,
and sofor all r E KG.
We now
apply
Theorem5, taking
T =WKà(G)(0),
so that thepartial quotient ring Q
is as definedabove,
to deduce that thereexist b,
d EC(KG), d
ECKc(O),
such thatThus the
embedding
defined in Lemma 7 is onto, and theproof
iscomplete.
Theorem A will follow from the above result if we can show that
under the
assumption
that4 +(G )
is finite. Sinceby
Lemma1(c)
and(b),
to prove(5)
it isenough
to show thatsee
[6], §4.3, Proposition
2. This we shall do in Lemma10,
but first wemust prove that
Qci(C(KG)
is’locally
Artinian’. This follows from the next result and Lemma 6.LEMMA 9: Let H be a
finitely generated
normalsubgroup of 4 (G).
Then
is Artinian.
PROOF: Since H is a
finitely generated FC-group, H
contains acentral
subgroup
of finite index. Since thissubgroup
is alsofinitely generated,
H contains a torsion-free centralsubgroup Z,
normal inG,
such thatIH: Z/
00. Since Z is torsion-freeabelian,
KZ is a domain.Let a E
KZB{O};
then ifdenote the
finitely
manyG-conjugates
of a, which all lie in KZ asZ 1
G,
we havesince KZ is commutative. Put R =
C(KG) rl KZ,
so that R * =R)(0)
isa
right
divisor set ofregular
elements of KG. It follows from(6)
thatF,
thepartial quotient ring
of KZ formedby inverting
the elements ofR *,
is afield,
thequotient
field of KZ.Furthermore,
F contains the subfieldWe claim that
IF: LI oc.
Since Z is afinitely generated subgroup
of
à(G),
and Z is normal inG,
it follows thatCG(Z)
is a normalsubgroup
of finite index inG,
so that G =GICG(Z)
actsfaithfully
as agroup of
automorphisms
ofZ,
and so of KZ. Notice that G fixesR,
so that G acts on F as a group of fieldautomorphisms,
with fixed field L.To see
this,
observe that if88-’c
F is fixedby
all elements ofG,
where 8E R,
then6
E R and so83-’e
L. Henceby
GaloisTheory, [ 1 ],
Theorem14, F : LI = G
ce.Since
IH: ZI 00, KH@KzF
is a finite dimensionalalgebra
overF,
and so is an Artiniansubring
ofQ,I(KH),
so thatThus,
since[F : L[
00,Q,I(KH)
is a finite dimensionalalgebra
over L.By Lemma 6,
and we deduce that
Qcl( C(KG) rl KH)
is a finite dimensional L-algebra,
asrequired.
REMARK: The argument to show that
IF: LI
00 in the aboveproof
is
adapted
from theproof
of[8],
Theorem 6.5.LEMMA 10:
If a+(G)
isfinite,
PROOF: As observed
above,
it isenough
to prove thatQ,I(C(KG»
is its own maximal
quotient ring.
This will beaccomplished
if we canshow that
Qci(C(KG»
is theonly
dense ideal ofQci(C(KG».
Wemust prove,
therefore,
that every proper ideal ofQI(C(KG»
hasnon-zero annihilator.
We show first that :-
We shall denote the above
ring by
R.Take a,
c EC(KG),
c ECKG(O),
such that a
= ac-t E Qci(C(KG»BN[Qci(C(KG»],
and put H =(supp
a, suppc),
so that H is afinitely generated
normalsubgroup
ofL1(G). By
Lemma 9.is Artinian. Note that
since
Qcl(C(KG) n KH) ç Qcl(C(KG», by
Lemma6,
and sinceQcl(C(KG»
is commutative. Since a EQcl(C(KG) n KH),
thereexists 8
EQcl(C(KG)
nKH)
such thatThus
(7) follows, since (3
EQ,I(C(KG».
By [5],
Theorem2.1, R
is eitherArtinian,
or R contains an infiniteset of
pairwise orthogonal idempotents.
If the latter is the case, thenby lifting
overN[Qcl(C(KG»]
we deduce thatQcl(C(KG»
must havean infinite set of
orthogonal idempotents.
Aspreviously noted,
since4+(G)
is finite Theorem A of[2] implies
thatQcl(K.1(G»
exists and isArtinian. Now
C(KG)
is asubring
ofK4(G),
and indeed it follows from Lemma 6 thatQci(C(KG»
is asubring
ofQci(Ki1(G».
Inparticular, therefore, Qci(C(KG»
mustsatisfy
thedescending
chaincondition on annihilator ideals. Since this
precludes
the existence ofan infinite set of
orthogonal idempotents
inQci(C(KG»,
we deducethat R is
Artinian,
saywhere é;
= ëE R,
andRéi
is afield,
1 i :5 n.Now
and
N(C(KG’))G N(KG).
Since4 +(G )
isfinite, N(KG)
isnilpotent, by [8],
Theorem20.3,
and soN[Qc/(C(KO»)]
is alsonilpotent. Lifting {e., e2, ..., en}
to acomplete
set oforthogonal idempotents le,,
e2, ...,en)
ofQc/( C(KG »,
we conclude thatwhere f or i =
1,..., n,
which is a
field,
andN[Qcf(C(KG»e;]
isnilpotent,
so thatQcf(C(KG»e¡
is a localring.
It is now clear thatQcf(C(KG»
is theonly
dense ideal ofQcf(C(KG»,
thusproving
the lemma.For
convenience,
we summarise the main steps in theproof
ofTheorem A.
PROOF OF THEOREM A:
We are
given that à’(G)
isfinite,
and we have to show thatBy Proposition 8,
and
by
Lemma10,
The theorem follows.
REMARKS:
(i)
In view of theproof
of Lemma10,
it is natural to ask whetherQ,(C(KG))
isactually
Artinianwhen d+(G)
is finite. 1 do not know the answer to thisquestion. Clearly
it would be sufficient to show thatN[Qci(C(KG»]
is afinitely generated
ideal ofQci(C(KG»,
but
although N(KG)
is afinitely generated right
ideal of KG when4+(G)
isfinite, by [8],
Theorem20.2,
it is not clear that the desired result can be deduced from this fact.(ii) Since, when 4+(G)
isfinite, Qci(C(KG»
is its own maximalquotient ring,
onemight
suspect that thisring
isalways self-injective.
This is the case when G is
abelian,
forexample, by [2],
TheoremB,
and when KG issemiprime.
However it iscertainly
not the case ingeneral.
Forexample,
if we takethe
quaternion
group of ordereight,
and K is the field of twoelements,
thenC(KG)
isArtinian,
and soNow
C(KG)
contains the idealsand since the
augmentation
ideal A of KG isnilpotent,
andKG/A = K,
KG has no non-trivialidempotents.
Thus ifC(KG)
is a self-injective ring,
it must be an essential extension of both I and J. This isclearly impossible.
REFERENCES
[1] E. ARTIN: Galois Theory, Notre Dame Mathematics Lectures, No. 2, Notre Dame, Indiana, 1959.
[2] K.A. BROWN: Artinian quotient rings of group rings. J. Algebra, 49 (1977) 63-80.
[3] E. FORMANEK: Maximal quotient rings of group rings, Pac. J. Math., 53 (1974), 109-116.
[4] A. HORN, Twisted group rings and quasi-Frobenius quotient rings, Archiv der Math., 26 (1975), 581-587.
[5] I. KAPLANSKY, Topological representations of algebras II, Trans. Amer. Math.
Soc., 68 (1950), 62-75.
[6] J. LAMBEK, Lectures on Rings and Modules, Ginn-Blaisdell, 1966.
[7] D.S. PASSMAN, On the ring of quotients of a group ring, Proc. Amer. Math. Soc., 33 ( 1972), 221-225.
[8] D.S. PASSMAN, Infinite Group Rings, Marcel Dekker, New York, 1971.
[9] M. SMITH, Group algebras, J. Algebra, 18 (1971), 477-499.
[10] P.F. SMITH, Quotient rings of group rings, J. London Math. Soc., (2) 3 (1971), 645-660.
(Oblatum 11-I-1977) Mathematics Institute
University of Warwick Coventry CV4 7AL U.K.