C OMPOSITIO M ATHEMATICA
K UANG -Y EN S HIH
P-division points on certain elliptic curves
Compositio Mathematica, tome 36, n
o2 (1978), p. 113-129
<http://www.numdam.org/item?id=CM_1978__36_2_113_0>
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113
P-DIVISION POINTS ON CERTAIN ELLIPTIC CURVES
Kuang-yen
Shih*1. Introduction
Let p be an odd
prime,
E =(_1)(p-l)/2@
and k =Q(B/,Ep).
Consider anelliptic
curve E defined over k.Adjoin
to k the x-coordinates of thepoints
of order p on E and denote theresulting
fieldby Fp (E),
orsimply Fp.
It is known(see [7, 6.1])
thatFp
is a Galois extension of k andGal(Fplk)
can be identified with asubgroup
ofGZ.(Z/pZ)/{±l2},
where
Note that if
Gal(F,/k)
is the wholeG’Z(Z/pZ)/{±l2},
thenFp
containsa subfield F normal over the
quadratic
field k such thatGal(F/k)
isisomorphic
toPSL2(Z/p Z).
One purpose of this paper is to discusssome conditions on E under which
Fp(E)
contains a subfield K normal over the rational number fieldQ
so thatGal(K/Q)
is isomor-phic
toPSL2(Z/pZ).
Denote the non-trivial
automorphism
of kby
or.Suppose
there are aquadratic
non-residue N modulo p, and anN-cyclic isogeny
À of E toits
conjugate
EU such that(1.1)
C = ker À is rational overk,
andHere
E(N)
stands for the group of N-divisionpoints
on E. Theexistence of such À
implies
thatFp
is notonly
normalover k,
but alsoover
Q.
This will beproved
in§2.
We also determine the Galois groupGal(Fp/Q).
We show inparticular
thatGal(F,/Q)
is a group extensionof
PSL2(Z/pZ)
ifSijthoff & Noordhoff International Publishers-Alphen aan den Rijn
Printed in the Netherlands
Using
thetheory
of arithmeticautomorphic functions,
we con-structed in
[5]
Galois extensions overQ
withPSL2(Z/p Z)
as Galoisgroups for a certain
family
ofprimes
p. In§3,
we show that the above result serves as a modularinterpretation
of this construction. We work out some numericalexamples
in§4.
Careful consideration of the
generic
case enables us to write downgeneral equations
with Galois groupPSL2(Z/pZ)
for smallp’s.
In§5,
we carry this out for p =
5, 7,
11 and 13 in the fashion of Fricke[2].
2. The Galois group
Gal(F(pn)/Q)
Let E be an
elliptic
curve defined over k =Q(Vep)
and À anN-isogeny
of E to EUsatisfying
conditions(1.1)
and(1.2).
We furtherassume that
Aut(E) = {±id.}.
Take a non-zeroholomorphic
differentialcv on E rational over k. Then
for some s E C.
(See [8, §10]
for similardiscussion.)
For T EAut(C/k),
À-: E ---> E’ is anisogeny,
andby (1.1),
ker A’ = C. In view of theassumption Aut(E)
={±id.},
this shows A T = ±À. Hence s’ = s or -s,depending
on whether 03BB T = À or -A. It follows that À is definedover
k(s),
and[k(s) : k]
= 1 or 2.Now let T be an
automorphism
of C such that T = a on k. From(2.1)
we have w -,k’ = sT03C903C3 HenceObserve that 03BB T À has
E(N)
=ker(N - id.)
as its kernel. Infact, by (1.2)
we haveSince the
degree
of À’ o,k isN2,
this proves our assertion. Therefore À’ o À = ±N . id.By (2.2),
we haveFrom this we see that s does not
belong to k,
for otherwise(2.3)
wouldimply
that N is aquadratic
residue modulo p. Therefore[k(s) : k]
= 2.Especially,
À is not defined over k.Note that s has
exactly
fourconjugates
overQ, namely, s,
-s,N/s and -N/s.
Hencek(s)
is normal overQ
andGal(k(s)/Q)
isisomorphic
to the Klein
four-group.
We use o-i(resp. 03C32)
to denote the element ofGal(k(s)/Q)
which sends s to -s(resp. N/s).
The restriction of 03C3i(resp. U2)
to k is id.(resp. o-).
Let
be an affine
equation
of E. Then the canonical function h on E is defined to beLet
E(p")
be the group ofp n-division points
on E. Thenis a Galois extension of k.
Fix tl,
t2 EE(pn)
so thatE(pn)
=zt,
+Zt2.
Then we can define an
injective homomorphism 0
ofGal(F(pn)/k)
into
GL2(Z/pnZ)/{j:12},
as in[7, 6.1].
ForTE Gal(F(pn)/k), ~(T)
isrepresented by
theintegral
matrix a such thatIt is known that the field
F(pn)
contains thecyclotomic
fieldQ(C), 03B6 = exp(21ri/p").
If a EM2(Z)
represents0(t),
T EGal(F(pn)/k),
thenyT = (deta,
see[7,
prop.6.3].
Since T = id. on k =Q(Vep),
we see thatdet a is a
quadratic
residue modulop n.
ThereforeG,
theimage
of~,
is contained in
G’L*(Z/p"Z)/{±Î2},
whereGL(Z/pnZ) = {a
EGL2(Z/pnz)ldet
a is a square in(Z/pnZ)x}.
Let E’ =
EU, h’
the canonical function onE’,
andObviously
thecomposite F(pn)F’(pn)
is normal overQ.
We show thatF(pn)
=F’(p n),
soF(pn)
is a Galois extension ofQ.
Let T be anautomorphism
of C which induces theidentity
map onF(p n).
Thenwe have
Put
tÍ = À(tt)
andt2 = À(t2).
ThenE’(pn) = ZtÍ + Zt2.
As observedearlier,
03BBT = À or -À.Using
this we seeeasily
thatIn other
words,
T induces theidentity
map onF’(p n).
SoF’(pn)
is asubfield of
F(pn). Similarly, F(pn)
is a subfield ofF’(p n).
HenceF(p n) = F’(pn).
Thus
F(p")
is a Galois extension ofQ. Identify Gal(F(p")/k)
withthe
subgroup
of
Gal(F(pn)/Q),
and denote the non-trivial coset of Aby
B. Anelement p of
Gal(F(p n)/Q) belongs
to B if andonly
if p = 03C3 on k. Let ti , t2 EE(p n)
andtÍ, t2 E E’(p n)
be as above. Then for p E B we havefor
some (3
EM2(Z).
PROPOSITION 1: The determinant
of 03B2
is aquadratic
residue modulop n.
PROOF: Let e
(resp. e’)
be the Weilpairing [7, 4.3]
onE(p n )
xE(pn) (resp. E’(pn) x E’(pn». Then 03B6 = e(tl, t2)
is aprimitive p n-th
root ofunity.
We haveSince p = u on k and N is a
quadratic
non-residue modulo p, weconclude that
det (3
is aquadratic
residue modulop n.
Let
03C8(p)
be the element ofGL(Z/pnZ)/{±l2} represented by {3.
Then Q
is a well-defined one-to-one map from B toGLt(Z/pZ)/(± l).
Theimage
G’of tp
is a coset of G.(It
canhappen
that G’ =
G.) Obviously
we havefor T, T’ E A and p E B. And it is not hard to see that
for p,
p’ E {3, using
the factthat À 8 0 À = ±lV,
where & is anyautomorphism
of Cextending
p.Let
Gl
be the setconsisting
of all(IL, 1) with i£
E G and(g’, a)
withg’E
G’. Introduce a group structure onG, by employing
the follow-ing multiplication
table:The above argument shows that
Gal(F(pn)/Q)
isisomorphic
toG1.
Define a
homomorphism X
ofG,
toPSL2(Z/P"Z) by
Denote
by
D thesubgroup
ofG’Z(Z/p"Z)/{±l2} consisting
of ele-ments
represented by
scalar matrices. Then the kernelof X
isLet K be the subfield of
F(pn) corresponding
toker x. By
Galoistheory,
K is normal overQ
andGal(K/Q)
isisomorphic
to thesubgroup x( G1)
ofPSL2(Z/pnZ).
Now assume
G = GLt(Z/p Z)/(± l).
Then G’ = G andX(G1) = PSL2(Z/pnz).
Hence we haveTHEOREM 2: Let notation be as above.
If Gal(F(pn)/k) is
isomor-phic to
thefull G’L*2(Z/p"Z)/{±l2},
thenF(p n ) contains a subfield
Knormal over
Q
such thatGal(K!Q) is isomorphic to PSL2(Z!pnZ).
3. The twisted modular curve
Xo(N)
Let
H = {z E ci Im(z) > O}
be thecomplex
upper halfplane.
Thegroup
acts on H
by
fractional linear transformations. For a natural numberM,
letfm
be the field of modular functions of level M on H whose Fourierexpansions
withrespect
toqM = exp(27riz/M)
havecoefficients in the
cyclotomic
fieldQ(Cm), Cm
=exp(21ri/M).
Put F =U §M= FM.
Let
GL2(A)
be the adelization ofGL2
andGL+2(A)
thesubgroup
ofGL2(A) consisting
of elements whose components atinfinity belong
toGL2(R).
The groupGL2(A)
acts on F as a group ofautomorphisms
inthe way described in
[7, 6.6].
Theimage
off
E f¥ under x EGL2(A)
will be denoted
by f’.
Denote
by Ze
thering
of e-adicintegers.
PutThen U is a
locally
compact opensubgroup
ofGL2(A).
For a naturalnumber
M,
letUM
be thesubgroup
of Uconsisting
of those a =(ae)
such that ae =12(mod
M .M2(Ze))
for all finite t.By [7, (6.6.3)], FM
is the subfield of F fixedby SM
=QX . UM.
The fieldFl
isgenerated
over
Q by
the modular invariantj.
Let N be a
positive integer.
Denoteby
03C9N the element ofGL2(A)
whose component at a rational
prime dividing N
is[ 0 -1 1 lIN] and
atwh ose component
at
arational prime
ivid ing N is -1 0 0 |’ and atall other
places
theidentity
matrix12.
Note that 03C9N can be decom-posed
as x . 03B1, where x E U and 03B1 =| -1 0 EGL+2(Q).
Therefore03C9N maps
FM
intoFMN.
When(M, N) = 1,
the Fourier coefficients off
EFM
andf03C9N
EFMN
are related as follows.PROPOSITION 3:
Suppose (M, N)
= 1. Letbe the Fourier
expansion of f
EFM.
Thenwhere u denotes the
automorphism of Q(Cm)
that sends(M
to03B6NM.
PROOF: Let
Then x =
(xl)
E U andHence it is sufficient to show
For a E
M-1Z2, ~ Z2, define f a
as in[7, 6.1].
Then thef a’s together
with the modular
invariant j
generateFM
overQ,
see[7,
prop.6.9].
The Fourier coefficients of
fa’s
are knownexplicitly,
and thoseof j
are rational. For these
generating functions, (3.1)
can be verified in astraightforward
way. Therefore(3.1)
holds for allf
EJm. Q.E.D.
Now let
jM
be the modular function of level M definedby jm(z) = j(Mz).
The fieldi%M
=Q(j, jm)
is thefixed
subfield ofTM
=QX . U M,
whereIf
(M, N) = 1,
thenwN’TmNwN
=TMN
and03C92NE TMN. Therefore,
wN induces an involution onLMN. Actually,
this isexactly
the Atkin-Lehner involution WN on
YmN: i --> jN, jM ~~ imN.
This follows fromProposition 3,
or moredirectly,
from the observation03C9NwNl E TMN.
PROPOSITION 4: For every M
relatively prime
toN,
úJN induces the Atkin-Lehner involution WN onQ(j, jMN).
Now take
M = p n,
and assume that N is aquadratic
non-residue modulo p. Then mN induces the non-trivialautomorphism cr
onk =
Q(Vep).
Let£mN (resp. LN)
be the subfield ofk5tMN (resp. k5tN)
fixed
by
IWN. ThenQ
isalgebraically
closed inif MN
and inifN.
Let
Xo(N) (resp. Xo(N))
be aprojective non-singular
curve overQ
whose function field overQ
isisomorphic
toYN (resp. LN).
Thenboth
Xo(N)
andXo(N)
are models of thequotient
of Hby
thecongruence
subgroup
Let
WN
be the involution ofXo(N)
inducedby
the involutionz*-->-IlNz
of H. ThisWN corresponds
to the involution wN onYN-
Now ’;N
is the fixed subfield ofkLN
=kYN
under OJN.Therefore, by
a well-known fact(see [7, Appendix 6]
forexample),
there is a bira- tionalbiregular map f/1
ofXo(N)
toXo(N)
over k such that03C803C3 0 03C8-1 =
WN.
As before a stands for the non-trivialautomorphism
of k. Wehave the
following proposition,
which isjust
arephrasing
of[5,
Lemma
9].
PROPOSITION 5: A
point
xof Xo(N)
is rational overQ if
andonly if
y =
03C8(x)
EXa(N)
is rational over k andy’
=WN(y).
COROLLARY. There is no
Q-rational
cuspson Xo(N).
PROOF:
Suppose s
EXo(N)
is aQ-rational
cusp. Thenby Proposi-
tion
5, t
=f/1(s)
is rational over k. Since all cusps ofXo(N)
are rationalover
Q(CN), t
is rational overQ. However,
we have t" =WN(t).
Therefore
WN(t)
= t, i.e. the cusp t ofXo(N)
is a fixedpoint
ofWN.
But this is not the case, see for
example [3,
prop.3]. Q.E.D.
Now any non-cusp k-rational
point
y ofXo(N)
isrepresented by
apair (E, C) consisting
of anelliptic
curve E defined over k and ak-rational
cyclic subgroup
C of E of order N. If y is sorepresented,
then
WN(y)
isrepresented by (EIC, E(N)/C). Therefore, by Prop.
5and its
Corollary,
anyQ-rational point
ofXo(N)
isrepresented by
a k-rationalpair
such that(E’, CU)
isisomorphic
to(E/C, E(N)/C).
Forsuch
(E, C),
there is anisogeny À
of E to EU with kernel C such thatA(E(N))
= C’. Then k satisfies(1.1)
and(1.2).
In thefollowing,
weshall call a
pair (E, À)
rational over k and of type(N)
if E is anelliptic
curve over k and À is anisogeny
of E to EU withproperties (1.1)
and(1.2).
We state the above observation as the firstpart
of thefollowing:
THEOREM 6:
Every Q-rational point of Xo(N)
isrepresented by
a k-rationalpair (E, À) of
type(N). Conversely,
every suchpair
represents aQ-rational point of Xo(N).
The converse
part
of the theorem can beproved by reversing
theabove argument.
Let x be a
Q-rational point
ofXo(N) represented by (E, À).
Con-struct the
algebraic
number fieldF(p N)
from E as in§2.
Choose apoint zo E H
which isprojected
to x. Consider the Galois extensionFMLN (M = pn)
ofk5tN.
Under thespecialization f --> f (zo), FMLN (resp. 5tN)
isspecialized
toF(pn) (resp. k).
HenceFM0Nlk0N
isspecialized
toF(pn)lk.
NowHence in view of Hilbert’s
irreducibility theorem,
we have the fol-lowing :
THEOREM 7:
Suppose Xo(N)
is a rational curve. Then there areinfinitely
many k-rationalpairs (E,À) of
type(N) satisfying
thecondition
Gal(F(pn)/k) ~ GLt(ZlpZ)/(±l).
Here k denotes thequadratic field Q(N/,Ép).
The situation under which
Xo(N)
is a rational curve wasgiven
astable
(4.4)
in[5]. Especially,
we know thatXo(N)
is rational when N =2,
3 or 7.Combining
this with Theorems 2 and7,
we obtained the main result of[5]: If p is an
oddprime
such that2, 3,
or 7 is aquadratic
non-residue modulo p, thenPSL2(Z/pnZ),
n ?1,
can be realized as the Galois groupof
some Galois extension overQ.
In thefollowing section,
wegive
someexamples
ofpairs (E,
03BB) that generate such extensions.REMARK 1. The Galois group
Gal(FMLNlLN)
isisomorphic
toG,
of§2
with G =GLt(ZlpZ)1(±l).
This can bejustified
as follows.Firstly,
thesubgroup Gal(FMLN/kLN)
isisomorphic
toG,
see(3.2).
Secondly,
the restriction & of mN toFMLN
is in the center ofGal(FMLNILN).
Andthirdly, S2
= N -12
under the identification(3.2).
The extension
FMLNlLN
isspecialized
to an extension of the formF(pn)/Q
when the functions inFMLN
are evaluated at a rationalpoint
of
Xo(N).
REMARK 2: We discuss
briefly
the case where the genus ofXo(N)
is 1. Under thiscondition,
it is known[2]
that5tN
isgenerated
overQ
by
two functions or and T withdefining equation cT2
=f(T),
wheref(x) E Q[x]
is ofdegree
4.Furthermore,
wN fixes T andchanges
thesign
of a. Therefore the twistitN
ofi%N
over k =Q(%/Ep)
isgenerated
over
Q by x
= T and y =(Ep )-1/203C3,
with thedefining equation Epy2 ==
f (x).
SoXo(N)
isexactly
the twisted curve of Birchinvestigated
in[1].
As in[1],
we see from the zeta-function ofXo(N)
that the Birchand
Swinnerton-Dyer conjecture predicts
that there areinfinitely
many rational
points
onXo(N)
if p - 1(mod 4).
In otherwords,
there should beinfinitely
many k-rationalpairs (E, À)
of type(N)
in view ofTheorem 6. It would be
interesting
to know whether suchpairs actually exist,
and ifexist,
whether any of them satisfies(1.3).
4. Numerical
examples
For each N such that
Xo(N)
is a rational curve,5tN
isgenerated by
a
Hauptmodul
TN such that itsimage
under wN iscNlrN
for some rationalinteger
cN. PutThen
LN = Q(s, t)
andS2 _ Ept2 =CN-
It follows that2N
is pure transcendental overQ
if andonly
if eN is the norm of some element from k. Thisgives
anotherproof
of[5, Prop. 11].
Suppose iÙN
is pure transcendental overQ,
and leta, b
EQ
be such thata2 - Epb2
= cN. Thengenerates 2N
overQ. Express j E ItN
=Q(TN)
in terms of TN.Solving
TN in terms of xN from
(4.1),
we see that every rational value of xNgives
rise to a valueof j
in k =Q(Y Ep).
Let E be anelliptic
curvedefined over k with this value as its
j-invariant.
Then there is anisogeny À
such that(E, À)
is of type(N). Conversely,
allpairs
oftype (N)
are obtained this way. For agiven (E, À),
we can check whether(1.3)
is satisfiedusing
the method of[4]
and[6].
Thefollowing examples
are obtainedby
thisprocedure.
1°. p
=5,
N = 2. Denote the fundamental unit(1
+V5)/2 of Q(v5)
by
u. LetThe discriminant of E is 4 =
33u
14 and thej-invariant
isBy [2,
page394], j
EY2
=Q(T2)
has theexpression
Hence
jE = j(T2)
with T2 =(3
+V5-)1(3 - V/5).
This value of T2 cor-responds
to x2 = 3.Therefore,
there is anisogeny
À of E to EU suchthat
(E,À)
is oftype (2).
We show that the Galois group G =
Gal(F(5)/Q(V5))
isthe
fullG’L*2(Z/5Z)/{±l2}.
Reduce E modulo theprime
idealt=(6-V5)
ofnorm n = 31. Let A be the number of rational
points
on the reducedcurve E modulo 1 and t = 1 + n - A. Then we have A =
34, t
= -2 andt2 - 4n
= 5 .(-24).
In view of[6,
Lemma1],
the order of G is divisibleby
5.By [4,
prop.15],
G either containsPSL2(Z/SZ)
or is contained in a Borelsubgroup.
The secondpossibility
can be ruledout
by looking
at the curve E reduced module 1 =(4 + V5).
The normof
1 is n =11,
the number of rationalpoints
on the reduced curve is A = 16. Hence t = 1 + n - A = -4and t2 -
4n = -28. Since -28 is aquadratic
non-residue modulo5,
G is not contained in a Borelsubgroup.
So G must containPSL2(Z/SZ).
On the other handF(5)
containsQ(03B65).
Hence theimage
of G under the determinant map is the fullsubgroup
ofquadratic
residues. This shows G=M(Z/5Z)/{±l2}.
2° p =
5,
N = 3. Consider the curvedefined over
Q(N/5)
with discriminant-2433(1
+YS)2.
Thej-invariant
of E is
which can be written as
Hence
by [2,
page395],
there is anisogeny
À of E to EU such that(E,À)
isof type (3).
The Galois group G =
Gal(F(5)/Q(V5))
in this case is a Borelsubgroup.
Infact,
we haveu
being
the fundamental unit ofQ(V5). Hence,
in view of[2,
page399],
E has aQ(V5)-rational subgroup
of order 5. This shows G iscontained in a Borel
subgroup
B. We see that G isactually equal
to Busing
thefollowing
table.(Notation: 1
= aprime
ideal ofQ(V5),
n = norm of
1,
A = number of rationalpoints
on E reducedmod r,
and t =
1 + n - A.)
Let
K/Q
be the subextension ofF(5)/Q
considered at the endof § 1.
Then
Gal(K/Q)
isisomorphic
to thesubgroup
of
PSL2(Z/5Z).
An
elliptic
curve overQ(V-7)
with thisj-invariant
isThe discriminant of E is
243311 (2 + 1/-7)2.
From the way we con- struct E we see that there is anisogeny À
such that(E, A)
is of type(3).
We can show thatGal(F(7)IQ(1/-7))
=GLt(Z17Z)1(± l) using
thefollowing
data andreasoning
as inexample
1°.Then
and
with
T2 == (X2 + 2Y -19)/(x2 - 2V -19), x2 = 3.
Therefore there is anisogeny
À such that(E, À)
is of type(2).
We have thefollowing
table:Since -56 is a
quadratic
residue modulo19,
-28 aquadratic
non-residue,
and(-4)2/11
----2(mod 19),
we see that(1.3)
holds in view of[4,
prop.19].
5? p =
29,
N = 2. Let u =(5
+V29)/2
be the fundamental unit ofQ(N/29).
ConsiderThen d
= - 335u6(u - 1),
andjE
=2633/5u3(u - 1),
which can be writtenas
Hence there is an
isogeny
À of E to EU such that(E, À)
is of type(2).
We have the
following
table:By [4,
prop.19],
we see thatGal(F(29)/Q(Y29»
’=GLt(Z129Z)/(± 12).
5.
Equations
ofdegree 6, 8,
12 and 14Let
M = pn
and N aquadratic
non-residue modulo p. Then the Galois group of the Galois closure of2MN
overLN
isisomorphic
toPSL2(Z/pnZ).
We are interested in theequation
of the extension2MN/2N
when2N
is pure transcendental overQ.
We consider thefollowing
cases in this section:(M, N) = (5, 2), (7, 3), (11, 2)
and(13,2).
1°
(M, N) = (5, 2).
Let T2(resp.
T5,T)
be theHauptmodul
forro(2) (resp. ro(5), To(10)).
We have thefollowing
identities from[2,
p.407-408]:
From the same source, we know that W2 permutes T2 with
1/T2
and TSwith
T2(2T
+5)/(T
+2)2.
It follows thatTherefore both
and
are invariant under úJ2, hence
belong
to’;’10. Actually, -Iîio
=Q(s, t).
We have
5s2 - t2
= -20. Hence210
=Q(y)
withPut
Then
L2
=Q(x).
To find an
equation
for the extensionQ(y)/Q(x),
solve T in terms ofy from
(5.2):
Substituting (5.4)
in(5.1)
and then(5.1)
in(5.3),
we obtainThis is an
equation
in y overQ(x)
withPSL2(Z/SZ)
as Galois group.where q
is the Dedekind function. ThenQ(T)
is the subfield ofI£21
fixedby
W21. We have TW3 =lIT.
Thereforeis fixed
by
W3, and hencebelongs
toîll.
The fieldQ(y)
has index 2 inY21.
Let r3 be the
Hauptmodul
forFO(3).
PutThen
L3
=Q(x)
andL21= Q(x, y).
Solve T in terms of y and T3 in terms of x. Then an
equation
forQ(x, y)/Q(x)
can be obtained from the modularequation connecting
Tand T3. To obtain such a modular
equation,
we follow Fricke’smethod.
Note that
T3 21
=T61T3.
Therefore the functionT(T3 + T6/T3)
is in-variant under w21, hence
belongs
toQ(T). Counting poles
and zeros, we find the function is apolynomial
ofdegree
8 in T. Thecomparison
of the Fourier coefficients
gives
usThen T generates the subfield of
I£22
fixedby
wl l, and TW2 =lIT.
Asbefore,
we find22
=Q(x)
andL22
=Q(x, y),
whereThe
equation
forQ(x, y)/Q(x )
can be obtained from the modularequation
4?
(M,N) = (13, 2).
This case is similar to case 2°. The subfield ofY26
fixedby
W26 isgenerated by
We have T"’2 =
1/T. Proceeding
asbefore,
we find22 == Q(x),
and226
=Q(x, y),
whereThe modular
equation relating
T2 and T isSolving
T2 in terms of x and T in terms of y, andsubstituting
theresults in the above modular
equation,
we obtain anequation
ofdegree
14 in y overQ(x)
which admitsPSL2(Z/13Z)
as Galois group.REMARK 1: Our method
depends
on the factthat,
for each of the above(M, N), Xo(MN)
modulo a certain Atkin-Lehner involution is arational curve. In view of
Ogg’s
result[3],
the above 4examples
exhaust all
interesting
cases that can be so treated.REMARK 2: The modular
equation
in 2° isequivalent
to33(T3/T3 +r’lr3)
=T4 - 14T3 + 45T2 + 66 T - 250, T = T + 1I T.
Note that T is the
Hauptmodul
for the groupgenerated by To(21),
W3 and W7.Similarly,
the modularequations
in 3° and 4° areequivalent
torespectively
and
Acknowledgment
1 would like to thank Professor Atkin for
showing
me theequations
that appear in
3°,
4° and Remark 2.REFERENCES
[1] B. J. BIRCH: Diophantine analysis and modular functions. Proc. Conf. Algebraic Geometry (Bombay, 1968) 35-42.
[2] R. FRICKE: Lehrbuch der Algebra III. Braunschweig 1928.
[3] A. P. OGG: Hyperelliptic modular curves. Bull. Math. Soc. France, 102 (1974) 449-462.
[4] J.-P. SERRE: Propriétés galoisiennes des points d’ordre fini des courbes elliptiques.
Inventiones Math., 15 (1972) 259-331.
[5] K.-y SHIH: On the construction of Galois extensions of function fields and number fields. Math. Ann., 207 (1974) 99-120.
[6] G. SHIMURA: A reciprocity law in non-solvable extensions. J. Reine Angew. Math., 221 (1966) 209-220.
[7] G. SHIMURA: Introduction to the arithmetic theory of automorphic functions. Publ.
Math. Soc. Japan, No. 11, Iwanami Shoten and Princeton University Press, 1971.
[8] G. SHIMURA: Class fields over real quadratic fields and Hecke operators. Ann. of Math., 95 (1972) 130-190.
(Oblatum 18-X-1976) Department of Mathematics
University of Michigan
Ann Arbor, Michigan 48104
Department of Mathematics University of Maryland College Park, Maryland 20742
*Partially supported by NSF grant MPS 75-07948.