A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
T AKAO K OBAYASHI
Propagation of singularities for a first order semi-linear system in C
n+1Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 12, n
o2 (1985), p. 173-189
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Propagation Singularities
for
aFirst Order Semi-Linear System in Cn+1.
TAKAO KOBAYASHI
Introduction.
We consider the non-characteristic
Cauchy problem
withsingular
datain the
complex
domain. We are interested in thesingularities
of the solu- tions in theholomorphic category.
This has beenintensively
studied forlinear
equations.
Few are,however,
known for non-linearequations.
Let us first observe the
simplest
ones:For k > 0 the solution u of
(1) (resp. (2))
issingular along
the non-charac- teristic surface(resp. {X 2k - 2t = 0}),
which differs for each k.That
is, singularities propagate along
various non-characteristic surfacesissuing
from~x
=0}.
The
following example,
due to T.Ishii,
is alsointeresting:
Let P bea linear differential
operator
of order m withholomorphic
coefficients andbe an
integer.
Assume that and thator m is odd. Then for any non-characteristic surface
K: 92
= 0 for P theequation
has a solution of the form u = x holo.ft.,
which rami- fiesalong
g.Therefore,
if the initial surface{t
=0}
is non-characteristic forP,
then for any non-characteristic surface .gissuing
from{t
= ri =0}
there is a solution to the
Cauchy problem
for Pu = u" whosesingularities propagate along
K.Pervenuto alla Redazione I’ll
Luglio
1983.Thus
singularities
do notnecessarily propagate along
characteristicseven for semi-linear
equations. Then,
when dothey
do so? Note that in the aboveexamples
the solutions are unbounded near the non-characteristic surfaces.Furthermore,
in(1)
and(2)
for - k >0, f/:.z (then
the initial dataramify
but arebounded)
the solutions u =x-k t)
and u = x-k/(1- 2x-2k t)i
aresingular only along
the characteristic surface(z
=0}
ina
neighborhood
of theorigin.
Motivated
by this,
we shall prove in this paper that if the initial dataare
bounded,
thensingularities
of the solutionspropagate (locally) along
characteristics for certain first order semi-linear
systems
with two charac- teristics in where the spacedimension n ~
1.In Section
1,
we state the mainresult,
Theorem 1 and some remarks.In Section
2,
we discuss the continuous deformation of contoursatisfying
certain conditions. When n =
1,
this is doneeasily.
In Section3,
weprove Theorem 1.
We
finally
remark that J. Rauch and M. Reed[1], [2]
discussedsingulari-
ties in detail for
hyperbolic
semi-linearsystems
in two variables in the realcategory.
1. -
Statements
of results.Let .~ c
(resp.
D’ cCnf be
an open connectedneighborhood
of theorigin
of(resp.
ofCn).
Letai(t, x), bi(t, x)
E0(-Q), i
=1,
..., n(t
EC,
x =
(x1,
...,Xn)
ECn)
andand
be
holomorphic
vector fields on S~. Here0 (Q)
is the set of allsingle-valued holomorphic
functions in Q. For a connected set U we denoteby
the universal
covering
of U. Weidentify many-valued holomorphic
func-tions on U with
single-valued
ones onGiven ramified data
~~,
=0})),
we consider theCauchy problem
for thesystem
where
f,
g EX C2).
Since we consider localproblems
near theorigin,
we may assume that Q’= Q n
{t
=0}.
Letp°
be anarbitrary point
in[2’ -
{Xl
=0~ .
Fix branches of UO and VO atpo. Then, by
theCauchy-
Kovalevskaja Theorem,
eq.(3)
has aunique
solution(u, v) holomorphic
near
p°.
Ourproblem
is theanalytic
continuation of the germs u, v atp°
in a
neighborhood
of theorigin
ofTHEOREM 1. Assume that
(A.1) ac1(0, 0) ~ b~(0, 4),
(A.2)
there is a constant.~Q
such thatThen there exists an open ball centered at the
origin
such thatNamely, for
anarbitrary point pO
E ú) r1ft
=0,
0153I =r0)
the germs u, v atpo
satisfying (3)
can beanalytically
continued toholomorphic functions
on- U
Kb»).
HereKa
andKb
are characteristicsurfaces issuing from
=
01.
úJdepends
onRo
in(4)
but not on UO and vO.With a,n obvious
change
of notations Theorem 1 is valid for vector- valued u and v. Forexample,
let n = 1 and A =A(t, x)
be aholomorphic
m X m matrix-valued function on Q. Consider the
Cauchy problem
for theunknown vector w =
(WI’
...,(w°, ... , 1 WO)
andw°
E{0153 == 01)) satisfy (A.2). Sup-
pose that
(i)
det(T
+A) == (r
+a(t, + b(t, x))l~’, (ii) a (0, 0)
~b (0, 0)
and
(iii)
all the(m 2013 l)-th
minors of T + A are divisibleby (r
+.
(z + b)N-1.
oThen,
we can reduce eq.(6)
to thediagonal form,
eq.(3)
withvector-valued u, v
whereXa - alat
+a(alax)
and.Xb
=alat -~-
Hence
wi’s
areholomorphic
on -(Ka
UKgb))
with some (o.In the
above,
if(iii)
does nothold,
then w may besingular along
non-characteristic surfaces. For
instance,
thepair u == ~"~
tan(x-4 t), v = xG
isthe solution of
Obviously
issingular along
the non-characteristic surfaces(and {x
=01) issuing
fromIx
=01.
We next see
hypothesis (A.1).
If it isviolated,
we can not take (o inTheorem
1,
ingeneral.
Consider thesystem
Then
is the solution of
(8).
In a smallneighborhood
of theorigin,
we may assumelt(X - «
1.But,
however small x maybe,
we can make the secondterm
arbitrarily large
if we go round t== :=l:: xl
many times. Hence to avoid thesingularities
-~- x arcsin(x-2 t)
=11
we must shrink »to 0 as we turn round x - t2 = 0.
The same
phenomenon
occurs forsimple
characteristicsystems
withmore than two characteristics. For
instance,
consider thesimple
charac-teristic 3x3
system
The solution of
(9)
isgiven by u = (x
-t) 2, v = (x
-~-t)t
and w =(1- ~
.
(t(X2
-t2)2
-~- x2 arcsin(x-1 t)))-1. By
the same reason asabove,
w shrinksto 0 as we turn round t ~ x = 0.
We remark that the obstruction in the first case is different from that in the last
two, where, though
we can not take w, it seems thatsingulari-
ties
essentially propagate along
characteristics.2. - Deformation of contours in characteristic curves.
We
put a = (aI,
..., and b =(b1,
...,bn).
In whatfollows ,u
denotesa or b. Let
y) (,u =
a,b)
be the solution of the canonicalsystem
and
y,(t, x)
be the solution of the eiconalequation
Then we have
Letting Q,
,~’ and ro besmall,
if necessary, y we may assume thatWe
put
for p E Qthat
is,
is the(complex) p- characteristic
curvethrough
p. Ifp =
(0, y), y
E 921(we
have assumed ,~’= Q nIt
=0})
we shall write instead ofT,((0, y)).
Wedenote,
forsimplicity, by h,
the first com-ponent
of y,~ , thatis, hi,
is the solution ofPut for
which is a
(complex) regular hypersurface
in S~ forsufficiently
small z E C.in Theorem 1 is
just
LEMMA 1. Give y E Cn and z E C and consider the
equation for
theknown scalar t:
Then there exist
positive
constants r,Co
withCo
eo r such thatfor
anylzl jyj
eq.(18)
has aunique
solution t =ta(z, y) (resp. tb(z, y))
in
It
rsatisfying
Here
00
isindependent of
e.REMARK.
Letting
r and besufficiently small,
we may assume that the set{(t, y ) ) : It
Cr, y J C
is contained in S~.PROOF. From
(10)
and(16)
it follows thatBy (A.1)
the last terms do not vanishat y
=0,
and t = 0 satisfies(18)
for
(z, y )
=(0, 0).
Therefore theimplicit
function theoremimplies (19).
(20)
is alsoclear, because t,,
isLipschitz continuous.
We
put
which are
holomorphic
in eo, Then in{(t, x) : It
Cr), (resp
intersectsKb(z) (resp. only
at(resp.
Therefore
for Izl
go,Iyl
eo we haveFor e,
0 ~o we take an open ball OJsufficiently
small so thatwhere
Co
is the constant in(20).
Later we willmake o
smaller a finitenumber of times.
Accordingly
we must shrink cv tosatisfy (23).
Let y
E (o -(Ka
U be a continuouspath
in w -(Ka
Ustarting
fromy(0)
=po
E a) nft
= ~0}
where I is the closed unit interval. Letyo
be thet-component
of y. Thenby (23)
we havewhere
D(Co o)
is the closed disc in C of radiusCoo. By (23) (ya(y(s))’ C
(2,this and
(20) imply
thatta(0, ya(y( ~ ))~
is apath
in the open discD(60 0) :
If
ta(z,
= 0(resp.
=yo(s)),
thenTherefore
y (s ) í .K~ implies
thatIn view of
(24), (25)
and(26),
we can find afamily
of smoothpaths s E I,
a continuous deformation of the constant map 0along yo avoiding
thatis,
Further,
since 1:8 is apath
inpoint},
we can make thelength
of 1:8 shorter than Hence
modifying
the arclength parameter,
wemay assume that
Then it is clear that the
family
ofcontours,
as ,s E I,
definedby
satisfy
Since Y tt,
c,and t,
areholomorphic,
we can find a constant01
> 0 such thatLEMMA 2.
Suppose
that(28)
and(31)
hold. Then we havein
particular,
PROOF.
(32) easily
follows from(28), (29)
and(31-b).
Since
0)
=y(s), using
theintegral formula,
we haveNow
(31-a)
and(32) imply (33).
By (23), )~(/))~~
hence+ + e ,
which proves
(3 4 ) .
,We
take e
> 0 sothat o o§f(1
+ Then we define afamily
ofsmooth contours
~S , s
EI, by
that
is, s,)
is theintersection
of andsl))).
Since eo, 9
/hb(rx)/ eo by (34)
andPb(Z, y)
eo,/y/
(35)
is well-defined.Figure
1 Note thatLEMMA 3. The
family of
smooth contoursf3s,
s EI, satisfy
PROFF. To prove
(37-a),
it isenough
to showp°
EKa(hb(PO»)
n.I’b(y(0))
because of
(22)
and oco ---p°. Obviously p° E hb(y(0))
=Fb(pO).
Recall thatha = hb
= XI on t = 0 and thatp°
EIt
=0}.
Therefore =which shows
PO
E’
By (30-b)
we havehence
This proves
(37-b).
From the definition we can
easily
see(37-c, d).
We differentiate
~3 using (21)
and(35):
This
equality, (31)
and(32) yield (38).
We can
prove (39)
in ~ the same way as(33).
We introduce the
following
notation:We now define
inductively
a countable number of maps0 s i 1, c~k 1,
as follows:Figure
2LEMMA 4. ..Let
°3
= max(4°0°1’
and e beThen ak and
f3k
arewell-defined by (41),
andsatisfy
thefollowing for
k =1, 2, 3, ....
.where we have
put
a° =~80
= r.PROOF. We prove Lemma 4
by
induction on k. For k == 1 we havealready
done it(see
Lemmas2,
3 and(30)).
Let us assume that the asser-tions hold for k =
1, 2,
... l. Then(42)
and(45) imply
Especially,
for k = 1 we have oo. Therefore andare well-defined. We can
easily
see(43-a)
and(44).
So weverify (43-c)
for Let =
(Gz,
1-j,).
Thenc~~+1
=1 -,&,. Using
thisequality
and
(36)
we findTherefore
which shows
1- ö=z) = (0,
Analogously
we canverify (43-c)
for and(43-b). Finally
we see(45).
By (43-b)
we findhence
The first term on the
right
is estimatedby
and the second termby
hence the left side is estimatedby
The estimate for isexactly
the same.Thus we have
completed
the induction. r3. - Proof of Theorem 1.
We solve eq.
(3) by
successiveapproximation:
The solution of
(47)
isgiven by
Since for any
path V
in y,~oy arepaths
in Q’ - =01,
uo and vo can be
analytically
continued toholomorphic
functions onLet po
be anarbitrary point
in Q’ -fxl == 0}.
Thenby
theCauchy- Kovalevskaja
Theorem we obtainsuccessively c , v , j = 1, 2, ... ,
whichare
holomorphic
nearpo. They
areexpressed
alsoby integrals
on charac-teristic curves:
where a
(resp. fl)
is a contourjoining (0, ya(t, x)) (resp. (0, yb(t, 0)))
and(t, o)
inx) (resp. o)),
and on âand f3 Ui and v,
areholomorphic.
If
(t, x)
issufficiently
close topo,
we can take as 0153or fl
the line(st, x»)),
9 s E I.Let y be a
path
in S~starting
frompo.
If there exists afamily
of smoothcontours
o2s
such thatthen we can continue
along
y to the terminalpoint.
Here is theinverse
path
of&s , rIs
is the restrictionof y
on[0, s]
and * stands for thepath product.
The same assertion is true for if wereplace
a with bin
(50).
Let oi be as in Section 2 and y E
C°(I;
(JJ - Ugb))
withy(o)
=p°
E (JJ r1
{t
=0,
xl ~0}.
Let =1, 2,
..., be the maps in Lemma 4.Let d =
...)
be a sequence ofpositive
numberssatisfying
Then for each u =
...) satisfying (51)
we define apath ya(S), 0 s
so
+ :L
7 as follows:that
is,
where , I and
LEmmA 5. be as above. Then
for
any asatisfying (51),
uj andv, , j
=0, 1, 2,
..., are allanalytically
eontinuabtealong
y« .,PROOF. We prove the lemma
by
induction onj.
Since ~y arepaths
in Q -
(Ka u
the assertion is truefor j
= 0. Let us assume that theassertion holds
for j
=0, 1,
..., l. To see and Vl+1 areanalytically
continuable
along
YC1, it isenough
to construct deformationsalong
ya satis-fying (50).
Define afamily
of contours&8
withparameter s
as follows:Then it
easily
follows from Lemma 3 that~8
satisfies(50-a, b, c).
Since foreach s there is a
sequence a satisfying (51)
such that&81~y~~$ =
ya, the inductivehypothesis
assures(50-d).
For the deformation
satisfies
(50) (where a
isreplaced by b).
’
.. Thus we have
completed
theproof..
Fix a
positive
number Rlarger
thanRo
in(A.2).
Let M and L be the maximum and theLipschitz constant, respectively,
onR~:
where q:;
=f,
g.LEMMA 6..Let ~o be
Then
for
all yaand j
=0, 1, 2,
..., we havePROOF. Induction on
j. For j
=0, (A.2) implies (58).
Note that(44) implies
Then
(49)
with(56) yield
where 3 = 1 if 1 if
s > so .
Similarly
we canobtain ’the
estimate forv f+1.
0LEMMA 7. For all yQ
and j
=1, 2, 3,
..., thefollowing
estimates hold:where
PROOF. We prove the lemma
by
inductionon j. For j
= 0 see(59).
Suppose (60)
is true for1, 2, ..., j.
ThenBy
Lemma 6 we can use(57),
henceSince
b~(q) =
+go - 27)
with some i =(so, 9,,, 82’ ...),
the inductivehypothesis implies
The estimate for
V1+1
isexactly
the same. Thus we havecompleted
theproof. ·
REMARK. The essential
point
of theproof
is that we can take the con-stant
0,
in(44)
which isindependent
of k and e.The constants
M, K, C3 and e
areindependent
of y inTherefore for any
point p
in - U we haveWe write
The
right
side convergenceabsolutely
anduniformly
on(Ka
uKb»)’
hence the limit
functions u,
v, the solution of(3),
areholomorphic
onKb»). Furthermore, oi depends
on e,and e
onM,
but not on u° and v°.
Thus we have
completed
theproof
of Theorem 1.Lastly
we remark that if the space dimension n isequal
to one, then coincides with hence for any8]L)l a 2 (s° , ~ ,
is a con-tour in
rb(a(so, s.,)) (of
coursea2(so, sl, ~ )
is a contour inLa(f3(so, s1))~.
FSo we can prove Theorem 1
using only
CX2.REFERENCES
[1] J. RAUCH - M. REED,
Jump
discontinuitiesof
semi-linearstrictly hyperbolic
sys- tems in two variables: creation andpropagation,
Comm. Math.Phys.,
81 (1981),pp. 203-227.
[2] J. RAUCH - M. REED, Nonlinear microlocal
analysis of
semilinearhyperbolic
systems in
one space dimension, Duke Math. J., 49 (1982), pp. 397-475.[3]
T. ISHII, Constructionof
solutions withsingularities for
semi-linearequations,
inpreparation.
Department
of MathematicsFaculty
of Science andTechnology
Science
University
ofTokyo
Noda