R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
A LBERTO F ACCHINI
Fiber products and Morita duality for commutative rings
Rendiconti del Seminario Matematico della Università di Padova, tome 67 (1982), p. 143-159
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Duality
for Commutative Rings.
ALBERTO FACCHINI
(*)
The lack of
examples
of commutativerings
with a Moritaduality
has been noticed
by
many authors(e. g.
P. Vamos[8],
B. Bal-let
[1], etc.). Apart
fromcomplete
Noetherian localrings
and maximalvaluation
rings, only
a few other« sporadic» examples ([8])
seem toexist in the literature. In this paper we show that fiber
product
is auseful tool for the construction of commutative
rings
with a Moritaduality starting
from knownexamples;
with it we are able to con-struct a number of
examples
of suchrings.
In
particular
theexamples
we obtain in this way allow us togive
acomplete
characterization of all the trees with a finite number of maximal chains which areorder-isomorphic
tospectra
of commutativerings
with a Moritaduality.
I.Kaplansky
has observed that thespectra X
of commutativerings
possess thefollowing
twoproperties (as partially
orderedsets):
(Kl) Every
chain in X has a least upper bound and agreatest
lower
bound;
(K2) If x, y
E X and x y then there exist elements xl , with such that there is no element of Xproperly
bet-ween xx and y1.
(*)
Ind. dell’A.: Istituto diAlgebra
e Geometria, Universith - Via Bel- zoni 7 - 35100 Padova.Lavoro
eseguito
nell’ambito del G.N.S.A.G.A., mentre l’A, usufruiva diuna borsa di studio del C.N.R.
We prove that every tree .X with a finite number of maximal chains and with
properties (Kl)
and(K2)
isorder-isomorphic
to thespectrum
of a commutativering
with a Moritaduality.
Therefore all the trees with a finite number of maximal chains which are
order-isomorphic
tospectra
of commutativerings
are alsoorder-isomorphic
tospectra
of commutativerings
with a Moritaduality.
1. Notation and
elementary
results.All
rings
in this note are commutative withidentity,
y andring morphisms respect
the identities.Let
A, B,
C be commutativerings,
and let a : A -C, ~ : B -~
Cbe
ring morphisms.
Then there exist a commutativering
P and tworing morphisms
ce’ : P - B and~’ :
P - A such that with thefollowing property: given
anyring
D and any tworing morphisms
D - A and 1jJ: D - B such that there exists a
unique morphism
cv : D - P suchthat 99
=and y
= a’cv.Disregarding
0153,f3, a’,
is called thefiber product
of A and Bover
C,
denotedby
AX CB.
It isunique
up toisomorphism
in theobvious way. The easiest way to visualize A
X C B
is as asubring
ofA X B
(direct product
of therings
A andB), by defining
AX CB
==
{(a, b)
EA =(the operations
are of courseby
com-ponents)
andby taking
theprojections
on the first and the second factor asfl’
and a’respectively.
It is easy to
generalize
the above construction to any finite number ofrings A¡, ..., An
andmorphisms
Xiy ... , with ai :Ai --~
C..It is also easy to prove the existence of the
following
canonicalisomorphisms:
The
isomorphism
in1)
is theexchange;
in3)
themorphism
C - C is the
identity; 2)
isimproved
in thefollowing
lemma.1.1. LEMMA. Zet
Ai, A2, A, Ci,
commutativerings,
andCl,
CX21:A2 --~ C1,
a22 :.A2 --~ C2, A3 -* C2
bering morphisms.
Then a22
canonically
induces amorphism à22: Al x clA2
-C2
andcanonically
induces amorphism i2l: A2 X ca 4.a ~ C1. Constructing
thefiber product
withrespect
to thesemorphisms,
there is ac canonical iso-morph2sm (AI
XCi A2)
XAl X c1 (A2
·The
proof
is standard. Another lemma whichplays
a fundamental role in thesequel
is thefollowing:
1.2. LEMMA. Let
A, B,
C be commutativerings,
and cx: A -C,
B -~ C be
ring morphisms.
Let C’ =oc(A)
r1 A’ =a 1(C’),
B’ =_ ~8-1 ( C’ ).
ThenA’, B’,
C’ aresubrings of A, B,
Crespectively,
andthere is a canonical
isomorphism
A A’X cIB’.
This
proof
is standard too. Note that in Lemma 1.2 themorphisms
A’ --~
C’,
B’ -~ C’ used in the construction of the fiberproduct
A’ XcIB’
are the restrictions of a and
fl.
These restrictions aresurjective ring morphisms.
Since we shallessentially employ
the fiberproduct
toconstruct new
types
ofrings
with a Moritaduality,
Lemma 1.2 says that we may limit ourselves to the case in which the twomorphisms
oc: A -~ C and
~3 :
B --~ C aresurjective.
Thishypothesis considerably simplifies
ourapproach.
Hencefrom
now on whenever we construct thefiber product
A XcB,
we shall suppose that the twomorphisms
a : A - Care
surjective.
We conclude this section with threeelementary
lemmas which will be useful in thesequel.
1.3. LEMMA. Let
A, B,
C be commutativerings,
ix: A - B - Csurjective ring morphisms.
Then thering morp h2sms
cc’ : A XcB -
B and~’ :
Ax c B - A
aresurjeetive.
The
proof
is trivial(think
of as asubring
of A xB andof a’ and
~’
as the restrictions of the canonicalprojections).
Recall that a
ring
is local if it has aunique
maximal ideal.1.4. LEMMA. Let
A, B,
C be corrzmutativerings,
0153: A -0, f3:
B - Csurjeetive ring morphisms.
Then A XcB
is localif
andonly if
A and Bare local.
PROOF. The
necessity
follows from Lemma 1.3. Theproof
of thesufficiency
is standard as soon as AxOB
is viewed as asubring
ofA
X B;
in this case the maximal ideal of A Xc B
is(A
XaB) n
X 1where
9NA
is the maximal ideal of A(B).
1.5. LEMMA. Let
A, B,
C be commutativerings,
0153: A -C, f3:
B - 0surjective ring morphisms.
Then AX CB
is a Noetherianring if
andonly if
A acnd B are Noetherianrings.
PROOF. The
necessity
follows from Lemma 1.3.Sufficiency:
Con-sider A and B as A
X CB-modules via
anda’ ;
then the A submodules of A and B areexactly
their ideals. Hence A and B are Noetherian AXCB-modules,
and therefore A X B is a Noetherian Ax,B-module.
But A is a submodule of A X B.2.
Spectrum
of a fiberproduct.
In Section 5 we need a
description
of thespectrum
of a fiberproduct.
The fiberproduct
A of tworings
A and B over a thirdring
C may be viewed as apasting
of the tworings
A and Balong
C.It follows that its
spectrum Spec (A x,,B)
is obtainedby pasting together Spec (A)
andSpec (B) along
two closed setshomeomorphic
to
Spec ( C) .
This is betterspecified
inProposition
2.1.Let A, B,
C be commutativerings
and sur-jective ring morphisms.
Consider thetopological
space X =Spec (A)
VU
Spec (B), disjoint
union ofSpec (A)
andSpec (B)
with thetopology
in which the open sets are
exactly
the union of an open set ofSpec (A )
and an open set of
Spec (B).
If andQ
ESpec (B),
setP - Q
if P:2 ker a,Q:2 ker @
anda(P) _ f3(Q).
Consider theequival-
ence relation in X
generated by -.
Call thisequivalence
relationtoo. Then it is
possible
to consider thequotient topological
space(Spec (A) u Spec (B) )/~
of thetopological
space X =Spec (A)
u~J
Spec (B)
modulo theequivalence
relation ~.2.1. PROPOSITION.
Spec (A xOB) ig canonically homeomorphic to
(Spec (A)
uSpec (B) )/~.
PROOF.
Apply
the functorSpec
to the commutativediagram
of commutative
rings
andsurjective ring morphisms,
andget
thecommutative
diagram
of
topological
spaces and continuous maps.Spec (oc), Spec (fl), Spec (a’ )
and
Spec (~’ )
arehomeomorphisms
ofSpec ( C), Spec ( C), Spec (B), Spec (A)
ontoV(ker ot), V(ker V(ker (a’)), V(ker ~’) respectively
(here
if I is an ideal of aring .R, V(I)
is the closed set ofSpec (R) consisting
of allprime
ideals of .Rcontaining I).
Thus if X is the
disjoint
union ofSpec (A)
andSpec (B)
andX -
Spec (A x,,B)
is the map which restricted toSpec (A)
co-incides with
Spec (~8’)
and restricted toSpec (B)
coincides withSpec then 99
is a continuous map. Furthermore ker ot Inker @’
=0,
so everyprime
ideal of A XCB
contains either ker ce’ or ker~8’.
This meansthat p
issurjective. Using
the fact that the restrictionsof g
toSpec (A)
andSpec (B)
areinjective,
it is also easy to check that the kernelof 99
is theequivalence
relation ~. In order to prove the theorem itonly
remains to show that the continuous map g is aquotient
map, i.e. that thetopology
ofSpec (A
XCB)
is the finest forwhich 99
iscontinuous,
i. e. that if Y is a subset ofSpec (A X CB)
and is closed in X then Y is closed in
Spec (A X CB).
Butif Y is a subset of
Spec (A X CB)
andcp-1( Y)
=Spec (~’)w( Y)
UU
Spec ((X’)-1( Y)
is closed in.~Y,
thenSpec (fJ’)-l( Y)
is closed inSpec (A).
But
Spec (@’)
is ahomeomorphism
ofSpec (A )
ontoV(ker @’).
Itfollows that Y r1
V(ker ~’ )
is closed inV(ker fl’),
hence it is closedin
Spec (A Similarly
is closed inSpec (A
Thus Y =
( Y r1 Y(ker a’ ) )
is closed inSpec (A x cB).
Intuitively Proposition
2.1 says thatSpec (A)
andSpec (B)
eachcontains a closed set
homeomorphic
toSpec ( C)
and that if wepaste Spec (A)
andSpec (B) together by identifying
these two closedsets,
weget Spec (A (under
thehypothesis
that 0153: A --~ Cand (3:
B - Care
surjective,
ofcourse).
3.
Injective envelope
of asimple
module in a local fiberproduct.
In Section 2 we studied the
spectrum
of the fiberproduct
of tworings.
This paper is devoted to thestudy
of the commutativerings
with a Morita
duality.
Now aring
with a Moritaduality
islinearly compact (in
the discretetopology) [6,
Theorem1]
and everylinearly compact
commutativering
is the directproduct
of a finite numberof local
rings [10, Proposition 14].
Hence without loss ofgenerality
we
only
have tostudy
the local case.Now
by
Lemma1.4,
if 0153: A - C B -~ C aresurjective,
A
X CB
is local if andonly
if both A and B arelocal;
in this case Cis local
too;
moreover it is immediate to see that in this case theunique (up
toisomorphism) simple
modules overA, B,
C and AX CB
are
isomorphic (as
AX CB-modules).
Hence we need tostudy
theinjective envelope
of theunique (up
toisomorphism) simple
AX CB- module,
i.e. the minimalinjective cogenerator
in thecategory
of allA X
cB-modules.
Thesituation,
described in thefollowing theorem,
is the best we could
hope
for: since AX cB
is thepull-back
of A and Bover
C,
the minimalinjective cogenerator
in thecategory
of all AX C B-
modules is thepush-out
of the minimalinjective cogenerators
in thecategories
of all A- and B-modules over the minimalinjective
co-generator
in thecategory
of all C-modules.In the
sequel
if R is aring,
I an ideal of Rand .1~ anR-module,
then
AnnM I
denotes the set of all x E M such that Ix = 0 and denotes theinjective envelope
of M.3.1.
THEOREM. Let A, B,
C be localrings,
and a: A -C, ~8:
B - Cbe
surjective ring morphisms.
Let AX CB
be thefiber product of
A and Bover
C,
be theunique (up
toisomorphism) simple
C-module.Then
1)
S is theunique (up
toisomorphism) simple A-,
B- and AX CB-
module.2)
0153 induces amonomorphism of
A-modules(and therefore of
A
xaB-modules)
0153*:-* BA(S)
whoseimage
is simi-larly for fl.
3) If
P is thepush-out of
thefollowing diagram of
then P is the
injective envelope of
thesimple
A S.PROOF:
1)
is obvious.2) easily
follows from[7, Proposition 2.27];
note that == for a e
A, e
e3).
Let us view A as asubring
of A x B. Then if P is thepush-out
of the abovediagram,
we have P =(EA(S)EÐ
where M = -
~* ( e ) ) ~ e
E themultiplication
of an element(a, b)
e Ax c B by
an element where x EBA(S)
y EEB(S)
andthe bar denotes reduction modulo
M,
is definedby (a, b)(x, y)
=(ax, by).
Note that the map ~: - P
(dotted
in the abovediagram)
issimply
the canonicalembedding
of intoEA(S) (9 EB(S)
followedby
the reduction modulo .M~. It isclearly injective. Similarly
forWe want to prove that Let us show that P is an
injective
Ax cb-module.
Theproof
is divided into foursteps.
STEP 1: For each ideal I in A every A
X aB-morphism
I - Pextends to an A X
cB-morphism
A - P.Similarly tor
B.In fact if I is an ideal of A and 99: I - P is an A X
cB-morphism,
then because I ker
j~’ -
0. NowBut if and y then
(x, y) - (x + 0)
mod M,
and thusAnnp(ker ~’ j
= Henceand thus there exists an A X
OB-morphisrn
I --RA(S)
such thatg = SAV.
But y
is also anA-morphism
and isA-injective.
Therefore there exists an
A-morphism ip:
A ~extending
V.Thus A - P is an A
X cB-morphism extending
g.Similarly
for B.Let be an A
X cB-morphism.
Since kerB’ =
0 EÐ kerfl, by
the firststep 99
extends to an AX CB-morphism
0 EÐ B -P;
thisin turn
trivially
extends to an whoserestriction to A X
C B
is an A XC B-morphism extending
g. Therefore everyA X cB-morphism
extends to anA x cb-morphism A X cB - P.
Consider the exact sequence
By
applying
the functor weget
an exact sequence Hom(A
X CB, P) -~
Hom(ker ~’, P) - Ext1(A, P) -~
Ext1(A
X cB, P).
In this sequence the last module in zero and we have
just proved
that the first
morphism
issurjective.
HencexcB(A, P)
= 0.STEP 3:
If
I is anideal of A, P)
= 0.Similarly f or
B.Consider the exact sequence 0 - 1 - A --~ 0.
By applying
the functor
HomA
X,B(-, P)
weget
the exact sequence Hom(A, P) -~
- Hom
(I, P) -~
Exti(A/.I, P) -~
Exti(A, P). By
the firststep
thefirst
morphism
issurjective
andby
the secondstep
the lastmodule
is zero. Thus
Xc B(A/I, P)
= 0.Similarly
for B.STEP 4: P is an
injective
A XaB-module.
We must show that if I is an ideal of A X
C B,
everymorphism
I - P extends to a
morphism
A P. We shall even showthat
every
morphism
I - P extends to amorphism
A X B ~ P. To dothat it is
enough
to prove that "exact sequence 0
get
the exact sequenceBut
(A 0
+(I
+B)
and(I
+BjB (B I,
where A r1
(I
+B)
and B n I are A XcB-submodules
of A and Brespectively,
i.e. ideals in A and B.By
the thirdstep,
the first and the last module in(*)
are zero. Hence P is aninjective
A xcb-module.
Let us show that P is an
indecomposable
A XC B-module. Let cp
be a non-zero .A.
X C B-endomorphism
of P suchthat 992
= cpo It isenough
to provethat p
is theidentity morphism. Now p
Ann, (ker fl’ ) .
In theproof
ofStep
1 we have seen thatAnnP(kerB’)
=Hence
Therefore T
induces anA
X CB-endomorphism
ofêA(EA(S)),
i.e. anA-endomorphism
ofEA(S),
which coincides with its own square. Since is an
indecomposable A-module,
it follows that either 0 or 998A = EA.Similarly
either99EB:= 0 or 998B =:: EB-
Since 99 =A
0 andêAEA(S)
+ =P,
wemust have either 99EA = EA or = BB. If for instance s , then
=
EA(S).
But = Hence =0,
fromwhich 99EB = EB - Hence we must have both 99EA = EA and 998B EB . But then if
(x, y) E I’~ cp(x, y)
= +êB(Y))
= +99--B(Y)
==
8A(X)
+EB(Y)
=(x, y).
Hence 99 is theidentity
of P and P is inde-composable.
Therefore P is an
indecomposable injective
module and contains thesimple
Ax,B-module
S. Hence P =EA 11, B(S)
4. Fiber
products
and Moritaduality.
We
essentially
know threeoperations
of commutativerings
whichpreserve the
property
« to have a Moritaduality » :
1)
Directproduct:
If A and B arerings
with a Moritaduality,
ythen A X B has a Morita
duality. (Note
that every commutativering
with a Morita
duality
is a finite directproduct
of localrings
with aMorita
duality.)
2) Homomorphic images:
If A is aring
with a Moritaduality
and I is an ideal of
..A.,
thenAll
has a Moritaduality.
3) Taking linearly compact
extensions andconversely:
Let A c Bbe commutative
rings,
y and let B be alinearly compact
A-module.Then A has a Morita
duality
if andonly
if B has a Moritaduality.
This is a theorem due to Peter Vamos
[8,
Theorem2.14].
In this section we prove that such a
property
is alsopreserved by
fiberproduct; assuming,
without loss ofgenerality,
y that the fiberproduct
islocal,
we shall prove thefollowing
statement:4)
LetA, B,
C be localrings
and let 0153: A -C,
B -~ C besurjective ring morphisms.
Then AX CB
has a Moritaduality
if andonly
if A and B have a Moritaduality.
We must notice that we also know other
operations
between com-mutative
rings
which preserve theproperty
«to have a Morita dual-ity >>,
but all suchoperations easily
follow from theoperations 1 ), 2)
and
3).
For instance:c~) Taking finitely generated integral
extensions(this
followsfrom
3)~
and is the case ofExample
2.4 in[8]);
b ) Taking split extensions, by joining
alinearly compact
moduleas a
nilpotent
ideal(see [5,
Theorem10];
this is the case of Ex-ample
2.4in [8], too);
c) Group rings:
if 1-~ is a commutativering
with a Moritaduality
and G is a finite abelian group, then the group
ring [G]
has a Moritaduality (it
follows froma) ) ;
etc.The interest in
proving 4)
lies in the fact that with the oper- ation4)
it ispossible
to construct a number ofexamples
of commutativerings
with a Moritaduality.
The(local)
commutativerings
with aMorita
duality
known up to now areessentially
thefollowing:
i) complete
Noetherian localrings;
ii)
maximal valuationrings;
iii) rings
with aprime
ideal such that1)
P iscomparable
to every ideal of
.Z~,
that is I c P or p c I for all ideals I of1~ ; 2)
thecanonical
morphism
isinjective; 3) .Rp
has a Moritaduality;
4)
has alinearly compact
field of fractions. This class ofrings
was discovered
by
P. Vamos[8].
Muller([8,
page285])
has noticedthat such
rings
are the fiberproduct
of therings .R/P
andRp (but
here the
morphisms
are not bothsurjective).
All other known
examples
of commutativerings
with a Moritaduality
are obtained from theserings
withoperations 1), 2)
and3).
This is the case, for
instance,
y for the domains withlinearly compact
field of fractions
([8]).
The
following
result has anelementary proof,
but since itplays
an essential role in the paper, we shall
give
two differentproofs
of it.4.1. THEOREM. Let
A, B,
C be localrings,
and let a: A -C, fl: B - C be surjective ring morphisms.
Then AX CB
has a Moritaduality if
andonly if
A and B have a Moritaduality.
FIRST PROOF. The
necessity
isobvious,
since A and B are homo-morphic images
of Thesufficiency
will beproved by using
Mullets Theorem 1
[6]
and our Theorem 3.1. Aring
.,R has a Moritaduality
if andonly
if .R and the minimalinjective cogenerator
arelinearly compact.
Thus if A and B have a Moritaduality,
A and Bare
linearly compact A X C B-modules,
and thereforeis
linearly compact.
On the other hand the minimalinjective
co-generators
arelinearly compact
A- and B-modules.By
Theorem 3.1the A
X C B-minimal injective cogenerator
islinearly compact;
henceA
X C B
has a Moritaduality.
SECOND PROOF. Let us prove the
sufficiency by using
Miiller’sTheorem 1
[6]
and Vamos’ Theorems 2.14[8].
If A and B have a Moritaduality,
then A and B arelinearly compact rings.
Hencethey
are
linearly compact
AX C B-modules,
from which A X B is alinearly compact
AX C B-module.
Since A X B has a Moritaduality,
.A.X C B
has a Morita
duality
too.The last
part
of this paper is devoted to thestudy
of the localrings
with a Moritaduality
which are obtained as fiberproducts.
Note that if
A, B,
C arerings
anda: A - C, (3: B --~ C
aresurjec-
tive
ring morphisms,
then AX CB
is acomplete
Noetherian localring
if and
only
if A and B arecomplete
Noetherian localrings (this follows,
forinstance,
from1.4,
1.5 and4.1);
henceby taking
fiberproducts (via surjective ring morphisms)
of Noetherianrings
with aMorita
duality
we still obtainrings
of the sametype.
On thecontrary
we
get
newexamples
of commutativerings
with a Moritaduality
by taking
fiberproducts (via surjective ring morphisms)
either of aNoetherian
ring
and a valuationring
or of two valuationrings,
andby iterating
such constructions a finite number of times. This is what we shall do in the next section.5. Particular cases.
Let
A, B,
C be commutativerings
and let a : A --~C, ~ :
B -~ Cbe
surjective ring morphisms.
Assume A is acomplete
Noetherianlocal
ring
and B is a maximal valuationring.
Then C must be aNoetherian maximal valuation
ring.
Hence C has to be of one ofthe
following
threetypes: 1)
afield; 2)
a local artinianprincipal
idealring
which is not afield; 3)
acomplete
DVR.In this case
Spec (A
isSpec (A)
to which the chain of allprime
non-maximal ideals of B(in
cases1)
and2))
or the chain of allprime
ideals ofcoheight
> 1 of B(in
case3))
has beenpasted
under the maximal ideal
~~
of A(in
cases1)
and2))
or under theprime
ideala-1(0)
ofcoheight
1 in A(in
the case3)).
The
Noetherianity
of A and the fact that B is a valuationring (i.e.
every ideal in B is the union of a chain ofprincipal ideals)
« mix »in A
X C B
in thefollowing
sense: every ideal ofA X C B
is the union of anascending
chain offinitely generated
ideals. If we fix an ideal I ofJL Xc-Sy
this caneasily
be seenby considering
the exact sequence0 - 1 n
ker f3’
2013~ .I4 ~(1)
2013~ 0 andby taking
a set ofgenerators
of Iconsisting
of a finite number of elements of I whose#’-images generate
and of a set of
generators
of In kerf3’.
5.1. EXAMPLE. Let be a
field, X1, ..., Xn indeterminates,
A =
kQX~, ...,
thepower-series ring,
G atotally
ordered abelian group, B =k[G]
thelong power-series ring
relative to k and G. ThenA xoB,
fiberproduct
of acomplete
Noetherian localring
and amaximal valuation
domain,
is a commutative localring
with a Moritaduality.
5.2. EXAMPLE.
Let k7
A and G be as in the aboveexample,
letG(f) Z
have thelexicographic order,
B =Z]
be thelong
power-series
ring,
C =... , Xn ) ~
5.3. EXAMPLE. Let
k, A, G,
B be as inExample 5.2,
and let nbe an
integer >
1. Take C =X2 ,
... ,B/I,
where I is theideal of B
consisting
of all elements of B withvaluation > (0, n).
5.4. EXAMPLE. Let p be a
prime number,
A thering
ofp-adic integers,
G atotally
ordered abelian group, C =Z/pZ, B
= thelong power-series ring.
Examples 5.2, 5.3, 5.4,
likeExample 5.1,
are localrings
with aMorita
duality,
which are fiberproducts
of a Noetherianring
and avaluation domain.
Now,
on thecontrary,
letA, B,
C be maximal valuationrings,
and let
a : A - C, fl : B - C be surjective ring morphisms. By Prop-
osition 2.1 the
spectrum
of AX CB
looks like a reverse Y. The fact that A and B are valuationrings (i.e.
everyfinitely generated
idealis
principal)
is inheritedby
A in thefollowing
way: everyfinitely generated
ideal ofA X C B
can begenerated by
two elements.5.5. EXAMPLE. Let k be a
field, G1, G2, H
betotally
orderedabelian groups,
G1tBH,
have thelexicographic
order. SetC = 1~QG~, long power-series rings.
Then A
X C B
islocal,
has a Moritaduality,
is the fiberproduct
oftwo valuation
rings
and everyfinitely generated
ideal can be gen- eratedby
two elements.Such a construction can be
easily
iterated to any finite number of maximal valuationrings A1, ... , An, C1, ... ,
andsurjective
mor-phisms
ai :A i --~ Ci ,
=1, ... ,
n -1. In this case thespectrum
ofAl X Ca ... X On-l An
is a tree with at most n maxi-mal chains and every
finitely generated
ideal can begenerated by n
elements.
Let us invert such a result with a construction which is
curiously
dual to a construction due to S.
Wiegand [9].
Recall that a chain of apartially
ordered set X is atotally
ordered subset of .X..A tree is apartially
ordered set X with maximum such thatis a chain of X for all x E X.
S.
Wiegand [9] proved
that if X is a finitetree,
then there exists aBezout domain R such that
Spec (R)
is orderanti-isomorphic
to Xand
.Rp
is a maximal valuation domain for all P ESpec (R).
We shallprove that if X is a finite
tree,
then there exists a localring
1~ with aMorita
duality
such thatSpec (.R)
is orderisomorphic
to X andRIP
is a maximal valuation domain for all P E
Spec (.R) .
In fact we shallprove much more,
allowing X
to be infinite but with a finite number n of maximalchains,
and we shall obtain that the R constructed will have theproperty
that everyfinitely generated
ideal of R can begenerated by n
elements.Of course not every tree with a finite number of maximal chains is
order-isomorphic
to thespectrum
of a commutativering.
In factlet .X be a
partially
ordered set and suppose that X is order-iso-morphic
toSpec (.1~)
for some commutativering
1~.Then,
as notedby
I.Kaplansky [3,
page6,
Theorems 9 and11] (see
also[4]),
thefollowing
twoproperties
hold:(Kl) Every
chain in .X has a supremum(sup)
and an infimum(inf).
(K2)
If and then there exist elementssuch that and there does not exist an element of X
properly
between xl and y1.Recall the definition of
lexicographic product [2, Chap. III, § 15,
Exercise
3].
Let be afamily
oftotally
ordered abelian groups, and assume that4
istotally
ordered under a relation . Let G= fl Ga,
be the directproduct
of the groupsGa, .
We consider thekEA
elements of G as functions
f : U Ga
such thatf(A)
EGa
for each Ain ll. For we define the
support of f ,
denotedS(f),
to beLet is a well-ordered subset of
11~.
Then L is a
subgroup
of G. We define arelation
on L as follows.If f, g E L, f =1= g,
and if A is the first element ofS(g - f ),
thenif and
only
ifcg(~,).
Then therelation
is a total order com-patible
with the groupoperation
on L. The group.L,
under the rela- tion c , is called thelexicographic product
of the groupsAlso recall that a
subgroup
.H of atotally
ordered group G isconvex if
y E H
whenever andFirst we need a lemma.
5.6. LEMMA. Let
(X, c )
be atotally
ordered set withproperties (Kl )
and
(K2).
Let Y ={y
E has an immediatepredecessor
in.X }. Let ~
be the order reZation in Y
defined by
yl,y2 E Y
andin X. Let L be the
lexicographic product of
afamily of totally
orderedgroups
isomorphic
to Z indexedby ( Y, ~ ).
Then the setof
all convexsubgroups of
L ordered is orderisomorphic
to(X, c ) .
PROOF. Let
C(L)
be the set of all convexsubgroups
of L.Define a map 99:
g~ ( o )
= Notethat (p
is well-defined because X istotally
or-dered and has
property (Kl).
Furthermore ifC1, C2 E C(L)
andC2 ,
then
g~(C1) ~g~(C2).
Define a map
It is easy to check that
y(r)
is a convexsubgroup
of Z andLet us show that 99
and Y
are inverses of each other. If x EX,
We have to show that for all
f
EL, f
E C if andonly
ifThe
«only
if )) is trivial.Conversely
ifthen there egists h E C such that
C6C ’
otherwise,
sincewould have an immediate
predecessor y
inX ;
it would follow that- I B
diction. Hence h exists. But then if n =
11(supxS(f)) I +
1 EZ,
nE
Cand Since C is convex,
Ifle
C and thusf
E C.We are
ready
for our last theorem.5.7. THEOREM. Let X be a tree with a
f inite
number nof
maximalchains. The
following
areequivalent : (i)
X hasproperties (Kl)
and(K2).
(ii)
There exists ac commutativering
.R such thatSpec (R)
~ X(as
an orderedset).
(iii)
There exists a commutativering
R such that:1 ) Spec (R)
~ X(as
an orderedset) ; 2)
R islocal;
3 )
.R has a Moritaduality;
4) RIP
is a maximal valuation domainf or
all P ESpec (.R) ; 5) Every finitely generated
idealof
R can b egenerated by
nelements.
PROOF.
(iii)
~( ii )
is trivial and( ii j
~( i )
isKaplansky’s
remark.We
only
have to prove that( i )
~(iii).
Let .X be a tree with a finitenumber n of maximal chains and
with properties (Kl)
and(K2).
Let
01, ..., Cn
be the maximal chains of X . ThenC1, ..., Cn ,
as or-dered subsets of
X, satisfy (Kl)
and(K2),
too. LetL1,
... ,.Ln
be theordered groups
corresponding
toC1, ... , Cn
via Lemma 5.6(Li
is asuitable
lexicographic product
ofcopies
ofZ,
whose set of convexsubgroups
isorder-isomorphic
toCi ) .
Then
Oi (1 C;i
is a chain in~,
hence it has an inf in X. Suchan inf
belongs
to bothCi
andCi+, (i
=1, ... , n -1 ).
LetCi n Ca+~
be the inf of
C$ n C,+,.
Now letL’
be the convexsubgroup
ofL, consisting
of all elementsf
such that for all x ES( f ).
Then.L~
is
canonically isomorphic
to a convexsubgroup
of.Li+,~ (i
=1,
...,n -1).
Now let k be any field and letA1= 1~QL1~, ...,
C1= 7~ QLI~,
... , be thelong power-series rings
overL1, ... , Ln , i L’7 I
... ,respectively.
Leti =
1, ... , n -1,
be thesurjective
canonicalring morphisms
inducedby
theembeddings L§ - Za , L§ - respectively.
Thenclearly
.R =has the
properties required
in(iii).
REMARK. . Of course with the fiber
product
it ispossible
to con-struct
examples
ofrings
with a Moritaduality by starting
fromrings
which are neither Noetherian nor
valuation,
too.5.8. EXAMPLE. Let A be Vamos’
Example (3.3)
in[8].
If C = kis a field and B = ... ,
7 X,,l ,
whereXl,
... ,Xn
are indeterminatesover k,
then AX C B
is a localring
with a Moritaduality.
5.9. EXAMPLE. Let p be a
prime number,
C be the fieldof p
el-ements,
A thering
ofp-adic integers,
B thering
of[8, Example (3.3)].
REFERENCES
[1]
B. BALLET, Sur les modules linéairement compacts, Bull. Soc. Math. France, 100(1972),
pp. 345-351.[2] R. GILMER,
Multiplicative
idealtheory,
Marcel Dekker Inc., New York,1972.
[3] I. KAPLANSKY, Commutative
rings, Allyn
and Bacon, Boston, 1970.[4]
W. J. LEWIS, TheSpectrum of
aRing
as aPartially
Ordered Set, J. ofAlgebra,
25(1973),
pp. 419-434.[5] B. J. MÜLLER, On Morita
duality,
Canad. J. Math., 21(1969),
pp. 1338-1347.[6]
B. J. MÜLLER, Linear compactness and Moritaduality,
J.Algebra,
16(1970),
pp. 60-66.[7] D. W. SHARPE - P. VAMOS,
Injective
modules,Cambridge
Univ. Press,London-New York, 1972.
[8] P. VAMOS,
Rings
withduality,
Proc. London Math. Soc., (3) 35(1977),
pp. 275-289.
[9] S. WIEGAND,
Locally
maximal Bezout domains, Proc. Amer. Math. Soc., 47(1975),
pp. 10-14.[10]
D. ZELINSKY,Linearly
compact modules andrings,
Amer. J. Math., 75(1953),
pp. 79-90.Pervenuto in redazione il 6