R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
C. N AST ˘ ˘ ASESCU N. R ODINÒ
Group graded rings and smash products
Rendiconti del Seminario Matematico della Università di Padova, tome 74 (1985), p. 129-137
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Group Rings
C.
N0103ST0101SESCU -
N. RODINò(*)
SUNTO - Mediante una nuova caratterizzazione del Smash
prodotto
si dimo-strano direttamente e in forma un
po’ piu generale
i teoremi di dualita di Cohen eMontgomery.
Introduction.
Let .R
= ~ R~
be ak-algebra graded by
a finite groupG,
withR,e
QEG
the
component corresponding
to theidentity
element e of G(k
is acommutative
ring).
In the paper[1]
M. Cohen and S.Montgomery
define the
ring
R #k[G]*,
called the «Smashproduct »
associatedto the
graded ring
.R. Thisring
may be used to obtain many proper- ties of thegraded ring
1~. The main tools areprovided by
the twoDuality
Theorems:Duality
Theorem for Action andDuality
Theoremfor Coaction
(see
Theorem 3.2 and 3.5 of[1]).
In this paper wegive
a new characterization of the Smash Product .R ~
k[G]* (Theorems
1.2and
1.3)
and we deducedirectly
from it and in a little moregeneral
form Cohen and
Montgomery Duality
Theorems(Theorems
2.2 and2.3).
1. The
rings End.,-, U), EndR( U)
and their structure.If R =
O.RQ
is ak-algebra graded by
a finite groupG,
we denoteoco
by R-gr
thecategory
of all unitalright graded
R-modules. If .M =are two
objects
of then themorphisms
in are
R-homomorphisms f :
such that forall or E ~. It is well known that
R-gr
is a Grothendieckcategory (see [2~).
(*)
Indirizzodegli
AA.: C. NASTAsESCU : Facultatea de Matematica, Uni-versity
of Bucharest, Str. Academiei 14, 70105 Bucharest 1, Romania; N. Ro- DINO: Istituto di Matematica « U. Dini », VialeMorgagni 67/A,
50134 Firenze(Italy).
130
If M
= ~
Mi is agraded
R-module and c~E G,
thenM(a)
is thegraded
AEG
module obtained from .M
by putting M(a)).
= thegraded
moduleis called the
a-suspension
of M[2].
It is well-known that themapping
.1~C ~M(a)
defines a functor fromR-gr
toR-gr
which isan
equivalence
ofcategories
for all E G. M ER-gr
is said to be G-znvacriant[2]
if for alla E G, if (or)
inR-gr.
Consider now thegraded
modules if and N. A R-linearmapping f :
M- N is said tobe a
graded morphism
ofdegree
r, r EG,
iff ( M6)
c Nur for all a E G.Graded
morphisms
ofdegree r
build up an additivesubgroup HOMR( M, N) Z
ofN) .
It is clear thatN) =
is a
graded
abelian group oftype
G andIn
particular,
ifM = N,
theni is a
graded ring
oftype
G. In thesequel
we will denote
by
U= +R(o).
Since is afamily
of genera-"eG
tors for
R-gr [2],
it follows that U is agenerator
for.R-gr.
When Gis a finite group, we also remark that
ENDR( U)
=EndR( U) (see [2]).
PROPOSITION 1.1.
[2] If
G = = e, g2, ... ,gn~
is afinite
group,then the
ring EndR( U)
isisomorphic
to the matrixring M n(R) equipped
with the
grading
where
In
particular,
thering
isisomorphic
to the matrixring
PROOF. See
Corollary
1.5.3 of[2].
By
an aetion of a group G on ak-algebra A
we mean a group mor-phism
a: let ag denote theimage
ofg E G
inAutk (A).
We may define the skew group
ring ( or
trivial crossedproduct)
denotedby A * G,
asbeing
the freeright
and left A-module with basis E6~}
and with
moltiplication given by (ag). (bh)
= aot,(b)gh,
where a, b EA, g, h E
G. Thering
A ~ G is agraded ring: A ~
G= ~ (A ~ G)6,
where"~
THEOREM 1.2.
I f G
=~gl
= e, g2 , ... ,gn~ is a finite
group, then thering EndR ( U)
isisomorphic
to the skew groupring EndR.gr ( U) ~
G.PROOF.
By Proposition
1.1 we have thatEndR ( U)
isisomorphic
to the matrix
ring Mn (R).
We consider the setwhere on the first
row
is on theki-th position, kl being
such thatUkl
=9,.A;
on the secondrow
is on thek2-th position, where k2
is such thatgka
=U2Ä;
... ; on the n-th row.Rn
is on thekn-th position,
where Ukn =
UnÄ.
Since G is a group it is easy to see that{1,2,...,~}==
-
(kl, k2,
... ,kn~.
Moreover one may see that Ua cM n (R)A.
LetU).EU).,
From the definition of U~. it follows that ui has a 1 on each column and all the other entries are 0. We will show now that the
system
has the
property
that u).tt, forall 1,
Let132
where 1 in the first row is on the
ll-th column, where gl1
= 1 inthe second row is on the
Z2-th column,
= g2/J; ... ; 1 in the n-th row is on theIn-th column,
whereg~n
= gn,u.There exists a
unique column,
saythe s-th,
such as its intersec-tion with the
kl-th
row has a 1 and the rest of its entries are zero.Thus we have that Since
gk, =
then g, =g, Alz
andso in the matrix uaua we have 1 on the first row in the s-th
position,
all the other entries of the first row
being
zero. Hence the first rowof the matrix uxul, is the same as the first row of the matrix
u).p.
Using
the sameargument
for the other rows, we deduce that ==== ’U).p. In
particular, since ue
isequal
to the unitmatrix,
we obtainthat each
Using
now Theorem 5.3.23 of[2],
we obtain that is
isomorphic
to the skew groupring ( Z7) ~
G.Q.E.D.
Let now A
== ffi Ag
be agraded k-algebra,
where k is a commuta-gEG
tive
ring
and G is a finite group.By [1],
the construction of the smashproduct A ~ k[G]*
is thefollowing: A # k[G]*
is the free left andright
A-module with basis g EG},
a set oforthogonal idempotents
whose sum is 1 and with the
moltiplication given by
the rule:(ap~) ~ - (bph)
=abgh-1Ph,
a, b E A.THEOREM 1.3. Let
R R,
be agraded k-algebra,
where G =y~?
- ~gl
= e, g2, ... ,gn~ is a finite
group. Then thering EndR_gr ( U)
isisomorphic
to the smashproduct
PROOF. We have seen that the
ring EndR-gr ( U)
isisomorphic
tothe matrix
ring
Define as follows: if for all g
E G,
thenput
It is clear
that 99
is additive andinjective.
It isstraightforward
tocheck that if then we have =
Consequently,
q is a
ring morphism.
Let S =T(B).
Hence S is asubring
of T. Con- sider the elements:i.e.
pg
is a matrix with 1 at the intersection of the k-th row with the k-thcolumn,
all its other entriesbeing
zero. Then thesystem
of ele-ments is a
system
oforthogonal idempotents
whose sumis 1. It is clear that
Let us prove that 1 k ~2, is a linear
independent system
overthe
ring
S. LetA
where sk
E S. Hence134
Then
and
hence a’
0 == g1g2 1 = ... = = ... =a;1g;;1 ag1gn = 0,
forall k, 1 k n.
ThusS1 = s2 = ... = sn = 0. The
ring S
is agraded ring
oftype
G withthe
grading
whereand Rg
is on the first row on theki-th position, ki being
such thatg = on the second row on the
k2-th position
suchthat g
==
g2gka ,
... , on the n-th row on thekn-th position
such that g = Thus it is clear that p: R - S becomes anisomorphism
ofgraded rings.
To finish theproof
we need to show that :To see this
let g = gm, h = g~
andWe have that
and thus
On the other
hand,
since is a matrix which has on the first row asingle
non zeroelement,
on thek1-th position,
forwhich gm
- on the second row a
single
non zeroelement,
on thek2-th position,
where92 gk2
..., on the n-th row asingle
nonzero
element, bUmuï:1,
on thekn-th position
such thatgmg-¡l ==
itis clear that
km
= 1and k,
~ 1 m, 1 s n. We deduce thatand thus = so
clearly (sp9)(tph)
= for all s, tESand g,
hEG.2.
Cohen.Montgomery duality
theorems.The notation in this section will be the same as the one in sec-
tion 1.
136
THEOREM 2.1. Let R
= @ Ru be a graded ring of type G,
where GQEG
is a
finite
group.If
we denote U= 0 ,R(Q),
then thef unetor
oEG
-
HomR-gr ( U,
anequivalence
thecategory R-gr to
the eate-gory
( U)-mod.
PROOF. Since is a set of
generators
forR-gr [2],
then Uis a
generator
forR-gr.
On the otherhand,
U is afinitely generated projective
R-module. Hence U is a smallprojective generator
for.R-gr
andtherefore,
after a classical result of B. Mitchel(see [3]),
the functor
HomB.,,r ( U, M)
is anequivalence
between the cate-gories .R-gr
andQ.E.D.
REMARKS:
1) Bearing
in mind Theorem1.2,
Theorem 2.1 isnothing
elsethat Theorem 2.2 of
[1].
for every a E G there exists a
homogeneous
invertible element ua The structure of crossedproducts
isgiven
in Theorem 1.3.23 of[2].
THEOREM 2.2. Let R
== EB
.Ra be agraded k-algebra
which is a crossed" -e
product,
where G is afinite
group with n = ThenPROOF. Since B is a crossed
product,
then B - in the cate- goryR-gr
for any a E G. ThereforeLEMMA. Let C be an abelian
category
and M anobject o f
C.Then, for
n > 0PROOF.
Straightforward (see [3]).
We may use the Lemma to obtain that
( U) (R)).
But and therefore We
apply
now Theorem 1.3 and obtain that
REMARK. This result is a
slight
extension of Theorem 3.2(Duality
Theorem for
Action)
of Cohen andMontgomery [1],
which isgiven
in the case .R = ~S * G is a skew group
ring.
THEOREM 2.3.
(Duality
forCoactions) (see [1]).
Let«EJ
be a
graded k-algebra,
where G 2s afinite
group with n = ThenPROOF.
By
Theorem 1.2 and Theorem 1.3 we have thatEndR
If
(.R ~ k[G]*) ~
G. Since U = then in thecategory
R-modit is Therefore °
REFERENCES
[1]
M. COHEN - S. MONTGOMERY,Group-Graded Rings,
Smash Product andGroup
Actions, Trans. Am. Math. Soc.,282,
no. 1(1984),
pp. 237-258.[2]
C. N0103ST0101SESCU - F. VAN OYSTAEYEN, GradedRing Theory, North-Holland,
Math.
Library,
Vol. 28 (1982).[3] Bo STENSTRÖM,
Rings of Quotients, Springer-Verlag,
Berlin, 1975.Manoscritto pervenuto in redazione il 18