! "# $% & $' () " $* % " $+ ,-.& +/ # - + $ 0 ' (1 + 2 3 4 & #$ # 3 + ' & " 5 ' , ' 5 5 6 7 +7 % ' () " $* % " $+ , -8 # +# 9
S
B
`
λ = β
`
! " # $ !
S = (L, Σ, <)
L
%(Σ, <)
&L
<
%rep
S
:
N
→ L
val
S
= rep
−1
a
∗
n 0 1
2
3
4
· · ·
rep(n) ε a aa aaa aaaa · · ·
{a, b}
∗
, a < b
n 0 1 2
3
4
5
6
7
· · ·
rep(n) ε a b aa ab ba bb aaa · · ·
a
∗
b
∗
, a < b
n 0 1 2
3
4
5
6
· · ·
rep(n) ε a b aa ab bb aaa · · ·
X
⊆
N
S
! # " "!rep
S
(X) ⊆ Σ
∗
" ! ! ! ! $
S = (L, Σ, <)
! # ! ! ! $ " ! # " " # #λ
∈
N
# $S
! # " ! !X
! !λX
" "S
! # " !
S
S = (L, Σ, <)
&S
&u
L
(n)
n
L
&L
⊆ Σ
∗
u
L
(n) ∈ Θ(n
k
)
k
∈
N
S = (L, Σ, <)
& %S
λ
λ = β
k+1
β
∈
N
&
L
! !u
L
(n) ∈ O(1).
L
⊂ Σ
∗
S = (L, Σ, <)
&X
⊆
N
S
X
&S
&X
⊆
N
S
λX
S
λ
∈
N
&
β > 0
&S = (a
∗
b
∗
,
{a < b}),
β
2
%S
β
&
B
`
= a
∗
1
· · · a
∗
`
%Σ
`
= {a
1
< . . . < a
`
}
`
≥ 1.
(B
`
, Σ
`
)
rep
`
val
`
&X
⊆
N
B
`
! # " !rep
`
(X)
%Σ
`
.
λ
%f
λ
: B
`
→ B
`
.
! ! ! " ! # ! ! ! $ " ! # " " # ! " " # " # ! ! ! ! ! #B
`
` = 2
Σ
2
= {a, b}
λ = 25
&8
−−−→ 200
×25
rep
2
↓
↓ rep
2
a b
2
−−−→ a
×25
9
b
10
N
−−→
×λ
N
rep
`
↓
↓ rep
`
B
`
−→ B
f
λ
`
λ = 25
f
λ
B
2
w, w
0
∈ B
2
f
λ
(w) = w
0
val
2
(w
0
) = 25 val
2
(w)
&
B
`
u
`
(n) :=
u
B
`
(n) = #(B
`
∩ Σ
n
`
)
v
`
(n) := #(B
`
∩ Σ
≤n
`
) =
n
X
i=0
u
`
(i).
`
≥ 1
n
≥ 0
%u
`+1
(n) =
v
`
(n)
u
`
(n) =
n + `
− 1
`
− 1
.
S = (a
∗
1
· · · a
∗
`
,
{a
1
<
· · · < a
`
})
& %val
`
(a
n
1
1
· · · a
n
`
`
) =
`
X
i=1
n
i
+ · · · + n
`
+ ` − i
`
− i + 1
.
n
∈
N
|rep
`
(n)| = k ⇔
k + `
− 1
`
|
{z
}
val
`
(a
k
1
)
≤ n ≤
`
X
i=1
k + i
− 1
i
|
{z
}
val
`
(a
k
`
)
.
3
a
∗
b
∗
c
∗
aaa < aab < aac < abb < abc < acc < bbb < bbc < bcc < ccc.
%
val
3
(aaa) =
5
3
= 10
val
3
(acc) = 15
&
ϕ :
{a, b, c} → {a, b, c}
∗
ϕ(a) = ε, ϕ(b) = b, ϕ(c) = c
3
ε < b < c < bb < bc < cc < bbb < bbc < bcc < ccc.
%
val
3
(acc) = val
3
(aaa) + val
2
(cc)
val
2
b
∗
c
∗
&%
u
B
`
(n) ∈ Θ(n
`−1
).
%λ = β
`
.
`
∈
N
\ {0}
&n
n =
z
`
`
+
z
`−1
`
− 1
+ · · · +
z
1
1
z
`
> z
`−1
>
· · · > z
1
≥ 0
&
rep
`
(n).
% &t
i
≤
n
<
t
+1
i
←
←
t
i
←
%α
1
, . . . , α
`
α
i
+ · · · + α
`
=
z
(` − i + 1) − ` + i,
i = 1, . . . , `.
rep
`
(
n
) = a
α
1
1
· · · a
α
`
`
&
` = 3
12345678901234567890 =
4199737
3
+
3803913
2
+
1580642
1
%
n
1
+ n
2
+ n
3
= 4199737 − 2
n
2
+ n
3
= 3803913 − 1
n
3
= 1580642
⇔ (n
1
, n
2
, n
3
) = (395823, 2223270, 1580642),
%rep
3
(12345678901234567890) = a
395823
b
2223270
c
1580642
.
λ = β
`
S = (a
∗
b
∗
c
∗
,
{a < b < c}),
β
∈
N
\ {0, 1}
β
6≡ ±1 (mod 6)
β
3
%S
&
β
`
%S
S = (a
∗
1
· · · a
∗
`
,
{a
1
<
· · · < a
`
})
B
`
%`
β =
k
Y
i=1
p
θ
i
i
p
1
, . . . , p
k
`
&